how does the gravitational pull of the blue supergiants impact the direction of your star?

Answers

Answer 1

Answer:

Blue supergiants represent a slower burning phase in the death of a massive star. Due to core nuclear reactions being slightly slower, the star contracts and since very similar energy is coming from a much smaller area (photosphere) then the star's surface becomes much hotter.

Explanation:

I know this may not be the answer youre looking for, but hopefully this can help somehow!


Related Questions

Fill in the blanks with the correct types of energy.

Answers

Energy in 1 is Chemical energy, 2 is Thermal energy, 3 is electrical energy the correct answer is option B that is, Chemical, thermal and electrical energy.

Energy Conversion

Energy is the ability to do work.

The conservation of energy state that energy can neither be created nor be distroyed but can be transformed from one form to the other.

According to the question,

CASE 1

The furnance makes use of burning coal to process water to steam in a boiler. The energy involved is Chemical energy.

CASE 2

The steam produce by the boiler is used to power the rotation of the turbine. The energy involved is Thermal energy.

CASE 3

The rotation of the turbine helps the generator to produce electricity. The  energy involved is electrical energy.

Therefore, the correct answer is option B that is, Chemical, thermal and electrical energy.

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An object moves at a constant speed.
​What will happen to this object's motion over time if no new forces are applied

A. it will change direction
B. it will increase speed
C. it will decrease in speed
D. It will maintain a constant speed

Answers

D

It’ll maintain its speed until a force acts upon it

If no new force is applied then the motion of the object will maintain a constant speed over time. So, the correct option is (D).

What is Inertia?

The inertia of a body is a property that resists efforts to set it in motion or, if it is already in motion, to change its speed or direction. A body's inertia is a passive characteristic which allows it to resist only active agents like forces and torques.

A moving body continues to move not because of its inertia but because there is no external force causing it to slow down, deviate from course, or accelerate. Newton's first law of motion explained the law of inertia that every object at rest or in uniform motion will remain in a straight line unless compelled to change its position by the action of an external force.

If no new force is applied to an object that moves at a constant speed, it will remain in its inertia of motion and the object will continue to move in the same direction with the same speed.

Thus, if no new force is applied then the motion of the object will maintain a constant speed over time. So, the correct option is (D).

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If a car takes 3500j of total energy to make 1200j of useful energy, how energy efficient is it

Answers

Answer: 34%

Explanation: eff = (Eout/Ein) *100(for % form)

1200/3500 * 100 = 34%

Who came up with the 3 Laws of Motion?

Answers

Answer:

Isaac Newton came up with the 3 Laws of Motion

Answer:

Isaac Newton came up with three laws of motion

A plant is sitting on a table.
What, if any, forces are acting on the plant? (If there are forces acting on the
plant, include what direction they are acting.)
1 - Gravity (down)
11- Static Friction
111 - Normal (support) Force (up)
IV - Air Resistance to the left)
V - Applied Force (to the right)

Answers

#1

Yes gravity is acting downwards

#2

No static friction as its at rest

#3

Normal reaction is applied upwards

#4

No air resistance

$5

No Applied force

what property of light is suggested by the formation of shadows​

Answers

Answer:

The reflection and rectilinear propagation of light helps in the formation of shadows and also tells light doesn't penetrate opaque materials.

2. Which of the diagrams shows the least gravitational force between the two objects?
a. I
b. II
c. III
d. IV

Answers

Question:-

Which of the diagrams shows the least gravitational force between the two objects?

Options :-

a. I

b. II

c. III

d. IV

Answer :- Option D . IV

Explanation :-

Gravitational force directly proportional to both the masses and in 4th and 3th case we have least mass of 2 on both side which is less than 10 in 2 cases Gravitational force is inversely proportional to square of the distance between the masses and in case 1st and 4th we have more distance than in 2nd and 3th . we know larger the distance lesser will be the force

From above observation we can conclude that gravitational force is least in 4th case because we have less mass on both side and we have more distance between the 2 masses that others with same mass .

The resultant of two vectors is of magnitude 3 units and 4 units is 1 units, what is the value of their dot product? ​

Answers

Answer:

A dot B = C     is the vector equation for this expression

A · B = A B cos θ

3 * 4 cos θ = 1       the value 1 is their dot product

cos θ = 1 / 12 = .083       θ = 85.2 deg

A rope is wrapped around a pulley many times. The pulley can be modeled as a solid disk of radius R and mass M, and a mass mA hangs vertically from the pulley. The mass is released from rest. show answer Incorrect Answer 25% Part (a) What is the magnitude of the tangential acceleration of the hanging mass?

Answers

The magnitude of the tangential acceleration of the hanging mass is 2mg/MR

Tangential acceleration of the hanging mass

The tangential acceleration of the hanging mass around the pulley is determined from the principle of conservation of angular momentum as shown below;

τ = Iα

Where;

I is the moment of inertiaα is the angular velocity

[tex]\alpha = \frac{\tau}{I} \\\\\alpha = \frac{mgR}{3/2MR^2} \\\\\alpha = \frac{2mgR}{3MR^2} \\\\\alpha = \frac{2mg}{3MR}[/tex]

Where;

m is the hanging massM is the mass of solid disk

The tangential acceleration is calculated as follows;

[tex]a = \alpha R\\\\a = \frac{2mg}{3MR} \times R\\\\a = \frac{2mg}{3M}[/tex]

Thus, the magnitude of the tangential acceleration of the hanging mass is 2mg/MR

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What is the relationship between latent heat and the hydrogen bonds which hold the molecules together?

Answers

Answer:

The molecules form strong hydrogen bonds, and water has a correspondingly high latent heat of vaporization. When no strong bonds are present, heating a liquid can easily free the molecules to form a gas, and the latent heat of vaporization is low.

Explanation:

A horizontal push of 197 N is applied to a 49.1 kg crate to slide it along a level floor. The crate is accelerating at 3.337 m/s2 (speeding up). What is the magnitude of the kinetic friction force between the crate and the floor

Answers

The magnitude of the kinetic friction force between the crate and the floor is 33.15 N.

Kinetic frictional force

The magnitude of kinetic frictional force is determined by applying Newton's second law of motion as shown below;

F - Ff = ma

where;

Ff is kinetic frictional forcea is acceleration of the crateF is the applied force

Subsitute the given parameters and solve for kinectic frictional force

197 - Ff = 49.1(3.337)

197 - Ff = 163.85

Ff = 33.15 N

Thus, the magnitude of the kinetic friction force between the crate and the floor is 33.15 N.

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Three identical 6.67-kg masses hang at rest from three identical springs, numbered as in the figure. Each spring has an unstretched length of 0.23 m and a spring constant of 8.13 kN/m. How long, L , is spring 2?

[Hint: Draw some FBDs and apply Newton's second law. Remember to account for both the spring's stretch and its unstretched length.]

Answers

The length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.

Extension of the spring 2

The extension of the spring 2 is determined from the net force acting on spring 2.

F(net) = Kx

Net force on spring 2 = sum of forces acting downwards - sum of forces acting upwards.

Net force on spring 2 = (force on 2 + force on 3) - (force on 1)

F(net) = (m₂ + m₃)g - (m₁)g

F(net) = (6.67 + 6.67)9.8  -  (6.67)9.8

F(net) = 130.732 - 65.366

F(net) = 65.366 N

x = F/k

x = (65.366)/(8130)

x = 0.00804 m

The length of spring 2 = x + 0.23 m

                                     = 0.00804 m + 0.23 m = 0.238 m

Thus, the length of the spring 2 due to arrangement of the equal masses is determined as 0.238 m.

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16. The energy absorbed in 10minutes by an electrical heater is 1.5 MJ. The supply voltage is 240 V. calculate: a) The current drawn b) The quantity of electricity in Coulombs taken in 5 minutes c) The energy absorbed in 100 hours.

Answers

Answer:

If by 1.5 MJ you mean 1.5E6 Joules then

W = P t    = power X time

W / t = P   power

P = 1.5E6 J / 600 sec = 2500 J / s

P = I V

a) I = 2500 J/s / (240 J/c) = 10.4 C / sec  = 10.4 amps

b) Q = I t = 10.4 C / sec * 300 sec = 3120 Coulombs

c)  E = P * t = 2500 J / sec * 100 hr * 3600 sec / hr = 9.0E8 Joules

A curve is banked at an angle of 29.1 degrees above the horizontal and the road surface has a coefficient of static friction of 0.4. What must the radius of curvature be for the safe minimum speed of 27.1 m/s?

Answers

Hi there!

We can begin by summing the forces acting on the car.

Along the axis of the incline, the forces of friction and gravity are working. The force of friction points towards the top of the ramp, while the force of gravity works towards the bottom.

We can use trigonometry to determine the force due to gravity along the ramp.

[tex]F_g = Mg sin\theta[/tex]

The force due to friction is equal to:
[tex]F_f = \mu N[/tex]

The normal force is the vertical component of the force due to gravity, so:
[tex]F_f = \mu Mgcos\theta[/tex]

Now, the combination of these two forces produces a component of the centripetal force. Drawing a diagram, we see that the true centripetal force is the HYPOTENUSE, while these forces sum up to its horizontal component along the ramp.

Therefore:
[tex]F_c sin\theta = Mgsin\theta - \mu Mgcos\theta[/tex]

The centripetal force is equivalent to:
[tex]F_c = \frac{Mv^2}{r}[/tex]

m = mass (kg)

v = velocity (m/s)
r = radius (m)

Rewrite:
[tex]\frac{Mv^2}{r}sin\theta = Mgsin\theta - \mu Mgcos\theta[/tex]

Cancel out 'M'.

[tex]\frac{v^2}{r}sin\theta = gsin\theta - \mu gcos\theta[/tex]

Rearrange to solve for 'r'.

[tex]r = \frac{v^2sin\theta}{gsin\theta - \mu gcos\theta}[/tex]

Plug in values and solve.
[tex]r = \frac{(27.1^2)sin(29.1)}{(9.8)sin(29.1) - 0.4(9.8)cos(29.1)} = \boxed{266.365 m}[/tex]

If something weighs 2891N on earth, what’s it’s mass?

Answers

Answer:

289.1kg

Explanation:

because W=M*G, and M=W/G, so 2891N/10m/s²=289.1kg

what is one type of compact star with a mass similar to the sun but a diameter similar to earth?

Answers

Explanation:

neutron star, any of a class of extremely dense, compact stars thought to be composed primarily of neutrons. Neutron stars are typically about 20 km (12 miles) in diameter. Their masses range between 1.18 and 1.97 times that of the Sun, but most are 1.35 times that of the Sun.

Which of the following is an example of the characteristic of excretion?

A) We shiver when we get cold.
B) Moss on the side of the tree is active even though it looks still.
C) Human kidneys produce urine.
D) A rabbit gets nutrients from a carrot.

Answers

Answer:

C

because urine is waste product

Which of the following is a renewable source of energy?
Tick one box.
A bio-fuel
B coal
C natural gas
D oil

Answers

Answer:

A. boi-gas

Explanation:

This may help u

Which of the following would NOT cause acceleration?
A. an object falling towards the earth
B. the wind catching the sail of a sailboat
C. a car traveling at a constant velocity
D. a pitcher throwing a baseball

Answers

I think the answer is C.


The figure (Figure 1) shows a pV diagram for 4.00×10−3 mole of ideal H2 gas. The temperature of the gas does not change during segment bc. What volume does this gas occupy at point c?

Answers

The volume that the gas will occupy based on the temperature given will be 0.80 liters.

How to calculate the volume?

From the information, it was stated that the figure shows a pV diagram for 4.00×10−3 mole of ideal H2 gas and that the temperature of the gas does not change during segment bc.

Therefore, the volume will be:

= (0.20) × (2.0/0.50)

= 0.20 × 4

= 0.80

In conclusion, the volume is 0.80 liters.

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Need help with this question. Thirty points.

Answers

[tex]1)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12 mv^2 \\\\\implies m = \dfrac{2E_k}{v^2} = \dfrac{2\times 4500}{30^2}=10~ kg\\ \\2)\\\\\text{Kinetic energy,}\\\\E_k = \dfrac 12mv^2 \\\\\implies v^2 = \dfrac{2E_k}m\\\\\implies v = \sqrt{\dfrac{2E_k}{m}}=\sqrt{\dfrac{2 \times 320}{\dfrac{20}{9.8}}}= 17.709 ~ ms^{-1}\\\\3)\\\\\text{Kinetic energy,}\\\\E_k=\dfrac 12 mv^2=\dfrac 12 \times 50 \times 10^2=2500 ~J\\\\\\[/tex]

[tex]4)\\\\\text{Potential energy,}\\\\E_p =mgh = 5\times 9.8\times 1.5 = 73.5 ~J[/tex]

What must be the charge of a particle having E = 81 N/C at 49 mm from the said particle? Express in Coulombs. Use k = 9.0 x 109 kg⋅m3⋅s−2⋅C−2​

Answers

[tex]\text{Given that,}\\\\\text{Electric field strength,}~ E = 81 ~NC^{-1} \\ \\ \text{Distance,}~ d= 49mm = 49 \times 10^{-3} ~m\\ \\\text{Coulomb's constant,}~ k = 9\times 10^9 ~Nm^2 C^{-2}\\\\ \\E= k\dfrac{q}{d^2} \\\\\implies q=\dfrac{Ed^2}{k} = \dfrac{81 \times \left(49 \times 10^{-3}\right)^2}{9\times 10^9} = 2.1609\times 10^{-11} ~C\\\\\\\text{The charge of the particle is}~2.1609\times 10^{-11} ~C[/tex]

define capacitance of a capacitor and state its SIbunit​

Answers

Answer: what I know that the unit is farad

Explanation:

The jet engine of an airplane expels hot gas.
A. The airplane is propelled in the same direction as the hot gas.
B. The airplane is propelled in the opposite direction as the hot gas.
C. The airplane is propelled against the outside air.

Answers

Answer:

B. The airplane is propelled in the opposite direction as the hot gas.

Have an amazing day!!

Please rate and mark brainliest!!

.
A
saloon car starting from rest will accelerates
to velocity of 48 km/h in 10 seconds. calculate
the
aceleration-
What’s the answer ?

Answers

Answer:

47

Explanation:

48km:1hr (10sec×60min=600hr)

¥ :600hr

1hr÷¥=1. 48×600÷1=2800

2800÷60=47

47 will be the acceleration

[tex]\text{Initial velocity,}~ u = 0 ~ ms^{-1}\\\\\text{Final velocity,}~ v = 48~kmh^{-1} = \dfrac{48\times 1000}{3600} ms^{-1} = 13.33 ms^{-1}\\ \\\text{Time,}~ t = 10~ sec\\\\\text{Acceleration,}~ a = \dfrac{v-u}{t} = \dfrac{13.33-0}{10} = \dfrac{13.33}{10} = 1.33 ~ ms^{-2}\\\\\text{Hence the acceleration of the car is}~ 1.33 ~ms^{-2}.[/tex]

Which of the following examples BEST describes the life characteristic of respiration?

A) A cheetah races across the plain.
B) Starfish cells divide and multiply as it gets larger.
C) Humans eliminate some wastes through urine and feces.
D) Humans breathe in oxygen and release carbon dioxide.

Answers

Answer:

D if I'm incorrect then sorry.

Explanation:

The answer is C. Sorry if I’m wrong, if I’m right please give me brainliest.

A capacitor of cylindrical shape as shown in the red outline, few cm long carries a uniformly distributed charge of 7.2 uC per meter of length. By constructing a suitable Gaussian surface around the wire, Find the magnitude and direction of the electric field at points

a)5.5m

b)2.5m

perpendicular from the center of the wire.​

Answers

(a) The magnitude of the electric field at point 5.5m is 2.35 x 10⁴ N/C.

(b) The magnitude of the electric field at point 2.5m is 5.18 x 10⁴ N/C.

Electric field at a point on the Gaussian surface

The magnitude of the electric field at a point on the cylindrical Gaussian surface is calculated as follows;

E = λ/2πε₀r

where;

λ is linear charge densityε₀ is permitivity of free spacer is the position of the chargeAt a distance of 5.5 m

[tex]E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 5.5} \\\\E = 2.35 \times 10^4 \ N/C[/tex]

At a distance of 2.5 m

[tex]E = \frac{\lambda}{2\pi \varepsilon _0 r} \\\\E = \frac{7.2 \times 10^{-6}}{2\pi \times 8.85 \times 10^{-12} \times 2.5} \\\\E = 5.18 \times 10^4 \ N/C[/tex]

Thus, the magnitude of the electric field at points of 5.5m is 2.35 x 10⁴ N/C, and the magnitude of the electric field at points of 2.5m is 5.18 x 10⁴ N/C.

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Which process describes the warm ocean that transfers heat to the air above it?
O conduction
O convection
O reflection
O radiation

Answers

Answer:

convection is the answer

The process that describes the warm ocean that transfers heat to the air above it is known as Convection. Thus, the correct option for this question is B.

What are some characteristics of heat?

Some characteristics of heat are as follows:

It has no mass, shape, color, odor, volume, and weight.It is one of the invisible forms of energy.It stimulates the presence of warmth.It gets remarkably transferred from one body to another.This form of energy has the capacity to flow in each and every direction.

The process of convection transfers heat with the help of the migration of a fluid (liquid or gas) between areas of different temperatures. It is an approach that signifies the transfer of heat between two bodies by involving currents of moving gas or fluid.

Therefore, convection is the process that describes the warm ocean that transfers heat to the air above it. Thus, the correct option for this question is B.

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Which statement correctly describes the relationship between frequency and wavelength?
A :As the frequency of a wave increases, the longer its wavelength is

B: As the frequency of a wave increases, the shorter its wavelength is.

C: As the frequency of a wave increases, its wavelength remains the same.

Answers

Answer:

It is B

Explanation:

Option B talks about how the frequency of the wave increases the shorter it's wavelengths

Answer:

It's b

Explanation:

a=5i+4j-6k ,b=-2i+2j+3k ,c=4i+3j+2k. find the vector perpendicular to a and c​

Answers

Answer:

Explanation:

You can use the cross product. Let the vector that perpendicular to a and c is [tex]\vec{d}[/tex], so:

[tex]\vec{d}=\vec{a}\times\vec{c}=\left|\left[\begin{array}{ccc}\hat{i}&\hat{j}&\hat{k}\\5&4&-6\\4&3&2\end{array}\right] \right|=(8+18)\hat{i}-\hat{j}(10+24)+\hat{k}(15-16)=26\hat{i}-34\hat{j}-\hat{k}[/tex]

To check that c is perpendicular with a and b, do the dot product between c and a and also c and b and if the result is zero, you're true.

[tex]\vec{d}.\vec{a}=(26*5)-(34*4)+(6)=0[/tex]  (c perpendicular to a)

[tex]\vec{d}.\vec{c}=(4*26)-(34*3)-(2*1)=0[/tex] (d perpendicular to c)

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