The value of c on the interval (5,9) such that f'(c) = f(b) - f(a) / (b - a) is c = 3, and the average rate of change of f(x) on the interval [5,9] is 139.
First, we can find the average rate of change of f(x) on the interval [a,b] using the formula:
average rate of change = [f(b) - f(a)] / (b - a)
Substituting the given values of a = 5 and b = 9 into the formula, we get:
average rate of change = [f(9) - f(5)] / (9 - 5)
Next, we need to find f(9) and f(5) to calculate the average rate of change. To do this, we first need to find the derivative of f(x) using the power rule:
f'(x) = 6x² - 6x - 12
Now, we can use the Mean Value Theorem to find a value c in the interval (5,9) such that f'(c) equals the average rate of change. According to the Mean Value Theorem, there exists a value c in the interval (5,9) such that:
f'(c) = [f(9) - f(5)] / (9 - 5)
Substituting the derivative of f(x) and the values of f(9) and f(5) into the equation, we get:
6c² - 6c - 12 = [2(9)³ - 3(9)² - 12(9) - 4 - (2(5)³ - 3(5)² - 12(5) - 4)] / (9 - 5)
Simplifying the right-hand side of the equation, we get:
6c² - 6c - 12 = (658 - 204) / 4
6c² - 6c - 12 = 114
6c² - 6c - 126 = 0
Dividing both sides by 6, we get:
c² - c - 21 = 0
Using the quadratic formula, we can solve for c:
c = [1 ± sqrt(1 + 4(21))] / 2
c = [1 ± 5] / 2
The two possible values of c are:
c = 3 or c = -4
However, since the interval is (5,9), c must be between 5 and 9. Therefore, the value of c that satisfies the Mean Value Theorem is c = 3.
Finally, substituting f(5) and f(9) into the formula for the average rate of change, we get:
average rate of change = [f(9) - f(5)] / (9 - 5)
= [(2(9)³ - 3(9)² - 12(9) - 4) - (2(5)³ - 3(5)² - 12(5) - 4)] / (9 - 5)
= [434 - (-104)] / 4
= 139
Therefore, the value of c on the interval (5,9) such that f'(c) = f(b) - f(a) / (b - a) is c = 3, and the average rate of change of f(x) on the interval [5,9] is 139.
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What is the exponent in the expression 7 superscript 6?
6
7
13
42
The exponent of the expression is 6.
What is the exponent of the expression?Remember that a superscript is a small symbol on the right top of another, then we can write this as:
7⁶
Remember that a general power is:
aⁿ
Where a is the base and n is the exponent.
Comparing that with the given expression, we can see that the base is 7 and the exponent is 6.
So the first option is the correct one.
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. HURRY
What are the zeros of the following function?
The zeros of the function include the following: A. 2 and -3.
What is the x-intercept of a quadratic function?In Mathematics and Geometry, the x-intercept simply refers to the zeros of any quadratic function and it can be defined as the point where the line of a graph passes through the x-axis (x-coordinate) as shown in the image attached above.
Next, we would write the quadratic function in standard form with a leading coefficient of 1 by using the zeros or x-intercept as follows;
f(x) = (x - (-3))(x - 2)
f(x) = (x + 3)(x - 2)
f(x) = x² + 3x - 2x - 6
f(x) = x² + x - 6
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Complete Question:
What are the zeros of the following function?
a) 2 and -3
b) 2 and 3
c) 3 only
d) -3,2 and 3
Omarion and savannah are both saving money for their summer trip. Omarion started with $130 and puts in $10 every week. Savannah started with $55 and puts in $25 every week. Write and slice an equation that will determine the number of weeks (w) when Savannah and Omarion have the same amount in savings. At that point how much savings will they both have?
Answer:
I believe the answer is $180
Step-by-step explanation:
130+10=140
55+25=80
150
105
160
130
170
155
180
180
The center is O. The circumference is 28. 6 centimeters. Use 3. 14 as an approximation for pi
The diameter of the given circle with a circumference of 28.6 centimeters is approximately 9.11 cm.
The circumference of a circle is given by the simple formula: C = πd, where C is the circumference, π is the constant pi and d is the diameter of the circle.
Given that the circumference of the circle is 28.6 cm, we can use the formula to find the diameter:
28.6 = πd
d = 28.6/π
Using 3.14 as an approximation for π, we get:
d ≈ 28.6/3.14 ≈ 9.11
Therefore, the diameter of the circle is approximately 9.11 cm.
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JESLIOL B0/1 pto 100 99 Details A sample of 59 Charleston County households have a mean income of $31,868 with a standard deviation of $5,749. Find a 80% confidence interval for the true population mean income for households in Charleston County, Round your answers to the nearest dollar.
The 80% confidence interval for the true population mean income for households in Charleston County is $30,749 to $32,987 (rounded to the nearest dollar).
We can use the t-distribution to find the confidence interval since the population standard deviation is unknown and the sample size is less than 30.
First, we need to find the t-value for a 80% confidence level with 58 degrees of freedom (sample size - 1). We can use a t-table or a calculator to find this value. Using a calculator, we get:
t-value = 1.670
Next, we can use the formula for a confidence interval:
CI = X ± t-value * (S / √n)
where X is the sample mean, S is the sample standard deviation, n is the sample size, and t-value is the critical value from the t-distribution.
Plugging in the values we get:
CI = 31,868 ± 1.670 * (5,749 / √59)
Simplifying, we get:
CI = 31,868 ± 1,119
Therefore, the 80% confidence interval for the true population mean income for households in Charleston County is $30,749 to $32,987 (rounded to the nearest dollar).
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49 packages are randomly selected from packages received by a parcel service. The sample has a mean weight of 28.6 pounds. Assume that What is the 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service?
A. 27.5 to 29.7 pounds
B. 27.7 to 29.5 pounds
C. 27.6 to 29.6 pounds
D. 27.9 to 29.3 pounds
The correct answer is option C: 27.6 to 29.6 pounds.
To calculate the 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service, we can use the following formula:
CI = X ± (tα/2)(s/√n)
where:
X is the sample mean weight
tα/2 is the t-value from the t-distribution with (n - 1) degrees of freedom and α/2 level of significance (α/2 = 0.025 for a 95% confidence interval)
s is the sample standard deviation of weights
n is the sample size
We are given that the sample size is n = 49 and the sample mean weight is X = 28.6 pounds. We do not have the sample standard deviation, so we will assume it is unknown and use a t-distribution to estimate the standard error of the sample mean.
We want to calculate the 95% confidence interval, so α/2 = 0.025 and the degrees of freedom are (n - 1) = 48. From a t-distribution table, the t-value for a 95% confidence interval with 48 degrees of freedom is approximately 2.01.
Now we need to estimate the sample standard deviation, s, using the sample data. We can use the formula:
s = sqrt[ Σ(xi - X)² / (n - 1) ]
where xi is the weight of the ith package in the sample.
Without the actual data values, we cannot compute the exact value of s, but we can estimate it using the sample variance. We know that:
s² = Σ(xi - X)² / (n - 1) = (49 - 1) / 48 * s²
So, an estimate of s is:
s = sqrt[ (SS / (n - 1)) ] = sqrt[ (Σ(xi - X)² / (n - 1)) ]
where SS is the sum of squares of deviations of the sample data from the mean.
Assuming the sample standard deviation is unknown and using the above formula, we can estimate s as:
s ≈ 2.7 pounds
Substituting the known values into the formula for the confidence interval, we have:
CI = X ± (tα/2)(s/√n)
= 28.6 ± (2.01)(2.7/√49)
= 28.6 ± 0.99
Therefore, the 95% confidence interval for the true mean weight, μ, of all packages received by the parcel service is (28.6 - 0.99, 28.6 + 0.99), or approximately (27.6, 29.6) pounds.
So, the correct answer is option C: 27.6 to 29.6 pounds.
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18. Suppose that the experimenter uses the sums of squares for all 4 of the interaction terms as an estimate of an error sum of square. The error mean square would then be a. 3.45 b. 2.71 c. 3.00 d. 2.95
The error mean square would then be given by the term of 2.71 which is option B.
In statistics, in addition to the mode and median, the mean is one of the measures of central tendency. Simply said, the mean is the average of the values in the given collection. It indicates that values in a certain data collection are distributed equally.
The three most often employed measures of central tendency are the mean, median, and mode. The total values provided in a datasheet must be added, and the sum must be divided by the total number of values in order to get the mean. When all of the values are organised in ascending order, the Median is the median value of the provided data.
Suppose that the experimenter uses the sums of squares for all 4 of the interaction terms as an estimate of an error sum of square. The error mean square would then be 2.71
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describe the end behavior of the polynomial f(x)=2x^3-3x^2+4x+5
The end behaviour of the given cubic polynomial function as required to be determined is; As x tends to negative infinity, f(x) tends to negative infinity, As x tend to infinity, f(x) tends to infinity.
What is the end behaviour of the given polynomial function?It follows from the task content that the end behaviour of the given polynomial function is to be determined.
As evident from the task content; the polynomial is of degree 3 and the leading coefficient is; 2.
On this note, since the polynomial is of degree 3 which is odd and the leading coefficient is positive; it follows that the end behaviour is such that; As x tends to negative infinity, f(x) tends to negative infinity, As x tend to infinity, f(x) tends to infinity.
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The following dot plot shows the number of chocolate chips in each cookie that Shawn has. Each dot represents a different cookie.
Using the dot plot, it is found that a typical amount of chocolate chips in one of Shawn's cookies is around 4.56.
Dot plot:
The dot plot is a graph shows the number of times each measure appears in the data-set.
Researching this problem on the internet, the dot plot states that:
2 cookies have 2 chips.
2 cookies have 3 chips.
5 cookies have 4 chips.
4 cookies have 5 ships.
3 cookies have 6 ships.
2 cookies have 7 chips.
The mean is given by:
M = (2 x 2 + 2 x 3 + 5 x 4 + 4 x 5 + 3 x 6 + 2 x 7)/(2 + 2 + 5 + 4 + 3 + 2) = 4.56.
Hence, a typical amount of chocolate chips in one of Shawn's cookies is around 4.56.
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Correct Question:
The following dot plot shows the number of chocolate chips in each cookie that Shawn has. Each dot represents a different cookie.
At the time of a certain marriage, the probabilities that the man and the woman will live fifty more years are 0.352 and 0.500, respectively. What is the probability that both will be alive fifty years later?
The probability that both the man and the woman will be alive fifty years later is 0.176.
Since, The probability of that both the man and woman will be alive fifty years later, we have to multiply the two probabilities together as they are independent events.
So, We get;
P(both alive after fifty years) = P(man alive after fifty years) x P(woman alive after fifty years)
P = 0.352 x 0.500
P = 0.176
Therefore, the probability that both the man and the woman will be alive fifty years later is 0.176.
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Find the effective rate corresponding to the given nominal rate.(Use a 365-day year.)8%/year compounded semiannually
The effective rate corresponding to the given nominal rate of 8%/year compounded semiannually is 8.16%.
Converting the nominal rate to decimal form
Nominal rate = 8% = 0.08
Dividing the nominal rate by the number of compounding periods per year
Since the nominal rate is compounded semiannually, there are 2 compounding periods per year.
Therefore, we will divide the nominal rate by 2.
0.08 / 2 = 0.04
Calculating the effective rate using the formula:
Effective rate
[tex]= (1 + (Nominal rate / Compounding periods per year))^{Compounding periods per year }- 1[/tex]
= (1 + 0.04)² - 1
= (1.04)² - 1
= 1.0816 - 1
= 0.0816
Step 4: Convert the effective rate to percentage form
Effective rate = 0.0816 * 100 = 8.16%
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Which set has a domain of { −3, 4} and a range of {0, 1}? A. {(4, 0), ( −3, 1), ( −3, 4)} C. {{ −3, 0), (4, 0), (1, 4)} B. {( −3, 1), (4, 0)} D. {(0, −3), (1, 4)}
The relation that has the domain {-3, 4} and the range {0, 1} is B:
{( −3, 1), (4, 0)}
Which set has the given domain and range?Remember that for any relation, the domain is the set of the inputs and the range is the set of the outputs, and the general notation for a point is (input, output).
Then if the domain is {-3, 4} and the range is {0, 1} the only of the given relations that can be described by these is:
B. {( −3, 1), (4, 0)}
So that is the correct option.
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Let (an)nen and (bn)nen be sequences in R. Suppose that |an< 135642 for all n e N and the sequence (bn)nen converges to 0. Prove that the sequence (an bn)nen is convergent.
The sequence (an bn)nen is convergent given that |an| < 135642 for all n e N and (bn)nen converges to 0.
To prove the convergence of the sequence (an bn)nen, we need to show that it is a Cauchy sequence. Let ε > 0 be arbitrary. Since (bn)nen converges to 0, there exists a natural number N such that |bn| < ε for all n ≥ N. Also, since |an| < 135642 for all n, we have
|an bn - am bm| = |an(bn - bm) + (an - am)bm|
≤ |an||bn - bm| + |an - am||bm|
< 135642ε + |an - am|ε
We can make the first term less than ε/2 by choosing n and m large enough so that |bn - bm| < ε/(2×135642), which is possible by the convergence of (bn)nen to 0.
For the second term, we can make it less than ε/2 by choosing n and m large enough so that |an - am| < ε/(2M), where M is any upper bound for the sequence (|an|)nen. Then we have
|an bn - am bm| < ε
for all n, m ≥ max(N, N') where N' corresponds to ε/(2M). Therefore, the sequence (an bn)nen is a Cauchy sequence, and since R is complete, it converges to some limit L.
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What is the value of a
Answer:
The value of a is 2 since 2/4 = 1/2.
whats -12(-36 = i have to pass math class, if i dont im going to fail
Answer:
432
Step-by-step explanation:
-12(-36) = 432
Kylie and Reuben are on the same mountain side with a uniform slope connecting the two of them. Find the point that is exactly halfway in-between Kyle and Reuben along the slope of the mountain.
Assume that Alpha and Beta are the only sellers of a product and they do not cooperate. Each firm has to decide whether to raise the product price. The payoff matrix below gives the profits, in dollars, associated with each pair of pricing strategies. The first entry in each cell shows the profits to Alpha, and the second, the profits to Beta.Assuming both firms know the information in the matrix, which of the following correctly describes the dominant strategy of each firm? a) Alpha: Do not raise price Beta: Do not raise Price b) Alpha: Do not raise Price Beta: Raise price c) Alpha: Raise Price Beta: No dominant strategy d) Alpha: Raise price Beta: Do not raise price e) Alpha: no dominant strategy Beta: Raise Price
Based on the given information in the matrix, you should compare the profits of each firm in the different scenarios to identify their dominant strategies. The correct option would be the one that matches the conditions mentioned above for each firm's dominant strategy.
To determine the dominant strategy for each firm, we will analyze the payoff matrix and compare the profits for each firm under different scenarios. A dominant strategy is one that provides a higher payoff for a firm, no matter what the other firm chooses to do.
Payoff Matrix:
(A1, B1): Alpha raises price, Beta raises price
(A2, B2): Alpha raises price, Beta does not raise price
(A3, B3): Alpha does not raise price, Beta raises price
(A4, B4): Alpha does not raise price, Beta does not raise price
Let's analyze Alpha's strategies first:
- If Beta raises the price, Alpha's profits are A1 (raise price) and A3 (do not raise price).
- If Beta does not raise the price, Alpha's profits are A2 (raise price) and A4 (do not raise price).
Alpha's dominant strategy:
If A1 > A3 and A2 > A4, Alpha should raise the price.
If A1 < A3 and A2 < A4, Alpha should not raise the price.
Now, let's analyze Beta's strategies:
- If Alpha raises the price, Beta's profits are B1 (raise price) and B2 (do not raise price).
- If Alpha does not raise the price, Beta's profits are B3 (raise price) and B4 (do not raise price).
Beta's dominant strategy:
If B1 > B2 and B3 > B4, Beta should raise the price.
If B1 < B2 and B3 < B4, Beta should not raise the price.
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A shelf using 2 boards she found the 1st board is 7⁄10 of a meter long the second board is 23/100 of a Meter long what is the Combine Lenght in meters of the 2 boards
The combined length of two boards is 93/100 or 0.93 of a meter based on the length of two boards.
The combined length of the two boards will be calculated by finding sum of their lengths. The formula that will form is -
Combined length = length of first board + length of second board
Keep the values in formula
Combined length = 7/10 + 23/100
Solving the sum
Total length = (7×10) + 23/100
Solving the parenthesis
Combined length = (70 + 23)/100
Performing addition
Total length = 93/100
Thus, the combined length of the shelf is 93/100 of a meter.
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Find the volume of the cone. Express your answer in terms of .
Radius of 6mm
Height if 28 mm
Answer:
The volume of the cone is approximately 1051.2 cubic millimeters (mm^3).
Step-by-step explanation:
The formula for the volume of a cone is given as V = (1/3) * π * r^2 * h, where r is the radius of the circular base of the cone, h is the height of the cone, and π is the mathematical constant pi.
Substituting the given values, we get:
V = (1/3) * π * (6mm)^2 * 28mm
V = (1/3) * π * 216mm^3 * 28mm
V = (1/3) * π * 6048mm^3
V = (π/3) * 6048mm^3
Hence, the volume of the cone is (π/3) * 6048mm^3, which is the exact answer. If you need an approximate decimal answer, you can use a calculator and substitute the value of π as 3.14159 to get V ≈ 20,107.06mm^3 (rounded to two decimal places).
Answer:V≈1.06×10-6m³
r= Radius 6mm
h= Height 28mm
Unit Conversion:
r=6×10-3m
h=0.028m
Solution
V=πr2h
3=π·6×10-32·0.028
3≈1.05558×10-6m³
There is a picnic table located along Path A. The table is located 1.5 miles along the path from the campsite. Which map shows the picnic table in the correct location?
The map that shows the picnic table in the correct location is illustrated below.
Firstly, we need to understand the concept of scale on a map. Maps are often drawn to scale, which means that the distances between different points on the map represent a proportional distance in real life. For instance, if one inch on the map equals one mile in real life, then two inches on the map would represent two miles in real life.
To do this, we need to locate the campsite on the map and measure out 1.5 miles along Path A. Once we have done this, we can mark this location on the map as the location of the picnic table.
However, we need to make sure that we are using a map that is drawn to scale. Otherwise, we might not be able to accurately measure the distance and locate the picnic table correctly.
Therefore, we need to examine the different maps that we have and find one that is drawn to scale. Once we have found a suitable map, we can measure out the distance from the campsite to the location of the table along Path A, and mark it on the map.
Finally, we can compare the location we have marked on the map with the location of the table as described in the problem. If they match up, we have found the correct location of the table on the map.
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There is a bag filled with 3 blue, 4 red and 5 green marbles.
A marble is taken at random from the bag, the colour is noted and then it is not replaced.
Another marble is taken at random.
What is the probability of getting exactly 1 blue?
The probability of getting exactly 1 blue marble is 9/22 or approximately 0.409.
The probability of getting exactly 1 blue marble can be calculated in two steps:
Step 1: The probability of drawing a blue marble on the first draw is:
P(Blue on first draw) = 3/12
After drawing a blue marble, there will be 2 blue, 4 red, and 5 green marbles left in the bag.
The probability of drawing a non-blue marble on the second draw is:
P(Non-blue on second draw) = 9/11
Alternatively, if a non-blue marble is drawn first, there will be 3 blue, 4 red, and 4 green marbles left in the bag. The probability of then drawing a blue marble on the second draw is:
P(Blue on a second draw after non-blue on the first draw) = 3/11
So the probability of getting one blue and one non-blue marble on the first and second draws in any order is:
P(One blue and one non-blue) = P(Blue on first draw) × P(Non-blue on second draw) + P(Non-blue on first draw) × P(Blue on second draw after non-blue on first draw)
P(One blue and one non-blue) = (3/12) × (9/11) + (9/12) × (3/11) = 27/132
Step 2: There are two possible orders in which we can get exactly 1 blue marble is:
blue on the first draw and non-blue on the second draw, or non-blue on the first draw and blue on the second draw.
The probability of getting exactly 1 blue marble is:
P(Exactly 1 blue) = P(One blue and one non-blue) + P(One non-blue and one blue)
P(Exactly 1 blue) = 27/132 + 27/132 = 54/132
Simplifying, we get:
P(Exactly 1 blue) = 9/22
Therefore, the probability of getting exactly 1 blue marble is 9/22 or approximately 0.409.
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A merchant bought an item for $50.00 and sold it for 30% more. For what price did the merchant sell the item?
If a merchant bought an item for $50.00 and sold it for 30% more (markup), the item's selling price was $65.00.
What is the markup?The markup is the percentage or amount by which an item is sold.
The markup is based on the cost price. After adding the markup amount, the selling price is determined to generate some profits for the seller.
The purchase price of an item = $50.00
The markup = 30%
Markup factor = 1.3 (1 + 0.3)
The selling price of the item = $65.00 ($50.00 x 1.3)
Thus, for adding 30% more (markup) on the cost of the item, the selling price is determined as $65.00.
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Find dy/dx for the following function, simplifying your answare as much as possible. (v) y = ttan x - phi kuadrat
The derivative of the function y = t*tan(x) - phi^2 with respect to x is dy/dx = t*sec^2(x).
Find the derivative dy/dx for the given function y = tan(x) - phi^2. Please note that there seems to be a typo in the function, so I'll assume that "phi kuadrat" should be "phi squared" and rewrite the function as y = t*tan(x) - phi^2.
To find the derivative dy/dx, we'll apply the rules of differentiation to each term separately:
1. Differentiate tan(x) with respect to x:
Since t is a constant, we only need to differentiate tan(x) which is sec^2(x). So, the derivative of t*tan(x) is t*sec^2(x).
2. Differentiate phi^2 with respect to x:
Since phi^2 is a constant, its derivative is 0.
Now, combine the derivatives of both terms:
dy/dx = t*sec^2(x) - 0
Simplify the answer:
dy/dx = t*sec^2(x)
So, the derivative of the function y = t*tan(x) - phi^2 with respect to x is dy/dx = t*sec^2(x).
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You frop a ball off a 50-foot roof to see how long it will bounce. Wach bounce looses 10% of the height of its previous bounce. How high will the 8th bounce be in feet?
Answer:
[tex]50( {.9}^{8} ) = 21.52[/tex]
The 8th bounce will be about 21.52 feet high.
PLEASE HELP!! URGENT!! ITS DUE IN A FEW MINUTES PLEASEEE!!!
The solution to the equation 5 + 3x -7x(x+8) = 9-x is -20
How is this so?First, simplify
5 + 3x - 7x - 56 = 9-x
Simplifying further:
-4x - 51 = 9-x
-4x - 51 + x = 9
-3x - 51 = 9
-3x = 60
x = 60/-3
x = -20
based on the above, we can state that the solution the equation is -20
Note that an equation is a mathematical statement that includes the sign 'equal to' between two expressions with equal values. For instance, 3x + 5 equals 15. There are several sorts of equations, such as linear, quadratic, cubic, and so on.
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if ab is dilated by a scale factor of 2 centered at (3,5), what are the coordinates of the endpoints of its image, a9b9 ? (1) a9(27,5) and b9(9,1) (3) a9(26,8) and b9(10,4) (2) a9(21,6) and b9(7,4) (4) a9(29,3) and b9(7,21)
To find the coordinates of the endpoints of the image A'B' (A9B9) after dilation of AB by a scale factor of 2 centered at (3,5), follow these steps:
Step 1: Use the given scale factor (2) and center of dilation (3,5).
Step 2: Apply the dilation formula to the coordinates of the original points A and B. The formula for dilation with scale factor k centered at (h,k) is:
A'(x', y') = (h + k(x - h), k + k(y - k))
Step 3: Substitute the given options for A9 and B9 into the dilation formula and check which pair of coordinates satisfy the formula.
After applying the formula, it is determined that the coordinates of the endpoints of the image A9B9 after dilation with a scale factor of 2 centered at (3,5) are:
A9(21, 6) and B9(7, 4).
Option (2) is correct.
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what is the nearest interger to 0.87
Answer:
1
Step-by-step explanation:
This question is basically asking us to round 0.87 to the nearest integer, which is going to be a whole number in this case because 0.87 is positive. To do this, we're going to have to look at the digit in the tenths place; in this case, that digit is 8.
Is 8 closer to 10 or 0? Well, it's obviously closer to 10. So, we're going to round 0.87 up, bringing us to 1.
If that's confusing or you need more clarification, let me know. :)
Suppose that the duration of a particular type of criminal trial is known to be normally distributed with a mean of 22 days and a standard deviation of 6 days. Let X be the number of days for a randomly selected trial. Round all answers to 4 decimal places where possible. b. If one of the trials is randomly chosen, find the probability that it lasted at least 21 days. c. If one of the trials is randomly chosen, find the probability that it lasted between 21 and 27 days. d. 74% of all of these types of trials are completed within how many days? (Please enter a whole number)
74% of the trials are completed within 20 days (rounded to the nearest whole number).
b. To find the probability that a trial lasted at least 21 days, we need to find the area to the right of 21 under the normal curve. Using a standard normal table or calculator, we can find:
z = (21 - 22) / 6 = -0.1667
P(X ≥ 21) = P(Z ≥ -0.1667) = 0.5675
So the probability that a trial lasted at least 21 days is 0.5675.
c. To find the probability that a trial lasted between 21 and 27 days, we need to find the area between 21 and 27 under the normal curve. Again using a standard normal table or calculator, we can find:
z1 = (21 - 22) / 6 = -0.1667
z2 = (27 - 22) / 6 = 0.8333
P(21 ≤ X ≤ 27) = P(-0.1667 ≤ Z ≤ 0.8333) = 0.3454
So the probability that a trial lasted between 21 and 27 days is 0.3454.
d. We need to find the value of X such that 74% of the trials are completed within that number of days. Since the normal distribution is symmetric, we can find the z-score that corresponds to the 37th percentile (half of 74%). Using a standard normal table or calculator, we can find:
P(Z ≤ z) = 0.37
z = -0.3528
Now we can use the z-score formula to find X:
z = (X - μ) / σ
-0.3528 = (X - 22) / 6
X - 22 = -2.1168
X = 19.8832
So 74% of the trials are completed within 20 days (rounded to the nearest whole number).
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Answer is not 1 or 3 or 5.
How many ordered pairs (A,B), where A, B are subsets of {1,2,3,4,5), are there if: |A| + B = 4 1
The total number of ordered pairs (A,B) such that |A|+|B|=4 is:
1x5 + 10x6 + 10x10 + 5x1 = 141
So the answer is 141.
The problem is asking for ordered pairs (A,B), where A and B are subsets of {1,2,3,4,5} such that the cardinality (number of elements) of set A plus the cardinality of set B equals 4.
We can approach this problem by counting the number of ways to choose subsets A and B with the given cardinality and then multiply the results.
First, let's count the number of subsets of {1,2,3,4,5} with cardinality k, for k=0,1,2,3,4,5.
k=0: there is only one subset with no elements, the empty set.
k=1: there are 5 subsets with one element, namely {1},{2},{3},{4},{5}.
k=2: there are 10 subsets with two elements, namely {1,2},{1,3},{1,4},{1,5},{2,3},{2,4},{2,5},{3,4},{3,5},{4,5}.
k=3: there are 10 subsets with three elements, namely {1,2,3},{1,2,4},{1,2,5},{1,3,4},{1,3,5},{1,4,5},{2,3,4},{2,3,5},{2,4,5},{3,4,5}.
k=4: there are 5 subsets with four elements, namely {1,2,3,4},{1,2,3,5},{1,2,4,5},{1,3,4,5},{2,3,4,5}.
k=5: there is only one subset with five elements, the whole set {1,2,3,4,5}.
Next, let's count the number of ordered pairs (A,B) such that |A|=k and |B|=4-k, for k=0,1,2,3,4.
k=0: there is only one subset A with no elements, and only one subset B with 4 elements, so there is only one possible ordered pair (A,B).
k=1: there are 5 possible subsets A and 1 possible subset B, so there are 5 possible ordered pairs (A,B).
k=2: there are 10 possible subsets A and 6 possible subsets B, so there are 60 possible ordered pairs (A,B).
k=3: there are 10 possible subsets A and 10 possible subsets B, so there are 100 possible ordered pairs (A,B).
k=4: there are 5 possible subsets A and 1 possible subset B, so there are 5 possible ordered pairs (A,B).
Therefore, the total number of ordered pairs (A,B) such that |A|+|B|=4 is:
1x5 + 10x6 + 10x10 + 5x1 = 141
So the answer is 141.
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A group of 10 Science Club students is on a field trip. That number of students represents 20% of the total number of students in the Science Club. What is the total number of students in the Science Club?
Choices:
A 20
B 30
C 50
D 80