A linear equation can have solutions in three forms: one solution, no solution, and infinite solutions.
ONE SOLUTION EQUATION:
These are equations that will give only one solution when solved, such that the variable is equal to a single answer.
If the graph is drawn, the linear equations all cross or intersect at one point in space.
An example of a one-solution equation is shown below:
[tex]3x+5=2x-7[/tex]Solving this equation, we have:
[tex]\begin{gathered} 3x-2x=-7-5 \\ x=-12 \end{gathered}[/tex]We can therefore see that it has only one solution, one value for x which is -12.
NO SOLUTION EQUATION:
In this case, the coefficients of the variables on both sides of the equation are the same. Simplifying the equation will give an expression that is not true.
Graphically, the system is inconsistent and the linear equations do not all cross or intersect.
Consider the equation below:
[tex]2x+5=2x-7[/tex]If we attempt to solve the equation by subtracting 2x from both sides, we have the solution below:
[tex]\begin{gathered} 2x+5-2x=2x-7-2x \\ 5=-7 \end{gathered}[/tex]We can see that what we have left is not a valid statement, since 5 is not equal to -7:
[tex]5\neq-7[/tex]Thus, we can say that the equation has no solutions.
INFINITE SOLUTION EQUATION:
This follows the same format as the no solution equations. However, the final statement gotten from the simplification of the equation will give us a true statement instead.
Graphically, the linear equations are the same line in space and some variables are unconstrained.
Consider the equation below:
[tex]2x+5=2x+5[/tex]If we subtract 2x from both sides, we have:
[tex]\begin{gathered} 2x+5-2x=2x+5-2x \\ 5=5 \end{gathered}[/tex]Since the statement left is true, as 5 is equal to 5, then the equation has an infinite number of solutions.
the sugar sweet company is going to transport its sugar to market. it will cost 7500 to rent trucks,and it will cost an additional 225 for each ton of sugar transportlet C represent the total cost (in dollars) and let s represent the amount of sugar ( in tons ) transported. write an equation relating C to S. then use this equation to find the total cost to transport 18 tons of suger.
Given that a sugar sweet company costs to transport its sugar, 7500 to rent truck and additional 225 for each ton.
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pls help i Dont get it
Answer:
what do you need
Step-by-step explanation:
Scatter PlotWhich statement best describes the association betweenvariable X and variable Y?.moderate negative association. Perfect negative association. Moderate positive association. Perfect positive association
It's moderate negative association
The table shows claims and their
probabilities for an insurance
company.
Amount of claim
(to the nearest $20,000)
$0
$20,000
$40,000
$60,000
$80,000
$100,000
Probability
0.70
0.16
0.09
0.03
0.01
0.01
Answer:
Step-by-step explanation:
This is an equation! Solutions: x=1.
Graphical form: Equation 3%2Ax-x%2B2=4 was fully solved.
Text form: 3*x-x+2=4 simplifies to 0=0
Cartoon (animation) form: simplify_cartoon%28+3%2Ax-x%2B2=4+%29
For tutors: simplify_cartoon( 3*x-x+2=4 )
If you have a website, here's a link to this solution.
By what factor does the population grow every 2 years? Use rhis information to fill out the table.By what factor does the population grow every year? explain how you know, and use this information to complete the table.
From the table, we see that:
• Year 0 has a population of 10,
,• Year 2 has a population of 20.
So after two years, the population of fish is doubled.
1) By year 4, we will have double the population of year 2, so the population will be 2*20 = 40.
2) To function that describes the growth of the population is:
[tex]P(t)=P_0\cdot r^t._{}[/tex]Where P_0 is the initial population and r is the growth factor.
We know that after two years, the population of fish is doubled:
[tex]P(t+2)=2\cdot P(t)\text{.}[/tex]Using the formula above evaluated in t + 2, we have:
[tex]P(t+2)=P_0\cdot r^{t+2}=(P_0\cdot r^t)\cdot r^2=P(t)\cdot r^2[/tex]Equalling the last two equations, we have:
[tex]P(t+2)=2\cdot P(t)=P(t)\cdot r^2\text{.}[/tex]Solving for r the last equation, we have:
[tex]\begin{gathered} 2=r^2, \\ r=\sqrt[]{2}\text{.} \end{gathered}[/tex]So the growth factor is r = √2.
Answer:
1. 40
2. √2
which number below comes first when the numbers are listed from least to greatest? Explain. Then write the numbers in order from least to greatest 1/6, -3, the square root of 5, -9 / 2, 4.6 which number comes first when the numbers are listed from least to greatest?A. 1/6B.-3C.-9/2D.Square root of 5E. 4.6
Answer:
The number that comes first when the numbers are listed from least to greatest is;
[tex]\frac{-9}{2}[/tex]And, arranging the numbers from least to greatest will give;
[tex]\frac{-9}{2},-3,\frac{1}{6},\sqrt{5},4.6[/tex]Explanation:
We want to arrange the number given below from least to greatest;
[tex]\frac{1}{6},-3,\frac{-9}{2},\sqrt{5},4.6[/tex]From the list of numbers, let us simplify each of them to their approximate decimal.
[tex]\begin{gathered} \frac{1}{6}=0.1667 \\ -3 \\ \frac{-9}{2}=-4.5 \\ \sqrt{5}=2.236 \\ 4.6 \end{gathered}[/tex]From the given number, the highest negative number will be the least number.
Because the higher a negative number the lower it becomes.
The highest negative is -4.5 followed by -3.
So, arranging from the least to the greatest we have;
[tex]-4.5,-3,0.1667,2.236,4.6[/tex]Rewriting it in its initial form we have;
[tex]\frac{-9}{2},-3,\frac{1}{6},\sqrt{5},4.6[/tex]Therefore, The number that comes first when the numbers are listed from least to greatest is;
[tex]\frac{-9}{2}[/tex]And, arranging the numbers from least to greatest will give;
[tex]\frac{-9}{2},-3,\frac{1}{6},\sqrt{5},4.6[/tex]For the situation select expression or equation that is not equivalent to the rest.A $79 hoodie is on sale for 25% off.
Given:
$79 hoodie is on sale for 25% off
We can solve or express this in many ways;
If it is 25% off, then the price is;
(100% - 25%) x 79
= (75%) x 79
= (0.75) (79)
OR
The price is;
79 - 25%(79)
= 79 - (0.25)(79)
OR
0.75 x 79 is the same as;
(1 - 0.25)(79)
Therefore, the expression or equation that is NOT equivalent to the rest is
25/100 (79)
Two people out of a group of 75 will win tickets to an upcoming concert. How many different groups of two are possible?
To calculate the combinations of groups of 2, since the order doesn't matter, we can use combination. In this case we have a total of 75 to choose from and will choose 2, so this is "75 choose 2".
The equation to use is (n choose k):
[tex]C(n,k)=\frac{n!}{(n-k)!k!}[/tex]In this case, we have n = 75 and k = 2, so:
[tex]C(75,2)=\frac{75!}{73!2!}[/tex]For the property of factorials, 75! / 73! = 75*74, because the terms less or equal 73 cancel out. so:
[tex]C(75,2)=\frac{75\cdot74}{2!}=\frac{75\cdot74}{2}=75\cdot\frac{74}{2}=75\cdot37=2775[/tex]So, there are 2775 different groups of 2 in this case.
Another way of doing this calculation is by thinking of choosing one at a time.
At first, we can choose from 75 possible people, so we start at 75.
When we choose the second one, we already picked the first, so there are only 74 people left. So we get:
[tex]75\cdot74[/tex]This are the two first people, but, in this way we are considering too many groups, since here we considere the order matter, to fix this we divide by k!, where k is the number of picks, which is 2 in this case (so, permutation of 2). So:
[tex]\frac{75}{2}\frac{74}{1}=\frac{75\cdot74}{2}=2775[/tex]find the sum of all two-digit natural numbers which are not divisible by 3。Want formulas and algorithms
The sum of all two-digit numbers which are not divisible by 3 is 2240.
What is Arithmetic progression?
An arithmetic sequence or progression is defined as a sequence of numbers in which for every pair of consecutive terms, the second number is obtained by adding a fixed number to the first one.
The sum of two-digit number in AP is Sn = n/2[2a+(n-1)d]
First, sum of two digit number 10, 11.....99 is
n = 90, a = 10 an= 99
Sn = n/2[2a+(n-1)d]
Sn = 90/2[2(10)+(90-1)1]
Sn = 45[20+89]
Sn= 4905
Now, the sum of two digit number divisible by 3 =
12, 15,...99
a = 12, n = 30, d = 3
Sn = n/2[2a+(n-1)d]
Sn=30/2[2(12)+(30-1)3]
Sn= 1665
Hence, sum of two digit number not divisible by 3 are 4905-1665
=2240
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What is the value of x in the equation7 (4x + 1) – 32 5.7 · 13?X=
Given
[tex]\begin{gathered} 7(4x+1)-3x=5x-13 \\ 28x+7-3x=5x-13 \\ 25x-5x=-13-7 \\ 20x=-20 \\ x=-1 \end{gathered}[/tex]Solve for the hypotenuse and then determine the ratios below (show all work)
hypotenuse=29
[tex]\sin x=\frac{20}{29}[/tex][tex]\cos y=\frac{20}{29}[/tex]
Explanation
Step 1
a) hypotenuse
to find the hypotenuse we can use the Pythagorean theorem ,it statse that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle)
so
[tex]\begin{gathered} 21^2+20^2\text{= hypotenuse}^2 \\ 441+400=\text{ hypotenuse}^2 \\ 841=\text{hypotenuse}^2 \\ taking\text{ the square root in both sides} \\ \sqrt{841}=\sqrt{(hypotenuse)^2} \\ 29=hypotenuse \end{gathered}[/tex]so
hypotenuse=29
Step 2
now, sin x
the sin of an angle is the ratio of the opposite side ( the one in front of the angel) to the hypotenuse
[tex]\sin\theta=\frac{opposite\text{ side}}{hypotenuse}[/tex]hence, replace
[tex]\sin x=\frac{20}{29}[/tex]Step 3
finally, cos of y
the cos of an angle is the ratio of the adjancent side( the side the makes the angle) to the hypotenuse
[tex]cos\theta=\frac{adjacent\text{ side}}{hypotenuse}[/tex]so,replace
[tex]\cos y=\frac{20}{29}[/tex]I hope this helps you
which of the following are like terms3y^5, 2x^53y^5, 2y^56y^2, 2 z3y^4, 4x^3
In this case the answer is very simple.
3y^5, 2y^5 are like terms.
Because the variables and their exponents are the same.
110,169 is larger than 110,72
110,169 is larger than 110,72
This is false as the first decimal of 110.169 is 1 and the first decimal of 100,72 is 7.
110,169 is larger than 110,72
This is false as the first decimal of 110.169 is 1 and the first decimal of 100,72 is 7.
I inserted a picture of the questionPlease state whether it’s A B C or DCheck all that apply
Given the initial function,
[tex]f(x)=2^x[/tex]In general, a vertical stretch/compression is expressed by
[tex]f(x)\to k\cdot f(x)[/tex]If k>1, the function gets a vertical stretch; on the other hand, if 0Therefore, in our case,
[tex]g_1(x)=\frac{1}{3}f(x)\to\text{vertical compression by a factor of 1/3}[/tex]A vertical shift is given by the following formula
[tex]\begin{gathered} f(x)+k \\ k>0\to\text{shifted up} \\ k<0\to\text{shifted down} \end{gathered}[/tex]In our case,
[tex]g(x)=g_1(x)-7\to\text{vertical shift down by 7 units.}[/tex]Therefore, the answers are B and D.
Reflect triangle YWZ across line YW. Which of these is a valid reason why the image of Z will coincide with X?
Triangle WYZ
line YW
then YW is a bisector of, ZX
cost to rent a paddle boat at the city park includes a intentral fee of $7.00, plus $3.50 per hour. Which equation models the relationship between the total cost, y, and the number of hours, X, that the paddle boat is rentedA. y = 3.5x + 7. B. y = 7x + 3.5C. y = x/7 + 3.5. D. y = x/3.5 + 7
The total cost is represented as y, and the number of hours as x.
The intentral fee is $7.00.
Since the cost is $3.50 per hour, the total cost is
y=3.5x+7.
Hence, option A is correct.
I’ve been working on these similar questions but coming to this question. I found myself being stuck.
Solution:
If the variation in pressure is P pounds per square inch, then the Loudness L in decibels is;
[tex]L=20\log _{10}(121.3P)[/tex]When L=115 decibels;
[tex]\begin{gathered} 115=20\log _{10}(121.3P) \\ \text{Divide both sides by 20;} \\ \frac{115}{20}=\frac{20\log_{10}(121.3P)}{20} \\ \log _{10}(121.3P)=5.75 \end{gathered}[/tex]But from the logarithmic law, we have;
[tex]\log _ba=c\leftrightarrow a=b^c[/tex]Thus,
[tex]\begin{gathered} \log _{10}(121.3P)=5.75 \\ 121.3P=10^{5.75} \\ 121.3P=562341.33 \end{gathered}[/tex][tex]\begin{gathered} \text{Divide both sides by 121.3;} \\ \frac{121.3P}{121.3}=\frac{562341.33}{121.3} \\ P\cong4635.95 \end{gathered}[/tex]FINAL ANSWER:
[tex]4636.0\text{ pounds per square inch.}[/tex]What is the procedure for 31/4-17/8= I'm getting 25/8
Evaluate the value of the expression:
[tex]3\frac{1}{4}-1\frac{7}{8}[/tex]Step 1: The mixed fraction will be converted to improper fraction
[tex]\begin{gathered} 3\frac{1}{4}-1\frac{7}{8} \\ =\frac{3\times4+1}{4}-\frac{1\times8+7}{8} \\ =\frac{12+1}{4}-\frac{8+7}{8} \\ =\frac{13}{4}-\frac{15}{8} \end{gathered}[/tex]Step 2: The denominator of 8 will be used as the L.C.M, since it's the greatest of the two
[tex]\begin{gathered} \frac{13}{4}-\frac{15}{8} \\ =\frac{26-15}{8} \\ =\frac{11}{8} \\ =1\frac{3}{8} \end{gathered}[/tex]Hence the correct answer = 1 3/8
[tex]1\frac{3}{8}[/tex]An item is regularly priced at $85. Yolanda bought it at a discount of 65% off the regular price?
what is 3 8/9 + 8 1/2
Find the slope of the line that passes through (8, 7) and (6, 2).
[tex]m = \frac{y2 - y1}{x2 - x1} \\ m = \frac{2 - 7}{6 - 8} \\ m = \frac{ - 5}{ - 2} \\ m = \frac{5}{2} [/tex]
ATTACHED IS THE SOLUTION WITH THE FORMULA TO CALCULATE THE SLOPE BETWEEN POINTS.
f (x+2) - 3o vertical shiftvertical stretchhorizontal reflectionhorizontal shiftvertical compressionhorizontal stretchhorizontal compressionvertical reflection
ANSWER:
[tex]\begin{gathered} (5x+3)\cdot(x+4) \\ x=-\frac{3}{5}\text{ and }x=-4 \end{gathered}[/tex]STEP-BY-STEP EXPLANATION:
We have the following function:
[tex]5x^2+23x+12[/tex]we factor and calculate the roots like this:
[tex]\begin{gathered} (5x+3)\cdot(x+4) \\ (5x+3)=0\rightarrow x=-\frac{3}{5} \\ (x+4)=0\rightarrow x=-4 \end{gathered}[/tex]Therefore the factored form would be
[tex](5x+3)\cdot(x+4)[/tex]And the roots of the functions are - 3/5 and -4
Use the graphs below to help you answer the question.
Which of the following is the best approximation to a solution of the equation e* = 4x+1?
A. 10
B. 2
C. 3
D. 1
Answer:
I would say the answer is D.
Step-by-step explanation:
If you solve for x you get 1/4.
In decimal form that is 0.4
log 2x = 3 what is x
The value of x is 10.04 using log properties.
What is the log in math?The power to which a number must be increased in order to obtain another number is known as a logarithm. The exponential function is thought of as the inverse of the logarithmic function because of their close relationship. The logarithmic function logₐN = x is created from the exponential function [tex]a^{x}[/tex] = N. For instance, since ten raised to the power of two equals 100, the base ten logarithms of 100 is 2: log 100 = 2.
logₐ xy = logₐ x + logₐ y (product property)
logₐ x/y = logₐ x - logₐ y (quotient property)
logₐ [tex]x^{y}[/tex] = ylogₐ x (power property)
log2x = 3
2x = e³
x = e³/2
= 10.04
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If tan=21/20,0
a. sin a/2
b. cos a/2
c. tan a/2
Using trigonometry we can conclude that the value is sin a/2=7/58, cos a/2= -3/√58, tan a/2= -7/3.
What is Trigonometry?A branch of mathematics called trigonometry looks at how triangle side lengths and angles relate to one another. Applications of geometry to astronomical research led to the development of the field in Hellenistic civilization during the third century BC.We are aware:
x=tan(a/2)And,
tan(a)=2tan(a/2)/1-tan²(a/2)=21/20= 2x/1x2⇒21−21x²=40x⇒21x²+40x−21=0⇒21x²+49x−9x−21=0⇒7x(3x+7)−3(3x+7)=0⇒(3x+7)(7x−3)=0Thus, x=7/3 or x=3/7
It is now given:
180<a<270⇒ 90<a/2<135The a/2 second quadrant.
As a result:
x = tan(a/2)negativeTherefore,
x = tan(a/2)= -7/3sin(a/2) => +veThis means that:
sin(a/2) = 1/cos(a/2) = 1/(1+cot²(a/2))= 1/(1+1/tan(a/2))=1/√(1+9/49)=7/√58The formula is now:
cos(a/2)=sin(a/2)/tan(a/2)=7/√58/ -7/3cos(a/2) = -3/√58Therefore, using trigonometry we can conclude that the value is sin a/2=7/58, cos a/2= -3/√58, tan a/2= -7/3.
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6. Find the distance from A to B for the hexagonal nut shown below: А 1.50 in BYo I've asked tutors and they have been unable to answer, after all it's only given one side and I need some help.
Let
x ------> the length side of the regular polygon
we have a regular hexagon
that means
the interior angle of this polygon is
180(6-2)/6=120 degrees
A regular hexagon can be divided into 6 congruent equilateral triangles
see the attached figure to better understand the problem
in the right triangle of the figure
we have that
sin(60)=0.75/x
solve for x
x=0.75/sin(60)
Remember that
[tex]\sin (60^o)=\frac{\sqrt[]{3}}{2}[/tex]substitute
[tex]\begin{gathered} x=0.75\colon\frac{\sqrt[]{3}}{2} \\ \\ x=\frac{1.50}{\sqrt[]{3}}\cdot\frac{\sqrt[]{3}}{\sqrt[]{3}}=\frac{1.50\sqrt[]{3}}{3}=\frac{\sqrt[]{3}}{2} \end{gathered}[/tex]Part 2
Find the distance AB
Applying the Pythagorean Theorem
AB^2=1.5^2+x^2
substitute the value of x
AB^2=2.25+(3/4)
AB^2=3
[tex]AB=\sqrt[]{3}\text{ in}[/tex]the distance AB is the square root of 3 inchesI need help the right side box are the answer choices
Statement: JKLM is a parallelogram
Reason - Give
Statement:
[tex]JK\parallel LM,\text{ }KL\parallel MJ[/tex]Reasons:
Definition of a parallelogram.
Statement:
[tex]\angle1\cong\angle2,\angle3\cong\angle4[/tex]Reasons:
Alternate interior angle theorem.
Statement:
[tex]Jl\cong Jl[/tex]Reasons:
Reflexive Propert
Statement:
[tex]\Delta JKL\cong\Delta LMJ[/tex]Reasons:
ASA
Statement:
[tex]JK=LM,KL=MJ[/tex]Reasons:
CPCTC
Quinton will flip a coin and roll a die.What is the probability that he will flip "tails" and roll a "2
Answer:
there is a 50 percent chance he will land tails, and about a 33 percent chance he will rol a 2
Step-by-step explanation:
Find The measure of the indicated to the nearest angle
The given figure is a right triangle, then we can apply the sine function to find the missing angle, so:
[tex]\sin\theta=\frac{opposite}{hypotenuse}[/tex]The opposite side to the angle measures 17, and the hypotenuse measures 19.
By replacing these values, we can find the angle:
[tex]\begin{gathered} \sin\theta=\frac{17}{19} \\ \\ \theta=\sin^{-1}(\frac{17}{19}) \\ \\ \theta=63.47 \\ \theta\approx64\degree \end{gathered}[/tex]The answer is 64°.
Find the slope of the tangent line when x=3 using the limit definition f(x) = X^2 - 5
SOLUTION
From the limit definition, we have that
[tex]f^{\prime}(x)=\lim _{h\to0}\frac{f(x+h)-f(x)}{h}[/tex]Now applying we have
[tex]\begin{gathered} f\mleft(x\mright)=x^2-5 \\ f^{\prime}(x)=\lim _{h\to0}\frac{f(x+h)-f(x)}{h} \\ =\lim _{h\to0}\frac{((x+h)^2-5)-(x^2-5)}{h} \\ =\lim _{h\to0}\frac{x^2+2xh+h^2^{}-5-(x^2-5)}{h} \\ =\lim _{h\to0}\frac{x^2+2xh+h^2-5-x^2+5}{h} \\ =\lim _{h\to0}\frac{x^2-x^2+2xh+h^2-5+5}{h} \\ =\lim _{h\to0}\frac{2xh+h^2}{h} \end{gathered}[/tex]factorizing for h, we have
[tex]\begin{gathered} =\lim _{h\to0}\frac{h(2x+h)^{}}{h} \\ \text{cancelling h} \\ =\lim _{h\to0}2x+h \\ =2x \end{gathered}[/tex]So, when x = 3, we have
[tex]\begin{gathered} =2x \\ =2\times3 \\ =6 \end{gathered}[/tex]Hence, the answer is 6