Answers
The length of the lines GH and CH are 16 units and 12 units.
What is a line?A line is an object in geometry that is infinitely long and has neither width nor depth nor curvature. Since lines can exist in two, three, or higher-dimensional spaces, they are one-dimensional objects. The term "line" can also be used to describe a line segment in daily life that has two points that serve as its ends. In geometry, lines are drawn with arrows at either end to indicate that they extend indefinitely. Two line points can be used to name a line (for example, AB) or just a letter, usually in lowercase (for example, line m ). The ends of a line segment are two.So, the measure of lines GH and CH:
We know that AC ⊥ GH hence cuts GH in two equal lines.
GB = BH GB is 8 units then BH is also 8 units.GB = BH = 8 units.But,
GH = GB + BHGH = 8 + 8GH = 16 unitsWe can observe that △GCH is an isosceles triangle.
GC = CHGC = CH = 12 unitsTherefore, the length of the lines GH and CH is 16 units and 12 units.
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Related Questions
Complete the square for each expression. Write the resulting expression as a binomial. x^2+14x+____
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To complete the square is take the second term in the expression, divided it by 2 and then squared it. This will be the number that we have to add to the original expression.
(14/2)^2=49
so, completing the expression:
x^2+14x+49
Then, the new expression can be factored into a single term squared:
x^2+14x+49= (x+7)^2
(spanish only) (Foto)
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Respuesta:
Rectángulo.
Explicación paso a paso:
Cuando un triangulo isósceles (ángulos de la base de igual magnitud) miden 45°, significa que el ángulo que no conocemos será de 90 grados por el teorema de los ángulos internos de un triángulo.
180-(45+45)=90.
Por lo tanto, se forma un triangulo rectángulo, significa que tiene un ángulo recto de 90°.
The question is which of these statements are true about radicals exponents and rational exponents
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We have the following:
I)
[tex]\sqrt[n]{a}=a^{\frac{1}{n}}[/tex]It´s true
II)
[tex]a^{\frac{1}{2}}=\sqrt[]{a}[/tex]It´s true
III)
[tex]\begin{gathered} a^{\frac{p}{q}}=\sqrt[p]{a^q}=(\sqrt[p]{a})^q \\ (\sqrt[p]{a})^q=(a^{\frac{1}{p}})^q=a^{\frac{q}{p}} \end{gathered}[/tex]It´s false
IV)
[tex]\sqrt[]{a}[/tex]It´s true
V)
[tex]\begin{gathered} a^{\frac{1}{n}}=\sqrt[]{a^n} \\ \sqrt[]{a^n}=a^{\frac{n}{2}} \end{gathered}[/tex]It´s false
Open the image attached belowProve that:sec n/(tan n + cot n) = sin n
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Given:
We are required to prove:
[tex]\frac{\sec\text{ }\theta\text{ }}{\tan\text{ }\theta\text{ + cot}\theta}\text{ = sin}\theta[/tex]From the left-hand side:
[tex]\begin{gathered} =\frac{\sec\text{ }\theta\text{ }}{\tan\text{ }\theta\text{ + cot}\theta}\text{ } \\ =\text{ }\frac{\frac{1}{\cos\theta}}{\frac{\sin\theta}{\cos\theta}\text{ + }\frac{\cos \theta}{\sin \theta}} \\ =\text{ }\frac{\frac{1}{\cos\theta}}{\frac{\sin ^2\theta+cos^2\theta}{\sin \theta\cos \theta}} \\ \end{gathered}[/tex]From standard trigonometric identity, we have:
[tex]\sin ^2\theta+cos^2\theta\text{ = 1}[/tex]Substituting we have:
[tex]\begin{gathered} =\text{ }\frac{\frac{1}{\cos\theta}}{\frac{1}{\sin \theta\cos \theta}} \\ =\text{ }\frac{\sin \theta\cos \theta}{\cos \theta} \\ =\text{ sin }\theta\text{ (Right-hand side)} \end{gathered}[/tex]Rain equation for the line that is parallel to the given line and that passes through the given point
Answers
From the properties of line
If two lines are parallel, then thier slope are equal.
The general equation of line with slope m is; y = mx + b
The given equation of line us y = -5x + 3, slope of the given line is (-5)
The line is passes through the point (-6,3) and slope (-5)
The general equation of line is;
[tex]y-y_1=m(x-x_1)[/tex]Substitute the coordinates as;
[tex]x_1=-6,y_1=3[/tex]Thus;
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-3=-5(x+6) \\ y-3=-5x-30 \\ y+5x-3+30=0 \\ 5x+y+27=0 \\ y=-5x-27 \end{gathered}[/tex]Answer : y = -5x - 27
,,,
Which of the following polar coordinates would not be located at the point?
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Explanation
We are asked to select the option that would not be located at the given point
To do so, let us find the original coordinates of the given polar point
The point is located 6 units away from the origin in a direction of 270 degrees
The equivalent coordinates are
[tex]\begin{gathered} (6,\frac{3\pi}{2}) \\ (6,\frac{-\pi}{2}) \\ (-6,90^0) \end{gathered}[/tex]Thus, we are to eliminate any option that is not equivalent to the above, we are left with
[tex](6,\frac{-3\pi}{2})[/tex]Thus, the answer is option A
At a party 15 handshakes took place. Each person shook hands exactly once with each of the other present. How many people were at the party?
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2 people => 1 handshake (AB)
3 people => 3 handshakes (AB, BC, AC)
4 people => 6 handshakes (AB, AC, AD, BC, BD, CD)
Do you see a pattern here?
We can write a general formula for this
[tex]handshakes=\frac{n\cdot(n-1)}{2}[/tex]Since we are given that there were 15 handshakes
[tex]15=\frac{n\cdot(n-1)}{2}[/tex][tex]\begin{gathered} 2\cdot15=n\cdot(n-1) \\ 30=n\cdot(n-1) \\ 30=6\cdot(6-1) \\ 30=6\cdot(5) \\ 30=30 \end{gathered}[/tex]This means that n = 6 people were present at the party.
You can substitute n = 6 into the above formula and you will notice that it will give 15 handshakes
[tex]handshakes=\frac{n\cdot(n-1)}{2}=\frac{6\cdot(6-1)}{2}=\frac{6\cdot5}{2}=\frac{30}{2}=15[/tex]i have already graphed the problem, please help me fill in the following.
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ANSWER
There are 3 major points to prove that a quadrilateral is a rhombus
1. Indicate that the diagonals of the shape are bisectors that are perpendicular to each other
2. Indicate that the diagonal of the shape bisects both pair of opposite angles
3. Indicate that the shape is a parallelogram with sides of the same length
Completely factor the expression by grouping if possible 2xy+3x+10y+15
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The required factor of the given expression is given as (2y + 3)(x + 3).
Given that,
The factor of the given expression 2xy+3x+10y+15 is to be determined.
The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.
Here
= 2xy+3x+10y+15
Simplifying through factorization,
= x(2y + 3) + 5(2y + 3)
= (2y + 3)(x + 3)
Thus, the required factor of the given expression is given as (2y + 3)(x + 3).
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I need help on question number 1 I have been stuck on it for a long time
Answers
Explanation
Step 1
Vertical angles are formed when two lines intersect each other. Out of the 4 angles that are formed, the angles that are opposite to each other are vertical angles. vertical angles are congruent so
[tex]\begin{gathered} m\angle5=m\angle7\rightarrow reason\text{ vertical angles} \\ \end{gathered}[/tex]Step 1
replace the given values
[tex]\begin{gathered} m\angle5=m\angle7\rightarrow reason\text{ vertical angles} \\ -2(3x-4)=3(x-3)-1 \end{gathered}[/tex]now, we need to solve for x
a)
[tex]\begin{gathered} -2(3x-4)=3(x-3)-1 \\ \text{apply distributive property} \\ -6x+8=3x-9-1 \\ \text{add like terms} \\ -6x+8=3x-10\rightarrow reason\text{ distributive property} \end{gathered}[/tex]b)subtract 3x in both sides( additioin or subtraction property of equality)
[tex]\begin{gathered} -6x+8=3x-10 \\ subtract\text{ 3x in both sides} \\ -6x+8-3x=3x-10-3x \\ -9x+8=-10 \\ \text{subtract 8 in both sides} \\ -9x+8-8=-10-8 \\ -9x=-18 \\ -9x=-18\rightarrow reason\colon\text{ addition and subtraction property of equality} \end{gathered}[/tex]c) finally, divide both sides by (-9) division property of equality
[tex]\begin{gathered} -9x=-18 \\ \text{divide both side by -9} \\ \frac{-9x}{-9}=\frac{-18}{-9} \\ x=2\rightarrow\text{prove} \end{gathered}[/tex]i hope this helps you
What is the equation of the line that is parallel to the graph of y = 2x - 5 and passes through the point (8, 10)?
Answers
We know that the equation of a line is given by
[tex]y-y_1=m(x-x_1)[/tex]To find it we need the slope m and a point that the line passes thorugh. In this case we have the point (8,10) but we don't know the slope. What we know is that the line we are looking for is parallel to the line
[tex]y=2x-5[/tex]We also know that for two lines to be parallel they have the same slope. Then, if we fin the slope of the line y=2x-5, we have the slope of the line we are looking for. To find the slope of the line y=2x-5 we note that it is written in the slope-intercept form
[tex]y=mx+b[/tex]From this we know that the slope is multiplying the x variable when it is written in that form. Hence m=2.
Then the line we are looking for has an slope of 2 and passes through the point (8,10). Pluggin the values in the equation of a line we have.
[tex]y-10=2(x-8)[/tex]Writting it in the slope intercept form we have
[tex]\begin{gathered} y-10=2(x-8) \\ y-10=2x-16 \\ y=2x-16+10 \\ y=2x-6 \end{gathered}[/tex]Then the line parallel to y=2x-5 and passes through the point (8,10) is
[tex]y=2x-6[/tex]To make banana berry smoothies, Just Juice mixes water and juice in a ratio of 5 to 3. How much water should Just Juice mix with 23 gallons of juice to make banana berry smoothies?
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Answer:
38 1/3 gallons.
Step-by-step explanation:
[tex]\frac{w}{j}[/tex] = [tex]\frac{w}{j}[/tex] set up a ratio of the ratio of water to juice to the actual amount of water in juice. Fill in the numbers that you know and solve for the actual amount of water.
[tex]\frac{5}{3}[/tex] = [tex]\frac{w}{23}[/tex] Cross multiply and solve
3w = 5(23)
3w = 115 Divide both side by 3
w = 38 1/3 Gallons
proportional relationships, math
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The answer is yes, the equation represents a proportional relationship.
The reason is that a proportional relationship is best described as that in which the value of one variable depends on what happens to the other variable. Just like having one more child every year would mean spending more money on education, etc.
In a proportiona; relationship as shown in this question, y is the total cost of a pizza and each x (each topping) would determine how much is y. So requesting for 5 more toppings would result in 1.5 multiplied by 5, and requesting 10 more would result in 1.5 multiplied by 10. So as the amount of toppings (x variable) increases, the total cost (y variable) likewise would increase.
As x increases or decreases, the value of y would likewise increase or decrease. That makes this equation a proportional relationship
In a probability experiment, Craig rolled a six-sided die 62 times. The die landed on a number greater than three 36 times. What is the ratio of rolls greater than three to rolls less than or equal to three?
Answers
Answer:
31/55
Step-by-step explanation:
Which set of ordered pairs does not show y as a function of x? A. {(3,-2); (5,-3); (7,-4); (9,-5)} B. O {(3,-2); (6,-2); (9,-2); (12,-2)} c.{(4, -2); (5,-3); (6,-4); (7,-5)} D.O{(4, -2); (5,-3); (4,-8); (5,-9)}
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-2(k - 5) + 2K = 5k +5A)k=0B)k=4C)k1D)k=2
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The equation we have is:
[tex]-2(k-5)+2k=5k+5[/tex]Now we can simply the equation by multiply the -2 into the parenthesis
[tex]\begin{gathered} -2k+10+2k=5k+5 \\ 10=5k+5 \end{gathered}[/tex]now we can solve for k
[tex]\begin{gathered} 10-5=5k \\ 5=5k \\ \frac{5}{5}=k \\ 1=k \end{gathered}[/tex]suppose g(x) = f(x - 3) - 4. I need the graph of g(x) with the graph of f(x)
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In order to graph g(x) with the graph of f(x), first we need a translation of 3 units to the right, because of the term f(x - 3)
Then, we need a translation of 4 units down, because of the term -4.
So the movements are: translations of 3 units right and 4 units down.
Find the area of the shaded region in the figure Type an integer or decimal rounded to the nearest TENTH
Answers
Answer:
The area of the shaded region is;
[tex]18.7\text{ }in^2[/tex]Explanation:
Given the figure in the attached image.
The area of the shaded region is the area of the larger circle minus the area of the smaller circle;
[tex]\begin{gathered} A=\frac{\pi D^2}{4}-\frac{\pi d^2}{4} \\ A=\frac{\pi}{4}(D^2-d^2) \end{gathered}[/tex]Given;
[tex]\begin{gathered} D=6 \\ d=3\frac{1}{2} \end{gathered}[/tex]Substituting the given values;
[tex]\begin{gathered} A=\frac{\pi}{4}(D^2-d^2) \\ A=\frac{\pi}{4}(6^2-3.5^2) \\ A=\frac{\pi}{4}(23.75) \\ A=18.65\text{ }in^2 \\ A=18.7\text{ }in^2 \end{gathered}[/tex]Therefore, the area of the shaded region is;
[tex]18.7\text{ }in^2[/tex]Topic 8.2: Solving Using Linear/HELP RN!!!!!Area Scale Factor3. Examine the two similar shapes below. What is the linear scale factor? What is the area scalefactor? What is the area of the smaller shape?3a. Linear scale factor =3b. Area scale factor =Area =99 un.2=3c. Area of small shape =
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Solution
Question 3:
- Let the dimension of a shape be x and the dimension of its enlarged or reduced image be y.
- The linear scale factor will be:
[tex]sf_L=\frac{y}{x}[/tex]- If the area of the original shape is Ax and the Area of the enlarged or reduced image is Ay, then, the Area scale factor is:
[tex]sf_A=\frac{A_y}{A_x}=\frac{y^2}{x^2}[/tex]- We have been given the area of the big shape to be 99un² and the dimensions of the big and small shapes are 6 and 2 respectively.
- Based on the explanation given above, we can conclude that:
[tex]\begin{gathered} \text{ If we choose }x\text{ to be 6, then }y\text{ will be 2. And if we choose }x\text{ to be 2, then }y\text{ will be 6} \\ \text{ So we can choose any one.} \\ \\ \text{ For this solution, we will use }x=6,y=2 \end{gathered}[/tex]- Now, solve the question as follows:
[tex]\begin{gathered} \text{ Linear Scale factor:} \\ sf_L=\frac{y}{x}=\frac{2}{6}=\frac{1}{3} \\ \\ \text{ Area Scale factor:} \\ sf_A=\frac{y^2}{x^2}=\frac{2^2}{6^2}=\frac{1}{9} \\ \\ \text{ Also, we know that:} \\ sf_A=\frac{A_y}{A_x}=\frac{y^2}{x^2} \\ \\ \text{ We already know that }\frac{y^2}{x^2}=\frac{1}{9} \\ \\ \therefore\frac{A_y}{A_x}=\frac{1}{9} \\ \\ A_x=99 \\ \\ \frac{A_y}{99}=\frac{1}{9} \\ \\ \therefore A_y=\frac{99}{9} \\ \\ A_y=11un^2 \end{gathered}[/tex]Final Answer
The answers are:
[tex]\begin{gathered} \text{ Linear Scale Factor:} \\ \frac{1}{3} \\ \\ \text{ Area Scale Factor:} \\ \frac{1}{9} \\ \\ \text{ Area of smaller shape:} \\ 11un^2 \end{gathered}[/tex]the bearing from S to R is 160° what is the bearing of S from R
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.
The bearing of S from R is given as;
[tex]90+90+90+70=340\degree[/tex]the circle below has center E. Suppose that m
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Notice that the triangle △GEF is an isosceles triangle, since GE=EF (both sides are radii of the circle).
Since △GEF is an isosceles triangle with GE=EF, then the measure of the angles opposed to those sides is the same:
[tex]m\angle GFE=m\angle EGF[/tex]Since the line FH is tangent to the circle, the angle ∠HFE is a right angle.
Since ∠HFG and ∠GFE are adjacent angles, then:
[tex]m\angle\text{HFG}+m\angle\text{GFE}=m\angle\text{HFE}[/tex]Substitute m∠HFG=62 and m∠HFE=90 to find m∠GFE:
[tex]\begin{gathered} 62+m\angle\text{GFE}=90 \\ \Rightarrow m\angle GFE=28 \end{gathered}[/tex]Since the sum of the internal angles of any triangle is 180 degrees, then:
[tex]m\angle\text{GFE}+m\angle\text{EGF}+m\angle\text{FEG}=180[/tex]Substitute the values of m∠GFE and m∠EGF:
[tex]\begin{gathered} 28+28+m\angle\text{FEG}=180 \\ \Rightarrow\angle FEG=124 \end{gathered}[/tex]Therefore:
[tex]\begin{gathered} \text{m}\angle\text{FGE}=28 \\ m\angle FEG=124 \end{gathered}[/tex]the sign shown below is posted in front of a roller coaster ride at the Wadsworth country fairgrounds.if h represents the height of a rider in inches,what is the correct translation of the statement on this sign?h<48h>58h≤48h≥48
Answers
Answer:
h≥48
Explanation:
If all riders must be at least 48 inches tall, it can mean the following.
0. The height of the riders can be ,exactly 48 inches, tall (h=48)
,1. The height of the riders can be, greater than 48 inches,, (h>48).
Combining the two, we have:
h≥48
Given:• UZ | VW• UV ZUZ306Nw4511Which is closest to mZW?26.630°60°63.49
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From the image, given that UZ is parallel to VW, UV is congruent to UZ. We can redraw the image to include some extra details.
The image is below;
With the image above, we can the find the angle W, using tangent function of trigonometry.
This is seen below;
[tex]\begin{gathered} \tan w=\frac{opposite}{\text{Adjacent}} \\ \text{opposite =30ft} \\ \text{Adjacent}=15ft \\ \therefore\tan w=\frac{30}{15} \\ \tan w=2 \\ w=\tan ^{-1}2 \\ w=63.4^0 \end{gathered}[/tex]The angle closest to m
Answer: 63.4
The polynomial is not written in order how many terms does the polynomial have
Answers
Answer:
[tex]\text{This polynomial has 4 terms.}[/tex]Step-by-step explanation:
a TERM is a variable, number, or product of a number and one or more variables with exponents.
Then, ordering the polynomial:
[tex]\begin{gathered} x^3+2x^2+4x-2 \\ \text{This polynomial has 4 terms.} \end{gathered}[/tex]Rabbit's run: distance (meters) time (minutes) way 800 1 900 5 1107.5 20 1524 32.5
Answers
Answer:
Notice that:
[tex]\begin{gathered} \frac{800}{1}=800, \\ \frac{900}{5}=180, \\ \frac{1107.5}{20}=\frac{443}{8}, \\ \frac{1524}{32.5}=\frac{3048}{65}. \end{gathered}[/tex]Since all reduced fractions are different, the distance traveled by the rabbit and the time are not proportional.
mark has a bag containing a mixture of 30 green and white marbles.
Answers
SOLUTION:
From the experiment performed;
Mark got 10 green marbles and 5 white marbles after 15 trials. Since the number of green marbles gotten in the experiment is more than the white, the conclusion best supported by the experiment is ;
The bag contains more green than white marbles.
The bank requires that customers select a PIN (personal identification number) so ATM’s can be accessed. The PIN must be 3 digits followed by one letter. How many different PIN numbers can be selected if the first digit cannot be zero?
Answers
Answer:
A lot
Step-by-step explanation:
use random numbers from 1 to 9 and or 0, after the first natural number. And different letters, so there is no specific amount to say that can be used.
A $300,000 property appreciated in value by 3%. What is its new value?
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Answer:
The word "Appreciated" means "Increase" in value of something.
Here, The value of property is Appreciated by 3%
Therefore,
New price = Old price + 3% of Old price
New price = $300000 + 3% of $300000
New price = $300000 + $( 3/100 × 300000)
New price = $300000 + $9000
New price = $309000
I hope it's helpful
Answer:
$309 000.
Step-by-step explanation:
It is now worth 3% more than its original 100%
So 103% ( in decimal 1.03)
1.03 * 300 000 = 309 000 dollars
Simplify 2+^3 ÷ 2- ^3
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We want to simplify the following expression:
[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}[/tex]This means that we want to "remove" the denominator".
STEP 1If we observe the denominator:
[tex](2-\sqrt[]{3})[/tex]If we multiply it by
2 + √3, then
[tex]\begin{gathered} (2-\sqrt[]{3})(2+\sqrt[]{3}) \\ =4-\sqrt[]{3}^2=4-3=1 \end{gathered}[/tex]STEP 2We know that if we multiply both sides of a fraction by the same number or expression, the fraction will remain the same, then we multiply both sides by 2 + √3:
[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}=\frac{(2+\sqrt[]{3})(2+\sqrt[]{3})}{(2-\sqrt[]{3})(2+\sqrt[]{3})}[/tex]For the denominator, as we analyzed before
[tex](2-\sqrt[]{3})(2+\sqrt[]{3})=1[/tex]For the denominator:
[tex](2+\sqrt[]{3})(2+\sqrt[]{3})=(2+\sqrt[]{3})^2[/tex]Then,
[tex]\frac{2+\sqrt[]{3}}{2-\sqrt[]{3}}=\frac{(2+\sqrt[]{3})(2+\sqrt[]{3})}{(2-\sqrt[]{3})(2+\sqrt[]{3})}=\frac{(2+\sqrt[]{3})^2}{1}=(2+\sqrt[]{3})^2[/tex]STEP 3Now, we can simplify the result:
[tex]\begin{gathered} (2+\sqrt[]{3})^2=(2+\sqrt[]{3})(2+\sqrt[]{3}) \\ =2^2+2\sqrt[]{3}+(\sqrt[]{3})^2+2\sqrt[]{3} \\ =4+4\sqrt[]{3}+3 \\ =7+4\sqrt[]{3} \end{gathered}[/tex]Answer: 7+4√3The Hernandez family and the Cox family each used their sprinklers last summer. The Hernandez family’s sprinkler was used for 15 hours. The fox familys sprinkler was used for 30 hours. There was a combined total output of 1275 L of water. What was the water output rate for each sprinkler if the sum of the two rates was 50 L per hour?
Answers
ANSWER
The output rate for the Hernandez family was 15 L/hr and for the Fox family was 35 L/hr.
EXPLANATION
To solve this problem, we have to create a system of two simultaneous equations.
Let the output rate of the Hernandez family sprinkler be h.
Let the output rate of the Fox family sprinkler be f.
The product of the rate and the time used is equal to the output:
[tex]\text{Rate}\cdot\text{time}=\text{output}[/tex]We have that the combined total output for both sprinklers is 1275 L, which means that:
[tex]\begin{gathered} (15\cdot h)+(30\cdot f)=1275 \\ \Rightarrow15h+30f=1275 \end{gathered}[/tex]The sum of the two rates is 50 L/hr, which means that:
[tex]h+f=50[/tex]Now, we have a system of two simultaneous equations:
[tex]\begin{gathered} 15h+30f=1275 \\ h+f=50 \end{gathered}[/tex]Solve the equations by substitution.
Make h the subject of the formula in the second equation:
[tex]h=50-f[/tex]Substitute that into the first equation:
[tex]\begin{gathered} 15(50-f)+30f=1275 \\ 750-15f+30f=1275 \\ 750+15f=1275 \\ \Rightarrow15f=1275-750=525 \\ f=\frac{525}{15} \\ f=35\text{ L/hr} \end{gathered}[/tex]Recall that:
[tex]h=50-f[/tex]Therefore, we have that:
[tex]\begin{gathered} h=50-35 \\ h=15\text{ L/hr} \end{gathered}[/tex]Hence, the output rate for the Hernandez family was 15 L/hr and for the Fox family was 35 L/hr.