Answers
Given:
Perimeter = 40 feet,
The measure of the four sides is 11 feet, g, 11 feet, and g.
We know that the perimeter = the sum of the four sides.
[tex]\text{perimeter =11+g+11+g}[/tex]Replace perimeter =40, we get
[tex]\text{40=11+g+11+g}[/tex]Adding 11 and 11, we get
[tex]\text{40=11+11+g+g}[/tex][tex]\text{40=22+g+g}[/tex]Related Questions
What is the largestNumber of these wooden Els that can be packed in a box that is 2 cm x 4 cm x 6 cm
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The largest number of the wooden Els with it's total surface area that can be packed in the 2cm×4cm×6cm box is 2 wooden Els.
Total Surface Area of Solid ShapesIn finding the total surface area of a solid cuboid, add the areas of all 6 faces. We can also label the length (l), width (w), and height (h) and use the formula, SA=2(lw+lh+hw), to find the surface area.
For the box, l=2cm, w=4cm and h=6cm
total surface area of box=2(2×6+2×4+6×4) cm square units
total surface area of box=2(44) cm square units
total surface area of box=88cm square units
For the top cuboid of the wooden El, l=3cm, w=1cm and h=2cm
total surface area of top El cuboid=22cm square units
For the bottom cuboid of the wooden El, l=1cm, w=1cm and h=2cm
total surface area of bottom El cuboid=10cm square units
total surface area of the El=32cm square units
(88cm²/32cm²)=2.75
This implies that only two(2) whole Els with total surface area of 32cm² can be packed in the box.
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Write an absolute value inequality that represents all real numbers more than 4 units away from x
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We have to write as inequality the following
"All real numbers more than 4 units away from x""4 units away from x" means four units plus x. So, the expression would be
[tex]|x|>4[/tex]Where x represents real numbers.
This expression is referring to all real numbers more than 4 units and less than -4 units because according to the property of absolute values for inequalities, we have
[tex]|x|>x-4\rightarrow x>x-4,or,x<-(x-4)[/tex]This is represented in the following graph to see it better
For x=1
[tex]\begin{gathered} |1|>x-4\rightarrow1>1-4,or,1<-(1-4) \\ 1>-3 \\ 1<3 \end{gathered}[/tex]Both results are true.
To find this absolute value inequality we used the following property
[tex]|x|>a\rightarrow a>b,or,a<-b[/tex]Where the absolute value inequality has "more than" we rewrite the expression in two inequalities.
Question 8 of 10According to this diagram, what is tan 62°?
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In this problem, we want to determine tangent of 62 degrees.
Recall the identity of tangent:
[tex]\tan\theta=\frac{\text{ opposite side}}{\text{ adjacent side}}[/tex]We are given the triangle:
Since we are referencing 62 degrees, the arrow pointing away from the 62 degrees is headed toward the opposite side. Therefore, the opposite side is 15, and the adjacent side is 8.
[tex]\tan62=\frac{15}{8}[/tex]Tangent of 62 degrees is 15/8.
Make a tree diagram, Please complete number 18.Please be quick, I am in a hurry.
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Explanation:
The question wants us to list out all the possible outcomes in question 18
From the question
We have a spinner that has 5 possible outcomes
[tex]\mleft\lbrace\text{Red, Orange, Green, Purple, Yellow}\mright\rbrace[/tex]The outcomes of flipping a coin are
[tex]\begin{gathered} \mleft\lbrace\text{Head, Tail}\mright\rbrace\text{ } \\ \text{which can be written as} \\ \mleft\lbrace H,T\mright\rbrace \end{gathered}[/tex]Thus, to get the possible outcomes, we will have
Fido ran away from home at a speed of 5 mi/hour. He ran in a straight line. After a while he decided to go back home for dinner so turned around and walked home along the same path he had run on. He walked at 2 mi/hour. The walk home took one hour longer than the run did. How long did Fido run?
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Distance = Speed x time
For the run; speed = 5 mi/hr, time = t
For the walk: speed= 2 mi/hr, time = t + 1
Since he walked on a straight line and he returned following the same path
Distance travelled for the run = distance travelled for the walk
Distance for run: 5 x t = 5t
Distance for walk : 2 (t + 1) =2t + 2
Thus , 5t = 2t + 2
5t - 2t = 2
3t = 2
t = 2/3 hour = 2/3 x 60 minutes = 2x 20 = 40 minutes
He took him 40 minutes to run
Speeds of Cars (in miles per hour)Intersection 1Intersection 2十十十十18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34• Part 1: Find the range of intersection 1 as a way to measure the variability of the data, showing your work. Remember, range isfound by taking the largest value minus the smallest value. (2 points)• Part 2: Find the range of intersection 2 as a way to measure the variability of the data, showing your work. Remember, range isfound by taking the largest value minus the smallest value. (2 points)
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PART 1)
Range of intersection 1
(Max value - Min value )=
Largest value = 31 , Lowest value = 26
Then range1 is 31 - 26 = 5 miles /hour
Now PART 2:)
Maximum value= 27
Minimum value = 22
Then range2 is 27-22 = 5 miles/hour
Covert the decimal into a fraction and reduce to the lowest terms
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Solution
- The number given to us can be rewritten as follows:
[tex]92.698=92+0.698[/tex]- Thus, we already know what is in the whole number bracket; 92.
- The fraction representation of 0.698 is what will occupy the fraction brackets.
- 0.698 can be rewritten as:
[tex]0.698=\frac{698}{1000}[/tex]- Let us simplify this fraction as follows:
[tex]\begin{gathered} \frac{698}{1000}=\frac{349\times2}{500\times2} \\ \\ 2\text{ crosses out.} \\ \\ =\frac{349}{500} \end{gathered}[/tex]- Thus, the answer is
What is special about a unit circle? How does this help us when finding the six trigonometric ratios?
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Answer:
A circle is a closed geometric figure without any sides or angles. The unit circle has all the properties of a circle, and its equation is also derived from the equation of a circle. Further, a unit circle is useful to derive the standard angle values of all the trigonometric ratios.
Step-by-step explanation:
8 O 6 4. N Which function is graphed? 2. 4 6 8 -8 -6 -4 -2 0 -2 -6 O A. Y- (x² + 4, x=2 1-x+4,452 (x² + 4, x2 OD. V- x + 4, x32 1-x+4,4
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The given curve is parabola and its last point is on the x axis at x = 2
So, the equation of curve is :
[tex]x^2+4,x<2[/tex]In the equation of line,
The line start from x = 2 so, x ≥ 2
So, Equation of line is : -x + 4, x ≥ 2
Answer : B)
[tex]y=\begin{cases}x^2+4,x<2 \\ \square \\ -x+4,\text{ x}\ge2\end{cases}[/tex]Given the following information, determine which lines, if any, are parallel. State the converse that justifies your answer.
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1. angle j and k.
Due to the Converse of Corresponding Angles Postulate, j || k.
2. Angles 2 and 5 are the alternating inner angles of the lines j and k. Given that angle 2 = angle 5,
The Converse of Alternate Interior Angles Theorem states that j || k.
J || K converse alternative interior angles.
what are parallel angles?similarly
3. angle 3 = angle 10 The exterior angles of the lines l and m, respectively, are angle 3 and angle 10. Since the Converse of Alternate Exterior Angles Theorem states that angle 3= angle 10, l || m.
converse alternative exterior angles l || m.
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Which value of x proves that the two triangles above are similar? 42.7 ft 26.7 ft 10 ft 25.6 ft
Answers
Explanation
Step 1
we have two triangles
ACE and BCD
if the triangles are similar, then the ratio of the sides must be the same:
[tex]\begin{gathered} \frac{\text{red line}}{purple\text{ line}}=\frac{blue\text{ line}}{\text{green line}} \\ \text{replacing} \\ \frac{16+x}{32}=\frac{x}{20} \end{gathered}[/tex]Step 2
solve for x
[tex]\begin{gathered} \frac{16+x}{32}=\frac{x}{20} \\ \text{cross multiply} \\ 20(16+x)=32\cdot x \\ 320+20x=32x \\ \text{subtrac 20x in both sides} \\ 320+20x-20x=32x-20x \\ 320=12x \\ \text{divide both sides y 12} \\ \frac{320}{12}=\frac{12x}{12} \\ \text{ x=26.66} \end{gathered}[/tex]rounded
[tex]x=26.7\text{ }[/tex]I hope this helps you
I need help on this and no this isn't a quiz
Answers
Concept:
Parallel planes are planes in the same three-dimensional space that never meet.
Parallel Lines or parallel Segments are always the same distance apart, they will never meet.
skew lines are two lines that do not intersect and are not parallel.
Question: Name a plane parallel to plane PQR:
Answer: plane JKL
Question: Name a segment parallel to segment KP:
Answer: segment OJ
Question: Name a segment that is skew to OJ
Answer: segment SR
Mr. Ocana drove 15 miles to go to work last week. Due to construction on the road, this week he drove 21 miles to go to work. What is the percent increase in the number of miles he drove to work this week? О 40% 50% ООО 60% O 70%
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ANSWER:
40%
STEP-BY-STEP EXPLANATION:
In this case, what we must do is calculate the percentage that represents 21 miles, assuming that 100% is 15 miles, like this
[tex]21\cdot\frac{100}{15}=140\text{\%}[/tex]Now we subtract 100% from this value, like this:
[tex]140\text{\%}-100\text{\%}=40\text{\%}[/tex]Help me pleaseeee quicklyyyyy
Answers
∠6 and ∠5 are alternative interior angle thus the measure of angles ∠5 = 45° , ∠6 = 45° ,∠7 = 45° and ∠8 = 135°.
What is an angle?An angle is a geometry in plane geometry that is created by 2 rays or lines that have an identical terminus.
The identical endpoint of the two rays—known as the vertex—is referenced as an angle's sides.
Angles 1,2,7 are the interior angles of a triangle and we know that the sum of all interior angles inside a triangle is 180°.
Therefore, ∠1 + ∠2 + ∠7 = 180°
Given, ∠1 = 70° and ∠2 = 65°
∠7 = 180° - (70 + 65) = 45°
Now, ∠8 = 180 - ∠7 ⇒ ∠8 = 135°
Now, ∠7 = ∠6 (vertical opposite angle) so ∠6 = 45°
∠6 = ∠5 (alternative interior angle) so ∠5 = 45°
Hence "∠6 and ∠5 are alternative interior angle thus the measure of angles ∠5 = 45° , ∠6 = 45° ,∠7 = 45° and ∠8 = 135°".
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hey can anyone help me on this im failing school xd
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slope of line is -3 for points (1,0) and (0,3)
What is Slope of Line?The slope of the line is the ratio of the rise to the run, or rise divided by the run. It describes the steepness of line in the coordinate plane.
The slope intercept form of a line is y=mx+b, where m is slope and b is the y intercept.
The slope of line passing through two points (x₁, y₁) and (x₂, y₂) is
m=y₂-y₁/x₂-x₁
From graph let us take two points (1, 0) and (0, 3)
x₁=1, x₂=0, y₁=0,y₂=3
Substitute these values in slope formula
m=3-0/0-1
m=3/-1
m=-3
Hence slope of line is -3.
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Hello. I would like help with problem. Quick answer is OK.Thank you
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not continuous, 2 holes. Option A is correct
Explanations;For a function to be continuous, the left hand limit of a function must be equal to the right hand limit at the point x = a
From the graph shown you can see that the limit of the function from the left is not equal to the limit of the function from the right at x = 0. Therefore, we can conclude that there are discontinuities at x = 0.
You can also see that the function has 2 holes at (0, 0) and (0, -1).
Admission to a state fair is $10, and each ride ticket costs $2.50. Write an en
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EXPLANATION
Let's call t to the number of tickets and c to the total cost, the appropiate relationship would be:
c = 2.5t + 10
The variable in the expression represents the number of tickets.
Which set can represent the side lengths of a right triangle?
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The set that represents a right triangle has to satisfy Pythagorean's Theorem where the greatest side is the hypothenuse. Let's evaluate each of them until we get the right set.
[tex]\begin{gathered} 7^2=6^2+(\sqrt[]{21})^2 \\ 49=36+21 \\ 49=57 \end{gathered}[/tex][tex]\begin{gathered} (5\sqrt[]{3})^2=7^2+5^2 \\ 25\cdot3=49+25 \\ 75=74 \end{gathered}[/tex][tex]\begin{gathered} (2\sqrt[]{5})^2=4^2+2^2 \\ 4\cdot5=16+4 \\ 20=20 \end{gathered}[/tex]As you can observe, set B satisfies the theorem.
Hence, B is the answer.Dan's dog walking job pays $15 per hour his job as a car wash attendant pays $400 each week Dan wants to know how many hours he needs to spend walking dogs to earn more than $520 in a week. Which three equalities can model this situation? select all the correct answers.
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Answer:
520<400+15x
15x>120
15x+400>520
Explanation:
Pay of Dan's car wash attendant job =$400 per week
The amount he earns per hour walking dogs = $15
Let the number of hours spent walking dogs in a week = x
Therefore, total earning for walking dogs =$15x
Since he wants to earn more than $520, we have that:
[tex]15x+400>520\text{ (Option F)}[/tex]We can rewrite this as:
[tex]520<400+15x\text{ (Option B)}[/tex]If we collect like terms, we have:
[tex]\begin{gathered} 520-400<15x \\ 120<15x \\ \implies15x>120\text{ (Option C)} \end{gathered}[/tex]So the inequalities are:
0. 520<400+15x
,1. 15x>120
,2. 15x+400>520
Write the equation of the line with x-intercept -2 and y-intercept -1 in slope-intercept form
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The x-intercept of -2 gives us an idea that point (-2,0) if found along the line. The y-intercept of -1, tells us that point (0,-1), this also tells us that b = -1.
Now that we have two points, we can solve for slope m
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ \text{Given two points} \\ (-2,0)\rightarrow(x_1,y_1) \\ (0,-1)\rightarrow(x_2,y_2) \\ \\ \text{Substitute} \\ m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-1-0}{0-(-2)} \\ m=-\frac{1}{2} \end{gathered}[/tex]Now that we have both m and b. Substitute these values to the slope intercept form
[tex]\begin{gathered} \text{Slope intercept form is} \\ y=mx+b \\ \text{where} \\ m\text{ is the slope} \\ b\text{ is the y-intercept} \\ \\ \text{Substitute the values from before and we get} \\ y=-\frac{1}{2}x-1 \end{gathered}[/tex]Solve the system using addition. Use pencil and paper. Explain why the addition method is a good choice for solving the system. If you wanted to solve for x first, is the addition method still a good choice? Explain. X-4.6y = - 8.8 -x+2.9y = 3.7 The solution is. (Type an order
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Find the principal which amounts to #5,000 at simple interestin 5 years at 2% per annum
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To answer this we have to apply the simple interest formula:
I =P x r x t
Where:
I= interest
P= Principal
R= Interest rate ( in decimal form)
t = time (years)
Replacing with the values given:
Interest= I
Principal = ?
Interest rate = 2/100 =0.02
time= 5 years
I = P x 0.02 x 5
I= 0.1P
Amount= P+I
A = P+0.1P
5,000= P+0.1P
5,000= 1.1P
5,000/1.1 =P
4,545.45 =P
Hello, I need some assistance with this homework question please for precalculusHW Q1
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To transform a function about the y axis
f(x) becomes f(-x)
y = sqrt( x) +2
To transform replace x with -x
y = sqrt(-x) +2
The 2 is a vertical translation up 2
Which expression is equivalent to (xy)z?A (x+y)+zB 2z(xy)C x(yz)D x(y+z)
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The expression (xy)z can be simplified as;
[tex]\begin{gathered} (xy)z=xyz \\ \text{Therefore xyz;} \\ xyz=x(yz) \end{gathered}[/tex]The correct answer is option C
Writing the equation of the line through two given points(1,-3) (5,-1). y=mx+b form
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Given points (1,-3) and (5,-1).
Since the slope of the line passing through two points
[tex](x_1,y_1)(x_2,y_2)[/tex]The slope of the equation is
[tex]\begin{gathered} m=\frac{y_2-y_1}{x_2-x_1} \\ m=\frac{-1-(-3)}{5-1} \\ m=\frac{2}{4} \\ m=\frac{1}{2} \end{gathered}[/tex]Therefore, the slope of the line is 1/2.
Now, use the slope and the point (1,-3) to find the y-intercept.
[tex]\begin{gathered} y=mx+c \\ -3=\frac{1}{2}\times1+c \\ c=-3-\frac{1}{2} \\ c=-\frac{-7}{2} \end{gathered}[/tex]Write the equation in slope-intercept form as
[tex]\begin{gathered} y=mx+c \\ y=\frac{1}{2}x-\frac{7}{2} \end{gathered}[/tex]a teacher asks 15 students to estimate an answer to a question the answers or 1, 5, 5, 6, 7, 8, 10, 12 the correct estimate is 7 the teacher wants to calculate how far of the estimate were by finding the absolute value of the difference between each estimate and the answer which estimate was off by the most
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We have the following estimations:
1, 5, 5, 6, 7, 8, 10, 12
The absolute value between each estimate and the answer is calculated as:
Estimate Absolute
Answer value
1 |1-7| = |-6| = 6
5 |5-7| = |-2| = 2
5 |5-7| = |-2| = 2
6 |6-7| = |-1| = 1
7 |7-7| = |0| = 0
8 |8-7| = |1| = 1
10 |10-7| = |3| = 3
12 |12-7| = |5| = 5
So, the estimated answer that was off by the most is 1.
18. The surface area of a cone is 12611 square meters. The diameter of the 5 points cone's circular base is 22 meters. What is the lateral area of the cone? Round your answer to the hundredths place value. * A 1 5 7 1 +/- B 5 -- C С 3 2 6 7 3 +/- D 1 4 7 0 2 7 +/-
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data
Area = 126pi m^2
diameter = 22
TA = pi r h + pir^2
126pi = LA + pi(11)^2
LA = 126pi - 121pi
LA = 5pi
Letter B.
Can I please have help finding the answer? I am really struggling!
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Given: An AP whose first term is -20 and a common difference of 3.
Required: To determine the 119th term of the AP.
Explanation: An AP with the first term, a, and with a common difference, d, is of the form-
[tex]a,a+d,a+2d,...,a+(n-1)d[/tex]where n is the number of terms in the AP.
The following formula gives the nth term of the AP-
[tex]a_n=a+(n-1)d[/tex]Here it is given that-
[tex]\begin{gathered} a=-20 \\ d=3 \\ n=19 \end{gathered}[/tex]Substituting these values into the formula for nth terms as-
[tex]a_{19}=-20+(19-1)3[/tex]Further solving-
[tex]\begin{gathered} a_{19}=-20+54 \\ =34 \end{gathered}[/tex]Final Answer: The 19th term of the AP is 34.
You spin the spinner once. What is P(2 or odd)?
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Answer:
P(2 or odd)=1
Explanation:
The spinner has 3 parts.
The probability of spinning a 2:
[tex]P(2)=\frac{1}{3}[/tex]The probability of spinning an odd number (1, 3):
[tex]P(\text{odd)}=\frac{2}{3}[/tex]Therefore:
[tex]\begin{gathered} P(2\text{ or odd)=}\frac{1}{3}+\frac{2}{3} \\ =\frac{3}{3} \\ =1 \end{gathered}[/tex]In parallelogram PQRS, diagonals PR and QS intersect at point T.Which statement would prove PQRS is a rhombus?PT > QTPT QTPR QSSTQT
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We can have more arguments to prove that PQRS is a rhombus, but, the argument that we will use here is:
Let's look at the first statement, we have
[tex]PT>QT[/tex]That's not correct, it would just prove that QR/2 > PS/2,
[tex]PR=QS[/tex]This statement implies
[tex]\begin{gathered} PR^2=QS^2 \\ \\ PS^2+SR^2=PQ^2+QR^2 \end{gathered}[/tex]We cannot conclude that
[tex]PS=SR=PQ=QR[/tex]The next statement is
[tex]PT=QT[/tex]A rhombus can have different diagonals, and in fact they have. Then let's go to the next one
[tex]ST=QT[/tex]That also not exactly says it's a rhombus, it's a pallelogram property.
[tex]\angle SPT=\angle QPT[/tex]By doing that we have that the diagonal bissects the angle
That implies that the angle b is also bissect.
The last statment is
[tex]\angle PTQ=\angle STR[/tex]That's literally the vertex angle, it's true always, not only in that case, therefore the only possible answer is
[tex]\angle SPT=\angle QPT[/tex]Pro