Answer:
I'm pretty sure its radiation and reflection. Some of the Sun's energy gets reflected off into space. (I could be wrong though)
Answer:
radiation and reflection
hope helps you
have a nice day
Explanation:
hope this will surely be helpful to you
Which statement best describes covalent bonding?
A. Two nonmetal atoms share electrons between them.
B. Two metal atoms share electrons between them.
C. Many atoms give up electrons that can move among the atoms.
D. A metal atom transfers electrons to a nonmetal atom.
Answer:
A. Two nonmetal atoms share electrons between them
General Formulas and Concepts:
Chem
Covalent Bonding: between 2 nonmetalsIonic Bonding: between a metal and a nonmetalMetallic Bonding: between 2 metalsExplanation:
Covalent bonds are the ones between 2 nonmetal elements. Covalent bonding has 2 subcategories: Nonpolar Covalent and Polar Covalent.
Convert 7.5 g/cm3 to kg/m3
Answer:
7500
Explanation:
multiply the mass / volume value by 1000
what do electrons move from
Answer:
Negatively charged, to positively charged parts
Explanation:
Electrons are negative, negative is attracted to positive.
As the ball rolls down the ramp, there are changes in kinetic and potential energy. How much kinetic energy does the
ball have when it reaches point B?
A) 0J
B) 25J
C) 50J
D)100J
The answer is C, 50J
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How does Health & Physical Education relate to any other subject you now study in
school?
Answer:
Health relates to science because
in science you study, research, and knowledge in this case, health science, which helps you under stand more about how humans and animals function. And Physical education relates to science because , you study the way of human movement, think of push-ups as a example.
I hope I helped U ´꓃ ` U
I need help and I don't understand if you can help me but let it be before 6:00
Answer:
balanced: a train moving at a constant speed, the moon orbiting the earth at a constant speed, a lamp sitting on a desk, an apple hanging on a tree
unbalanced: a skier coming down a mountain, a car accelerating from the start line, a soccer ball after it was kicked, a parachuter falling to ground
Explanation:
all the balanced ones are either moving at a constant speed or are skill
all the unbalanced ones were disturbed by some sort of force causing them to accelerate, go faster, blah blah blah
During a race, a sprinter increases from 5.0 m/s to 7.5 m/s over a period of 1.25s. What is the sprinter’s average acceleration during this period?
Answer:
[tex]\boxed {\boxed {\sf 2 \ m/s^2}}[/tex]
Explanation:
Acceleration can be found by dividing the change in velocity by the time.
[tex]a=\frac{\Delta v}{t}[/tex]
The time is 1.25 seconds. The change in velocity is the difference between the initial velocity and the final velocity.
[tex]\Delta v=v_f-v_i[/tex] The final velocity is 7.5 m/s and the initial velocity is 5.0 m/s[tex]\Delta v =7.5 \ m/s-5.0 \ m/s=2.5 \ m/s[/tex][tex]\Delta v= 2.5 \ m/s\\t=1.25 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{2.5 \ m/s}{1.25 \ s}[/tex]
Divide.
[tex]a=2 \ m/s^2[/tex]
The sprinter's average acceleration is 2 meters per second squared.
Answer: 2 m/s^2
Explanation: Hope this helps :)
plz help, and no silly answers cuz i will report you
How much force (newtons) is required to accelerate a 2.55 kg remote-controlled toy car at a rate of 6.00 m/s2
Answer:
15.3 N
Explanation:
Force = mass x acceleration
= 2.55 kg x 6.00 m/s^2
= 15.3 kgm/s^2 = 15.3 N
The required force to accelerate a 2.55 kg remote-controlled toy car at a rate of 6.00 m/s^2 be 15.3 N.
What is force?The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.
Given parameters:
Mass of the remote-controlled toy car : m = 2.55 kg.
Acceleration of the remote-controlled toy car :a = 6.00 m/s^2
Now according to Newton's 2nd law of motion,
Force = mass x acceleration
= 2.55 kg x 6.00 m/s^2
= 15.3 kgm/s^2
= 15.3 N
Hence, required force is 15.3 N.
Learn more about force here:
https://brainly.com/question/13191643
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A student wishes to conduct an investigation on heat transfer that demonstrates convection, Which
method should the student use?
A.
Pour hot, colored water into a bowl of cooler water that is another color,
B.
Melt chocolate bars in a microwave at different settings,
C.
Leave a glass of ice water outside in the direct sunshine.
D.
Place a spoon that is room temperature on top of a hot burner on a stove,
which other element is most likely to be a non-reactive gas
A. Na, number 11
B. F, number 9
C. Cs, number 55
D. Xe, number 54
Answer:
C
Explanation:
Tap the point on this graph where the ball has the greatest Kinetic Energy if it were to move from Point A to G. Target Image
I don't understand the question
Answer:
As the ball falls from C to E, potential energy is converted to kinetic energy. The velocity of the ball increases as it falls, which means that the ball attains its greatest velocity, and thus its greatest kinetic energy, at E. 19.
Explanation:
A metal ball has a mass of 2.05 kg and a volume of 6.8 cm. What is its density? Remember
Answer:
the density is 0.301 :)
the value of g is greater at the poles than at the equator why
Answer:
because the gravitational pull is maximum at the poles and decreases as it comes down toward the equator.
Calcula la fuerza magnética de una carga que se desplaza hacia la derecha con una velocidad de 5 X 10 a la 6 metros sobre segundo. Que forma un campo magnético de 0.8 Teslas. Recuerda que la carga de un electrón es de 1.602 X 10 a la menos 19 [Coulombs]
Answer:
La fuerza magnética del electrón es 6.41x10⁻¹³ N.
Explanation:
Podemos encontrar la fuerza magnética (F) usando la ley de Lorentz:
[tex] F = qv\times B [/tex]
En donde:
q: es la carga del electrón = 1.602x10⁻¹⁹ C
v: es la velocidad del electrón = 5x10⁶ m/s
B: es el campo magnético = 0.8 T
[tex] F = qv\times B = 1.602 \cdot 10^{-19} C*5\cdot 10^{6} m/s*0.8 T = 6.41 \cdot 10^{-13} N [/tex]
Por lo tanto, la fuerza magnética del electrón es 6.41x10⁻¹³ N.
Espero que te sea de utilidad!
Under what circumstances will the distance traveled by an object be the same as the magnitude of the displacement of an object?
Can include a single word part on one side , with the meaning on the other side . Stephen can test himself or can enlist the help of someone else to hold them up to test him
Incomplete question; Full question read;
Type the correct answer in the box. Spell all words correctly. Stephen is a student who wants to test his knowledge of medical terminology. Which option could he use?
For medical terminology, ___________ can include a single word part on one side, with the meaning on the other side. Stephen can test himself or can enlist the help of someone else to hold them up to test him.
Answer:
Flashcard
Explanation:
It is interesting to note that a flashcard is an effective memory and teaching aid. It usually has a question on one side, and the other side contains the answer.
Hence, Stephen can build his knowledge of medical terminology by making use of a flashcard himself or can enlist the help of someone else to hold them up to test him.
What is Latin word for "little lumps?"
Answer:
tura paulo
Explanation:
sry if im wrong ;)
3. An airplane is heading north with an airspeed of 325 m/s with a wind from the east at 55.0 m/s. What is the airplane's velocity relative to the ground? Is the airplane's ground speed faster or slowerthan its air speed? Why?
Let a denote the airplane's velocity in the air, g its velocity on the ground, and w the velocity of the wind. (Note that these are vectors.) Then
a = g + w
and we're given
a = (325 m/s) j
w = (55.0 m/s) i
Then
g = - (55.0 m/s) i + (325 m/s) j
The ground speed is the magnitude of this vector:
||g|| = √[ (-55.0 m/s)² + (325 m/s)² ] ≈ 330. m/s
which is faster than the air speed, which is ||a|| = 325 m/s.
The relative velocity of the airplane with respect to the ground is 329.6 m/s.
The airplane's ground speed is faster than the airspeed because the relative speed of the the ground is zero causing the airplane to appear faster.
The given parameters;
speed of the airplane, [tex]V_P[/tex] = 325 m/s northspeed of the wind, [tex]V_w[/tex] = 55 m/s eastThe velocity of the airplane relative to the ground is calculated by applying Pythagoras theorem as follows;
[tex]V_G_P^2 = 325^2 + 55^2\\\\V_G_P = \sqrt{325^2 + 55^2} \\\\V_G_P = 329.6 \ m/s[/tex]
Thus, we can conclude that the airplane's ground speed is faster than the airspeed because the relative speed of the the ground is zero causing the airplane to appear faster.
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What is the value of the initial horizontal velocity?
Initial Velocity is the velocity at time interval t = 0 and it is represented by u. It is the velocity at which the motion starts.
I hope this helps...Good day :)Which of the following is not an example of work?
1.a man pushing a heavy box across the floor
2.an air hockey puck traveling at a constant speed
3.a magnet repelling a 4.compass needle
ship movement that causes ripples in the water
Answer:
3 a is the ans i think so ....
A crane lifts a 75kg mass a height of 8 m. Calculate the gravitational potential energy gained by the mass (g = 9.8 N/kg.
What does it mean for objects to be at different temperatures?
my third time trying asxhcgxvbsxnsxfsgxscn gOsSHsHSHSHh look at the picture :))
unit of power is derived unit why
Answer:
it was given the name Newton (N). from this, the derived unit of energy (or work) is defined ,as the work produced when the unit of force causes a displacement equal to the unit of length of its point of application along its direction . It was given the name Joule (J).
Explanation:
relationship between voltage, resistance and current in a circuit
Answer:
V = I×R
where -
V = potential difference across
I = current flowing in the circuit
R = Equivalent Resistance in the circuit
Answer:
Answer:
V = I×R
where -
V = potential difference across
I = current flowing in the circuit
R = Equivalent Resistance in the circuit
Explanation:
A car speeds up from 0.00 m/s to 60.0
m/s in 8.53 s.
The acceleration of the car is:
A. 512 m/s2
B. 8.53 m/s2
C. 68.5 m/s2
D. 7.03 m/s2
change the following to celisus
a.-400f b.800f
please its urgent i will give u brainliest
Physics help, please? :)
3. Consider a locomotive and the rest of a freight train to be a single object. Suppose the locomotive is pulling the train up a hill. Describe the action and reaction forces that cause the locomotive to move up the hill, such as the reaction force and gravity.
4. Is the force of the earth’s gravity on the sun stronger, weaker, or the same as the force of the sun’s gravity on the earth? Explain why the sun’s attraction affects the motion of the earth more than the earth’s attraction affects the sun’s motion. Employ Newton’s second and third laws in your answer.
If anyone could help me at all, with either question it would be greatly appreciated, Physics is my hardest subject, and I struggle with it.
Answer:
Explanation:
3. Newton’s third law explains how every action has an equal but opposite reaction, meaning that forces comes in pairs. While the locomotive’s wheels are pushing back against the ground as the action force, the ground is producing a reaction force towards the locomotive, propelling it forward. Another pair of forces that act on the locomotive is gravity and normal force. While gravity is pulling the locomotive towards the ground, the normal force the ground exerts on the locomotive is why the locomotive doesn’t fall through the ground.
4. The force of Earth’s gravity on the Sun is weaker than the force of the Sun’s gravity on Earth. The Sun’s attraction affects the motion of Earth more than the Earth’s attraction affects the Sun’s motion because according to Newton’s second law, force has mass as one of its factors. The Sun has a significantly higher mass than Earth, meaning that its force of gravity would also be significantly higher. Newton’s third law is why the Earth doesn’t get marginally closer to the Sun, stating that every action has an equal and opposite reaction. As the Sun is pulling Earth towards itself, Earth is pulling away from the Sun.
A 12.0 kg box is being pulled along level ground at constant velocity by a horizontal force of 38.0 N. What is the coefficient of kinetic friction between the box and the floor?
The coefficient of kinetic friction between the box and the floor is 0.323.
By Newton's Law of Motion we understand that an object is at equilibrium if and only if it is at rest or it is moving at constant velocity. If a horizontal force is applied on the box and it is moving, then a force with equal magnitude and opposed to that force must exists, which corresponds to the kinetic friction. Let suppose that the box is moving on a horizontal ground.
The equation of equilibrium for the box is described below:
[tex]\Sigma F = P - \mu_{k}\cdot m\cdot g = 0[/tex] (1)
Where:
[tex]P[/tex] - External force, in newtons.[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, no unit.[tex]m[/tex] - Mass, in kilograms.[tex]g[/tex] - Gravitational constant, in meters per square second.An expression for the kinetic coefficient of friction is derived by clearing the variable in (1):
[tex]\mu_{k} = \frac{P}{m\cdot g}[/tex] (2)
If we know that [tex]P = 38\,N[/tex], [tex]m = 12\,kg[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then the kinetic coefficient of friction is:
[tex]\mu_{k} = \frac{38\,N}{(12\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}[/tex]
[tex]\mu_{k} = 0.323[/tex]
The coefficient of kinetic friction between the box and the floor is 0.323.
We kindly invite to see this question on friction: https://brainly.com/question/18332986
cuky and Magneton Post. Tout (OL//17
A student has wired lights for a model house project for class. To properly demonstrate the circuit, the student wants to show that Bulb #3
will not light, but all of the others do.
Peshw1
Lik
LE
Reso2
At which point must the break in the circuit be located for this to happen, provide evidence to support your claim and what would one need
to do in order to make the entire circuit work? (AKS 10b)
Answer:
the switch or the wire
Explanation: