If the distance from the Earth’s center to the Moon’s center were suddenly doubled, what would occur to the gravitational force between them?
(A) Gravitational force would decrease by a factor of 4.
(B) Gravitational force would increase by a factor of 4.
(C) Gravitational force would decrease by a factor of 2.
(D) Gravitational force would increase by a factor of 2.

Answer:

Displacement is 42.426 m NE and the angle is opposite/adjacent or 30/30 which would equal 1 degree which doesn't seem right but hopefully its an answer.

Explanation:

Answer: A,B, and E

Explanation: Just checked I got them right:)

Answer:

huh

Explanation:

Answer:

The horizontal component of the velocity is approximately 13.22 m/s

Explanation:

The velocity of the kick which the football player gives the ball = 21 m/s

The angle of the path taken by the ball = 51°

The velocity can be represented vectorially, showing the vertical and horizontal components as follows;

v = 21 × cos(51°)·[tex]\hat i[/tex] + 21 × sin(51°)·[tex]\hat j[/tex]

Where we have;

The horizontal component of the velocity = 21 × cos(51°)

The vertical component of the velocity = 21 × sin(51°)

Therefore;

The horizontal component of the velocity = 21 × cos(51°) ≈ 13.22 m/s

The horizontal component of the velocity ≈ 13.22 m/s.

Answer:

Problem 1-

The acceleration = 5 m/s²

Problem 2 -

The acceleration = 3.[tex]\overline 3[/tex] m/s²

Problem 3 -

The acceleration = 2.5 m/s²

Problem 4-

The force applied = 7.5 N

Problem 5-

The mass of the object,  = 0.5 kg.

Explanation:

Problem 1-

The mass of the ball, m = 0.5 kg

The force (applied) with which it was hit, F = 2.5 N

The acceleration, a = Force/Mass = 2.5 N/(0.5 kg) = 5 m/s²

The acceleration = 5 m/s²

Problem 2 -

The mass of the box, m = 15 kg

The force (applied) with which it was hit, F = 50 N

The acceleration, a = Force/Mass = 50 N/(15 kg) = 10/3 = 3.[tex]\overline 3[/tex] m/s²

The acceleration = 3.[tex]\overline 3[/tex] m/s²

Problem 3 -

The mass of the object, m = 2.0 kg

The force (applied) with which it was hit, F = 5.0 N

The acceleration, a = Force/Mass = 5.0 N/(2.0 kg) = 2.5 m/s²

The acceleration = 2.5 m/s²

Problem 4-

The mass of the object, m = 3.0 kg

The acceleration, a, of the object = 2.5 m/s²

The force applied to it, F = Mass × Acceleration = 3.0 kg × 2.5 m/s² = 7.5 N

The force applied = 7.5 N

Problem 5-

The acceleration, a, of the object = 12 m/s²

The force applied, F = 6.0 N

The mass of the object, m = Force/Acceleration = 6.0 N/(12 m/s²) = 0.5 kg

The mass of the object,  = 0.5 kg.

Answer:

A magnetic force can convert kinetic energy stored in a magnetic field to potential energy. Kinetic energy can convert potential energy stored in a gravitational field. A magnetic energy can convert potential energy stored in a gravitational field to kinetic energy.

Answer:

50 or 1.3333

Explanation: Explanation you cancel out the mass and the force to see what your acceleration would be or you could divide F by M

Answer:

The components of the net force acting on the cart are;

Horizontal force, Fₓ ≈ 23.5 N acting east

The vertical force, [tex]F_y[/tex] ≈ 76.96 N

Explanation:

The parameters given in the question are;

The magnitude of the force on the rope acting horizontally to the west = 75 N

The magnitude of the force on the other rope east acting at an angle to the horizontal = 125 N

The angle to the horizontal of the force on the other rope east to the horizontal = 38°

Therefore, we have;

The horizontal component of the force acting east = 125 × cos(38°) ≈ 98.5 N

The net sum of the horizontal forces, ∑Fₓ noting that the horizontal forces are acting in opposite direction is given as follows;

∑Fₓ = 75 - 125 × cos(38°) = 75 - 98.3 = -23.5N

Given that the difference in forces is negative, and hat we took the force acting east as negative, we have that the net horizontal force is acting east with a horizontal component of 23.5N

The net vertical force, ∑F[tex]_y[/tex], is given as follows;

∑F[tex]_y[/tex] = 125 × sin(38°) ≈ 76.96 N

Therefore, the components of the net force acting on the cart are;

Horizontal force, Fₓ ≈ 23.5 N, the vertical force, [tex]F_y[/tex] ≈ 76.96 N

The components of the net force on the cart are 23.5 Newton and 76.96 Newton.

Given the following data:

To find the components of the net force on the cart:

First of all, we would determine the horizontal component of the force acting due east.

[tex]F_y = Fcos(\theta)\\\\F_y = 125cos(38)\\\\F_y = 125 \times 0.7880\\\\F_y = 98.5 \; Newton[/tex]

Next, we would find the resultant horizontal forces:

[tex]\sum F_y = F + F_y\\\\\sum F_y = 75 + (- 98.5)\\\\\sum F_y = -23.5 \;Newton[/tex]

Therefore, the horizontal component of the net force acts in the opposite direction due east.

Horizontal component of the net force = 23.5 Newton

For the vertical component of the net force:

[tex]\sum F_x = Fsin(\theta)\\\\\sum F_x = 125cos(38)\\\\ \sum F_x = 125 \times 0.6157\\\\ \sum F_x = 76.96\; Newton[/tex]

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Answer:

The parachute to open in 15 sec.

Explanation:

Given that,

Velocity = 120 km/hr

Height = 1000 m

If his parachute must open 500. m above the ground.

We need to calculate the time for parachute to open

Using formula of time

[tex]v=\dfrac{d}{t}[/tex]

[tex]t=\dfrac{d}{v}[/tex]

Where, d = distance

t = time

v = velocity

Put the value into the formula

[tex]t=\dfrac{500}{120\times\dfrac{5}{18}}[/tex]

[tex]t=15\ sec[/tex]

Hence, The parachute will be open in 15 sec.

Answer:

[tex]a=-1.388\ m/s^2[/tex]

Explanation:

Initial velocity of car, u = 50 km/h = 13.88 m/s

It stops, v = 0

Time, t = 10 s

We need to find the car's deceleration while slowing down. As the car is slowing down, it will have deceleration. It can be calculated as follows :

[tex]a=\dfrac{v-u}{t}\\\\a=\dfrac{0-13.88 }{10}\\\\a=-1.388\ m/s^2[/tex]

So, the deceleration of the car is [tex]1.388\ m/s^2[/tex].

Answer:

B) Decreases

Explanation:

Gravitational force is inversely proportional to distance. As distance between 2 objects increase, gravitational force between the 2 objects decreases.

Hope this helps!

Answer:

The answer would be B

Explanation:

Answer: B. Evolution

Explanation:

As species grow older over time they will gradually evolve through natural selection and evolution.

The gradual change in a species over time is known as evolution (b).

The process of evolution occurs through several mechanisms, including mutation, migration, and natural selection.

Mutation (a) is the spontaneous change in the genetic material of an organism. These changes can result in new traits that may be advantageous, disadvantageous, or neutral for survival. When mutations occur, they can introduce genetic variation within a population, which serves as the raw material for evolution.

Natural selection is a crucial factor driving evolution. Individuals with advantageous traits that better suit their environment are more likely to survive and reproduce, passing on these advantageous traits to their offspring. Over generations, the frequency of beneficial traits increases in the population, leading to the adaptation and evolution of the species.

Variation (d) encompasses the differences in physical traits and genetic makeup among individuals within a population. This variation is essential for evolution to occur since it provides the raw material for natural selection to act upon.

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Answer:

The law of conservation of energy states that energy can neither be created nor destroyed - only converted from one form of energy to another. This means that a system always has the same amount of energy, unless it's added from the outside. This is particularly confusing in the case of non-conservative forces, where energy is converted from mechanical energy into thermal energy, but the overall energy does remain the same. The only way to use energy is to transform energy from one form to another.

Explanation:

Hope this helps!

Answer:

means that energy can neither be created nor destroyed; rather, it can only be transformed or transferred from one form to another.

Explanation: this is a shorter answer.

Answer:

serial in which container is filled

Solid -base of container

Liquid- above solid

Gas- above liquid

Explanation:

If any mixture of  matter in different state (that solid , liquid or gas )are kept in any container, then substance with higher density will be settled at lowest surface first and similarly the substance with lowest density will be at upper part of container.

In the given container we have to keep solid, liquid and gas

based on this

solid will be at surface of container

above sold will be liquid

above liquid will be presence of Gas

serial in which container is filled

Solid -base of container

Liquid- above solid

Gas- above liquid

Answer: Got this from a web search... Change the answer up a bit

Explanation:

The distance travelled is the path taken by a body to get from an initial point to an end point in a given period of time, at a certain velocity. If the velocity is constant: Distance = time * velocity. d = v*t.

Answer:

I researched and found it to be TIME * VELOCITY ( d= v*t)

Explanation:

When I use * I just mean multiply. So its time 'multiplied by velocity' in order to get 'distance'

Answer:

The focus of Lesson 1 is Newton's first law of motion - sometimes referred to as the law of inertia. Newton's first law of motion is often stated as. An object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

Explanation:

Answer:

Newton's first law is also called the law of Inertia.

Explanation:

The property of a body by virtue of which it wants to remain in its position, is called inertia.

Mainly there ae three types of inertia-

Inertia was discovered by Galileo and it was modified by Newton.

If a body is in motion or in rest, it wants to remain in its position unless any external force is applied.

Thus Newton's first law of motion is also called law of inertia.

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Answer:

1) and 2)

Explanation:

Hydrogen fuel is very efficient. More energy is extracted from this fuel source than with conventional power technologies, according to Tobin Smith for Billion Dollar Green. Fossil fuels have a high combustion rate and are capable of releasing tremendous amount of energy.

Answer:

[tex]a \: = \frac{v - u}{t} [/tex]

2 = v-0/2.9

2× 2.9 = v

v = 5.8 m/s

[tex]v \: = \frac{d}{t} [/tex]

5.8 = d/2.9

5.8×2.9 = d

d = 16.82 m

Answer:

B) 15 m/s

Explanation:

Since most of the answer choices are in m/s, you can try dividing 60 meters/4 seconds in order to get the seconds on the bottom to become 1 second.

You want to find how many meters the object can travel in 1 second, rather than 4 seconds.

Now you can see that for every 1 second of time, the object can travel 15 meters. This corresponds to answer choice B) 15 m/s.

The last option, D, is incorrect because we are not dealing with hours as our unit of time. We are dealing with seconds.

Answer:

b) 15 m/s

hope it help you

Answer: .4 m/s^2= acceleration

Explanation:

f = m*a

We can rearrange this equation to solve for acceleration. Therefore,

a=f/m

a= 28N/70kg

a= 0.4 m/s^2

Answer:

yes absolutely

Explanation:

why not

Answer:

c

Explanation:

i took the test

Answer:

1) t_total = 140 min ,  v = 126.7 m / min ,  2)  v = 0.628 m / s ,

3) v = 0.592 m / s ,  θ = -39.3 º

Explanation:

Here we have some short kinematics problems

1) d₁ = 4200 m at T1 = 25 min

    d₂ = 4.54 km at t2 = 1 h

    d₃ = 9000 m at t3 = 55 min

of the statement the direction of each route is the same

Let's reduce the distances to the SI system

     d₂ = 4.54 km (1000 m / 1 km) = 4540 m

     t₂ = 1 h (60 min / 1 h) = 60 min

Total time is

    t_total = t1 + t2 + t3

   t_total = 25 + 60 +55

   t_total = 140 min

the distance is

    d_total = 4200 + 4540 +9000

     d_total = 17740 m

with movement it is in one dimension and all displacement is in the same direction, distance equals displacement.

Speed ​​is

       v = 17740/140

       v = 126.7 m / min

in the direction of travel

Speed ​​is the modulus of speed

        | v | = 126.7 m / min

2) the angular velocity is

        w = θ / t

In this exercise

        t = 2 min (60 s / 1min) = 120 s

        θ = 30 rev (2π rad / 1 rev) = 60π rad

         w = 60π / 120

         w = 1.57 rad / s

linear velocity  is

        v = w r

        v = 1.57 0.40

        v = 0.628 m / s

velocity is the speed tangential to the  trajectory

3) the data for this exercise are

     distance = (number of steps) (distance of one step)

         d₁ = 500 0.40 m = 200 m West

         d₂ = 400 0.35 m = 140 m North

         d₃ = 300 0.30 m = 90 m East

in a total time of t = 2 min and 120 s

           t = 2  60 + 120 = 240 s

the distance traveled is

x axis we assume the direction towards + x (East) positive

           x_total = d₃ -d₁

           x_total = 90-200 = -110 m

y axis  

          y_total = d₂

          y_total = 140 m

we use the Pythagorean theorem to find the distance0

           D = √ (x_total² + y_total²)

           D = √ (110² + 90²)

           D = 142.13 m

The speed is

           v = D / t

            v = 142.13 / 240

           v = 0.592 m / s

speed is

           v = 0592 m / s

           tan θ = Y / X

           θ = tan -1 y / x

           θ = tan -1 (90 / (- 110))

           θ = -39.3 º

4) This angle is measured on the positive side of the x axis in a clockwise direction

          θ = 1.5 rev (2π rad / 1 rev) = 3π rad

           t = 90 s

the angular velocity is

           w = θ / t

           w = 3πi / 90

           w = 0.1047 rad / s

the speed is

            v = w R

            v = 0.14047 250

            v = 26.17 m / s

velocity is tangent to path

Answer: 5.4 seconds

Explanation:

The time taken to stop the bicycle is 5.4 seconds. The final velocity is zero. Then, the distance travelled by the bicycle is 36.45 m.

Acceleration is a physical quantity that, measures the rate of change in velocity. It is a vector quantity thus having both magnitude and direction. It can be defines as the ratio of change in velocity to the change in time.

Given initial velocity = 13.5 m/s

final velocity is zero since the bicycle is stopping.

then Δt = Δv/a

Δt = 13.5 m/s/ 2.50 m/s² = 5.4 seconds.

Hence, the bicycle will take 5.4 s to complete stop.

The distance covered within this time can be determined using the equation as follows:

s = ut + 1/2 at²

where u is the initial velocity

s =  (13 m/s × 5.4 s) + (-2.50 m/s² ×5.4 s ×5.4 s) = 36.4 m.

Therefore, the bicycle will travel up to 36.4 m before stopping.

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