Answers
For the given functions, the two compositions are:
(f o g)(x) = 9x² + 5
(g o f)(x) = 3*x² + 15
How to find the compositions of the functions?Here we have two functions which are:
f(x) = x² + 5
g(x) = 3x
Now we want to find the compositions:
(f o g)(x) = f( g(x) )
So we just need to evaluate f(x) in g(x), we will get:
f( g(x) ) = g(x)² + 5
f( g(x) ) = (3x)² + 5 = 9x² + 5
The other composition is:
(g o f)(x) = g(f(x))
And we can get this in a similar way:
g(f(x)) = 3*f(x) = 3*(x² + 5) = 3*x² + 15
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Related Questions
Mary Anne wants the professor to build a ramp to make it easier to get things into the cook hut. The ramp has to rise 2 feet and will have anangle of 12 degrees with the ground.Calculate how far out from the hut the ramp will go. Round to the nearest 1 decimal. _____What length of timbers will be needed to build the ramp (how long is the distance along the ramp) Round to the nearest 1 decimal. _____
Answers
The next figure illustrates the problem
x is computed as follows:
tan(12°) = opposite/adjacent
tan(12°) = 2/x
x = 2/tan(12°)
x = 9.4 ft
y is computed as follows:
sin(12°) = opposite/hypotenuse
sin(12°) = 2/y
y = 2/sin(12°)
y = 9.6 ft
(30 points) Solve for the missing side of the triangle. Round to the hundredths place if needed.
Answers
Answer:
[tex]6 \sqrt{6} [/tex]
Step-by-step explanation:
The square value of hypotenuse is equal to the square value of sum of the two legs:
[tex] {15}^{2} + {x}^{2} = {21}^{2} [/tex]
225 + x^2 = 441 subtract 225 from both sides
x^2 = 216 find the root of both sides
x = 6√(6)
Hi, can you help me to solve this problem, please!!
Answers
In this problem, we have a vertical parabola open downward
that means
the vertex represents a maximum
looking at the graph
the maximum has coordinates (1,9)
therefore
the vertex is (1,9)There are 12 freshman 6 sophomores 12 juniors and 16 seniors. What percentage of club members are sophomores
Answers
Answer:
13% (rounded)Step-by-step explanation:
12 + 6 + 12 + 16 = 46
46 total students
out of those 46 students, 6 are sophomores
so put that into a fraction it becomes
[tex]\frac{6}{46}[/tex]
which equals
0.130434783
which in percentage is
13.0434783%
or 13% rounded
Austin and carly despoit 500.00 into a savings account which earns 1% interest compounded monthly they want to use the money in the account to go on a trip in 2 years how much will they be able to spend
Answers
EXPLANATION
Let's see the facts:
Austin and Carly deposit: $500
Interest rate= 1%
Compounding period = monthly
Total number of years = 2
Given the Compounding Interest Rate formula:
[tex]\text{Compound amount = P (1+r/n)\textasciicircum{}nt}[/tex]n is the compounding period
t is the number of years
r is te interest rate in decimal form
Replacing the given values will give us:
[tex]\text{Compound amount = 500 (1+}\frac{0.01}{12})^{12\cdot2}[/tex]Solving the power:
[tex]\text{Compound amount = 500 }\cdot1.020192843[/tex][tex]\text{Compound amount = \$510.09}[/tex]Answer: Austin and Carly will be able to spend $510.09.
For the function f(x) = 6e^x, calculate the following function values:f(-3) = f(-1)=f(0)= f(1)= f(3)=
Answers
Consider the given function,
[tex]f(x)=6e^x[/tex]Solve for x=-3 as,
[tex]\begin{gathered} f(-3)=6e^{-3} \\ f(-3)=6(0.049787) \\ f(-3)=0.2987 \end{gathered}[/tex]Thus, the value of f(-3) is 0.2987 approximately.
Solve for x=-1 as,
[tex]\begin{gathered} f(-1)=6e^{-1} \\ f(-1)=6(0.367879) \\ f(-1)=2.2073 \end{gathered}[/tex]Thus, the value of f(-1) is 2.2073 approximately.
Solve for x=0 as,
[tex]\begin{gathered} f(0)=6e^0 \\ f(0)=6(1) \\ f(0)=6 \end{gathered}[/tex]Thus, the value of f(0) is 6 .
Solve for x=1 as,
[tex]\begin{gathered} f(1)=6e^1 \\ f(1)=6(2.71828) \\ f(1)=16.3097 \end{gathered}[/tex]Thus, the value of f(1) is 16.3097 approximately.
Solve for x=3 as,
[tex]\begin{gathered} f(3)=6e^3 \\ f(3)=6(20.0855) \\ f(3)=120.5132 \end{gathered}[/tex]Thus, the value of f(3) is 120.5132 approximately.
What is the opposite of the number −12?
A(-1/12
B(1/12
C(0
D(12
Answers
Answer: D(12)
Step-by-step explanation: To find the opposite it the number you would do -12= -12 x -1 = 12
PLEASE ANSWER ASAP ! Thanks :)
Answers
The inverse function table of the function is given by the image at the end of the answer.
How to calculate the inverse function?A function y = f(x) is composed by the following set of cartesian points:
(x,y).
In the inverse function, the input of the function represented by x and the output of the function represented by y are exchanged, meaning that the coordinate set is given by the following rule:
Thus, the points that will belong to the inverse function table are given as follows:
x = -8, f^(-1)(x) = -2, as the standard function has x = -2 and f(x) = -8.x = -4.5, f^(-1)(x) = -1, as the standard function has x = -1 and f(x) = -4.5.x = -4, f^(-1)(x) = 0, as the standard function has x = 0 and f(x) = -4.x = 0, f^(-1)(x) = 2, as the standard function has x = 2 and f(x) = 0.More can be learned about inverse functions at https://brainly.com/question/3831584
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Answer:
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5} \vphantom{\dfrac12} x &-8 &-4.5 & -4&0 \\\cline{1-5} \vphantom{\dfrac12} f^{-1}(x) &-2 & -1& 0&2 \\ \cline{1-5}\end{array}[/tex]
Step-by-step explanation:
The inverse of the graph of a function is its reflection in the line y = x.
Therefore, the mapping rule to find the inverse of the given ordered pairs is:
(x, y) → (y, x)Therefore:
The inverse of (-2, -8) is (-8, -2)The inverse of (-1, -4.5) is (-4.5, -1)The inverse of (0, -4) is (-4, 0)The inverse of (2, 0) is (0, 2)Completed table:
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5} \vphantom{\dfrac12} x &-8 &-4.5 & -4&0 \\\cline{1-5} \vphantom{\dfrac12} f^{-1}(x) &-2 & -1& 0&2 \\ \cline{1-5}\end{array}[/tex]
solve the quadratic equation below.3x^2-9=0
Answers
Using the rotation R, can you create a function R(ABCD) that is equivalent to the reflection of ABCD across both the x-axis and y-axis?
Answers
The reflection over the x-axis is given by:
[tex]R(x,y)\to(-x,y)[/tex]And the reflection over the y-axis is given by:
[tex]R(x,y)\to(x,-y)[/tex]Thus, a function that is equivalent to the reflection of ABCD across both axis would be:
[tex]R(x,y)\to(-x,-y)[/tex]Question 2 of 10The one-to-one functions g and h are defined as follows.g={(-8, 6), (-6, 7), (-1, 1), (0, -8)}h(x)=3x-8Find the following.g-¹(-8)=h-¹(x) =(hoh− ¹)(-5) =
Answers
Answer: We have to find three unknown asked quantities, before we could do that we must find the g(x) from the coordinate points:
[tex]\begin{gathered} g=\left\{\left(-8,6\right),(-6,7),(-1,1),(0,-8)\right\}\Rightarrow(x,y) \\ \\ \text{ Is a tabular function} \\ \end{gathered}[/tex]The answers are as follows:
[tex]\begin{gathered} g^{-1}(-8)=0\text{ }\Rightarrow\text{ Because: }(0,-8) \\ \\ \\ h^{-1}(x)=\frac{x}{3}+\frac{8}{3} \\ \\ \\ \text{ Because:} \\ \\ h(x)=3x-8\Rightarrow\text{ switch }x\text{ and x} \\ \\ x=3h-8 \\ \\ \\ \\ \text{ Solve for }h \\ \\ \\ h=h^{-1}(x)=\frac{x}{3}+\frac{8}{3} \end{gathered}[/tex]The last answer is:
[tex]\begin{gathered} (h\text{ }\circ\text{ }h^{-1})(-5) \\ \\ \text{ Can also be written as:} \\ \\ h[h^{-1}(x)]\text{ evaluated at -5} \\ \\ h(x)=3x-8 \\ \\ h^{-1}(x)=\frac{x}{3}+\frac{8}{3} \\ \\ \\ \therefore\Rightarrow \\ \\ \\ h[h^{-1}(x)]=3[\frac{x}{3}+\frac{8}{3}]-8=x+8-8=x \\ \\ \\ \\ h[h^{-1}(x)]=x \\ \\ \\ \\ h[h^{-1}(-5)]=-5 \end{gathered}[/tex]Suppose that 27 percent of American households still have a traditional phone landline. In a sample of thirteen households, find the probability that: (a)No families have a phone landline. (Round your answer to 4 decimal places.) (b)At least one family has a phone landline. (Round your answer to 4 decimal places.) (c)At least eight families have a phone landline.
Answers
Answer:
(a) P = 0.0167
(b) P = 0.9833
(c) P = 0.0093
Explanation:
To answer these questions, we will use the binomial distribution because we have n identical events (13 households) with a probability p of success (27% still have a traditional phone landline). So, the probability that x families has a traditional phone landline can be calculated as
[tex]\begin{gathered} P(x)=nCx\cdot p^x\cdot(1-p)^x \\ \\ \text{ Where nCx = }\frac{n!}{x!(n-x)!} \end{gathered}[/tex]Replacing n = 13 and p = 27% = 0.27, we get:
[tex]P(x)=13Cx\cdot0.27^x\cdot(1-0.27)^x[/tex]Part (a)
Then, the probability that no families have a phone landline can be calculated by replacing x = 0, so
[tex]P(0)=13C0\cdot0.27^0\cdot(1-0.27)^{13-0}=0.0167[/tex]Part (b)
The probability that at least one family has a phone landline can be calculated as
[tex]\begin{gathered} P(x\ge1)=1-P(0) \\ P(x\ge1)=1-0.167 \\ P(x\ge1)=0.9833 \end{gathered}[/tex]Part (c)
The probability that at least eight families have a phone landline can be calculated as
[tex]P(x\ge8)=P(8)+P(9)+P(10)+P(11)+P(12)+P(13)[/tex]So, each probability is equal to
[tex]\begin{gathered} P(8)=13C8\cdot0.27^8\cdot(1-0.27)^{13-8}=0.0075 \\ P(9)=13C9\cdot0.27^9\cdot(1-0.27)^{13-9}=0.0015 \\ P(10)=13C10\cdot0.27^{10}\cdot(1-0.27)^{13-10}=0.0002 \\ P(11)=13C11\cdot0.27^{11}\cdot(1-0.27)^{13-11}=0.00002 \\ P(12)=13C12\cdot0.27^{12}\cdot(1-0.27)^{13-12}=0.000001 \\ P(13)=13C13\cdot0.27^{13}\cdot(1-0.27)^{13-13}=0.00000004 \end{gathered}[/tex]Then, the probability is equal to
P(x≥8) = 0.0093
Therefore, the answers are
(a) P = 0.0167
(b) P = 0.9833
(c) P = 0.0093
A square paddock has an area of 7140.25m².
How long is each side?
Answers
Answer:
it's 84.5 m ...................
what are the terms in 7h+3
Answers
Input data
7h + 3
Procedure
A term is a single mathematical expression.
3 = is a single term.
It is simply a numerical term called a constant.
7h = is also a single term. , The coefficient of the first term is 7
Identify the property of equality that justifies the missing step to solve the given equation.Equation3x + (1 - 8) = 124r-I8 = 12StepsOriginal equationAssociative property of addition4r= 20r=5Division property of equalitya. subtraction property of equalityb. addition property of equalityc. division property of equalityd. multiplication property of equality
Answers
From the attached image;
[tex]4x-8=12[/tex]The next step is to add 8 to both sides of the equation to remove -8.
[tex]\begin{gathered} 4x-8+8=12+8 \\ 4x=20 \end{gathered}[/tex]Since we added to the equation.
The step is an addition property of equality
URGENT!! ILL GIVE
BRAINLIEST! AND 100 POINTS!!!!!!
Jimmy ran 20 meters west
from home and then turned
north to jog 25 meters. Jimmy
ran 45 meters, but could have
arrived at the same point by in
a straight line. How many
meters could he have using a
line distance?
A. 3.5 meters
B. 7 meters
C. 32 meters
D. 45 meters
Answers
Answer:
32 meters
Step-by-step explanation:
If Jimmy ran straight from his house, the answer wouldnt be 45 because thats what he did originally when he ran a longer route from his home. 3.5 and 7 meters are too short because he ran at least 25 based off of when he turned from the West. 32 is the only reasonable answer because it would be a shorter distance than 45 meters but longer than 25 because of the route he takes in a straight line.
Answer:
here is the answer to your question
hope you get it well
What is the solution to the equation below? Round your answer to two decimal places.ex = 5.9A.x = 124.50B.x = 1.77C.x = 365.04D.x = 0.77
Answers
We have the next given equation:
[tex]e^x=5.9[/tex]Now, we can solve for x using the exponent's properties:
Add both sides ln:
[tex]\ln e^x=\ln5.9[/tex]With the ln we can take down the exponent and simplify ln*e = 1.
Hence,
[tex]\begin{gathered} x=\ln(5.9) \\ x=1.77 \end{gathered}[/tex]Hence, the correct answer is option B.
i need some help list the integers in the set
Answers
Solution
The integers are the set of real numbers consisting of the natural numbers, their additive inverses and zero. {...,−5,−4,−3,−2,−1,0,1,2,3,4,5,...} The set of integers is sometimes written J or Z for short. The sum, product, and difference of any two integers is also an integer.
The whole numbers are set of real numbers that includes zero and all positive counting numbers. Whereas, excludes fractions, negative integers, fractions, and decimals. All the whole numbers are also integers, because integers include all the positive and negative numbers
The integers are real numbers
Therefore the numbers are list of integers
[tex]-8,9,\frac{0}{7},\frac{12}{4}[/tex]Solve for x(2x+3)(3x-2)=(3x+3)(2x-2)
Answers
To solve for x, we need to apply distributive property as:
[tex]\begin{gathered} \left(2x+3\right)\left(3x-2\right)=\left(3x+3\right)\left(2x-2\right) \\ 2x\cdot3x+2x\cdot(-2)+3\cdot3x+3\cdot(-2)=3x\cdot2x+3x(-2)+3\cdot2x+3\cdot(-2) \\ 6x^2-4x+9x-6=6x^2-6x+6x-6 \\ 6x^2+5x-6=6x^2-6 \\ 6x^2+5x-6+6=6x^2-6+6 \\ 6x^2+5x=6x^2 \\ 6x^2+5x-6x^2=6x^2-6x^2 \\ 5x=0 \\ x=0 \end{gathered}[/tex]Answer: x = 0
Hello! I need some help with this homework question, please? The question is posted in the image below. Q6
Answers
Step 1
Given;
[tex]g(x)=3x^2-5x-2[/tex]Required; To find the zeroes by factoring
Step 2
Find two factors that when added gives -5x and when multiplied give -6x
[tex]\begin{gathered} \text{These factors are;} \\ -6x\text{ and x} \end{gathered}[/tex][tex]\begin{gathered} -6x\times x=-6x^2 \\ -6x+x=-5x \end{gathered}[/tex]Factoring we have and replacing -5x with -6x and x we have
[tex]\begin{gathered} 3x^2-6x+x-2=0 \\ (3x^2-6x)+(x-2)_{}=0 \\ 3x(x-2)+1(x-2)=0 \\ (3x+1)(x-2)=0 \\ 3x+1=0\text{ or x-2=0} \\ x=-\frac{1}{3},2 \\ \text{The z}eroes\text{ are, x=-}\frac{1}{3},2 \end{gathered}[/tex]Graphically the x-intercepts are;
The x-intercepts are;-1/3,2
Hence, the answer is the zeroes and x-intercepts are the same, they are;
[tex]-\frac{1}{3},2[/tex]The baker has 305 cakes to send to the farmers market. If he can pack up to 20cakes in a crate for shipping, what is the minimum number of boxes required toship all of the cakes. Explain your reasoning.
Answers
We have 305 cakes. As we know
Determine which of the following lines, if any, are perpendicular • Line A passes through (2,7) and (-1,10) • Line B passes through (-4,7) and (-1,6)• Line C passed through (6,5) and (7,9)
Answers
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data:
Line A:
point 1 (2,7)
point 2 (-1,10)
Line B:
point 1 (-4,7)
point 2 (-1,6)
Line C:
point 1 (6,5)
point 2 (7,9)
Step 02:
perpendicular lines:
slope of the perpendicular line, m’
m' = - 1 / m
Line A:
slope:
[tex]m\text{ = }\frac{y2-y1}{x2-x1}=\frac{10-7}{-1-2}=\frac{3}{-3}=-1[/tex]Line B:
slope:
[tex]m=\frac{y2-y1}{x2-x1}=\frac{6-7}{-1-(-4)}=\frac{-1}{-1+4}=\frac{-1}{3}[/tex]Line C:
slope:
[tex]m\text{ = }\frac{y2-y1}{x2-x1}=\frac{9-5}{7-6}=\frac{4}{1}=4[/tex]m' = - 1 / m ===> none of the slopes meet the condition
The answer is:
there are no perpendicular lines
the difference of twice h and 5 is as much as the sum of h and 4
Answers
The value of h by solving the given relationship we get, h = 9
In the above question, a word problem is given with the following relations which are as
First we'll express the given word problem statements into mathematical equation expressions
Therefore, The difference of twice of h and 5 is as much as the sum of h and 4
It can be written as in mathematical equation form as
2h - 5 = h + 4
Now, we need to find the value of h by solving the above mathematical equation formed put of the given relationship
Here,
2h - 5 = h + 4
2h - h = 5 + 4
h = 9
Hence, The value of h by solving the given relationship we get, h = 9
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A population of values has a normal distribution with u = 203.6 and o = 35.5. You intend to draw a randomsample of size n = 16.Find the probability that a single randomly selected value is greater than 231.1.PIX > 231.1) =Find the probability that a sample of size n = 16 is randomly selected with a mean greater than 231.1.P(M > 231.1) =Enter your answers as numbers accurate to 4 decimal places. Answers obtained using exact z-scores or Z-scores rounded to 3 decimal places are accepted.
Answers
Part 1:
The probability that a single randomly selected value is greater than 231.1 equals one minus the probability that it is less or equal to 231.1:
P(x > 231.1) = 1 - P(x ≤ 231.1)
Now, to find P(x ≤ 231.1), we can transform x in its correspondent z-score, and then use a z-score table to find the probability:
x ≤ 231.1 => z ≤ (231.1 - 203.6)/35.5, because z = (x - mean)/(standard deviation)
z ≤ 0.775 (rounding to 3 decimal places)
Then we have:
P(x ≤ 231.1) = P( z ≤ 0.775)
Now, using a table, we find:
P( z ≤ 0.775) ≅ 0.7808
Then, we have:
P(x > 231.1) ≅ 1 - 0.7808 = 0.2192
Therefore, the asked probability is approximately 0.2192.
Part 2
For the next part, since we will select a sample out of other samples with size n = 16, we need to use the formula:
z = (x - mean)/(standard deviation/√n)
Now, x represents the mean of the selected sample, which we want to be greater than 231.1. Then, we have:
z = (231.1 - 203.6)/(35.5/√16) = 27.5/(35.5/4) = 3.099
P(x > 231.1) = 1 - P(x ≤ 231.1) = 1 - P(x ≤ 231.1) = 1 - P( z ≤ 3.099) = 1 - 0.9990 = 0.0010
Therefore, the asked probability is approximately 0.0010.
Sally started on the 12th floor. She walked up 4 flights. Then she went down 2 flights. Then she ran up 8 flights of stairs. a) Write an ADDITION expression b) What floor did she end up on? SHOW ALL WORK!
Answers
1) Gathering the data
Initial point 12th floor
2) She started on 12th floor and walked up 4 flights of stairs, assuming from each floor to another we have just 1 flight of stair. And we're using an addition expression, Hence, we can say:
12 +4-2+8=
16 +6
22
She ended up on the 22th floor
Choose a student in grades 9 to 12 at random and ask if he or she is studying a language other than English. Here isthe distribution of the students:
Answers
Solution:
a) 0.38
b)0.36
c)0.33
Analysis:
a)Studying a language other than English: In this case, we add all probabilities of the chart, except None (Because that is people don't study a la
If the cost of a car is $6,345.00, and the tax rate is 6%, how much is the total cost of the car?
Answers
Given:
Cost of Car is $6,345
Tax rate is 6%
[tex]\begin{gathered} \text{Tax Amount=6345}\times\frac{6}{100} \\ \text{Tax Amount= \$380.70} \end{gathered}[/tex][tex]\begin{gathered} \text{Total cost of the car =6345+380.70} \\ \text{Total cost of the car = \$6725.70} \end{gathered}[/tex]Trapezoid W'X'Y'Z' is the image of trapezoid W XYZ under a dilation through point C What scale factor was used in the dilation?
Answers
The scale factor is basically by what we need to multiply the original to get the dilated one.
Simple.
We can see that the original one is Trapezoid WXYZ and the dilated one is W'X'Y'Z'.
THe dilated trapezoid is definitely bigger than original. So the scale factor should be larger than 1.
One side of original is "6" and the corresponding side of dilated trapezoid is "14".
So, what we have to do to "6", to get "14"??
This is the scale factor!
To get 14, we have to multiply 6 with, suppose, "x", so:
[tex]\begin{gathered} 6x=14 \\ x=\frac{14}{6} \\ x=\frac{7}{3} \end{gathered}[/tex]Hence, SF is 7/3
i inserted a picture of the question state whether it’s a b c or d please don’t ask tons of questions yes i’m following
Answers
The possible values for any probability are between zero and one. With this in mind we conclude that A, B, C and E are allowed probabilities
Mr. Alvarez is laying square paver blocks in sections in rows that look like steps.Section 1 has 3 rows that look like steps, the section is 6 blocks wide, and the bottom step is 8 blocks long. Section 2 has 4 rows that look like steps, the Section is 8 blocks wide, and the bottom step is 10 blocks long. Each Section after that is 2 blocks wider and 2 blocks longer.Drag the numbers to complete the table. Numbers may be used once, more than once, or not at all.
Answers
12
14
36 blocks
56 blocks
108 blocks
Explanation:The length of section 1 = 8
The length increases by 2 uits as the section increases
Section 2 length of block = length of section 1 + 2 =
= 8 + 2
length of block = 10
Section 3 length of block = length of section 2 + 2
= 10 + 2
length of block = 12
Section 4 length of block = length of section 3 + 2
= 12 + 2
length of section = 14
Number of blocks needed:
if the blocks are counted,
For section 1 there are 6 rows . So we count the total number of blocks on each of them
= 4 + 4 + 6 + 6 + 8 + 8
Section 1 = 36 blocks
For section 2, we count the number of blocks on each row
= 4 + 4 + 6 + 6 + 8 + 8 + 10 + 10
section 2 = 56 blocks
For sectoion 3: The length and width increases by 2 respectively
previous length + 2 = 10 + 2 = 12
Due to the increase we would have two length of 12
= 4 + 4 + 6 + 6 + 8 + 8 + 10 + 10 + 12 + 12 = 80
Already given = 80
For section 4: The length and width increases by 2 respectively
previous length + 2 = 12 + 2 = 14
The increase causes an addition of two length of 14 blocks
Total blocks = 4 + 4 + 6 + 6 + 8 + 8 + 10 + 10 + 12 + 12 + 14 + 14
Total blocks for Section 4 = 108