The original function is:
[tex]f(x)\text{ = x+1}[/tex]We want to find the value of the function when the input is "x + 7". So in the place of the original "x" we will add "x+7".
[tex]\begin{gathered} f(x+7)\text{ = (x+7)+1} \\ f(x+7)\text{ = x+7+1} \\ f(x+7)\text{ = x+8} \end{gathered}[/tex]The value of the expression is "x + 8"
A recent study conducted by a health statistics center found that 27% of households in a certain country had no landline service. This raised concerns about the accuracy of certain surveys, as they depend on random-digit dialing to households via landlines. Pick five households from this country at random. What is the probability that at least one of them does not have a landline _________
We are going to use Binomial Probability Distribution
Probability that they have no landline = q = 27/100 = 0.27
Probability that they have landline = p = 1 - 0.27 = 0.73
Now, to find the probability that at least one of them does not have a landline, we have to find the probability that all the five have a landline first.
So let's find the probability that all the five have a landline:
[tex]\begin{gathered} P(X=x)=^nC_xp^xq^{n-x} \\ ^5C_5(0.73)^5(0.27)^{5-5} \\ P(X\text{ = 5) = }0.2073 \end{gathered}[/tex]So the probability that all the five have a landline = 20.73%
Now is the time to find the probability that at least one of them does not have a landline:
P(at least one has no landline) = 1 - P(All have landline)
= 1 - 0.2073
= 0.7927
So the probability that at least one of them does not have a landline = 79.27%
That's all Please
HELP!! My question isUsing the formula below, solve when s is 3The formula is A = 6s² and I need to know the steps on how to solve it please help! I really dont understand and my teacher is not at school to help me
The given expression : A = 6s²
Substitute s = 3 in the given expression
A = 6s²
A = 6(3)²
as : 3² = 3 x 3
3² = 9
A = 6 x 9
A = 54
Answer : A = 54
5. Graph the function f (x) = 3sin (2x) + 1 Be sure to identify the midline, period, and amplitude.
Given that f(x) = 3 sin (2x) + 1
Given that : a sin (bx + c ) + d
let a = amplitude,
Midline is the that runs between the maximum and minimum value
[tex]\begin{gathered} \text{ Since, amplitude = 3} \\ \text{the graph is shifted 1 unit in positive y - coordinate} \\ \text{Maximum value = 3 - 1 = 2} \\ \text{ minimum value = -3 - 1 = -4} \\ \text{Midline is the center of (2, - 4)} \\ \text{Midline = }\frac{\text{2 - 4}}{2} \\ \text{midline = -1} \end{gathered}[/tex]Period is calculated as
[tex]\begin{gathered} \text{period = }\frac{2\pi}{|b|} \\ \\ \text{b = 2} \\ \text{Period = }\frac{2\pi}{2} \\ \text{Period = }\pi\text{second} \end{gathered}[/tex]Frequency = 1 / period
[tex]\text{frequency = }\frac{1}{\pi}\text{ Hz}[/tex]Hello. I think I have this one correct but I'm not 100% sure. Would you mind helping me work this through?
1) To better set the measurements in that picture, we need to consider that parallel line segments in this picture have the same measurements.
2) Based on that, we can look at that picture this way:
And set the following equation, given that Perimeter is the sum of all lengths of a polygon:
[tex]\begin{gathered} P=2+2+1+2+3+3+1+1+1+1+4+3 \\ P=24\:cm \end{gathered}[/tex]The polynomial expression x(3x^2+25)(10x^2+4x+6), where x is in inches, can be used to mod the number of cubic inches of cement that will be needed for a new porch. The cement contractor used 2 for the value of x.
Since x is given in cubic inches, let's split the expression like this:
[tex]\begin{gathered} h=height=x \\ w=width=(3x^2+25) \\ l=length=(10x^2+4x+6) \end{gathered}[/tex]For x = 2:
[tex]\begin{gathered} h=2in \\ w=3(2)^2+25=37in \\ l=10(2)^2+4(2)+6=54in \end{gathered}[/tex]Find the areas of the figures for parts (a) and (b) below.
SOLUTION:
Case: Area of plane shapes
Method:
a) Parallelogram
To find the area we need to find the perpendicular height (using Pythagoras theorem)
[tex]\begin{gathered} h^2+7^2=25^2 \\ h^2+49=625 \\ h^2=625-49 \\ h^2=576 \\ h=\sqrt{576} \\ h=24 \end{gathered}[/tex]The Area of a parallelogram is given as:
[tex]\begin{gathered} A=bh \\ A=23\times24 \\ A=552\text{ }ft^2 \end{gathered}[/tex]b) Triangle
To find the area of the triangle, we need to find the base first
First, lets find 'a'
[tex]\begin{gathered} a^2+60^2=70^2 \\ a^2+3600=4900 \\ a^2=4900-3600 \\ a^=\sqrt{1300} \\ a=36.06 \end{gathered}[/tex]The base, b
b= 2(a)
b= 2 (36.06)
b= 72.12
The area of the triangle is:
[tex]\begin{gathered} A=\frac{1}{2}bh \\ A=\frac{1}{2}\times72.12\times60 \\ A=2163.6 \end{gathered}[/tex]Final answer:
a) Parallelogram,
A= 552 square feet
b) Triangle
A= 2163.6 square feet
A loan is paid off in 15 years with a total of $192,000. It had a 4% interest rate that compounded monthly.
What was the principal?
Round your answer to the nearest cent and do not include the dollar sign. Do not round at any other point in the solving process; only round your answer.
The principal amount with the given parameters if $165.
Given that, Amount = $192,000, Time period = 15 years and Rate of interest = 4%.
What is the compound interest?Compound interest is the interest on savings calculated on both the initial principal and the accumulated interest from previous periods.
The formula used to find the compound interest = [tex]A=P(1+\frac{r}{100} )^{nt}[/tex]
Now, [tex]192,000=P(1+\frac{4}{100} )^{15\times 12}[/tex]
⇒ [tex]P=\frac{192,000}{(1.04)^{180}}[/tex]
⇒ P = $164.93
≈ $165
Therefore, the principal amount with the given parameters if $165.
To learn more about the compound interest visit:
https://brainly.com/question/14295570.
#SPJ1
Answer:
Step-by-step explanation:
Use the compound interest formula and substitute the values given: $192,000=P(1+.0412)12(15). Simplify using order of operations: $192,000=P(1+.0412)180
P=192,000(1+.0412)180
P≈$105477.02
PLEASE HELP I WILL GIVE BRAINLYEST!! ALGEBRA 1 HW
Answer:
look below
Step-by-step explanation:
White the inequality shows by the shaded region in the graph with the boundary line y=x/3-5
From the given figure
Since the line is a dashed line, then
The sign of inequality does not have equal (< OR > )
Since the shading area is down the line, then
The sign of inequality should be smaller than (<)
Then the inequality is
[tex]y<\frac{x}{3}-5[/tex]1) A car is traveling down a highway at a constant speed, described by the equation d = 65t, where d represents the distance, in miles, that the car travels at this speed in t hours. a) What does the 65 tell us in this situation? b) How many miles does the car travel in 1.5 hours? Show your work. c) How long does it take the car to travel 26 miles at this speed? Show you
The equation d = 65t
represents the distance (d) the car travels at a 65 mile speed in t hours
a. 65 tells us the speed at which the car travels
b. If the car travels in 1.5 hrs, then
d = 65(1.5)
= 97.5 milestone.
c. To travel 26 miles, we have d = 26
26 = 65t
t = 26/65
= 0.35 (approximately)
If f (x) = 3x2 - 2x + 1, select all of the following that are TRUE?f(-1) = 6f(1) = 0f (2) = 9f(0) = 1Previous
The function is:
[tex]f(x)=3x^2-2x+1[/tex]to check witch is true we have to evaluate the function in -1, 1, 1 and 0 so:
for
Triangle HFG is similar to triangle RPQ. Find the value of x. Find the length of HG.
Answer:
• x=1
,• HG=8 units
Explanation:
If triangles HFG and RPQ are similar, the ratios of their corresponding sides are:
[tex]\frac{HF}{RP}=\frac{HG}{RQ}=\frac{FG}{PQ}[/tex]Substitute the given values:
[tex]\frac{4}{2}=\frac{6x+2}{x+3}=\frac{6}{3}[/tex]First, we solve for x:
[tex]\begin{gathered} \frac{4}{2}=\frac{6x+2}{x+3} \\ 2=\frac{6x+2}{x+3} \\ 2(x+3)=6x+2 \\ 2x+6=6x+2 \\ 6-2=6x-2x \\ 4=4x \\ x=1 \end{gathered}[/tex]Finally, calculate the length of HG.
[tex]\begin{gathered} HG=6x+2 \\ =6(1)+2 \\ =8\text{ units} \end{gathered}[/tex]Find the links of the sides of these special triangles
From the triangle, we express the tangent of 60° as:
[tex]\tan 60\degree=\frac{Z}{7}[/tex]But tan(60°) = √(3), then:
[tex]\begin{gathered} \frac{Z}{7}=\sqrt[]{3} \\ \Rightarrow Z=7\sqrt[]{3}\text{ ft} \end{gathered}[/tex]f(x) = square root of x - 5. find f^-1 (x) and it’s domain
Given:
f(x) = root x - 5
Rewrite the function using y,
[tex]y=\sqrt[]{x}-5[/tex]Now, interchange the position of x and y in the function,
[tex]x=\sqrt[]{y}-5[/tex]Isolate the dependent variable
[tex]\begin{gathered} \sqrt[]{y}=x+5 \\ y=(x+5)^2 \end{gathered}[/tex]Therefore,
[tex]f^{-1}(x)=(x+5)^2[/tex]And the domain is minus infinity to infinity
[tex]\begin{gathered} f^{-1}(x)=(x+5)^2 \\ \text{Domain}=(-\infty,\infty) \end{gathered}[/tex]Write and solve the equation that has been modeled below.
Solution
[tex]\begin{gathered} x+x+1+1+1+1+1+1+1=1+1+1+1+1+1+1+1+1 \\ 2x+7=9 \\ \text{Separate similar terms} \\ 2x=9-7 \\ 2x=2 \\ \text{Divide both sides by 2} \\ \frac{2x}{2}=\frac{2}{2} \\ \\ x=1 \end{gathered}[/tex]The final answer
[tex]x=1[/tex]Had someone explain it and I didn’t get it still
From the question:
Let f(x) = 2x² + 2x - 8
g(x) = √x - 2
We are aske to write f(g(x))
f(x) = 2x² + 2x - 8, g(x) = √x - 2
g(x) = √x - 2
= f(√x - 2)
f(√x - 2): 2x + 2√x - 2 - 12
f(g(x)) = 2x - 12 + 2√x - 2.
Given Hx)= vx and g(x) = \» ,which is the graph of (fºg)(x)?-2-222&DONE
Answer:
Step-by-step explanation:
A composite function is created when one functions is substituted into another function.
Given:
[tex]\begin{gathered} f(x)=\sqrt[]{x}\text{ and g(x)=}\lvert x\rvert \\ \text{Then, (f }\circ g)(x)\text{ would be f(g(x))} \end{gathered}[/tex]Therefore,
[tex](f\circ g)(x)=\sqrt[]{\lvert x\rvert}[/tex]Now, graphing this function...
A baker paid $15.05 for flour at a store that sells flour for $0.86 per pound.
Solution:
Given that a store sells flour for $0.86 per pound, this implies that
[tex]1\text{ lb}\Rightarrow\$0.86[/tex]Given that a baker paid $15.05, let y represent the amount of flour the baker bought.
Thus,
[tex]y\text{ lb}\Rightarrow\$15.05[/tex]To solve for y,
[tex]\begin{gathered} 1\text{lb}\operatorname{\Rightarrow}\operatorname{\$}0.86 \\ y\text{ lb}\Rightarrow\$15.05 \\ cross-multiply, \\ y\text{ lb = }\frac{\$\text{15.05}}{\$0.86}\times1\text{ lb} \\ =17.5\text{ lb} \end{gathered}[/tex]Hence, the baker bought 17.5 lb of flour.
3 1/2 ÷ 47/815/88/73/4
the given expression is,
[tex]\begin{gathered} 3\frac{1}{2}\div4=\frac{7}{2}\div4 \\ =\frac{\frac{7}{2}}{4}=\frac{7}{8} \end{gathered}[/tex]so the answer is option A
had a question about this and i cant find a answer
A line is given by the expression:
y=mx+b
where, m is the slope of the line and since we have to write an equation that is parallel to the given line, both lines have the same slope:
We can find the equation of the line by the slope-point form of a line, with the given point (-8, -7) and the slope of -4
[tex]\begin{gathered} y-y_0=m(x-x_0) \\ y+7=-4(x+8) \\ y+7=-4x-32 \\ y=-4x-32-7 \\ y=-4x-39 \end{gathered}[/tex]4 boxes of crayons cost $12.50 How much would 16 boxes cost? (Show work) Thank you!
Answer:
$50.08
Step-by-step explanation:
Find the unit rate.
[tex]\frac{12.50}{4}[/tex] Each box cost $3.125. We cannot have .125 cents, so round up to 3.13
3.13 x 16 = $50.08
Y + 41 = 67 solve y using one step equation
Answer:
Y = 26
Step by step explanation:
[tex]y\text{ + 41 = 67}[/tex]
Then we pass the 41 to substract.
[tex]y\text{ = 67 - 41 = 26}[/tex]Which of the following tables shows a uniform probability model?
The answer is the third choice
Where all probability are equal
Benjamin invested an amount of $12,000.00 in a mutual fund. After 4 years and 6 months the accumulated value of his investment was $13,407.58. What is the nominal interest rate of the investment if interest is compounded semi-annually?__________%Round to two decimal places
Given:
The accumulated value of investment is A = 13,407.58.
The invested amount is P = 12,000.00.
The time period is 4 years and 6 months.
Explanation:
The formula for the accumulated value at r rate of interest is compounded semi-annually.
[tex]A=P(1+\frac{r}{200})^{2\cdot t}[/tex]Substitute the values in the formula to determine the value of r.
[tex]\begin{gathered} 13407.58=12000(1+\frac{r}{200})^{2\cdot4.5} \\ \frac{13407.58}{12000}=(1+\frac{r}{200})^9 \\ 1+\frac{r}{200}=(\frac{13407.58}{12000})^{\frac{1}{9}} \\ \frac{r}{200}=1.01239-1 \\ r=0.01239\cdot200 \\ =2.478 \\ \approx2.48 \end{gathered}[/tex]So the rate of interest is 2.48%.
Quadrilateral TUVW is a rhombus and m∠SVU=4z+56°. What is the value of z?WTUVS26°z=°Submit
From the question, we were told:
TUVW is a rhombus
Angle SUV = 4z + 56˚
We are asked to find the value of z.
From the diagram, we can see that angle SVU is 90˚
So, to get the value of z, we equate the value of SVU to 90˚
4z + 56˚ = 90˚
subtract 56˚ from both sides:
4z + 56 - 56 = 90 - 56
4z = 34
divide both sides by 4 to make z the subject of formula:
z = 34/4
z = 8.5
Perform the following matrix row operation and write the new one.
Given: A matrix
[tex]\begin{bmatrix}{1} & {-3} & {2} \\ {3} & {9} & {5} \\ {} & & {}\end{bmatrix}[/tex]Required: To perform the following matrix row operation
[tex]-3R_1+R_2[/tex]Explanation: The operation is to be applied on the first row of the given matrix. Hence the second row will be same as that of the initial matrix.
The elements of the first row are first multiplied by 3 and then added with second row to give the required matrix.
Hence,
[tex]\begin{bmatrix}{-3+3} & {9+9} & {-6+5} \\ {3} & {9} & {5} \\ {} & {} & {}\end{bmatrix}[/tex]which gives
[tex]\begin{bmatrix}{0} & {18} & {-1} \\ {3} & {9} & {5} \\ {} & {} & {}\end{bmatrix}[/tex]Final Answer: The required matrix is
[tex]\begin{bmatrix}{0} & {18} & {-1} \\ {3} & {9} & {5} \\ {} & {} & {}\end{bmatrix}[/tex]Tony will rent a car for the weekend. He can choose one of two plans. The first plan has an initial fee of $60and costs an additional $0.50per mile driven
The second plan has noinitial fee and costs an additional $0.70per mile driven
E
For what amount of driving do the two plans cost the
Same
Plan 1:
Initial (fixed) fee: $60
Variable fee: $0.50 per mile
Plan 2:
Initial (fixed) fee: $0
Variable fee: $0.70 per mile
If we call x to the number of miles driven by Tony, then the cost of Plan 1 is:
P1 = 60 + 0.5x
The cost of Plan 2 is:
P2 = 0.7x
It's required to find the number of miles Tony should drive for both plans to cost the same, that is:
60 + 0.5x = 0.7x
Subtracting 0.5x:
60 = 0.7x - 0.5x
Operating:
60 = 0.2x
Dividing by 0.2:
x = 60 / 0.2
x = 300
Tony should drive 300 miles for both plans to cost the same.
Under that condition, both plans cost the same. Plan 1 cost:
P1 = 60 + 0.5*300
P1 = 60 + 150
P1 = $210
Plan 2 cost:
P2 = 0.7*300
P2 = $210
Both costs are equal
A study determined that 9% of children under 18 years of age live with their father only. Find the probability that at most 2 persons selected at random from 12 children under18 years of age lived with their father onlyThe probability that at most 2 children live with their father only is(Do not round until the final answer. Then round to the nearest thousandth as needed)
Step 1: Write out the formula for binomial distribution
[tex]P(x)=^nC_x\times p^x\times q^{n-x}[/tex]Where
[tex]\begin{gathered} p\Rightarrow\text{probability of success} \\ q\Rightarrow\text{probability of failure} \\ n\Rightarrow\text{ number of trails } \\ x\Rightarrow\text{ number of success required} \end{gathered}[/tex]Step 2: State out the parameters needed in the formula to find the probabilty
[tex]\begin{gathered} p=9\text{ \%=}\frac{9}{100}=0.09 \\ q=1-p=1-0.09=0.91 \\ n=12 \\ x\Rightarrow\le2\Rightarrow0,1,2 \end{gathered}[/tex]Step 3: The probability that at most 2 children live with their father only can be described as;
[tex]P(x\le2)=P(0)+P(1)+P(2)[/tex]Step 4: Find the probability of each number of successes required
[tex]\begin{gathered} P(0)=^{12}C_0\times(0.09)^0\times(0.91)^{12-0} \\ P(0)=1\times1\times0.322475487=0.322475487 \end{gathered}[/tex][tex]\begin{gathered} P(1)=^{12}C_1\times(0.09)^1\times(0.91)^{12-1} \\ =^{12}C_1\times(0.09)^1\times(0.91)^{11} \\ =12\times0.09\times0.354368667=0.38271816 \end{gathered}[/tex][tex]\begin{gathered} P(2)=^{12}C_2\times(0.09)^2\times(0.91)^{12-2} \\ =^{12}C_2\times(0.09)^2\times(0.91)^{10} \\ =66\times0.0081\times0.389416118=0.208181856 \end{gathered}[/tex]Step 5: Add all the number of successess required
[tex]\begin{gathered} P(x\le2)=0.322475487+0.38271816+0.208181856 \\ =0.913375503 \\ \approx0.913 \end{gathered}[/tex]Hence, the probability that at most 2 children live with their father only is 0.913
a1. The amount of milk in a one-gallon milk container has a normal distribution with a meanof 1.07 gallons and a standard deviation of 0.12 gallons.Calculate and interpret the z-score for exactly one gallon of milk.
The z-score formula is given to be:
[tex]z=\frac{x-\mu}{\sigma}[/tex]where
[tex]\begin{gathered} x=score \\ \mu=mean \\ \sigma=standard\text{ }deviation \end{gathered}[/tex]From the question given, the mean and standard deviations are provided as:
[tex]\begin{gathered} \mu=1.07 \\ \sigma=0.12 \end{gathered}[/tex]Therefore, the z-score of exactly 1 gallon is calculated to be:
[tex]\begin{gathered} x=1 \\ \therefore \\ z=\frac{1-1.07}{0.12}=\frac{-0.07}{0.12} \\ z=-0.583 \end{gathered}[/tex]Therefore, the z-score is -0.583.
This tells us that a container with exactly one gallon of milk lies 0.583 standard deviations below the mean.
you randomly select one card from a 52 card deck. find the probability of selecting a black three or a red jack
Probability of selecting a black three or a red jack = 1/13
Explanations:There are a total of 52 cards in a deck of cards
Total number of ways of selecting one card from 52 cards = 52C1 = 52 ways
There are two red jacks in a deck of cards
Number of ways of selecting a red jack = 2C1 = 2 ways
There are two blacks 3s in a deck of cards
Number of ways of selecting a black three = 2C1 = 2 ways
[tex]\begin{gathered} \text{Probablity of selecting a black 3 = }\frac{2}{52}=\text{ }\frac{1}{26} \\ \text{Probability of selecting a red jack = }\frac{2}{52}=\frac{1}{26} \end{gathered}[/tex]Probability of selecting a black three or a red jack = (1/26) + (1/26)
Probability of selecting a black three or a red jack = 2/26 = 1/13