Johan can get lunch at Joe’s Deli for $12, and he can get lunch at Majestic for $8. In one month, Johan spent $96 on lunches (and he only went to those two places, and he always got the same thing). Which equation represents possible combinations of how many lunches Johan bought at Joe’s and Majestic?
A)y=4x+96
B)12x+8y=20
C)y-8=96(x-12)
D)12x+8y=96

The z-scores for a deta seller making $13 and $17 an hour will be [tex]Z_{13}=0.5 \ \ \ Z_{17}=2.5[/tex]

The z-scores give us information about how many standard deviations from the mean the data are. This difference can be negative, if the data are n deviations to the left of the mean, or it can be positive if the data are n deviations to the right of the mean.

To calculate the Z scores, we calculate the difference between the value of the data and the mean and then divide this difference by the standard deviation.

[tex]Z=\dfrac{X-\mu}{\sigma}[/tex]

Where x is the value of the data, μ is the mean and σ is the standard deviation

In this case :

μ = 12 $/h

[tex]\sigma[/tex] = 2 $/h

We need to calculate the Z-scores for x=17 and x=13

[tex]Z_{13}=\dfrac{13-12}{2}=0.5[/tex]

[tex]Z_{17}=\dfrac{17-12}{2}=2.5[/tex]

Thus the z-scores for a deta seller making $13 and $17 an hour will be [tex]Z_{13}=0.5 \ \ \ Z_{17}=2.5[/tex]

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Answer:

811

Step-by-step explanation:

i d k

Answer:

4:18

6:27

8:36

Hope this helps! :)

Answer: a6=70

Step-by-step explanation:

we know that

In the Arithmetic Sequence the formula is:

an= a1 + d(n−1)

where

a1 is the first term

d is the common difference

n is the number of terms

in this problem

a1=5

a2=18

a3=31

a4=44

a5=57

so

d=a2-a1 or a3-a2 or a4-a3 or a5-a4

d=57-44----> 13

find a6

a6= a1 + d(n−1)

n=6

d=13

a1=5

a6=5+13*(6-1)----> a6=5+13*5----> a6=70

Answer:

Answer:

50

Step-by-step explanation:

By the triangle midsegment theorem, 2(VX)=YZ.

This means that 2(t-25)=t, and thus t=50.

Answer:

15x + 50y = 5 (3x + 10y)

5 is a common factor

15/3x = 3x

50/5y = 10y

the answer is 5

[tex] \huge \mathbb \orange{HEY \: THERE}[/tex]

[tex] \mathfrak \red{AnSwEr~}[/tex]

[tex] \mathfrak \red{Explaination}[/tex]

[tex] \mathsf \pink{15x + 50y = 5(3x + 10y)}[/tex]

[tex] \mathsf \pink{5 \: is \: multiplied \: with \: both \: 3x \: and \: 10y}[/tex]

[tex] \huge \mathbb \orange{HOPE \: IT \: HELPS}[/tex]

Answer:

The correct answer is 351.

Step-by-step explanation:

We will use order of operations to solve this problem. Recall that order of operations, AKA PEMDAS, states we should simplify numeric expressions in the following order:

Parentheses

Exponents

Multiplication/Division (ordered left to right)

Addition/Subtraction (ordered left to right)

Begin by evaluating the parentheses:

[tex]2+7^3+4(9-6)^2\div6\\2+7^3+4(3)^2\div6[/tex]

Simplify the exponents:

[tex]2+7^3+4(3)^2\div6\\2+343+4(9)\div6[/tex]

Multiply:

[tex]2+343+4(9)\div6\\2+343+36\div6[/tex]

Divide:

[tex]2+343+36\div6\\2+343+6[/tex]

Add:

[tex]2+343+6\\345+6\\351[/tex]

Answer:

$531.83

Step-by-step explanation:

88*4=352

75+120+85+140=420. Take away the 200 he was allowed. Leaves 220

220*.20 =44

18.50*4=74

gas is set at 61.83

Sum each of those.

352+44+74+61.83= $531.83

The area of the triangle def round to the nearest tenth of a square unit is 10.3 square units.

When the two sides and an angle of a  triangle is known, then the area of the triangle can be found out with the following formula.

[tex]A=ab\sin\left(\dfrac{C}{2}\right)[/tex]

Here, a,b are the adjacent sides and C is the angle made between them.

The image of the triangle DEF is attached below. In this the two adjacent sides are given with the length 5 units ans 8 units long.

The angle made between them has the measure of 31 degrees. Put the values in the above formula as,

[tex]A=(5)(8)\sin\left(\dfrac{31}{2}\right)\\A=10.3\rm\; unit^2[/tex]

Hence, the area of the triangle def round to the nearest tenth of a square unit is 10.3 square units.

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Answer: A, 10.3

Step-by-step explanation: edge 2022

Answer:

4 blocks

Step-by-step explanation:

Answer:

h=[tex]-\frac{1}{3}[/tex]

Step-by-step explanation:

[tex]6h-1=-3\\6h=-2\\h=-\frac{2}{6} \\h=-\frac{1}{3}[/tex]

Answer:

Step-by-step explanation:

Isolate by the h from one side of the equation.

6h-1=-3

First, add by 1 from both sides.

[tex]\sf{6h-1+1=-3+1}[/tex]

Solve.

-3+1=-2

Rewrite the problem down.

6h=-2

Then, you divide by 6 from both sides.

[tex]\sf{\dfrac{6h}{6}=\dfrac{-2}{6} }[/tex]

Solve.

-2/2=-1

6/2=3

Rewrite as a fraction.

[tex]\boxed{\sf{h=-\dfrac{1}{3}=0.33}}[/tex]

I hope this helps you! Let me know if my answer is wrong or not.

[tex]a = 6(4) - 3 = 24 - 3 = 21[/tex]

Check the picture below, so the circle looks more or less like that one.

well, the center of it is simply the Midpoint of those two points, and its radius is simply half-the-distance between them.

[tex]~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left(\cfrac{ 3 -5}{2}~~~ ,~~~ \cfrac{ 5 + 9}{2} \right)\implies \left( \cfrac{-2}{2}~~,~~\cfrac{14}{2} \right)\implies \stackrel{center}{(-1~~,~~7)} \\\\[-0.35em] ~\dotfill[/tex]

[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-5}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{5})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ \stackrel{diameter}{d}=\sqrt{[3 - (-5)]^2 + [5 - 9]^2}\implies d=\sqrt{(3+5)^2+(-4)^2} \\\\\\ d=\sqrt{8^2+16}\implies d=\sqrt{80}\implies d=4\sqrt{5}~\hfill \stackrel{\textit{half the diameter}}{\cfrac{4\sqrt{5}}{2}\implies \underset{radius}{2\sqrt{5}}}[/tex]

Answer:

$12

Step-by-step explanation:

3/7 of 56 = 24 hats  

24 x $3.5 = $84

The remaining hats 56-24 =32 hats

HALF of 32 =16hats

    16x$3 =$48

$84 + $48 = $132

  But he spent $120

The profit Ravi made = 132-120 = $12

Answer:

(a) 8000 times 5 times 2 = 800

Answer:

0.64

Step-by-step explanation:

Given the sides of a triangle, we can solve for any angle using the Law of Cosines: [tex]a^2=b^2+c^2-2bc(cosA)[/tex]

Our variables:

a = 27

b = 36

c = 45

B = 90°

[tex]a^2=b^2+c^2-2bc(cosA)[/tex]

[tex](27)^2=(36)^2+(45)^2-2(36)(45)(cosA)[/tex]

[tex]720=1296+2025-3240(cosA)[/tex]

[tex]720-3321=-3240(cosA)[/tex]

[tex]-2601=-3240(cosA)[/tex]

[tex]\frac{2601}{3240} =cosA[/tex] ≈ [tex]0.80278[/tex]

[tex]cos^-(A)=cos^-(\frac{2601}{3240})[/tex]

[tex]< A = 0.63885708[/tex]

This might be wrong, but you get the method. I would repost for a better answer from someone else because I'm practically half asleep. Very sorry but I hope you get some help soon! Best of luck

Answer:

Step-by-step explanation:

The y-intercept is the point where the graph cuts the y axis - that is when x = 0.

f(x)=138⋅1.9x

ehen x = 0 f(x) = 0 so the y-intercept is at (0, 0).

Answer:

  D. perpendicular; midpoint

Step-by-step explanation:

A perpendicular bisector is perpendicular to a line segment and intersects the line segment at its midpoint .

__

This is a vocabulary question. It is always a good idea to learn the vocabulary, so you can understand statements that make use of these words. In the attached image, the line segment containing C is the perpendicular bisector of segment AB.

The fraction of her collection that is 21pennies is 56

Given the fraction for Puja's collection expressed as 3/8

Leet x be the  fraction of her collection which is 6 pennies, to have;

x of 3/8 = 6

3x/8 = 6

3x = 48

x = 16

Hence the fraction of her collection that is 6pennies is 16

Let y be the  fraction of her collection which is 21 pennies, to have;

x of 3/8 = 21

3x/8 = 21

x = 56

Hence the fraction of her collection that is 21pennies is 56

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Answer:

-4<x≤5

Step-by-step explanation:

An open circle means 'less than' or 'greater than' while a closed cirlce means 'less than or equal to' or 'greater than or equal to'

Answer:

I think Option C is the correct answer

I think it will help you.

The function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

From the complete information, it should be noted that the function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

Also, f(x) = x³ and g(x) = |x|³ are not equal. This is because both functions are not equal for x < 0. This can be illustrated when x = -1. In this case, f(x) = -1 and g(x) = 1.

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The function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

Two functions are equal if they have the same domain and codomain and their values are the same for all elements of the domain.

The function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

Also, f(x) = x³ and g(x) = |x|³ are not equal.

This is because both functions are not equal for x < 0.

This can be illustrated when x = -1. In this case, f(x) = -1 and g(x) = 1.

Hence, the function f(x) = x² and g(x) = |x|² are the same since they both give a positive value.

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#SPJ4

Answer:

Step-by-step explanation:

All you have to do for this problem is take 3, over the 20, and then turn into a percent. Your final answer is D. 15%, because if you multiply 3/20 by 5, you get 15/100, which is easier to turn into a percent, leaving you with 15%

Step-by-step explanation:

inscribed angles subtended by the same arc are equal.

the central angle of a circle is twice any inscribed angle subtended by the same arc.

the first statement tells us that the 53° angle as well as y stay the same size no matter where on their arcs (between the 2 points connected to O) they would be. so, we don't need to bother with any line lengths.

the 2nd statement tells us that x = 2×53 = 106°. the 53° and x angles refer to the short arc on the right of the 2 points connected to O.

and y and x refer to the larger arc on the left of the 2 line connected to O. that means according to the second statement : 360-x (the big angle around O) = 2y

so,

360 - 106 = 2y

254 = 2y

y = 127°

Answer:

15:11 ,where 15 = 435

So, 11 = 435×11//15 = 29×11 = 319

Hence, No. of girls = 319

Answer:

319 girls

Step-by-step explanation:

Given

Solving

Answer:

r:
The function is

The remainder when f(x) is divided by x−2 is 23.

To find:The value of k.

Solution:

According to the remainder theorem, if a polynomial P(x) is divided by (x-c), then the remainder is P(c).

It is given that, the remainder when f(x) is divided by x−2 is 23. By using remainder theorem, we get

Put x=2, to find the value of f(2).Therefore, the value of k is 8.

Step-by-step explanation:

Answer:

120 marbles

Step-by-step explanation:

we can find the answer by dividing the volume of the cylinder by the volume of the marble.

V of a cylinder is

pi×r^2×h = 1280pi

V of marble is

4/3 × pi × r^3

V is 32/3 pi

so final answer is 1280pi ÷ (32/3 × pi)

ANSWER IS 120 MARBLES

Answer:

[tex] \sf \: x = 2[/tex]

Step-by-step explanation:

Let's solve your equation step-by-step.

[tex] \sf 6x+6=10x−2 [/tex]

Step 1: Subtract 10x from both sides.

[tex] \sf6x+6−10x=10x−2−10x[/tex]

[tex] \sf−4x+6=−2[/tex]

Step 2: Subtract 6 from both sides.

[tex] \sf−4x+6−6=−2−6[/tex]

[tex] \sf−4x=−8[/tex]

Step 3: Divide both sides by -4.

[tex] \sf \frac{−4x}{−4}=\frac{−8}{−4}[/tex]

[tex] \sf x=2[/tex]

Answer:

13.  [tex]x^2+y^2+2x-3\sqrt{x^2+y^2}=0[/tex]

14.  [tex]r=3\cos(\theta)-2\sin(\theta)[/tex]

Step-by-step explanation:

Question 13

Conversion from Polar equation to rectangular equation:

[tex]x=r \cos(\theta) \implies \cos(\theta)=\dfrac{x}{r}[/tex]

[tex]y=r \sin(\theta) \implies \sin(\theta)=\dfrac{y}{r}[/tex]

[tex]x^2+y^2=r^2 \implies r=\sqrt{x^2+y^2}[/tex]

Given:

[tex]r=3-2\cos(\theta)[/tex]

[tex]\textsf{Substitute }\cos(\theta)=\dfrac{x}{r}:[/tex]

[tex]\implies r=3-\dfrac{2x}{r}[/tex]

Multiply both sides by r:

[tex]\implies r^2=3r-2x[/tex]

[tex]\implies r^2+2x-3r=0[/tex]

[tex]\textsf{Substitute }x^2+y^2=r^2\:\textsf{and }r=\sqrt{x^2+y^2}:[/tex]

[tex]\implies x^2+y^2+2x-3\sqrt{x^2+y^2}=0[/tex]

---------------------------------------------------------------------------------------------

Question 14

Conversion from Rectangular equation to polar equation:

[tex]x=r \cos(\theta)[/tex]

[tex]y=r \sin(\theta)[/tex]

[tex]x^2+y^2=r^2 \implies r^2\cos^2(\theta)+r^2\sin^2(\theta)=r^2[/tex]

Given:

[tex]x^2+y^2-3x+2y=0[/tex]

[tex]\textsf{Substitute }x^2+y^2=r^2\:\textsf{and }x=r \cos(\theta)\:\textsf{and }y=r \sin(\theta):[/tex]

[tex]\implies r^2-3r\cos(\theta)+2r\sin(\theta)=0[/tex]

Factor out common term r:

[tex]\implies r(r-3\cos(\theta)+2\sin(\theta))=0[/tex]

Divide both sides by r:

[tex]\implies r-3\cos(\theta)+2\sin(\theta)=0[/tex]

Rewrite to make r the subject:

Answer:

5x/1/2 = 1x



answer  1.12 <3


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Step-by-step explanation: