Review the table showing the population of a city.
What are the values of a, b, and c for a logistic
regression model y =c/1+ae^-bx
that represents this population?
a = 27.47, b = 3.26, and c = 0.30
a = 3.26, b=0.30, and c = 27.47
a = -0.09, b = 4.53, and c = 2.81
a= -0.09, b = 2.81, and c = 4.53

Answer:8:26

Step-by-step explanation:you subtract what time it is by 1:34 then take away 60 for a hour and add it to a hour so taking 60 mins gives you a hour

Answer: The graph is attached.

I suggest you use Desmos Graphing Calculator it helps me out so much!

Answer:

2

Step-by-step explanation:

Degree of the monomial is the highest power in the monomial.

Highest power in the monomial - 1.57k^2 is 2.

So, the degree of the monomial - 1.57k^2 is 2.

Answer:

$158,035.41 rounded to the nearest 10 dollars is $158,040

Step-by-step explanation:

Look to the next smallest place value, the digit to the right of the place value you're rounding to. For example, if you want to round to the nearest ten you'd look at the ones place. If the digit in the next smallest place value is less than five (0, 1, 2, 3, or 4), you leave the digit you want to round to as-is.

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Miss Hawaii

Answer:

(8x-3) (2x-5)

= 16x²-46x+15

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Answer:

803,800,000

Step-by-step explanation:

8.038 x 10^8

8.038 x 100,000,000

803,800,000

Hope you understand the answer. Have a great day!

Answer: if the x is negative the answer will be positive but if -10 is the only negative it would be negative. The way I remember is if their is a even amount of negatives is will be positive if theirs a odd amount it would be negative . Hope this helps :)

Step-by-step explanation:

Answer:

9375

Step-by-step explanation:

x=weekly cost

direct labor= 30/100*x

raw aterial= 2000+2*2000=6000

x=0.3x+6000+0.06x

x-0.36x=6000

0.64x=6000

64x=600000

x=9375

Simplify the expression:

7 + -10c² + 100

collect like terms:

7+100-10c²

107-10c²

If you meant, 7+ -10c² + 10c, then it can't be simplified further as there are no like terms.

Answer:

F, D, E

Step-by-step explanation:

the smallest angle is opposite the smallest side, the largest angle is opposite the largest side, etc.

Answer:

80 feet

Step-by-step explanation:

6 cm = 15 feet

1 cm = 5/2 feet

32 cm = 90 feet

The actual perimeter of the room is 90 feet.

A scale factor is defined as the ratio between the scale of a given original object and a new object,

We have,

The scale drawing of a rectangular room measures 10 cm long by 6 cm wide.

The actual width of the room is 15 feet.

This means,

6cm = 15 feet

1 cm = 15/6 feet

1 cm = 5/2 feet

Now,

The perimeter of the rectangular room.

= 2(10 + 6)

= 2 x 16

= 32 cm

1 cm = 5/2 feet

So,

32 cm = 32 x 5/2 feet

32 cm = 16 x 5 feet

32 cm = 90 feet

Thus,

The actual perimeter of the room is 90 feet.

Learn more about scale factors here:

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Answer:

26.7

Step-by-step explanation:

Use a  c a l c u l a t o r :P

Answer:

The range is the y-values that satisfices the graph.  0 to  all negative  numbers.

Step-by-step explanation:

The graph highest value is 0 on the y-axis and goes down ( any negative numbers).

Answer:

3102.12

Step-by-step explanation:

add the starting weight 788.52 plus the weight he gained 2.313.6

788.52 + 2.313.6 = 3102.12

58% должно быть вашим ответом

Answer:

58%

Step-by-step explanation:

вычтите исходный процент из 100, и вы получите еще один, и это абрикосы

Answer: 8lbs

Step-by-step explanation:

The baby gained one pound

Assuming linear growth, the baby would weigh approximately 8 lbs after 4 weeks.

Assuming linear growth, we can use the concept of a slope to estimate the baby's weight after 4 weeks.

Given information:

Weight at birth (0 weeks): 7 lbs

Weight after 20 weeks: 12 lbs

We can calculate the rate of change (slope) of the baby's weight per week:

Slope = (Change in weight) / (Change in weeks)

Slope = (12 lbs - 7 lbs) / (20 weeks - 0 weeks)

Slope = 5 lbs / 20 weeks

Slope = 0.25 lbs/week

Now, using the slope, we can estimate the baby's weight after 4 weeks:

Estimated weight change = Slope * Number of weeks

Estimated weight change = 0.25 lbs/week * 4 weeks

Estimated weight change = 1 lb

So, the baby's weight after 4 weeks would be the initial weight (7 lbs) plus the estimated weight change (1 lb):

Estimated weight after 4 weeks = Initial weight + Estimated weight change

Estimated weight after 4 weeks = 7 lbs + 1 lb

Estimated weight after 4 weeks = 8 lbs

Learn more about linear equation

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Answer:

You also have to pay attention to the signs when you multiply and divide. There are two simple rules to remember: When you multiply a negative number by a positive number then the product is always negative. When you multiply two negative numbers or two positive numbers then the product is always positive.

Step-by-step explanation:

Answer:

0.049

Step-by-step explanation:

17÷1=17

17÷12=1.42

1.42÷29=0.049

Answer:

There are 8 flowers.

Step-by-step explanation:

You have the 3 you filled in correct. Since there are 12 flowers, and we know that there are only two colors, once we know one color we can figure the other one out. We are told that there are 4 pink flowers. Since we know there are 4 pink flowers, we can do subtraction to find how many red flowers there are. 12-8=4. You begin with 12, then count back 4. 11, 10, 9, and then 8. This is how you find the answer. I hope this helps!

Answer:

Step-by-step explanation:

63 is the sum of 15 and Gail's score:

9514 1404 393

Answer:

Step-by-step explanation:

1. Successive y-values have neither a common difference nor a common ratio. The table is neither linear nor exponential.

__

2. Successive y-values differ by 4. The table is linear.

__

3. Successive y-values have a ratio of 3. The table is exponential.

_____

Additional comment

For evenly-spaced x-values, the y-values will have a common difference for a linear function, and a common ratio for an exponential function.

If the table can be represented by a polynomial function, the level at which differences are constant will tell the degree of the polynomial. First differences are constant for a degree 1 (linear) function. Second differences are constant for a degree 2 (quadratic) function. This is the case in Table 1, where second differences are 2.

Answer:

9990 is the right answer

Answer:

The solution is B. -1/8 - 1/4

Step-by-step explanation:

From the problem, we immediately know that the result of calculating the fraction is -3/8. We can find a way to get easily.

-1/8 - 1/4

= -1/8 - 2/8

= -3/8

Answer:

29 and 17

Step-by-step explanation:

Sum: 29 + 17 = 46

Difference: 29 - 17 = 12

Answer:

The answer is 17 and 29.

17+29=46.

29-17=12

Rewrite f(x) as a nested exponential-logarithm expression :

[tex]\left(\ln(3x)\right)^{2x} = \exp\left(\ln\left(\ln(3x)\right)^{2x}\right)[/tex]

(where [tex]\exp(x) = e^x[/tex])

One of the properties of logarithms lets us drop the exponent as a coefficient:

[tex]\exp\left(\ln\left(\ln(3x)\right)^{2x}\right) = \exp\left(2x\ln\left(\ln(3x)\right)\right)[/tex]

Now, by the chain rule, we have

[tex]f(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \implies \\\\ f'(x) = \left(\exp\left(2x\ln\left(\ln(3x)\right)\right)\right)' \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2x\ln\left(\ln(3x)\right)\right)'[/tex]

By the product rule,

[tex]f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(   (2x)' \ln\left(\ln(3x)\right) + 2x\left(\ln\left(\ln(3x)\right)\right)'   \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(   2\ln\left(\ln(3x)\right) + 2x\left(\ln\left(\ln(3x)\right)\right)'   \right)[/tex]

By the chain rule again,

[tex]f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + 2x \cdot \dfrac1{\ln(3x)} \cdot \left(\ln(3x)\right)'  \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2x}{\ln(3x)} \cdot \dfrac1{3x} \cdot (3x)' \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{3\ln(3x)} \cdot 3 \right) \\\\ f'(x) = \exp\left(2x\ln\left(\ln(3x)\right)\right) \cdot \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{\ln(3x)} \right)[/tex]

Then simplify this to

[tex]f'(x) = \boxed{\left(\ln(3x)\right)^{2x} \left(2\ln\left(\ln(3x)\right) + \dfrac{2}{\ln(3x)} \right)}[/tex]