Answer:
3/4 or 0.75
Step-by-step explanation:
Rewrite (156 + 243) using factoring
A. 3(52 + 81)
B. 6(24 + 40)
C. 12(13 + 21)
D. 18(9 + 13)
) assembly comprises 769 team members. given that tmm operates two shifts a day, and assembly has 353 stations, what is the proportion of team members not assigned to one of the stations?
Among the 769 team members, 706 of them are assigned to operates in 2 shifts schedule. The proportion of team members not assigned to one of the stations is 63 / 769
Proportion means a share from total set being discussed.
Data from the given case:
- The assembly has 769 team members.
- The assembly has 353 stations
- At each station, there are 2 shifts operations.
Assuming that 1 person is assigned to 1 shift operation, then there will:
353 x 2 = 706 person assigned.
The remaining team members that not assigned is:
769 - 706 = 63 person.
Therefore, the share or the proportion of unassigned team members is:
63/769
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Point A(3, 5) was dilated, and the point after dilation was A'(6, 10). What was the scale factor used?
Answer:2 is the scale factor
Step-by-step explanation:
Please help me dont know the answer
Answer:
First answer is obtuse
The second answer is scalene
Step-by-step explanation:
Obtuse is when an angle is over 90
Scalene since all the angles are different, all the side lengths are different.
A group of people were asked if they owned a dog. 191 responded "yes", and 485 responded "no".Find the probability that if a person is chosen at random, they own a dog. 191485 294191 191676
Given:
There are given that the number of people who said yes is 191 and who said no is 485.
Explanation:
According to the given question:
The total number of people is:
[tex]191+485=676[/tex]That means the total outcome is 676.
Now,
The probability that the person is chosen own dog is:
[tex]P=\frac{The\text{ number of people who have their own dog}}{\text{Total number of outcomes}}[/tex]So,
[tex]P=\frac{191}{\text{6}76}[/tex]Final answer:
Hence, the correct option is C.
Answer:
191/676.
Step-by-step explanation:
The total number of people asked is 191 + 485
= 676.
So. the required probability
= number of people owning a dog/ total number of people
= 191/676.
Simplify by combining like terms. 9x + 6 - 4x - 2x + 1 - 15
9x + 6 - 4x - 2x + 1 - 15
9x - 4 x- 2x = (9-4-4)x = 3x
6 +1 -15 = -8
____________
Answer
3x -8
______________
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write the slope intercept form:through: (4, -5), perp. to x= -4
The line should be perpendicular to x = -4
x= -4 is a vertical line crossing the x axis at x= -4
The slope is undefined in x =-4
For an equation in slope intercept form, the general form is ;
y= mx + b where m is the slope and b is the y-intercept
So for any y value, x is always -4
Thus the slope for line x = -4 is not defined
A line perpendicular to x = -4 will thus be a horizontal line with slope 0
For the equation of this line
0= y--5/x-4
0 = y+5 /x-4
0{x-4} = y +5
0 = y+5
y= - 5
I need help asap and the coordinates are (1,3) (6,5)
I need the equation in point slope using either point I NEED HELP ASAPP
Answer: the Equation is y-3=0.4(x-1) or y-5=0.4(x-6).
Step-by-step explanation: I hope this helps.
A train ticket in a certain city is 3.00. People eho use the train also have the option of purchasing a frequent rider pass for 18.75 each month. With the pass, each ticket costs only 2.25. Determine the number of times in a month the train must be used so that the total monthly cost without the pass is the same as the total monthly cost with the pass.
The number of times for which the train must be used so that the monthly cost without the pass is same as with the pass is; 6.25 times.
How to solve Word Problems using algebraic expressions.It follows from the task content that the regular train ticket costs, 3.00.
Therefore, the cost for travelling x times with the month is; 3x.
On this note, for the total monthly cost without the pass to be same as that with the pass; the equation which must hold is;
3x = 18.75
x = 18.75/3
x = 6.25 times.
Therefore, after taking the train 6.25 times, the cost without the pass is same as that with the pass.
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a large industrial firm purchases several new word processors at the end of each year, the exact num- ber depending on the frequency of repairs in the previ- ous year. suppose that the number of word processors, x, purchased each year has the following probability distribution: x 0 1 23 f(x) 1/10 3/10 2/5 1/5 if the cost of the desired model is $1200 per unit and at the end of the year a refund of 50x2 dollars will be issued, how much can this firm expect to spend on new word processors during this year?
The money which is expected to spend on new word processors during this year is
The probability distribution is
x: 0 1 2 3
f(x) [tex]\frac{1}{10}[/tex] [tex]\frac{3}{10}[/tex] [tex]\frac{2}{5}[/tex] [tex]\frac{1}{5}[/tex]
If the cost of the desired model is $1200 per unit and at the end of the year a refund of 50x2 dollars
So total money spent in this year is [tex]1200x-50x^2[/tex]
Then the equation of expenses will be
[tex]\text{Expenses}=E(1200x-50x^2)[/tex]
We can rewrite it as
[tex]\text{Expenses}=E(1200x)-E(50x^2)[/tex]
[tex]\text{Expenses}=1200E(x)-50E(x^2)[/tex] -----------------(1)
Now the mean of the probability distribution is ,
[tex]E(x)=\sum_{ }^{ }((x_i)(f(x_i))\\=(0\times\frac{1}{10})+(1\times\frac{3}{10})+(2\times\frac{2}{5})+(3\times\frac{1}{5})\\=\frac{3}{10}+\frac{4}{5}+\frac{3}{5}\\\\=\frac{3+8+6}{10}\\\\=\frac{17}{10}\\\\=1.7[/tex]
The variance of the function is
[tex]E(x)=\sum_{ }^{ }(x_i^2)(f(x_i)[/tex]
[tex]=(0^2\times\frac{1}{10})+(1^2\times\frac{3}{10})+(2^2\times\frac{2}{5})+(3^2\times\frac{1}{5})[/tex]
[tex]=\frac{3}{10}+\frac{8}{5}+\frac{9}{5}[/tex]
[tex]=\frac{37}{10}[/tex]
[tex]=3.7[/tex]
On substituting the values in equation (1)
[tex]\text{Expenses}=1200E(x)-50E(x^2)[/tex]
[tex]=1200(1.7)-50(3.7)^2[/tex]
[tex]=2040-684[/tex]
[tex]=1855[/tex]
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1.5 x 10 9
8.9 x 10 7
a package boodins weighs 6.2 ounces. A package of rews weighs 9.97 ounces. how much more does a package of rews weigh than a package of boondins
Based on the package of boondins and the package of rews, the package of rews will have a weight in relation to the package of boondins that is 3.77 ounces
How to find the different in weights?To find how much more that the package of rews weighs over the boondins, deduct the weight of the package of boondins from the weight of a package of rews.
Weight of package of rews = 9.97 ounces
Weight of package of boondins = 6.2 ounces
The difference in the weight of the packages is:
= 9.97 - 6.2
= 3.77 ounces
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The required difference in the package of the bodies and rews is 3.77 ounces.
As per the given in the question,
boudin is 6.2 ounces in weight and rews are 9.97 ounces in weight.
here,
As per observation, rews weighs more than bodies, and the difference between their weights is simply evaluated from the subtraction between the weight. So,
Weigh difference = weigh of rews - weigh of boodins
Substitute the value in the above equation,
Weigh difference = 9.97 - 6.2 = 3.77.
Thus, the required difference in the package of the bodies and rews is 3.77 ounces.
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Which list shows the absolute values in order from greatest to least select each correct answer.
A: | 11 7/10 |, | 11 3/5 |, | 10 3/10 |
B: | -3 1/3 |, | -3 2/3 |, | 2 2/3 |
C: | -1 5/6 |, | 1 7/12 |, | 1 5/12 |
D: | -6 5/7 |, | -6 3/7 |, | 5 2/7 |
Please help I will give 100!
Step-by-step explanation:
A./11.7/,/22.6/,10.3/
11.7<22.6>10.3
B./-10.3/,/-10.7/,/7.3/
10.3<10.7>7.3
C./-2.5/,/1.42/,/1.25/
2.5>1.42>1.25
D./-9.3/,/-9/,/7.43/
9.3>9>7.43
therefore the answer is C and D
twenty-five percent of all automobiles undergoing an emissions inspection at a certain inspection station fail the inspection. (round your answers to three decimal places.) among 15 randomly selected cars, what is the probability that at most 5 fail the inspection?
The required probability is 0.852
Here, n=15
P(X ≤5) = P(X = 1)+...+ P(X = 5)
= [(¹⁵₀)(0.25)⁰ (1-025)¹⁵⁻⁰ +...(¹⁵₅)(0.25)⁵ (1-0.25)¹⁵⁻⁵]
= 0.01336+...+0.16515
= 0.85163
= 0.852 (Round to 3 decimal place)
Hence, the required probability is 0.852
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Select the correct answer. sean used cross multiplication to correctly solve a rational equation. he found one valid solution and one extraneous solution. if 1 is the extraneous solution, which equation could he have solved? a. the equation is = because 1 makes a denominator equal zero and is a solution of the equation derived from cross multiplying. b. the equation is = because 1 is a solution of both the original equation and the equation derived from cross multiplying. c. the equation is = is because 1 makes a numerator equal zero and is a solution of the equation derived from cross multiplying. d. the equation is = because 1 makes a denominator equal zero and is not a solution of the equation derived from cross multiplying.
The equation is = because 1 makes a denominator equal zero and is a solution of the equation derived from cross multiplying. A valid solution to a problem that vanished during the process of solving it is referred to as a missing solution.
What is extraneous equation?An extraneous solution in mathematics is a solution that develops during the process of addressing the problem but is not a legitimate solution to the problem, such as the answer to an equation. A valid solution to a problem that vanished during the process of solving it is referred to as a missing solution.
We have to open the equation by using cross multiplication
10(3x - 3) = 15(x² - 1)
= 30x - 30 = 15x² - 15
we would have to factorize
30(x-1) = 15(x-1)(x+1)
We have to divide by 15(x-1)
2 = x + 1
take the like terms
2 -1 = x
x = 1
Hence the equation that has the extraneous solution is option a because the solution is 1.
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Hello, I’m struggling with my geometry homework. It’s number 2
An inscribed circle is the largest circle contained in the polygon (triangle):
• Bisects two angles of the triangle.
,• The angle bisector will intersect at the intercenter.
Procedure
To draw the inscribed circle, we have to use the intercenter (O, in our case) as the center, pointing one of the compass points in O, and draw the circle touching the edges.
Use the following two points to answer parts a -c . (2, 3) , (- 1, - 6) a. Find the slope of the line passing through the two pointsb . Write an equation of a line passing through the two points in point slope form . c . Rewrite the equation of the line in slope -intercept form .
sSlope means the inclination of the line
Intercept is the point where the line touches the Y axis.
Jimmy thought he had purchased 7folders, but he had only purchased 6.What was his percent error? round to the nearest percent
We can define the percent error as the difference between the estimated value and the actual value, divided by the actual value.
In this case, the estimated value (what Jimmy thought he had purchased) is 7 and the actual value is 6.
Then, the percent error is:
[tex]e=\frac{E-A}{A}=\frac{7-6}{6}=\frac{1}{6}\cdot100\%=16.666\ldots\%\approx16\%[/tex]The percent error is 16%.
A model car is a 1/40 if the length of the real car is 5.5 m what is the length of the model car
Answer:
0.14 meters, or 140 mm
Step-by-step explanation:
(1/40) means that the model car will have dimensions that are (1/40) the original car.
Real car = 5.5 meters.
Model car = (1/40)*(5.5 m) = 0.14 meters, or 140 mm
A plant s 6.2cm tall.
The height of the plant increases by 11% each week
Find how tall the plant will be after 2 weeks
The height of plant will be 7.56cm tall after 2 weeks
How to calculate the height of the plant ?The original height of the plant is 6.2cm
The height increases by 11% each week
= 11/100
= 0.11
The increase of the plant in a week
= 0.11 × 6.2
= 0.682
The height of the plant after two weeks can be calculated as follows
= 0.682 + 0.682
= 1.364
= 6.2 + 1.364
= 7.56
Hence the height of the plant after 2 weeks is 7.56cm
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Writing the Equation of a Line in Different Forms
Write the equation of the line MN, which is formed by the
points M(-3, 5) and N(2, 0).
Step 1: Identify the slope. m = -1v
Step 2: Write the equation in point-slope form:
y-0= -1(x - 2)
y0 = -1(x + 2)
y-5=-1(x - 3)
y-5=-1(x + 3)
y - 5 = -1 ( x + 3 ) is Equation of a Lin in slope intercept form,.
What is in slope-intercept form?
Given the slope of the line and the intercept it forms with the y-axis, the slope intercept form in mathematics is one of the forms used to determine the equation of a straight line. Y = mx + b is the slope intercept form, where m is the slope of the straight line and b is the y-intercept.Slope between the points M(-3, 5) and N(2, 0).
m = 0 - 5/2 + 3
m = -5/5 = -1
the equation of point-slope form
y - y₁ = m ( x - x₁ )
y - 5 = -1 ( x - ( -3 ))
y - 5 = -1 ( x + 3 )
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Find the quotient and remainder using synthetic division.−x2 + x − 7x + 1quotient remainder
Given:
[tex]\begin{gathered} -x^2+x-7 \\ x+1 \end{gathered}[/tex]Required:
To find the quotient and remainder using synthetic division.
Explanation:
Consider
[tex]\begin{gathered} x+1=0 \\ x=-1 \end{gathered}[/tex][tex]\begin{gathered} -1|-1\text{ }+1\text{ }-7 \\ \text{ }|\text{ }+1\text{ }-2 \\ ------------------- \\ \text{ }-1\text{ }+2\text{ }-9 \\ \end{gathered}[/tex][tex]-x+2-\frac{9}{x+1}[/tex]Here the quotient is
[tex]-x+2[/tex]And the remainder is
[tex]-9[/tex]Final Answer:
Quotient :
[tex]-x+2[/tex]Remainder : -9.
Which equation can be rewritten as x + 4 = x²? Assume x > 0.
Answer:
We have been given an equation . We are also told that x is greater than 0. We are asked to choose the equation that can be written as our given equation.
Since x is greater than, so we will take positive root on both sides of our given equation as:
Upon looking at our given choices, we can see that option C is same as our answer.
Step-by-step explanation:Therefore, option C is the correct choice.
Answer:2=x
Step-by-step explanation:
x+4=x^2
0+4=x^2
Square root 4 = square root x^2
2=x
Write an equation in standard form of the line that passes through the given points.
7. (-3, 2); m = 1
Answer:
y=x+1
Step-by-step explanation:
y-y1=m(x-x1)
y-2=1(x+3)
y-2=x+3
y=x+1
suppose that the members of a student governance committee will be selected from the 40 members of the student senate. there are 18 sophomores, 12 juniors and 10 seniors who are members of the student senate. in how many ways can the governance committee be selected, if it must be made up of 2 sophomores, 2 juniors and 3 seniors? assume that each of the sophomores, each of the juniors and each of the seniors is equally likely to be selected for the committee. a. 339 b. 1211760 c. 2160 d. 18643560 e. 25920
Assuming that each of the sophomores, each of the juniors and each of the seniors is equally likely to be selected for the committee, there are b. 1211760 ways can the governance committee be selected, if it must be made up of 2 sophomores, 2 juniors and 3 seniors. The committee can be selected in 1,211,760 ways.
Combination formula:
Cn,x is the number of different combinations of x objects from a set of n elements, given by:
Cnₓ= n!÷ x! (n-x!)
In this problem:
2 sophomores from a set of 18.
2 juniors from a set of 12.
3 seniors from a set of 10.
They are independent, so we can just multiply them, thus:
T= C₁₈,₂ × C₁₂,₂× C₁₀,₃ = 18! ÷2!6! × 12!÷ 2!10! × 10!÷ 3!×7! = 1211760
The committee can be selected in 1,211,760 ways.
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What is the center of the hyperbola?
(y+3)^2/9 − (x−2)^2/2 = 1
Enter your answer by filling in the boxes.
The center of the hyperbola is (2, -3)
What is an hyperbola?A hyperbola is a curve that is open and that has two branches and it is symmetrical
How to solve the center of the hyperbola?The equation is given as
(y + 3)²/9 − (x − 2)²/2 = 1
A hyperbola is represented as
(y - k)²/a² − (x − h)²/b² = 1
Where the center of the hyperbola has the coordinates of (h, k)
The values of h and k in the given equation (y + 3)²/9 − (x − 2)²/2 = 1 are
h = 2 and k = -3
This means that:
(h, k) = (2, -3)
So, we have coordinates of the center to be (2, -3)
Hence, the center is (2, -3)
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The area of a rectangular room is 750 square feet. The width of the room is 5 feet less than the length of the room. Which equations can be used to solve for y, the length of the room? Select three options. y(y + 5) = 750 y2 – 5y = 750 750 – y(y – 5) = 0 y(y – 5) + 750 = 0 (y + 25)(y – 30) = 0
Answer:
The three options you would pick is
y2 – 5y = 750
750 – y(y – 5) = 0
(y + 25)(y – 30) = 0
Step-by-step explanation:
Hope this helps! :))
I figured x equals a specific number in every single question involving something like this. X is on all sides, there's no given number.
The angle x of the triangle is 60 degrees.
How to find the angles in a triangle?A triangle is a polygon with three sides. The sum of angles in a triangle is equals to 180 degrees.
A triangle can be classified base on the sides and angles. For example equilateral triangle, scalene triangle and isosceles triangle.
Therefore, the angle x of the triangle can be found as follows:
x + x + x = 180
3x = 180°
divide both sides of the equation by 3
3x / 3 = 180 / 3
x = 180 / 3
x = 60 degrees.
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Answer:
the person below or above me is the answer. Yeah
Step-by-step explanation:
Write your answer as a fraction in simplest form.
910+(−45)=
Answer:
-44.09
Step-by-step explanation:
Trust bro i am passing collage math at 15
NOBODY'S ANSWERING MY QUESTION, HELLO? I WILL GIVE BRAINLIEST :(
Answer:B
Step-by-step explanation:
Answer:
(C) I and III only.
Step-by-step explanation:
Hello! It's me again! Let's help you with this question too!
Now, let's start understanding what information is given to us.
[tex]a < b < 0[/tex]
This means that, some integer a is lower than some integer b and b is lower than 0. So right out of the gate, both integer a and b are both negative numbers. Here, we can evaluate all 3 possibilities like so:
I. [tex]\frac{a}{b} > 0[/tex]
To start, let's see if this is true. The simplest way is to substitute values into integer a and b to where [tex]a < b < 0[/tex] holds true as well. For this example, we can say [tex]a=-2[/tex] and [tex]b=-1[/tex]. If we evaluate as such, it would be:
[tex]\frac{-2}{-1} > 0[/tex]
[tex]2 > 0[/tex]
From this example, 2 is higher than 0. Meaning this is true. Now, it'll be true for every value due to something called the fraction rule. Fraction rule is simply just stating that, if the numerator and denominator both have a negative sign, they cancel each other out and become a positive fraction. So, we can say I. is true.
II. [tex]-b > -a[/tex]
This is simple to prove, all it's saying is that negative integer b is always going to be higher than negative integer a. Using our same example from I. we can substitute as such and evaluate:
[tex]-(-1) > -(-2)[/tex]
[tex]1 > 2[/tex]
Here, we can see that 1 is not greater than 2 and no matter what numbers you substitute, that will always be the case because you're essentially putting the lowest number first and seeing if it's greater than the lower number. So II. is false.
III. [tex]0 < \frac{b}{a} < 1[/tex]
Now this one is a bit more difficult. However, there isn't much we need to do here. This is saying that 0 is lower than [tex]\frac{b}{a}[/tex] but [tex]\frac{b}{a}[/tex] is lower than 1. Let's split this into 2 parts.
Part 1: [tex]0 < \frac{b}{a}[/tex]
This isn't the same as I. as the numerator and denominators have switched. Let's use the values we've set back in I. to see if this holds true:
[tex]0 < \frac{-1}{-2}[/tex]
[tex]0 < \frac{1}{2}[/tex]
From here, we find that it is true. And it also holds true that it is less than 1. We can use another set of values to see if this still holds. Let's try [tex]a=-7[/tex] and [tex]b=-3[/tex]:
[tex]0 < \frac{-3}{-7}[/tex]
[tex]0 < \frac{3}{7}[/tex]
As you can see here, using the fraction rule. So long as there is an integer a and b are different (they always will be because of [tex]a < b < 0[/tex]), regardless of what they will be, it will always give us a fraction answer. And a fraction answer will always be lower than 1. Therefore, III. is also true.
So, the answer to this question is C. I and III only