To determine the data that is within 2 population standard deviations of the mean, let's calculate the mean first.
To determine the mean, let's add all the data and divide the result by the total number of data.
[tex]28+65+114+74+68+75+70+69+64=627[/tex][tex]627\div9=69.66667[/tex]The mean is 69.66667.
Let's now calculate the standard deviation. Here are the steps:
1. Subtract the mean from each data, then square the result.
[tex]\begin{gathered} 28-69.66667=(-41.66667)^2=1,736.1114 \\ 65-69.66667=(-4.66667)^2=21.7778 \end{gathered}[/tex][tex]\begin{gathered} 114-69.66667=(44.33333)^2=1,965.4441 \\ 74-69.66667=(4.33333)^2=18.7777 \end{gathered}[/tex][tex]\begin{gathered} 68-69.66667=(-1.66667)^2=2.7778 \\ 75-69.66667=(5.33333)^2=28.4444 \end{gathered}[/tex][tex]\begin{gathered} 70-69.66667=(0.33333)^2=0.1111 \\ 69-69.66667=(-0.66667)^2=0.4444 \\ 64-69.66667=(-5.66667)^2=32.1111 \end{gathered}[/tex]2. Add the results in step 1.
[tex]1,736.1114+21.7778+1,965.4441+18.7777+2.7778=3,744.8888[/tex][tex]28.4444+0.1111+0.4444+32.1111=61.111[/tex][tex]3,744.8888+61.111=3,805.9998[/tex]The sum is 3, 805.9998.
3. Divide the sum by the total number of data.
[tex]3,805.9998\div9=422.8889[/tex]4. Square root the result in step 3.
[tex]\sqrt{422.8889}\approx20.56[/tex]The standard deviation is approximately 20.56.
So, the data that are within 2 population standard deviations of the mean are between:
[tex]\begin{gathered} 69.67-(2)(20.56)=28.55\approx29 \\ 69.67+(2)(20.56)=110.79\approx111 \end{gathered}[/tex]The data that are within 2 population standard deviations of the mean are between 29 and 111. Based on the given data, the data that are between 29 and 111 are the following: 64, 65, 68, 69, 70, 74, and 75. There are 7 data that are within 2 population standard deviations of the mean.
Classify each Polynomial by degree and number of terms.1. X^3 + 5x 2. X^2 - 2x - 1 3. 5x^4 4. 6x^5 - 3x^2 + 7x + 9 5. -11x - 5 6. 4x^2 + 10 7. 128. 9x^3 - x^2 + 6x - 1]9. -3x^5 + 6x^4 v- 8THESE ARE THE OPTIONS Degree Name using degree 0 Constant 1 Linear 2 quadratic 3 Cubic 4 quartic 5 quintic 6 6th degreeTHESE ARE ALSO THE OTHER OPTIONSTerms NAME USING # OF TERMS1, monomial 2 , binomial3 trinomial4 or more polynomial
For the point P (-12,22) and Q (-7, 27), find the distance d(P,Q) and the coordinates of the midpoint M of the segment PQ. What is the distance?
The distance d(P,Q) is equal to 7.1 units and the coordinates of the midpoint M of the segment PQ are (-9.5, 24.5).
How to determine the distance between points P and Q?Mathematically, the distance between two (2) points that are located on a coordinate plane can be calculated by using this formula:
Distance = √[(x₂ - x₁)² + (y₂ - y₁)²]
Substituting the given parameters into the formula, we have;
Distance, d(P, Q) = √[(-7 + 12)² + (27 - 22)²]
Distance, d(P, Q) = √[5² + 5²]
Distance, d(P, Q) = √[25 + 25]
Distance, d(P, Q) = √50
Distance, d(P, Q) = 7.1 units.
Midpoint on x-coordinate is given by:
xm = (x₁ + x₂)/2
xm = (-7 - 12)/2
xm = -19/2
xm = -9.5
Midpoint on y-coordinate is given by:
ym = (y₁ + y₂)/2
ym = (27 + 22)/2
ym = 49/2
ym = 24.5
Therefore, the coordinates of the midpoint M are equal to (-9.5, 24.5).
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random variables, probability distributions and expected value Alyssa likes to play roulette, but she doesn't like the low probability of betting on a single number. Therefore, she bets on a block of 4 numbers, increasing her probability of winning to 38. She generally places a $5 chip on her block of 4. If any other number comes up she loses her bet, but if one of her 4 numbers come up, she wins $40 (and gets to keep her bet!). What is the expected value for Alyssa playing roulette? Round to the nearest cent. Do not round until your final calculation.
We have to calculate the expected value for Alyssa playing roulette.
The expected value is calculated as the weighted sum of all the possible the outcomes, weighted by the probabilities of occurrence of this outcomes.
Then, we start by listing all the outcomes:
1) One of the numbers of the block comes up.
This will happen with a probability of 4 out of 38 (P=4/38). NOTE: The total numbers of the roulette are 38.
The net prize, that is excluding the $5 she bets, is $40.
2) None of the numbers of the block comes up.
That will happen with probability 34 out of 38 (P=34/38).
The net prize, as she will lose the $5 she bets, is -$5.
The expected value can be calculated as:
[tex]E=\sum ^2_{i=1}p_i\cdot X_i=\frac{4}{38}\cdot40+\frac{34}{38}\cdot(-5)=\frac{160}{38}-\frac{170}{38}=\frac{-10}{38}\approx-0.26[/tex]The expected value for Alyssa is -$0.26.
solve each system by substitution.y =-2x + 5y =-8x+17
To solve the equation system by substitution, since the equations are expressed in terms of y, you have to equal both expressions and calculate the value of x:
[tex]\begin{cases}y=-2x+5 \\ y=-8x+17\end{cases}[/tex][tex]\begin{gathered} y=y \\ -2x+5=-8x+17 \end{gathered}[/tex]To calculate the value of x, the first step is to pass the x-term to the left side of the equation by applying the opposite operation:
[tex]\begin{gathered} -2x+8x+5=-8x+8x+17 \\ 6x+5=17 \end{gathered}[/tex]Next, pass 5 to the right side of the equation:
[tex]\begin{gathered} 6x+5-5=17-5 \\ 6x=12 \end{gathered}[/tex]Finally, divide both sides by 6 to reach the value of x
[tex]\begin{gathered} \frac{6x}{6}=\frac{12}{6} \\ x=2 \end{gathered}[/tex]Now that we have determined the value of x, replace it in either one of the original equations to determine the value of y:
[tex]\begin{gathered} y=-2x+5 \\ y=-2\cdot2+5 \\ y=-4+5 \\ y=1 \end{gathered}[/tex]The solution for this equation system is (2,1)
Can you please help me out with a question
right. the lateral area of a hemisfere is the curved area, wich is half the area of a complete sphere
area of a sphere:
4πr²
So, half the area is 1/2(4πr²)= 2πr²
Now, the total surface is the lateral area plus the area of the base. the base is a circle, so the area is equal to πr²
And the volume of a hemisfere is equal to half the volume of a sphere:
[tex](\frac{4}{3}\pi r^3)\cdot\frac{1}{2}\text{ =}\frac{2}{3}\pi r^3[/tex]So, the anwsers are:
[tex]2\pi r^{2}\text{ = }2\pi(24ft)^{2}\text{ = 1152}\pi ft^2[/tex][tex]\pi r^{2}\text{ = }\pi(24ft)^2\text{ = 576}\pi ft^2[/tex][tex]\frac{2}{3}\pi r^3\text{ = }\frac{2}{3}\pi(24ft)^3\text{ = 9216}\pi ft^3[/tex]The answers are in order
2 ABC Company has a large piece of equipmentthat cost $85,600 when it was first purchased 6years ago. The current value of the equipment is$30,400. What is the average depreciation of theequipment per year?F. $ 5,800G. $ 9,200H. $15,200J. $27,600K. $42,800
The intial cost of the equipment is C, which is given as 85,600.
The present value is PV, which is given as 30,400.
This simply means the total depreciation over the last 6 years can be derived as;
Depreciation = C - PV
Depreciation = 85600 - 30400
Depreciation = 55200
However, the method of depreciation is not given/specified, and hence the question requires that you calculate the average depreciation per year. That is, the total depreciation would be evenly spread over the 6 year period (which assumes that the depreciation per year is the same figure)
Average depreciation = Total depreciation/6
Average Depreciation = 55200/6
Average Depreciation = 9200
The correct option is option G: $ 9,200
In the picture shown below, a cube with a side of 5 inches is placed directly on top of a larger cube which has a side of 18 inches. Then, another cube with a side of 3 inches is placed directly to the side of the lower cube. What is the surface area of this assembly? (drawing below is not to scale)
For this problem, we are given three cubes. Cube A is on top of cube B, the cube C is glued to the side of cube B. We need to calculate the surface area for the whole piece.
The surface area of a cube is given by the following:
[tex]A_{\text{surface}}=6\cdot l^2[/tex]Where "l" is the measurement of the length of the side on each cube.
To calculate the whole surface area, we need to calculate each cube individually then sum them. Let's start with cube A, since this cube is on top of Cube b, one of its faces shouldn't count for the surface area, therefore we have:
[tex]\begin{gathered} A_{\text{cubeA}}=5\cdot5^2=125\text{ square inches} \\ \end{gathered}[/tex]Now we need to calculate the surface area for cube C, which is very similar to cube A, as shown below:
[tex]A_{\text{cubeC}}=5\cdot3^2=45\text{ square inches}[/tex]Finally, we need to calculate the area for cube B, this one is different because we need to subtract one face from cube A and one for group C.
[tex]\begin{gathered} A_{\text{cubeB}}=6\cdot18^2-5^2-3^2 \\ A_{\text{cubeB}}=6\cdot324-25-9 \\ A_{\text{cubeB}}=1994-25-9=1910 \end{gathered}[/tex]The total area is the sum of all areas:
[tex]A=1910+45+125=2080[/tex]The total surface area is equal to 2080 square inches.
Evaluate the rational expression for the given x value. Express the answer as a fraction in simplest form.
Given the expression:
[tex]\frac{x-3}{2x+3}[/tex]We need to find the value of the expression when x = 7
So, we will substitute with x = 7 into the expression as follows:
[tex]\frac{7-3}{2\cdot7+3}=\frac{7-3}{14+3}=\frac{4}{17}[/tex]so, the answer will be 4/17
The area of a parallelogram is 22, and the lengths of its sides are 9.2 and 2.6. Determine, to the nearest tenth of a degree, the measure of the obtuse angle of the parallelogram.
The measure of obtuse angle of the parallelogram is 113.12° .
The Area of Parallelogram with sides a and b and the angle between them as x° is given by the formula .
Area of Parallelogram = a×b×Sin(x)°.
In the question ,
it is given that
the area of the parallelogram is = 22
length of one side of parallelogram = 9.2
length of other side of parallelogram = 2.6 .
Substituting the values in the Area formula , we get
22 = (9.2)×(2.6)×Sin(x)°
22 = 23.92×Sin(x)°
Sin(x)° = 22/23.92
Sin(x)° = 0.9197
x = 66.88°
Since this is an acute angle , we will subtract it from 180° to find the obtuse angle .
So , obtuse angle = 180-66.88 = 113.12°
Therefore , the measure of obtuse angle of the parallelogram is 113.12° .
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8. A certain virus infects one in every 700 people. A test used to detect the virus in a person is positive 90% of the time if the person has the virus and 10% of the time if the person does not have the virus. (a) Find the probability that a person has the virus given that they have tested positive. (b) Find the probability that a person does not have the virus given that they have tested negative.
Part a
Find the probability that a person has the virus given that they have tested positive
Probability in fraction form
p=(1/700)*(90/100)=90/70,000
simplify
P=9/7,000Part b
Find the probability that a person does not have the virus given that they have tested negative
Probability in fraction form
P=(699/700)*(10/100)
P=6,990/70,000
simplify
P=699/7,000In a recent year, 24.8% of all registered doctors were female. If there were 54,100 female registered doctors that year, what was the total number of registered doctors? Round your answer to the nearest whole number.
To solve for total number of registered doctors:
Explanation:
The questions says, "24.8% of all registered doctors are females"
(Consider, total number of registered doctors as x)
that's,
[tex]\begin{gathered} 24.8\text{ \% of the x are female registered doctor} \\ 24.8\text{ \% of x = 54,100} \end{gathered}[/tex]Mathematically,
[tex]\begin{gathered} \frac{24.8}{100}.x=54,100 \\ \text{cross multiply} \\ 24.8x=54,100\text{ x 100} \\ 24.8x=5410000 \\ \frac{24.8x}{24.8}=\frac{5410000}{24.8} \\ x=218145.16 \\ x\approx218,145\text{ (nearest whole number)} \end{gathered}[/tex]Therefore the total number of registered doctors ≈ 218,145
does (51, 58) make the equation y =x -7 true?
The objective is to verify whether the point (51,58) maes the equation y=x-7.
Substitute the values of x and y coordinate in the given equation.
[tex]\begin{gathered} y=x-7 \\ y-x=-7 \\ 58-51=-7 \\ 7=-7 \end{gathered}[/tex]Since, LHS is not equal to RHS.
Thus, the coordinate (51,58) does not make the equation y=x-7.
Hence the answer is NO.
My answer is correct or no please check
Answer:
D) 5 minus a number M
hope this helps!
Answer:
Yep. You got it right. Good job!
Step-by-step explanation:
If Triangle ABC is dilated by a scale factor of 3 and the length of side AB is 15 inches, what is the length of side A'B'? Complete the statement: The length of side A'B' would be inches. Your answer
If Triangle ABC is dilated by a scale factor of 3 and the length of side AB is 15 inches, what is the length of side A'B'? Complete the statement: The length of side A'B' would be inches.
To find out the length side of A'B' multiply the length side AB by the scale factor
so
A'B'=3*(15)=45 inches
The cargo of the truck welghs no more than 2,800 pounds.Use w to represent the weight (in pounds) of the cargo.
We know that
• The truck weighs no more than 2,800 pounds.
This problem is about inequalities.
"no more" indicates an inequality sign, specifically, it shows that we should use "less than or equal to", because this sign indicates the same as the problem do.
Therefore, the expression of the truck weight is
[tex]w\leq2,800[/tex]Jacob took a taxi from his house to the airport. The taxi company charged a pick-upfee of $1.30 plus $5 per mile. The total fare was $16.30, not including the tip. Writeand solve an equation which can be used to determine , the number of miles in the
Let the total number of fare be f and total number of miles be m.
Therefore, the total fare f is given by:
[tex]f=1.30+5m[/tex]Substitute f = 16.30 into the equation:
[tex]\begin{gathered} 16.30=1.30+5m \\ 16.30-1.30=5m \\ 15=5m \\ \frac{15}{5}=\frac{5m}{5} \\ 3=m \\ m=3 \end{gathered}[/tex]Therefore, the required number of miles is 3.
What is the area of the real object that the scale drawing models?Scale factor: 1:3Area =6 square cmScale drawingOA. 54 square cmOB. 2 square cmO C. 18 square cmD. 6 square cmReal object
We have a drawing object with an area of 6 square centimeters. Since we have a scale factor of 1 : 3, it means that the real object is 3 times greater than the drawing object.
Therefore, if the drawing object has an area of 6 square centimeters, then the real object will have:
[tex]6cm^2*3=18cm^2[/tex]The real object will be 3 times greater than the one in the drawing.
Therefore, in summary, the real object will have 18 square centimeters (.
Tents-R-Us makes and sells tents. Tents-R-Us' motto is“Keep It Simple.” The company decides to makes justthree sizes of tents: the Mini, the Twin, and theFamily-Size. All the tents they make have equilateraltriangular ends as shown at right.1. For the Twin, each edge of the triangle will be 8 ft. Find the heightof the tent at the center, correct to the nearest inch. One way to findthis height is to make an accurate scale drawing and measure.
The company decides to make just three sizes of tents: the Mini, the Twin, and the Family-Size.
The shape of these tents is an equilateral triangle.
Part 1:
For the Twin, each edge of the triangle will be 8 ft.
The height of the tent is given by
[tex]h=a\cdot\frac{\sqrt[]{3}}{2}[/tex]Where a is the length of the edge of the triangle.
Since we are given that a = 8 ft
[tex]\begin{gathered} h=a\cdot\frac{\sqrt[]{3}}{2} \\ h=8\cdot\frac{\sqrt[]{3}}{2} \\ h=4\sqrt[]{3} \\ h=6.9\: ft \end{gathered}[/tex]Therefore, the height of the Twin tent at the center is 6.9 ft
Part 2:
The Mini tent will have edges 5 ft long.
The height of the tent is given by
[tex]h=a\cdot\frac{\sqrt[]{3}}{2}[/tex]Where a is the length of the edge of the triangle.
Since we are given that a = 5 ft
[tex]\begin{gathered} h=a\cdot\frac{\sqrt[]{3}}{2} \\ h=5\cdot\frac{\sqrt[]{3}}{2} \\ h=4.3\: ft \end{gathered}[/tex]Therefore, the height of the Mini tent at the center is 4.3 ft
Part 3:
The Family-Size tent will have a height of 10 ft at the center.
Recall that the height of the tent is given by
[tex]h=a\cdot\frac{\sqrt[]{3}}{2}[/tex]Re-writing the formula for edge (a)
[tex]a=h\cdot\frac{2}{\sqrt[]{3}}[/tex]Since we are given that h = 10 ft
[tex]\begin{gathered} a=h\cdot\frac{2}{\sqrt[]{3}} \\ a=10\cdot\frac{2}{\sqrt[]{3}} \\ a=\frac{20}{\sqrt[]{3}} \\ a=11.6\: ft \end{gathered}[/tex]Therefore, the length of edges of the Family-Size tent is 11.6 ft
2. Given: ZMOP is a right angle RP I OP Prove: MO || RP
Given that;
[tex]\begin{gathered} \measuredangle MOP\text{ is a right angle.} \\ \measuredangle MOP=90^0 \end{gathered}[/tex]And;
[tex]\vec{RP}\perp\vec{OP}[/tex]Since line RP is perpendicular to line OP, Angle RPO must be a right angle.
[tex]\measuredangle RPO=90^0[/tex]Recall that for two parallel lines intersected by a straight line, Same side interior angles are supplementary.
[tex]A+B=180^0[/tex]So, for line MO to be parallel to line RP, the sum of angle MOP and angle RPO must be equal to 180 degree.
[tex]\measuredangle MOP+\measuredangle RPO=90+90=180^0[/tex]Since the sum of angle MOP and angle RPO is equal to 180 degree, then line MO is parallel to line RP.
[tex]\begin{gathered} \text{ Since} \\ \measuredangle MOP+\measuredangle RPO=180^0 \\ \text{Then;} \\ MO\Vert RP \end{gathered}[/tex]Proved
Calculate the probability of winning: Roll two standard dice. You win if you get a sum of 4 or get a sum of 8. Round answer to one decimal place, for example if your answer is 0.65 enter 0.7
SOLUTION
The possible outcomes for sum of numbers when rolling two dice is shown
The total possible outcome is 36
The possible number of outcome of obtaining a 4 is 3
Therefore the probability of getting a sum of 4 is
[tex]\frac{3}{36}=\frac{1}{12}[/tex]The possible number of outcome of obtaining a 8 is 5
Therefore the probability of getting a sum of 8 is
[tex]\frac{5}{36}[/tex]Hence the probability of getting a sum 4 or a sum of 8 is
[tex]\frac{1}{12}+\frac{5}{36}[/tex]This gives
[tex]0.2[/tex]Therefore the probability of getting a sum 4 or a sum of 8 is 0.2
162-317-3113-510Is this relation a function?
can you see my messages?
309+23143240-59234881
Given data:
The given numbers are 309+23143240-59234881.
The simplification of the given numbers is,
-36091332.
what does this mean i dont get it pls help :)
Answer:
Left circle: 6x + 2y
Bottom middle circle: 5x
Bottom right rectangle: 3x + y
Step-by-step explanation:
According to the question, the expression in each circle is the result of the sum of the two rectangles connected to it.
The expression in the left circle is the sum of the expressions in the rectangles above and below it:
⇒ (4x + 3y) + (2x - y)
⇒ 4x + 3y + 2x - y
⇒ 4x + 2x + 3y - y
⇒ 6x + 2y
Therefore, the expression in the left circle is 6x + 2y.
The expression in the right circle is the sum of the expressions in the rectangles above and below it, however the expression in the rectangle below this circle is missing.
To find the missing expression, subtract the expression in the rectangle above the circle from the expression in the circle:
⇒ (4x + 5y) - (x + 4y)
⇒ 4x + 5y - x - 4y
⇒ 4x - x + 5y - 4y
⇒ 3x + y
Therefore, the expression in the lower right rectangle is 3x + y.
The expression in the bottom middle circle is is the sum of the expressions in the rectangles to its left and right:
⇒ (2x - y) + (3x + y)
⇒ 2x - y + 3x + y
⇒ 2x + 3x - y + y
⇒ 5x
Therefore, the expression in the bottom middle circle is 5x.
This is not from a test or graded assessment. The Question is included in the picture.
Given:
[tex]\begin{gathered} g(x)=-x^5-4x^3+6x \\ \\ h(x)=x^4+2x^3-2x^2+x-7 \\ \\ j(x)=3x^4+7x^2 \end{gathered}[/tex]It's required to determine if the functions are odd, even, or neither.
An even function satisfies the property:
f(-x) = f(x).
And an odd function satisfies the property:
f(-x) = -f(x)
We substitute x by -x on each function as follows:
[tex]\begin{gathered} g(-x)=-(-x)^5-4(-x)^3+6(-x) \\ \\ g(-x)=x^5+4x-6x \end{gathered}[/tex]Note the function g(-x) is the inverse (negative) of g(x), thus,
g(x) is odd
Now test h(x):
[tex]\begin{gathered} h(-x)=(-x)^4+2(-x)^3-2(-x)^2+(-x)-7 \\ \\ h(-x)=x^4-2x^3-2x^2-x-7 \end{gathered}[/tex]Comparing h(-x) and h(x) we can see none of the properties are satisfied, thus:
h(x) is neither odd nor even
Let's now test j(x):
[tex]\begin{gathered} j(-x)=3(-x)^4+7(-x)^2 \\ \\ j(-x)=3x^4+7x^2 \end{gathered}[/tex]Since j(-x) and j(x) are equal,
j(x) is even
I don’t understand how to get the second x intercept
In this problem
the vertex is given ------> (40/2,12)-------> (20,12)
The first intercept is (0,0)
therefore
second intercept is
x-intercept=20+20=40
(40,0) is the coordinates of the second x-intercept
(the vertex is the midpoint between the first and second x-intercept)
see the attached figure
It takes 6 eggs, 5 oz of cheese, and 2 oz of butter to make twoomelets. What is the cost per omelet if eggs cost $.99 per dozen,1 lb of cheese costs $4.29, and 1/2 lb of butter costs $1.25?a. $2.15b. $1.34c. $1.08d. $.31
Given:
It takes 6 eggs, 5 oz of cheese, and 2 oz of butter to make two
omelets
Eggs cost per dozen = $0.99
So, the cost of 6 eggs = 0.99/2 = 0.495
1 lb of cheese costs $4.29
1 lb = 16 oz
So, the cost of 5 oz =
[tex]\frac{5}{16}\cdot4.29=1.34[/tex]1/2 lb of butter costs $1.25
So, the cost of 2 oz =
[tex]\frac{2}{8}\cdot1.25=0.3125[/tex]So, the cost of two omelets = 0.495+1.34+0.3125 = 2.1475
So, the cost of one omelet = 2.1475/2 ≈ 1.08
So, the answer will be option c. $1.08
Sofia ordered sushi for a company meeting. They change plans and increase how many people will be at the meeting, so they need at least 100 pieces of sushi in total. Sofia had already ordered and paid for 24 pieces of sushi, so she needs to order additional sushi. The sushi comes in rolls, and each roll contains 12 pieces and costs $8. Let R represent the number of additional rolls that Sofia orders.Which inequality described this scenario?What is the least amount of additional money sofia can spend to get the sushi they need?
Answer:
the least amount Sofia can spend is $608
In a school, 10% of the students have green eyes. Findthe experimental probability that in a group of 4students, at least one of them has green eyes.The problem has been simulated by generating randomnumbers. The digits 0-9 were used. Let the number "9"represent the 10% of students with green eyes. A sampleof 20 random numbers is shown.
Given that in a group of 4 students at least one has green eyes.
Also, the number 9 represents the 10% of the students with green eyes.
From the 20 random experimental numbers given, the number 9 appeared in only nine of them.
The experimental probability in percentage will be:
[tex]\frac{9}{20}\ast100\text{ = }45\text{ percent}[/tex]ANSWER;
45%
what is 0.554 / 0.041
Answer:
13.5
Step-by-step explanation:
Hello!
Here is your solution after dividing the given decimals.
[tex]0.554[/tex] ÷ [tex]0.041[/tex] = [tex]13.51219[/tex] ← (There is a line passing over all numbers to the right side of the decimal.)
In summary, the final answer is 13.5 ← (Line over 5)
Hope this helps!
Instructions: Find the circumference of the circle and round to the nearest tenth.
The circumference of the circle formula is
[tex]C=2\pi r[/tex][tex]r\rightarrow radius[/tex][tex]\begin{gathered} diameter=7.8yd \\ r=\frac{diameter}{2}=\frac{7.8}{2}=3.9yd \\ \end{gathered}[/tex][tex]\begin{gathered} C=2\pi r \\ C=2\times\pi\times3.9 \\ C=24.5yd \end{gathered}[/tex]Hence, the circumference of the circle is 24,5yd