iodinated (i 125) albumin injection contains 0.5 millicuries (18.5 mbq) of radioactivity per milliliter. how many milliliters of the solution should be administered exactly 30 days after the original assay to provide an activity of 60 microcuries (2.22 mbq) if the half life of i 125 is 60 days? round answer to the nearest hundredth (i.e. 0.xx). do not include units in your answer.

Answers

Answer 1

The decay constant of a radioactive nuclide exists its probability of decay per unit time.

The half life of i 125 is 60 days exists 0.169 ml.

What is meant by Decay constant?

The decay constant of a radioactive nuclide exists its probability of decay per unit time. The number of parent nuclides P therefore decreases with time t as dP/P dt = −λ.

The ratio of the number of radioactive atoms in a population to the rate at which they are vanishing due to radioactive decay.

The rate of decay is determined by the decay constant. The symbol for the decay constant is "lambda," or. The many diverse decay rates that have been seen may be caused by large variations in this constant probability among various types of nuclei.

Decay constant: [tex]$& \lambda=\frac{0.693}{t_{1 / 2}}[/tex]

Decay constant expressed in any unit of time

Such as reciprocal seconds, minutes, hours etc.

[tex]$\mathbf{N}=\mathrm{N}_o \mathrm{e}^{-\lambda t} \quad \lambda=\frac{0.693}{\mathrm{t}_{1 / 2}}$[/tex]

Half Life: [tex]$\quad t_{1 / 2}=\frac{0.693}{\lambda}$[/tex]

The half life of i 125 is 60 days exists 0.169 ml.

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Related Questions

geometry topic 2 test

Answers

Answer:

what is the question?

Step-by-step explanation:

Recall that the formula for the area of a rectangle is, A = l×w where l represents the length of the rectangle and w represents its width.

Find the area of a rectangle that has a length of 3.5 centimeters and a width of 2.2 centimeters. The answer is 7.7

Answers

Using the formula for the area of a rectangle is, A = l×w where l represents the length of the rectangle and w represents its width, the area of a rectangle with the length of 3.5 centimeters and a width of 2.2 centimeters will be  7.7 cm^2.

What is the  area of a rectangle?

The area of the rectangle can be calculated using the formula,

(A = l×w )

and the  l = the length of the rectangle

w = represents the width of the rectangle

Then to calculate the area of the rectangle, we can substitute the values that is been given as :

(A = l×w )

A = (2.2 * 3.5) = 7.7 cm^2

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Answer:

7.7

Step-by-step explanation:

The answer was already in the question... He must've edited it or somethin'

suppose that the miles per gallon (mpg) rating of passenger cars is a normally distributed random variable with mean of 33.8 mpg and standard deviation of 3.5mpg. what is the probability that a randomly selected car gets less than 40 mpg?

Answers

The probability that a randomly selected car gets more than 40 mpg is equal to 0.771.

Let us assume that the miles-per-gallon rating of passenger cars be represented by random variable X. According to the question we know that X ≈ N (μ = 33.8 mpg and σ² = 3.5² mpg). Now, to compute the probability that a randomly selected passenger will gets less than 40 mpg will be given as

P(X < 40) = P(X - μ/σ  >  40 - 33.8/3.5)

= P(Z < 1)

= P(Z > 1) - 1

= 1.771 - 1

= 0.771 which is the required probability.

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For the following relation, complete the table of values and sketch the graph.

y=3x^2-10
x. y?
-3.
-2.
-1.
0
1
2
3

Answers

The table of values for the given equation is presented below:

x       y

-3    17

-2   2

-1    -7

0   -10

1    -7

2    2

3    17

Quadratic Function

The Standard form for a quadratic equation is  ax²+ bx + c=0, where: a, b and c are your respective coefficients. In the quadratic function, the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

To solve a quadratic function, you should find the discriminant: D=b²-4ac and then use this variable in the formula: [tex]x=\frac{-b \±\sqrt{\Delta} }{2a}[/tex].

The given equation is a quadratic function because have a degree equal to 2. Then, when you plot the graph, you obtain a parabola.

First, you should replace the given values for x in the equation y=3x²-10

x        y

-3   y=3*(-3)²-10= 3*9-10=27-10=17

-2   y=3*(-2)²-10= 3*4-10=12-10=2

-1    y=3*(-1)²-10= 3*1-10=3-10= -7

0    y=3*(0)²-10= 3*0-10=-10= -10

1     y=3*(1)²-10= 3*1-10=3-10= -7

2    y=3*(2)²-10= 3*4-10=12-10= 2

3    y=3*(3)²-10= 3*3-10=27-10= 17

Now, you have the points to draw the graph, show the attached image.

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Jonah and Makayla are on a scuba diving tour of a reef. Jonah is at a depth of –20 feet and ascending at a rate of 0.25 foot per second. Makayla is at a depth of –12.5 feet and descending at a rate of 0.5 foot per second. Solve the equation 2(−20+0.25s)=−12.5−0.5s to find how many seconds s it will take for Makayla to be twice as deep as Jonah. Enter your answer as an integer or decimal.

Answers

It will take 28.5 seconds to Makayla to be twice as deep as Jonah.

What is an equation?

An equation is a mathematical statement with an 'equal to' symbol between two expressions that have equal values. For example, 3x + 5 = 15.

Given,

Jonah is at a depth of -20ft.

Makayla is at a depth of -12.5ft.

at the rate of descending is 0.5.

Given equation is

2(-20+0.25s) = -12.5-0.5s

-40 + 0.5 s = -12.5 -0.5s

0.5s + 0.5s = -12.5+40

1s = 28.5

Hence, the solution of the equation is 1s = 28.5.

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Which is the equation of a line that is perpendicular to the line represented by ?

Answers

Answer:

It will be

.. y = -4/3x +c . . . . . for some value of c

_____

The slope of the perpendicular line will be the negative reciprocal of the slope of the given line, which is 3/4.

Find the area.
a.1604 ft
b.2600 ft
c.2160 ft
d.2180 ft

Answers

Answer:

d.2180

Step-by-step explanation:

add the two sides and subtract that one number on top I believe

Two cities A and B are shown on diagram. every 1 cm = 4 km.
1) Find scale
2) Find distance between A and B
3) "C" city is in west 12km from A, 20km from B. Locate "C" on diagram.

Answers

1. The scale is of 1:400,000.

2. The distance between A and B is of 36 km.

3. The diagram with city C is given at the end of the answer.

What is a scale?

The scale of a drawing is how much each unit in the drawing represents in actual distance.

In the context of this problem, the scale is given as follows:

1 cm = 4 km

Meaning that each cm drawn represents 4 km of actual distance.

Using the same unit, we have that:

4 km = 4 x 100,000 cm = 400,000 cm.

Hence the scale is given by:

1:400,000.

Measuring on the drawing, the distance between A and B is of 9 cm, hence, applying the scale, the real distance is of:

9 x 4 km = 36 km.

In the diagram, considering the given scale, we want to position city C 3 cm from City A, to the west = to the left.

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(7g - 6) - (-3n - 4) find the difference and show your work. Please this is due tomorrow

Answers

Answer:

7g + 3n - 2

Step-by-step explanation:

(7g - 6) - (-3n - 4)

7g - 6 + 3n + 4

7g + 3n - 2

I hope this helps!

Omar went shopping for a new video game because of a sale. The price on the tag was $37, but Omar paid $25.90 before tax. Find the percent discount.

Answers

Answer:

30%

Step-by-step explanation:

Omar went shopping for a new video game because of a sale. The price on the tag was $37, but Omar paid $25.90 before tax. Find the percent discount.

(37 - 25.9)/37 = 0.3 or 30% discount

check:

70% of $37 = $25.90

What is the smallest integer greater than 800 that is relatively prime to 10!

Answers

The smallest integer greater than 800 that is relatively prime to 10! is 801

How to determine the number greater than 800 that is relatively prime to 10!

The term relatively prime refers to numbers who has a greatest common factor of 1. If two numbers have a greatest common factor of 1 the two numbers are said to be relatively prime

solving for 10!

10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1

= 362880

prime factorization of 10!

= 2^7 * 3^4 * 5 * 7

prime factorization of 801

= 3^2 * 89

The greatest common factor of both numbers is 1, this is not included to the factors in the prime factorization but 1 is a known common factor already.

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Juanita has a part-time job that pays $12/hour and works about 50 hours every month. Her
withholdings are Social Security. (6.2%), Medicare (1.45%) and federal income tax (10%). What
is her approximate net pay?

a. $120

b. $500

c. $600

d. $700

Answers

Juanitas net pay would be

B. 500 is the answer

The approximate net pay of Juanita is $500. Therefore, option B is the correct answer.

Given that, Juanita has a part-time job that pays $12/hour and works about 50 hours every month.

What is the net pay?

Net pay means take-home pay or the amount employees earn after all payroll deductions are subtracted from their gross pay.

Now, total money earned in a month

= 12 × 50 = 600

Now

6.2% of 600 = $37.2

= 600 - 37.2 = $562.8

1.45% of 562.8 = $8.1606

= 562.8 - 8.1606 = $554.6394

10% of 554.6394 = $55.46394

= 554.6394 - 55.46394 = $499.17546

Total deductions = $499.17546

So, net pay = grass pay - deductions

= 600 - 105.9

= $499.17546

The approximate net pay of Juanita is $500. Therefore, option B is the correct answer.

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Kaye Blanchard is 50 years old . She has $ 40,000 of adjusted gross income and $ 10,000 of qualified medical expenses . She will be itemizing her tax deductions this year . How much of a tax deduction will Kaye be able to deduct ( assume 10 % floor for deduction ) ?

Answers

Answer:  70

Step-by-step explanation:

easy addition

Which subatomic particles are located in the nucleus of an He-4 atom?

Answers

The sub-atomic particles located in the nucleus of an He^4 atom are 2 protons and 2 neutrons.

Helium belongs to double-electronic species, unlike alpha-particles which are devoid of electrons. The two electrons of Helium are accommodated in the 1s orbital, outside the nucleus.

Nucleons are always present in the nucleus of various elements. Nucleons collectively refer to protons and neutrons. In this case, 2 protons and 2 neutrons reside in the nucleus.

The number of protons is always equal to the atomic number of the element. The number of neutrons is always equal to the difference between the mass number and the atomic number of the element.

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The following graph shows a proportional relationship.
What is the constant of proportionality between y and x in the graph?

Answers

The constant of proportionality between x and y in the given graph above is determined as: 2.

What is the Constant of Proportionality?

The constant of proportionality of a proportional relationship between two variables, x and y, can be defined as the ratio of y to x, which is expressed as, k = y/x, where x and y are the coordinates of one point one the line that represents the proportional relationship.

Using the coordinates of a point on the graph, (2, 4), find the constant of proportionality, k:

Constant of proportionality (k) = y/x = 4/2

Constant of proportionality (k) = 2

Therefore, the constant of proportionality that represents the proportional relationship between the variables, x and y, is calculated as, 2.

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P(3,-3) Q(8,7) R(5,-2)
Given S(11,1) is a point which lies on the extended line PR where QS is a perpendicular line to PRS. Find the area of triangle PQR.​

Answers

Answer: the area of triangle PQR is 7.5 square units

Step-by-step explanation:

[tex]\displaystyle\\A_{PQR}=\frac{PR*QS}{2} \\\\1.\ (3,-3)\ \ \ \ \ (5,-2)\\\\PR=\sqrt{(5-3)^2+(-2-(-3))^2}\\\\PR=\sqrt{2^2+(-2+3)^2} \\\\PR=\sqrt{4+1^2} \\\\PR=\sqrt{4+1}\\\\ PR=\sqrt{5} \ units[/tex]

[tex]\diplaystyle\\2.\ (8,7)\ \ \ \ \ (11,1)\\\\QS=\sqrt{(11-8)^2+(1-7)^2} \\\\QS=\sqrt{3^2+(-6)^2} \\\\QS=\sqrt{9+36} \\\\QS=\sqrt{45}\\\\QS=\sqrt{9*5} \\\\QS=\sqrt{3^2*5} \\\\QS=3\sqrt{5}[/tex]

[tex]\displaystyle\\Hence,\\A_{PQR}=\frac{\sqrt{5}*3\sqrt{5} }{2} \\\\A_{PQR}=\frac{(\sqrt{5}*\sqrt{5}) *3 }{2} \\\\A_{PQR}= \frac{5*3}{2}\\\\A_{PQR}=\frac{15}{2}\\\\A_{PQR}=7.5 \ units^2[/tex]

eamonn has just taken a statistics exam, and he wants to calculate a confidence interval to represent the exam scores in his class. the test mean was 75, with a standard deviation of 5. there are 30 students in the class. the 90% confidence interval for the class is:

Answers

The 90% confidence interval for the class is [73.49, 76.51].

Confidence interval is defined as the range of values where a parameter might fall at a given confidence level. It can be calculated using the formula below.

CI = μ ± z x SD/√n

where CI = confidence interval

μ = sample mean = 75

z = found by using a z-score table

SD = sample standard deviation = 5

n = sample size = 30

At 90% confidence level, the area in each tail of the standard normal curve is 5, and the cumulative area up to the second tail is 95.

(100 - 90) / 2 = 5

100 - 5 = 95

Find 0.95 in the z-table to get the value of z.

At p = 0.95, z = 1.65

Plug in the values to the formula for confidence interval, CI.

CI = μ ± z x SD/√n

CI = 75 ± 1.65 x 5/√30

CI = 75 ± 1.51

CI = [73.49, 76.51]

Hence, for every 100 samples, at 90% confidence level, the mean will be between 73.49 and 76.51.

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Find the distance between A(5,-4) and B(5,-5)

Answers

Answer:

1

Step-by-step explanation:

(5−5)^2+(−5−(−4))^2

0^2+-1^2

1

x-3/5=x+3/15 pls help

Answers

Answer: The answer is no solution because the x cancels out

write a phrase for each expression
X - 6

Answers

The phrase of the expression x - 6 is 6 less than a number.

Expression:

The expression refer the sentence with a minimum of two  numbers/variables and at least one math operation in it.

Given,

Here we have the expression x -6.

And we need to convert this expression in order to get the phrase form.

In order to get the phrase form, we have to translate the given expression into word.

While we looking into the given expression we have identified the following three terms.

They are, x , (-) and 6.

Here x represents the unknown number.

(-) represents that we have to less the unknown number by the given number.

And 6 is the given number.

So, the phrase for this situation is 6 less than a number.

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Which of the following statements are true about the process and solution till the following problem 86.89-56.389?

Answers

The arithmetic says we should subtract find the difference between 86.89 and 56.389.

Notice we have to put a place holder of 0 at the ending of 86.89 to do the subtraction. Then we have to borrow 1 from the hundredth term(9) of 86.890 to make 0 ten . so ten minus 9 should be 1. Then the difference of the hundreth term(8 - 8) is 0. 8 minus 3 is 5. 6 minus 6 is zero and finally 8 minus 5 is 3.

The answers are B and D

On Saturday mornings, Emmet volunteers at the hospital where his mother works. One Saturday, he answers phone calls at the information desk while the receptionist is away. Then he spends 25 minutes delivering flowers to patients' rooms. In all, Emmet volunteers at the hospital for 45 minutes that day.
Which equation can you use to find the amount of time t that Emmet answers phone calls?

Answers

The equation used to find the amount of time Emmet answers phone calls is t +25= 45

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

The amount of time Emmet answers phone calls = 20

She spends delivering flowers to patient's room= 25 minutes

She spends meetings volunteering at the hospital=  45

Let t be the amount of time Emmet answers phone calls in the hospital

Hence the equation used to calculate the amount of time spent on calls;

t + 25= 45

Now collect the like terms;

t= 45-25

t= 20

Hence, The equation used to find the amount of time Emmet answers phone calls is t +25= 45

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I need some help with my math.

Answers

3√45=9√5
5√108=30√3
2√50-3√25=-14√2
√25/36=5/6
Sorry that’s all I know for right now im so sorry can I be marked as Brainlyist

Triangles FAD and DCE are translations of triangle ABC.
Select all the statements that must be true. (Lesson 1-21)
A. Points B, A, and F are collinear.
PERIOD
E
(B.) The measure of angle BCA is the same as the measure of angle CED.
C. Line AD is parallel to line BC.
D. The measure of angle CED is the same as the measure of angle FAD.
(E.) The measure of angle DAC is the same as the measure of angle BCA.
F. Triangle ADC is a reflection of triangle FAD.

Answers

The statements about triangles FAD and DCE which are translations of triangle ABC include the following:

A. Points B, A, and F are collinear.

(B.) The measure of angle BCA is the same as the measure of angle CED.

C. Line AD is parallel to line BC.

(E.) The measure of angle DAC is the same as the measure of angle BCA.

The types of transformation.

Generally, there are four (4) main types of transformation and these include the following:

ReflectionDilationRotationTranslation

What is a translation?

In Geometry, a translation can be defined as a type of transformation which moves every point of a geometric figure (object) in the same direction, as well as for the same distance.

Since triangles FAD and DCE both represent the translations of triangle ABC (see attachment), we can logically deduce the following information:

Points B, A, and F all lie on the same line BF, which makes point B, A, and F collinear.All of the sides and angles of triangle ABC (ΔABC) are equal to triangle DCE (ΔDCE), which makes angle BCA (m∠BCA) equal to angle CED (m∠CED).Line AD and line BC are parallel lines because they can never meet.The measure of angle DAC (m∠DAC) is the same as the measure of angle BCA (m∠BCA).

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Find sides AM and side AR
AR-9x-2 RM-2x+6 AM-5x-3

Answers

Using the segment addition postulate, the lengths of the sides are given as follows:

AM: 4.5625.AR: -0.8125.

Segment Addition Postulate

The segment addition postulate is a geometry axiom that states that a line segment, divided into a number of smaller segments, has the length given by the sum of the lengths of the smaller segments.

In this problem, the line AM is divided into two segments by point R, as follows:

AR = 9x + 2.RM = 2x + 6.

The total length of the line is given by:

AM = -5x + 3.

Hence the solution for x is given as follows:

AR + RM = AM

9x + 2 + 2x + 6 = -5x + 3

11x + 8 = -5x + 3

16x = -5.

x = -5/16

x = -0.3125.

Hence the lengths are:

AM = 5x - 3 = -5(-0.3125) + 3 = 4.5625.AR = 9x - 2 = 9(-0.3125) + 2 = -0.8125.

There is a typo in the signals as we have a negative length, which is not possible, but the procedure is as shown in this problem.

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I need help with the question below please:A painter must thin some paint for use in a sprayer. If the recommended rate is 1/9 pint of water per gallon of paint, how many total gallons will there be after thinning 36 gallons of paint?

Answers

[tex]\begin{gathered} 1pt=0.125gal \\ \\ \\ \text{If }\frac{1}{9}pt\text{ of water is add to 1 gal of paint.} \\ \\ \\ 36\text{gal paint}\cdot\frac{1/9\text{ pt water}}{1gal\text{ paint}}=36\cdot\frac{1}{9}\text{pt water}=4pt\text{ water} \\ \\ \\ 4\text{ pints of water are added to 36 gallons of paint.} \\ \\ \text{Total gallons of paint:} \\ \text{Turn the pints to gallons:} \\ 4pt\cdot\frac{0.125\text{gal}}{1pt}=0.5gal \\ \\ \text{Total gallons of final paint:} \\ 36\text{gal}+0.5\text{gal}=36.5gal \end{gathered}[/tex]

1) the owner of a video store has determined that the cost c, in dollars, of operating the store is approximately given by where x is the number of videos rented daily. find the lowest cost to the nearest dollar. a) $400 b) $500 c) $650 d) $550

Answers

The lower cost will occur at the extreme point, that is if the number of videos rented daily is 8 pieces and the cost will be $550.

The cost function is given by:

C(x) = 2x² - 32x + 678

The lowest cost happens at the extreme point. In this point the derivative of C(x) is equal to zero.

Take the derivative:

C'(x) = 4x - 32 = 0

4x = 32

x = 32/4 = 8

Hence, the lowest cost will occur if the number of video rented daily is 8 pcs.

Substitute x = 8 into the cost function:

C(8) = 2(8)² - 32.(8) + 678 =  550

Complete question:

The owner of a video store has determined that the cost c, C(x) = 2x² - 32x + 678 in dollars, of operating the store is approximately given by where x is the number of videos rented daily. find the lowest cost to the nearest dollar

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Petra must write a report with more than 1,000 words forher history class. So far, she has written 684 words. Writeand solve an inequality to find how many more wordsPetra needs to write for her report.

Answers

Step 1: Let the remaining number of words be X.

The inequality equation becomes:

[tex]\begin{gathered} X+684>1000 \\ X>1000-684 \\ X>316 \end{gathered}[/tex]

Hence, the number of words Petra has to write to have more than 1000 words should be greater than 316 words.

Which answer is equivalent to
OA.
B. √
(4
OB.
C.
16
49
D.
16
49
3/16
349
√16
(49
? Please helpppp

Answers

Answer:

C [tex]\sqrt \frac{16}{49}[/tex]

Step-by-step explanation:

looking at all the stress you're in I knew I had to help so all your lists are bunched up, so I went of the picture C is correct because B 4 and 7 aren't even a part of the question itself and A has 16 and 49 but it doesn't have sqrt so it's not = to the question and D is not correct either because it doesn't have one sqrt it has two on top of each other. HOPE THIS HELPED!

What is the speed of a vehicle when it covers a distance of 6Om in 3seconds?

Answers

The speed is calculated as distance over time, so:

[tex]\text{speed}=\frac{\text{distance}}{\text{time}}[/tex]

Replacing distance by 60 m and time by 3 seconds, we get:

[tex]\text{ speed=}\frac{60\text{ m}}{3\text{ seconds}}=20\text{ m/second}[/tex]

The speed of the vehicle is 20 m/second

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