how many grams of Na2co3 will be produced from the thermal decomposition of 250.0 g of nahco3?. 157.7 g​

Answers

Answer 1
The answer is 247.66
How Many Grams Of Na2co3 Will Be Produced From The Thermal Decomposition Of 250.0 G Of Nahco3?. 157.7

Related Questions

What volume of .15M NaOH could be produced with only 5 grams of NaOH and water?

Answers

The volume of 0.15M NaOH that could be produced with only 5 grams of NaOH and water is 0.83L.

How to calculate volume?

The volume of a substance can be calculated using the following expression:

Molarity = number of moles ÷ volume

The number of moles of NaOH can be calculated by dividing the mass of NaOH by its molar mass.

Molar mass of NaOH = 40g/mol

n = 5/40

n = 0.125moles

Volume of NaOH = 0.125mol ÷ 0.15M

Volume = 0.83L

Therefore, the volume of 0.15M NaOH that could be produced with only 5 grams of NaOH and water is 0.83L.

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What is the first principle energy level called

Answers

Answer is s orbital. Hopes this helps

Answer:

S orbital

Explanation:

no explanation, just a name you memorize

what is safe storage of produced materials exlain long ​

Answers

Answer:

Stacking storage sacks/ bags by interlocking, and placing heavier object on lower shelves.

Explanation:

Not sure what you meant exactly, but this is my best guess.

According to the given equation, how many moles of O, are required to react with 4.71 moles of C4H10?
2C4H10 + 1302 —8CO2 + 10 H

Answers

According to the given equation, 2C4H10 + 1302 — 8CO2 + 10H, 2 moles of O are required to react with 4.71 moles of C4H10.

How to calculate number of moles?

The number of moles of a compound can be calculated stoichiometrically as follows:

The balanced chemical equation is given as follows:

2C4H10 + 1302 — 8CO2 + 10H

Based on the above equation, 2 moles of C4H10 reacts with 13 moles of O

Therefore; 4.71 moles of C4H10 will react with 4.71 × 6.5 = 30.62 moles of O

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Answer: 30.6

Explanation:

How much 1.75 M H3PO4, in mL, would you need to add to 50.00 mL of 3.50 M Ca(OH)2 in order to neutralize the solution

Answers

The volume of the 1.75 M H₃PO₄ solution required to neutralize 50 ml of 3.5 M Ca(OH)₂ solution is 66.67 mL

Balanced equation

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

The mole ratio of the acid, H₃PO₄ (nA) = 2The mole ratio of the base, Ca(OH)₂ (nB) = 3

How to determine the volume of H₃PO₄ Molarity of acid, H₃PO₄ (Ma) = 1.75 MVolume of base, Ca(OH)₂ (Vb) = 50 mLMolarity of base, Ca(OH)₂ (Mb) = 3.5 MVolume of acid, H₃PO₄ (Va) =?

MaVa / MbVb = nA / nB

(1.75 × Va) / (3.5 × 50) = 2/3

(1.75 × Va) / 175= 2/3

Cross multiply

1.75 × 3 × Va  = 175 × 2

5.25 × Va = 350

Divide both side by 5.25

Va = 350 / 5.25

Va = 66.67 mL

Thus, the volume of the H₃PO₄ solution needed is 66.67 mL

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How many grams of oxygen gas are required to react completely with 2.8 g of solid sodium
in a synthesis reaction?

Answers

Explanation:

0.9 grams of oxygen gas we need.

Consider the structure shown.

A central S atom is bonded to three O atoms, two through a single line and one through two lines. There are six dots around two of the O atoms and 4 dots around the third O atom.

Determine the number of shared and unshared electrons in the structure.

shared (bonding) electrons:
unshared (lone, nonbonding) electrons:
Determine the number of shared and unshared pairs of electrons in the structure.
shared (bonding) pairs of electrons:
unshared (lone, nonbonding) pairs of electrons:
Determine the total number of valence electrons in the structure.
total valence electrons:

Answers

There are eight lone pairs and four bond pairs of electrons in the SO3 molecule. The valence electrons are found on the valence shell of the molecule.

Lewis structure of SO3

The molecule SO3 is represented by the Lewis structure shown in the image attached to this answer. The central atom in the molecule is sulfur.

There are sixteen non bonding electrons in the molecule and eight bonding electrons in the molecule Hence, we have eight lone pairs and four bond pairs of electrons in the molecule as shown in the Lewis structure.

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When Thomas Edison first sold electricity, he used zinc coulometers to measure charge consumption. (In a coulometer the cathode is weighed before a current is passed through it, and then again after the passage of current. The weight increase is proportional to the amount of current that flows through the cathode.) If the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, how much charge had passed through it

Answers

When the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

Ionization of zinc

The zinc metal will ionize as shown below;

Zn²₊ + 2e⁻ → Zn

The molar mass of zinc metal is given as 65.38 g/mol

Amount of charge passed through 65.38 g/mol

Amount of charge that will deposite the given mass of zinc is calculated as follows;

e⁻ = 96500 C

2e⁻ = 2 x 96500 C = 193,000 C

Amount of charge passed through 7.85 g

65.38 g -------> 193,000 C

7.85 g -----------> ?

= (7.85 x 193,000)/(65.38)

= 23,173 C

Thus, when the zinc plate in one of Edison's coulometers increased in mass by 7.85 g, the amount of charge that had passed through it is 23,173 C.

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(a)Determine the number of KNO3 molecules in 0.750 mol KNO3.
(b) What is the mass (in milligrams) of 2.39 x 1020 molecules of Ag2SO4.
(c) Estimate the number of NaHCO2 molecules in 3.429 g of NaHCO2.

Answers

A. The number of molecules in 0.750 mole of KNO₃ is 4.515×10²³ molecules

B. The mass (in milligrams) of 2.39×10²⁰ molecules of Ag₂SO₄ is 124 mg

C. The number of molecules in 3.429 g of NaHCO₂ is 3.04×10²² molecules

Avogadro's hypothesis

1 mole of substance = 6.02×10²³ molecules

A. How to determine the number of molecules

1 mole of KNO₃ = 6.02×10²³ molecules

Therefore,

0.750 mole of KNO₃ = 0.75 × 6.02×10²³

0.750 mole of KNO₃ = 4.515×10²³ molecules

B. How to determine the mass of Ag₂SO₄

6.02×10²³ molecules = 312 g of Ag₂SO₄

Therefore,

2.39×10²⁰ molecules = (2.39×10²⁰ × 312) / 6.02×10²³

2.39×10²⁰ molecules = 0.124 g

Multiply by 1000 to express in mg

2.39×10²⁰ molecules = 0.124 g × 1000

2.39×10²⁰ molecules = 124 mg of Ag₂SO₄

C. How to determine the number of molecules

68 g of NaHCO₂ = 6.02×10²³ molecules

Therefore,

3.429 g of NaHCO₂ = (3.429 × 6.02×10²³) / 68

3.429 g of NaHCO₂ = 3.04×10²² molecules

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Between a water molecule and an anion, like Cl-, a _____A_____ occurs between a _____B_____ of the water molecule and the anion.

Answers

Between a water molecule and an anion, like Cl-, a hydrogen bon occurs between hydrogen atom of the water molecule and the anion.

What is hydrogen bond?

Hydrogen bond is a weak bond between two molecules resulting from an electrostatic attraction between a proton in one molecule and an electronegative atom in the other. Hydrogen atom in water molecule attract anion due to presence of hydrogen bond.

So we can conclude that hydrogen bond occurs between hydrogen atom of the water molecule and the anion.

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Answer:

Explanation:88766

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What are the processes that lead to the formation of sedimentary rocks? I WILL GIVE BRAINLIEST

A.weathering and erosion followed by dispersion.
B.volcanic eruptions followed by dispersion,
C. volcanic eruptions followed by compaction
D.weathering and erosion followed by compaction

Answers

Answer:

erosion, weathering, dissolution, precipitation, and lithification So,D.weathering and erosion followed by compaction

Explanation:

mark me brainliest!!

A sample of excited atoms lie 3.314×10−19 J above the ground state. Determine the emission wavelength of these atoms.

Answers

The emission wavelength of the atoms excited above the ground state is 599.8 nm.

Emission wavelength of the atoms

The emission wavelength of the atom is determined by using the following formulas as shown below;

E = hf

E = hc/λ

where;

E is the energy of the atomh is Planck's constantc is speed of lightλ is the emission wavelength

λ = hc/E

λ = (6.626 x 10⁻³⁴ x 3 x 10⁸) / (3.314 x 10⁻¹⁹)

λ = 5.998 x 10⁻⁷ m

λ = 599.8 x 10⁻⁹ m

λ = 599.8 nm

Thus, the emission wavelength of the atoms is 599.8 nm.

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What does absolute zero physically mean at the particle level?
ASAP!

Answers

Answer:

Absolute zero is the lowest limit of the thermodynamic temperature scale, a state at which the enthalpy and entropy of a cooled ideal gas reach their minimum value, taken as zero kelvin.

Suppose that a car's starter motor draws 221 A of current for 6.20 s to start the car. What mass of Pb is oxidized in the lead–acid battery to supply this much electricity?

1.47 grams
Actually, I figured it out., here is the answer in case anyone is wondering:
It has two electrons in the process and Q is 1370.2 (Q= I*T= 221*6.2=1370.2) this gets to 1370.2/192736 (the number on the denominator is due to that fact that there are two electrons involved) That equals 0.007 Mols, and then using the grams per mol from the periodic table for lead, we get that value is equal to 1.47 grams.

Answers

The lead acid battery produces energy by oxidation of lead. The amount of lead oxidized in this case is 1.47 g.

What is lead acid battery?

The lead acid battery is the common accumulator that we have in use. It is made up of a cell that contains lead electrodes in an acid.

The oxidation of lead occurs according to thr equation;

Pb(s) ----> Pb^2+(aq) + 2e

If 207 g of Pb is oxidized by 2(96500)C

x g of lead is oxidized by (221 * 6.20) C

x = 207 g * (221 * 6.20) C/2(96500)C

x = 1.47 g

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Amphetamine (C9H13N) is a weak base with a pKb of 4.2.

Calculate the pH of a solution containing an amphetamine concentration of 215 mg/L .
Express your answer to two decimal places.

Answers

Weak base: [OH⁻] = √Kb.C

pKb = 4.2

[tex]\tt Kb=10^{-4.2}[/tex]

c = concentration

MM Amphetamine (C9H13N) = 135.21 g/mol

c = 215 mg/L = (0.215 g : 135,21 g/mol) / L = 0.00159 mol/L = 1.59  x 10⁻³ mol/L

[tex]\tt [OH^-]=\sqrt{10^{-4.2}\times 1.59\times 10^{-3}}=3.17\times 10^{-4}[/tex]

pOH = 4 - log 3.17

pH = 14 - (4 - log 3.17)

pH = 10 + log 3.17 = 10.50

1. How many joules of heat are necessary to melt 500 g of ice at its freezing point?

Answers

Answer: To melt 500 g of ice, 4000 joule of heat is required.

Explanation:

I love the helps

The energy required to melt one gram of ice is 334 J. Then the heat energy required to melt 500 g of ice into water is 1.6 × 10⁵ J.

What is heat of fusion ?

The change in energy associated with a phase change or any chemical reaction is called enthalpy change. Then, heat energy required to melt or freeze the substance.

The heat of fusion of ice is 334 J/g. Therefore, the heat energy required to melt the 1 g of ice is 334 J. Now the equation being used to  find the energy for m g of ice to melt is:

q = mHf.

Hf = 334J/g

m = 500 g

q = 500 × 334 J/g = 1.6 × 10⁵ J

Therefore, the heat energy needed to melt 500 g of ice to water is 1.6× 10⁵ J.

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Nitrogen (iv) oxide is passed through the combustion tube before copper is heated.Give a reason for this?​

Answers

to generate steam which act on copper

• How do the physical and chemical properties of each packaging type help create new and better product?

Answers

Answer:

chemical composition and physical properties of packaging materials determine their ability to fulfill the various functions expected from the package. 

If 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate, determine the molarity of the lead (II) nitrate solution. Note: First write the balance equation between potassium iodide and lead (II) nitrate.

Answers

The molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

How to calculate molarity?

The molarity of a solution can be calculated using the following formula:

CaVa/CbVb = na/nb

Where;

Ca = concentration of acidCb = concentration of baseVa = volume of acidVb = volume of basena = number of moles of acidnb = number of moles of base

The balanced equation of the reaction is as follows:

Pb(NO3)2 (aq) + 2KI (aq) → 2KNO3 (aq) + PbI2 (s)

22 × 2/18 × Cb = 2/1

44/18Cb = 2

Cb = 44 ÷ 36

Cb = 1.2M

Therefore, the molarity of the lead(II) nitrate solution if 22.00 mL of 2.00 M potassium iodide is needed to reach the equivalence point with 18.00 mL of lead (II) nitrate is 1.2M.

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NH4NO3+Zn(OH)2

Balance the equation

Answers

Answer:

Balanced equation: Zn (NO 3) 2 + 2 NH 4 OH = 2 NH 4 NO 3 + Zn (OH) 2 Reaction type: double replacement

Explanation:

What is the total number of atoms contained in 3.63 moles of nickel?

Answers

Answer:

Explanation:

1 mole of nickel contains 6.02 * 10^23 atoms

3.63 mols of nickel contain x atoms.

What you have is a proportion. A proportion consists of 2 ratios or 4 parts.

Of the 4 parts, you know three of them. The problem is to solve for the 4th.

1/3.63 = 6.02*10^23 / x               Cross multiply

x = 3.63 * 6.02* 10^23                Combine the right.

Answer: x = 2.19*10^24 atoms

Which of the following are characteristics of stratovolcanoes? Select all that apply.
More common near convergent boundaries
More common at hotspots
Effusive eruptions
Explosive eruptions
High viscosity magma
Low viscosity magma

Answers

Answer:

More common near convergent boundaries

Explosive Eruptions

Low Viscosity Magma

Explanation:

Hot spots like hawaii are better known for shield volcanoes. The magma is high viscosity which causes them to build pressure before erupting, leading to explosive eruptions.

*PLEASE HELP**
Which of the following aqueous solutions would have the lowest freezing point?
0.1 M sodium chloride
0.1 M calcium phosphate
0.2 M potassium sulfide
0.3 M aluminum nitrate
0.3 M barium chloride

Answers

Answer:

0.1 M Calcium phosphate

Explanation:

Which is also

0.1mCal2

At 4.5 atm of pressure, the solubility of a gas is 9.5 g/L.
How much gas, in grams, will dissolve in 1 L if the pres.
sure is reduced by 3.5 atm?

Answers

For a gas at 4.5 atm of pressure, the solubility of a gas is 9.5 g/L.

How much gas, in grams, is mathematically given as

s2=8.3782grams

What is the amount of gas in grams?

Generally, the equation for the   is mathematically given as

Si /S2 √P1/√P2

Therefore

[tex]s2=9.5*\sqrt{3.5}/\sqrt{4.5}[/tex]

s2=8.3782g

In conclusion. The solubility is

s2=8.3782g

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A patient who is scheduled for an x-ray expresses concerns about being exposed to radiation because he witnessed the effects of radiation on his father, who died of cancer. How should the dental assistant respond to this patient’s concerns?

Answers

The dental assistant should respond to this patient’s concerns by telling him that the amount of x-ray is very minimal and can't cause any negative effect.

What is X-ray?

This is a penetrating form of electromagnetic radiation which produces images of the structures inside your body.

Exposure to large amounts of radiation could increase risk of cancer which is why minimal amounts which is safe is adopted.

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When 20.4g of sodium metal are mixed with chlorine gas, are 52.0 g of sodium chloride
produced? Explain (use calculations to prove your answer.
.ves or no
-with amounts shown)

Answers

Answer: True

Explanation:

[tex]\mathrm{The\ balanced \ chemical \ equation\ is\ :}\\$2 \mathrm{Na}{(s)}+\mathrm{Cl}_{2}(g) \rightarrow 2 \mathrm{NaCl}(s)[/tex]

For Na

[tex]\\$Given mass $=20.4 \mathrm{~g}$ \ \ Molecular mass $=23 \mathrm{~g}\ \ $Number of moles $=\frac{\text { Given mass }}{\text { Molecular mass }}$$$\begin{aligned}&=\frac{20.4}{23} \\&=0.887 \text { moles }\end{aligned}$$Stoichiometric ratio of $\mathrm{Na}$ is same as that of $\mathrm{NaCl}$ i.e., $1: 1$.$\therefore$ Moles of $\mathrm{NaCl}=0.887$ motes[/tex]

For NaCl

[tex]$$\\\begin{aligned}\text { Molecular mass } &=23+35.5 \\&=58.5 \mathrm{~g}\end{aligned}$$[/tex]

[tex]\begin{aligned}\\& $\therefore$ Mass of $\mathrm{NaCl}$ produced will be=\text { No.of moles } \times \text { Molecular mass } \\&=0.887 \times 58.5 \\&=51.9 \\&\simeq 52 \mathrm{~g} \quad\end{aligned}$$[/tex]

Therefore, it is true that when 20.4g of sodium metal are mixed with chlorine gas, 52.0 g of sodium chloride is produced

Explanation:

The answer: True

I explained the answer to your question in the submitted photo

Which of the compounds below will dissociate in water? Check all that apply.
Ba(NO3)2
CaSO4
CO2
H2CO3
Mg3(PO4)2
those numbers are subscripts

Answers

An ionic compound does dissociate to a large extent in water. The compound that will completely dissociate in water here is Ba(NO3)2.

What is a soluble compound?

A soluble compound is a compound that can dissociate to a large extent in water. Not all compounds are soluble in water. Only ionic compounds are soluble in water.

The compound that  would dissolve in water among the list of compounds here is Ba(NO3)2.

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Answer:

A) Ba(NO3)2

B) CaSO4

C) CO2

D) H2CO3

E) Mg3(PO4)2

Explanation:

Wish I could give a good explanation, but I am still learning myself. Try searching up a video explaining this concept!

What do ferns and gymnosperms have in common?They are all vascular plants.
Reproduction depends on birds, bees, and other animals.
They all produce seeds.
They depend on water for fertilization.

Answers

Answer:

They are all vascular plants.

Explanation:

Vascular plants, also known as tracheophytes, are highly advanced plant creatures with leaves, stems, and roots, as well as a vascular system made up of conducting vessels. Ferns are herbaceous, pteridophytic vascular plants that do not produce flowers or seeds. Gymnosperms are vascular plants that produce seeds but do not produce blooms. Because the seeds aren't covered or protected by an ovary, they can be seen on the plant's leaves or other components. Angiosperms are flowering plants containing seeds that develop inside the ovary, which develops and produces fruit.

Answer:

They all produce seeds

Explanation:

In picture 4, the net force on the car is mostly the result of? A. Gravity. B. Constant velocity. C. Wind. D. Friction.

Answers

Answer:

D beacuse I think that's Force

Calculate the volume in mL of 0.279 M Ca(OH)2 needed to neutralize 24.5 mL of 0.390 M H3PO4 in a titration.



Note: the answer should have 3 significant digits. Do not include the unit mL in the answer.

Answers

The volume of the 0.279 M Ca(OH)₂ solution required to neutralize 24.5 mL of 0.390 M H₃PO₄ is 51.4 mL

Balanced equation

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

From the balanced equation above,

The mole ratio of the acid, H₃PO₄ (nA) = 2The mole ratio of the base, Ca(OH)₂ (nB) = 3

How to determine the volume of Ca(OH)₂ Molarity of acid, H₃PO₄ (Ma) = 0.390 MVolume of acid, H₃PO₄ (Va) = 24.5 mLMolarity of base, Ca(OH)₂ (Mb) = 0.279 MVolume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(0.39 × 24.5) / (0.279 × Vb) = 2/3

9.555 / (0.279 × Vb) = 2/3

Cross multiply

2 × 0.279 × Vb = 9.555 × 3

0.558 × Vb = 28.665

Divide both side by 0.558

Vb = 28.665 / 0.558

Vb = 51.4 mL

Thus, the volume of the Ca(OH)₂ solution needed is 51.4 mL

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