Subtract and simplify the answer. 8/9 - 1/3

Answers

Answer 1

Solution

We want to simplify

[tex]\frac{8}{9}-\frac{1}{3}[/tex]

Now

[tex]\begin{gathered} \frac{8}{9}-\frac{1}{3}=\frac{8}{9}-\frac{1\times3}{3\times3} \\ \frac{8}{9}-\frac{1}{3}=\frac{8}{9}-\frac{3}{9} \\ \frac{8}{9}-\frac{1}{3}=\frac{8-3}{9} \\ \frac{8}{9}-\frac{1}{3}=\frac{5}{9} \end{gathered}[/tex]

Therefore, the answer is

[tex]\frac{5}{9}[/tex]


Related Questions

Identify the domain and range of the relation. Is the relation a function? Why or why not?
{(-3, 1), (0, 2), (1, 5), (2, 4), (2, 1)}

Answers

Domain={-3, 0, 1, 2}, Range={1,2,5,4} and the relation is not a function.

What is a function?

A relation is a function if it has only one y-value for each x-value.

The given relation is {(-3, 1), (0, 2), (1, 5), (2, 4), (2, 1)}

The domain is the set of all the first numbers of the ordered pairs.

In other words, the domain is all of the x-values.

Domain={-3, 0, 1, 2}

The Range is the set of all the second numbers of the ordered pairs.

In other words, the range is all of the y-values.

Range={1,2,5,4}

The given relation is not a function because there are two values of y  for one value of x. It means 4 and 1 are values of 2.

Hence Domain={-3, 0, 1, 2}, Range={1,2,5,4} and the relation is not a function.

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38. A right rectangular prism has a volume of 5 cubic meters. The length ofthe rectangular prism is 8 meters, and the width of the rectangular prismis a meter.What is the height, in meters, of the prism?Niu4© 30 10

Answers

It's important to know that the volume formula for a rectangular prism is

[tex]V=l\cdot w\cdot h[/tex]

Where V = 5, l = 8, and w = 1. Let's use these values and find h

[tex]\begin{gathered} 5m^3=8m\cdot1m\cdot h \\ h=\frac{5m^3}{8m^2} \\ h=0.625m \end{gathered}[/tex]Hence, the height of the prism is 0.625 meters.

Write the first 4 terms of the sequence defined by the given rule. f(1)=7 f(n)=-4xf(n-1)-50

Answers

The first 4 terms of the sequence defined by the rule f(n) = -4 x f(n - 1) - 50 are 7,

Sequence:

A sequence is an enumerated collection of objects in which repetitions are allowed and order matters.

Given,

The rule of the sequence is  f(n) = -4 x f(n - 1) - 50

Value of the first term = f(1) = 7

Now we need to find the other 4 others in the sequence.

To find the value of the sequence we have to apply the value of n.

Here we have to take the value of n as 1, 2, 3, and 4.

We already know that the value of f(1) is 7.

So, now we need to find the value of f(2), that is calculated by apply the value on the given rule,

f(2) = -4 x f(2 - 1) - 50

f(2) = -4 x f(1) - 50

f(2) = -4 x 7 - 50

f(2) = -28 - 50

f(2) = -78

Similarly, the value of n as 3, then the value of f(3) is,

f(3) = -4 x f(3 - 1) - 50

f(3) = -4 x f(2) - 50

f(3) = -4 x - 78 - 50

f(3) = 312 - 50

f(3) =  262

Finally, when we take the value of n as 4 then the value of f(4) is,

f(4) = -4 x f(4 - 1) - 50

f(4) = -4 x f(3) - 50

f(4) = -4 x 262 - 50

f(4) = -1048 - 50

f(4) =  -1099

Therefore, the first 4 sequence are 7, - 78, 262 and -1099.

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-1.5(x - 2) = 6. What is X equaled to

Answers

[tex]\begin{gathered} -1.5(x-2)=6 \\ (x-2)=\frac{6}{-1.5} \\ x-2=-4 \\ x=-4+2 \\ x=-2 \\ \\ \text{ x is equal to -2} \end{gathered}[/tex]

Answer:

x-2=6÷(-1.5)

x-2=-4

x=-4-2

x=-6

What is a solution of a system of linear equations in three variables?

Answers

Hello!

When we have a system with the same number of variables and equations, we can obtain the value for all variables.

Knowing it, the right alternative will be:

Alternative B.

please help me please

Answers

F (x) = (-1/20)x + 13.6

Then

Radmanovics car y -intercept is= 13.6 gallons

Mr Chin's car y-intercept is= 13.2

Then , in consecuence

Radmanovics car has a larger tank, than Mr Chin's car.

Answer is OPTION D)

What are all of the x-intercepts of the continuousfunction in the table?Х-4-20246f(x)02820-20 (0,8)O (4,0)O (4,0), (4,0)O (4,0), (0, 8), (4,0)

Answers

The x-intercepts of any function f(x) occur when f(x)=0.

As a reminder, f(x) corresponds to the y coordinate for any given x.

So, we need to focus on the parts of the table where f(x)=0 and look at the x value, that will give us the coordinates of the x-intercepts.

We can see the first entry in the table has f(x)=0 and x= -4.

The only other entry in the table where f(x)=0 has x=4.

As such, the x-intercepts of the given function are (-4,0) and (4,0), which are the coordinates presented in the third option.

which point lies on the line with the slope of m=7 that passes through the point (2,3)

Answers

Answer:

B. Monkey Man

Step-by-step explanation:

M+o+n+k+e+y

5. Graph the system of inequalities. Then, identify a coordinate point in the solution set.2x -y > -3 4x + y < 5

Answers

We have the next inequalities

[tex]\begin{gathered} 2x-y>-3 \\ 4x+y<5​ \end{gathered}[/tex]

as we can see if we graph these inequalities we will obtain the next graph

where the red area is the first inequality and the blue area is the second inequality

and the area in purple is the solution set of the two inequalities

one coordinate point in the solution set could be (0,0)

A chef is going to use a mixture of two brands of italian dressing. the first brand contains 7% vinegar and the second brand contains 12% vinegar. the chef wants to make 280 milliliters of a dressing that is 9% vinegar. how much of each brand should she use

Answers

We know that

• The first brand contains 7% vinegar.

,

• The second brand contains 12% vinegar.

,

• The chef wants 280 milliliters with 9% vinegar.

Using the given information, we can express the following equation.

[tex]0.07x+0.12(280-x)=0.09(280)[/tex]

Notice that 0.07x represents the first brand, 0.12(280-x) represents the second brand, and 0.08(280) represents the final product the chef wants to make.

Let's solve for x.

[tex]\begin{gathered} 0.07x+33.6-0.12x=25.2 \\ -0.05x=25.2-33.6 \\ -0.05x=-8.4 \\ x=\frac{-8.4}{-0.05} \\ x=168 \end{gathered}[/tex]Therefore, the chef needs 168 of the first brand and 112 of the second brand.

Notice that 280-168 = 112.

Find the value of x that makes ADEF ~AXYZ..yE1052x – 114D11FX5x + 2Zх=

Answers

Given that the triangles are similar, we can express a proportion between their sides. DE and XY are corresponding sides. EF and YZ are corresponding sides. Let's define the following proportion.

[tex]\begin{gathered} \frac{XY}{DE}=\frac{YZ}{EF} \\ \frac{10}{5}=\frac{14}{2x-1} \end{gathered}[/tex]

Now, we solve for x

[tex]\begin{gathered} 2=\frac{14}{2x-1} \\ 2x-1=\frac{14}{2} \\ 2x=7+1 \\ x=\frac{8}{2} \\ x=4 \end{gathered}[/tex]Hence, the answer is x = 4.

A trapezoid has a height of 16 miles. The lengths of the bases are 20 miles and 35miles. What is the area, in square miles, of the trapezoid?

Answers

Given:

A trapezoid has a height of 16 miles.

The lengths of the bases are 20 miles and 35 miles.

To find:

The area of the trapezoid.

Explanation:

Using the area formula of the trapezoid,

[tex]A=\frac{1}{2}(b_1+b_2)h[/tex]

On substitution we get,

[tex]\begin{gathered} A=\frac{1}{2}(20+35)\times16 \\ =\frac{1}{2}\times55\times16 \\ =440\text{ square miles} \end{gathered}[/tex]

Therefore the area of the trapezoid is 440 square miles.

Final answer:

The area of the trapezoid is 440 square miles.

For 5 years, Gavin has had a checking account at Truth Bank. He uses a bank ATM 2 times per month and a nonbank ATM once a month. He checks his account statement online. How much money would Gavin save per month if he switched to Old River Bank?

Answers

EXPLANATION

Let's see the facts:

Number of years: 5

Account period = 2 times/month

Nonbank ATM -------> once/ month

If he switch the account to Old River Bank he would save:

$6 - $4.95 = $1.05

Transaction cost_Trust Bank = $1/transaction * 2 = $2

Nonbank_Trust Bank = $2/transaction = $2

Trust Bank Cost = 2 + 2 + 6 = $10

The account in the Old River Bank would be:

Account Services = $4.95

Bank ATM Cost = $0.00

Nonbank ATM Cost = $2.5/transactions * 1 = $2.5

----------------------

$7.45

The total cost at Old River would be = $7.45

The difference between Truth Bank and Old River would be $10-$7.45 = $2.55

Gavin would save $2.55 per month.

follow me and get brainist and 100 points​

Answers

Answer:

followed

Step-by-step explanation:

now gimmie

suppose that z varies jointly with x and y. When x=2, y=2, z=7 write the equation that models the relationship

Answers

[tex]\begin{gathered} z=\text{ x + y + b} \\ 7\text{ = 2+2+b} \\ 7\text{ = 4+b} \\ 7-4=b \\ b=\text{ 3} \\ z=\text{ x + y +3} \end{gathered}[/tex]

Find equation of a parallel line and the given points. Write the equation in slope-intercept form Line y=3x+4 point (2,5)

Answers

Given the equation:

y = 3x + 4

Given the point:

(x, y ) ==> (2, 5)

Let's find the equation of a line parallel to the given equation and which passes through the point.

Apply the slope-intercept form:

y = mx + b

Where m is the slope and b is the y-intercept.

Hence, the slope of the given equation is:

m = 3

Parallel lines have equal slopes.

Therefore, the slope of the paralle line is = 3

To find the y-intercept of the parallel line, substitute 3 for m, then input the values of the point for x and y.

We have:

y = mx + b

5 = 3(2) + b

5 = 6 + b

Substitute 6 from both sides:

5 - 6 = 6 - 6 + b

-1 = b

b = -1

Therefore, the y-intercept of the parallel line is -1.

Hence, the equation of the parallel line in slope-intercept form is:

y = 3x - 1

ANSWER:

[tex]y=3x-1[/tex]

Y = X - 8. y = -x +6* Parallel Perpendicular Neither

Answers

The equation of a line given in slope-intercept form is written as

[tex]\begin{gathered} y=mx+b \\ \text{Where m is the slope. This means the coeeficient of x is the slope} \end{gathered}[/tex]

For two lines to be parallel, their slopes must equal to each other. Also for the two lines to be perpendicular, their slopes must be a negative inverse of each other. An example of negative inverse is given as;

[tex]\begin{gathered} -\frac{1}{4}\text{ is a negative inverse of 4} \\ \text{Likewise, -4 is a negative inverse of }\frac{1}{4}\text{ } \end{gathered}[/tex]

The slope of the first line is 1, since the line is given as,

y = x - 8

(The coefficient of x is 1)

The slope of the second line is -1, since the line is given as,

y = -x + 8

(The coefficient of x is -1)

Therefore, since both slopes are not equal and not negative inverses of each other, then the correct answer is NEITHER.

How do we determine the number of hours each family used the sprinklers?

Answers

Given:

The output rate of Martinez family's sprinkler is 25L per hour and Green family's sprinkler is 35L per hour. The combined usage of sprinkler is 40 hours. The resulting water output is 1250L.

To find:

The number of hours each family used the sprinkler.

Solution:

Let Martinez family used sprinkler for x hours and Green family used sprinkler for y hours.

Since the combined usage of sprinklers is 40 hours. So,

[tex]x+y=40...\left(i\right)[/tex]

The output rate of Martinez family's sprinkler is 25L per hour and Green family's sprinkler is 35L per hour. The resulting water output is 1250L. So,

[tex]\begin{gathered} 25x+35y=1250 \\ 5x+7y=250...\left(ii\right) \end{gathered}[/tex]

Multiply (i) by 7 and subtract from (ii), to get:

[tex]\begin{gathered} 5x+7y-7\left(x+y\right)=250-7\left(40\right) \\ 5x+7y-7x-7y=250-280 \\ -2x=-30 \\ x=\frac{-30}{-2} \\ x=15 \end{gathered}[/tex]

Now, we get x = 15, Put x = 15 in the equation (i):

[tex]\begin{gathered} 15+y=40 \\ y=40-15 \\ y=25 \end{gathered}[/tex]

Thus, x = 15, y = 25.

There are two boxes containing only red and purple pens.Box A has 12 purple pens and 3 red pens.Box B has 14 purple pens and 6 red pens.A pen is randomly chosen from each box.List these events from least likely to most likely.Event 1: choosing a purple or red pen from Box A.Event 2: choosing a green pen from Box B.Event 3: choosing a purple pen from Box B.Event 4: choosing a purple pen from Box A.Least likelyMost likelyEventEventEventEvent

Answers

Event 1: choosing a purple or red pen from Box A

All pens are purple or red so the probability is:

[tex]P=\frac{12+3}{15}=\frac{15}{15}=1[/tex]

Event 2: choosing a green pen from Box B

We don't have green pens, so the probability is 0.

Event 3: choosing a purple pen from Box B

We have 14 purple pens and 20 total pens, so:

[tex]P=\frac{14}{20}=\frac{7}{10}=0.7[/tex]

Event 4: choosing a purple pen from Box A

We have 12 purple pens and 15 total pens, therefore:

[tex]P=\frac{12}{15}=\frac{4}{5}=0.8[/tex]

Listing from least likely to most likely, we have:

event 2 < event 3 < event 4 < event 1

Answer:

Event 2, Event 3, Event 4, Event 1

An arctic village maintains a circular cross-country ski trail that has a radius of 2.9 kilometers. A skier started skiing from the position (-1.464, 2.503), measured in kilometers, and skied counter-clockwise for 2.61 kilometers, where he paused for a brief rest. (Consider the circle to be centered at the origin). Determine the ordered pair (in both kilometers and radii) on the coordinate axes that identifies the location where the skier rested. (Hint: Start by drawing a diagram to represent this situation.)(x,y)= (  ,  ) radii(x,y)= ( ,  ) kilometers

Answers

The solution to the question is given below.

[tex]\begin{gathered} The\text{ 2.6km is some fraction of the entire Circumference which is: C= 2}\pi r\text{ = 2}\times\text{ }\pi\text{ }\times2.9 \\ \text{ = 5.8}\pi cm \\ \text{ The fraction becomes: }\frac{2.61}{5.8\pi}\text{ = }\frac{0.45}{\pi} \\ \text{The entire circle is: 2 }\pi\text{ radian} \\ \text{ = }\frac{0.45}{\pi}\text{ }\times2\text{ }\times\pi\text{ = 0.9} \\ The\text{ skier has gone 0.9 radian from (-.1.464, 2.503)} \\ \text{The x- cordinate become: =-1.}464\text{ cos}(0.9)\text{ = -1.4625} \\ while\text{ the Y-cordinate becomes: =-1.}464\text{ sin}(0.9)\text{ = -}0.0229 \\ \text{The skier rested at: (-1.4625, -0.0229)} \\ \end{gathered}[/tex]

Graph the function and state the domain and range.g(x)=x^2-2x-15Domain-Range-Graphed function-

Answers

Answer:

The domain: -∞ < x < ∞

The range: g(x) ≥ -16

Explanation:

The given function is:

[tex]g(x)\text{ = x}^2\text{-2x-15}[/tex]

The domain is a set of all the valid inputs that can make the function real

All real values of x will make the function g(x) to be valid

The domain: -∞ < x < ∞

The range is the set of all valid outputs

From the function g(x):

a = 1, b = -2

[tex]\begin{gathered} \frac{b}{2a}=\frac{-2}{2(1)}=-1 \\ g(-1)=(-1)^2-2(-1)-15 \\ g(-1)=1-2-15 \\ g(-1)=-16 \end{gathered}[/tex]

Since a is positive, the graph will open upwards

Therefore, the range of the function g(x) is: g(x) ≥ -16

The graph of the function g(x) = x^2 - 2x - 15 is plotted below

The Max or Min can be found by using the line of symmetry. That line of symmetry can be found by finding the midpoint of the two x-intercepts.Since the line of symmetry is x =-1 Write the function rule to find the coordinate to the minimum of this parabola.[tex]f (x) = (x - 2)(x + 4)[/tex]your answer should be in the form (_,_)

Answers

We know that, for a parabola, the minimum, or the maximum, is given by the vertex of the parabola. The formula for the vertex of the parabola is given by:

[tex]x_v=-\frac{b}{2a},y_v=c-\frac{b^2}{4a}[/tex]

And we have the coordinates for x and y for the vertex.

We can see that the line of symmetry is x = -1, and this is the same value for the value of the vertex for x-coordinate, that is, the x-coordinate is equal to x = -1.

With this value for x, we can find the y-coordinate using the given equation of the parabola:

[tex]f(x)=(x-2)\cdot(x+4)\Rightarrow f(-1)=(-1-2)\cdot(-1+4)\Rightarrow f(-1)=(-3)\cdot(3)[/tex]

We can also expand these two factors, and we will get the same result:

[tex]f(x)=(x-2)\cdot(x+4)=x^2+2x-8=(-1)^2+2\cdot(-1)-8=1-2-8=-1-8=-9[/tex]

Therefore, the value for the y-coordinate (the value for the y-coordinate of the parabola, which is, at the same time, the minimum point for y of the parabola) is:

[tex]f(-1)=(-3)\cdot(3)\Rightarrow f(-1)=-9[/tex]

The minimum point of the parabola is (-1, -9) (answer), and we used the given function (rule) to find the value of the y-coordinate.

We can check these two values using the formula for the vertex of the parabola as follows:

[tex]f(x)=(x-2)\cdot(x+4)=x^2+2x-8[/tex]

Then, a = 1 (it is positive so the parabola has a minimum), b = 2, and c = -8.

Hence, we have (for the value of the x-coordinate, which is, at the same time, the value for the axis of symmetry in this case):

[tex]x_v=-\frac{2}{2\cdot1}\Rightarrow x_v=-1[/tex]

And for the value of the y-coordinate, we have:

[tex]y_v=c-\frac{b^2}{4a}\Rightarrow y_v=-8-\frac{2^2}{4\cdot1}=-8-\frac{4}{4}=-8-1\Rightarrow y_v=-9[/tex]

Consider the graph of g(x) shown below. Determine which statements about the graph are true. Select all that apply.

Answers

SOLUTION

From the graph, the root of the equation is the point where the graph touches the x-axis

[tex]x=-4,x=0[/tex]

Hence the equation that models the graph becomes

[tex]\begin{gathered} x+4=0,x-0=0 \\ x(x+4)=0 \\ x^2+4x=0 \\ \text{Hence } \\ g(x)=x^2+4x \end{gathered}[/tex]

Since the solution to the equation are x=-4 and x=0

Hence the equation has two real zeros

The minimum of g(x) is at the point

[tex]\begin{gathered} (-2,-4) \\ \text{Hence minimum is at x=-2} \end{gathered}[/tex]

The minimum of g(x) is at x=-2

The vertex of g(x) is given by

[tex]\begin{gathered} x_v=-\frac{b}{2a} \\ \text{and substistitute into the equation to get } \\ y_v \end{gathered}[/tex][tex]\begin{gathered} a=1,\: b=4,\: c=0 \\ x_v=-\frac{b}{2a}=-\frac{4}{2\times1}=-\frac{4}{2}=-2 \\ y_v=x^2+4x=(-2)^2+4(-2)=4-8=-4 \\ \text{vertex (-2,-4)} \end{gathered}[/tex]

Hence the vertex of g(x) is (-2,-4)

The domain of the function g(x) is the set of input values for which the function g(x) is real or define

Since there is no domain constrain for g(x), the domain of g(x) is

[tex](-\infty,\infty)[/tex]

hence the domain of g(x) is (-∞,∞)

The decreasing function the y-value decreases as the x-value increases: For a function y=f(x): when x1 < x2 then f(x1) ≥ f(x2)

Hence g(x) decreasing over the interval (-∞,-2)

Therefore for the graph above the following apply

g(x) has two real zeros (option 2)

The minimum of g(x) is at x= - 2(option 3)

the domain of g(x) is (-∞,∞) (option 4)

g(x) decreasing over the interval (-∞,-2)(option 4)

Which of the following ordered pairs is a solution to the equation 2x+y=2? Select all that apply.(11,0)(−4,10)(−13,4)(−11,−1)(0,2)

Answers

You have the following equation:

2x + y = 2

In order to determine which of the given pairs is a solution, replace the values of x and y of such pairs and verify the equation, as follow:

(11,0)

2(11) + 0 = 22 ≠ 2 it's not a solution

(-4,10)

2(-4) + 10 = -8 + 10 = 2 it's a solution

(-13,4)

2(-13) + 4 = -26 + 4 ≠ 2 it's not a solution

(-11,-1)

2(-11) + (-1) = -22 - 1 ≠ 2 it's not a solution

(0,2)

2(0) + 2 = 2 it's a solution

Determine which is the better investment 3.99% compounded semi annually Lee 3.8% compounded quarterly round your answer 2 decimal places

Answers

Remember that

The compound interest formula is equal to

[tex]A=P(1+\frac{r}{n})^{nt}[/tex]

In the 3.99% compounded semiannually

we have

r=3.99%=0.0399

n=2

substitute

[tex]\begin{gathered} A=P(1+\frac{0.0399}{2})^{2t} \\ \\ A=P(1.01995)^{2t} \end{gathered}[/tex]

and

[tex]\begin{gathered} A=P[(1.01995)^2]^t \\ A=P(1.0403)^t \end{gathered}[/tex]

the rate is r=1.0403-1=0.0403=4.03%

In the 3.8% compounded quarterly

we have

r=3.8%=0.038

n=4

substitute

[tex]\begin{gathered} A=P(1+\frac{0.038}{4})^{2t} \\ A=P(1.0095)^{2t} \\ A=P[(1.0095)^2]^t \\ A=P(1.0191)^t \end{gathered}[/tex]

the rate is r=1.0191-1=0.0191=1.91%

therefore

the 3.99% compounded semiannually is a better investment

cos(alpha + beta) = cos^2 alpha - sin^2 beta

Answers

The trigonometric identity cos(α + β)cos(α - β) = cos²(α) - sin²(β) is verified in this answer.

Verifying the trigonometric identity

The identity is defined as follows:

cos(α + β)cos(α - β) = cos²(α) - sin²(β)

The cosine of the sum and the cosine of the subtraction identities are given as follows:

cos(α + β) = cos(α)cos(β) - sin(α)sin(β).cos(α - β) = cos(α)cos(β) + sin(α)sin(β).

Hence, the multiplication of these measures is given as follows:

cos(α + β)cos(α - β) = (cos(α)cos(β) - sin(α)sin(β))(cos(α)cos(β) + sin(α)sin(β))

Applying the subtraction of perfect squares, it is found that:

(cos(α)cos(β) - sin(α)sin(β))(cos(α)cos(β) + sin(α)sin(β)) = cos²(α)cos²(β) - sin²(α)sin²(β)

Then another identity is applied, as follows:

sin²(β) + cos²(β) = 1 -> cos²(β) = 1 - sin²(β).sin²(α) + cos²(α) = 1 -> sin²(α) = 1 - cos²(a).

Then the expression is:

cos²(α)cos²(β) - sin²(α)sin²(β) = cos²(α)(1 - sin²(β)) - (1 - cos²(a))sin²(β)

Applying the distributive property, the simplified expression is:

cos²(α) - sin²(β)

Which proves the identity.

Missing information

The complete identity is:

cos(α + β)cos(α - β) = cos²(α) - sin²(β)

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Consider the angle shown below that has a radian measure of 2.9. A circle with a radius of 2.6 cm is centered at the angle's vertex, and the terminal point is shown.What is the terminal point's distance to the right of the center of the circle measured in radius lengths? ______radii   What is the terminal point's distance to the right of the center of the circle measured in cm?_______ cm   What is the terminal point's distance above the center of the circle measured in radius lengths?_____ radii   What is the terminal point's distance above the center of the circle measured in cm? _____cm   

Answers

Remember that we can use some trigonometric identities to find relations between distances in a circle when the central angle is provided:

If we measure each distance in radius lengths, it is equivalent to take r=1 on those formulas.

A)

The terminal point's distance to the right of the center of the circle, measured in radius lengths, would be:

[tex]\cos (2.9\text{rad})=-0.9709581651\ldots[/tex]

This distance is signed since it indicates an orientation, but we can ignore the sign if we are only interested on the value of the distance.

Then, such distance would be approximately 0.97 radii,

B)

Multiply the distance measured in radius lengths by the length of the radius to find the distance measured in cm:

[tex]0.97\times2.6cm=2.52\operatorname{cm}[/tex]

C)

The terminal point's distance above the center of the circle can be calculated using the sine function:

[tex]\sin (2.9\text{rad})=0.2392493292\ldots[/tex]

Therefore, such distance is approximately 0.24 radii.

D)

Multiply the distance measured in radius length times the length of the radius to find the distance measured in cm:

[tex]0.24\times2.6\operatorname{cm}=0.62\operatorname{cm}[/tex]

Rafael is buying ice cream for a family reunion. The table shows the prices for different sizes of two brands of ice cream.

Answers

the correct answer is that the small size of the brand Cone dreams, because the price of each pint in it will be $2.125 =4.25/2, and if we calculate the price per pint with the other options it would be the minimum of all of them.

Assume that each circle shown below represents one unit. Express the sha amount as a single fraction and as a mixed number. One Fraction: Mixed Number:

Answers

The shaded portions for the first three circles are a total of 15 while for the fourth one is 1. As a fraction it is therefore,

[tex]\frac{16}{5}[/tex]

As mixed numbers it is;

[tex]3\frac{1}{5}[/tex]

In statistics, how do I find the p-value? I understand how to get the z-value. Please help! I am so confused. Thank you in advance!

Answers

SOLUTION:

Step 1:

In this question, we are meant to discuss the p-value.

1. The p-value is calculated using the sampling distribution of the test statistic under the null hypothesis, the sample data, and the type of test being done (lower-tailed test, upper-tailed test, or two-sided test).

2.

3. What is the p-value in statistics?

The p-value is a number, calculated from a statistical test, that describes how likely you are to have found a particular set of observations if the null hypothesis were true. P-values are used in hypothesis testing to help decide whether to reject the null hypothesis.

4. How do I know when the test is left-tailed, right-tailed, or two-tailed?

Left-tailed test: The critical region is in the extreme left region (tail) under the curve.

Right-tailed test: The critical region is in the extreme right region (tail) under the curve.

5. How do you know when to use a one - tailed or two - tailed test?

This is because a two-tailed test uses both the positive and negative tails of the distribution.

In other words, it tests for the possibility of positive or negative differences. A one-tailed test is appropriate if you only want to determine if there is a difference between groups in a specific direction.

6. The formulae that involves z-score:

7. The formulae that involves p -value and standard deviation:

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