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Explanation:
x = total number of balls
x-4 = number of blue
x-4 = number of green
x-4 = number of red
3(x-4) = 3x-12 = total number of blue, green, or red
x - (3x-12) = x-3x+12 = -2x+12 = number of other colors
If there are other colors, then we want this quantity to be larger than 0, so,
-2x+12 > 0
-2x > -12
x < -12/(-2)
x < 6
There are less than 6 balls in the bag.
At the same time, we want each x-4 to be greater than zero
x-4 > 0
x > 4
------------------
We found that x > 4 and x < 6
This combines to 4 < x < 6 which has us land on x = 5
This computes x-4 = 5-4 = 1, showing there's one of each blue, green and red. There are 5-1-1-1 = 2 balls of some other color not mentioned.
------------------
If x = 6, then,
x-4 = 2 each of blue, green and red
There wouldn't be any other color since 6-2-2-2 = 0
a local business Club has 11 exclusive board members and 22 General members how many committees of 7 members can be chosen so that only General members are excluded
we have:
general members are excluded then
[tex]11C7=330[/tex]answer: 330
Determine which of the following lines, if any, are perpendicular • Line A passes through (2,7) and (-1,10) • Line B passes through (-4,7) and (-1,6)• Line C passed through (6,5) and (7,9)
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
Line A:
point 1 (2,7)
point 2 (-1,10)
Line B:
point 1 (-4,7)
point 2 (-1,6)
Line C:
point 1 (6,5)
point 2 (7,9)
Step 02:
perpendicular lines:
slope of the perpendicular line, m’
m' = - 1 / m
Line A:
slope:
[tex]m\text{ = }\frac{y2-y1}{x2-x1}=\frac{10-7}{-1-2}=\frac{3}{-3}=-1[/tex]Line B:
slope:
[tex]m=\frac{y2-y1}{x2-x1}=\frac{6-7}{-1-(-4)}=\frac{-1}{-1+4}=\frac{-1}{3}[/tex]Line C:
slope:
[tex]m\text{ = }\frac{y2-y1}{x2-x1}=\frac{9-5}{7-6}=\frac{4}{1}=4[/tex]m' = - 1 / m ===> none of the slopes meet the condition
The answer is:
there are no perpendicular lines
Please help me answer the following question with the picture below.
Answer:
9x+b
Step-by-step explanation:
H +6g when 9=g and h=4
Hey there!
[tex]g+6g\\g=9,h=4[/tex]
[tex]4(h)+6(9(g))[/tex]
[tex]4+6(9)[/tex]
[tex]=58[/tex]
Hope this helps!
What’s the correct answer answer asap for brainlist
Answer: serbia
Step-by-step explanation:
Need help with is math.
For the given polynomial the roots can't have multiplicity, and the polynomial is:
p(x) = (x - 2)*(x - 3)*(x - 5).
How to find the polynomial?Here we know that we have a cubic polynomial (of degree 3) with the following zeros:
2, 3, and 5.
Can any of the roots have multiplicity?
No, because a cubic polynomial can have at maximum 3 zeroes, and here we already have 3.
Now let's get the polynomial
Remember that a cubic polynomial with zeros a, b, and c can be written as:
p(x) = (x - a)*(x - b)*(x - c)
Then the polynomial in this case is:
p(x) = (x - 2)*(x - 3)*(x - 5).
Learn more about polynomials:
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Boy earns 20.56 on Monday 32.90 on Tuesday and 20.78 on Wednesday he spends half what he earned during three days how much he have left
First, we need to calculate the total earned during the three days, so we need to sum 20.56, 32.90, and 20.78 as:
So, the total earned is 74.24, then half of 74.24 is calculated as:
[tex]\frac{74.24}{2}=37.12[/tex]If he spends the half, he has left the half. Therefore, he has left 37.12
Answer: 37.12
PLEASE HELP ME!! a shoe company is going to close one of its two stores and combine all the inventory from both stores these polynomials represented the inventory in each store. which expression represents the combined inventory of the two stories?
Add the two expressions together;
[tex]\begin{gathered} (\frac{1}{2}g^2+\frac{7}{2})+(3g^2-\frac{4}{5}g+\frac{1}{4}) \\ =\frac{1}{2}g^2+3g^2-\frac{4}{5}g+\frac{7}{2}+\frac{1}{4} \\ =3\frac{1}{2}g^2-\frac{4}{5}g+(\frac{14+1}{4}) \\ =\frac{7}{2}g^2-\frac{4}{5}g+\frac{15}{4} \end{gathered}[/tex]The first option is the correct answer
Given the special right triangle, find the value of x and y. Express your answer in simplest radical form.
Mary Anne wants the professor to build a ramp to make it easier to get things into the cook hut. The ramp has to rise 2 feet and will have anangle of 12 degrees with the ground.Calculate how far out from the hut the ramp will go. Round to the nearest 1 decimal. _____What length of timbers will be needed to build the ramp (how long is the distance along the ramp) Round to the nearest 1 decimal. _____
The next figure illustrates the problem
x is computed as follows:
tan(12°) = opposite/adjacent
tan(12°) = 2/x
x = 2/tan(12°)
x = 9.4 ft
y is computed as follows:
sin(12°) = opposite/hypotenuse
sin(12°) = 2/y
y = 2/sin(12°)
y = 9.6 ft
Hello! I need some help with this homework question, please? The question is posted in the image below. Q6
Step 1
Given;
[tex]g(x)=3x^2-5x-2[/tex]Required; To find the zeroes by factoring
Step 2
Find two factors that when added gives -5x and when multiplied give -6x
[tex]\begin{gathered} \text{These factors are;} \\ -6x\text{ and x} \end{gathered}[/tex][tex]\begin{gathered} -6x\times x=-6x^2 \\ -6x+x=-5x \end{gathered}[/tex]Factoring we have and replacing -5x with -6x and x we have
[tex]\begin{gathered} 3x^2-6x+x-2=0 \\ (3x^2-6x)+(x-2)_{}=0 \\ 3x(x-2)+1(x-2)=0 \\ (3x+1)(x-2)=0 \\ 3x+1=0\text{ or x-2=0} \\ x=-\frac{1}{3},2 \\ \text{The z}eroes\text{ are, x=-}\frac{1}{3},2 \end{gathered}[/tex]Graphically the x-intercepts are;
The x-intercepts are;-1/3,2
Hence, the answer is the zeroes and x-intercepts are the same, they are;
[tex]-\frac{1}{3},2[/tex]Decide whether the change is an increase or decrease and find the percent change. Original number = 45 New number = 18 Answer: 60% decrease 60% increase 150% increase 150% decrease
The percentage change can be found below
[tex]\begin{gathered} \text{percentage change = }\frac{\text{ new number}-\text{original number}}{\text{original number}}\times100 \\ \text{percentage change=}\frac{18-45}{45}\times100 \\ \text{percentage change}=-60 \\ \end{gathered}[/tex]Since the percentage is negative, this means there is a 60% decrease.
PLEASE ANSWER ASAP ! Thanks :)
The inverse function table of the function is given by the image at the end of the answer.
How to calculate the inverse function?A function y = f(x) is composed by the following set of cartesian points:
(x,y).
In the inverse function, the input of the function represented by x and the output of the function represented by y are exchanged, meaning that the coordinate set is given by the following rule:
Thus, the points that will belong to the inverse function table are given as follows:
x = -8, f^(-1)(x) = -2, as the standard function has x = -2 and f(x) = -8.x = -4.5, f^(-1)(x) = -1, as the standard function has x = -1 and f(x) = -4.5.x = -4, f^(-1)(x) = 0, as the standard function has x = 0 and f(x) = -4.x = 0, f^(-1)(x) = 2, as the standard function has x = 2 and f(x) = 0.More can be learned about inverse functions at https://brainly.com/question/3831584
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Answer:
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5} \vphantom{\dfrac12} x &-8 &-4.5 & -4&0 \\\cline{1-5} \vphantom{\dfrac12} f^{-1}(x) &-2 & -1& 0&2 \\ \cline{1-5}\end{array}[/tex]
Step-by-step explanation:
The inverse of the graph of a function is its reflection in the line y = x.
Therefore, the mapping rule to find the inverse of the given ordered pairs is:
(x, y) → (y, x)Therefore:
The inverse of (-2, -8) is (-8, -2)The inverse of (-1, -4.5) is (-4.5, -1)The inverse of (0, -4) is (-4, 0)The inverse of (2, 0) is (0, 2)Completed table:
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5} \vphantom{\dfrac12} x &-8 &-4.5 & -4&0 \\\cline{1-5} \vphantom{\dfrac12} f^{-1}(x) &-2 & -1& 0&2 \\ \cline{1-5}\end{array}[/tex]
29 graph in desmos and label points of inflection, critical points, local extremes, absolute extremes, asymptotes, etc
Given:
There are given the function:
[tex]f(x)=\frac{3x}{x^2-1}[/tex]Explanation:
According to the question:
We need to draw the graph of the given equation:
So,
The graph is:
vertical asymptotes are (-1,1)
And,
The horizontal asymptotes is
y = 0.
What is the solution to the equation below ? 0.5x = 6 A . 3 B . 12 C . 60
Given the equation:
[tex]0.5x=6[/tex]Multiplying both sides by 2
[tex]\begin{gathered} 2\cdot0.5x=2\cdot6 \\ x=12 \end{gathered}[/tex]So, the answer will be option B) 12
What is a rational number between -0.45 and -0.46?
Answer:-0.4545555...,-0.453333...,-0.45222.....
hope i helped
Step-by-step explanation:
Question 2 of 10The one-to-one functions g and h are defined as follows.g={(-8, 6), (-6, 7), (-1, 1), (0, -8)}h(x)=3x-8Find the following.g-¹(-8)=h-¹(x) =(hoh− ¹)(-5) =
Answer: We have to find three unknown asked quantities, before we could do that we must find the g(x) from the coordinate points:
[tex]\begin{gathered} g=\left\{\left(-8,6\right),(-6,7),(-1,1),(0,-8)\right\}\Rightarrow(x,y) \\ \\ \text{ Is a tabular function} \\ \end{gathered}[/tex]The answers are as follows:
[tex]\begin{gathered} g^{-1}(-8)=0\text{ }\Rightarrow\text{ Because: }(0,-8) \\ \\ \\ h^{-1}(x)=\frac{x}{3}+\frac{8}{3} \\ \\ \\ \text{ Because:} \\ \\ h(x)=3x-8\Rightarrow\text{ switch }x\text{ and x} \\ \\ x=3h-8 \\ \\ \\ \\ \text{ Solve for }h \\ \\ \\ h=h^{-1}(x)=\frac{x}{3}+\frac{8}{3} \end{gathered}[/tex]The last answer is:
[tex]\begin{gathered} (h\text{ }\circ\text{ }h^{-1})(-5) \\ \\ \text{ Can also be written as:} \\ \\ h[h^{-1}(x)]\text{ evaluated at -5} \\ \\ h(x)=3x-8 \\ \\ h^{-1}(x)=\frac{x}{3}+\frac{8}{3} \\ \\ \\ \therefore\Rightarrow \\ \\ \\ h[h^{-1}(x)]=3[\frac{x}{3}+\frac{8}{3}]-8=x+8-8=x \\ \\ \\ \\ h[h^{-1}(x)]=x \\ \\ \\ \\ h[h^{-1}(-5)]=-5 \end{gathered}[/tex]What is the opposite of the number −12?
A(-1/12
B(1/12
C(0
D(12
Answer: D(12)
Step-by-step explanation: To find the opposite it the number you would do -12= -12 x -1 = 12
A very large bag contains more coins than you are willing to count. Instead, you draw a random sample of coins from the bag and record the following numbers of eachtype of coin in the sample before returning the sampled coins to the bag. If you randomly draw a single coin out of the bag, what is the probability that you will obtain apenny? Enter a fraction or round your answer to 4 decimal places, if necessary.Quarters27Coins in a BagDimes21Nickels24Pennies28
Given:
The number of quarters = 27
The number of dimes = 21
The number of Nickels = 24
The number of Pennies = 28
Required:
Find the probability to obtain a penny.
Explanation:
The total number of coins = 27 + 21 + 24 +28 = 100
The probability of an event is given by the formula:
[tex]P=\frac{Number\text{ of possible outcomes}}{Total\text{ number of outcomes}}[/tex]The number of penny = 28
[tex]\begin{gathered} P(penny)=\frac{28}{100} \\ P(penny)=0.28 \end{gathered}[/tex]Final Answer:
The probability of obtaining Penny is 0.28.
Comparing Two Linear Functions (Context - Graphically)
start identifying the slope and y-intercept for each high school.
The slope represents the growth for each year, in this case for high school A is 25 and for high school B is 50.
The y-intercept is the number of students that are enrolled currently, in this case for A is 400 and for B is 250.
The complete equations in the slope-intercept form are
[tex]\begin{gathered} A=25x+400 \\ B=50x+250 \end{gathered}[/tex]Continue to graph the equations
High school B is projected to have more students in 8 years.
Trapezoid W'X'Y'Z' is the image of trapezoid W XYZ under a dilation through point C What scale factor was used in the dilation?
The scale factor is basically by what we need to multiply the original to get the dilated one.
Simple.
We can see that the original one is Trapezoid WXYZ and the dilated one is W'X'Y'Z'.
THe dilated trapezoid is definitely bigger than original. So the scale factor should be larger than 1.
One side of original is "6" and the corresponding side of dilated trapezoid is "14".
So, what we have to do to "6", to get "14"??
This is the scale factor!
To get 14, we have to multiply 6 with, suppose, "x", so:
[tex]\begin{gathered} 6x=14 \\ x=\frac{14}{6} \\ x=\frac{7}{3} \end{gathered}[/tex]Hence, SF is 7/3
Jonathan is playing a game or a regular board that measures 60 centimeters long and 450 mm wide. which measurement is closest to the perimeter of the Jonathan's game board in meters?
According to the problem, the length is 60 cm and the width is 450 mm.
Let's transform 450mm to cm. We know that 1 cm is equivalent to 10 mm. So,
[tex]450\operatorname{mm}\times\frac{1\operatorname{cm}}{10\operatorname{mm}}=45\operatorname{cm}[/tex]Then, we use the perimeter formula for rectangles.
[tex]P=2(w+l)[/tex]Where w = 45 cm and l = 60 cm.
[tex]\begin{gathered} P=2(45\operatorname{cm}+60\operatorname{cm})=2(105cm) \\ P=210\operatorname{cm} \end{gathered}[/tex]The perimeter is 210 centimeters long.However, we know that 1 meter is equivalent to 100 centimeters.
[tex]P=210\operatorname{cm}\cdot\frac{1m}{100\operatorname{cm}}=2.1m[/tex]Hence, the perimeter, in meters, is 2.1 meters long.
Option A is the answer.b) A survey on the nationality of the student in the St Thomas international school is conducted and the results are shown below:i) if two students are randomly selected, what is the probability that both of them are European (correct to 4 decimal places)ii) if one student is randomly selected, what is the probability that a student is not Asian. (correct to 4 decimal places)
Given:-
A survey on the nationality of the student in the St Thomas international school is conducted and the results are shown.
To find if two students are randomly selected, what is the probability that both of them are European and if one student is randomly selected, what is the probability that a student is not Asian.
So now the total number of students are,
[tex]230+110+85+25=450[/tex]So now the probability of getting European is,
[tex]\frac{110}{450}=\frac{11}{45}[/tex]So the probability is,
[tex]\frac{11}{45}[/tex]So now the probability is asian is,
[tex]\frac{230}{450}=\frac{23}{45}[/tex]So the probability that it is not asian is,
[tex]1-\frac{23}{45}=\frac{45-23}{45}=\frac{22}{45}[/tex]so the required probability is,
perpendicular lines homework
I need help with system B. I have one right. And if the answer is infinitely. It asks to satisfy and it has Y=
We have the next system of equations
[tex]\begin{gathered} -5x-y=5 \\ -5x+y=5 \end{gathered}[/tex]We can sum both equations we can eliminate one variable
[tex]\begin{gathered} -10x=10 \\ \end{gathered}[/tex]then we isolate the x
[tex]x=\frac{10}{-10}=-1[/tex]Therefore x=-1 then we substitute the value of x in order to find the value of y in the second equation
[tex]-5(-1)+y=5[/tex]Then we simplify
[tex]5+y=5[/tex]Then we isolate the y
[tex]y=5-5[/tex][tex]y=0[/tex]ANSWER
x=-1
y=0
A country's population in 1994 was 182 million.In 2002 it was 186 million. Estimatethe population in 2004 using the exponentialgrowth formula. Round your answer to thenearest million.
we have the exponential formula
[tex]P=Ae^{(kt)}[/tex]so
we have
A=182 million ------> initial value (value of P when the value of t=0)
The year 1994 is when the value ot t=0
so
year 2002 -----> t=2002-1994=8 years
For t=8 years, P=186 million
substitute the value of A in the formula
[tex]P=182e^{(kt)}[/tex]Now
substitute the values of t=8 years, P=186 million
[tex]\begin{gathered} 186=182e^{(8k)} \\ e^{(8k)}=\frac{186}{182} \\ \text{apply ln both sides} \\ 8k=\ln (\frac{186}{182}) \\ k=0.0027 \end{gathered}[/tex]the formula is equal to
[tex]P=182e^{(0.0027t)}[/tex]Estimate the population in 2004
t=2004-1994=10 years
substitute the value of t in the formula
[tex]\begin{gathered} P=182e^{(0.0027\cdot10)} \\ P=187 \end{gathered}[/tex]therefore
the answer is 187 millionWatch help videoGiven the matrices A and B shown below, find – B - A.318154B12be-12
Given two matrices
[tex]A=\begin{bmatrix}{-18} & {3} & {} \\ {-15} & {-6} & {} \\ {} & {} & {}\end{bmatrix},B=\begin{bmatrix}{-4} & {12} & {} \\ {8} & {-12} & {} \\ {} & {} & {}\end{bmatrix}[/tex]We will solve for the resultant matrix -B - 1/2A.
This operation is represented as
[tex]-B-\frac{1}{2}A=-\begin{bmatrix}{-4} & {12} & {} \\ {8} & {-12} & {} \\ {} & {} & {}\end{bmatrix}-\frac{1}{2}\begin{bmatrix}{-18} & {3} & {} \\ {-15} & {-6} & {} \\ {} & {} & {}\end{bmatrix}[/tex]Let's simplify the matrices further based on scalar operations that can be done here. The B matrix will be multiplied by -1 while the A matrix will be multiplied by 1/2. We now have
[tex]-B-\frac{1}{2}A=\begin{bmatrix}{4} & {-12} & {} \\ {-8} & {12} & {} \\ {} & {} & {}\end{bmatrix}-\begin{bmatrix}{-9} & {\frac{3}{2}} & {} \\ {\frac{-15}{2}} & {-3} & {} \\ {} & {} & {}\end{bmatrix}[/tex]Now, we apply the subtraction of matrices to the simplified matrix operation above. We have
[tex]\begin{gathered} -B-\frac{1}{2}A=\begin{bmatrix}{4-(-9)} & {-12-\frac{3}{2}} & {} \\ {-8-(-\frac{15}{2})} & {12-(-3)} & {} \\ {} & {} & {}\end{bmatrix} \\ -B-\frac{1}{2}A=\begin{bmatrix}{4+9} & {-12-\frac{3}{2}} & {} \\ {-8+\frac{15}{2}} & {12+3} & {} \\ {} & {} & {}\end{bmatrix} \\ -B-\frac{1}{2}A=\begin{bmatrix}{13} & {\frac{-27}{2}} & {} \\ {-\frac{1}{2}} & {15} & {} \\ {} & {} & {}\end{bmatrix} \end{gathered}[/tex]Hence, the resulting matrix for the operation -B - 1/2A is
[tex]-B-\frac{1}{2}A=\begin{bmatrix}{13} & {\frac{-27}{2}} & {} \\ {-\frac{1}{2}} & {15} & {} \\ {} & {} & {}\end{bmatrix}[/tex]what are the terms in 7h+3
Input data
7h + 3
Procedure
A term is a single mathematical expression.
3 = is a single term.
It is simply a numerical term called a constant.
7h = is also a single term. , The coefficient of the first term is 7
For the function f(x) = 6e^x, calculate the following function values:f(-3) = f(-1)=f(0)= f(1)= f(3)=
Consider the given function,
[tex]f(x)=6e^x[/tex]Solve for x=-3 as,
[tex]\begin{gathered} f(-3)=6e^{-3} \\ f(-3)=6(0.049787) \\ f(-3)=0.2987 \end{gathered}[/tex]Thus, the value of f(-3) is 0.2987 approximately.
Solve for x=-1 as,
[tex]\begin{gathered} f(-1)=6e^{-1} \\ f(-1)=6(0.367879) \\ f(-1)=2.2073 \end{gathered}[/tex]Thus, the value of f(-1) is 2.2073 approximately.
Solve for x=0 as,
[tex]\begin{gathered} f(0)=6e^0 \\ f(0)=6(1) \\ f(0)=6 \end{gathered}[/tex]Thus, the value of f(0) is 6 .
Solve for x=1 as,
[tex]\begin{gathered} f(1)=6e^1 \\ f(1)=6(2.71828) \\ f(1)=16.3097 \end{gathered}[/tex]Thus, the value of f(1) is 16.3097 approximately.
Solve for x=3 as,
[tex]\begin{gathered} f(3)=6e^3 \\ f(3)=6(20.0855) \\ f(3)=120.5132 \end{gathered}[/tex]Thus, the value of f(3) is 120.5132 approximately.
A population of values has a normal distribution with u = 203.6 and o = 35.5. You intend to draw a randomsample of size n = 16.Find the probability that a single randomly selected value is greater than 231.1.PIX > 231.1) =Find the probability that a sample of size n = 16 is randomly selected with a mean greater than 231.1.P(M > 231.1) =Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or Z-scores rounded to 3 decimal places are accepted.
Part 1:
The probability that a single randomly selected value is greater than 231.1 equals one minus the probability that it is less or equal to 231.1:
P(x > 231.1) = 1 - P(x ≤ 231.1)
Now, to find P(x ≤ 231.1), we can transform x in its correspondent z-score, and then use a z-score table to find the probability:
x ≤ 231.1 => z ≤ (231.1 - 203.6)/35.5, because z = (x - mean)/(standard deviation)
z ≤ 0.775 (rounding to 3 decimal places)
Then we have:
P(x ≤ 231.1) = P( z ≤ 0.775)
Now, using a table, we find:
P( z ≤ 0.775) ≅ 0.7808
Then, we have:
P(x > 231.1) ≅ 1 - 0.7808 = 0.2192
Therefore, the asked probability is approximately 0.2192.
Part 2
For the next part, since we will select a sample out of other samples with size n = 16, we need to use the formula:
z = (x - mean)/(standard deviation/√n)
Now, x represents the mean of the selected sample, which we want to be greater than 231.1. Then, we have:
z = (231.1 - 203.6)/(35.5/√16) = 27.5/(35.5/4) = 3.099
P(x > 231.1) = 1 - P(x ≤ 231.1) = 1 - P(x ≤ 231.1) = 1 - P( z ≤ 3.099) = 1 - 0.9990 = 0.0010
Therefore, the asked probability is approximately 0.0010.