How many students age 15 and above take a car to school? Show work
A. 18
B. 38
C. 87
Answers
im pretty sure its B or most likeley C
98 (total amt of students who take cars) - 60 (amount of students under 15 who take cars) = 38
Related Questions
Please help
graph x<2.
Answers
Answer:
Bottom right
Step-by-step explanation
Answer:
first answer is correct
3:5:7=....:30:...
help me keeds please
Answers
Answer:
3=6 5=10 7=14
Step-by-step explanation:
here's how to do it u wwould have to sum (+) up all the ratios then it would give u 15 after then u divide the sum by 15 hen u multiply by ratios .
Please
A man is lying on the beach, flying a kite. he holds the end of the kite string at ground level and estimates the angle of elevation of the kite to be 50
Answers
The kite's height above the earth is 287 feet.
A right-angled triangle is formed by the length of the string, the height of the kite (h) above ground, and the perpendicular distance from the end of the kite string to the man.
The link between the lengths and angles of a right-angled triangle is demonstrated through trigonometry.
Using trigonometric ratios,
the height of the kite above the ground is
sin(55) = h ÷ 350
h = 287 ft
As a result, the kite's height above ground is 287 feet.
A trigonometric function is a real function in mathematics that relates the angle of a right triangle to the ratio of the lengths of the sides. They are frequently used in earth sciences such as navigation, structural mechanics, astrophysics, geography, and many other fields.
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7+[-8-5^2]/(1-4)^3+17
Answers
2.6
Explanations:Given the expression;
[tex]\frac{7+\lbrack-8-5^2\rbrack}{(1-4)^3+17}[/tex]Simplify the expression in the bracket to have:
[tex]\begin{gathered} =\frac{7+\lbrack-8-25\rbrack}{(-3)^3+17} \\ =\frac{7+(-33)}{(-3\times-3\times-3)+17} \\ =\frac{7+(-33)}{-27+17} \end{gathered}[/tex]Simplify the result to have;
[tex]\begin{gathered} =\frac{7-33}{-10} \\ =\frac{-26}{-10} \\ =2.6 \end{gathered}[/tex]Hence the result of the given function on simplification is 2.6
TEST SCORES The average test score in a class is 74%. Half of the class scored within 7 points of the average.
One student received a score of x%. Which shows an expression that could be used to determine how far the student's score is from the average?
A. |74-7|
B. |x|-74
C. |x-74|
D. 74-|7|
Answers
It is to be noted that the absolute expression that shows how far the student's score is from the average is given as: "| x - 74| (Option C)
What is the justification for the above result?The student obtained a score of x% based on the question. As a result, x% might be larger or lower than the average score of 74%.
To establish how distant the student's score is from the average, we must subtract the student's score from the average score; i.e. (x - 74)
This difference, however, might be negative: as a result, the absolute value of (x - 78) must be calculated, yielding |x - 74|.
As a result, the phrase that may be used to assess how distant the student's score is from the average is as follows: |x - 74| which is the same as option c - An Absolute expression.
Absolute expressions are or modulus of a real number x, abbreviated |x| in mathematics, is the non-negative value of x regardless of its sign.
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X=
////////////////////////
Answers
Answer: [tex]x=90[/tex]
Step-by-step explanation:
Using the alternate exterior angles theorem,
[tex]180-x=x\\\\180=2x\\\\x=90[/tex]
Find the value of $x$ so that the ratios are equivalent.
$3$ to $2$ and $x$ to $18$
Answers
x=27
I think it's because if 3 is to 2 then 18+9=27. which means 27 is to 18.
The volume of a gas V held at a constant temperature in a closed container varies inversely with its pressure P. If the volume of a gas is 800 cubic centimeters when the pressure is 450 millimeters of mercury (mm Hg), find the volume when the pressure is 200 mm Hg.
Answers
SOLUTION:
Step 1:
In this question, we are given the following:
The volume of a gas V held at a constant temperature in a closed container varies inversely with its pressure P. If the volume of a gas is 800 cubic centimeters when the pressure is 450 millimeters of mercury (mm Hg), find the volume when the pressure is 200 mm Hg.
Step 2:
This is an application of Boyle's law which states that:
Boyle’s law is a gas law that states that the pressure exerted by a gas (of a given mass, kept at a constant temperature) is inversely proportional to the volume occupied by it. In other words, the pressure and volume of a gas are inversely proportional to each other as long as the temperature and the quantity of gas are kept constant.
[tex]\begin{gathered} Mathematically,\text{ we have that:} \\ V\text{ }\propto\text{ }\frac{1}{P} \\ Then,\text{ we have that:} \\ V\text{ =}\frac{k}{P}\text{ \lparen where k is a constant \rparen} \end{gathered}[/tex][tex]when\text{ V = 800 cubic centimetres , then P = 450 mm Hg}[/tex][tex]\begin{gathered} 800\text{ =}\frac{k}{450} \\ cross-multiply,\text{ we have that:} \\ \text{k = 800 x 450 = 360,000} \end{gathered}[/tex][tex]\begin{gathered} Then,\text{ the equation connecting V and P =} \\ \text{ V }=\frac{360,000}{P} \end{gathered}[/tex]Next:
[tex]when\text{ P = 200 mm Hg, we have that:}[/tex][tex]\begin{gathered} V\text{ = }\frac{360,000}{200} \\ \text{V = 1800 cubic centimetres } \end{gathered}[/tex]CONCLUSION:
The volume when the pressure is 200 mm Hg is:
[tex]V\text{ = 1800 cubic centimetres}[/tex]10. The data set below shows the mileage and selling prices of eight used cars of the same model. Mileage Price 21,000 $16,000 34,000 $11,000 41,000 $13,000 43,000 $14,000 65,000 $10,000 72,000 $12,000 76,000 $7,000 84,000 $7,000 (a) Calculate r , the correlation coefficient between these two variables. r = (b) Interpret the value of r : the association is positive or negative and (strong or moderate or weak or negligible) (c) Compute the regression line for predicting price from mileage. ˆ y = x + (d) Predict the price of a car with 30,000 miles. $ (e) Does the student with 43,000 miles on it have a higher or lower price than the one predicted by the regression line? Higher Lower
Answers
Step 1
Plot a graph with the given table.
Step 2
Calculate r, the correlation coefficient between the two variables.
[tex]\begin{gathered} \text{From the graph,} \\ r\text{ = }-0.839 \end{gathered}[/tex]Step 3
Interprete the value of r
[tex]\text{The association is a strong and negative relationship}[/tex]Step 3
Compute the regression line for predicting price from mileage
[tex]\hat{y}=-0.118136x+17688.4[/tex]Step 4
Predict the price of a car with 30,000 miles
[tex]\begin{gathered} \hat{y}=-0.118136(30000)+17688.4 \\ \hat{y}=-3,544.08+17688.4 \\ \hat{y}=\text{\$}14,144.32 \end{gathered}[/tex]Step 5
[tex]\begin{gathered} \hat{y}=-0.118136(43000)\text{ + 17688.4} \\ \hat{y}=-5079.848+17688.4 \\ \hat{y}=\text{\$}12608.552\text{ } \\ \hat{y}\approx\text{\$12608.55} \\ \text{The given price for the mileage of 43000 is \$}14000 \\ \text{Therefore, the student with 43000 mileage on it will have a higher price than the one predicted by the regression line.} \end{gathered}[/tex]a box contains 2828 red balls, 2020 green balls, 1919 yellow balls, 1313 blue balls, 1111 white balls, and 99 black balls. what is the minimum number of balls that must be drawn from the box without replacement to guarantee that at least 1515 balls of a single color will be drawn?
Answers
7069 are the minimum number of balls that must be drawn without replacement to complete the requirement that all balls of a single color be drawn.
First of all, we’ll look at the worst possible scenario and determine the minimum number of balls needed. We know that the color we are looking for is not blue, nor white, nor black (as there are less than 1515 of the same color when talking about those). In our worst possible scenario, we’ll first pull out all the blue, white, and black balls. Add them up. That means that we’ll definitely pull out 2523 balls( 1111 white + 1313 blue + 99 black). We are not done yet. From all the given balls, we are left with red, green, and yellow colored balls. In our worst scenario, we’ll pull out 1514 balls of every single color, and then we’ll finish it with one color (it doesn’t matter which). Since, we have 3 different colors left, that’s 3*1515+1 = 4545+1 = 4546 that is 4546 more balls.
To finish, we simply add the first 2523 balls with 4546, yielding 2523+4546 = 7069 balls.
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6 divided by 396 long divison attatch work !
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there is an ongoing debate about how many spaces should be placed after a period in typed documents. alana read about a study where 100100100 participants all read the same document typed in courier new font. half of the participants were randomly assigned the document with one space after each period, and the other half were given the document with two spaces after each period. participants who read the document with two spaces after each period were able to finish reading significantly faster than those with one space after each period. alana concluded that using two spaces after each period will help people read all documents faster. why is alana's conclusion not appropriate?
Answers
Alana's conclusion from the study is not appropriate.
Why is Alana's conclusion from the study is not appropriate?
In this study, there was no attempt made to research the alternative fonts. Alana reads about the study that includes only courier new font and arrives at a conclusion.The study in inconsistent with the standard scientific methods as it is not inclusive of all factors and possibilities and is thus inappropriate.What is an appropriate study?
The achievement of the research objectives is ensured by an appropriate study design. The important element of appropriate studies known as formulated research are missing from observational studies.Observational studies are in which the outcome is not tried to be altered through analysis unlike appropriate studies.This describes an investigation of a specific phenomenon that meets all requirements and adheres to the scientific method.To learn more about appropriate studies, refer:
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Jane has a pre-paid cell phone with NextFell. She can't remember the exact costs, but her plan has a monthly fee and a charge for each minute of calling time. In June she used 200 minutes and the cost was $75.00. In July she used 680 minutes and the cost was $195.00.
Answers
We are given that Jane used 200 minutes and the cost was $75, and also she used 680 minutes and the cost was $195. To determine a function of the cost "C" as a function of the minutes "x" we will assume that the behavior of this function is that of a line. Therefore, the function must have the following form:
[tex]C(x)=mx+b[/tex]Where "m" is the slope and "b" the y-intercept. We will determine the slope using the following formula:
[tex]m=\frac{C_2-C_1}{x_2-x_1}[/tex]Where:
[tex](x_1,C_1),(x_2,C_2)[/tex]Are points in the line. The given points are:
[tex]\begin{gathered} (x_1_{},C_1)=(200,75) \\ (x_2,C_2)=(680,195) \end{gathered}[/tex]Substituting in the formula for the slope we get:
[tex]m=\frac{195-75}{680-200}[/tex]Solving the operations we get:
[tex]m=\frac{120}{480}=\frac{1}{4}[/tex]Now we substitute in the formula for the line:
[tex]C(x)=\frac{1}{4}x+b[/tex]Now we determine the value if "b" by substituting the first point. This means that when C = 200, x = 75.
[tex]200=\frac{1}{4}(75)+b[/tex]Solving the product:
[tex]200=18.75+b[/tex]Now we subtract 18.75 from both sides:
[tex]\begin{gathered} 200-18.75=b \\ 181.25=b \end{gathered}[/tex]Therefore, the formula of the cost is:
[tex]C(x)=\frac{1}{4}x+181.25[/tex]Part B. We are asked to determine the cost is there is a consumption of 323 minutes. To do that we will substitute in the formula for "C" the value of x = 323.
[tex]C(323)=\frac{1}{4}(323)+181.25[/tex]Solving the operations we get:
[tex]C(323)=262[/tex]Therefore, the cost is $262.
Answer:
Step-by-step explanation:
We will make use of algebra here.
First of all, we know that the monthly fee will be the same throughout all the months.
So, let's consider that cost to be the yet-to-find constant: [tex]a[/tex].
A charge is accumulated for every minute on the call, so let's consider that minutely charge to be the constant: [tex]b[/tex].
[tex]x[/tex] is the number of minutes spent on the call.
So, the total charge after talking for [tex]x[/tex] minutes would be:
[tex]b \times x\\=bx[/tex]
The monthly cost is the sum of the monthly fee and the total charge.
So, if this is represented mathematically, we get:
[tex]C(x)= a+bx[/tex]
A piece of information that we have is that, after calling for 200 minutes (which means [tex]x=200[/tex]), the monthly cost ( [tex]C(x)[/tex] ) would be $75.
Upon substituting these values in the equation we found above, we get:
[tex]C(x)=a+bx\\\\75=a+200b[/tex]
Similarly, we have another piece of information, which states that calling for 680 minutes ([tex]x=680[/tex]) produced a monthly cost of $195.
Upon substituting these values in the equation we found above, we get:
[tex]C(x)=a+bx\\\\195=a+680b[/tex]
And, thus we have found a system of equations:
[tex]a+200b=75\\a+680b=195[/tex]
For the first equation, let's make [tex]a[/tex] the subject:
[tex]a+200b=75\\\\a+200b-200b=75-200b\\\\a=75-200b[/tex]
Substitute this expression for [tex]a[/tex] into the second equation:
[tex]a+680b=195\\\\75-200b+680b=195\\\\75+480b=195[/tex]
Find the value of [tex]b[/tex] using this equation:
[tex]75+480b=195\\\\75+480b-75=195-75\\\\480b=120\\\\\frac{480b}{480}=\frac{120}{480}\\\\b=\frac{1}{4}[/tex]
Insert the value for [tex]b[/tex] into the expression for [tex]a[/tex]:
[tex]a=75-200b\\\\a=75-200(\frac{1}{4})\\\\a=75-50\\\\a=25[/tex]
Since we have the values for the constants [tex]a[/tex] and [tex]b[/tex], we can complete the function/equation [tex]C(x)[/tex]:
[tex]C(x)=a+bx\\\\C(x)=25+\frac{1}{4}x[/tex]
So, the answer for (A) is:
[tex]C(x)=25+\frac{1}{4}x[/tex]
For (B), we have to find the monthly bill/cost ( [tex]C(x)[/tex] ) when 323 minutes have been spent on calling.
So, we just have to substitute [tex]x[/tex] for 323, since [tex]x[/tex] represents the number of minutes spent on calling:
[tex]C(x)=25+\frac{1}{4}x\\\\C(x)=25+\frac{1}{4}(323)\\\\C(x)=25+80.75\\\\C(x)=100.75[/tex]
The answer for (B) is [tex]\$100.75[/tex]
most states run a lottery game in which players may select a three digit number, then later that day a televised drawing randomly selects a winning three digit number. suppose you select one three digit number and buy a ticket. what is the probability that your three digit number is an exact match with the winning three digit number?
Answers
The probability that the selected three digit number is an exact match with the winning three digit number = 1/1000
The 10 digits are 0, 1, 2, 3, 4, 5, 6,7, 8, 9. From these 10 digits 3 digits are selected.
Total number of ways of selecting a three-digit number = Number of ways of selecting a digit from 10 digits for each place(one's, ten's and hundred's place)
Thus a three-digit number can be selected in 10 x 10 x 10 = 1000 ways.
So there are 1000 possibilities for a three digit number.
From this only one choice matches exactly with the winning number.
So the number of favorable outcome = 1
Hence, The probability that the selected three digit number is an exact match with the winning three digit number = 1/1000
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we have a coin which, with equal odds, is either weighted so that heads has .75 probability, or weighted so that heads has .25 probability. we flip the coin twice and observe two heads. what is the conditional probability that the coin is weighted toward heads with .75 probability?
Answers
The Conditional Probability that the coin is weighted towards heads is 0.25/0.75 . Conditional probability is the result of Bayes’ Theorem .
A coin is tossed twice . So, total outcomes are { HH , TH , HT, TT} that is 4 .
Probability= favourable outcomes / total outcomes
Probability of getting two heads = ¼ = 0.25
Favourable outcomes are { HH , HT, TH}
Probability of getting at least one head = ¾ = 0.75
Conditional probability is measure of the probability of an event occurring, given that another event has already occurred.
Formula , P(A|B) = P(A and B)/ P(B)
Here, p(A|B) is conditional probability of A given B
P(B) is probability of event B occur
P(A and B) is probability of both events A and B occur
We have to find conditional probability that coin is weighted towards heads and it is = Probability of getting both heads / probability of getting at least one head
= ¼ / ¾ = 0.25 / 0.75
Which is required result .
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Which of the following is a graph of a function
Please help as soon as possible!!!!!!
Answers
To determine if a graph is a function, it has to pass what we call the “Vertical Line Test.” In this test, the x-coordinate cannot repeat, and the graph cannot have multiple points on the same vertical line. An example of two points that would make a graph not a function would be (2, 5) and (2, 3). Because 2 repeats, the graph collectively isn’t a function. Graph A is the only graph that passes this test, so it would be a function.
PLEASE HELP ASAP! What is the rate of change (slope) and the initial value (y-axis) for this table?
Answers
Answer: m = 24
Step-by-step explanation:
The right side of the table is the x value, and the left side is the y value.
Pick two points, I will pick (1,35) and (3,83).
Once you pick the points, input them in the rise over run formula:
y2-y1/x2-x1
83-35/3-1 = 48/2 = 24
1+2 |x-1| less than or equal to 9
Answers
SOLUTION
The question is
[tex]1+2|x-1|\leq9[/tex]Now let's solve. This becomes
[tex]\begin{gathered} 1+2|x-1|\leq9 \\ 2|x-1|\leq9-1 \\ 2|x-1|\leq8 \\ \\ \text{dividing both sides by x we have} \\ \\ |x-1|\leq4 \end{gathered}[/tex]This becomes
[tex]\begin{gathered} x-1\leq4 \\ or \\ x-1\ge4 \end{gathered}[/tex]So we have our x as
[tex]undefined[/tex]In Emily's physics class, she had to solve the equation 9 = 12at2 + ut for u. Each step of her work is shown below.
Use the drop-down menus to explain each step.
Answers
The equation of u when it is the subject is u = 9/t - 12at
How to determine the solution for the equation for u?From the question, the original equation is given as
9 = 12at2 + ut
Next, we rewrite the equation to show the exponents
This is represented as
9 = 12at² + ut
To solve further, we simply isolate the variable term ut
This is done by subtracting 12at² from both sides of the equation
So, we have the following equation
9 - 12at² = 12at² - 12at² ut
Evaluate the like terms in the equation
So, we have
9 - 12at² = ut
Lastly, divide both sides of the equation by t
So, we have
(9 - 12at²)/t = ut/t
Evaluate the quotients
9/t - 12at = u
Make us the subject
u = 9/t - 12at
Hence, the solution for the equation for u is u = 9/t - 12at
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which two county libraries charge the same penalty per week
Answers
Answer:
where's the rest of the question⁉️
4. The density of gold is 18 g/cm3. If the volume of a plece of gold is 13cm, how many grams will it be?
Answers
ANSWER:
Therefore there are about 234 grams
STEP-BY-STEP EXPLANATION:
We have that the density is given by this formula
[tex]\begin{gathered} d=\frac{m}{V} \\ \text{where m is the mass and V the volume} \end{gathered}[/tex]We have the value of the density and the volume, therefore we can calculate the number of grams as follows:
[tex]\begin{gathered} 18=\frac{m}{13} \\ m=18\cdot13 \\ m=234 \end{gathered}[/tex](a) Find an angle between 0° and 360° that is coterminal with 600°.(b) Find an angle between 0 and 2n that is coterminal withЗп2
Answers
Coterminal Angles are angles that share the same initial side and terminal sides.
Finding coterminal angles is as simple as adding or subtracting 360° or 2π to each angle, depending on whether the given angle is in degrees or radians.
QUESTION A
The angle is given as 600°.
To find the coterminal angle between 0° and 360°, we subtract 360° from the angle.
Therefore,
[tex]\text{Coterminal angle = 600 - 360 = 240}\degree[/tex]The coterminal angle is 240°.
QUESTION B
The angle is given as
[tex]-\frac{3\pi}{2}[/tex]To get an angle between 0 and 2π, we will add 2π to it.
Hence, we have
[tex]\begin{gathered} \text{Coterminal angle = 2}\pi-\frac{3\pi}{2} \\ =\frac{\pi}{2} \end{gathered}[/tex]The coterminal angle is π/2.
What is Y=2x+5 solved
Answers
The answer of the linear equation for Y=2x+5 is x = (y-5)/2.
What is linear equation?
An equation is said to be linear if the maximum power of the variable is consistently 1. Another name for it is a one-degree equation. The standard form of a linear equation in one variable is of the form Ax + B = 0. Now in this equation, x is a variable, A is a coefficient, and B is constant.
The given linear equation is,
Y=2x+5
Now, solve this linear equation for x
Take 5 to LHS it will change sign to -ve
y-5 = 2x
Next, take coefficient of x below to LHS
(y-5)/2 = x
Now, swap the sides
x = (y-5)/2
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how to find the inverse of f(x) = 3x - 7
Answers
To get the inverse of this function you need two steps. First, we leave the variable [tex]x[/tex] alone in the function. Finally, write [tex]f^{-1}(x)[/tex] where you see the letter [tex]x[/tex] and [tex]x[/tex] where you see the letter [tex]y[/tex].
First step:Leave the variable [tex]x[/tex] alone.
[tex]y=3x-7[/tex][tex]y+7=3x[/tex][tex]\frac{y+7}{3}=x[/tex]Last step:Make lettering according to the rule above.
[tex]\frac{x+7}{3} =f^{-1}(x)[/tex]2.a statewide real estate sales agency, farm associates, specializes in selling farm property in the state of nebraska. its records indicate that the mean selling time of farm property is 90 days. because of recent drought conditions, the agency believes that the mean selling time is now greater than 90 days. a statewide survey of 100 farms sold recently revealed that the mean selling time was 94 days, with a standard deviation of 22 days. at the .10 significance level, has there been an increase in selling time?
Answers
The increase in the selling price is 1.818.
Test statistic:
A test statistic is a statistic used in statistical hypothesis testing. A hypothesis test is typically specified in terms of a test statistic, considered as a numerical summary of a data-set that reduces the data to one value that can be used to perform the hypothesis test.
The given values are:
a = 0.1
x = 94
μ = 90
The formula for test statistic will be:
t = ((x- μ) / ([tex]\frac{s}{vn}[/tex])
Now put the values in the given equation we have:
t = (94-90) / ([tex]\frac{22}{10}[/tex])
= 4/2.2
= 1.818
Therefore the increase in the selling price is 1.818.
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4. Find all values of x that make the statement true.
Answers
By solving ( 3 / x - 4) = (x - 5) / x equation we get ,
x = 10 and x = 2 .
Solution:
Given ( 3 / x - 4) = (x - 5) / x,
3x = (x - 5) (x - 4)
By solving this equation,
3x = x( x - 5 ) - 4( x- 5)
3x = x² - 5x - 4( x - 5)
3x = x² - 5x - 4x + 20
3x = x² - 9x + 20 = 0
3x - x² + 9x -20 = 0
12x - x² - 20 = 0
-x² + 12x -20 = 0
-1(x(x - 2 ) - 10( x - 2 )) = 0
-1( x - 10) ( x - 2) = 0
x - 10 = 0
x - 2 = 0
∴ x = 10
x = 2
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Marty graphs the hyperbola (y+2)2/36−(x+5)2/64=1 .
How does he proceed?
Drag a value, phrase, equation, or coordinates in the boxes to correctly complete the statements.
Put responses in the correct input to answer the question. Select a response, navigate to the desired input and insert the response. Responses can be selected and inserted using the space bar, enter key, left mouse button or touchpad. Responses can also be moved by dragging with a mouse.
Marty first identifies the center of the hyperbola as Response area, and that the hyperbola opens Response area. Since a = Response area, the coordinates of the vertices are Response area.
The slopes of the asymptotes of this parabola are ± Response area, and the asymptotes pass through the center of the hyperbola. The equations of the asymptotes are Response area.
Once this information is gathered, the asymptotes are graphed as dashed lines, and the hyperbola is drawn through the vertices, approaching the asymptotes.
Answers
To construct the graph of the hyperbola, the procedure is as follows:
Marty first identifies the center of the hyperbola as (-5,2), and that the hyperbola opens up and down. Since a = 6, the coordinates of the vertices are (-5, -4) and (-5, 8).The slopes of the asymptotes of this parabola are a = ± 3/4, and the asymptotes pass through the center of the hyperbola. The equations of the asymptotes are y - 2 = ± 3/4(x + 5).Equation of an hyperbolaThe equation of a vertical hyperbola with center (x*, y*) is given according to the following equation:
(y - y*)²/a² - (x - x*)²/b² = 1.
A vertical hyperbola opens up and down.
In this problem, the equation is:
(y + 2)²/36 - (x + 5)²/64 = 1.
Hence the center is:
(-5, 2).
The value of coefficient a is:
a² = 36 -> a = 6.
Then the vertices of the hyperbola are:
(-5, 2 - 6) = (-5,-4).(-5, 2 + 6) = (-5,8).The slopes of the asymptotes of the parabola are given as follows:
±a/b.
Hence:
a/b = 6/8 = 3/4.-a/b = -6/8 = -3/4.Since the asymptotes pass through the center, the equation is:
y - 2 = ± 3/4(x + 5).
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SAMANTHA HAS $27 TO RENT A BIKE FROM CYCLES RUS. SHE
HAS TO PAY A $IO FEE PLUS $2 FOR EVERY HOUR SHE HAS THE
BIKE. WRITE AND SOLVE AN INEQUALITY TO FIND THE
MAXIMUM NUMBER OF HOURS SAMANTHA CAN RENT THE BIKE.
Answers
Answer:
2 hours
Step-by-step explanation:
10+10= 20, so $20 fee
2+2= 4, so a fee for every hour she has the bike.
20+4= $24, so 2 hours maximum
If you tried adding another hour (which would be $12) that would equal $36 which is over her budget.
Please help!
Write an equation that represents the function graphed in blue by using transformations from y = |x| , which is graphed in green.
Answers
Answer:
-1/4*|X-1|Step-by-step explanation:
Let the green graph be G and the blue graph, be B:
1) Be cognate of the fact that the function in blue is completely negative, while the upper green graph is positive
Note: First, we should note that the blue function must therefore be a transformation of the Green function.
This means B takes the form:
y = (s)*a*|X+b|
We are required to find a, b, and s, where s is the sign.
2) From (1), we can deduce that, if graph G was transformed into B, then the first transformation begins by reflecting G along the X-axis (multiplying by -1).
Therefore, s = -1
3) From (2), it follows that the first transformation produces the following effect:
y = |X| transformed to y = -|X|
and B now takes the form y = -a*|X+b|
4) We notice again that the apexes of both functions do not touch. This means G was not only reflected along the X-axis but was also shifted or translated along the X-axis.
5) Building from (4), we notice that the Blue function takes a value of 0 when x is 1. If we put this in the general equation for B;
Finding b:
y = -a*|X+b| implies;
0= -a*|1+b|
|1+b| = 0/-a
|1+b| = 0
1+b = 0
b = -1and y becomes:
y = -a*|X-1|Finding a:
Notice also that when the x is 5, the Blue function now takes a value of -1. If we put this in a general equation for B;
y = -a*|X-1|
-1 = -a*|5-1|
-1 = -a*|4|
-4a = -1
a = 1/4The general equation for blue, B:y = -1/4*|X-1|Blaise M.
Make up a word problem to solve for system of equations. Be creative
Answers
Consider the following problem.
A student library has 24 tables, X tables with 4 seats each, Y tables with 6 seats each, and Z tables with 10 seats each. The total seating capacity of the cafeteria is 148. For a special student academic meeting, half of the X tables, 1/4 of the Y tables, and 1/3 of the Z tables will be used, for a total of 9 tables. Determine X, Y, and Z.
The conditions of this problem give rise to the following system of equations
[tex]x\text{ +y + z = 24}[/tex][tex]4x\text{ + 6y + 10z = 148}[/tex][tex]\frac{1}{2}x\text{ + }\frac{1}{4}y+\frac{1}{3}z\text{ = 9}[/tex]Multiplying the second equation by 1/2 and the third equation by 12, we get:
[tex]x\text{ +y + z = 24}[/tex][tex]2x\text{ + 3y + 5z = 74}[/tex][tex]6x\text{ + 3}y+4z\text{ = 108}[/tex]Now, multiply the first equation by -2 and add it to the second equation. In this way we obtain:
[tex]x\text{ +y + z = 24}[/tex][tex]y+3z\text{ =26}[/tex][tex]6x\text{ + 3}y+4z\text{ = 108}[/tex]Multiply the first equation by -6 and add it to the last equation. In this way we obtain:
[tex]x\text{ +y + z = 24}[/tex][tex]y+3z\text{ =26}[/tex][tex]\text{ -3y -2z = -36}[/tex]Finally, the process is completed by adding the second multiplied by 3 to the third equation.
[tex]x\text{ +y + z = 24}[/tex][tex]y+3z\text{ =26}[/tex][tex]7z\text{ = 42}[/tex]then, if we perform back substitution we get the desired solutions:
[tex]x=10[/tex][tex]z=6[/tex]and
[tex]y=8[/tex]We can conclude that the correct answer is:
Answer:Problem:
A student cafeteria has 24 tables, X tables with 4 seats each, Y tables with 6 seats each, and Z tables with 10 seats each. The total seating capacity of the cafeteria is 148. For a special student meeting, half of the X tables, 1/4 of the Y tables, and 1/3 of the Z tables will be used, for a total of 9 tables. Determine X, Y, and Z.
System of equations:
[tex]x\text{ +y + z = 24}[/tex][tex]4x\text{ + 6y + 10z = 148}[/tex][tex]\frac{1}{2}x\text{ + }\frac{1}{4}y+\frac{1}{3}z\text{ = 9}[/tex]Solution for this system of equations:
[tex]x=10[/tex][tex]y=8[/tex][tex]z=6[/tex]