Q. According to Lewis dot theory, what types of electron pairs would you find surrounding the central atom of the sulfate ion?A. three bonding and one lone pairs of electrons.B. six bonding and no lone pairs of electrons.C. two bonding and two lone pair of electrons.D. one bonding and three lone pairs of electrons.

By using an appropriate conversion factor, the size of this popular car's engine is equal to 356.78 cubic inches.

A conversion factor simply refers to a number that is typically used to convert a number in one (1) set of units to another, either by dividing or multiplying.

Generally speaking, an appropriate conversion factor to an equal value must be used when it is necessary to perform any mathematical conversion.

Conversion:

1 cubic centimeter = 0.061023744094732 cubic inches.

5,840 cubic centimeter = X cubic inches.

Cross-multiplying, we have:

X = 0.061023744094732 × 5,840

X = 356.78 cubic inches.

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Complete Question:

A popular car has an engine that is reported to have a volume of 5840 cm³. What is the size in cubic inches?

Answer:

0.999

Explanation: divide by 10

Explanation:

A patient receives 100 mL of a 25 % m/v mannitol solution every hour. We have to find the mass in grams of mannitol that the pacient is receiving in 1 hour. We can use the formula of the mass/volume percent to find the answer to our problem.

% m/v = mass of solute in g/(volume of solution in mL) * 100 %

We know the concentration of the solution and we have the volume of solution in mL, so we can solve the formula for the mass of solute and get the answer to the problem.

25 % m/v = mass of solute in g/100 mL * 100 %

mass of solute in g = 25 * 100/100 g

mass of solute in g = 25 g

Answer: In 1 hour the patient receives 25 g of mannitol.

The PV work formula is:

w = -Pexternal * ΔV

w = -44.0 atm * (89.0 - 90.0)

w = -44.0 atm * -1 L

w = 44.0 L atm

For each L atm, we will have 101.325 Joules, therefore

44.0 L atm * 101.325 J

w = 4458.3 J or 4.4 kJ

STP stands for Standard Temperature and Pressure. Nowadays the STP is temperature of 0°C (273.15K) and pressure of 1 bar.

Assuming the gas behaves as an ideal gas, in these conditions the volume of each mol of gas is approximately 22.7 L.

Using rule of three, we can calculate the volume of 0.001 mol of H₂S:

Volume --- Number of moles

x --- 0.001 mol

22.7L --- 1 mol

So, the volume is approximately 0.0227 L.

Answer:

333.33 torr

Explanation:

Initial Pressure = 500 torr

Let Final Pressure be 'P'

Initial Temperature = 27 °C = 300 K

Final Temperature = -73 °C = 200 K

Initial Volume = Final Volume

From Combined Gas Law,

(Initial Pressure × Initial Volume) / Initial Temperature = (Final Pressure × Final Volume) / Final Temperature

So, P = (500 torr × 200 K) / 300 K = 333.33 torr

a)ultraviolet rays

Explanation:

ultraviolet rays are electromagnetic waves that are found in the range of 240 and 310 somewhere in between the electromagnetic spectrum

b)310nm causes minimum energy because the ultraviolet rays have reacted with oxygen to produce zone

c) 310nm to

=3.1×10^-7m once converted find the frequency using the converted wavelength as your wavelength AND once that has been done find your

E=hv=6.626×10^-34×9.68×10^14=6.414×10^-10J convert J to KJ/MOL will be 386.3KJ/MOL.

The frequency of the light that has a wavelength of 16.23 × 10⁻⁹ meter would be 1.84  × 10¹⁶ Hz , as the frequency and the wavelength are inversely proportional to each other.

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

C = λν

As given in the problem we have to calculate the frequency of the light if the wavelength of light is 16.23 × 10⁻⁹ meter.

The frequency of the light = 3 × 10⁸ / 16.23 × 10⁻⁹

                                            = 1.84  × 10¹⁶ Hz

Thus, the frequency of the light would be  1.84  × 10¹⁶ Hz.

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Answer:

Explanation:

To write the Lewis structure, it is important to look for the electrons of each atom in the Periodic Table of Elements.

C has 4 valence atoms, H has 1 valence atom and Cl has 7 valence atoms.

We write the C atom in the center. Then we have to complete the Octet in each atom, except in Hydrogen, because it can only has 2 electrons bonded.

1) Write the chemical equation.

2) List the elements in the reactants and in the products.

Reactants.

P: 4

O: 2

Products

P: 4

O: 10

Balance O.

3) Moles of O2 needed.

The molar ratio between P4 and O2 is 1 mol P4: 5 mol O2.

If 3.8 mol P4 are used, 19 mol O2 are needed.

.

If 1.53 g of copper is heated with excess sulfur to yield 1.76 g of copper (I) sulfide, the percent yield would be  75.43%.

The percent yield of a reaction is the actual yield relative to the theoretical yield of the same reaction.

The percent yield of a reaction is mathematically expressed as:

Percent yield = actual yield/theoretical yield x 100%.

Let us now consider the reaction in question. The equation of the reaction is given as:

[tex]Cu + S --- > CuS[/tex]

The mole ratio of the copper that reacts to the copper sulfide that is formed is 1:1.

Recall that: mole = mass/molar mass

The molar weight of copper is 63.55 g/mol

Mole of 1.53 g copper = 1.53/63.55

                           = 0.024 moles

The equivalent mole of copper sulfide produced will also be 0.024 moles.

The molar mass of CuS is 95.61 g/mol

Mass of 0.024 moles CuS = 0.024 x 96.61

                                      = 2.32 g

2.32 g is the theoretical yield of the reaction. But 1.76 g of copper sulfide is the actual yield.

Percent yield = 1.75/2.32 x 100%

                      = 75.43%

Thus, the percent yield of the reaction, if 1.53 g of copper is heated with excess sulfur to produce 1.76 g of copper (I) sulfide, is 75.43%.

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The change in the temperature of the gas, given that the volume is held constant is 63 °C

Let's begin by obtaining the new temperature of the gas. This can be obtained as follow:

P₁ / T₁ = P₂ / T₂

4.62 / 300 = 5.59 / T₂

Cross multiply

4.62 × T₂ = 300 × 5.59

Divide both side by 4.62

T₂ = (300 × 5.59) / 4.62

T₂ = 363 K

Subtract 273 to obtain answer in °C

T₂ = 363 – 273 K

T₂ = 90 °C

Finally, we shall determine the change in the temperature. This is illustrated below:

ΔT = T₂ – T₁

ΔT = 90 – 27

ΔT = 63 °C

The, the change in the temperature is 63 °C

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Complete question:

See attactched photo

A) 0.78 moles

B) 49.15grams

C) 1.73L

The formula for calculating the molarity of a solution is expressed as;

Given the following parameters

molarity of HNO3 = 1.3M

volume of HNO3 = 0.6L

A) moles of HNO3 = 1.3 * 0.6

moles of HNO3 = 0.78moles

B) Mass of HNO3 = moles * molar mass

Mass of HNO3 = 0.78 * 63.01

Mass of HNO3 = 49.15grams

There are 49.15grams of HNO3 present in 0.6L of the solution

C) According to dilution formula

Therefore the final volume of the solution will be 1.73L

Answer:

Chemistry - States of matter - Kinetic Molecular Theory

This is the theory that explains the states of the matter and is based on the idea that matter is composed of tiny particles that are always on motion.

Part 1: Check all the statements that apply to the behavior of an ideal gas

The behaviors that apply are:

1.Gas paarticles behave like hard sphares.

2.Gas particles travel randomly.

5. Average kinetic energy of a collection of gas particles depends on the temperature.

Part 2: According to kinetic-molecular theory the one that would not be considered an ideal gas is:

A gas with highly polar molecules that have very strong intermolecular forces.

This is because the theory consideres thhat there are no forces of attraction of repultion between gas particles.

Answer:

The difference between chemical and physical equilibrium. Physical is a reversible change of state. Chemical is a reversible chemical reaction that can go in the direction to create products or to create reactants.

A physical equilibrium is an equilibrium state in which the physical state of the system does not change. Chemical equilibrium is the equilibrium state in which the concentrations of reactants and products is not changed with time.

Hope this helps!

EXPLANATION:

Homologous series can be defined as a sequence of compounds with the same functional group and similar chemical properties in which the members of the series differ by -CH2. The homologous series the chemical properties of the element.

Below are the characteristics of the homologous series

1. The members of the homologous series have the same functional group

2. The members of the homologous series have a general method of preparation

3. The members of the homologous series differ by -CH2

4. The members of the homologous series have the same chemical properties.

The molarity of Blue I in Gatorade is 0.00010 mol L⁻ molecules of Blue I would you consume by drinking the entire bottle of Gatorade is 4.77 mol

Molarity is the amount of substance in certain volume of solution and also moles of solute per liter of solution

Here given data is

Volume = 946 mL

Molar mass = 792.84 g/mol

Concentration = 0.100mg/L

We have to find molarity and molecules of Blue I would you consume by drinking the entire bottle of Gatorade = ?

Molarity = number of moles of solute/volume of solution

Molarity = 0.100mg/L/946 mL

Molarity =0.00010 mol L⁻

Now we have to find molecules of Blue I = ?

Molecules of Blue I = 792.84 g/mol × avagadro number

Avagadro number = 6.022×10²³

Molecules of Blue I = 792.84 g/mol×6.022×10²³

Molecules of Blue I = 4.77 mol

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So,

The s sublevel has just one orbital, so can contain 2 electrons max. The p sublevel has 3 orbitals, so can contain 6 electrons max. The d sublevel has 5 orbitals, so can contain 10 electrons max. And the 4 sublevel has 7 orbitals, so can contain 14 electrons max.

Therefore, the correct answer is:

s:2, p:6, d:10, and f:14

Answer: The oxidation states can be labelled as:

- In Fe2O3: Fe = +3, O = -2

- In CO: C = +2, O = -2

- In Fe: Fe = 0

- In CO2: C = +4, O = -2

Fe is being reduced (changes from +3 to 0) and C is being oxidized (changes from +2 to +4).

Explanation:

The question requires us to label the oxidation states of each element in the following chemical equation, and then determine which one is being oxidized and which one is being reduced.

To solve this problem, we need to keep in mind a few points:

- oxidation occurs when its oxidation number increases (the element "loses" an electron);

- reduction occurs when its oxidation number decreases (the element "gains" an additional electron);

- the oxidation number of some elements is usually the same; a good example is oxygen (O): in most cases, O presentes oxidation number equals to -2.

Next, let's analyze the oxidation numbers of the elements in the reaction:

- Fe2O3: since O has oxidation number = -2, in the compound Fe2O3 the total charge brought by O is (-2) * 3 = -6, thus 3 atoms of Fe must have charge +6. We can say Fe has oxidation number = +3 in Fe2O3 (because (+3) * 2 + (-2) * 3 = 0).

- CO: O has oxidation number = - 2, thus C must present oxidation number = +2 in CO.

- Fe: Elementar Fe presents oxidation number = 0;

- CO2: Since O has oxidation number = -2, C must present oxidation number = +4 (because (+4) * 1 + (*2( * 2 = 0.

Thus, the oxidation states can be labelled as:

- In Fe2O3: Fe = +3, O = -2

- In CO: C = +2, O = -2

- In Fe: Fe = 0

- In CO2: C = +4, O = -2

Analyzing the oxidation states in the reactants (left side) and products (right side), we can see that Fe goes from +3 to 0, thus it is being reduced, while C goes from +2 to +4, thus it is being oxidized.

First, we have to complete the reactions with the respective products:

1.00147g of of cobalt-60 remain after 104.7 min if you start with 1024g.

According to nuclear decay [tex]N_{t} = N_{0 } e^[/tex]^-λt

for half-life ----[tex]t_{\frac{1}{2} }[/tex] =  0.693/λ

half-life of cobalt [tex]t_{\frac{1}{2} }[/tex] = 10.47

initial amount [tex]N_{0}[/tex] = 1024g.

t = 104.7 min

final product [tex]N_{t}[/tex] =?

[tex]t_{\frac{1}{2} }[/tex] = 0.69/λ   ( according to half-life)

10.47 = 0.693/λ

λ = 0.693/10.47 [tex]min^{-1}[/tex]

[tex]N_{t} = N_{0 } e^[/tex]^-λt

 [tex]N_{t}[/tex] = 1024[tex]\times e^{\frac{-0.693}{10.47} } \times 104.7 min[/tex]

[tex]N_{t}[/tex] = 1024 g[tex]\times e^{-6.93}[/tex]

[tex]N_{t}[/tex] = 1.00147g

Half-life is the time it takes for a quantity to decrease to half its original value. This term is often used in nuclear physics to describe how quickly unstable atoms decay radioactively or how long stable atoms last. The term is also used more generally to describe any type of exponential decay.

The half-life of a radioactive isotope is the  time required for half of the radioactive isotope to decay. The half-life of a given radioactive isotope is constant. it is unaffected by conditions and is independent of the initial amount of that isotope.

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In order to solve this question, we can use the electronegativity table (or also just a regular periodic table), which will give us the values of electronegativity for each element.

As we can see in this table, the least electronegative element will be Al, with only 1.61 of value. If you were with a regular periodic table, you could find this answer by thinking about the periodic table trend, or we can also call it a rule, that in most elements the electronegativity will grow in value from left to right and from the bottom to the top, then you would also get Al as your answer

Answer = Al, letter D

1) Set the chemical equation

2) Find out how many moles of HCl react in the solution.

3) Find out how many moles of NaOH reacted with HCl

4) Find out the milliliters of NaOH

In this question, we have a gas presenting volume and pressure, and the gas law that we can use to calculate it is Boyle's gas Law, which perfectly correlates both pressure and volume, the formula is:

P1V1 = P2V2

We have:

P1 = 27.5 atm

V1 = 103.4 L

P2 = 69.3 atm

V2 = ?

Now we add these values into the formula:

27.5 * 103.4 = 69.3 * V2

V2 = 41.0 L

The name for MgBr2 is Magnesium bromide

answer and explanation

now that we have the x value we can find the equilbrium concentratoins of tehegases

for Iodine

x =0.456

= 0.5-x

= 0.5-0.456

= 0.035mols

concentration = 0.035mols/ 0.250L

= 0.14M

for Bromine

x =0.456

= 0.5-x

= 0.5-0.456

= 0.035mols

concentration = 0.035mols/ 0.250L

= 0.14M

the concentration of the two gases is 0.14M

Electron capture occurs when one of the electrons in the atom is captured by the atom's nucleus. The captured electron combines with one proton to form a neutron.

We have to find the nuclide that is produced when the aluminum-28 undergoes an electron capture.

If we look for the atomic number of Al in the periodic table we will see that it is 13. That means that it has 13 protons. Then we are given the atomic mass of aluminum, it is 28. That means that if we add the number of protons and the number of neutrons we get 28.

atomic mass = n° of protons + n° of neutrons = 13 + 15 = 28

atomic number = n° of protons = 13

The nucleus of the aluminum atom will capture one electron that will combine with a proton of the nucleus to form a neutron. So the atomic number will change because it will have 1 proton less. But the atomic mass won't change because we are losing one proton but winning a neutron, so it remains the same. After the electron capture, the new nuclide will have:

atomic mass nuclide = n° of protons + n° of neutrons = 12 + 16 = 28

atomic number nuclide = n° of protons = 12

If we look for the element that has an atomic number of 12 in the periodic table we will see that it is magnesium.

Finally we can express this like a reaction:

28 0 28

Al + e --------> Mg

13 -1 12

Answer:

28

Mg

12

Answer

NO is the limiting reactant

Explanation

Given that:

The mass of NH3 that reacted = 43.4 g

The mass of NO that reacted = 30 g

The equation for the reaction is: 4NH3 + 6NO --> 5N2 + 6H2O

What to find:

The limiting reactant.

Step-by-step solution:

The first step is to convert the given mass of the reactants to moles.

Using the mole formula and the molar masses of (NH3 = 17.0 g/mol and NO = 30.0 g/mol)

The final step is to determine the limiting reactant by comparing the mole ratio from the given equation with the mole ratio in the step above.

From the equation, 4 moles of NH3 reacted with 6 moles of NO

So 2.55 moles of NH3 is expected to react with (2.55 x 6)/4 = 3.825 moles of NO

1.0 mol NO is less than 3.825 mol NO, hence, NO is the limiting reactant because it will be the reactant to be completely used up first.

Answer

19.6 grams

Explanation

Given:

Mass of calcium phosphate produced = 50.500 g

Equation: 3Ca(s) + 2H3PO4(aq) ---> Ca3(PO4)2(s) + 3H2(g)

What to find:

The grams of calcium required to produce 50.500 g of calcium phosphate.

Step-by-step solution:

From the equation, 3 mol Ca produce 1 mol Ca3(PO4)2

1 mole Ca3(PO4)2 = 310.19 grams

1 mole Ca = 40.078 grams

This means, (3 x 40.078 g) = 120.234 g Ca produce 310.19 g Ca3(PO4)2

So x grams Ca will be required to produce 50.500 grams Ca3(PO4)2

x grams Ca will be equal

The grams of calcium required to produce 50.500 g of calcium phosphate = 19.6 grams