HEY CAN ANYONE PLS ANSWER THESE QUESTION!!!!!

HEY CAN ANYONE PLS ANSWER THESE QUESTION!!!!!

Answers

Answer 1

1. A model can come in many shapes, sizes, and styles.

2. Models can help scientists communicate their ideas, understand processes, and make predictions.

3. Thomson's experiments with cathode ray tubes showed that all atoms contain tiny negatively charged subatomic particles or electrons.

4. The plum pudding model has electrons surrounded by a volume of positive charge

5. Electrons are kept in the orbit around the nucleus by the electromagnetic         force.

IamSugarbee


Related Questions

What is the molar mass of the molecule C8H18, crude oil?

Answers

Answer:

114.23 g/mol

Explanation:

a tennis ball is thrown straight up with an initial velocity of 22.5 m/s how much total time is the ball in the air

Answers

Answer:

4.6s

Explanation:

v=u+at

0=22.5+(-9.8)t

-22.5=-9.8t

t=-22.5/-9.8

t=2.295 s

The total time will double

2.295×2=4.59s

=4.6s

Select the correct answer.
Type O negative blood is considered the universal red blood cell donor because it
OA.
Has all 3 types of antigens.
OB.
Has all 3 types of antibodies.
Lacks all 3 types of antigens.
OD
Lacks all 3 types of antibodies.

Answers

Answer:

The answer is C.) Lacks all 3 types of antigens.

A soccer player applies a force of 48.4 N to a soccer ball while kicking it. If the ball has
a mass of 0.44 kg, what is the acceleration of the soccer ball?
A. 27.3 m/s2
B. 21.3 m/s2
C. 110 m/s2
D. 104 m/s2

Answers

Answer:

C. 110 m/s2

Explanation:

Force = Mass x Acceleration

Since we have the force and the mass, we can rearrange this equation to solve for acceleration by dividing both sides by mass:

Force/Mass = (Mass x Acceleration)/Mass

Acceleration = Force/Mass

Now we just have to plug in our values and calculate!

Acceleration = 48.4/0.44

Acceleration = 110m/s/s

It is option C. 110 m/s2

Hope this helped!

Yea C is the answer the first answer is right

A water skier is towing by motorboat at a constant velocity of magnitude 15 km /h. The boat speed up, and after a short interval the skier is towed at a new constant velocity of magnitude 20 km/h. What is the net force on the skier when she is moving at 15 km/h? And at 20 km/h?

Answers

Answer:

The skier is experimenting a net force of 0 newtons in both cases. ([tex]v_{1} = 15\,\frac{km}{h}[/tex], [tex]v_{2} = 20\,\frac{km}{h}[/tex])

Explanation:

According to Newton's First Law, an object is in equilibrium when it is either at rest or moving at constant velocity, which means that net force is equal to 0 newtons.

Therefore, the skier is experimenting a net force of 0 newtons in both cases.

To get employees to work longer hours, employers often offer __________ in the form of extra pay.
A.
costs
B.
benefits
C.
incentives
D.
consequences

Answers

C- Incentives it’s like a reward ~!

Answer:

C

Explanation:

I took the test

Find the resultant of an easterly force of 100 N and a southeast force of 80 N acting at 65 degrees to the 100 N force

Answers

Answer:

Resultant is 152 N at 28.5 degrees south to the 100 N force

Explanation:

A student fires a cannonball vertically upwards. The cannonball returns to the
ground after a 4.60s flight. Determine all unknowns and answer the following
questions. Neglect drag and the initial height and horizontal motion of the
cannonball. Use regular metric units (ie. meters).
How long did the cannonball rise?
unit
What was the cannonball's initial speed?
unit
What was the cannonball's maximum height?
unit
V

Answers

Answer:

(a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

Explanation:

Given that,

Time = 4.60 s

We need to calculate the initial velocity

Using equation of motion

[tex]v=u-gt[/tex]

Put the value into the formula

[tex]0=u-9.8\times4.60[/tex]

[tex]u=45.0\ m/s[/tex]

We need to calculate the distance

Using formula of distance

[tex]d=v\times t[/tex]

Put the value into the formula

[tex]d=45\times4.60[/tex]

[tex]d=207\ m[/tex]

We need to calculate the maximum height

Using equation of motion

[tex]v^2=u^2-2gh[/tex]

Put the value into the formula

[tex]0=(45.0)^2-2\times9.8\times h[/tex]

[tex]h=\dfrac{(45.0)^2}{2\times9.8}[/tex]

[tex]h=103.3\ m[/tex]

Hence, (a). The distance is 207 m.

(b). The initial velocity is 45.0 m/s

(c). The maximum height is 103.3 m

What is the name of the kind of stretch that involves stretching as far as you can and then holding for 10-30 seconds

Question 2 options:

PNF


ballistic


dynamic


static

Answers

Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

Which event is an example of condensation?
A. Wet clothes are drying on a clothesline.
B. A mirror fogs up when someone takes a hot shower.
C. Water drips from an icicle on the edge of a roof.
O D. Rain turns to sleet as it nears the ground.

Answers

Answer:

the answer to your question is b a mirror fogs up when someone takes a hot shower.

The process of conversion of gaseous water to its liquid form is called condensation. The fogs formed on the mirror from the hot shower is an example of condensation.

What is condensation?

Condensation is the process of cooling up of water vapor to liquid water. Water vapor condenses when it cools. Condensation can be best understood from the reason behind raining.

When water vaporizers from resources and cools from the sky, and the vapor condenses to form liquid droplets. Similarly we can observe water droplets in the window pane due to the similar effect.

The water vapor arises from the hot shower condenses in the atmosphere and forms the drops on the mirror. Therefore, the mirror fogs up by the hot shower is an example of condensation.

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In economics, _________ is the amount of a resource that firms and producers are willing and able to provide to the marketplace

Answers

sectors are the amount of resources

A moving car skids to a stop with the wheels locked across a level roadway. Of the forces listed, identify which act on the car.
Normal
Gravity
Applied
Friction
Tension
Air resistance

Answers

Answer:

Normal, Gravity, Friction, and Air Resistance.

Explanation:

When a moving car skid to stop and its wheels are locked across, then the following forces will be applied on the car:

Normal force: It will act counter to gravity that pushes an object against a surface and acts perpendicular to the contact surface.

Gravity: Gravity force acts in each and every object having mass and it can not be avoidable. So, the gravity force will also apply to the car and attract it to the earth's surface.

Friction: Friction is a force that acts opposite to the motion and stops or slows motion. Friction will be applied to the car that will oppose the motion of the car and stop it.

Air resistance: air resistance is defined as the forces exerted by air that acts opposite to the relative motion of an object. Air resistance will also be applied to the car when it will skid to stop as we are always surrounded by the air.

Hence, the correct answers are "Normal, Gravity, Friction, and Air Resistance."

A freshly prepared sample of radioactive isotope has an activity of 10 mCi. After 4 hours, its activity is 8 mCi. Find: (a) the decay constant  and half-life T1/2; (b) How many atoms of the isotope were contained in the freshly prepared sample? (c) What is the sample's activity 30 hours after it is prepared?

Answers

Answer:

(a). The decay constant is [tex]1.55\times10^{-5}\ s^{-1}[/tex]

The half life is 11.3 hr.

(b). The value of N₀ is [tex]2.38\times10^{11}\ nuclei[/tex]

(c). The sample's activity is 1.87 mCi.

Explanation:

Given that,

Activity [tex]R_{0}=10\ mCi[/tex]

Time [tex]t_{1}=4\ hours[/tex]

Activity R= 8 mCi

(a). We need to calculate the decay constant

Using formula of activity

[tex]R=R_{0}e^{-\lambda t}[/tex]

[tex]\lambda=\dfrac{1}{t}ln(\dfrac{R_{0}}{R})[/tex]

Put the value into the formula

[tex]\lambda=\dfrac{1}{4\times3600}ln(\dfrac{10}{8})[/tex]

[tex]\lambda=0.0000154\ s^{-1}[/tex]

[tex]\lambda=1.55\times10^{-5}\ s^{-1}[/tex]

We need to calculate the half life

Using formula of half life

[tex]T_{\dfrac{1}{2}}=\dfrac{ln(2)}{\lambda}[/tex]

Put the value into the formula

[tex]T_{\dfrac{1}{2}}=\dfrac{ln(2)}{1.55\times10^{-5}}[/tex]

[tex]T_{\dfrac{1}{2}}=44.719\times10^{3}\ s[/tex]

[tex]T_{\dfrac{1}{2}}=11.3\ hr[/tex]

(b). We need to calculate the value of N₀

Using formula of [tex]N_{0}[/tex]

[tex]N_{0}=\dfrac{3.70\times10^{6}}{\lambda}[/tex]

Put the value into the formula

[tex]N_{0}=\dfrac{3.70\times10^{6}}{1.55\times10^{-5}}[/tex]

[tex]N_{0}=2.38\times10^{11}\ nuclei[/tex]

(c). We need to calculate the sample's activity

Using formula of activity

[tex]R=R_{0}e^{-\lambda\times t}[/tex]

Put the value intyo the formula

[tex]R=10e^{-(1.55\times10^{-5}\times30\times3600)}[/tex]

[tex]R=1.87\ mCi[/tex]

Hence, (a). The decay constant is [tex]1.55\times10^{-5}\ s^{-1}[/tex]

The half life is 11.3 hr.

(b). The value of N₀ is [tex]2.38\times10^{11}\ nuclei[/tex]

(c). The sample's activity is 1.87 mCi.

Consider a buggy being pulled by a horse.
Which is correct?
1. The horse can pull the buggy forward only
if the horse weighs more than the buggy.
2. The force on the buggy is as strong as the
force on the horse. The horse is joined to the
Earth by flat hoofs, while the buggy is free to
roll on its round wheels.
3. The horse pulls before the buggy has time
to react so they move forward.
4. The horse pulls forward slightly harder
than the buggy pulls backward on the horse,
so they move forward.

Answers

Answer:

Option 2

Explanation:

Answer:B

Explanation:because she started of with no money and now she made her money up

can we add 2 atoms together? 3? How do particles combine to form the variety of matter one observes?

Answers

yes you can add two atoms together
yes you can add them together

the solubility of sugar is 30 degree Celsius at 220 what does it mean​

Answers

Answer:

So, that if you put 100 mL of 30 degree water in a beaker, you could add up to 220 grams of sugar and it would eventually dissolve. In other words, that mass of sugar should dissolve in 100 mL of water to make a solution that is just saturated.

The solubility of sugar is 30° C at 220. This means 220g of sugar is dissolved in 100g of solvent to make the saturated solution at 30° C. Solutions.

What is the solution?

Most frequently, the solubility is represented in terms of mass per volume of water. Solubilities are frequently stated as g/100 mL, g/100 g, or g/L of water.

The ratio you provided is probably 1 g of sugar to 100 mL of water. In other words, if you put 100 mL of water at 30 degrees in a beaker, you could add up to 220 grams of sugar, and it would finally dissolve.

To generate a solution that is just saturated, the mass of sugar should dissolve in 100 mL of water.

Therefore, at 220 degrees, sugar dissolves at 30 degrees. This indicates that to create the saturated solution at 30° C, 220g of sugar must be dissolved in 100g of solvent.

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A moving object with a decreasing velocity covers distance during
each new second than it covered in the previous second.


A.the same
B.more
C.less

Answers

The answer is C. Less

Where are streams located?

Answers

Answer:

Larger seasonal streams are more common in dry areas. Rain-dependent streams (ephemeral) flow only after precipitation. Runoff from rainfall is the primary source of water for these streams. Like seasonal streams, they can be found anywhere but are most prevalent in arid areas.

Explanation:

7. Your teacher has mixed salt, pepper, and water. Describe a procedure that you could use to separate this mixture. Be sure to list all of the materials you would need, your set up, and your expected results.​

Answers

Answer:

hope this could help you

a car travels at a speed of 50 m/s for 13 seconds. what is the distance that the car travels?​

Answers

To find the distance, we should multiply the speed and time.

d = s x t

= 50m/s x 13 s

= 650 m

The answer is 650m. Let me know if I got wrong

1. According to Newton's third law of motion, how are action
and reaction forces related?
2. How is momentum conserved?
3. Suppose you and a friend, who has exactly twice your mass,
are on skates. You push away from your friend. How does the
force with which you push your friend compare to the force
with which your friend
pushes you? How do your
accelerations compare?
4. Thinking Critical be ly comparing and Contrasting
Which has more momentum, a 250-kg dolphin swimming
at 6 m/s, or a 450-kg manatee swimming at 2 m/s?
(need 1-4 answered ASAP)

Answers

Answer:

you couldn't do this on your own or search it up on google

2
How is acceleration related to force when mass is constant, according to Newton's second law of motion?
A. The acceleration is directly proportional to the net force,
OB
The acceleration is inversely proportional to the net force.
C. The acceleration is inversely proportional to the square root of the net force.
OD
The acceleration is directly proportional to the square root of the net force.
Reset
Next Question

Answers

Answer:

A

Explanation:

The acceleration of an object is directly proportional to its net force.

[tex]a = \frac{f}{m} [/tex]

Answer:

Correct choice: A. The acceleration is directly proportional to the net force

Explanation:

Newton's Second Law of Motion

According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force F and inversely proportional to the object's mass m:

[tex]\displaystyle a=\frac{F}{m}[/tex]

Correct choice: A. The acceleration is directly proportional to the net force

What are the SI units for distance and time?

Answers

Answer:

distance is meters, time is seconds

Answer:

distance is meters(m)

time is seconds (s)

Explanation:

A force of 500 N acts for a time interval of 0.001 second on an object of mass 0.20 kg that was initially at rest. Calculate the final velocity of the object after the force acts

Answers

Answer:

100

Explanation:

The final velocity of the object after the force acts is 2.5 meters per second.

To calculate the final velocity of the object after the force acts, we can use Newton's second law of motion, which states that:

Force = Mass × Acceleration

We need to find the acceleration of the object first. Since the object was initially at rest, its initial velocity (u) is 0 m/s.

The force acting on the object is 500 N, and the mass of the object is 0.20 kg. We can rearrange the equation to find the acceleration (a):

Acceleration (a) = Force / Mass

a = 500 N / 0.20 kg

a = 2500 m/s²

Now, we can use the kinematic equation to find the final velocity (v) of the object:

Final velocity (v) = Initial velocity (u) + (Acceleration × Time)

The initial velocity (u) is 0 m/s (since the object was initially at rest), and the time interval (t) is 0.001 second.

Final velocity (v) = 0 m/s + (2500 m/s² × 0.001 s)

v = 0 m/s + 2.5 m/s

v = 2.5 m/s

Hence, the final velocity of the object after the force acts is 2.5 meters per second.

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protons are present in sodium atom.
a 11
b 10
C 12
d 9

Answers

11

Explanation:

There are 11 protons in a sodium atom


3. A person who is initially stationary is eventually walking
at a speed of 1.5 m/s after an acceleration of 0.5 m/s?,
calculate the distance it takes them to reach this speed.
4. A lorry pulls forward after initially being stationary, it
takes the lorry 40 m to reach a speed of 8 m/s, calculate the
lorry's acceleration.

7. A person begins moving after initially being stationary, the person
accelerates at 0.5m/s2 over a distance of 9m what is their final speed

Answers

Explanation:

3. A person who is initially stationary is eventually walking

at a speed of 1.5 m/s after an acceleration of 0.5 m/s?,

calculate the distance it takes them to reach this speed.

Given parameters:

Initial velocity  = 0m/s

Final velocity  = 1.5m/s

Acceleration = 0.5m/s

Unknown:

Distance  = ?

Solution:

To solve this problem, we apply the relevant motion equation;

    V² = U² + 2aS

where V is the final velocity

          U is the initial velocity

          a is the acceleration

         S is the distance

Input the parameters;

     1.5² = 0 + 2 x 0.5 x S

    2.25= S

The distance to reach this speed is 2.25m

4. A lorry pulls forward after initially being stationary, it

takes the lorry 40 m to reach a speed of 8 m/s, calculate the

lorry's acceleration.

Given parameters:

   Initial velocity = 0m/s

   Final velocity  = 8m/s

   Distance  = 40m

Unknown:

Acceleration = ?

Solution:

    V² = U² + 2aS

Input the parameters and solve;

  8² = 0² + 2 x a x 40

   64 = 80a

      a = [tex]\frac{64}{80}[/tex]  = 0.8m/s²

   

7. A person begins moving after initially being stationary, the person

accelerates at 0.5m/s2 over a distance of 9m what is their final speed

    Given parameters:

    Initial velocity  = 0m/s

    acceleration  = 0.5m/s²

     distance  = 9m

Unknown:

Final velocity  = ?

Solution:

     V² = U² + 2aS

Input the parameters and solve;

   V² = 0² + 3 x 0.5 x 9

    V² = 13.5

    V  = 3.7m/s

A rocket takes off from Earth. It travels 825km in 75 seconds. What is the
speed of the rocket?
0 1 km/s
11 km/s
O 1.1 km/s
O 111 km/s

Answers

Answer:

11 km/s

Explanation:

v=s/t

v=825km/75s

v=11km/s

At a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2. What can the staff member estimate for the original speed of the race car if it came to a stop during the skid?

Answers

Answer:

27.1 m/s

Explanation:

Given that at a race car driving event, a staff member notices that the skid marks left by the race car are 9.06 m long. The very experienced staff member knows that the deceleration of a car when skidding is -40.52 m/s2.

Using third equation of motion,

V^2 = U^2 + 2aS

Since the car is decelerating, the final velocity V = 0

Substitute all the parameter into the equation above,

0 = U^2 - 2 * 40.52 * 9.06

U^2 = 734.22

U = [tex]\sqrt{734.22}[/tex]

U = 27.096

U = 27.1 m/s  approximately

Therefore, the staff member can estimate for the original speed of the race car to be 27.1 m/s if it came to a stop during the skid

conversion
18230 mJ to kJ?

Answers

Answer:

0.01823

Explanation:

big brain

Will was riding his bike when a dog ran out in front of him. He slammed on his brakes. During this quick stop, some of the mechanical energy (his motion) was changed into
A) heat energy.
B) light energy.
C) kinetic energy.
D) gravitational energy.

Answers

Answer:

A

Explanation:

big brain

During this quick stop, some of the mechanical energy (his motion) was changed into heat energy.

What is energy?

Energy is the ability to do work. There are different types of energy such as Heat energy, light energy, kinetic energy, and gravitational energy.

Heat is the energy that moves from one body to another when temperatures are different. Heat passes from the hotter to the colder body when two bodies with differing temperatures are brought together.

The joule is a unit of energy that serves as the SI unit for heat (J). The calorie (cal), which is defined as "the amount of heat necessary to raise the temperature of one gram of water from 14.5 degrees Celsius to 15.5 degrees Celsius," is another common unit of heat measurement.

Therefore, During this quick stop, some of the mechanical energy (his motion) was changed into heat energy.

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