force = 100 N
Impulse ( N.s ) : Force ( N ) * Time ( s )⇒ 100 N.s = force * 1 s
⇒ force = 100/1
⇒ force = 100 N
Answer :-
The required Force is 100 Newton .Explanation :-
As per the provided information in the given question, we have been given that the Impulse of the Object is 100 Ns . It's Time is given as 1 sec . And, we have been asked to calculate the Force .
For calculating the Force , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed {\sf { \: Force \: = \: \dfrac {Impulse}{Time} \: }} [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \sf {Force \: = \: \dfrac {Impulse}{Time}} [/tex]
[tex] \Longrightarrow \: \: \: \sf {Force \: = \: \dfrac {100}{1}} [/tex]
[tex] \Longrightarrow \: \: \: \textbf {\textsf {Force \: = \: 100}} [/tex]
Hence :-
Force = 100 Newton .[tex] \underline {\rule {180pt}{4pt}} [/tex]
It is diffult to measure the volume of gas.Why?
Answer:
The volume of a gas is dependent on pressure and temperature.
Explanation:
Pressure and temperature affect different gases differently giving varied conclusions to the exact volume of that gas.
:-befrank
What are the nicknames for the planets in our solar system?
Answer:
History of the 9 Planets in our solar system The ancient Greeks came across seven lights in the sky that moved against the background pattern of stars: the sun, the moon, Mercury, Venus , Mars, Jupiter, and Saturn. then they decided to name them Planetes, or Wanderers.
Explanation:
A planet is a celestial body. The nickname for the earth is "blue planet".
What is a planet?A celestial body is differentiated from the fixed stars by its apparent mobility (including the moon and sun), especially in relation to its claimed impact on people and events.
The nicknames for the planets in our solar system are:
Swift Planet for Mercury, Morning Star and Evening Star for Venus, Blue Planet for Earth, Red Planet for Mars, Giant Planet for Jupiter, Ringed Planet for Saturn, Ice Giant for Uranus,Big Blue Planet for Neptune.Learn more about Planet:
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Which of the following can be used to measure temperature accurately
Celsius
Fahrenheit
Kelvin
All of these are correct
Answer:
Any of those terms can be converted to either of the other terms, so either term is correct. People are accustomed to everyday temperatures in Fahrenheit. The ideal gas law specifies that
P V = N R T where T is in Kelvin which is Celsius + 273 deg.
Pls answer this questions
Reagan rides on a playground roundabout with a radius of 2. 5 feet. To the nearest foot, how far does reagan travel over an angle of 4π3radians? ______ ft
Answer:
S = θ R where S is the arc length and θ the arc length in radians
S = 2.5 ft * 4 π^3 rad = 2.5 * 124 = 310 ft (1 radian = 2.5 ft)
Assuming 4π3 means 4π^3
The Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.
What is a circle?It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).
We have Reagan rides on a playground roundabout with a radius of 2.5 feet.
We know the relation between arc length and radius of the circle:
S = R∅
Here R = 2.5 feet, and central angle ∅ = 4π/3
[tex]\rm S = 2.5\times \frac{4\pi}{3}[/tex]
S = 10.47 feet ≈ 10 feet
Thus, the Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.
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Suppose you have a 100 mhz cpu and a a/d converter with an 8 khz sampling rate. Samples of the a/d converter are 32-bits
The sampling rate that's given regarding the CPU will produce a rate of 256kps.
How to calculate the rate?The following can be gotten from the question:
Sampling rate = 8KHx
Number of bits = 32
The data rate will be:
= 32 × 8kbps
= 256kps
In conclusion, the sampling rate that's given regarding the CPU will produce a rate of 256kps.
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The sampling rate specified for the CPU will result in a 256kb/s rate.Sampling rate is also known as the sampling frequency.
What is sampling rate?The number of samples per second collected from a continuous signal to create a discrete or digital signal is referred to as sampling rate or sampling frequency.
The given data in the problem is;
Sampling rate= 100 mhz cpu
Number of bits=32
The rate of the data is;
[tex]\rm R = 32 \times 8 kb/ s \\\\ \rm R = 256 kb / s \\\\[/tex]
Hence the sampling rate specified for the CPU will result in a 256kb/s rate.
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Phys-1A Horizontal Practice 2
Ground-to-Ground Equations
Horizontal Equations
Vicos
Vertical Equations
sin
ay earth).-9.8 m/s
Horizontal Launch Equations
Horizontal Equations
Vertical Equational
Velocity-as-Hits:
wv * , te
Use. Pythagorean Range
and tan (9)
Show work/use units !!
1. For each problem, solve for "?" and "?", and Velocity-as-it-Mits. Circle your final answers with units.
2.26, 226, 24.3 65.7
Vf, V+ay.t
wh25
V4.0
(Pythag. +
7+17,
tan
Velocity-as-Hits -
2. For each problem, solve for "7" and "?", and Velocity-as-it-Hits Circle your final answers with units.
2.02,742, 21.1 69.5
W.77
VF, VI+ ayt
VF,
Mercede
(Pythag.+ v
tan
Velocity-as-Hits -
What is current of 12 ohm? help me pleasee
1. 0.25 A
2. 0.5 A
3. 1 A
4. 1.5 A
5. 2 A
please show solution.
Answer:
the current is 5.2 Amps
a car of mass 850kg hits a crash barrier at a speed of 30m/s . the car stops in 0.4s.calculate the force of the car.
During the collision an impulse is created which due to which is equal to change in momentum.
Mathematically,
[tex]\green{ \underline { \boxed{ \sf{Impulse, F\times t = m (v-u) }}}}[/tex]
where
F = forcet = time span m = massv= final speedu = initial speedNow,
[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times (0-30) \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times -30 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf F = -\frac{25500}{0.4} \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf F = -63750 N \\\end{gathered} [/tex]
[tex]\quad\quad\quad\quad\quad\quad[/tex](-ve sign denotes opposite direction)
Therefore, a force of 63750 Newton will act on the car in opposite direction.
What causes changes in the orbit of objects in the solar system.
Explain diffraction at a single slit (light)
Answer:
At some point on say, the receiving screen, light emanating from the left side of the slit will be out of phase (a difference of 1/2 wavelengths) from light coming from the center of the slit.
Thus for every point that is left of the center of the slit, there will be a point on the right side of the slit that is out of phase,
There will be no light on the screen at that particular point and thus there will be a dark fringe there.
That is the basic explanation for the appearance of dark and bright fringes on the receiving screen.
A 0. 5 kg mass on a 1-m-long string swings in a circle on a horizontal, frictionless table at a steady speed of 2 m/s. How much work does the tension in the string do on the mass during one revolution?
The tension does no (zero) work
F· S = W
Since the tension is perpendicular to the direction of motion, and there is no change in S the work done is zero.
What units are appropriate to express specific heat?.
Answer:
The units for specific heat can either be joules per gram per degree (J/goC) or calories per gram per degree
Explanation:
A solid sphere is released from the top of a ramp that is at a height
h1 = 2.20 m.
It rolls down the ramp without slipping. The bottom of the ramp is at a height of
h2 = 1.87 m
above the floor. The edge of the ramp is a short horizontal section from which the ball leaves to land on the floor. The diameter of the ball is 0.14 m.
a.) Through what horizontal distance d, in meters, does the ball travel before landing?
b.) How many revolutions does the ball make during its fall?
Hi there!
We can use the work-energy theorem and apply it to this situation.
At the top of the ramp, the ball only has gravitational potential energy, and at the bottom of the ramp, the ball has BOTH translational and rotational kinetic energy.
We must use the following equations:
[tex]GPE = mgh \\KE_T = \frac{1}{2}mv^2\\\\KE_R = \frac{1}{2}I \omega^2[/tex]
m = mass of sphere (kg)
g = acceleration due to gravity (m/s²)
h = height of ramp (m)
v = final velocity (m/s)
I = Moment of Inertia (kgm²)
ω = angular velocity (rad/sec)
Since:
[tex]E_i = E_f\\\\mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega ^2[/tex]
In order to make things easier, since the ball is not slipping, we can relate angular velocity to translational velocity:
[tex]\omega = \frac{v}{r}[/tex]
Also, recall the equation for the moment of inertia for a solid sphere:
[tex]I = \frac{2}{5}mr^2[/tex]
We can use these to simply our equation:
[tex]KE_R = \frac{1}{2}(\frac{2}{5}mr^2)(\frac{v}{r})^2 = \frac{1}{5}mv^2[/tex]
Now, we can rewrite the equation and solve for 'v'.
[tex]mgh = \frac{1}{2}mv^2 + \frac{1}{5}mv^2\\\\mgh = \frac{7}{10}mv^2\\\\v = \sqrt{\frac{10gh}{7}} = \sqrt{\frac{10(9.8)(2.2 - 1.87)}{7}} = 2.149\frac{m}{s}[/tex]
a)
We can begin by solving for the time taken for the ball to land on the ground. The ball only has a horizontal velocity, so this is essentially a free-fall situation. Use the rearranged kinematic equation:
[tex]t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2(1.87)}{9.8}} = .6178 s[/tex]
Now, use the following equation to solve for horizontal distance given horizontal velocity and time:
[tex]d_x = v_x t\\\\d_x = 2.149 * .6178 = \boxed{1.328 m}[/tex]
b)
We can use the previously-stated relationship between translational and angular velocity to solve for the angular velocity.
[tex]\omega = \frac{v}{r}[/tex]
It is given that the diameter is 0.14 m, so the radius is 1/2th the diameter, or 0.07 m.
Solve for the angular velocity:
[tex]\omega = \frac{2.149}{0.07} = 30.706 \frac{rad}{sec}}[/tex]
Using the above fall time and dimensional analysis to convert from rad/sec to revolutions, we can solve for the # of revolutions made by the ball:
[tex]\frac{30.706rad}{sec} * .6178 sec * \frac{1 rev}{2\pi rad} = \boxed{3.019 rev}[/tex]
A car’s tire rotates 5.25 times in 3 seconds. What is the tangential velocity of the tire?
The tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire which is 11(r) m/s.
Angular velocity of the tireThe angular velocity of the tire is the rate of change of angular displacement of the tire with time.
The magnitude of the angular velocity of the tire is calculated as follows;
ω = 2πN
where;
N is the number of revolutions per secondω = 2π x (5.25 / 3)
ω = 11 rad/s
Tangential velocity of the tireThe tangential velocity of the car's tire is the product of the angular velocity and radius of the car's tire.
The magnitude of the tangential velocity is caculated as follows;
v = ωr
where;
r is the radius of the car's tirev = 11r m/s
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Before beginning an experiment, mrs. wilson warns her science class not to drop the bar magnets on the floor. what is the most likely reason for mrs. wilson’s warning? the magnet might lose its magnetism. the magnet might make a startling noise. the magnet might become stuck to the floor. the magnet might cause the floor to become magnetic.
The most likely reason for Mrs. Wilson's warning will be the magnet might lose its magnetism.
What is magnetism?Magnetism is a component of the larger phenomena of electromagnetic. The most well-known effects occur in ferromagnetic materials,
Which are highly attracted by magnetic fields and maybe magnetized to become permanent magnets, hence creating magnetic fields. It is also feasible to demagnetize a magnet.
We should not drop a magnet on the floor since magnets progressively lose magnetism and grow weak over time if they are not properly preserved.
Hence this is most likely the reason for Mrs. Wilson's warning will be the magnet might lose its magnetism.
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Answer:
The correct answer is A!
Explanation:
~Hope this helps! :)
Which kind of wave moves back and forth along the direction of the wave?.
sitting at rest on top of a spring with a spring constant of 10N /m. the spring is compressed 5m
Answer:
50N
Explanation:
this is because 5×10all over 100 ,0 will cancile 0 remaining 10 ,1 into 10 ,10times ,so 5×10 =50N
the north pole magnet is brought near a refrigerator door , and the magnet sticks. if the magnet is removed and the south pole is brought near the door instead, will it also stick explain
Answer:
no
Explanation:
because if the north pole of the magnet is brought the the refrigerator and it sticks that means the refrigerator is the south pole. So if the south pole magnet is brought the the refrigerator that is also a south pole it would not stick because same poles repel and opposite poles attract.
What is another name for coal, natural gas, and oil? (two words)
The answer is fossil fuel
its formed from the remains of ancient plants and animalHope it helps!
The answer is fossil fuel
In what type of system is mechanical energy lost to its surroundings?
A. internal
B. external
C. closed
D. open
Answer:
open
Explanation:
in open system mechanical energy is lost to its surroundings
what other fees are associated with each credit card
Answer:
Finance costs (also known as interest fees) aren't added to your account in a set amount like other fees.
OR
A credit card is a payment card that is issued to users to allow them to pay a merchant for products and services depending on their outstanding debt. The card issuer opens a revolving account for the cardholder and provides a line of credit from which the cardholder can borrow money to pay a merchant or get a cash advance. Consumer credit cards and business credit cards are the two types of credit cards available. The majority of the cards are plastic, however, there are a few metals and gemstone-encrusted metal cards.
Explanation:
Find fff, the magnitude of the force applied to each side of the nutcracker required to crack the nut
Force is a vector, as such we know that the force required to crack a nut is the resultant of the individual forces applied form all sides of the nut.
What is force?The term force is used to describe that which causes a change in the position of an object. Now the question is incomplete but I will try to help you the much I can.
Recall that force is a vector quantity. Hence the magnitude of the force required to crack a nut is the resultant of the individual forces applied form all sides of the nut.
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3. Three lightbulbs are connected in a series. A switch is placed between the first lightbulb and the second lightbulb. If that
switch is opened, what happens to each of the three lightbulbs?
Please help explanation
In series connection the current flow remains constant
If switch is placed between first and second lightbulbThen if it's turned on. the three bulbs will be lighted up with same currentAn object is in simple harmonic motion of the following quantities related to the object, which set of three can have maximum
magnitudes at the same instant of time?
i. displacement
ii. velocity
iii. acceleration
iv. kinetic energy
v. potential energy
Answer:
displacement, acceleration, potential energy
Explanation:
pretty sure this is correct but dont hold me to it.
The set of three that can have maximum magnitudes at the same instant of time will be displacement, acceleration, and potential energy.
What is simple harmonic motion?Simple harmonic motion is periodic motion caused by a restoring force that is proportionate to the deviation from equilibrium.
Simple harmonic motion is periodic motion but many other conditions are dependent.
The object is in simple harmonic motion of the following quantities related to the object.
The set of three that can have maximum magnitudes at the same instant of time will be displacement, acceleration, and potential energy.
Hence the set of three quantities is the options i, iii,v.
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The velocity of a car increases by 40 m/s in 80 seconds. What is the
acceleration of the car?
A. 40 m/s2
B. 0.5 m/s2
C. 120 m/s2
D. 0.25 m/s2
Answer:
B
Explanation:
a=v/t
a=(40m/s)÷(80s)
a=0.5m/s
A car of 15 kg is traveling on a circular track. If the radius of the track is
7. 8 m and the period is 8. 5 seconds, what's the centripetal force on
the car? (Round to the nearest hundredth)
The magnitude of the centripetal force on the car is 69.6 N.
What is centripetal force?This is a force acting on a body in circular path and it is directed to the center around which the body is moving.
To calculate the centripetal force on the car, we use the formula below.
Formula:
F = m(4π²/t²)........ equation 1Where:
F = Magnitude of the centripetal force on the car, m = mass of the cart = timeFrom the question,
Given:
m = 15 kgt = 8.5π = 3.14Substitute these values into equation 1
F = 15(4×3.14²/8.5²)F = 69.6 NHence, the magnitude of the centripetal force on the car is 69.6 N.
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If a train going 60 m/s hits the brakes, and it takes the train 85 seconds to stop, what is
the train's acceleration?
Question :-
If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?Answer :-
Acceleration of Train is 0.70 m/s² .Explanation :-
As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .
For calculating the Acceleration , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ [/tex]
Where ,
V denotes to Final Velocity .U denotes to Initial Velocity .T denotes to Time Taken .Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ [/tex]
[tex] \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ [/tex]
[tex] \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ [/tex]
[tex] \longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }} [/tex]
Hence :-
Acceleration = 0.70 m/s² .[tex] \underline {\rule {210pt} {4pt}} [/tex]
Note :-
Kindly Scroll the Screen from Right to Left for Better View .Answer:
Question :-
If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?
Answer :-
Acceleration of Train is 0.70 m/s² .
Explanation :-
As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .
For calculating the Acceleration , we will use the Formula :-
\begin{gathered} \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ \end{gathered}
★
Acceleration=
t
v−u
Where ,
V denotes to Final Velocity .
U denotes to Initial Velocity .
T denotes to Time Taken .
Therefore , by Substituting the given values in the above Formula :-
\begin{gathered} \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ \end{gathered}
†Acceleration=
Time
FinalVelocity−InitialVelocity
\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ \end{gathered}
⟼Acceleration=
85
0−60
\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ \end{gathered}
⟼Acceleration=
85
60
\longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }}⟼Acceleration = 0.70
Hence :-
Acceleration = 0.70 m/s² .
\underline {\rule {210pt} {4pt}}
Note :-
Kindly Scroll the Screen from Right to Left for Better View .
Does the buoyant force on a submerged object depend on the volume of the object or on the weight of the object?.
Answer:
The buoyant force on a submerged object depends upon the volume of the object.
Explanation:
What is the distance a spring is compressed if the spring constant is 10 m/n, and a force
of 25 n is applied?
Answer:
40n
Explanation:
10×25 all over 100 ,25 into hundred 4 times 10×4 =40n