Kathleen is rowing her canoe northward with an average force of 19.1 N. The wind is blowing directly south with an average force of 14.4 N. What is the net force on the canoe?
4.7 N north
33.5 N south
33.5 N north
4.7 N south

Answers

Answer 1

The net force on the canoe rowed northward with an average force of 19.1 N is 4.7 N North if the wind is blowing directly south with an average force of 14.4 N.

Net force = Force due to rowing - Force due to wind

Net force = 19.1 - 14.4

Net force = 4.7 N

The direction is towards North because the force due to rowing is greater than the force due to wind.

If two force act in opposite directions, the resultant force is the difference of these two forces and the resultant direction is the direction in which the greater force is applied.  

Therefore, the net force on the canoe is 4.7 N North

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Related Questions

A person is running at a velocity vv. By which factor would they need to increase their speed in order to double their kinetic energy?

Answers

The kinetic energy is given by:

[tex]K=\frac{1}{2}mv^2[/tex]

If we want to double it then we have:

[tex]2(\frac{1}{2}mv^2)=\frac{1}{2}m(\sqrt[]{2}v)^2[/tex]

Therefore the speed has to increas by a factor of square root of 2

A duck is paddling due East at 1.1 m/s across the river while it flows due South at 0.55 m/s What is her resultant velocity?

Answers

The diagram representing this scenario is shown below

A right angle triangle is formed. R represents the resultant velocity. To find R, we would apply the pythagorean theorem which is expressed as

hypotenuse^2 = one leg^2 + other leg^2

From the diagram,

hypotenuse = R

one leg = 1.1

other leg = 0.55

Thus,

R^2 = 1.1^2 + 0.55^2 = 1.5125

Taking square root of both sides,

R = square root of 1.5125

R = 1.23

The resultant velocity is 1.23 m/s

given q= 10^-6 c, v= (3i + 4j )m/(s) , b=1i tesla find magnetic force

Answers

Lorentz magnetic force is the force exerted on a charged particle 'q' which moves with a velocity 'v' through a magnetic field B. The Lorentz forces exerted by moving charges on one another are not equal and opposite.

Given:

Charge, q = [tex]10^{-6}[/tex] C

Velocity, v = (3i + 4j) m/s

Magnetic field, B = 1i T.

To find: Magnetic force, F.

From Lorentz force law, the magnetic force is given by,

F = q × (v × B)

Substituting the given values,

F =  [tex]10^{-6}[/tex] × ((3i + 4j) × 1i)

Since i×i = 0, and j×i = k,

F =  [tex]10^{-6}[/tex] × 4k

∴ F = 4 × [tex]10^{-6}[/tex] k newtons.

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A student makes the following claim, "Acceleration is when an object changes speed, so it can be discussed as a scalar quantity." Explain the error in the student's claim. Provide an example of each quantity to support your answer.

Answers

A student makes the following claim, "Acceleration is when an object changes speed, so it can be discussed as a scalar quantity." The error here is that acceleration is said to be done when either speed of that object changes or direction of that object changes. Hence , acceleration is not a scaler quantity.

Scalar quantities are quantities that are described only by a magnitude. They do not have a direction of action.

A vector quantity is defined as the physical quantity that has both directions as well as magnitude.

Acceleration is said to be occurred in two cases :

when the object changes its speed

or when the object changes its direction

since , acceleration depends upon both direction and magnitude ,hence it is a vector quantity not a scaler quantity.

for example : a stone attached to a string moving in a circular motion at a constant speed will be considered in accelerated motion because it is constantly changing its direction.

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Convert 500BTU/ft.s.F to g.cal/cm^2.s.°C

Answers

The requirement of the prompt is for 500 British Thermal Units /Calories (Cal) to be converted to Gram Calories. Hence, 500 BTU (cal) = 126,082cm²

What is a British Thermal Unit?

A British thermal unit is a heat unit defined as the amount of heat needed to raise the temperature of one pound of water by one degree Fahrenheit. It is also one of the customary units used in the United States.

To covert 500 BTU, one must note that according to established scientific metrics.:

1 BTU = 252.164 Gram (Cal).

Hence,

500 BTU = 252.164  x 500

= 126,082 cm²

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Does scarcity effect everyone?

Answers

Answer: Scarcity affects society in every way. First and foremost, scarcity affects the way that individuals make choices. Time and money are two examples of scarce resources that we make choices with every day.

Based on the periodic table why are He, Ne, Ar, Kr, and Xe the same
column/group/family?

Answers

The noble gases or inert gases helium (He), neon (Ne), argon (Ar), krypton (Kr), and radon (Rn) are found in group 8A of the periodic table. The name comes from little these elements react with other substances.

What is periodic table ?

The periodic table is a tabular arrangement of chemical elements arranged according to number of protons, starting with hydrogen and going up to the element the with highest atomic number. The quantity of protons found in the nucleus of an element's atom is referred as the element's atomic number.

Why is the periodic table important?

All known elements were grouped together in the periodic table of elements into groups with attributes. It becomes a crucial tool for chemists, nanotechnologists, and other scientists as a result. One can forecast what chemicals will react if you learn to use and understand the periodic table.

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What word am I looking for I have already tried losing

Answers

We will have the following:

neutral object becomes charged by losing electrons.

A 2.0 m long frictionless pendulum of mass 1.6 kg is released from point A at an angle & of
15 degrees. What is the speed of the pendulum at Point C.

Answers

The speed of pendulum at point C would be 0.47 m/sec when a 2 meter long frictionless pendulum of mass 1.6 kg is released from point A.

What is speed and how it is calculated out to be 0.47 meter/second?Speed is a quantity used to measure the distance travelled per unit time of the given time period.Here is given the length of rope be 2 meter and the mass of pendulum 1.6 kg released from point A.Using L cos theta = L ( 1 - cos theta) , we can write v^2/2g and putting all the numerical values we will get the speed be 0.47 m/s.Putting the angle that is theta be 15 degrees and getting the v the speed be 0.47 m/s.Hence the speed of the pendulum at point C would be 0.47 m/s.

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nd in Atlanta you decide to drive around the city. You turn a corner and are driving up a steep hill. Suddenly, a small boy runs out on the street chasing a ball. You slam on the brakes and skid to a stop leaving a 50-foot-long skid mark on the street. The boy calmly walks away but a policemen watching from the sidewalk walks over and gives you a speeding ticket. He points out that the speed limit on this street is 25mph. After you recover your wits, you begin to examine the situation. You determine that the street makes an angle of 25◦with the horizontal and that the coefficient of static friction between your tires and the street is0.80. You also find that the coefficient of kinetic friction between your tires and the street is 0.60. Your car’s information book tells you that the mass of your car is 1600 kg. You weigh 140 lbs. Will you fight the ticket

Answers

skid = 50 ft

Speed limit = 25 mph

angle = 25°

friction coefficient = 0.80

mass = 1600 kg

weight = 140 lbs

An object has 25 J of kinetic energy and 35 J of potential energy. What isthe total energy possessed by the object? *

Answers

The total energy possessed by the object is 60 J

Given:

The kinetic energy of the object, K=25 J

The potential energy of the object, P=35 J

To find:

The total energy possessed by the object.

Explanation:

The kinetic energy of an object is the energy possessed by it due to its motion. The kinetic energy is directly proportional to the square of the velocity of the object.

The potential energy of an object is the energy possessed by it due to its position. The gravitational potential energy of an object is directly proportioinal to the mass ofthe

You accidentally throw your car keys horizontally at 5.0 m/s from a cliff 45 m high. How far from the base of the cliff should you look for your keys?

Answers

The distance from the base of the cliff you should look for your key is 15 m

How to determine the distance from the cliff

To answer the question given above, we shall determine the time taken for the keyl to land. This can be obtained as follow:

Height (h) = 45 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) = ?

h = ½gt²

45 = ½ × 9.8 × t²

45 = 4.9 × t²

Divide both side by 4.9

t² = 45 / 4.9

Take the square root of both side

t = √(45 / 4.9)

t = 3 s

Finally, we shall determin the distance from the base of the cliff the key will land. This can be obatined as follow:

Horizontal velocity (u) = 5 m/sTime (t) = 3 sDistance (s) = ?

s = ut

s = 5 × 3

s = 15 m

Thus, you should look for your key at a distance of 15 from the base of cliff

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On a fishing trip Justin rides in a boat 12 km south. The fish aren't biting so they go 4 km west. They then follow a school of fish 1 km north. What is his total displacement?

Answers

ANSWER:

The displacement is 11.7 km

STEP-BY-STEP EXPLANATION:

The displacement is the vector sum from the start point to the end point. Vector addition is applying the formula of the distance between two points.. We will use this formula:

[tex]d=\sqrt[]{(x_2-x^{^{}}_1)^2+(y_2-y_1)^2^{}}[/tex]

To better understand the exercise, we will draw a picture of the situation, it would look like this:

Replacing the points (-4, -11) and (0, 0)

[tex]\begin{gathered} d=\sqrt[]{(-4-0^{}^{}_{})^2+(-11_{}-0_{})^2} \\ d=\sqrt[]{16+121^{}} \\ d=\sqrt[]{137} \\ d=11.7 \end{gathered}[/tex]

Atmospheric pressure is about 1.00 × 105 Pa on average.A. What is the downward force of the air on a desktop with surface area 2.59 m2?B. Convert the downward force of the air on a desktop with surface area 2.59 m2 to pounds to help others understand how large it is.

Answers

A)

The formula for calculating pressure is expressed as

pressure = force/area

From the information given,

pressure = 1.0 x 10^5 pa

Recall, 1 pa = 1 N/m^2

This means that

pressure = 1.0 x 10^5 N/m^2

surface area = 2.59 m^2

Force = pressure x area

Force = 1.0 x 10^5 x 2.59 = 259000 N

Recall,

B)

1 newton = 0.224808943 pounds

259000 newtons = 259000 x 0.224808943

= 58226 pounds

When a 10 V battery is connected to a resistor, 5 A of current flows through the resistor. What is the resistor's value?

Answers

Given data

*The value of battery voltage is V = 10 V

*The current flows through the resistor is I = 5 A

The formula for the resistor is given by the Ohm's law as

[tex]R=\frac{V}{I}[/tex]

Substitute the values in the above expression as

[tex]\begin{gathered} R=\frac{10}{5} \\ =2\text{ ohm} \end{gathered}[/tex]

A 20.0 kg penguin slides at a constant velocity of 3.3 m/s down an icy incline. The incline slopes above the horizontal at an angle of 6.0°. Determine the coefficient of kinetic friction.

Answers

The coefficient of kinetic friction down the slope is 0.105.

What is kinetic friction?

Kinetic friction is the friction that exists or acts between the surfaces of one object moving over another.

The kinetic frictional force of an object moving on an inclined plane is give by the formula below:

Kf = μk * mg *cosθ

where;

μk = coefficient of kinetic friction.

mg cosθ = component of the weight perpendicular to the inclined plane

θ = angle of inclination

For an object moving at a constant velocity, the component of the weight down the slope (mg sinθ) is equal to the kinetic frictional force.

Hence, μk * mg *cosθ = mg sinθ

μk =  mg sinθ / mg *cosθ

μk = tan θ

μk = tan 6.0

μk = 0.105

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a 2403 kg racecar has a total momentum of 9.912*10^4kgm/s at one point in the race. calculate the speed of the racecar at that point

Answers

In order to calculate the speed, we can use the formula for the momentum:

[tex]p=m\cdot v[/tex]

Where p is the momentum (in kg m/s), m is the mass (in kg) and v is the speed (in m/s).

So, using p = 99120 kg m/s and m = 2403 kg, we have:

[tex]\begin{gathered} 99120=2403\cdot v\\ \\ v=\frac{99120}{2403}\\ \\ v=41.25\text{ m/s} \end{gathered}[/tex]

Can all rocks be dated with radiometer methods? Explain

Answers

Answer: No.

Explanation:

Radiometer dating is used on igneous rocks.

Unlike the other two rock types, sedimentary annd metamorphisis, all igneous rocks possess one specific age/ time of origin.

A car going at 80 mph comes to a complete stop in 6 seconds. Calculate the acceleration

Answers

The acceleration is defined as:

[tex]a=\frac{v_f-v_0}{t}[/tex]

where vf is the final velocity, v0 is the initial velocity and t is the time. In this case we have:

The initial velocity is 80 mph

The final velocity is 0 mph (since the car stops)

The time it takes to slow down is 6 seconds.

Before we can do the calculation, we need to convert the velocity to appropriate units; let's write the initial velocity in ft/s units. To do this we need to remember that 1 mile is equal to 5280 ft and one hour is equal to 3600 s, then we have:

[tex]80\frac{mi}{h}\cdot\frac{5280\text{ ft}}{1\text{ mi}}\cdot\frac{1\text{ h}}{3600\text{ s}}=117.33\frac{ft}{s}[/tex]

Hence the initial velocity is 177.33 ft/s.

Now that we have all the values we need, we plug them in the equation for the acceleration:

[tex]\begin{gathered} a=\frac{0-117.33}{6} \\ a=-19.56 \end{gathered}[/tex]

Therefore, the acceleration is -19.56 feet per second per second. Note: The minus sign indicates that the car is slowing down.

Consider the graph shown. Which of the motions is consistent with the graph?a) The object has a constant velocity in the negative direction.b) The object is moving in the negative direction with a changing speed.c) The object is moving in the positive direction and slowing down.

Answers

Given:

The graph of velocity vs time of an object

To find:

Which of the motions is consistent with the graph?

Explanation:

We see here that the object's initial velocity is positive, and the final velocity is zero. So, the object is slowing down. as the initial velocity is positive, the object's direction of movement is positive.

Hence, The object is moving in a positive direction and slowing down.

A roller coaster car begins its roll from the top of the tracks at a speed of2 meters per second. When it reaches the bottom of the 200-meter drop four seconds later, its speed is 22 meters per second. What was the averagespeed of the roller coaster ride in meters per second over the 200-meter drop

Answers

The speed of the car from the top of the track is,

[tex]u=2ms^{-1}[/tex]

The distance traveled by the car is,

[tex]d=200\text{ m}[/tex]

The speed of the car after 4 seconds is,

[tex]v=22ms^{-1}[/tex]

Thus, the average speed of the car is,

[tex]v_{av}=\frac{u+v}{2}[/tex][tex]\begin{gathered} v_{av}=\frac{2+22}{2} \\ v_{av}=12ms^{-1} \end{gathered}[/tex]

Thus, the average speed of the roller coaster car is 12 meter per second.

Ultraviolet light has shorter wavelengths and higherfrequencies than visible light.TRUEFALSE

Answers

Ultraviolet light has shorter wavelengths and higher frequencies than visible light.

The answer is TRUE

A train is traveling down a straight track at 26 m/s when the engineer applies the brakes, resulting in an acceleration of −1.0 m/s2 as long as the train is in motion. How far does the train move during a 52-s time interval starting at the instant the brakes are applied?______ m

Answers

In order to calculate the distance the train will move, we can use the formula below:

[tex]\Delta S=V_0t+\frac{at^2}{2}[/tex]

Where V0 is the initial speed, t is the time and a is the acceleration.

Since the initial speed is 26 m/s and the train acceleration is -1 m/s², the train will completely stop after 26 seconds. In the remaining 26 seconds to complete the total of 52, the train will be stopped already, so there is no displacement.

Because of that, we will use a time t = 26 seconds.

So, using V0 = 26 m/s and a = -1 m/s², we have:

[tex]\begin{gathered} \Delta S=26\cdot26+\frac{(-1)26^2}{2}\\ \\ \Delta S=676-338\\ \\ \Delta S=338\text{ m} \end{gathered}[/tex]

Therefore the train will move 338 meters.

person pulls a toboggan for a distance of 35.0 m along the snow with a rope directed 32.0o above the snow. The tension in the rope is 105.0 N. How much work is done on the toboggan by the tension force?

Answers

The amount of work done on the toboggan by the tension force of 105 N with a rope directed 32° above the snow is 3.12 KJ

W = F d cos θ

W = Work done

F = Force

d = Distance

θ = Angle between force and displacement vector

d = 35 m

F = 105 N

θ = 32°

W = 105 * 35 * cos 35°

W = 105 * 35 * 0.85

W = 3123.75 N m

W = 3.12 KJ

Work done is energy transferred to make an object move to a distance. Its unit is Joules which is denoted as J. It is the amount of work done by a force of 1 Newton to move a distance of 1 meter.

Therefore, the amount of work done on the toboggan by the tension force is 3.12 KJ

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I need help on this science homework I forgot on what to do through number 4-7 including a,b,c,d, and e.

Answers

Answer:

[tex]\begin{gathered} (a)\Rightarrow v=2ms^{-1} \\ (b)\Rightarrow v=1ms^{-1} \\ (c)\Rightarrow v=6.67ms^{-1}_{} \\ (d)\Rightarrow v=1.2ms^{-1} \\ (e)\Rightarrow v=0ms^{-1} \end{gathered}[/tex]

Explanation: We need to calculate the speed on intervals a b c d and e, the speed can be calculated with the following formula:

[tex]v=\frac{\Delta S}{\Delta t}\Rightarrow(1)[/tex]

(a) 0-5 seconds Interval:

[tex]\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(10m-0m)}{(5s-0s)}=\frac{10m}{5s}=2ms^{-1} \\ v=2ms^{-1} \end{gathered}[/tex]

(b) 5-15 seconds Interval:

[tex]\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(20m-10m)}{(15s-5s)}=\frac{10m}{10s}=1ms^{-1} \\ v=1ms^{-1} \end{gathered}[/tex]

(c) 15-18 seconds Interval:

[tex]\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(40m-20m)}{(18s-15s)}=\frac{20m}{3s}=6.67ms^{-1} \\ v=6.67ms^{-1} \end{gathered}[/tex]

(d) 18-23 seconds Interval:

[tex]\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(46m-40m)}{(23s-18s)}=\frac{6m}{5s}=1.2ms^{-1} \\ v=1.2ms^{-1} \end{gathered}[/tex]

(e) 23-25 seconds Intervals:

[tex]\begin{gathered} v=\frac{\Delta S}{\Delta t}\Rightarrow v=\frac{(40m-40m)}{(25s-23s)}=\frac{0m}{2s}=0ms^{-1} \\ v=0ms^{-1} \end{gathered}[/tex]

You place a box weighing 276 N on an inclined plane that makes a 44.5° angle with the horizontal.
Compute the component of the gravitational force acting down the inclined plane.
Answer in units of N.

Answers

Answer:

this is the answer

Explanation:

hope it helps

Can you help me match these with the correct word

Answers

When an object is thrown up into the air the time up is equal to the time down.

When an object is thrown up into the air and reacher the apex, the velocity of the object is zero.

If you throw an object straight up the air the velocity of the object is decreasing on its way up.

7. What is the velocity of a 850kg car after starting at rest when 13,000J of work is done to it.

Answers

Answer:

5.53 m/s

Explanation:

The work is equal to the change in the kinetic energy, so

[tex]\begin{gathered} W=\Delta KE \\ W=\frac{1}{2}m(v^2_f-v^2_i)^{}^{} \end{gathered}[/tex]

Since the car starts at rest, the initial velocity vi = 0 m/s, so we can solve for the final velocity vf as follows

[tex]\begin{gathered} W=\frac{1}{2}mv^2_f \\ 2W=mv^2_f \\ \frac{2W}{m}=v^2_f \\ v_f=\sqrt[]{\frac{2W}{m}} \end{gathered}[/tex]

So, replacing the work W = 13,000J and the mass m = 850kg, we get:

[tex]\begin{gathered} v_f=\sqrt[]{\frac{2(13,000J)}{850\operatorname{kg}}} \\ v_f=5.53\text{ m/s} \end{gathered}[/tex]

Therefore, the velocity is 5.53 m/s

what do fusion and fission have in common

Answers

Answer:

Explanation:

they both involve nuclear reactions that produce energy, but the application are not the same  

A ski jumper competing for an Olympic gold metal wants to jump
a horizontal distance of 149 meters. The takeoff point of the ski
jump is at a height of 38.0 meters. With what horizontal velocity
must he leave the jump in order to travel 149 meters?

Answers

19.25 m/s is horizontal velocity must he leave the jump in order to travel 149 meters .

How fast is horizontal moving?

Standard definitions of horizontal velocity include miles per hour and meters per second, which are horizontal displacement times time. The distance an object has traveled since its origin is simply referred to as displacement.

How can one calculate vertical velocity using horizontal velocity?

V * cos() equals the horizontal velocity component Vx. V * sin() is equal to the vertical component of velocity, Vy.

Time before landing = sqrt ( 2 x height / gravity ), sqrt ( 2 x 38/ 9.81) = 7.75

distance / time = avg speed

149/ 7.75 ≅ 19.25 m/s

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