Helpppppppppppppppp
find x​

x=2

Step-by-step explanation:

y=7-2x -------(1)

6y=9x

y=9x/6 = 3x/2------(2)

Now,

Equation equation 1 and 2

7-2x= 3x /2

2(7-2x)=3x

14-4x=3x

14=4x+3x

14=7x

14/7=x

x=2

Answer:

option A

Step-by-step explanation:

Answer os option a

Answer: Angle 3 and Angle 2

Step-by-step explanation:

The angles form a linear pair, which means they are supplementary.

In order to solve a proportion, you should cross-multiply:-

[tex]\bf{\displaystyle\frac{3x}{10} =\frac{3}{2}}[/tex]

Multiply 3x times 2 and 10 times 3:-

[tex]\bf{6x=30}[/tex]

Divide both sides by 6:-

[tex]\boxed{\bf{x=5}}[/tex]

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I'll comment and/or edit my answer :)

The probability that the selected number is even, multiple of 4 and prime are 7/15, 1/5 and 2/5 respectively

Probability is the likelihood or chance that an event will occur.

Probability = Expected outcome/Total outcome

Given the following set

S=​{1, ​2, 3,​ 4,..., 15}

n(S) = 15

If the selected number is even

E = {2, 4, 6, 8, 10, 12, 14}

n(E) = 7

Pr(selecting even number) = n(E)/n(S)

Pr(selecting even number) = 7/15

If the selected number is a multiple of 4

E = {4, 8, 12}

n(E) = 3

Pr(multiple of 4) = n(E)/n(S)

Pr(multiple of 4) = 3/15 = 1/5

If the selected number is a prime number

E = {2, 3, 5, 7, 11, 13}

n(E) = 6

Pr(prime number) = n(E)/n(S)

Pr(prime number) = 6/15 = 2/5

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Although Alex and Lauren will both step into position 4,6, they will not do it at the same time, so they will not meet.

Lauren:

Alex:

Both will step in the position 4,6, However, Lauren will be in this positon in the second 4, while Alek will do it on the second 3.

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Answer:

16

Step-by-step explanation:

equal both using corresponding law

Answer:

Your answers: -5, 0, 1

Step-by-step explanation:

–8 < 3x + 7 ≤ 10 That is the original compount inequality given.

We need to solve it in order to get an easy option.

-15, -5, -3, 0, 1 are the options.

_________________________________________________

Steps to solve:

–8 < 3x + 7 ≤ 10

Subtract 7 from both sides

–8 < 3x ≤ 10 - 7

Now do 10-7

–8 < 3x ≤ 3

Do 3x divided by 3

–8 < x ≤ 1

________________________________________________________

Evaluation and Answer Explanation:

–8 < x ≤ 1

That is your inequality statement.

The inequality statement states that "x" is greater than -8 but less than or equal to 1.

We can automatically choose 0 and 1 because 0 is greater than -8 and less than or equal to 1.

1 is correct because it is greater than -8 and less than or equal to 1

Now, there are two answers remaining: -15; -5.

Let's try -15.

-15 isn't greater than -8 but is less than 1. This is incorrect because it follows one inequality but doesn't follow both.

**Rule: the bigger you go on the negatives like -20 or -99 your numbers get smaller. If you go more towards the 0 like -1, -5, -3 your numbers get bigger.

-5 works because it is greater than -8 and less than or equal to 1.

Your answers: -5, 0, 1

Answer:

coke red

Step-by-step explanation:

correct me if im wrong

Using the arrangements formula, it is found that 6 different orders of top-three finishers are possible.

The number of possible arrangements of n elements is given by the factorial of n, that is:

[tex]A_n = n![/tex]

In this problem, the possible orders are arrangements of 3 elements, hence, the number of orders is given by:

[tex]A_3 = 3! = 6[/tex]

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Answer:

Step-by-step explanation:

Given points P and Q have same x-coordinate but different y- coordinates.

The distance between P and Q is the difference of y- coordinates:

The area is 64 cm², it means the adjacent sides are

a)

If the points R and S are to the left, their coordinates are

b)

If the points R and S are to the right, their coordinates are

Answer:

Points R and S are to the left of Points P and Q

R = (-9, 4)

S = (-9, -4)

Points R and S are to the right of Points P and Q

R = (7, 4)

S = (7, -4)

Step-by-step explanation:

Given coordinates:

Points P and Q have the same x-value.

The vertical distance between these two points is:

[tex]\begin{aligned}\implies \sf y_P-y_Q & =\sf 4-(-4)\\ & =\sf 4+4\\ & =\sf 8\:units \\ & =\sf 8\:cm\end{aligned}[/tex]

Area of a rectangle = width × length

If the area of the rectangle PQRS is 64 cm² then:

[tex]\begin{aligned} \implies \sf 64 & = \sf width \times 8\\\implies \sf width & = \sf \dfrac{64}{8}\\\implies \sf width& = \sf 8 \: cm \end{aligned}[/tex]

This means that the y-values of points R and S will be the same as points P and Q, but the x-values will either be 8 less or 8 more.

Points R and S are to the left of Points P and Q

R = (-1 - 8, 4) = (-9, 4)

S = (-1 - 8, -4) = (-9, -4)

Points R and S are to the right of Points P and Q

R = (-1 + 8, 4) = (7, 4)

S = (-1 + 8, -4) = (7, -4)

Answer:

0

Step-by-step explanation:

7-11=-4

-4+4=0

Answer:

50, 30 and 20

Step-by-step explanation:

Check out the attached photo

Step-by-step explanation: please see attached to PDF document.

Answer:

a) 6

b) 1/3

c) 2

Step-by-step explanation:

a) 3 ( x + 1 ) - x = 15. expand the bracket

3x + 3 - x = 15

2x + 3 = 15. collect the like terms

2x = 15 - 3.

2x = 12.

x = 12/2 = 6

b) 5 ( x + 2 ) - 2x = 11. expand the bracket

5x + 10 - 2x = 11

3x + 10 = 11. collect the like terms

3x = 11 - 10

3x = 1

x = 1/3

c) 6 ( 1 - 2x ) = - 4 - 7x. expand the bracket

6 - 12x = -4 -7x. collect the like terms

6 + 4 = -7x + 12x

10 = 5x

or

5x =. 10

x = 10/5 = 2

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Answer:

9d^2(5d−2)

Step-by-step explanation:

Answer:

Step-by-step explanation:

1 pound = 16 ounces

16 ounces = $7.99

1 ounce = $0.50 (about)

Lets see

Left:-

Not left anything

Answer:

18.85 years

Step-by-step explanation:

Using the [tex]A=P(1+\frac{r}{n} )^{nt}[/tex] we can manipulate it to give us time.

However, let's identify our variables:

A is our final amount which is given to us, $1400.

P is our principle which is $500.

r is our rate which is 5.5% which can be traducted into 0.055.

n is the # of time our money get compounded per year, in this case quarterly means 4 times a year therefore n = 4.

t is time and is what we are trying to solve for.

Now let's manipulate our equation to find t:

[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]

[tex]\frac{A}{P} =(1+\frac{r}{n} )^{nt}[/tex]

[tex]\frac{1400}{500} =(1+\frac{0.055}{4} )^{4t}[/tex]

[tex]2.8=1.01375^{4t}[/tex]

[tex]log_{1.01375}(2.8)=log_{1.01375}1.01375^{4t}[/tex]

[tex]log_{1.01375}(2.8)=4t[/tex]

[tex]\frac{log_{1.01375}(2.8)}{4} =t[/tex]

[tex]18.84876253=t[/tex]

It would take about 18.85 years in order for you to accumulate at least $1400.

Answer:

not sure if the 4 is seperate but if it is then (30+26)+(6-33)

Step-by-step explanation:

Answer:

True

Step-by-step explanation:

like pirates, the stars were their navagation

Answer:

Cylinder height = 10

Semi-circle height = 3

Cone height = 4

Step-by-step explanation:

The height of the cylinder is always going to be the long side. 6 is the diameter of its circle. Here is a list of variables:

Diameter, D = 6

Radius, r = 3

Slant height of cone, c = 5

To find the height of the cylinder, we will need to find the height's of the cone and semi-circle:

CONE (see image attached)

a² + b² = c²

3² + h² = 5²

h² = 25 - 9

h = √16

h = 4

SEMI-CIRCLE

h = radius

h = 3

CYLINDER

Cylinder height = total h - semi-circle h - cone h

h = 17 - 3 - 4

h = 10

I'm not sure if you're trying to solve for volume, so I'll end it here LOL. Hope this helps and have a great evening!

The average velocity is the rate of the distance function over time

The average velocity over the interval [1, 3] is 8 kilometers per hour

The distance function is given as:

d(t) = 8(t³ - 6t² + 12t)

The interval is given as: [1,3]

Calculate d(1) and d(3)

d(3) = 8(3³ - 6 * 3² + 12 * 3)

Evaluate

d(3) = 72

d(1) = 8(1³ - 6 * 1² + 12 * 1)

Evaluate

d(1) = 56

The average velocity (v) is the calculated as:

v = (d(3) - d(1))/(3 - 1)

Substitute known values

v = (72 - 56)/(3 - 1)

Evaluate

v = 8

Hence, the average velocity over [1, 3] is 8 kilometers per hour

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1) The net area between the two functions is 2.

2) The net area between the two functions is 4/3.

3) The net area between the two functions is 17/6.

4) The net area between the two functions is approximately 1.218.

5) The net area between the two functions is 1/2.

The area between the two curves is determined by definite integrals for a interval between two values of x. A general formula for the definite integral is presented below:

[tex]A = \int\limits^{b}_{a} {[f(x) - g(x)]} \, dx[/tex]   (1)

Where:

Now we proceed to solve each integral:

The lower and upper limits between the two functions are 0 and 1, respectively. The definite integral is described below:

[tex]A = \int\limits^1_0 {x^{0.5}} \, dx - \int\limits^1_0 {x^{2}} \, dx[/tex]

[tex]A = 2\cdot (1^{1.5}-0^{1.5})-\frac{1}{3}\cdot (1^{3}-0^{3})[/tex]

[tex]A = 2[/tex]

The net area between the two functions is 2. [tex]\blacksquare[/tex]

The lower and upper limits between the two functions are -3 and -1, respectively. The definite integral is described below:

[tex]A = - 4 \int\limits^{-1}_{-3} {x} \, dx - \int\limits^{-1}_{-3} {x^{2}} \, dx - 3 \int\limits^{-1}_{-3}\, dx[/tex]

[tex]A = -2\cdot [(-1)^{2}-(-3)^{2}]-\frac{1}{3}\cdot [(-1)^{3}-(-3)^{3}] -3\cdot [(-1)-(-3)][/tex]

[tex]A = \frac{4}{3}[/tex]

The net area between the two functions is 4/3. [tex]\blacksquare[/tex]

The definite integral is described below:

[tex]A = \int\limits^{1}_{0} {x^{2}} \, dx + 2\int\limits^{1}_{0}\, dx + \int\limits^{1}_{0} {x} \, dx[/tex]

[tex]A = \frac{1}{3}\cdot (1^{3}-0^{3}) + 2\cdot (1-0) +\frac{1}{2}\cdot (1^{2}-0^{2})[/tex]

[tex]A = \frac{17}{6}[/tex]

The net area between the two functions is 17/6. [tex]\blacksquare[/tex]

The definite integral is described below:

[tex]A = \int\limits^{0}_{-1} {e^{-x}} \, dx+ \int\limits^{0}_{-1} {x} \, dx[/tex]

[tex]A = -(e^{0}-e^{1}) + \frac{1}{2}\cdot [0^{2}-(-1)^{2}][/tex]

[tex]A \approx 1.218[/tex]

The net area between the two functions is approximately 1.218. [tex]\blacksquare[/tex]

This case requires a combination of definite integrals, as f(x) may be higher that g(x) in some subintervals. The combination of definite integrals is:

[tex]A = \int\limits^{\frac{\pi}{3} }_0 {\sin 2x} \, dx - \int\limits^{\frac{\pi}{3} }_{0} {\sin x} \, dx + \int\limits^{\frac{\pi}{2} }_{\frac{\pi}{3} } {\sin x} \, dx -\int\limits^{\frac{\pi}{2} }_{\frac{\pi}{3} } {\sin 2x} \, dx[/tex]

[tex]A = -\frac{1}{2}\cdot (\cos \frac{2\pi}{3}-\cos 0)+(\cos \frac{\pi}{3}-\cos 0 ) -(\cos \frac{\pi}{2}-\cos \frac{\pi}{3} )+\frac{1}{2}\cdot (\cos \pi-\cos \frac{2\pi}{3} )[/tex]

[tex]A = \frac{1}{2}[/tex]

The net area between the two functions is 1/2. [tex]\blacksquare[/tex]

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Answer:

multiple tasking them right

Answer:

results-driven

Step-by-step explanation:

Answer:

144 sq cm

Step-by-step explanation:

The base is a triangle. Area of a triangle is:

A = 1/2 b • h

A = 1/2(4)•3

A = 6

There are 2 of these bases.

Area of 2 bases= 12.

There are three rectangular sides. Area of a rectangle is:

A = l × w (or b•h)

A = 5 × 11 = 55

A = 3 × 11 = 33

A = 4 × 11 = 44

Add up three rectangular faces and two bases for Total Surface Area:

12 + 55 + 33 + 44

= 144 sq cm

Answer:

144 cm ²

Step-by-step explanation:

The surface area of a right triangular prism is made up of 2 congruent triangles (these are called the "bases") and 3 rectangles.

Surface area of a right triangular prism formula

Surface area = (S₁ + S₂ + S₃)L + bh

where:

⇒ Surface area = (3 + 4 + 5)11 + 4 × 3

                          = (12)11 + 12

                          = 132 + 12

                          = 144 cm²

Answer:

Step-by-step explanation:

Owing represent a negative balance.

So the inequality for this case is:

The word owing is given which simply denotes to negative transaction

So here the inequality is

Or

Answer
[tex]\sqrt29[/tex]

Step-by-step explanation:

1. Write the distance formula:

[tex]\sqrt(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}[/tex]

2. Substitute

Substitue (6, -4) and (1, -6) into

[tex]\sqrt(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}[/tex]

[tex]\sqrt(1 - 6) ^{2} + (-6 + 4)^{2}[/tex]

3. Calculate

[tex]\sqrt(1 - 6) ^{2} + (-6 + 4)^{2}[/tex]

[tex]\sqrt(-5) ^{2} + (-2)^{2}[/tex]

[tex]\sqrt5 ^{2} + 2^{2}[/tex]

[tex]\sqrt25 + 4[/tex]

[tex]\sqrt29[/tex]

Answer:

81 [ft].

Step-by-step explanation:

1) the basic formula is: h=gt²/2, where g - acceleration due to gravity, t - elapsed time;

2) if the final velocity is 72, g=32, then it is possible to calculate elapsed time:

[tex]t=\frac{V}{g}=\frac{72}{32}=\frac{9}{4} [sec].[/tex]

3) if g=32, t=9/4, then the required height is:

[tex]h=\frac{32*(\frac{9}{4} )^{2} }{2}=\frac{16*81}{16}=81[ft].[/tex]

The height of the building comes to be 81 feet.

Initial velocity u= 0 feet/sec

Final velocity v= 72 feet/sec

The acceleration due to gravity g =32ft /sec²

Height of the building h= suppose h

The equation of a motion is:

[tex]v^{2} =u^{2} +2gh[/tex]

Where u and v are the initial and final velocities.

[tex]72^{2} =0+2*32*h\\144 = 64h\\h=81[/tex]

So, the height of the building = 81 feet.

Therefore, the height of the building comes to be 81 feet.

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Answer:

tan 70 times thirty gives you -1.70

The answer is 1/3.

If you're still not sure (and math teachers will appreciate you doing this), you can check. Divide 1 by 3 and you will get 0.333333333333...

I hope this answers your question.