Suppose m is the line with equation y = −4 and ΔA'B'C is mapped to ΔA"B"C" by applying the glide reflection T3, 0 Rm.
What are the coordinates of ΔA″B″C″?
Answers
Answer:
The coordinates of ΔA''B''C'' are;
A''(-1, -3), B''(-2, -6), C''(1 , -7)
Step-by-step explanation:
A glide reflection involves the reflection of the preimage over a given line, followed by the translation of the resulting image along the given line
Given that the coordinates of the triangle ΔA'B'C' are;
A'(-4, -5), B'(-5, -2), C'(-2, -1), we have by reflection across the line y = -4
A''(-4, -4 + 1) = A''(-4, -3)
B''(-5, -4 - 2) = B''(-5, -6)
C''(-2, -4-3) = C''(-2, -7)
Translation of A''B''C'' by T 3, 0, we have;
A''(-4, -3) → T₃, ₀ → A''(-4 + 3, -3) = A''(-1, -3)
B''(-5, -6) → T₃, ₀ → B''(-5 + 3, -6) = B''(-2, -6)
C''(-2, -7) → T₃, ₀ → C''(-2 + 3, -7) = C''(1 , -7)
The coordinates of ΔA''B''C'' are therefore;
A''(-1, -3), B''(-2, -6), C''(1 , -7).
Answer:
A″(−1, −3), B″(−2, −6), C″(1, −7)
option A
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NEEED HELP PLZZ :(
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Answer:
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Step-by-step explanation:
Answer:
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Step-by-step explanation:
Kinsey is 7 years less than twice Jacob's age. Let's call Jacob's age x. IF we call Jacob's age x, our equation can be 2x-7 = 13
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Step-by-step explanation:
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Step-by-step explanation:
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We have been given a line passing through points M (-3,5) & N (1,8) .
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Step-by-step explanation:
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Step-by-step explanation:
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Answer:
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Answer:
Step-by-step explanation:
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Answer:
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[tex]\bold{Hello!}\\\bold{Your~Answer~Is~Below!}[/tex]
______________________________
[tex]\bold{Solution~Steps:}[/tex]
[tex]1.)~54+3(1-1):[/tex]
[tex]\bold{Subtract~1~from~1~to~get~0.}[/tex][tex]\bold{Multiply~3~and~0~to~get~0.}[/tex][tex]\bold{Add~54~and~0~to~get~54.}[/tex][tex]2.)~54+3(2-1):[/tex]
[tex]\bold{Subtract~1~from~2~to~get~1.}[/tex][tex]\bold{Multiply~3~and~1~to~get~3.}[/tex][tex]\bold{Add~54~and~3~to~get~57.}[/tex][tex]3.)~54+3(3-1):[/tex]
[tex]\bold{Subtract~1~from~3~to~get~2.}[/tex][tex]\bold{Multiply~3~and~2~to~get~6.}[/tex][tex]\bold{Add~54~and~6~to~get~60.}[/tex][tex]4.)~54+3(4-1):[/tex]
[tex]\bold{Subtract~1~from~4~to~get~3.}[/tex][tex]\bold{Multiply~3~and~3~to~get~9.}[/tex][tex]\bold{Add~54~and~9~to~get~63.}[/tex]______________________________
[tex]\bold{Answers:}[/tex]
[tex]\bold{Term~1=\boxed{54}}[/tex][tex]\bold{Term~2=\boxed{57}}[/tex][tex]\bold{Term~3=\boxed{60}}[/tex][tex]\bold{Term~4=\boxed{63}}[/tex]______________________________
[tex]\bold{Hope~this~helps,}\\\bold{And~best~of~luck!}\\\\\bold{~~~~~~~-TotallyNotTrillex}[/tex]
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Answers
Answer:
Solution: x=5
Step-by-step explanation:
Equations
This is an equation in the form of a proportion or ratio:
[tex]\displaystyle \frac{2}{x+3}=\frac{5}{4x}[/tex]
To solve it, we eliminate the denominators by multiplying by both of them.
Multiply by (x+3)(4x):
[tex]\displaystyle (x+3)(4x)\frac{2}{x+3}=(x+3)(4x)\frac{5}{4x}[/tex]
Simplify both sides:
[tex](4x)*2=(x+3)*5[/tex]
Operate:
[tex]8x=5x+15[/tex]
Simplify:
[tex]3x=15[/tex]
Solve for x:
[tex]x=15/3=5[/tex]
Solution: x=5
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boi pretty sure the answer is 6