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Answer:

your answer should be B.273 K

Explanation:

Answer:

Kr, Ar, Ne, N

Explanation:

Hope this helps

Answer:

The medical philosophy of the ancient Greeks in which the state of health and disease was determined by the four body “humours”—blood, yellow and black bile, and phlegm—and their relationships with the four elemental humours—air, fire, earth and water. Segen's Medical Dictionary.

Explanation:

Answer:

ecstasy

Explanation:

Answer:

f = 0.534×10⁻² Hz

Explanation:

Given data:

Frequency of wave= ?

Wavelength of wave = 5.62×10¹⁰ m

Solution:

Formula:

Speed of wave = wavelength × frequency

Speed of wave = 3×10¹⁷ nm/s

λ  = 5.62×10¹⁰m×10⁹  nm/1 m = 5.62×10¹⁹ nm

Now we will put the values in formula.

3×10¹⁷ nm/s = 5.62×10¹⁹ nm ×  f

f = 3×10¹⁷ nm/s  / 5.62×10¹⁹ nm

f = 0.534×10⁻² s⁻¹   or

f = 0.534×10⁻² Hz

Answer:

During the reaction, chemical bonds break in the reactants and new chemical bonds form in the products.

Answer:

d. Atoms are rearranged.

Explanation:

10.8

7.2mol*3/2=10.8mol.

10.8 moles of H₂SO₄ is required for the reaction.

The balanced equation for the reaction is given below:

From the balanced equation above,

2 moles of Al required 3 moles of H₂SO₄.

Finally, we shall determine the number of mole of H₂SO₄ required to react with 7.20 moles of Al.

This can be obtained as follow:

From the balanced equation above,

2 moles of Al required 3 moles of H₂SO₄.

Therefore,

7.20 moles of Al will require = [tex]\frac{7.2 X 3}{2} \\\\[/tex] = 10.8 moles of H₂SO₄

Thus, 10.8 moles of H₂SO₄ is required for the reaction.

Learn more: https://brainly.com/question/18474161

Answer:

Explanation:

1. Cornstarch and water - decantation

2. Iron and sulfur

3. Rice grains and stones - sieving

4. Pebbles and soil - decantation

5. Muddy water - decantation

6. Ground pepper and water - decantation

7. Flour and coarsely ground corn - sieving

8. Needles in a box of beads - using a magnet

9. Sesame seeds in soy sauce -

10. Pebbles and iron nails - using a magnet

11. Fine sand from rocks - sieving

12. Sand from water - filtration

13. Gravel and sand - sieving

14. Salt and iron filings - sieving

15. Pins from assorted buttons - using a magnet

16. Coconut oil from coconut milk - filtration

17. Sand and pebbles - sieving

18. Pasta from water - sieving

19. Sand and thumb tacks - using a magnet

20. Salt solution - filtration

Answer:

light bulb B

Explanation:

more resistance

Answer:

Explanation:

The density of a substance can be found by using the formula

[tex]density = \frac{mass}{volume} \\ [/tex]

From the question we have

[tex]density = \frac{18}{24} = \frac{3}{4} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

option is (b)

Explanation:

please mark me as brilliant

Answer:

Zero

Explanation:

An an equal mixture of the R and S enantiomers of carvone is called a racemic mixture.

In a racemic mixture, the R enantiomer rotates plane polarized light in one direction while the S enantiomer rotates plane polarized light in another direction.

This cancels out the rotation due to each enantiomer since they are equal in magnitude but opposite in direction leading to a specific rotation of zero for the racemic mixture.

Answer:

The velocity would be if m was meters +1200

Explanation:

im smart

Answer:

At 10ºC or 50ºF water can cotain the most dissolved sugar.

Answer:

68.48%

Explanation:

The percent mass of an element in a compound tells us about the amount of such element contributed to the total compound.

In this case, 7.28 g sample of chromium metal was heated to produce chromium oxide with weight of 10.63 g. The percent mass of chromium in chromium oxide can be calculated by using the formula:

%mass of Cr = mass of Cr/mass of Chromium oxide × 100%

%mass of Cr = 7.28/10.63 × 100

%mass of Cr = 0.6848 × 100

%mass of Cr = 68.48%

Answer:

B. Suspension

Explanation:

A suspension is an heterogenous mixture in which the large particles settle out when not disturbed, thus ,can easily be separated by filtration.

An example is a mixture of sand and water.  When left for a while the sand particles are clearly visible at the bottom of the container if its transparent.

Answer:

20.180042 amu

Explanation:

From the question given above, the following data were obtained:

Isotope A (20Ne)

Mass of A = 19.9924356 amu

Abundance (A%) = 90.48%

Isotope B (21Ne):

Mass of B = 20.9938428 amu

Abundance (B%) = 0.27%

Isotope C (22Ne):

Mass of C = 21.9913831 amu

Abundance (C%) = 9.25%

Average atomic mass of Neon =.?

The average atomic mass of Neon can be obtained as follow:

Average atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100] + [(mass of C × C%)/100]

= [(19.9924356 × 90.48)/100] + [(20.9938428 × 0.27) /100] + [(21.9913831 × 9.25) /100]

= 18.0891557 + 0.05668338 + 2.03420294

= 20.180042 amu

Therefore, the average atomic mass of Neon is 20.180042 amu

Answer:

B) . six electrons in the triple bond of diatomic nitrogen

Explanation:

The three line in this Lewis dot structure represents the six electrons in the triple bond of diatomic nitrogen.

Nitrogen is made up of 7 electrons with 5 valence ones.

 A lewis structure is made up of the symbol of the element surrounded by dot to represent the valence electrons.

  In this nitrogen molecule, both species share  6 electrons. This makes each nitrogen atom isoelectronic with neon.

Answer:

Yes, you are correct.

Explanation:

I used Google.

Answer:

the answer is 101.96 g/mo

Explanation:

Answer:

101.96f/mal

Explanation:

Answer:

B & A

Explanation:

A Compound consists of two or more atoms from different elements, that are chemically bound together.

A electron carries a negative charge, because it is found in the electron cloud

If your wondering too, A proton carries A Positive charge.

Answer:

2 or more atoms from different elements that are chemically bonded together.

negative charge.

Answer:

liquid

Explanation:

correct answer hope it helps

Answer:

The answer is "[tex]37.45364 \ g[/tex]"

Explanation:

Equation:

[tex]2AgNO_3 (aq) + Na_2CO_3 (aq) \longrightarrow Ag_2CO_3 (s) + 2NaNO_3 (aq)[/tex]

Calculating  the mol of  [tex]AgNO_3[/tex]:

[tex]\to V = 40.0 mL\\\\[/tex]

       [tex]= 40.0 \times 10^{-2} \ L \\\\[/tex]

[tex]\to n = Molarity \times Volume \\\\[/tex]

       [tex]= 0.679 \times 40.0 \times 10^{-2}\\\\= 27.16 \times 10^{-2} \ mol[/tex]

mol of [tex]Ag_2CO_3= \frac{1}{2} \times n\\\\[/tex]

                         [tex]= \frac{1}{2} \times 27.16 \times 10^{-2}\\\\= 13.58 \times 10^{-2}\\\\[/tex]

Calculating the molar mass of [tex]Ag_2CO_3[/tex],:

[tex]= 2\times MM(Ag) + 1 \times MM(C) + 3 \times MM(O)\\\\= 2 \times 107.9 + 1 \times 12.01 + 3 \times 16.0\\\\= 275.81 \ \frac{g}{mol}[/tex]

Calculating the mass of [tex]Ag_2CO_3[/tex],

[tex]m = mol \times molar \ mass[/tex]

   [tex]= 13.38 \times 10^{-2}\ mol \times 2.758 \times 10^2 \ \frac{g}{mol}\\\\= 37.45364 \ g[/tex]

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