Answer:
As can be observed, every term in the given sequence: 2, 4, 6, 8, ..., is an even positive integer, and is, therefore, a multiple of 2:
1st term: 2 = 2(1)
2nd term: 4 = 2(2)
3rd term: 6 = 2(3)
4th term: 8 = 2(4)
Additional terms:
5th term: 10 = 2(5)
6th term: 12 = 2(6)
7th term: 14 = 2(7)
8th term: 16 = 2(8)
Therefore, using this same pattern, we see that the nth term of the given sequence is: 2n, where n is a positive integer that indicates the desired term of the sequence. For example, the 500th term of the sequence is: 2n = 2(500) = 1,000.
Notice that we add 2 to each term in order to get to the next term.
Since we use addition, we have an arithmetic sequence.
Hence, the nth term is:-
n+2
Hope it helps!
Any queries - comment !
Aiden invested $43,000 in an account paying an interest rate of 9 1/4 % compounded monthly. Hailey invested $43,000 in an account paying an interest rate of 8 7/8% compounded continuously. To the nearest dollar, how much money would Aiden have in his account when Hailey's money has doubled in value?
first off let's change the mixed fractions to improper fractions, and let's Hailey's account first.
[tex]\stackrel{mixed}{9\frac{1}{4}}\implies \cfrac{9\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{37}{4}} ~\hfill \stackrel{mixed}{8\frac{7}{8}}\implies \cfrac{8\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{71}{8}} \\\\[-0.35em] ~\dotfill[/tex]
[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &\stackrel{43000(2)}{\$86000}\\ P=\textit{original amount deposited}\dotfill & \$43000\\ r=rate\to \frac{71}{8}\%\to \frac{~~ \frac{71}{8}~~}{100}\dotfill &0.08875\\ t=years \end{cases} \\\\\\ 86000=43000e^{0.08875\cdot t}\implies \cfrac{86000}{43000}=e^{0.08875t}\implies 2=e^{0.08875t}[/tex]
[tex]\ln(2)=\ln(e^{0.08875t})\implies \log_e(2)=\log_e(e^{0.08875t})\implies \ln(2)=0.08875t \\\\\\ \cfrac{\ln(2)}{0.08875}=t\implies 7.81\approx t[/tex]
ok, now we know how long it takes for Hailey's money to double, how much money does Aiden have by then?
[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$43000\\ r=rate\to \frac{37}{4}\%\to \frac{~~ \frac{37}{4}~~}{100}\dotfill &0.0925\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &\frac{\ln(2)}{0.08875} \end{cases}[/tex]
[tex]A=43000\left(1+\frac{0.0925}{12}\right)^{12\cdot \frac{\ln(2)}{0.08875}}\implies A=43000\left( \frac{4837}{4800} \right)^{\frac{12\ln(2)}{0.08875}}\implies \boxed{A\approx 88311}[/tex]
notice, in Hailey's amount we used the logarithmic value for "t", just to avoid any rounding issues.
Mrs. Trevino was asked to provide at least 120 bagels for a workshop. She already has 2 dozen bagels. Mrs. Trevino will buy the remaining bagels in packages of 6. which inequality shows all the values of x if x equals the number of packages or bagels she could buy, beginning wath the minimum value of x? You must write and solve an inequality to receive credit.
First, we have "at least 120 bagels"
So we write ≥120 bagels.
Now, we are given that:-
Mrs. Trevino already has 2 dozen bagels.
Remember, a dozen is equal to 12, so if we have 2 dozen, then we have
[tex]\sf{2*12=24}\longleftarrow\sf{Mrs.Trevino~already~has~24~bagels}[/tex]
Now, she'll buy the remaining bagels in packages of 6, so we write
6x (packages of 6)
So the inequality looks like so:-
[tex]\sf{6x+24\geq 120}[/tex]
Now, let's solve the inequality :)
First, subtract 24 from both sides:-
[tex]\sf{6x\geq 120-24}[/tex]
[tex]\sf{6x\geq 96}[/tex]
Divide both sides by 6:-
[tex]\bigstar{\boxed{\pmb{x\geq 16}}}\longleftarrow\sf{number~of~packages~she~should~buy}[/tex]
note:-Hope everything is clear :)
Tumbleweed, commonly found in the western United States, is the dried structure of certain plants that are blown by the wind. Kochia, a type of plant that turns into tumbleweed at the end of the summer, is a problem for farmers because it takes nutrients away from soil that would otherwise go to more beneficial plants. Scientists are concerned that kochia plants are becoming resistant to the most commonly used herbicide, glyphosate. In 2014 , 19. 7% of 61 randomly selected kochia plants were resistant to glyphosate. In 2017 , 38. 5% of 52 randomly selected kochia plants were resistant to glyphosate. Do the data provide convincing statistical evidence, at the level of α=0. 05 that there has been an increase in the proportion of all kochia plants that are resistant to glyphosate
Using the z-distribution, it is found that the data provides convincing evidence that the proportion has increased.
What are the hypotheses tested?At the null hypotheses, it is tested if the proportion has not increased, that is, the difference of the 2017 proportion and the 2014 proportions is not positive, hence:
[tex]H_0: p_2 - p_1 \leq 0[/tex]
At the alternative hypothesis, it is tested if the proportion has increased, hence:
[tex]H_1: p_2 - p_1 > 0[/tex]
What are the mean and the standard error for the distribution of differences?For each sample, they are given by:
[tex]p_1 = 0.197, s_1 = \sqrt{\frac{0.197(0.803)}{61}} = 0.0509[/tex]
[tex]p_2 = 0.383, s_2 = \sqrt{\frac{0.385(0.615)}{52}} = 0.0675[/tex]
Hence, for the distribution of differences, they are given by:
[tex]\overline{p} = p_2 - p_1 = 0.383 - 0.197 = 0.186[/tex]
[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{0.0509^2 + 0.0675^2} = 0.0845[/tex]
What is the test statistic?It is given by:
[tex]z = \frac{\overline{p} - p}{s}[/tex]
In which p = 0 is the value tested at the null hypothesis.
Hence:
[tex]z = \frac{\overline{p} - p}{s}[/tex]
[tex]z = \frac{0.186 - 0}{0.0845}[/tex]
z = 2.2
What is the decision?Considering a right-tailed test, as we are testing if the proportion is higher than a value, the critical value at the 0.05 significance level is [tex]z^{\ast} = 1.645[/tex].
Since the test statistic is greater than the critical value for the left tailed test, the data provides convincing evidence that the proportion has increased.
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The rate (in mg carbon/m3/h) at which photosynthesis takes place for a species of phytoplankton is modeled by the function P = 110I I2 + I + 4 where I is the light intensity (measured in thousands of foot-candles). For what light intensity is P a maximum? I = thousand foot-candles
Using the vertex of a quadratic equation, it is found that P is at a maximum for l = -0.5 thousand foot-candles.
What is the vertex of a quadratic equation?A quadratic equation is modeled by:
[tex]y = ax^2 + bx + c[/tex]
The vertex is given by:
[tex](x_v, y_v)[/tex]
In which:
[tex]x_v = -\frac{b}{2a}[/tex]
[tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]
Considering the coefficient a, we have that:
If a < 0, the vertex is a maximum point.If a > 0, the vertex is a minimum point.In this problem, the function for P is given by:
[tex]P(l) = \frac{110l}{l^2 + l + 4}[/tex]
The function will be at a maximum when the denominator is at a minimum. The denominator is a quadratic function with coefficients a = 1, b = 1, c = 4, hence:
[tex]l_v = -\frac{b}{2a} = -\frac{1}{2} = -0.5[/tex]
P is at a maximum for l = -0.5 thousand foot-candles.
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*HIGHER POINTS* Solve for m<A
Answer:
The answer should be about 114.
Step-by-step explanation:
Of you look at the shape of the other angles. B and D seem to be about 90 and the shape of A is just a little bit bigger than ninety. I started by adding 78, 90, and 90 together which gave me 246. Then I subtracted 246 from 360 which gave me 114. I had estimated the answer to be around 110.
Compute x/y if
x + 1/y = 4 and
y + 1/x = 1/4
Please explain the process on how to solve it- I'll give brainliest!
Let first consider the equations one by one and will be solving one by one ;
[tex]{:\implies \quad \sf x+\dfrac{1}{y}=4}[/tex]
Multiplying both sides by y will lead ;
[tex]{:\implies \quad \sf xy+1=4y}[/tex]
[tex]{:\implies \quad \boxed{\sf xy=4y-1\quad \cdots \cdots(i)}}[/tex]
Now, consider the second equation which is ;
[tex]{:\implies \quad \sf y+\dfrac{1}{x}=\dfrac14}[/tex]
Multiplying both sides by x will yield
[tex]{:\implies \quad \sf xy+1=\dfrac{x}{4}}[/tex]
[tex]{:\implies \quad \sf xy=\dfrac{x}{4}-1}[/tex]
[tex]{:\implies \quad \boxed{\sf xy=\dfrac{x-4}{4}\quad \cdots \cdots(ii)}}[/tex]
As LHS of both equations (i) and (ii) are same, so equating both will yield;
[tex]{:\implies \quad \sf 4y-1=\dfrac{x-4}{4}}[/tex]
Multiplying both sides by 4 will yield
[tex]{:\implies \quad \sf 16y-4=x-4}[/tex]
[tex]{:\implies \quad \sf 16y=x}[/tex]
Dividing both sides by y will yield :
[tex]{:\implies \quad \boxed{\bf{\dfrac{x}{y}=16}}}[/tex]
Hence, the required answer is 16
what is the inverse of f(x)=x^2+5
Answer:
[tex]\sqrt{X-5}[/tex], [tex]-\sqrt{X-5}[/tex]
Step-by-step explanation:
Replace X with Y
solve for Y; X = Y^2 + 5
subtract 5 from both sides
X - 5 = Y^2
take the square root
Y = plus or minus sqrt(X-5)
sqrt(X-5); -sqrt(X-5)
How many solutions does the inequality x>12 have?
Answer:
infinte
Step-by-step explanation:
The answer is anything greater than 12 so it would be infinte
another question !!!
Answer:
All are complementary angles
Step-by-step explanation:
See attachment
Can someone help with these questions??
Will be helpful
if a town with a population of 10,000 doubles in size every 17years wat will population be 68 years from now
Answer:
20,000×17 gives 340,000
340,000×68 which gives 23,120,000
What is the least whole number n such that 84 divides n! ?
Answer:
5 should be the correct answer
Which value is the solution of
[tex] \sqrt[3]{3x} + 7 = 4[/tex]
A.-9
B.-1
C.3
D.19
Answer:
A
Step-by-step explanation:
[tex]\sqrt[3]{3x}[/tex] + 7 = 4 ( subtract 7 from both sides )
[tex]\sqrt[3]{3x}[/tex] = - 3 ( cube both sides to clear the radical )
3x = (- 3)³ = - 27 ( divide both sides by 3 )
x = - 9
please help me solve this?
Answer:
there are none (sorry if I got it wrong)
Step-by-step explanation:
also, there is none because there other numbers are really close to the other number
outliers are a number that is really small in the pack of numbers and outliers can also be the number that is really big for example I have the numbers 3 24 28 32 43 and then 100. 3 and 100 are outliers because one number (3) is really small from the other numbers are bigger and one number (100) is really big from the other number but sometimes there are no outliers
Which is the graph of g(x) = (0.5)x + 3 – 4?
On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = negative 4. It crosses the y-axis at (0, negative 4).
On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = 3. It crosses the y-axis at (0, 3).
On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = negative 4. It crosses the y-axis at (0, 4).
On a coordinate plane, an exponential function decreases in quadrant 2 and has a horizontal asymptote at y = 4. It crosses the y-axis at (0, 12).
Mark this and return
Answer:
the graph will be an exponential function that crosses the y-axis at about (0, -4).
Step-by-step explanation:
Answer:
The answer is the first graph.
Step-by-step explanation:
I just did the quiz
f(x)=2x^3-6x+k and the remainder when f(x) is divided by x+1=7 then what is the value of k
Given: f(x)=2x(cube)-6x+x
reaminder of f(x) when (x+1) diveded
to find value of k
solution,
f(x)=2x(cube)-6x+k
f(-1)=7
2(-1)(cube)+6+k=7
4+x=7
k=7
Hence,k=7
i need help with this i don't know how to do it.
Answer:
1935 were supporting the home team
Step-by-step explanation:
Since there are 4,500 people attending the game, we must find 43% of that. Doing this, we need to multiply 43% or .43 by 4,500.
After solving, you should get 1,935. There were 1,935 people supporting the home team.
simplify exponents please! need the answer immediately.
Answer:
[tex]\frac{w^{6} }{9 }[/tex]Step-by-step explanation:
Given
[tex]\frac{3^{-2}*k^{0}*w^{0} }{w^{-6} }[/tex]Remember :
Any term raised to the power 0 is equal to 1Solving
[tex]\frac{3^{-2} }{w^{-6} }[/tex][tex]\frac{w^{6} }{9}[/tex]Answer:
[tex]\huge\boxed{\bf\:\frac{w^{6}}{9}}[/tex]
Step-by-step explanation:
[tex]\frac{ 3 ^ { -2 } \times k ^ { 0 } \times w ^ { 0 } }{ w ^ { -6 } }[/tex]
Any number with 0 as its exponent will be equal to 1. So,
[tex]\frac{3^{-2} \times 1 \times 1}{w^{-6}}\\= \frac{3^{-2}}{w^{6}}[/tex]
Now,
[tex]\frac{3^{-2}}{w^{6}}\\= 3^{-2}w^{6}[/tex]
Then,
[tex]3^{-2}w^{6}\\= \frac{1}{3^{2}}w^{6}\\= \frac{1}{9}w^{6}\\= \boxed{\bf\:\frac{w^{6}}{9}}[/tex]
[tex]\rule{150pt}{2pt}[/tex]
A washer and dryer cost a total of $1184. The cost of the washer is three times the cost of the dryer. Find the cost of each of them.
The cost of a washer is $1184 while the cost of a drier is $296
Word ProblemGiven Data
Total cost of washer and dryer = $1184let the cost of a washer be = wlet the cost of a drier be = dHence,
w+d = 1184 -------------1
we know that the cost of the washer is three times the cost of the dryer.
w = 3d -------------------2
put w = 3d in equation 1
3d + d = 1184
4d = 1184
d = 1184/4
d = 296
The cost of a drier is $296
put d = $296 in equation 2
w = 3*296
w = $888
Check:
$888+$296 = $1184
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Chart Rodrigo's total utility for lattes and the marginal utility for the same using information
from the table.
Quantity
Utility
0
14
2
3
4
on ANO
22
28
32
35
5
1)
40
30
Units of Total Utility
20
10
0
1
2
3
4
N
5
Number of Lattés
2)
)
20
15
Units of Total Utility per Latte
10
5
0
1
2
3
4 5
Number of Lattés
The marginal utility is the extra satisfaction derived from the consumption of a product.
How to illustrate the marginal utility?Your information isn't well written. Therefore, an overview of utility will be given. The total utility is the total amount of satisfaction that a consumer derives from a product.
The marginal utility simply means the extra satisfaction that's gotten from a product when an additional unit is consumed.
The formula for marginal utility will be:
= Total utility difference/Quantity of goods difference
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The population of a city is given by P(t) = Poe
-0.04t where t is time measured in years and
P0 is the population at time t=0. Assume that Po = 1,000,000.
a. Find the population when t=3.
b. During what year will the population drop below 750,000. (solve an equation, no
guess-and-check)
Answer:
a. 885,920
b. year 8
Step-by-step explanation:
The population at a given time is described by the exponential formula ...
P(t) = P0·e^(-0.04t)
where P0 is given as 1,000,000.
a.We are asked for the value of P(3). This ccan be found by substituting 3 for t in the equation and evaluating the numerical expression.
P(3) = 1,000,000·e^(-0.04·3) = 1,000,000·e^(-0.12)
P(3) ≈ 886,920
The population when t=3 is about 886,920.
__
b.We can put the given numbers in the equation and solve for t.
750,000 = 1,000,000·e^(-0.04t)
0.75 = e^(-0.04t) . . . . . divide by 1,000,000
ln(0.75) = -0.04t . . . . . take the natural log
-ln(0.75)/0.04 = t ≈ 7.192
The population will drop below 750,000 in year 8.
_____
Additional comment
These values can be confirmed by a graphing calculator.
Note that "year 1" is the year between t=0 and t=1. So, "year 8" is the year between t=7 and t=8.
What is the answer I need help please
Answer:
i belive the answer is 73
Step-by-step explanation:
45+62=107
180-107=73
Find the area of the shaded polygon
Answer:
372
Step-by-step explanation:
area of trapezium = a+b/2 * h
a is the length on top
b is the length on the bottom
h is the height
7+24/2*24=
=372
How many pieces of tape measuring 2/3 meter can be cut from a roll of tape that measures 5 1/3 meters
how many pieces of tape can be cutted.
solution:[tex]5 \frac{1}{3} \div \frac{2}{3} [/tex]
[tex] = (5 + 0) + ( \frac{1}{3} + \frac{2}{3} )[/tex]
[tex] = 5 + \frac{1 + 2}{3} [/tex]
[tex] = 5 + \frac{3}{3} [/tex]
[tex] = 5 + \frac{3 \div 3}{3 \div 3} [/tex]
[tex] = 5 + \frac{1}{1} [/tex]
[tex] = 6[/tex]
therefore, 6 pieces of tape can be cutted.
help pls
just say what option
Answer:
D .the formation in the graph shows a positive non linear correlation, the weight of the dinosaur trends to increase according to its length.hope this helps you :)The information on the graph shows a positive nonlinear correlation and the weight of the dinosaur tends to increase according to its length.
What is a discrete graph?A discrete graph is also known as a scatter plot that shows the discontinuous and the nonlinear data point on the graph.
From the graph, we can see the increasing weight of the Dinosaur size vertical y-axis and the increasing length of the feet on the horizontal x-axis.
Therefore, we can conclude that the data points show an increasing nonlinear weight on the graph as the length increases.
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A rhombus has a perimeter of 52 inches. It’s shorter diagonal is 10 inches in length. which of the following is the length of its longer diagonal?
Answer:
ok it's a good question... so answer to that is... I also don't know..
Please help with this problem. I don’t understand the answer for this equation. The answer for this equation is 7/2( a+ b) i’m just not understanding where the seven is coming from.
Answer:
7/2(a+b)
Step-by-step explanation:
To add fractions you need to find the LCM (least common multiplier) and then combine.
least common multiplier of a+b, 2(a+b) : 2(a + b)
Adjust fractions based of LCM
2/2(a + b) + 5/2(a +b)
2+5/2 (a + b) =
7/2 (a + b)
I hope this makes sense! :)
The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station. suppose intensity is 8000 units at a distance of 2 miles. what will the intensity be at a distance of 11 miles? round your answer to the nearest unit. a. 247 units b. 228 units c. 264 units d. 290 units
Answer:
The ratio of the new distance to the old distance is (11/2) .
The intensity is inversely proportional to the square of the distance,
so the new intensity will be (2/11)² times the old intensity.
Intensity = 8,000 (2/11)² =
32,000 / 121 = 262.463 units
Rounded to the nearest whole unit: 262 units
Step-by-step explanation:
264 units of intensity came from a distance of 11 miles option (c) 264 units is correct.
It is given that the intensity is 8000 units at a distance of 2 miles.
It is required to find the intensity at a distance of 2 miles.
What is a fraction?Fraction number consists of two parts one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.
The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station.
Suppose the Intensity of the signal is I and the distance is d, then:
[tex]\rm I \propto\frac{1}{d^2}[/tex]
Intensity from the station [tex]\rm I_1=8000 \ units[/tex]
[tex]\rm I_1[/tex] intensity at distance [tex]\rm d_1=2 \ miles[/tex]
Intensity from the station [tex]=\rm I_2[/tex]
[tex]\rm I_1[/tex] intensity at distance [tex]\rm d_2=11 \ miles[/tex]
[tex]\rm \frac{I_2}{I_1} = \frac{d_1^2}{d_2^2}[/tex] (From the proportional relation)
[tex]\rm \frac{I_2}{8000} = \frac{2^2}{11^2}[/tex]
[tex]\rm I_2 =8000\times\frac{4}{121} \\\\\rm I_2 = 264.46 \ units[/tex] ≈ 264 units
Thus, the 264 units of intensity came from a distance of 11 miles.
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The cubic root of 400 lies between which two numbers?
Answer:
Let x = cube root of 400
Using a calculator x = 7.368 to 3 decimal places
So: 7 < x < 8
3) You need to paint shutters on a window that is on the second floor of your house. You have a 20 foot ladder that you will use. There is a warning on the ladder that states the angle formed by the ladder and the ground must not be less than 70 degrees, or the ladder may slip and cause serious injury or death. You planned on placing the bottom of the ladder 3 feet from the base of the house. Will the angle formed between the ground and the ladder be safe? What is the furthest possible distance the ladder can be placed to maintain a safe angle? Sketch:
Answer:
See below ↓↓
Step-by-step explanation:
Height of ladder = 20 feetDistance of base of ladder from house = 3 feetAngle must not be < 70°Taking the cos ratio of the angle
Let the angle formed be α cos α = adjacent side / hypotenusecos α = 3 / 20 = 0.15α = cos⁻¹ (0.15)α = 81.37°⇒ The angle formed is safe
Finding furthest possible distance
Take α to be 70°cos 70° = 0.34 = x/20⇒ x = 20 x 0.34 = 6.8 feetAnswer:
Yes, the angle formed between the ground and the ladder is safe
6.84 ft (nearest hundredth)
Step-by-step explanation:
We can use the cos trig ratio to determine the angle made between the 20ft ladder and 3ft from the base of the house (see first attached image for sketch).
[tex]\sf \cos(\theta)=\dfrac{A}{H}[/tex]
where:
[tex]\theta[/tex] is the angleA is the side adjacent to the angleH is the hypotenuseGiven:
A = 3 ftH = 20 ft[tex]\sf \implies \cos(\theta)=\dfrac{3}{20}[/tex]
[tex]\sf \implies \theta=\cos^{-1}\left(\dfrac{3}{20}\right)[/tex]
[tex]\sf \implies \theta=81.37307344..^{\circ}[/tex]
Therefore, as the ladder is forming an 81.37° angle and 81.37...° > 70° the angle formed between the ground and the ladder is safe.
To find the furthest possible distance the ladder can be placed, set [tex]\theta[/tex] to 70° (max safe angle) and the hypotenuse (ladder length) to 20, then solve for A (see second attache image for sketch):
[tex]\sf \implies \cos(70^{\circ})=\dfrac{A}{20}[/tex]
[tex]\sf \implies A=20\cos(70^{\circ})[/tex]
[tex]\sf \implies A=6.840402867...\: \sf ft[/tex]
So the furthest possible distance the ladder can be placed to maintain a safe angle is 6.84 ft (nearest hundredth).