Answer:
The rule for this question should be an=10*(-3)^(n-1)
Step-by-step explanation:
Because 10, -30, 90, and -270 divide (for example -30/10, 90/-30 and -270/90 which means the ratio equals -3) To find the ratio, you must divide by its previous term.
Then, the equation for the ratio would be a1 (first term in the sequence) multiplied by the ratio, then to the power of the number subtracted by 1. an=a1*r^(n-1) This is the formula to find the nth term of a geometric sequence.
Hope this helped!
hello evryone. please help if you know the answer. donr help if u dont know the answer. ill give brailest to the first person that answers
a WHOLE is always simplified to "1", namely 100/100 = 1, 57/57 = 1 and so on. Well, in this case we have a total of 21 students, so 21/21 is all of them, their "whole", but we also know that 6 of them read about animals and the rest about plants, so
[tex]\stackrel{whole}{\cfrac{21}{21}}\qquad \qquad \cfrac{\stackrel{animals}{6}~~ + ~~\stackrel{plants}{15}}{21}\implies \cfrac{6}{21}~~ + ~~\stackrel{plants}{\cfrac{15}{21}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{15}{21}\implies \cfrac{3\cdot 5}{3\cdot 7}\implies \cfrac{3}{3}\cdot \cfrac{5}{7}\implies 1\cdot \cfrac{5}{7}\implies \boxed{\cfrac{5}{7}}[/tex]
Answer:
I think its 5 over 7
Step-by-step explanation:
because 6-21 equals 15 so 15 is how many read about plants out of the total students at the library which is 21.if you divide 15 over 21 by 3 you get 5 over 7
Shane found a website that gives the daily weather report from mars. for 4 days, shane recorded the daily high and low temperatures on mars.use the dropdowns to complete each statement. table of daily high and low temperatures in degrees celsius. on day 1, the low was negative eighty-two; the high was negative twenty-four. on day 2, the low was negative eighty-three; the high was negative twenty-six. on day 3, the low was negative eighty-four; the high was negative twenty-seven. on day 4, the low was negative eighty-four; the high was negative twenty-eight.a. the average temperature on day 2 was blank.b. the difference of the average high temperature and the average low temperature for all four days is blank.c. the day with the greatest average temperature was blank.
The average temperature on day 2 was -54.5.
What is Average?This is usually calculated with the sum of the numbers divided by how many numbers are present.
The average temperature on day 2 = -83-26 /2 = -54.5The difference of the average high temperature and the average low temperature for all four days include the following:Day one = -82-(-24) = -58
Day two = -83-(-26) = -57
Day three = -84-(-27) = -57
Day four = -84-(-28) = -56
The day with the greatest average temperature was Day one = -82-24/2 = -53.
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Answer:
Step-by-step explanation:
Use the graphing calculator to graph the quadratic function y = x2 − 5x − 36. Which value is a solution of 0 = x2 − 5x − 36?
−9
−4
4
6
Answer: -4
Step-by-step explanation:
Once you graph it, the solutions are where the graph meets the x axis.
This is at -4 and 9.
Chloe has taken four tests this semester. Her scores on the three tests are 87, 78, and 61. If her test average is 78.5, what is her grade on her 4th test?
n = last test
(87 + 78 + 61 + n) : 4 = 78,5
87 + 78 + 61 + n = 78,5 x 4
n = 314 - 226
n = 88
How much, in total, did Noel spend to cash her three most recent paychecks?
The total amount of money that was spent by Noel to cash her three (3) most recent paychecks is equal to $10.99.
What is a paycheck?A paycheck can be defined as a financial document that is issued by an employer to an employee as payment for the work done over a period of time.
How to calculate the amount spent.From the table, we can see that the amount of money charged by the bank as check processing fee is equal to $1.99, as well as 1.99% (0.0199) of the amount being cashed by a customer.
Thus, we would compute the amount of money spent by Noel as follows:
Noel = (0.0199 × 100.53) + (0.0199 × 119.38) + (0.0199 × 122.52) + (1.39 × 3)
Noel = 2.00 + 2.38 + 2.44 + 4.17
Noel = $10.99.
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PLEASE HELP MEEEEE PLEASE ASAP
Suppose that 25 inches of wire costs 75 cents.
At the same rate, how much (in cents) will 21 inches of wire cost?
Answer:
73 cents
Step-by-step explanation:
first multiply 75×21 and you will get 1575 then divide 1575 by 25 and you get 73 which is 73 cents
Twelve people apply for a teaching position in mathematics at a local college. Six have a PhD and six have a master’s degree. If the department chairperson selects three applicants at random for an interview, find the probability that all three have a PhD
Using the hypergeometic distribution, it is found that there is a 0.0175 = 1.75% probability that all three have a PhD.
The applicants are chosen without replacement, hence the hypergeometric distribution is used to solve this question.
What is the hypergeometric distribution formula?The formula is:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.N is the size of the population.n is the size of the sample.k is the total number of desired outcomes.In this problem, the values of the parameters are as follows: N = 20, k = 6, n = 3.
The probability that all three have a PhD is P(X = 3), hence:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = 3) = h(3,20,3,6) = \frac{C_{6,3}C_{14,0}}{C_{20,3}} = 0.0175[/tex]
0.0175 = 1.75% probability that all three have a PhD.
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For what value of x does 3^4x=27^x-3?
0 -9
O-3
O 3
O 9
Answer:
the answer to the value of X is 0-3
Find the missing coordinate.
x = cos t
y = sin t
(-1, [?])
The vertices of a quadrilateral drawn in a coordinate plane are (-6,6), (4,6), (2,-5), and (-6,-9). what is the length of the side joining the vertex in quadrant i to the vertex in quadrant 11? a) 2 b) 8 c) 10 d) 12
Using the formula for the distance between two points, it is found that the length of the side joining the vertex in quadrant i to the vertex in quadrant ii is given by:
c) 10
What is the distance between two points?Suppose that we have two points, [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex]. The distance between them is given by:
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
In quadrant I, both coordinates are positive, hence the vertex is (4,6). In quadrant II, x is negative while y is positive, hence the vertex is (-6,6). Thus, the distance is given by:
[tex]D = \sqrt{(-6 - 4)^2+(6 - 6)^2} = 10[/tex]
Which means that option C is correct.
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Given that lines b and c are parallel, select all that apply.
Which pairs of angles are congruent?
3 and 7
2 and 8
3 and 5
1 and 4
Answer:
3 and 7
1 and 4
Step-by-step explanation:
[3 and 7]
These two angles are prooved congruent by corresponding angles
[1 and 4]
These two angles are prooved congruent by opposite vertical angles.
This composite figure is created by placing a sector of a circle on a rectangle. What is the area of this composite figure? Show your work.
Answer:
area of the figure: 29.92 m²
formula's:
area of rectangle: length * widtharea of sector: ∅/360 * πr²solving steps:
area of rectangle + area of sector
5.5 * 4 + 30/360 * π(5.5)²
22 + 7.919
29.92 m²
Answer:
Calculate the area of the sector and the area of the rectangle separately, then add them together to determine the area of the composite figure.
Rectangle
Area of a rectangle = width × length
= 4 × 5.5
= 22 m²
Sector
[tex]\textsf{area of sector}=\dfrac{\theta\pi r^2}{360} \textsf{ (when } \theta \textsf{ is measured in degrees)}[/tex]
[tex]=\dfrac{30 \cdot\pi\cdot5.5^2}{360}[/tex]
[tex]=\dfrac{121}{48}\pi \textsf{ m}^2[/tex]
Total area
total area = area of rectangle + area of sector
[tex]=22 +\dfrac{121}{48}\pi[/tex]
= 29.91943148...
= 29.9 m² (nearest tenth)
If Sam has 120 dollars to spent what will he use it on, 20 apples that cost $6 or 50 pears that cost $3 dollars
Answer:
50 pears = 3 dollars
Step-by-step explanation:
he would want to save as much as possible
Consider the system and find the eigenvalues and the eigenvectors
Eigenvalues are the special set of scalar values which is associated with the set of linear equations in matrix equations.
What are Eigenvalues?
Your information is incomplete. Therefore, an overview will be given. An eigenvector of a linear transformation is a nonzero vector that changes by a scalar factor when the linear transformation is applied to it.
The eigenvectors of matrix A are those vectors X for which multiplication by A will result in a vector in thesame direction or opposite direction to X.
Since the zero vector 0 has no direction, 0 is never allowed to be an eigenvector.
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An eigenvector of a linear transformation and eigenvectors of a system
Ax = Bx can be determined where B is an eigenvalue of A.
What are Eigenvalues?An eigenvector of a linear transformation is a nonzero vector that changes by a scalar factor when the linear transformation is applied to it.
The eigenvectors of matrix A are those vectors X for which multiplication by A will result in a vector in the same direction or opposite direction to X.
The basic equation is
Ax = Bx
here B is an eigenvalue of A.
Since the zero vector has no direction, zero is never allowed to be an eigenvector.
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#SPJ4
I need help with this
Answer:
You are correct with B!!
Step-by-step explanation:
(x⁹)²
We have to multiply 9 x 2, regardless of the parenthesis for this one.
9 × 2 is 18.
We cannot simply 18 further.
Carry the x in front of 18.
x¹⁸
I went to the store with $20. After buying all my groceries, I spent $15.87. How much money do I have left?
you would have 4.13 left
20-15.87=4.13
Answer:
The answer is $4.13
Step-by-step explanation:
It is easier to do this if we add two zeros at the end of 20 to make it 20.00 so the decimal places line up. Lets take it one place at a time. first is the hundreths, which is 0-7. This is not possible, so we borrow from the tenths, but the tenths is also a zero. The tenths zero has to borrow from the ones zero. Basically, the 2 in 20 becomes 1, and the zeros in the ones and tenths place become nines, and the last zero becomes 10. 10 minus 7 is 3, 9 minus 8 is 1, 9-5 is 4, and 1-1 is 0.
Hope this helps!
Rewrite each expression below using the Distributive Property :
a. 5 (2x + 1)
b. 34 (x - 1)
c. 9 (x + 3)
what is the square root of 6
A triangle has two sides of length 4 and 2. What is the smallest possible whole-number length for the third side?
Answer:
19
Step-by-step explanation:
**WILL GIVE BRAINLIEST** please help me
Answer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWERAnswer:
SORRY
Step-by-step explanation:
ANSWER
X 12. Find the volume of the composite solid. Use 3.14 for . 5.5 ft Find the volume of the cone using the formula.
Answer: 74.61 ft^3
Step-by-step explanation:
Given f(x) = 3x2 + kx – 7, and the remainder when f (x) is divided by x – 4 is
81, then what is the value of k?
Answer:
-243
Step-by-step explanation:
{3׳ykx-7 incluye
(За + 2b) (2а — b) HELP ME PLEASE
Answer:
6a^2 + ab - 2b^2
Step-by-step explanation:
[insert something smart]
what is the value of the expression (-2) to the third power (-2) to the second power
Answer:
-2 to the third power is -8
-2 to the second power is -4
Step-by-step explanation:
-2 to the 3 power = -2× -2×-2
-2 to the second power is -2×-2
I have to finish this before next week because of grades please thanks
Answer:
D
Step-by-step explanation:
What is the x to help me
Answer:
116 degrees
Step-by-step explanation:
the shape is 360 degrees in total
64+64 = 128
360-128 = 232
232/2 = 116
Which lines are parallel?
red and green
they go in the same direction, side by side, and will never touch
if log7=a and log…
help me solve ths math problem on picture
[tex]\qquad\qquad\huge\underline{\boxed{\sf Answer☂}}[/tex]
Let's solve ~
[tex]\qquad \sf \dashrightarrow \: log_{4}(39.2) [/tex]
[tex]\qquad \sf \dashrightarrow \: log_{4}( {2}^{3} \times {7}^{2} \times 10 {}^{ - 1} ) [/tex]
[tex]\qquad \sf \dashrightarrow \: log_{4}( {2}^{3} ) + log_{4}( {7}^{2} ) + log_{4}(10 {}^{ - 1} ) [/tex]
[tex]\qquad \sf \dashrightarrow \: log_{ {2}^{2} }( {2}^{3} ) + log_{ {2}^{2} }( {7}^{2} ) + log_{ {2}^{2} }(10 {}^{ - 1} ) [/tex]
[tex]\qquad \sf \dashrightarrow \: \frac{3}{2} log_{2}(2) + \frac{2}{2} log_{2}(7) - \frac{1}{2} log_{2}(10) [/tex]
[tex]\qquad \sf \dashrightarrow \: \frac{3}{2} + a - \frac{b}{2} [/tex]
That's the required result ~
also you can take it's LCM and write it as :
[tex]\qquad \sf \dashrightarrow \: \dfrac{2a - b + 3}{2} [/tex]
let f(x)=3x+4 and g(x)=2x-5 find (f-g)(x)
Step-by-step explanation:
find; (f-g)(x)
(f(x) - g(x))
f(x) = 3x + 4, g(x) = 2x - 5
3x + 4 - 2x + 5
x +9