Help me please help me help please help

Answer:

(-11[2-25/ l-2l + 5]

(11[2-25/2+5]

(11[23/7]

11(3.28571428571)

36.1428571429

Answer:

5y × 6y = 30y^2

Step-by-step explanation:

All you're doing is multiplying the coefficients 5 and 6, to get 30, and any variable multiplied by another variable will give you that variable, squared.

Friendly fun fact: When you give points, we are only earning half of that. (Just thought you'd like to know.)

Hope this helped :)

Answer:

60 ft

after subtracting the motor car

Answer:

y = 3x - 2

Step-by-step explanation:

Parallel lines have the same gradient in this case 3 is the gradient.

We will use the point (2,4) to form our own equation.

4 will be y, 3 will be m, 2 will be x

All we need is to find the C in the equation y=mx + c

4 = 3(2) + c

4 = 6 + c

C = -2

Therefore;

y = 3x - 2

Answer:

x = 12

Step-by-step explanation:

Answer:

Step 2: Commutative Property

Step 3: Associative Property

Step-by-step explanation:

According to the Commutative Property of Addition: Two real numbers can be added in either order.

a + b = b + a

Therefore, she used the Commutative Property in Step 2.

In Step 3, she used the Associative Property, in which the grouping of the addends does not change the sum.

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Explanation:

Note that 2^4 = 16 is one less than 17.

Because of this nature of being 1 less, we can say the remainder of 16/17 is -1 because it comes up one short.

In terms of modular arithmetic, we can say,

[tex]2^4 \equiv 16 \ (\text{mod } 17)\\\\2^4 \ \equiv -1 (\text{mod } 17)\\\\[/tex]

Then let's raise both sides to the 20th power. I'm picking 20 because 20*4 = 80 which will help build toward 81

[tex]2^4 \equiv -1 \ (\text{mod } 17)\\\\\left(2^4\right)^{20} \equiv (-1)^{20} \ (\text{mod } 17)\\\\2^{20*4} \equiv 1 \ (\text{mod } 17)\\\\2^{80} \equiv 1 \ (\text{mod } 17)\\\\[/tex]

Lastly, we'll multiply both sides by 2 to get to the final answer

[tex]2^{80} \equiv 1 \ (\text{mod } 17)\\\\2*2^{80} \equiv 2*1 \ (\text{mod } 17)\\\\2^{1}*2^{80} \equiv 2 \ (\text{mod } 17)\\\\2^{1+80} \equiv 2 \ (\text{mod } 17)\\\\2^{81} \equiv 2 \ (\text{mod } 17)\\\\[/tex]

So if we were to divide 2^81 over 17, then we get some quotient and a remainder of 2

Answer:

The answer would be , less than one .

The difference of 1.4 - 0.95 is less than one as per the concept of subtraction.

To determine this, we can simply subtract the two values:

1.4 - 0.95 = 0.45

Since the result of the subtraction is 0.45, which is less than one, we can conclude that the difference of 1.4 - 0.95 is indeed less than one.

In numerical terms, the difference is 0.45, which is 45 hundredths or less than half of one whole unit.

When comparing the two original values, 0.95 is almost half of 1.4, making the difference smaller than one.

In summary, the difference of 1.4 - 0.95 is less than one, specifically 0.45. It is essential to pay attention to the decimal values and their magnitudes when determining the difference between two numbers.

To learn more about subtraction;

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The sum of the interior angles of a triangle is 180 degrees. Therefore, we can add up angles E, F and G, set the sum equal to 180, and solve.

(8x - 16) + (x + 8) + (2x - 10) = 180

11x - 18 = 180

11x = 198

x = 18

Hope this helps!! :)

Answer:

Sorry i don't know but i need these points *Lol* i am honest

Step-by-step explanation:

Answer:

yeah f(x) = 2

Step-by-step explanation:

because there is no x and f(x) is on positive 2

Answer:

[tex]216[/tex]

Step-by-step explanation:

Remember that [tex]a^{b}=a*a*a*a*... b~~times[/tex].

So, [tex]6^3=6*6*6=(6*6)*6=36*6=\boxed{216}[/tex]

Answer:

284 scratched cups

Step-by-step explanation:

it's in the picture

Answer:

Student A: y=3+2x

Student B: y=5+1x

Answer: gas left after 4 hours :8

Gas left after t hours: 13-1.25t

Step-by-step explanation:

The gas left after 4 hours will be 8 gallons and expression for the gas left after t hours will be 13 - 1.25 t.

It is given that Ryan has 13 gallons of gas in his car and car uses 1.25 gallons of gas per hour.

We have to find out the amount of gas left after 4 hours and expression for the gas left after t hours.

What do you mean by algebraic expressions ?

The algebraic expressions are those which are made up of variables, constants and algebraic operations i.e., addition, subtraction, etc.

As per the question ;

Ryan has 13 gallons of gas in his car.

The gas used per hour = 1.25 gallons

The gas used by car in 4 hours will be ;

= 1.25 × 4

= 5 gallons

So ,

The gas left after 4 hours will be equal to ;

= 13 - 5

= 8 gallons

Also ;

The gas left after t hours can be represented by equation ;

= 13 - 1.25 t

Thus , the gas left after 4 hours will be 8 gallons and expression for the gas left after t hours will be 13 - 1.25 t.

To learn more about algebraic expressions click here ;

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The value of the numerical expression {[(30 − 60) ÷ (−30)]² − 15} ÷ (−7) will be 2.

When the relevant factors and natural laws of a mathematical model are given values, the outcome of the calculation it describes is the expression's outcome.

The expression is given below.

⇒ {[(30 − 60) ÷ (−30)]² − 15} ÷ (−7)

Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction are all part of the PEMDAS formula. To answer the problem properly and accurately, this rule must be followed.

⇒ {[(30 − 60) ÷ (−30)]² − 15} ÷ (−7)

⇒ {[(−30) ÷ (−30)]² − 15} ÷ (−7)

⇒ {[1]² − 15} ÷ (−7)

⇒ {1 − 15} ÷ (−7)

⇒ (−14) ÷ (−7)

⇒ 2

The value of the numerical expression {[(30 − 60) ÷ (−30)]² − 15} ÷ (−7) will be 2.

More about the value of the expression link is given below.

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Answer: 14

Step-by-step explanation:

you would write 2/3 X 21/1 and you would multiply 21 X 2 which is 42 divide that by 3 and you get 14

Answer: C

Step-by-step explanation: The surface of the lake.

Answer: -14.5

What I did was Subtract 3.5 from -11.

When you add them together, you get 14.5, but 14.5 isn't correct, as that's a very large number compared to -11.

Answer:

-14.5

Step-by-step explanation:

-11 - 3.5

Because 11 is already negative, when you subtract a number from a negative, think of -11 becoming "smaller" (smaller being -14, or -25).

When doing -11 - 3.5, think if it as adding 11 and 3.5 together !

When you add them together, you get 14.5, but 14.5 isn't correct, as that's a very large number compared to -11.

You add a negative sign to said -14.5, and that's your answer !

Subtracting from a negative is confusing, so I taught myself to think of it as adding the numbers as if they were positive and adding a negative sign !

(x - 4)/(x + 4)

Step-by-step explanation:

[tex]\begin{aligned}\tt\frac{x^2-16}{x^2+8x+16}&=\tt\frac{x^2-4^2}{\left(x+4\right)^2}\\&=\tt\frac{\left(x+4\right)\left(x-4\right)}{\left(x+4\right)^2}\\&=\tt\frac{x-4}{x+4}\end{aligned}[/tex]

Note :

[tex]▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ [/tex]

As we know that :

so, over here

plugging the value of i² as -1

Answer:

This cinder block has gravitational potential energy.

This cinder block has 15 484 joules of potential energy

Step-by-step explanation:

PE = mass*gravity*height and g= 9.8 m/s^2

PE = 79 * 9.8 * 20

PE = 15 484

Step-by-step explanation:

[tex]{ \huge{ \{}}{ \rm{ [(30 - 60) \div ( - 30)] {}^{2} - 15{ \huge{ \}}} \div ( - 7) }} \\ \\ \dashrightarrow \: { \huge{ \{}}{ \rm{[( - 30) \div ( - 30)] {}^{2}{ \huge{ \}}} \div ( - 7) }} \\ \\ \dashrightarrow \: { \huge{ \{}}{ \rm{[1] {}^{2} { \huge{ \}}} \div ( - 7)}} \\ \\ \dashrightarrow \: { \rm{1 \div ( - 7)}} \\ \\ { \boxed{ \boxed{ \rm{ \: - \frac{1}{7} \: \: }}}}[/tex]

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Answer:

x+5 > 4

Step-by-step explanation:

x+5 > 4 can be changed to

 -5 .   -5

x>-1

that is what is shown

Answer:

[tex]2) \: \: \frac{11}{2} [/tex]

Step-by-step explanation:

[tex] \frac{4}{5} + \frac{18}{20} \\ \\ \frac{4}{5 \times 4} + \frac{18}{20} \\ \\ \frac{4}{20} + \frac{18}{20} \\ \\ \frac{4 + 18}{20} \\ \\ \frac{22}{20} \\ \\ \frac{11}{2} [/tex]

Answer:

A 33

Step-by-step explanation:

135 - 3 = 132 photos for other pages

132/4 = 33 pages