Given
Principal = $8,000
Rate = 3%
Time = 48 years
Find
Amount at the end of the 48 years
Explanation
Amount = Simple interest + Principal
Simple Interest is given by
[tex]S.I=\frac{P\times R\times T}{100}[/tex]now substitute the values ,
[tex]\begin{gathered} S.I=\frac{8000\times3\times48}{100} \\ \\ S.I=11520 \end{gathered}[/tex]amount = 11,520 + 8000 = $19,520.00
Final Answer
Therefore , the amount at the end of the 48 years will be $19,520.00
If a red and a blue fair six sided die are rolled what is the probability the result is 8 or divisible by 3?
SOLUTION:
Step 1:
In this question, we are given that;
If a red and a blue fair six-sided die are rolled.
What is the probability the result is 8 or divisible by 3?
Step 2:
The table for the two dice rolled together is as shown below:
Green 1 2 3 4 5 6
Red
1 2 3 4 5 6 7
2 3 4 5 6 7 8
3 4 5 6 7 8 9
4 5 6 7 8 9 10
5 6 7 8 9 10 11
6 7 8 9 10 11 12
Step 3:
The probability that the result is 8 =
[tex]\begin{gathered} =\text{ }\frac{\nu mber\text{ of 8}}{\text{Total number }} \\ =\text{ }\frac{5}{36} \end{gathered}[/tex]Next,
The probability that the result is divisible by 3
=
[tex]\frac{12}{36}[/tex]Finally, the probability that the result is 8 or divisible by 3, we have that:
[tex]\frac{5}{36}+\frac{12}{36}\text{ =}\frac{17}{36}[/tex]
Solve the inequality -30 10-40x and write the solution using:
Inequality Notation:
Answer:
Step-by-step explanation:
Lindsay gets paid $15 per hour at her job. If we let s be her salary and h be the number of hours she has worked, write an equation that represents the direct variation.
A linear function or a direct variation function is represented by:
[tex]y=kx[/tex]where k is the constant rate of chante, in this case $15 per hour.
s=y= salary of Lindsay
h=x= hours she has worked
Then, the equation that represents the situation would be:
[tex]s=15h[/tex]DATE IN OUT IN OUT HOURS TEMPORARY EMPLOYEE TIME CARD NAME: Eugene Mueller 8/8 7:00 4:10 8/9 6:50 11:00 DEPT Sales 8/10 8/11 12:00 4:35 Note: No overtime rate. 10:55 3:25 EMPLOYEE SIGNATURE RATE per hour: $8.50 TOTAL HOURS:
7(x+2)=
4(x+4)=
9(x+6)=
Answer:
Step-by-step explanation:
7(x+2) = 7x+14
7(x+2)=7x+7 times 2
4(x+4)= 4x+16
4 times x = 4x
4 times 4 = 16
= 4x+16
9(x+6) = 9x+54
9 times x = 9x
9 times 6 = 54
= 9x+54
I need help solving
This problem
Weight required to destroy a bridge cable (in ponds) The type of variable is Nominal Categorical
A frequently used category variable is gender. Categorical variables can either be ordinal or numeric.
The closing price (in dollars) of the stock is a quantitative variable, and since the price involves an absolute zero, the scale of measurement is a ratio scale
Pounds is what type of variable?
Weight is a prime example of a ratio variable (e.g., in pounds). With certainty, we may state that 20 pounds weigh twice as much as 10 pounds. Ratio variables also have an important zero-point (e.g., exactly 0 pounds means the object has no weight)..
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In Abc,AB=5 feet and BC=3 feet.Which inequality represents all possible values for the length of AC,in feet?
The smallest value of length AC would be 5 ft - 3 ft = 2 ft while the largest length would be 5 ft + 3 ft = 8ft. The answer will be
2 < Ac < 8
0 1 2 3 4 5 6 7 8 9 100 1 2 3 4 5 6 7 8 9 100 1 2 3 4 5 6 7 8 9 10401234 5 6 7 8 9 10OB.C.OD. +Reset Selection
Okay, here we have this:
Considering the provided inequation, we are going to identify how can be represented on a number line, so we obtain the following:
So the first thing we will do is factor to find the solution intervals, we have:
[tex]\begin{gathered} 3x^2-27x\leq0 \\ x(x-9)\leq0 \\ 0\leq x\leq9 \end{gathered}[/tex]According to this, we finally obtain that the solution interval is option D, because it satisfies the found interval and its endpoints are closed.
True or False? Every rectangle is a parallelogram. Every rhombus is a parallelogram. Every quadrilateral is a square. Every rectangle with four congruent sides is a square. X S True O False True O False O True False O True O False ?
Given: Different statement relating different quadrilateral
To Determine: If true or false statement
Solution
The image below summarizes the properties of a quadrilateral
From the above, we can conclude that
Kathryn needs to include a scale drawing of a race car on her science science fair project. Her actual race car is 180 inches long and 72 inches tall. if she uses a scale factor of 1 inch= 8 inches, what will the dimensions of her scale drawing?
To find the scaled measures of the race car, you have to divide the original measures by the scale. This is:
[tex]\text{length}=\frac{182in}{8}=22.75in[/tex][tex]\text{height}=\frac{72in}{8}=9in[/tex]So the scaled measures of the race car are: length=22.75in and height=9in
A whole pizza is cut into twelfths. If Dexter eats 1/2 of the pizza and Landry eats 1/3 of the pizza, then 3 what fraction of the pizza remains?
Explanation
Step 1
Let
A whole pizza = 1 pizza
Dexter eats 1/2
Landry eats 1/3
x= fraction of the pizza remains
Step 2
the r
Vincent turned his head 30° to the side. Which of the following shows the angle that he turned his head?
Given data:
Vincent turned his head 30° to the side.
The figure in the option b is the angle that he turned his head.
Question 5 of 10 Solve the proportion below. 23 A 6 B. 8 C. 9 D.
solve for x
[tex]\begin{gathered} 12.6\times\frac{x}{12.6}=\frac{5}{7}\times12.6 \\ x=\frac{63}{7}=9 \end{gathered}[/tex]answer: C. 9
2)Find the missing coordinate (5, 7) and (8,y); m= 4/3
Answer:
y = 11
Step-by-step explanation:
Hello!
We can utilize the slope formula to create the equation for y:
[tex]\frac{y - 7}{8 - 5} = \frac{4}{3}[/tex]Solve for y[tex]\frac{y - 7}{8 - 5} = \frac{4}{3}[/tex][tex]\frac{y - 7}{3} = \frac{4}{3}[/tex] => Simplifyy - 7 = 4 => Multiply both sides by 3y = 11 => Add 7 to both sidesThe value of y is 11.
Fifth grade > Y.5 Compare and convert Which is more, 1/2 of a pound or 6 ounces? of a pound 2. 6 ounces neither; they are equal Submit
We should know that :
1 pound = 16 ounces
The question is :
Which is more, 1/2 of a pound or 6 ounces?
so,
1/2 of a pound = 1/2 x 16 = 8 ounces
So,
8 ounces > 6 ounces
so, the answer is option 1
The more is 1/2 of a pound
What is the distance between (-5, 5) and (1, -2)
Answer:
[tex]\displaystyle d=\sqrt{85}\text{, or about 9.22 units}[/tex]
Step-by-step explanation:
We will use the distance formula to solve.
[tex]\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}[/tex]
[tex]\displaystyle d=\sqrt{(1--5)^2 +(-2-5)^2}[/tex]
[tex]\displaystyle d=\sqrt{(6)^2 +(-7)^2}[/tex]
[tex]\displaystyle d=\sqrt{36+49}[/tex]
[tex]\displaystyle d=\sqrt{85}\text{, or about 9.22 units}[/tex]
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A major record label has seen its annual profit decrease in recent years. In 2011, the label's profit was $128 million. By 2015, the label's profit had decreased by 30%.What was the record label company's profit in 2015? million dollars Suppose the record label wants to increase its profit to $128 million by 2017. By what percent must the label's profit increase from its 2015 value to reach $128 million within the next two years? %
the company's profit in 2015 was $89,600,000 (89.6 million dollars)
43%
Explanation:
Profit in 2011 = $128 million
Profit in 2015 decreased by 30%
% decrease = (old price - new price)/old price
old price = Profit in 2011 , new price = Profit in 2015
30% = (128,000,000 - new price)/128000000
[tex]\begin{gathered} 30percent=\text{ }\frac{128,000,000 -newprice}{128000000} \\ 0.30\text{ = }\frac{128,000,000-newprice}{128000000} \\ \text{cross multiply:} \\ 0.3(128,000,000)\text{ = }128,000,000-newprice \end{gathered}[/tex][tex]\begin{gathered} 38400000\text{ = }128,000,000-newprice \\ \text{subtract }38400000\text{ from both sides:} \\ 38400000-\text{ }38400000\text{ = }128,000,000-38400000-newprice \\ \text{0 = 89600000 }-newprice \\ newprice\text{ = 89600000 } \end{gathered}[/tex]Hence, the company's profit in 2015 was $89,600,000 (89.6 million dollars)
Percentage increase = (new price - old price)/old price
new price = 128million dollars , old price = 89.6 million dollars
% increase = [(128 - 89.6)in millions/(89.6) in millions] × 100
% increase = 38.4/89.6 × 100
% increase = 0.43 × 100
% increase = 43%
Hence, the label's profit must increase by 43% from its 2015 value to reach $128 million within the next two years
Recipe A calls for 2 cups of sugar and makes 48 cookles. Recipe B calls for 3 cups of sugar and makes 54 of the same sized cookies. Determine which recipe contains more sugar in each cookle. Use complete sentences to explain your reasoning.
we are given two recipes for cookies and we are asked which of the two contains more sugar. To do that we need to find the amount of sugar per cookie for each recipe.
For recipe A we have:
[tex]2cups\rightarrow48cookies[/tex]This means:
[tex]\frac{2cups}{48cookies}=\frac{1}{24}\frac{cups}{cookies}[/tex]For recipe B we have:
[tex]3cups\rightarrow54\text{cookies}[/tex]This means:
[tex]\frac{3\text{cups}}{54\text{cookies}}=\frac{1}{18}(\frac{cups}{cookies})[/tex]Since 1/18 is greater than 1/24, this means that there is more sugar per cookie in recipe B than in recipe A.
Translate into a number sentence7. Four less than seven is greater than zero
In order to translate the words into a number sentence, first let's translate each word or expression separately:
Four less than seven: "7 - 4"
Is greater than: ">"
Zero: "0"
Therefore the number sentence will be:
[tex]7-4>0[/tex]what is the nessecary information you need to know about a cube?
Answer: the width, length and height
Step-by-step explanation: multiply the width length and height of a cube and you get the area
7.2. I have a question about advanced trig equations that I really need help with picture included
1) Let's start out isolating the cosine by dividing both sides by 2
[tex]\begin{gathered} 2\cos \mleft(\theta\mright)=\sqrt{3} \\ \frac{2\cos\left(θ\right)}{2}=\frac{\sqrt{3}}{2} \\ \cos \mleft(\theta\mright)=\frac{\sqrt{3}}{2} \\ \end{gathered}[/tex]2) From that we can find two general solutions in which the cosine of theta yields the square root of 3 over two:
[tex]\begin{gathered} \cos (30^{\circ})or\cos (\frac{\pi}{6})\text{ and }cos(330^{\circ}or\frac{11}{6}\pi)=\frac{\sqrt[]{3}}{2} \\ \theta=\frac{\pi}{6}+2\pi n,\: \theta=\frac{11\pi}{6}+2\pi n \end{gathered}[/tex]But not that there is a restraint, so we can write out the solution as:
[tex]\theta=\frac{\pi}{6},\: \theta=\frac{11\pi}{6}[/tex]Add.
47+13
Enter your answer as a fraction in simplest form by filling in the boxes.
Answer: 47+13 =60
60 as a fraction should be 3/5 in simplest form.
Step-by-step explanation:
A square pyramid has a volume of 108 cubic feet and a height of 4 feet.What is the length of each side of the base of the pyramid?A 4 ftOLOB. 9 ftC. 18 ftD. 27 ftO E. 81 ftHelp please very hard
okay so the answer is 9ft so option B
now we can take a look at how we arrived to that answer
do you know the formula for the volume?
Find the mean for this set of data. Write your answer as a decimal roundedto the nearest TENTH.32, 23, 34, 29, 15, 17, 23
Given:
The set of data is given as
[tex]32,23,34,29,15,17,23[/tex]Required:
To find the mean.
Formula:
[tex]\text{Mean(}\bar{\text{X}})=\frac{\Sigma x}{n}[/tex]Explanation:
Mean is the ratio of the sum of the values and the number of values.
No of values in the given data is 7.
[tex]n=7[/tex][tex]\begin{gathered} \text{Mean}=\frac{32+23+34+29+15+17+23}{7} \\ =\frac{173}{7} \\ =24.7 \end{gathered}[/tex]Final Answer:
[tex]\text{Mean}=24.7[/tex]
14#An ecologist randomly samples 12 plants of a specific species and measures their heights. He finds that this sample has a mean of 14 cm and a standard deviation of 4 cm. If we assume that the height measurements are normally distributed, find a 95% confidence interval for the mean height of all plants of this species. Give the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.)Lower limit:Upper limit:
Answer:
Lower limit: 11.7 cm
Upper limit: 16.263
Explanation:
The formula to find the lower and upper limits of the confidence interval (given the data is normally distributed) is :
[tex]CI=\mu\pm Z^*\frac{\sigma}{\sqrt{n}}[/tex]Where:
• μ = sample mean
,• σ = sample standard deviation
,• Z* = critical value of the z-distribution
,• n = is the sample size
In this case:
• μ = 14cm
• σ = 4cm
,• n = 12
The critical value of the z-distribution for a confidence interval of 95% is Z* = 1.96
Now, we can use the formula above to find the upper and lower limit:
[tex]CI=14\pm1.96\cdot\frac{4}{\sqrt{12}}=14\pm\frac{98\sqrt{3}}{75}=\frac{1050\pm98\sqrt{3}}{75}[/tex]Thus:
[tex]Lower\text{ }limit=\frac{1050-98\sqrt{3}}{75}\approx11.736cm[/tex][tex]Upper\text{ }limit=\frac{1050-98\sqrt{3}}{75}\approx16.263cm[/tex]Rounded to one decimal:
Lower limit: 11.7cm
Upper limit: 16.3cm
write an expression such that if you apply the distributive property to your expression it would give the same result presented. 8x + 12
Solution:
Let's find a expression such that if you apply the distributive property to your expression it would give the same result presented:
• 8x + 12 = 2 (4x + 6)
,• 8x + 12 = 4 (2x + 3)
,• 8x + 12 = 8 (x + 1.5)
Any of these expressions could be the solution to the question.
Write the nth rule for the following geometric sequence. Then find the fifth term. (you are given the first term and the common ratio)1-
The formula for determining the nth term of a geometric sequence is expressed as
Tn = ar^(n - 1)
Where
a represents the first term
r represents the common ratio.
n represents the number of terms
From the information given,
a = 2, r = 3
Thus, the rule for the nth term of the geometric sequence is
Tn = 2 x 3^(n - 1)
To determine the fifth term, we would substitute n = 5 into the equation. It becomes
T5 = 2 x 3^(5 - 1)
T5 = 2 x 3^4
T5 = 162
The fifth term is 162
6. Refer to the graph in question 5A) graph -f(x)B) graph f(x) -2
Given the graph of f(x):
Where the points A, B, and C have the coordinates:
[tex]\begin{gathered} A=(0,-2) \\ B=(3,2) \\ C=(5,2) \end{gathered}[/tex]Now, the transformation -f(x) is just a reflection about the x-axis. This is equivalent to a change of sign on the y-coordinate. The new points A', B', and C' are:
[tex]\begin{gathered} A^{\prime}=(0,2) \\ B^{\prime}=(3,-2) \\ C^{\prime}=(5,-2) \end{gathered}[/tex]And the graph looks like this:
Now, for the f(x) - 2 transformation, we see that this is just a shift of 2 units down. Then:
Where:
[tex]\begin{gathered} A^{\prime}^{\prime}=(0,-4) \\ B^{\prime}^{\prime}=(3,0) \\ C^{\prime}^{\prime}=(5,0) \end{gathered}[/tex]Write an equation of the line with the given slope and y-intercept.
Slope
1
6
, y−intercept (0, −2)
The equation of line is [tex]6y=6x$-$12[/tex].
The given slope is [tex]\frac{1}{6}[/tex].
The [tex]y $-$[/tex]intercept is [tex](0, $-$2)[/tex].
We have to write the equation of line using the given slope and [tex]y $-$[/tex]intercept.
The equation of line with the slope m and [tex]y $-$[/tex]intercept of [tex](0,a)[/tex] is [tex]y=mx+a[/tex].
From the question,
The value of [tex]m=\frac{1}{6}[/tex]
The value of [tex]a= $-$2[/tex]
Now putting the value of [tex]m[/tex] and [tex]a[/tex] in the equation of line.
[tex]y=\frac{1}{6}x+( $-$2)\\y=\frac{1}{6}x$-$2[/tex]
Multiply by [tex]6[/tex] on both side
[tex]y\times6=6\times(\frac{1}{6}x$-$2)\\6y=6\times\frac{1}{6}x$-$6\times2\\6y=6x$-$12[/tex]
The equation of line is [tex]6y=6x$-$12[/tex].
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Suppose that the future price p(t) of a certain item is given by the following exponential function. In this function, p(t) is measured in dollars and t is the number of years from today. p(t) = 3000 * (1.019) ^ t
The growth or decay of an original quantity C that increases or decreases in a p% per year after t years is given by the following equation:
[tex]p(t)=C\cdot(1\pm\frac{p}{100})^t[/tex]If the quantity increases (i.e. it growths) we use the + symbol inside the parenthesis. If the quantity decreases we use the - symbol. This implies that for a growth the term that is raised to t is greater than 1 and for a decay that term is smaller than 1.
Now let's compare that generic equation with the function given by the question:
[tex]3000\cdot(1.019)^t=C\cdot(1\pm\frac{p}{100})^t[/tex]One of the first things you can notice is that C=3000 which means that the initial price was $3000. Just to be sure that this is correct we can evaluate p(t) at t=0:
[tex]p(0)=3000\cdot(1.019)^0=3000[/tex]So the initial price was $3000.
Now let's compare the terms inside parenthesis that are raised to t:
[tex]1.019=1\pm\frac{p}{100}[/tex]As I stated before, if the term raised to t is greater than 1 then we are talking about a growth. 1.019 is greater than 1 so this function represents a growth. What's more, in the right side of the equation we must use the + symbol. This way we have an equation for the yearly percentage of change of the price:
[tex]1.019=1+\frac{p}{100}[/tex]We can substract 1 from both sides of this equation:
[tex]\begin{gathered} 1.019-1=1+\frac{p}{100}-1 \\ 0.019=\frac{p}{100} \end{gathered}[/tex]And we multiply both sides by 100:
[tex]\begin{gathered} 100\cdot0.019=\frac{p}{100}\cdot100 \\ 1.9=p \end{gathered}[/tex]So each year the price increases in a 1.9%.
AnswerThen the answers in order are:
$3000
growth
1.9%