For the line that passes through Y(3,0), parallel to DJ with D(-3,1) and J(3,3), complete the following: Find the slope. Write an equation in point-slope form. Graph the line.Slope:Point-slope form:

For The Line That Passes Through Y(3,0), Parallel To DJ With D(-3,1) And J(3,3), Complete The Following:

Answers

Answer 1

I am going to graph the situation on an external graphing utility and show you the answer, it will take a

minute, stay with me.

[tex]m\text{ = }\frac{rise\text{ }}{\text{run}}=\frac{change\text{ in y}}{\text{change in x}}=\frac{3}{1}=3[/tex][tex]y\text{ = mx+b}\rightarrow\text{ b =-1}[/tex]

So the equation of the line is.

[tex]y\text{ =3x -1}[/tex][tex]y\text{ -1 = m(3-0)}[/tex]

For The Line That Passes Through Y(3,0), Parallel To DJ With D(-3,1) And J(3,3), Complete The Following:

Related Questions

A. Marvin worked 4 hours a day plus an additional 5-hour day for a total of 29 hours.B. Marvin worked 9 hours a day for a total of 29 hoursC. Marvin worked 4 hours one day plus an additional 5 hours for a total of 29 hours.D. Marvin worked 4 days plus 5 hours for a total of 29 hours.

Answers

[tex]\begin{gathered} \text{Option A will be correct.} \\ 4\text{ hours per day+ }5\text{ hours =29 hours} \end{gathered}[/tex]

The slope of the line containing the points (-2, 3) and (-3, 1) is

Answers

Hey :)

[tex]\star\sim\star\sim\star\sim\star\sim\star\sim[/tex]

Apply the little slope equation. By doing that successfully, we should get our correct slope.

[tex]\large\boldsymbol{\frac{y2-y1}{x2-x1}}[/tex]

[tex]\large\boldsymbol{\frac{1-3}{-3-(-2)}}[/tex]

[tex]\large\boldsymbol{\frac{-2}{-3+2}}[/tex]

[tex]\large\boldsymbol{\frac{-2}{-1}}[/tex]

[tex]\large\boldsymbol{-2}}[/tex]

So, the calculations showed that the slope is -2. I hope i could provide a good explanation and a correct answer to you. Thank you for taking the time to read my answer.

here for further service,

silennia

[tex]\star\sim\star\sim\star\sim\star\sim\star\sim[/tex]

Given a function described by the table below, what is y when x is 5?XY264859612

Answers

Given a function described by the table

We will find the value of (y) when x = 5

As shown in the table

When x = 5, y = 9

so, the answer will be y = 9

im taking geometry A and i have a hard time with the keeping the properties straight in mathematical reasoning. the question im struggling with at the moment is in the picture here:thank you for your time

Answers

The given proposition is

[tex]m\angle UJN=m\angle EJN\rightarrow m\angle UJN+m\angle YJN=m\angle EJN+m\angle YJN[/tex]

As you can observe, it was added angle YJN to the equation on both sides. The property that allows us to do that it's call addition property of equalities.

Therefore, the right answer is "addition property".

Lisa's rectangular living room is 15 feet wide. If the length is 7 feet less than twice the width, what is the area of her living room?

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345ft²

1) Since we have the following data then we can write it down:

width: 15 ft

length: 2w-7

2) And we can write out the following equation regarding that the area of a rectangle is given by:

[tex]S=l\cdot w[/tex]

We can plug into that the given data:

[tex]\begin{gathered} S=15(2(15)-7)) \\ S=15(30-7) \\ S=15\cdot23 \\ S=345 \end{gathered}[/tex]

Notice we have used the FOIL acronym. And the PEMDAS order of operations prioritizing the inner parentheses.

3) So we can state that the area of her living room is 345ft²

Determine the frequency of each class and the table shown

Answers

Given:

The dataset and table with class.

Required:

Determine the frequency of each class.

Explanation:

Answer:

Answered the question.

A ball is thrown from an initial height of 4 feet with an initial upward velocity of 23 ft/s. The ball's height h (in feet) after 1 seconds is given by the following.h=4+231-167Find all values of 1 for which the ball's height is 12 feet.Round your answer(s) to the nearest hundredth.(If there is more than one answer, use the "or" button.)Please just provide the answer my last tutor lost connection abruptly.

Answers

Answer

t = 0.59 seconds or t = 0.85 seconds

Step-by-step explanation:

[tex]\begin{gathered} Given\text{ the following equation} \\ h=4+23t-16t^2\text{ } \\ h\text{ = 12 f}eet \\ 12=4+23t-16t^2 \\ \text{Collect the like terms} \\ 12-4=23t-16t^2 \\ 8=23t-16t^2 \\ 23t-16t^2\text{ = 8} \\ -16t^2\text{ + 23t - 8 = 0} \\ \text{ Using the general formula} \\ t\text{ }=\text{ }\frac{-b\pm\sqrt[]{b^2\text{ - 4ac}}}{2a} \\ \text{let a = -16, b = 23, c = -8} \\ t\text{ = }\frac{-23\pm\sqrt[]{(23)^2\text{ - 4}\cdot\text{ }}(-16)\text{ x (-8)}}{2(-16)} \\ t\text{ = }\frac{-23\pm\sqrt[]{529\text{ - 512}}}{-32} \\ t\text{ = }\frac{-23\pm\sqrt[]{17}}{-32} \\ \text{t = -23+}\frac{\sqrt[]{17}}{-32}\text{ or -23-}\frac{\sqrt[]{17}}{-32} \\ t\text{ = -23 }+\text{ 4.12/-32 or t = }\frac{-23\text{ - 4.12}}{-32} \\ t\text{ = }0.59\text{ seconds or t =0.85 seconds} \end{gathered}[/tex]

Therefore, t = 0.59 seconds or t = 0.85 seconds

A box has 14 candies in it: 3 are taffy, 7 are butterscotch, and 4 are caramel. Juan wants to select two candies to eat for dessert. The first candy will be selectedat random, and then the second candy will be selected at random from the remaining candies. What is the probability that the two candies selected are taffy?Do not round your intermediate computations. Round your final answer to three decimal places.

Answers

Okay, here we have this:

Considering the provided information we are going to calculate what is the probability that the two candies selected are taffy. So, for this, first we are going to calculate the probability that the first is taffy, and then the probability that the second is taffy. Finally we will multiply these two probabilities to find the total probability.

Remember that the simple probability of an event is equal to favorable events, over possible events.

First is taffy:

At the beginning there are 14 sweets, and 3 are taffy, so there are 3 favorable events and 14 possible, then:

First is taffy=3/14

Second is taffy:

Now, in the bag there are 13 sweets left, and of those 2 are taffy, so now there are 2 favorable events out of 13 possible:

Second is taffy=2/13

The first and second are taffy:

First is taffy*Second is taffy=3/14*2/13

First is taffy*Second is taffy=3/91

First is taffy*Second is taffy=0.033

First is taffy*Second is taffy=3.3%

Finally we obtain that the probability that the two candies selected are taffy is aproximately 0.033 or 3.3%.

Which of the following statements are true regarding functions? Check all that apply. A. The horizontal line test may be used to determine whether a function is one-to-one. B. The vertical line test may be used to determine whether a relatio is a function. C. A sequence is a function whose domain is the set of rational numbers. PREVIOUS

Answers

Statement A is true.

In the next example, we can see a function that is not one-to-one with the help of the horizontal line test:

Statement B is true.

In the next example, we can see a relationship that is not a function because it doesn't pass the vertical line test

Statement C is false.

A sequence is a function whose domain is the set of natural numbers

Let f(x)=3x-2. What is f^-1 (x) ?

Answers

Given the function:

f(x) = 3x - 2

Let's find the inverse of the function f⁻¹(x).

To find the inverse of the function, apply the following steps:

• Step 1.

Rewrite y for f(x)

[tex]y=3x-2[/tex]

• Step 2.

Interchange the x and y variables:

[tex]x=3y-2[/tex]

• Step 3.

Solve for y.

Add 2 to both sides:

[tex]\begin{gathered} x+2=3y-2+2 \\ \\ x+2=3y \end{gathered}[/tex]

• Step 4.

Divide all terms by 3:

[tex]undefined[/tex]

help ! it may or may not have multiple answers

Answers

From the given problem, there are 3 computer labs and each lab has "s" computer stations.

So the total number of computers is :

[tex]3\times s=3s[/tex]

Mr. Baxter is ordering a new keyboard and a mouse for each computer, since the cost of a keyboard is $13.50 and the cost of a mouse is $6.50.

Each computer has 1 keyboard and 1 mouse, so the total cost needed for 1 computer is :

[tex]\$13.50+\$6.50[/tex]

Since you now have the cost for 1 computer, multiply this to the total number of computers which is 3s to get the total cost needed by Mr. Brax :

[tex]3s\times(13.50+6.50)[/tex]

Using distributive property :

[tex]a(b+c)=(ab+ac)[/tex]

Distribute s inside the parenthesis :

[tex]3(13.50s+6.50s)[/tex]

One answer is 1st Option 3(13.50s + 6.50s)

Simplifying the expression further :

[tex]\begin{gathered} 3(13.50s+6.50s) \\ =3(20.00s) \end{gathered}[/tex]

Another answer is 4th Option 3(20.00s)

I need some help with this (and no this is not a test)

Answers

You have the following expression:

[tex]a_n=3+2(a_{n-1})^{2}[/tex]

consider a1 = 6.

In order to determine the value of a2, consider that if an = a2, then an-1 = a1. Replace these values into the previous sequence formula:

[tex]\begin{gathered} a_2=3+2(a_1)^{2}= \\ 3+2\mleft(6\mright)^2= \\ 3+2(36)= \\ 3+72= \\ 75 \end{gathered}[/tex]

Hence, a2 is equal to 75

According to the Florida Agency for Workforce, the monthly average number of unemployment claims in a certain county is given by () = 22.16^2 − 238.5 + 2005, where t is the number of years after 1990. a) During what years did the number of claims decrease? b) Find the relative extrema and interpret it.

Answers

SOLUTION

(a) Now from the question, we want to find during what years the number of claims decrease. Let us make the graph of the function to help us answer this

[tex]N(t)=22.16^2-238.5t+2005[/tex]

We have

From the graph above, we can see that the function decreased at between x = 0 to x = 5.381

Hence the number of claims decreased between 1990 to 1995, that is 1990, 1991, 1992, 1993, 1994 and 1995

Note that 1990 was taken as zero

(b) The relative extrema from the graph is at 5.381, which represents 1995.

Hence the interpretation is that it is at 1995 that the minimum number of claims is approximately 1363.

Note that 1363 is approximately the y-value 1363.278

geometric series in context

Answers

Solution

For this case we can model the problem with a geometric series given by:

[tex]a_n=600(1+0.2)^{n-1}[/tex]

And we can find the value for n=23 and we got:

[tex]a_{23}=600(1.2)^{23-1}=33123.69[/tex]

And rounded to the neares whole number we got 33124

and using the sum formula we got:

[tex]S_{23}=\frac{600(1.2^{23}-1)}{1.2-1}=195742[/tex]

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Z2
Find the midpoint m of z₁ = (9+7i) and Z₂ = (-7+7₂).
Express your answer in rectangular form.
m=
Re

Answers

The midpoint m of z₁ = (9+7i) and Z₂ = (-7+7i) is 1 + 7i .

Given complex numbers:

[tex]z_{1}[/tex] = (9 + 7i) and [tex]z_{2}[/tex] = (-7 + 7i)

compare these numbers with a1+ib1 and a2+ib2, we get

a1 = 9, a2 = -7 , b1 = 7 and b2 = 7.

Mid point of complex numbers = a1 + a2 /2 + (b1 + b2 /2)i

= (9 + (-7)/2 + (7 + 7 /2)i

= 2/2 + 14/2 i

Mid point m = 1 + 7i

Therefore the midpoint m of z₁ = (9+7i) and Z₂ = (-7+7i) is 1 + 7i

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Identify the constant of variation. 8y-7x=0

Answers

A direct variation between two variables "x" and "y" is given by the following formula:

y = kx

We can rewrite the given expression 8y-7x=0 to get an equation of the form y = kx like this:

8y - 7x = 0

8y - 7x + 7x = 0 + 7x

8y = 7x

8y/8 = 7x/8

y = 7/8x

The number that is being multiplied by x should be the constant of variation k, then in this case, the constant of variation equals 7/8

I will provide another picture with the questions to this problemBefore beginning: please note that this is lengthy, pre calculus practice problem

Answers

[tex]\begin{gathered} \text{For }Albert \\ For\text{ \$1,000} \\ t=10years=120\text{ months} \\ i=1.2\text{\%=0.012} \\ C=1,000(1+0.012)^{120} \\ C=1,000(1.012)^{120} \\ C=\text{\$}4,184.67 \\ \text{For \$}500 \\ \text{lost 2\%=0.02 over 10 years, hence} \\ C1=500(1-0.02) \\ C1=500(0.98) \\ C1=\text{ \$}490 \\ \text{For \$}500 \\ i=0.8\text{ \%=0.008} \\ t=10 \\ C2=500(1+0.008)^{10} \\ C2=500(1.008)^{10} \\ C2=\text{ \$}541.47 \\ \text{Total}=\text{\$}4,184.67+\text{ \$}490+\text{ \$}541.47 \\ \text{Total}=\text{ \$5,216.14} \\ After\text{ 10 year Albert has \$5,216.14} \\ \text{For Marie} \\ For\text{ \$1,500} \\ Quaterly \\ 1\text{ year has }3\text{ quaternions, hence in 10 years are 30 quaternions, t=30} \\ i=1.4\text{ \% monthly, hence } \\ \frac{1.4\text{ \% }}{3}=0.467\text{ \%=0.00467} \\ C=1,500(1+0.00467)^{30} \\ C=1,500(1.00467)^{30} \\ C=\text{ \$}1,725.02 \\ \text{For \$500} \\ C2=500(1+0.04) \\ C2=500(1.04) \\ C2=\text{ \$}520 \\ \text{Total}=\text{ \$}1,725.02+\text{ \$}520 \\ \text{Total}=\text{ \$}2,245.02 \\ After\text{ 10 year Marie has \$2,245.02} \\ \text{For }Hans \\ t=10 \\ i=0.9\text{ \%=0.009} \\ C=2,000(1+0.009)^{10} \\ C=2,000(1.009)^{10} \\ C=\text{\$}2,187.47 \\ After\text{ 10 year Hans has \$}2,187.47 \\ \text{For }Max \\ For\text{ 1,000} \\ t=10 \\ i=0.5\text{ \%=0.005} \\ C=1,000e^{(-0.005)(10)} \\ C=\text{\$}951.23 \\ \text{For 1,000} \\ i=1.8\text{ \%=0.018} \\ t=20 \\ C1=1,000(1+0.018)^{20} \\ C1=1,000(1.018)^{20} \\ C1=\text{ \$1,428.75} \\ \text{Total =\$}951.23+\text{ \$1,428.75} \\ \text{Total}=\text{ \$2,379.98} \\ After\text{ 10 year Max has \$2,379.98} \\ \\ At\text{ the end of the competition is \$10,000 richer than his siblings} \end{gathered}[/tex]

Lne segment AC and BD are parallel, what are the new endpoints of the line segments AC and BD if the parallel lines are reflected across the y-axis?

Answers

Given a point P = (x, y) a reflection P' alongside the y axis of that point follows the rule:

[tex]P=(x,y)\Rightarrow P^{\prime}=(-x,y)[/tex]

We need to multiply the x coordinates of the points by (-1)

The cordinates of the points in the problem are:

A = (2, 5)

B = (2, 4)

C = (-5, 1)

D = (-5, 0)

Then the endpoints of the reflection over the y axis are:

A' = (-2, 5)

B' = (-2, 4)

C' = (5, 1)

D' = (5, 0)

Which is the second option.

I need to find the radius and the diameter but I don't understand.

Answers

ANSWER

Radius = 3 yd

Diameter = 6 yd

EXPLANATION

We are given the circle in the figure.

The radius of a circle is defined as the distance between the centre of a circle and its circumference.

Therefore, from the circle given, the radius is 3 yards

The diameter of a circle is defined as the total distance (through the centre) from one end of a circle to another.

It is twice the radius. Therefore, the diameter of the given circle is:

D = 3 * 2

D = 6 yards

The diameter is 6 yards.

Not sure on how to do this. Would really like some help.

Answers

Given:

[tex]\cos60^{\circ}[/tex]

To find:

The value

Explanation:

We know that,

[tex]\cos\theta=\sin(90-\theta)[/tex]

So, we write,

[tex]\begin{gathered} \cos60^{\circ}=\sin(90-60) \\ =\sin30^{\circ} \\ =\frac{1}{2} \end{gathered}[/tex]

Final answer:

[tex]\cos60^{\circ}=\frac{1}{2}[/tex]

I need help doing this it’s the homework but I need to understand it for the test

Answers

By similar triangle, we have:

[tex]\begin{gathered} Let\text{ the unknown measurement be x} \\ \text{Thus, we have:} \\ \frac{14}{x}=\frac{8}{15} \\ \text{cross}-\text{multiply} \\ 8x=210 \\ x=\frac{210}{8} \\ x=26.25\text{ f}eet \end{gathered}[/tex]

Hence, the unknown measurement of the plan is 26.25 feet

write each of the following numbers as a power of the number 2

Answers

Answer

The power on 2 is either -3.5 in decimal form or (-7/2) in fraction form.

Explanation

To do this, we have to first note that

[tex]\begin{gathered} \sqrt[]{2}=2^{\frac{1}{2}} \\ \text{And} \\ 16=2^4 \end{gathered}[/tex]

So, we can then simplify the given expression

[tex]\begin{gathered} \frac{\sqrt[]{2}}{16}=\frac{2^{\frac{1}{2}}}{2^4}=2^{\frac{1}{2}-4} \\ =2^{0.5-4} \\ =2^{-3.5} \\ OR \\ =2^{\frac{-7}{2}} \end{gathered}[/tex]

Hope this Helps!!!

Find the sum of the first nine terms of the geometric series 1 – 3 + 9 - 27+....

Answers

Hello there. To solve this question, we'll have to remember some properties about geometric series.

Given that we want the sum of

[tex]1-3+9-27...[/tex]

First, we find the general term of this series:

Notice they are all powers of 3, namely

[tex]\begin{gathered} 1=3^0 \\ 3=3^1 \\ 9=3^2 \\ 27=3^3 \\ \vdots \end{gathered}[/tex]

But this is an alternating series, hence the general term is given by:

[tex]a_n=\left(-3\right)^{n-1}[/tex]

Since we just want the sum of the first 9 terms of this geometric series, we apply the formula:

[tex]S_n=\frac{a_1\cdot\left(1-q^n\right?}{1-q}[/tex]

Where q is the ratio between two consecutive terms of the series.

We find q as follows:

[tex]q=\frac{a_2}{a_1}=\frac{\left(-3\right)^{2-1}}{\left(-3\right)^{1-1}}=\frac{-3}{1}=-3[/tex]

Then we plug n = 9 in the formula, such that:

[tex]S_9=\frac{1\cdot\left(1-\left(-3\right)^9\right?}{1-\left(-3\right)}=\frac{1-\left(-19683\right)}{1+3}=\frac{19684}{4}[/tex]

Simplify the fraction by a factor of 4

[tex]S_9=4921[/tex]

This is the sum of the nine first terms of this geometric series and it is the answer contained in the second option.

The given point (-3,-4) is on the terminal side of an angle in standard position. How do you determine the exact value of the six trig functions of the angle?

Answers

In this problem -3 will be the adyacent side, -4 will be the opposite side and wwe can calculate the hypotenuse so:

[tex]\begin{gathered} h^{}=\sqrt[]{(-3)^2+(-4)^2} \\ h=\sqrt[]{9+16} \\ h=\sqrt[]{25} \\ h=5 \end{gathered}[/tex]

So the trigonometric function will be:

[tex]\begin{gathered} \sin (\theta)=-\frac{4}{5} \\ \cos (\theta)=-\frac{3}{5} \\ \tan (\theta)=\frac{4}{3} \\ \csc (\theta)=-\frac{5}{4} \\ \sec (\theta)=-\frac{5}{3} \\ \cot (\theta)=\frac{3}{4} \end{gathered}[/tex]

Rami practices his saxophone for 5/6 hour on 4 days each week.
How many hours does Rami practice his saxophone each week?

[] 2/[] Hr

Answers

Answer:

you take 5/6 and multiply it by 4/1.

which gives you 20/6

then reduce it by dividing the top number by the bottom number

 which gives you 3 with a remainder of 2

you then place the remainder over the

This tells you he practicedfor 3 2/6

Step-by-step explanation:

what is an identityA) an identity is a false equation relating to a mathematical expression to a real numberB) an identity is a true equation relating to a mathematical expression to a real numberC) an identity is a true equation relating one mathematical expression to another expressionD) an identity is a false equation relating to one mathematical expression to another expression

Answers

The right answer is C

Gloria's teacher asks her to draw a triangle with a 90° angle and a 42° angle.How many unique triangles can Gloria draw that meet her teacher's requirements?AOne unique triangle can be drawn because the third angle must measure 48º.BNo unique triangle can be drawn because the teacher only gave the measures of two angles.СInfinitely many unique triangles can be drawn because the side lengths of the triangles can be different sizes.DThere is not enough information to determine how many unique triangles can be drawn.

Answers

SOLUTION

Sum of angles in a triangle must be equal to 180°

So, since one of the angle measures 90° and the other is 42°, then

90 + 42 + y = 180°, where y is the third angle

So, 132 + y = 180

y = 180 - 132 = 48°.

Therefore, one unique triangle can be drawn because the third angle must measure 48º.

Option A is the correct answer.

Factor the following expression using the GCF.5dr - 40rr(5 dr - 40)5 r( d - 8)r(5 d - 40)5( dr - 8 r)

Answers

[tex]5dr-40r[/tex]

The greatest common factor (GCF) is: 5r

You multiply 5r by d to get the first term and multiply 5r by -8 to get the second term, then the factors are:

[tex]5r(d-8)[/tex]Answer: 5r(d-8)

create an original function that has at least one asymptote and possibly a removable discontinuity list these features of your function: asymptote(s) (vertical horizontal slant) removable discontinuity(ies) x intercept(s) y intercept and end behavior provide any other details that would enable another student to graph and determine the equation for your function do not state your function

Answers

We have to create a function that has at least one asymptote and one removable discontinuity (a "hole").

We then have to list the type of feature.

We can start with a function like y = 1/x. This function will have a vertical asymptote at x = 0 and a horizontal asymptote at y = 0.

We can translate it one unit up and one unit to the right and write the equation as:

[tex]y=\frac{1}{x-1}+1=\frac{1}{x-1}+\frac{x-1}{x-1}=\frac{x}{x-1}[/tex]

Then, the asymptotes will be x = 1 and y = 1. We have at least one asymptote for this function.

We can now add a removable discontinuity. This type of discontinuity is one that is present in the original equation but, when factorizing numerator and denominator, it can be cancelled. This happens when both the numerator and denominator have a common root: the rational function can be simplified, but the root is still present in the original expression.

We than can add a removable discontinuity to the expression by multiplying both the numerator and denominator by a common factor, like (x-2). This will add a removable discontinuity at x = 2.

We can do it as:

[tex]y=\frac{x(x-2)}{(x-1)(x-2)}=\frac{x^2-2x}{x^2-3x+2}[/tex]

This will have the same shape as y =x/(x-1) but with a hole at x = 2, as the function can not take a value that makes the denominator become 0, so it is not defined for x = 2.

Finally, we can find the x and y intercepts.

The y-intercepts happens when x = 0, so we can calculate it as:

[tex]\begin{gathered} f(x)=\frac{x^2-2x}{x^2-3x+2} \\ f(0)=\frac{0^2-2\cdot0}{0^2-3\cdot0+2}=\frac{0}{2}=0 \end{gathered}[/tex]

The y-intercept is y = 0, with the function passing through the point (0,0).

As the x-intercept is the value of x when y = 0, we already know that the x-intercept is x = 0, as the function pass through (0,0).

Then, we can list the features as:

Asymptotes: Vertical asymptote at x = 1 and horizontal asymptote at y = 1.

Removable discontinuity: x = 2.

y-intercept: y = 0.

End behaviour: the function tends to y = 1 when x approaches infinity or minus infinity.

With that information, the function can be graphed.

Professor Ahmad Shaoki please help me! The length of each side of a square is extended 5 in. The area of the resulting square is 64 in,2 Find the length of a side of the

original square. Help me! From: Jessie

Answers

The length of the original square must be equal to 3 inches.

Length of the Original Square

To find the length of the original square, we have to first assume the unknown length is equal x and then use formula of area of a square to determine it's length.

Since the new length is stretched by 5in, the new length would be.

[tex]l = (x + 5)in[/tex]

The area of a square is given as

[tex]A = l^2[/tex]

But the area is equal 64 squared inches; let's use substitute the value of l into the equation above.

[tex]A = l^2\\l = x + 5\\A = 64\\64 = (x+5)^2\\64 = x^2 + 10x + 25\\x^2 + 10x - 39 = 0\\[/tex]

Solving the quadratic equation above;

[tex]x^2 + 10x - 39 = 0\\x = 3 or x = -13[/tex]

Taking the positive root only, x = 3.

The side length of the original square is equal to 3 inches.

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The following diagram of a pendulum shows the path it takes as it swings back and forth.As the pendulum moves from point 2 to point 3, what happens to its mechanical energy? rtf, inc. common stock pays an annual dividend that increases by 4.4% annually. the expected rate of return on this stock is 8.2%. what is the dividend yield? ten B 15 cm 20 cm C when is a currency said to be externally convertible? multiple choice when only nonresidents can convert it into a foreign currency without any limitations. when both residents and nonresidents can purchase unlimited amounts of a foreign currency. when neither residents nor nonresidents are allowed to convert it into a foreign currency. when only residents can convert it into a foreign currency. Based on the experimental probability, predict the number of times that you will roll a 5 if you roll the number cube 300 timesExperiment result on previews question: The number 5 was rolled 9 times out of 20 on a previous question A man is pulling on a rope with a force of 44 Ndirected at an angle of 63to the horizontal.What is the x-component of this force?Answer in units of N. when rocks are broken down and worn away, they form loose materials of all sizes called blank . multiple choice question. magma lithified rock sediment lava I need help on doing this finding the slope of a line The midpoint of AB is M(0, -7). If the coordinates of A are (-2,-6), what arethe coordinates of B?Answer:Submit AnswerPASSA The sociological imagination emphasizes the connection between individual differences and commonalities. True or false? A 4 coulombs charged particle experiences an electric force of 200 N when placed at point P in an electric field. The magnitude of the electric field at point P is :a) 5 N/Cb) 800 N/Cc) 0.02 N/Cd) 50 N/C Please help, i really need help NEEED HELP PLSSSS . Find x in triangles Geometry. Read the passage from "The Goatherd and the Wild Goats."A goatherd, driving his flock from their pasture at eventide, found some Wild Goats mingled among them, and shut them up together with his own for the night.The next day it snowed very hard, so that he could not take the herd to their usual feeding places, but was obliged to keep them in the fold.He gave his own goats just sufficient food to keep them alive, but fed the strangers more abundantly in the hope of enticing them to stay with him and of making them his own.When the thaw set in, he led them all out to feed, and the Wild Goats scampered away as fast as they could to the mountains.The Goatherd scolded them for their ingratitude in leaving him, when during the storm he had taken more care of them than of his own herd.One of them, turning about, said to him: "That is the very reason why we are so cautious; for if you yesterday treated us better than the Goats you have had so long, it is plain also that if others came after us, you would in the same manner prefer them to ourselves.Which statement accurately explains the theme most exemplified in this passage?Good leaders treat everyone the same.Kindness inspires others to be kind.Strangers cannot always be trusted.Ingratitude leads to unhappiness. 12/13+-1/13 equals what ? if a foreign trade policy of a country states that multinational companies can enter its market only by merging with a local business partner, this would represent which environmental force? a packet tracer exercise requires that you organize all cables using a structured cabling approach. what mode in packet tracer will allow you to accomplish this task? 13 nickels to 43 dimes in a reduced ratio form [tex] f(x) = 3x^{2} - 2x + 3[/tex]if (-3,n) is an element of the function what is the value of n? Describe a current events issue that involves oppression of a marginalized (historically oppressed) community