How many stars are in a typical spiral galaxy, like our own?.

Answer:

m = 100 kg

Explanation:

F = ma

120 = m × 1.2

m = 120 ÷ 1.2

m = 100 kg

For a  flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω, the rate of energy being delivered is mathematically given as

P= 53 W

Generally, the equation for the Battery power  is mathematically given as

P = I (dt)V

Therefore

P= 2.50 A * 21.2V

P= 53 W

In conclusion, rate of energy being delivered

P= 53 W

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A flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω. It is connected to a 21. 2-v battery at the instant t = 0.The power developed will be 53 Watt.

Electric power is the product of the voltage and current. Its unit is the watt. It is the rate of the electric work done.

The given data in the problem is;

V is the voltage = 21.2 volt (V)

I is the electric current = 2.50 ampere (A)

The formula for the power is given as;

[tex]\rm P= V I \\\\\ P= 2.50 \times 21.2 \\\\ P=53 \ watt[/tex]

Hence electric power developed will be 53 Watts.

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Gwen's position is a function of his velocity and time

Gwen's position at 45 seconds is 63.9 feet

The function is given as:

v(t) = 250sin(t^2/120)/(t + 6)

When t = 45, we  have:

v(45) = 250sin(45^2/120)/(45 + 6)

Evaluate the sum, the exponent and the quotient

v(45) = 250sin(16.875)/(51)

Evaluate the sine ratio

v(45) = 250 * 0.2903/51

Evaluate the product and quotient

v(45) = 1.42

The position is then calculated as:

S(45) = v(45) * 45

This gives

S(45) = 1.42 * 45

Evaluate the product

S(45) = 63.9

Hence, Gwen's position at 45 seconds is 63.9 feet

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The displacement is the shortest between any two given points. The displacement of Gwen at the time period of 45 seconds is 63.9 feet.

The displacement is the shortest between any two given points. It is the product of velocity and time.

Given that the function of the velocity is [tex]v(t)=\dfrac{250\sin\left(\frac{t^{2}}{120}\right)}{\left(t+6\right)}[/tex]. Therefore, substitute the value of t as 45, to know the velocity of Gwen at 45 seconds,

[tex]v(t)=\dfrac{250\sin\left(\frac{t^{2}}{120}\right)}{\left(t+6\right)}[/tex]

[tex]v(45)=\dfrac{250\sin\left(\frac{45^{2}}{120}\right)}{\left(45+6\right)}\\\\v(45) = 1.42[/tex]

Since displacement is the product of velocity and time, therefore, the displacement is equal to,

[tex]s = v \times t\\\\s = 1.42 \times 45\\\\s = 63.9\rm \ feet[/tex]

Hence, the displacement of Gwen at the time period of 45 seconds is 63.9 feet.

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The necessary light intensity of the disk if the disk has mass 3.89 g and radius 2.40 cm is 6.483 x 10^12cd.

a. Given that:

I = P/A

= Force x Speed/Area

Gravitational force, F= GM1M2/r^2

F= ma, F= mg

I= mg x c/q

That is,

i= mass x gravitational acceleration x speed/area

b.

Mass= 3.89g

Radius, r= 2.40cm

i=?

i= mg x c/a

Speed of light= 3.0 x 10^8 m/s

Area, a= /pi r^2

= 3.142 x (0.024)^2

= 3.142 x 0.000576

= 0.0018m^2.

i= 3.89 x 10 x 3.0 x 10^8/0.0018

i= 6.483 x 10^12cd.

c. Light has no mass, therefore, it lacks momentum and cannot exert pressure for propulsion of materials.

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Answer:

ν = E/h = 4.56x10-19 J / 6.626x10-34 Jsec-1

ν = 6.88x1014 s-1

Explanation:

The frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

The number of waves that travel through a particular point in a given length of time is described by frequency. So, if a wave takes half a second to pass, the frequency is 2 per second.

Given that the energy of the photon is 4.56 x 10⁻¹⁹ J. Therefore, the frequency of the photon can be written as,

[tex]\rm \gamma = \dfrac{E}{h} = \dfrac{4.56x10^{-19} J}{6.626 \times 10^{-34}\ Jsec^{-1}}\\\\\\\gamma = 6.88 \times 10^{14}\ s^{-1}[/tex]

Hence, the frequency of a photon with an energy of 4.56 x 10⁻¹⁹ J is 6.88×10¹⁴ s⁻¹.

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Explanation:

The metre is currently defined as the length of the path travelled by light in a vacuum in 1299 792 458 of a second.

Hope it helps

Have a great day

TC

:DD

The range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.

The frequency of the visible light is determined  by using the following formulas relating speed of light and frequency of light.

c = fλ

where;

f = c/λ

f = (3 x 10⁸) / (300 x 10⁻⁹)

f = 1 x 10¹⁵ Hz

f = c/λ

f = (3 x 10⁸) / (700 x 10⁻⁹)

f = 4.29 x 10¹⁴ Hz

Thus, the range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.

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Explanation:

formation of compounds because the electric forces compel the atoms to attract each other and formed bonds which leads to the formation of chemical compounds. The attractive or repulsive interaction between any two charged bodies is known as an electric force so the attraction between two opposite charged atoms causes the formation of compounds so we can conclude that electric forces are important for the formation of compounds.

A hot tungsten filament emit electromagnetic radiation within the bulb because the tungsten is present within the bulb.

Due to its high melting point, tungsten can be heated to 3000°C where it glows white hot providing very good brightness due to the presence of argon.

So we can conclude that a hot tungsten filament emit electromagnetic radiation within the bulb.

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Electromagnetic radiation is made up of electromagnetic field waves. A hot tungsten filament emits electromagnetic radiation in the presence of Argon.

Electromagnetic radiation is made up of electromagnetic field waves that travel through space carrying electromagnetic radiant energy. Radio waves, microwaves, infrared, light, ultraviolet, X-rays, and gamma rays are all examples of electromagnetic waves.

When tungsten is heated to a temperature of around 3000 °C, the tungsten starts to emit lights. Tungsten when used in a bulb as a filament then because of its high melting point when electricity is passed through it, it starts to shine white-hot and provides extremely good brightness due to the presence of argon.

Hence, A hot tungsten filament emits electromagnetic radiation in the presence of Argon.

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Let's see

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{4}{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi\dfrac{2}{\sqrt{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=\dfrac{4\pi}{\sqrt{g}}[/tex]

So

[tex]\\ \rm\rightarrowtail g=\dfrac{16\pi ^2}{T^2}[/tex]

Answer:

g' = 1.09 m/s²

T = 12 s

Explanation:

Gravity due to acceleration

Time period

Answer:

90 km/h

Explanation:

we just divide the distance by the time to get the speed.

The speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.

The speed of the sound wave can be determined by applying echo formula as shown below;

v = 2d/t

where;

Substitute the given parameters and solve for speed.

v = (2 x 1.2)/(0.00695

v = 345.32 m/s

Thus, the speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.

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The position of the object can be used to find the kinetic energy in terms of k and a.

The term kinetic energy refers to the energy of an object that is in motion. The question is incomplete hence the syetem is not shown and the value of the kinetic energy can not be found in terms of  k and a.

Hence, when the system is shown, we can look at the position of the system and use it to obtain the value of the kinetic energy in terms of k and a.

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Answer:

K = 3/8k(A)^2

Explanation: Potential Energy --> Conservation of Energy

Because block B is at A/2, U = 1/2k(A/2)^2 which equals U = 1/8k(A)^2.

Now that you have the equation for potential energy, you can find kinetic energy in terms of the spring constant (k) and amplitude (A).

K = 3/8 k A^2

The measured specific heat will be less than the actual specific heat if a lower value is gotten than the actual mass.

This is defined as the quantity of heat needed to raise a substance's temperature by 1 degree Celsius.

If a substance has a low specific heat capacity , it loses water easily which makes the mass when measured to be smaller than the actual value.

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The magnitude of the work done by force experience by the object is (2a²b + 3b²)J.

The magnitude of the work done by force experience by the object is calculated as follows;

W = f.d

where;

The work done by the force is determined from the dot product of the force and the displacement of the object.

F = (2xyi + 3yj).(a + b)

W = (2abi + 3bj).(ai + bj)

W = (2a²b + 3b²)J

Thus, the magnitude of the work done by force experience by the object is (2a²b + 3b²)J.

The complete question is below:

The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.

How much work does the force do?

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The total work done  for an object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m is 3ab N.

Work done is the force applied on a body to move it over a distance. Work done for inclined plane can be given as,

[tex]W=F\times d[/tex]

Here (F) is the magnitude of force and (d) is the distance traveled.

An object moving in the xy-plane is subjected to the force

[tex]\vec f =(2xy\hat i +3y\hat j)[/tex]

Here, x and y are in meter.

The particle moves from the origin to the point with coordinates (a, b) by moving first along the x-axis to (a, 0), then parallel to the y-axis.

For the first part, the particle moves along x-axis. It moves zero along x-axis. Thus, the force, as y=0.

[tex]W_1=\int\limits^a_0 {2xy\hat i} \, dx =0\\[/tex]

Now, when the object moves along y-axis,

[tex]W_2=\int\limits^a_0 {3y\hat j} \, dx \\W_2=3\int\limits^b_0 {y\hat j} \, dx\\W_2=3y(a-0)\\W_2=3ba\\W_2=3ab[/tex]

Total work done,

[tex]W=0+3ab\\W=3ab\rm\; N[/tex]

Thus, the total work done  for an object moving in the xy-plane is subjected to the force f⃗ =(2xyı^ 3yȷ^)n, where x and y are in m is 3ab N.

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Answer:

Sound waves cannot travel through empty space

sound can travel through liqui

Sound waves cannot travel through empty space but can travel through liquids. Waves make the particles of matter up and down but do not along with them. The light waves are not true mechanical waves. Therefore, options (A), (B), (C), and (E) are correct.

Sound can transmit through liquids, gases, and plasma as longitudinal waves, also known as compression waves. It needs a medium to propagate so it can be propagated through solids as both longitudinal waves and transverse waves.

Longitudinal sound waves contain alternating pressure deviations causing compression and rarefaction, while transverse waves have waves of alternating shear stress perpendicular to the direction of propagation.

Waves can make matter move up and down or from side to side but do not carry along with them. Light waves are not considered true waves because they carry without the involvement of the motion of matter.

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Answer:

the acceleration of the car is 3 m/s².

Explanation:

The experiment was conducted in my toilet wash hand sink with a bar soap 30 centimeter away from the faucet, the number of drips record per minute is 120 drips

Data

Calculation for the number of drips per minute

= 20*6

= 120 drips

What is Control Experiment

Control  experiment are carried out to minimize the effects of variables other than the independent variable

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She need to release the cluch slowly and apply force on the accelator other than place her vehicle's gear in Drive and accelerate

We drive a car by applying pressure on the accelator, remove foot from the brakes and releasing cluch slowly. When the vehicle get speed, we have to change the gear.

So we can conclude that She need to release the cluch slowly and apply force on the accelator for driving a car.

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Hydroelectric dams generate electricity makings use of run-of-the-river systems, in which turbines are placed into the natural water flow.

Generally, Hydroelectric dams produce electricity by making use of turbines and generators, in a process where mechanical energy is produced when moving water turns the rotors of a turbine.

In conclusion, Hydroelectric dams use run-of-the-river systems, in which turbines are placed into the natural water flow.

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Which describes the vector calculation giving the magnetic force on a charged particle moving through a magnetic field? It is the cross product of the velocity vector and the magnetic field vector, which gives a vector perpendicular to those vectors.

Answer:

Planets that are farther from the sun than the earth (all but Mercury and Venus) will exhibit retrograde motion.

If the position of the planet is observed relative to the background stars, the planet will appear to move backward relative to the stars when the earth is moving in an Eastward direction faster than the planet, and the planet appears to move backwards relative to the stars

(The planet will be on the side of the earth that is opposite that of the sun)

The steps in the separation include;

Separation techniques has to do with how to obtain a substance in the presence of other substances. In this case, we have the substance XYZ mixed with iron filling and sand.

The separation process begins by using a magnet to remove all the iron fillings. Secondly, water is added and the substance XYZ dissolve in water since it is ionic. The sand can be separated form the solution by filtration.

Lastly, the solution is evaporated and the pure XYZ is obtained and sent to the police lab for analysis.

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Answer:

0.40s. He's dead, Jim.

Explanation:

The block accelerates at a rate of [tex]9.81 ms^-^2[/tex]. The moment it's 14 meters from the ground, it has traveled 39 meters, in about [tex]39=\frac12(9.81)t^2 \rightarrow 2.82 s[/tex].

For the man to dodge, the time left is the distance the block takes to go down to 2 meters from ground, or 51 meters from its starting point. Which translates in [tex]51=\frac12(9.81)t^2\rightarrow 3.22s[/tex]

He has thus less than half a second ([tex]0.40s[/tex] to be exact) to dodge.

The rotational inertia about an axis tangent to the sphere of the given mass and radius is ⁷/₅MR².

According to parallel axis theorem, the moment of inertia of a body about any axis is equal to the sum of the product of its mass and the square of the distance between the two parallel axis and the moment of inertia of the body about a parallel axis passing through its centre of mass.

The moment of inertia of the sphere about its parallel axis passing through its centre of mass = ²/₅MR²

The product of its mass and the square of the distance between the two parallel axis = MR²

Moment of inertia about an axis tangent to the sphere = MR² + ²/₅MR²

                                                                                           = ⁷/₅MR²

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The rotational inertia of a sphere of given mass and radius along a tangent axis is [tex]\rm \frac{7}{5} MR^2[/tex].

The sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation expresses a body's tendency to resist angular acceleration.

The given data in the problem is;

M is the sphere's mass.

R is the radius of a sphere

According to the parallel axis theorem,The rotational inertia of a sphere of given mass and radius along a tangent axis is found as;

[tex]\rm I=MR^2+\frac{2}{5} MR^2 \\\\ I=\frac{7}{5} MR^2[/tex]

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Answer: Mass Number

Explanation:

Atomic number is the number of just protons;

Nuclear Model is a theoretical description of what an atom looks like;

Energy levels are the energy states that electrons are in;

However, mass number is by definition the number of protons + number of neutrons. :)

a) The frequency of the wave is 4.0 Hz

b) The period T of the wave is 0.25s

c) The speed of the wave is 12m/s

Given the data in the question;

Frequency is simply the number of occurrences of a repeating phenomenon per unit time.

Period is the time needed for a complete cycle of vibration to pass a given point.

It is expressed as;

[tex]T = \frac{1}{f}[/tex]

Where f is the frequency

Speed is simply the distance traveled in a given interval of time or time ratio.

It is expressed as;

[tex]v = \lambda * f[/tex]

Where [tex]\lambda[/tex] is wavelength and f is frequency

a) Frequency

We said frequency is the number of occurrences of a repeating phenomenon per unit time.

Since the wave oscillates 4.0 times a second

Hence, the frequency of the wave is 4.0 Hz

b) Period

[tex]Period\ T = \frac{1}{f} \\\\Period\ T = \frac{1}{4.0Hz}\\\\Period\ T = \frac{1}{4.0s^{-1}}\\\\Period\ T = 0.25s[/tex]

Therefore, the period T of the wave is 0.25s

c) Speed

[tex]v = \lambda * f\\\\v = 3.0m * 4.0Hz\\\\v = 3.0m * 4.0s^{-1}\\\\v = 12ms^{-1}\\\\v = 12m/s[/tex]

Therefore the speed of the wave is 12m/s.

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Explanation:

No. Surface contact area also no. The main issue is the types of materials in contact. Surface roughness somewhat matters. Certain surfaces such as ice are special in that pressure melts the ice.

For  the​ body's position at time t  is mathematically given as

s(t)=4.9t^2+5t+16

Generally, the equation for the velocity is mathematically given as

v=ds/dt

v=9.8t+5 as velocity

s=4.9t^2+5t+c

s(0)=16

16=c

s(t)=4.9t^2+5t+16

In conclusion the​ body's position at time t

s(t)=4.9t^2+5t+16

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The body position at the given time t is s = 4.9t² + 5t + 16 if the velocity v= ds/dt and the initial position of a body moving along a coordinate line.

A numerical representation of the distance between two items or locations is called distance. A physical length or an approximation based on other considerations in physics or common usage can be referred to as distance.

We have:

[tex]\rm v = \frac{ds}{dt}[/tex]

[tex]\rm v = 9.8t+5[/tex]  is the velocity

[tex]\rm s = 4.9t^2+5t+c[/tex] is the speed

At t = 0 s(0) = 16

16 = c

[tex]\rm s = 4.9t^2+5t+16[/tex]

Thus, the body position at the given time t is s = 4.9t² + 5t + 16 if the velocity v= ds/dt and the initial position of a body moving along a coordinate line.

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Answer:

Because Geography says the higher one goes the colder it gets

Answer:

The nature of convection.

Explanation:

Warm air rises; cold air falls, so the freezer at the top provides cold air for the other compartments at the bottom.