Rank the circles from largest area to the smallest area Circle a has the diameter of 8 cm circle b has a radiusof 5 cm circle C has an area of 20 pi centimeters

In the incidence matrix, the element in row 1 column 5 is determined as 1.

The element in row 1 column 5 is calculated as follows;

In an incidence matrix, the rows represent the vertices of the graph, and the columns represent the edges.

Since vertex 1 and vertex 5 are adjacent to each other, the value of the element in row 1 column 5 will be 1, indicating that there is a connection between vertex 1 and vertex 5.

Had it been they are not adjacent, the element would have been 0. Since there will be no connection between them in the polygon.

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The Domain of the function would be the interval [0, 6].The increasing interval represents the point where the company is pricing the pens appropriately, resulting in increasing profit.Average rate of change = (f(5) - 120) / (5 - 3)

Part A:

The x-intercepts of the graph, located at the ordered pairs (0, 0) and (6, 0), represent the points where the profit function intersects the x-axis. In the context of the problem, these x-intercepts indicate the price values at which the company sells pens, resulting in zero profit. When the price is $0, the company does not make any profit, and when the price is $6, the company also does not make any profit. The x-intercepts represent the break-even points where the company covers its costs but does not generate any profit.

The maximum value of the graph, located at the vertex (3, 120), represents the peak profit achieved by the company. The vertex is the highest point on the graph and indicates the optimal price at which the company can maximize its profit. In this case, when the price of pens is $3, the company achieves a maximum profit of $120.

Regarding the intervals of increasing and decreasing profit, the function is decreasing to the left of the vertex (3, 120) and increasing to the right of the vertex. This means that for prices less than $3, the profit decreases, and for prices greater than $3, the profit increases. The decreasing interval represents the point where the company is pricing the pens too low, resulting in decreasing profit. The increasing interval represents the point where the company is pricing the pens appropriately, resulting in increasing profit.

Part B:

To find the approximate average rate of change of the graph from x = 3 to x = 5, we need to calculate the slope of the line segment connecting the two points. The average rate of change represents the average amount by which the profit changes per unit increase in price over the given interval.

Using the coordinates (3, 120) and (5, f(5)) on the graph, we can determine the change in profit and price:

Change in profit = f(5) - 120

Change in price = 5 - 3

Substituting the values of the points into the equation, we can calculate the approximate average rate of change:

Average rate of change = (f(5) - 120) / (5 - 3)

Part C:

The constraints of the domain refer to the limitations or restrictions on the values that x (the price of pens) can take. Based on the given information, the x-intercepts of the graph are at (0, 0) and (6, 0), indicating that the price cannot be negative or exceed $6. Therefore, the domain of the function would be the interval [0, 6]. The constraint is that the price of the pens must be within this range for the profit function to be applicable.

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Note the full question may be :

A bakery sells cupcakes for $2 each. The bakery's total revenue from selling cupcakes is given by the function R(x) = 2x, where x represents the number of cupcakes sold.

Part A: What does the x-intercept of the graph of R(x) represent? Explain its significance in the context of the bakery's revenue.

Part B: What is the slope of the graph of R(x)? Interpret the meaning of this slope in terms of the bakery's revenue and the price of cupcakes.

Part C: If the bakery wants to maximize its revenue, what should be the ideal number of cupcakes to sell? Explain your answer based on the graph of R(x).

Answer:

[tex](x - 3)^2 + (y + 2)^2 = 16[/tex]

Step-by-step explanation:

The equation of a circle with a center at (h, k) and radius r is given by:

[tex](x - h)^2 + (y - k)^2 = r^2[/tex]

We are given that the points G(5,-2) and H(1, −2) lie on the circle. We can use the distance formula to find the distance between these two points.

[tex]d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}[/tex]

[tex]d = \sqrt{(5 - 1)^2 + ((-2) - (-2))^2} = \sqrt{16} = 4[/tex]

Therefore, the radius of the circle is 4.

We can now find the center of the circle by taking the average of the x-coordinates and y-coordinates of the points G and H.

[tex](h, k) = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) = \left(\frac{5 + 1}{2}, \frac{-2 - 2}{2}\right) = (3, -2)[/tex]

Therefore, the equation of the circle is:

[tex](x - 3)^2 + (y + 2)^2 = 4^2[/tex]

Simplifying the equation, we get:

[tex]\bold{(x - 3)^2 + (y + 2)^2 = 16}[/tex] is a required equation.

Answer: A = 83.75

Step-by-step explanation:

A=a+b

2h=12.5+21

2·5=83.75

x+77=180

x=180-77=103°

x+5y-98=180

=> 103+5y-98=180

=> 5y=180-5

=> y=175/5=35°

Part A: equate the expressions 6x - 8 = 3x - 5

collect the like terms 6x -3x = -5 + 8

Divide by the coefficient x = 1

Part B: The values are (1, -3)

To determine the value of the variables,  we need to consider the equations.

From the information given, we have the equations given as;

y = 3x − 5

y = 6x − 8

Now, equate the expressions, we get;

6x - 8 = 3x - 5

collect the like terms, we have;

6x - 3x = -5 + 8

add or subtract the like terms

3x = 3

Divide by the coefficient

x = 1

Substitute the value

y= 6(1) - 9

expand the bracket

y = 6 - 9 = -3

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Answer:

4.816

Step-by-step explanation:

5.66sin45 = 4.816
sin = opposite over hypotenuse

Answer: 36

Step-by-step explanation: 3y by 56

The area of the kite is 38 mm squared.

A kite is a quadrilateral with two pairs of adjacent sides equal. The diagonals of a kite are perpendicular. The vertex angle are bisected by the diagonals.

It has two pairs of consecutive equal sides and perpendicular diagonals.

Therefore,

area of a kite = ab / 2

where

Therefore,

a = 9.5 mm

b = 4 mm

Therefore,

area of a kite = 9.5 × 4 / 2

area of a kite = 38 / 2

area of a kite = 19 mm²

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Answer:

The area of the kite would be 19 mm².

Step-by-step explanation:

A kite is a quadrilateral with two pairs of equal-length adjacent sides. The diagonals of a kite are perpendicular to each other and intersect at a right angle, dividing the kite into four right triangles. The area of a kite can be calculated by finding the product of the lengths of its diagonals and dividing it by 2.

If we assume that the height and width you provided are the lengths of the diagonals, we can calculate the area using the following formula:

Area = (height * width) / 2

Substituting the given values:

Area = (9.5 mm * 4 mm) / 2

= 38 mm² / 2

= 19 mm²

Therefore, if the height and width represent the lengths of the diagonals, the area of the kite would be 19 square millimeters.

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Answer:

3.999 millimeters.

Step-by-step explanation:

To find the height of the cylinder, we can use the formula for the volume of a cylinder:

V = πr²h

Given that the radius (r) of the cylinder is 4 millimeters and the volume (V) is 200.96 cubic millimeters, we can substitute these values into the formula and solve for the height (h).

200.96 = π(4²)h

200.96 = 16πh

To solve for h, we can divide both sides of the equation by 16π:

200.96 / (16π) = h

Using a calculator, we can calculate the approximate value of h:

h ≈ 200.96 / (16 × 3.14159)

h ≈ 3.999

Therefore, the height of the cylinder is approximately 3.999 millimeters.

Using the slope-intercept form, the equation of the lines are

a. 2y = x + 9

b. 3y = x + 1

c. y = x - 6

d. y = x + 10

e. y = -1/2x + 1

In the given question, we have the coordinate of a point and the slope of the line.

To determine the equation of the straight line, we have to use the formula of slope-intercept which is given as; y = mx + c.

Plugging the values into the formula.

a. (3, 6) and slope = 1/2

equation of line = y = mx + c = 6 = 1/2(3) + c

6 = 3/2 + c

c = 9/2

The equation of line is y = 1/2x + 9/2 ; 2y = x + 9

b. The point is (2,1) and slope is 1/3

Equation of line is;

y = mx + c

1 = 1/3(2) + c

c = 1 - 2/3

c = 1/3

Equation of line is y = 1/3x + 1/3; 3y = x + 1

c. The point is (4, -2) and slope is 1

y = mx + c

-2 = 1(4) + c

c = -2 - 4 = -6

y = x - 6

d. The point is (-2, 8) and slope is 1

y = mx + c

8 = 1(-2) + c

c = 10

y = x + 10

e. The point is (-4, 3) and slope is -1/2

y = mx + c

3 = -1/2(-4) + c

3 = 2 + c

c = 1

y = -1/2x + 1

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There is 90% confidence that the population standard deviation is between 5.094 weeks and 19.803 weeks.

The correct option is C.

To construct a confidence interval for the population standard deviation, we can use the chi-square distribution.

Given data:

Sample size (n) = 12

Sample standard deviation (s) = 9.904 weeks

The chi-square distribution is right-tailed and at 90% confidence level, the significance level is 0.1 on each tail.

Degrees of freedom (df) = n - 1

Degrees of freedom (df) = 12 - 1

Degrees of freedom (df) = 11

From the chi-square distribution table, the critical values for a 90% confidence level with 11 degrees of freedom are 3.816 and 22.362.

Therefore, the 90% confidence interval for the population standard deviation is:

Lower bound = √(n-1) * s² / χ² upper)

Lower bound = √(11 * 9.904²) / 22.362)

Lower bound = 5.094

Upper bound = √(n-1) * s² / χ² lower)

Upper bound = √(11 * 9.904²) / 3.816)

Upper bound = 19.803

Therefore, there is 90% confidence that the population standard deviation of the age at which babies first crawl is between approximately 5.094 weeks and 19.803 weeks.

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A. A system of equations in standard form that can be solved to find the number of adults and children who attended the performance is:

x + y = 282

3x + 5y = 1046

B. The number of adults who attended the performance is 182 adults.

The number of children who attended the performance is 100 children.

In order to write a system of linear equations to describe this situation, we would assign variables to the number of adult tickets sold and number of children tickets sold, and then translate the word problem into an algebraic equation as follows:

Since 282 people attended the recent performance by Cinderella, a linear equation that models the situation is given by:

x + y = 282     ....equation 1.

Additionally, adult tickets sold for $5 while children tickets sold for $3 each with a total revenue was $1046, a linear equation that models the situation is given by:

3x + 5y = 1046   .......equation 2.

Part B.

By multiplying equation 1 by 3, we have:

3x + 3y = 846     .......equation 3.

By subtracting equation 3 from equation 2, we have:

2y = 200

y = 100 children.

For the x-value, we have:

x = 282 - y

x = 282 - 100

x = 182 adults.

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Answer:

[tex]\textsf{B)} \quad f(x) = 5 \sin (16x) + 7}[/tex]

Step-by-step explanation:

The sine function is periodic, meaning it repeats forever.

[tex]\boxed{f(x) = A \sin (B(x + C)) + D}[/tex]

where:

Given values:

Calculate the value of B:

[tex]\dfrac{2\pi}{B}=\dfrac{\pi}{8}\implies 16\pi=B\pi\implies B=16[/tex]

Substitute the values of A, B C and D into the standard formula:

[tex]f(x) = 5 \sin (16(x + 0)) + 7[/tex]

[tex]f(x) = 5 \sin (16x) + 7[/tex]

Therefore, the sine function with an amplitude of 5, a period of π/8, and a midline at y = 7 is:

[tex]\Large\boxed{\boxed{f(x) = 5 \sin (16x) + 7}}[/tex]

Answer: There are 16 fluid ounces in 1 pint. To determine the number of pints in the jug, we need to divide the total number of fluid ounces by 16.

Given that the jug contains 36 fluid ounces of apple juice, we divide 36 by 16:

36 fluid ounces ÷ 16 fluid ounces/pint = 2.25 pints

Therefore, the jug contains 2.25 pints of apple juice.

Answer: The figure you are describing seems to be a rectangle with a length of 6 yards and a width of 4 yards. The area of a rectangle is calculated by multiplying its length by its width. So, the area of this rectangle would be 6 yd * 4 yd = 24 square yards.

Answer: Total Area = 36yd

Step-by-step explanation:

You have to find the area of both square and triangle.

Area Triangle = .5x5x8= 20yd
Area Square = 4x4 = 16yd

Triangle + Square - 20yd+16yd = 36yd

Answer:

Is 03.841

Step-by-step explanation:

To find the critical value needed to test the claim that the sentence is independent of the plea, we need to perform a chi-square test of independence. The critical value is based on the significance level (α) and the degrees of freedom.

In this case, the given significance level is 0.05. Since the table represents a 2x2 contingency table (two categories for plea and two categories for sentence), the degrees of freedom (df) can be calculated as (number of rows - 1) * (number of columns - 1) = (2 - 1) * (2 - 1) = 1.

To find the critical value at a significance level of 0.05 with 1 degree of freedom, we consult a chi-square distribution table or use statistical software.

The critical value for a chi-square test with 1 degree of freedom and a significance level of 0.05 is approximately 3.841.

Therefore, the correct answer is 03.841.

3666042 to the nearest hundred thousand is 3,700,000

The solution to the given simultaneous equations using Cramer's rule is x = -1, y = -4.92, z = -1.03.

To solve the given simultaneous equations using Cramer's rule, we need to find the determinants of various matrices.

Given the set of equation:

3x-3y+ 5z = 5

9x - 8y + 13z = 14

-3x+4y- 7z=-7

We start by finding the determinant of the coefficient matrix, which is denoted as D.

D = [tex]\left[\begin{array}{ccc}3&-3&5\\9&-8&13\\-3&4&-7\end{array}\right][/tex]

To calculate D, we use the formula:

D = (3 * (-8) * (-7) + (-3) * 13 * (-3) + 5 * 9 * 4) - ((-3) * (-8) * 5 + 3 * 13 * 4 + (-3) * 9 * (-7))

D = (-168 + 117 + 180) - (120 - 156 + 189)

D = 129 - 165

D = -36

Next, we need to find the determinants of the matrices obtained by replacing the columns of the coefficient matrix with the constant terms. These determinants are denoted as Dx, Dy, and Dz, respectively.

Dx = [tex]\left[\begin{array}{ccc}5&-3&5\\14&-8&13\\-7&4&-7\end{array}\right][/tex]

Dx = (-40 - 65 + 20) - (-70 - 60 + 189) = -85 - (-121) = -85 + 121

Dx= 36

Dy = [tex]\left[\begin{array}{ccc}3&5&5\\9&14&13\\-3&-7&-7\end{array}\right][/tex]

Dy = (21 + 75 + 35) - (-21 - 130 + 105) = 131 - (-46) = 131 + 46

Dy = 177

Dz = [tex]\left[\begin{array}{ccc}3&-3&5\\9&-8&14\\-3&4&-7\end{array}\right][/tex]

Dz = (39 - 39 + 0) - (-27 + 84 + 20) = 0 - (-37) = 0 + 37

Dz = 37

Finally, we can find the values of x, y, and z using the formulas:

x = Dx / D

y = Dy / D

z = Dz / D

Plugging in the values, we have:

x = 36 / -36 = -1

y = 177 / -36 ≈ -4.92

z = 37 / -36 ≈ -1.03

Therefore, the solution to the given simultaneous equations using Cramer's rule is x = -1, y ≈ -4.92, z ≈ -1.03.

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Answer:

A: The diameter is 6in.

B: The radius is 3in.

C: The diameter is given to us in the problem. A line is drawn out that strikes through the center point. of the circle, and it is labeled 6in in the middle, so we can deduce that it is the diameter. The radius of a circle is 1/2 the length of the diameter, so 6/2 = 3in. If the 6in was on either side of the line, then that would be labeling the radius.

The statements that are true regarding the expression with the exponents -1, -3, and 1 are;

An exponent is a quantity or power to which a value, expression or number is to be raised.

The specified expression can be presented as follows;

8⁻¹ × 8⁻³ × 8

Therefore; 8⁻¹ × 8⁻³ × 8 = 8⁽⁻¹ ⁺ ⁻³ ⁺ ¹⁾ = 8⁻³ = 1/8³

1/8³ = 1/512

Similarly, we get; 8⁷ × 8⁻¹⁰ = 8⁽⁷ ⁻ ¹⁰⁾ = 8⁻³ = 1/8³

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A surveyor wants to determine the width of a river is 43.34 m.

From given figure, angle ACB = angle ECD  (Vertically opposite angles are equal)

Angle BAC = Angle EDC = 90

So, triangle ABC and triangle ECD are similar.

AB/DE = AC/CD

AB/18.6 = 79.6/34.2

AB/18.6 = 2.33

AB = 2.33×18.6

AB = 43.34 m

Therefore, a surveyor wants to determine the width of a river is 43.34 m.

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The error in the problem is given by the equation in step(3). and the value is given by g ( x ) = 2x² + 4x - 4

Given data ,

Let the equation be represented as g ( x )

Now , the value of g ( x ) is

g ( x ) = 2 ( x + 1 )² - 6

On simplifying the equation , we get

From the distributive law of multiplication , we get

g ( x ) = 2 ( x + 1 ) ( x + 1 ) - 6

g ( x ) = 2 ( x² + 2x + 1 ) - 6

On further simplification , we get

g ( x ) = 2x² + 4x + 2 - 6

g ( x ) = 2x² + 4x - 4

Therefore, the value of g ( x ) is g ( x ) = 2x² + 4x - 4

Hence , the equation is g ( x ) = 2x² + 4x - 4

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The solution of the given expression is,

x = 1/2.

The given expression is,

[tex]36^{3x} = 216[/tex]

Since we know that,

As the name indicates, exponents are utilized in the exponential function. An exponential function, on the other hand, has a constant as its base and a variable as its exponent, but not the other way around (if a function has a variable as its base and a constant as its exponent, it is a power function, not an exponential function).

Now we can write it as,

⇒ [tex]6^{2^{3x}} = 6^3[/tex]

⇒  [tex]6^{6x}} = 6^3[/tex]

Now equating the exponents we get,

⇒ 6x = 3

⇒   x = 3/6

⇒   x = 1/2

Hence,

Solution is, x = 1/2.

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The limits for the 95% confidence interval are given as follows:

A confidence interval of proportions has the bounds given by the rule presented as follows:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which the variables used to calculated these bounds are listed as follows:

The confidence level is of 95%, hence the critical value z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.

The parameters for this problem are given as follows:

[tex]n = 225, \pi = \frac{159}{225} = 0.7067[/tex]

Then the lower bound of the interval is given as follows:

[tex]0.7067 - 1.96\sqrt{\frac{0.7067(0.2933)}{225}} = 0.65[/tex]

The upper bound of the interval is given as follows:

[tex]0.7067 + 1.96\sqrt{\frac{0.7067(0.2933)}{225}} = 0,77[/tex]

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The probability of not rolling factors of 5 on both dice is 25/36

From the question, we have the following parameters that can be used in our computation:

Rolling two number cubes

Using the above as a guide, we have the following:

Sample space,  S = {1, 2, 3, 4, 5, 6}

In the above sample space, we have

Not factors of 5 = {1, 2, 3, 4, 6}

So, we have

P(Not rolling factor of 5) = 5/6 * 5/6

Evaluate

P(Not rolling factor of 5) = 25/36

Hence, the probability is 25/36

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Question

Two six sided dice are rolled.

Find the probability of not rolling factors of 5 on both dice

The probability that the next customer will pay with something other than cash, rounded to the nearest Whole number, is approximately 12%.

The probability that the next customer will pay with something other than cash, we need to consider the total number of customers who paid with something other than cash and divide it by the total number of customers in the last week.

In the given information, it is stated that 69 customers paid with cash, 2 customers used a debit card, and 7 customers used a credit card. To find the total number of customers who paid with something other than cash, we add the number of customers who used a debit card and the number of customers who used a credit card:

Total number of customers who paid with something other than cash = Number of customers who used a debit card + Number of customers who used a credit card

= 2 + 7

= 9

Now, to calculate the probability, we divide the number of customers who paid with something other than cash by the total number of customers:

Probability = Number of customers who paid with something other than cash / Total number of customers

= 9 / (69 + 2 + 7)

= 9 / 78

= 0.1154 (rounded to four decimal places)

To express the probability as a percentage, we multiply the probability by 100:

Probability as a percent = 0.1154 * 100

≈ 11.54

Therefore, the probability that the next customer will pay with something other than cash, rounded to the nearest whole number, is approximately 12%.

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[tex] \begin{aligned}3 ^{3k} &= \frac{1}{81} \\3^{3k} &= \frac{1}{3^{4} } \\ 3^{ \blue{3k}} &= 3^{ - \blue{4}} \\ 3k&= - 4 \\ k&= \frac{ - 4}{3} \\ k&= \bold{ - \frac{4}{3} } \end{aligned}[/tex]

[tex]\rm{The\:value\:of\:\mathit{k}\:is\:\bold{ - \frac{4}{3}}} \\ \\ \small{ \blue{ \mathfrak{That's\:it\: :)}}}[/tex]

Answer: Let's try x = 1 as a potential solution:

Substituting x = 1 into the inequality:

3(1) - 7 ≥ -10

3 - 7 ≥ -10

-4 ≥ -10

Since -4 is greater than or equal to -10, x = 1 is a solution to the inequality.

Let's try x = -3 as a potential solution:

Substituting x = -3 into the inequality:

3(-3) - 7 ≥ -10

-9 - 7 ≥ -10

-16 ≥ -10

Since -16 is not greater than or equal to -10, x = -3 is not a solution to the inequality.

Therefore, x = 1 is a solution to the inequality 3x - 7 ≥ -10, while x = -3 is not a solution.

Step-by-step explanation:

Answer:

-----------------

Given a right triangle with two legs known.

Find the missing angle using tangent function:

Substitute values to get: