Select initial allele frequencies
2Click Next generation to wait a year for first generation of moths
3Click Capture moths to monitor population numbers
4Calculate phenotype frequencies in 5th generation. Record in Lab Data
5Calculate allele frequencies in 5th generation. Record in Lab Data
6Calculate genotype frequencies and number of moths in 5th generation. Record in Lab Data

Select Initial Allele Frequencies2Click Next Generation To Wait A Year For First Generation Of Moths3Click

Answers

Answer 1

p₀=0.5, q₀ = 0.5.// p₅=0.86, q₅ = 0.14.// p₅² = 0.74, 2pq₅ = 0.24, q₅² = 0.02. // 1062 Black individuals DD, 344 Black, 29 White individuals dd.

Note: Due to technical problems, in the attached files you will find the complete explanation.

1) Phenotype frequencies

⇒ F(white) = 0.02  

⇒ F(black) ≅ 0.98    

2) Allele Frequencies

f₀(D) = p = 0.5

f₀(d) = q = 0.5

f₅(D) = p = 0.86

f₅(d) = q = 0.14

3) Genotypic Frequencies

F₅(DD) = p² ≅ 0.74

F₅(Dd) = 2pq = 0.24

F₅(dd) = q² ≅ 0.02    

4) Number of individuals

⇒ DD Black individuals → ≅ 1062

⇒ Dd Black individuals → ≅ 344

⇒ dd White individuals → ≅ 29

----------------------------------

You can learn more about Hardy-Weinberg equilibrium at

https://brainly.com/question/12724120


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Answer:

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Practical Truth

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Answer:

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A. additive genetic variance times the selection differential

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Answers

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