find
the slope between (3,-3) and (12,-2) 50 POINTS SOLVE ASAP

In the parallelogram ABCD the value of DF is 13.33 metres or DF = 40/3 metres (rounded to two decimal places).

In the parallelogram ABCD, we can draw a diagonal AC that splits the parallelogram into two congruent triangles, namely, △ABC and △ADC.

Let x be the length of DF. We can use similar triangles to find x.

Notice that △BCE and △DFE are similar triangles, since they share the same angle at E and the angles at B and D are congruent due to opposite angles in a parallelogram. Therefore, we can write the following proportion:

BC/CE = DF/FE

Substituting the given values, we have:

16/8 = x/(20-x)

Simplifying this equation, we get:

2 = x/(20-x)

2(20-x) = x

40 - 2x = x

3x = 40

x = 40/3

Therefore, DF = 40/3 meters or 13.33 meters (rounded to two decimal places).

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The point one tick mark to the left of negative 3 on the number line is -3.25.

Number lines are horizontal straight lines in math where the intervals between the integers are equal. A number line can be used to show all of the numbers in a sequence. At both ends, this line continues indefinitely.

Each tick mark on the number line represents one-fourth of a unit, so the distance between negative 4 and negative 3 can be divided into 4 parts, each with a length of one-fourth of a unit. Starting from negative 4, the tick marks would be labeled as -4, -3.75, -3.5, -3.25, -3, and so on. Therefore, the point one tick mark to the left of negative 3 is at -3.25 on the number line.

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By alternately multiplying 2(n-2) by 1 and -1 for odd and even values of n, respectively, this formula yields the nth term of the sequence.

A sequence is a list of objects that is in order in mathematics. (or events). Similar to a set, it has members. (also called elements, or terms). The length of the sequence is the number of many ordered elements (potentially infinite).

Given :

The ratio between consecutive terms in the above sequence is not constant, hence it is not a geometric sequence. The series does, however, appear to rotate between positive and negative numbers.

The explicit formula for the nth term in this sequence is as follows:

a = (-1)^(n+1) * 2^(n-2) (n-2)

By alternately multiplying 2(n-2) by 1 and -1 for odd and even values of n, respectively, this formula yields the nth term of the sequence. For instance, when n is 1, we obtain:

n = 2 results in:

so forth.

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The value of the probability P(A ∪ B) if the events are independent events is  0.55

The formula for the probability of the union of two events is:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

Since the events A and B are independent, the probability of their intersection is simply the product of their individual probabilities:

P(A ∩ B) = P(A) × P(B)

Substituting the given values, we have:

P(A ∩ B) = 0.4 × 0.25 = 0.1

Now we can use the formula for the union:

P(A ∪ B) = P(A) + P(B) - P(A ∩ B)

So, we have

P(A ∪ B) = 0.4 + 0.25 - 0.1

This gives

P(A ∪ B) = 0.55

Therefore, the probability of the union of events A and B is 0.55.

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The equation of the graphed function, which is composed of translations to f(x) = x³, is given as follows:

B. y = f(x + 3) - 2.

A translation happens when either a figure or a function is moved horizontally or vertically on the coordinate plane.

The four translation rules for functions are defined as follows:

The turning point of f(x) = x³ is at the origin, while for the graphed function it is at point (-3,-2), hence the translations are given as follows:

Hence the graphed function is defined as follows:

B. y = f(x + 3) - 2.

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Answer: Scootering is faster

Step-by-step explanation: If it takes 20 minutes to go around walking going through the middle would technically split the time in half and 20 divided by 2 is 10 which is more than 8 therefore scootering is faster.

A proportional connection exists when two values may be expressed as y = kx, where k is a constant. To discover which ordered pairings have a proportionate connection with (0.2, 0.3).

We must find a value of k for each pair that makes this equation true. Let us begin with option A: (1.2, 2.3). If we wish to represent this combination as y = kx, we must discover the value of k that results in 2.3 = k. (1.2). When we solve for k, we get: k = 2.3 / 1.2 ≈ 1.92 As a result, (1.2, 2.3) does not have a proportionate connection with (0.2, 0.3) since the value of k is different for both couples. This procedure can be repeated for each of the others. options. Option B: (2.7, 4.3) yields: k = 4.3 / 2.7 ≈ 1.59 Option C: (3.2, 4.8) yields: k = 4.8 / 3.2 = 1.5 Option D: (3.5, 5.3) yields: k = 5.3 / 3.5 ≈ 1.51 Option E: (5.2, 7.8) yields: k = 7.8 / 5.2 = 1.5 As a result, alternatives C and E are proportional to (0.2, 0.3) since they can be represented in the form y = kx with the same k value. k = 1.5 in both situations.

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Answer:

We know that 120 can be factored as 2^3 * 3 * 5, so its totient function value can be found as follows:

φ(120) = φ(2^3) * φ(3) * φ(5)

= 2^2 * 2 * 4

= 16

Therefore, there are 16 numbers less than or equal to 120 that are relatively prime to 120

Donovan scored 6 points, Jeremy scored 18 points, and Kolby scored 12 points.        

Let's denote the number of points scored by Donovan as "D".    

According to the problem, Jeremy scored triple the number of points as Donovan, so he scored 3D points.

Similarly, Kolby scored double the number of points as Donovan, so he scored 2D points.

We also know that the total number of points scored by all three boys is 36. So we can write an equation:

D + 3D + 2D = 36

Simplifying this equation, we get:

6D = 36

Dividing both sides by 6, we get:

D = 6

So Donovan scored 6 points.

Using the values we found for Donovan's score, we can find the scores of Jeremy and Kolby:

Jeremy scored 3D = 3(6) = 18 points

Kolby scored 2D = 2(6) = 12 points

Therefore, Donovan scored 6 points, Jeremy scored 18 points, and Kolby scored 12 points.

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The probability of getting at least one "r" of the alphabet if letters of the alphabet are selected at random is 1/1.

The reason for this is that if any letter of the alphabet is selected at random, the probability of getting an "r" is 1/26, or 0.0385. Since letters can be used more than once, this probability remains the same regardless of how many letters are selected. Thus, the probability of getting at least one "r" of the alphabet if letters of the alphabet are selected at random is 1.

In summary, the probability of getting at least one "r" of the alphabet if letters of the alphabet are selected at random is 1. This is because, when a letter is selected at random, each letter has an equal chance of being chosen (1/26), and since the probability of selecting an "r" remains the same regardless of how many letters are selected, the probability of getting at least one "r" is also 1.

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[tex]t_2023[/tex] will be equal to the expression[tex]: t_2023 = [k*t_2022 + 1] / [k^2 * t_2021][/tex]. in terms of k.

The sequence given is defined by the recurrence relation:  [tex]t_n[/tex] = [tex][kt_(n−1)+ 1] /[k^2 t_(n−2)] for n ≥ 3,with t_1 = 1[/tex] and [tex]t_2[/tex] = 2, and [tex]t_3=(2k+1)/k^2[/tex], and [tex]t_4=(3k+1)/2k^3[/tex], and [tex]t_5=(k+1)/2k^2[/tex], and [tex]t_6[/tex]=1 and [tex]t_7[/tex]=2 and [tex]t_8=(2k+1)/k^2, t_9=(3k+1)/2k^3[/tex]. To find the value of [tex]t_2023[/tex], we need to find the values of the previous two terms, [tex]t_2022[/tex] and [tex]t_2022[/tex] . We can do this by using the recurrence relation, starting at n = 3 and going up until n = 2022.

Therefore,[tex]t_2022 = [k*t_2021 + 1] / [k^2 * t_2020][/tex].

Similarly, [tex]t_2021 = [k*t_2020 + 1] / [k^2 * t_2019[/tex]].

We can now plug in the values of [tex]t_2021[/tex] and [tex]t_2020[/tex], which can be found by continuing to work backwards in the recurrence relation until n = 9, and then we have the initial conditions of the sequence. Once we have the values of [tex]t_2021[/tex] and [tex]t_2021[/tex] , we can substitute them into the recurrence relation for[tex]t_2023[/tex] to get the desired result. Therefore, [tex]t_2023 = [k*t_2022 + 1] / [k^2 * t_2021].[/tex]

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Answer:

6 hours

Step-by-step explanation:

[tex]\frac{1}{6}[/tex] of Total battery life = [tex]\frac{1}{6} * 3600 = 600[/tex]milliamps

Assuming the battery takes 100 Milliamps per hour,

Time = Battery Capacity / Current hours

Time = 600 / 100 Mah = 6H

Answer:

265 ft

Step-by-step explanation:

its asking what is the hypotenuse

"SOHCAHTOA"

sine equals opposite over hypotenuse, cosine equals adjacent over hypotenuse, and tangent equals opposite over adjacent

use

soh because it has hypotenuse in it

sine equals opposite over hypotenuse

sine 49 = 200 / x

x & sine 49 can switch

x = 200/sin(49°)

x = 200/0.7547

x = 265.005962634

x = 265

using pythagorean theorem other leg is 173.85 or 174

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Answer: To find the total area of the grass that Yuri's dad needs to fertilize, we need to calculate the area of the back yard and the area of the front yard, and then add them together.

Area of the back yard:

The back yard measures 55 feet by 30 feet, so the area is:

55 feet x 30 feet = 1650 square feet

Area of the front yard:

The front yard is a square with a length of 42 feet on each side, so the area is:

42 feet x 42 feet = 1764 square feet

Total area:

To find the total area, we add the area of the back yard and the area of the front yard:

1650 square feet + 1764 square feet = 3414 square feet

Therefore, Yuri's dad needs to fertilize a total area of 3414 square feet.

Step-by-step explanation:

The caterpillar touches 15 points with two integer coordinates, including the start point (-3, -4) and the end point (25, 38).

What is co-ordinate geometry ?

Coordinate geometry is a branch of mathematics that deals with the study of geometry using the principles of algebra. In coordinate geometry, geometric figures are represented using algebraic equations and analyzed using techniques from algebra and calculus.

The caterpillar moves from (-3, -4) to (25, 38) in a straight line. We can find the equation of the line passing through these two points using the slope-intercept form of the equation of a line:

y - (-4) = (38 - (-4))/(25 - (-3)) * (x - (-3))

y + 4 = 42/28 * (x + 3)

y = 3/2 * x + 19

The caterpillar touches a point with two integer coordinates whenever x and y are both integers. To find these points, we can substitute integer values for x and solve for y. Since the slope of the line is 3/2, every time x increases by 2, y increases by 3.

Starting from x = -3, we can list the integer values of x that the caterpillar touches:

-3, -1, 1, 3, 5, ..., 25

For each value of x, we can compute the corresponding value of y using the equation of the line:

y = 3/2 * x + 1

For example, when x = -3, y = 3/2 * (-3) + 19 = 14.5, which is not an integer. When x = -1, y = 3/2 * (-1) + 19 = 17.5, which is also not an integer. However, when x = 1, y = 3/2 * 1 + 19 = 20, which is an integer. Similarly, we can find the integer values of y for all the other values of x.

Therefore, the caterpillar touches 15 points with two integer coordinates, including the start point (-3, -4) and the end point (25, 38).

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After answering the provided question, we can conclude that Therefore, the answer of quadratic equation is  D) [tex]$-3x^{2}+7$[/tex]

A quadratic equation is x ax² + bx + c = 0, so it's a single variable quadratic polynomial. a 0. Because this regression is of second order, the Fundamental Principle of Algebra helps to ensure that it includes at least one solution. Simple or complex solutions are possible. A quadratic equation is a quadratic calculation.

This means there is at least yet another word that must be squared. The formula "ax² + bx + c = 0" is a common solution for quadratic equations. where a, b, and c are arithmetical coefficients or constants. where the parameter "X" is unidentified.

To find g(h(x))

[tex]$\begin{array}{l}{{h(x)=3x^{2}-2}}\\ {{g(h(x))=g(3x^{2}-2)}}\\ {{g(3xA^2))=-3x^2-2}+5}}\\ {{g(h(x))=-3x^{2}+7}}\end{array}$[/tex]

Therefore, the answer is D) [tex]$-3x^{2}+7$[/tex]

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Answer:a

Step-by-step explanation:its simple

Answer:

what term?

Step-by-step explanation:

Explain the question.

Answer:

1

explanation in head

After expanding the polynomial (5x² + x - 7)(x - 4) - (2x³ + 5x² - 6), b = -24

A polynomial is a mathematical expression in which the power of the unknown is greater than or equal to 2.

Since we have the polynomial (5x² + x - 7)(x - 4) - (2x³ + 5x² - 6) and we want it expressed as a polynomial in the form ax³ + bx² + cx + d, to find the value of b, we proceeda s follows.

(5x² + x - 7)(x - 4) - (2x³ + 5x² - 6)

Expanding the brackets, we have that

(5x² + x - 7)(x - 4) - (2x³ +5x² - 6) = 5x³ - 20x² + x² - 4x - 7x + 28 - (2x³ + 5x² - 6)

= 5x³ - 20x² + x² - 4x - 7x + 28 - 2x³ - 5x² + 6

Collecting like terms, we have

= 5x³ - 2x³ - 20x²- 5x² + x² - 4x - 7x + 28 + 6

= 3x³ - 24x² - 11x + 34

So, comparing 3x³ - 24x² - 11x + 34 with ax³ + bx² + cx + d, we have that

b = - 24

So, b = -24

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The initial amount of salt in the tank is 60 kg, calculated using the formula M = ρV, where M is the mass of the salt, ρ is the density of the salt, and V is the volume of the tank.

Initially, the tank contains 60 kg of salt and 2000 liters of water. The amount of salt in the tank can be calculated using the formula M=ρV, where M is the mass of the salt, ρ is the density of the salt, and V is the volume of the tank. The density of salt is 2270 kg/m3. Assuming the tank has a constant volume, the mass of the salt in the tank is 60 kg.

The amount of salt in the tank changes due to the addition of pure water and mixing of the solution. The amount of salt in the tank at any given time can be calculated using the formula M=ρV, where M is the mass of the salt, ρ is the density of the salt, and V is the volume of the tank. The rate at which the salt is added to the tank is equal to the rate at which the salt-water solution is drained from the tank.

Therefore, the rate of change of the mass of the salt in the tank is equal to 8 liters/minute of pure water entering the tank minus 4 liters/minute of salt-water solution draining from the tank. Thus, the amount of salt in the tank initially is 60 kg.

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The upper bound of the volume of water left in the fish tank is 60 liters.

33.81 fluid ounces make up one litre (US).

One litre of water would fill about one-fourth of a gallon water bottle. Also, you should be aware that there are two different kinds of ounces used globally to measure water volume: (1 litre = 33.814 US ounces).

The maximum allowable mistake can be added to the actual value to determine the upper bound of the amount of water still in the fish tank.

The maximum error for 90 litres, rounded to one significant figure, is half of the value of the last significant figure, or 5. Hence, the actual value of 90 litres might be either 85 or 95.

The largest potential inaccuracy for 30 litres, rounded to one significant figure, is likewise 5. Hence, the actual value of 30 litres might be 25 or 35.

We subtract the lower bound of the withdrawn volume from the higher bound of the original volume to determine the upper bound of the volume of water still present in the tank.

The upper bound of the volume of water left in the fish tank can be found by adding the half of the absolute uncertainty to the measured value of 60 liters (90 - 30):

Upper bound = 60 + 0.5 x 1 = 60.5 liters (rounded to 1 significant figure)

Therefore, the upper bound of the volume of water left in the fish tank is 60 liters.

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The expected value and standard deviation of x are 1.6 and 0.66, respectively.

Given that:

Jimmy volunteers at events at the hospital each year.

The random variable x is the number of hospital events Jimmy works at each year.

We understand that he does not work for more than two events in a year

So, x can take on the values 0, 1, or 2.

From the question, we have:

Over the past ten years

So, the table is

X P(X)

0 0.1

1 0.2

2 0.7

To find the expected value, we take the sum of the products of x and P(x)

So, we have

E(x) = 0(0.1) + 1(0.2) + 2(0.7)

E(x) = 1.6

To find the standard deviation, we need to first calculate the variance:

Var(X) = E(x^2) - [E(x)]^2

Where

E(x^2) = 0^2(0.1) + 1^2(0.2) + 2^2(0.7)

E(x^2) = 3

So, we have

Var(X) = 3 - (1.6)^2

Var(X) = 0.44

This means that

SD(x) = √0.44

SD(x) = 0.66

Hence, the standard deviation is 0.66

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`C(p,k) * C(n-p,k)`

a. Proof: We will apply the same method we used in formula (1) in our class notes on this question. For this purpose, we choose a set containing `n + 1` elements. It contains all elements of the set of `n` elements and another element `y` that has not been included in the set of `n` elements.Let the number of sets of `n` elements that contain `k` particular elements `a` be `P(n, k)`. To count the number of sets of `n + 1` elements that contain `k` elements, we use the concept of permutations with repetition, such as -{n + 1} can be placed in any of the `k` places of the k-element subsets of `{1, 2,...,n}`, or it can be one of the remaining `n-k+1` elements in each of the `P(n,k)` sets that contain `k` elements.Let us use `A` to denote the set of sets of `n` elements that do not contain the element `y` and `B` to denote the set of sets of `n` elements that contain the element `y`. Then, `P(n+1,k)=|A|+|B|=P(n,k)+(n−k+1)P(n,k−1)`.b. Proof: To count the number of `k` element subsets from a set of `n` elements, we use `C(n, k)`.Let us consider two sets, `A` and `B`, where `|A|=n-k` and `|B|=p-k`. We want to choose `k` elements from these two sets such that the number of subsets we get from `A` is `x` and the number of subsets we get from `B` is `y`. In the set `A`, we select `x` elements by choosing `k-x` elements from the remaining `n-k` elements. Similarly, in the set `B`, we select `y` elements by choosing `k-y` elements from the remaining `p-k` elements.Thus, the total number of ways of choosing `k` elements from `A` and `B` is given by `C(n-k, x) * C(p-k, y)`. The total number of ways of choosing `k` elements from `n` elements is given by `C(n, k)`. Therefore, the total number of ways of choosing `k` elements from `n` elements such that `x` elements are chosen from `A` and `y` elements are chosen from `B` is `C(n-k, x) * C(p-k, y) * C(n, k)`.To get the total number of ways of choosing `k` elements from `n` elements such that `k` elements are chosen from `A` and `p-k` elements are chosen from `B`, we must sum over all possible values of `x` and `y`. Thus, the total number of ways of choosing `k` elements from `n` elements such that `k` elements are chosen from `A` and `p-k` elements are chosen from `B` is given by: `C(p,k) * C(n-p,k)`  which is the required result.

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The quantity of fuel that was utilized by the water in March is 230.4 liters.

Fuel capacity of the tanker = 460 liters

Fuel consumption rate = 5 km/ℓ

Total distance covered per full tank = fuel capacity * fuel consumption rate = 460 x 5 = 2,300 km

Number of full tanks required to make one round trip = distance per round trip / total distance covered per full tank = 18/2300

                                                                              =0.0078

Number of round trips made in March 2022 = 1/0.0078 x 2

                                                                          = 64.1

Total distance covered = number of round trips * distance per round trip                                      

                                      = 64 x 18

                                      = 1,152 km

Therefore, the total distance covered by the water tanker = 1,152 km

Quantity of fuel utilized = total distance covered / fuel consumption rate

                                       =  1152/5

                                       = 230.4 liters.

Therefore, The quantity of fuel that was utilized by the water in March is 230.4 liters.

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Your question is incomplete. The complete question is:

The water source is at a distance of about 18 km (return trip) from the construction site. The water tanker has a fuel capacity of 460 liters. The rate of fuel consumption of the Mercedes water tanker averages 5 km/t. The prices of fuel per liter in March and June 2022 appear below:

MARCH 2022 FUEL PRICES

DIESEL

50 ppm

COST

R19,55

JUNE 2022 FUEL PRICES

DIESEL

50 ppm

Hence, determine the quantity of fuel that was utilized by the water tanker in March 2022.

We can use the principle of inclusion-exclusion to find n(U), which states that for two sets A and B:

n(A union B) = n(A) + n(B) - n(A intersection B)

We can apply this to three sets r, s, and their complements r' and s':

n(U) = n(r union s)

= n(r) + n(s) - n(r intersection s)

= [n(r intersection s') + n(r intersection s)] + [n(s intersection r') + n(s intersection r)] - n(r intersection s)

= [(4 + n(r' intersection s)) + (n(r intersection s') + 7)] - 4

= n(r' intersection s) + n(r intersection s') + 3

= 7 + 3 + 3

= 13

Therefore, n(U) = 13.

x is the number of HD Big View television produced daily.

y is the number of Mega Tele box television produced daily.

A system of inequalities to represent the constraints of this problem are x ≥ 0 and y ≥ 0.

A graph of the system of inequalities is shown on the coordinate plane below.

In order to write a system of linear inequalities to describe this situation, we would assign variables to the number of HD Big View television produced in one day and number of Mega Tele box television produced in one day respectively, and then translate the word problem into algebraic equation as follows:

Since the HD Big View television takes 2 person-hours to make and the Mega TeleBox television takes 3 person-hours to make, a linear equation to describe this situation is given by:

2x + 3y = 192.

Additionally, TVs4U’s total manufacturing capacity is 72 televisions per day;

x + y = 72

For the constraints, we have the following system of linear inequalities:

x ≥ 0.

y ≥ 0.

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Answer:

1219.5 more centimeters of fabric

Step-by-step explanation:

First, we need to convert 12.5 meters to centimeters, since the given amount of fabric is in centimeters.

12.5 meters = 12.5 x 100 centimeters/meter = 1250 centimeters

Now we can find the difference between what Ray needs and what he has:

1250 centimeters - 30.5 centimeters = 1219.5 centimeters

Therefore, Ray needs 1219.5 more centimeters of fabric.

The solution of the system of equations from the graph is x = 2.

The point of intersection formula is used to determine where two lines meet, or the point at which they intersect. In Euclidean geometry, the intersection of two lines can be either an empty set, a point, or a line. Two lines must meet certain requirements in order to intersect, including being in the same plane and not being skew lines. The intersection of these lines may be determined using the intersection formula.

The solution of the system of equations can be determined from the graph by determining the point of intersection between the two lines.

From the graph we observe that the point of intersection of the two lines is at (0, 2).

Hence, the solution of the system of equations is x = 2.

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