The density of the sample of argon gas at 69 °C and 768 mmHg is 1.44 g/L (1st option)
How do i determine the density of the gas?From the question given above, the following data were obtained:
Temperature of gas (T) = 69 °C = 69 + 273 = 342KPressure of gas (P) = 768 mmHg = 768 / 760 = 1.01 atmGas constant (R) = 0.0821 atm.L/Kmol Molar mass of argon (M) = 40 g/molDensity of gas (D) = ?The density of the sample of argon gas can be obtained as illustrated below:
D = MP / RT
D = (40 × 1.01) / (0.0821 × 342)
D = 1.44 g/L
Thus, from the above calculation, we can conclude that the density of the gas is 1.44 g/L (1st option)
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