Figure 2 is a scaled copy of Figure 1.B.Figure 1AsADMYColJFigure 2MYHKProIdentify the side in Figure 2 that corresponds to side BC in Figure 1.

Figure 2 Is A Scaled Copy Of Figure 1.B.Figure 1AsADMYColJFigure 2MYHKProIdentify The Side In Figure

Answers

Answer 1

Figure 1 was enlarged to figure 2

Hence the side |AB| is corresspounding to the side |PQ|


Related Questions

An envelope is 15 centimeters wide, and it measures 17 centimeters along the diagonal. The envelope is __ centimeters tall.

Answers

An envelope is rectangular in shape.

Given the width = 15cm, and diagonal = 17cm

Let h represent the tall length of the envelope

Applying Pythagoras theorem, we have

[tex]\begin{gathered} 17^2=15^2+h^2 \\ 289=225+h^2 \\ h^2=289-225 \\ h^2=64 \\ h=\sqrt[]{64} \\ h=8\operatorname{cm} \end{gathered}[/tex]

The envelope is 8cm tall

Which expression demonstrates how the Distributive Property could be used to find the product of 5 and 48?
A. 50 − 5 (2)
B. 5 (50) − 2
C. 5 (50) + 5 (2)
D. 5 (50 − 2) + 5 (2)
E. None of these

Answers

Answer:

Step-by-step explanation:

C

8. Anna withdrew $50 from her checking account. She spent $28 on a pair of shoes. What fraction of her money does Anna have left?

Answers

Explanation:

If she spent $28 of the $50 she withdrew, she now has:

[tex]50-28=22[/tex]

$22

The fraction is:

[tex]\frac{22}{50}=\frac{11}{25}[/tex]

Answer:

Anna has 11/25 of her money left.

Given ΔABC with m∠B = 62°, a = 14, and c = 16, what is the measure of A?

Answers

1) Let's sketch this out to better grasp it

2) We can see that there are two legs and two angles (one of them is missing) so let's solve it using the Law of Sines:

[tex]undefined[/tex]

Find the solutions to the following quadratic equation negative 3X squared plus 4X plus one equals zero (-3x^2 + 4x + 1 = 0)

Answers

Answer:

Explanation:

Given:

[tex]-3x^2+4x+1=0[/tex]

To find:

the value of x using the quadratic formula

The quadratic formula is given as:

[tex]$$x\text{ = }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$$[/tex]

where a = -3, b = 4, c = 1

[tex]\begin{gathered} x\text{ = }\frac{-4\pm\sqrt{(4)^2-4(-3)(1)}}{2(-3)} \\ \\ x\text{ = }\frac{-4\pm\sqrt{16+12}}{-6} \\ \\ x\text{ = }\frac{-4\pm\sqrt{28}}{-6} \end{gathered}[/tex][tex]undefined[/tex]

Four points are labeled on the number line. M K L zo 0.5 1 Which point best represents 3? F. Point K G. H. Point 2 Point M Point N J.

Answers

The point that best represents 1/3 is point M .

The number line ranges from 0 to 0.5 with 10 divi

Graph the line y = 5x – 1, then name the slope and y-intercept by looking at the graph.

Answers

Answer:

m = 5

y-intercept = (0, -1)

Step-by-step explanation:

y = mx + b

y = 5x - 1

m = 5

y-intercept = b = (0, -1)

Point 1: (0, -1)

Point 2: (1, 4)

Point 3: (-1, -6)

I hope this helps!

The fraction models below represent two fractions of the same whole: How much of the8음을16

Answers

[tex]\begin{gathered} \frac{5}{8}x=\frac{1}{2} \\ x=\frac{1}{2}\times\frac{8}{5}=\frac{4}{5} \end{gathered}[/tex]

So 4/5 times 5/8 is 1/2.

SOMEONE PLEASE HELP ME QUICKLY WITH THIS,ITS AN EMERGENCY!!!!! pls explain how you get the solution as well, sorry!

Thank you <3

Answers

The statement that reflects the running rates is Pepe ran 9/8  mile in 1/2 hour and Paul ran 19/24 mile in 1/3 of an hour.

What is the speed?

Speed is the total distance run per time. It can be determined by dividing the total distance travelled by the total time.

Speed = distance / time

Speed if Paul ran 1/5 mile in 4/15 hour

Speed = 1/5 ÷ 4/15

1/5 x 15/4 = 3/4 miles per hour

Speed if Pepe ran 8/10 mile in 1/4 of an hour

Speed = 8/10 ÷ 1/4

8/10 x 4 = 16/5 = 3 1/5 mile per hour

Difference in speeds =

[tex]3\frac{1}{5}[/tex] - [tex]\frac{3}{4}[/tex]

[tex]3\frac{4 - 15}{20}[/tex] = [tex]2\frac{9}{20}[/tex]

Speed if Paul ran 4/15 mile in 1/5 hour

Speed = 4/15 ÷ 1/5

4/15 x 5 = 4/3 = 1 1/3 miles per hour

Speed if Pepe ran 1/4 mile in of 8/10 an hour

Speed = 1/4 ÷ 8/10

1/4 x 10/8 = 5 / 16

Difference in speeds = [tex]1\frac{1}{3} - \frac{5}{16}[/tex] = [tex]1\frac{1}{48}[/tex]

Speed if Paul ran 1/3 mile in 19/24 hour

Speed = 1/3 ÷ 19 / 24

1/3 x 24/19 = 8/19 miles per hour

Speed if Pepe ran 1/2 mile in of 9/8 an hour

Speed = 1/2  ÷ 9/8

1/2 x 8/9 = 4/9 mile per hour

Difference = 4/9 - 8/19 = 4/171

Speed if Pepe ran 9/8  mile in 1/2 hour

Speed = 9/8 ÷ 1/2

9/8 x 2 = 2 1/4  miles per hour

Speed if Paul ran 19 / 24 mile in of 1/3 an hour

Speed =  19 / 24  ÷ 1/3

19 / 24 x 3 = 2 3/8 miles per hour

Difference =

[tex]2\frac{3}{8} - 2\frac{1}{4}[/tex]

[tex]\frac{3 - 2}{8}[/tex] =  [tex]\frac{1}{8}[/tex] miles per hour

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22The value of the hypotenuse in the right triangle shown isinches.14 in48 inFigure not drawn to scale

Answers

SOL

Step 1 :

In this question, we are meant to find the value of

the hypotenuse in the right angle below:

Before, we proceed, we still need to remind ourselves of Pythagoras' theorem,

Pythagoras theorem states that “In a right-angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides“.

Step 2 :

From the above theorem, we can see that that the two adjacent sides are :

14 inches and 48 inches.

From the principle of Pythagoras' Theorem,

[tex]\begin{gathered} c^2=a^2+b^2 \\ \text{where a = 14 inches} \\ b\text{ = 48 inches} \\ c^2=14^2+48^2 \\ c^2\text{ = ( 14 x 14 ) + ( 48 x 48 )} \\ c^2\text{ = 196 + 2304} \\ c^2\text{ = 2500} \\ \text{square root both sides, we have that :} \\ c\text{ = 50 inches} \end{gathered}[/tex]

CONCLUSION :

The value of the hypotenuse in the Right angle, c = 50 inches.

Compare the triangles and determjne whether they can be proven congruent, if possible by SSS, SAS, ASA, AAS or HL

Answers

Since the triangles has a pair of congruent (equal) angles , and an equal side between the angles. It is congruent by ASA ( angle -side -angle)

Write an expression to show how much Gretchen paid for drama,action, and comedy videos if she paid $4 for each at a sale. Evaluate the expressionGretchen’s video purchasesMystery 6Action 3Comedy 5Drama 2Romance 2

Answers

Let d the number of drama videos, c the number of comedy videos and a the number of action videos.

If the cost per video (independently of the genre) is $4, then, for the total cost of the videos Gretchen payed, you can write:

total = 4d + 4c + 4a

Now, based on the given table, you have:

d = 2

c = 5

a = 3

By replacing the previous values into the expression for total, and by simplifying, you obtain:

total = 4(2) + 4(5) + 4(3)

total = 8 + 20 + 12

total = 40

Hence, Gretchen payed $40 for the videos

Use the graph to answer the question.Which statement matches the vector operation shown on the coordinate grid?

Answers

We have the correct statement about the vectors in the graph.

We can already see that it is a sum of vectors like:

[tex]v+w=u[/tex]

As v has starting point at (-1,0) and ending point at (3,3), we can describe the vector as:

[tex]v=(3-(-1))\hat{i}+(3-0)\hat{j}=4\hat{i}+3\hat{j}[/tex]

As w starts at (3, 3) and ends on (5, 2), we can describe it as:w

[tex]w=(5-3)\hat{i}+(2-3)\hat{j}=2\hat{i}-1\hat{j}[/tex]

Finally, u starts at (-1,0) and ends at (5,2), so it can be described as:

[tex]u=(5-(-1))\hat{i}+(2-0)\hat{j}=6\hat{i}+2\hat{j}[/tex]

Answer: v + w = u for v = 4i + 3j, u = 2i - j and u = 6i + 2j [Option C].

Please help me with the question below(also please answer the question in a maximum of 5-10 minutes).

Answers

Given that Tom's yard is in the shape of a trapezoid, you know that the formula for calculating the area of a trapezoid is:

[tex]A=\frac{(b_1+b_2)}{2}\cdot h[/tex]

Where "h" is the height of the trapezoid and these are the bases:

[tex]\begin{gathered} b_1 \\ b_2 \end{gathered}[/tex]

In this case, you can identify that:

[tex]\begin{gathered} b_1=65\text{ }ft \\ b_2=50\text{ }ft \\ h=30\text{ }ft \end{gathered}[/tex]

Then, you can substitute values into the formula and evaluate:

[tex]A=\frac{(65\text{ }ft+50\text{ }ft)}{2}\cdot30\text{ }ft[/tex][tex]A=\frac{115\text{ }ft}{2}\cdot30\text{ }ft[/tex][tex]A=\frac{3450\text{ }ft^2}{2}[/tex][tex]A=\frac{3450\text{ }ft^2}{2}[/tex][tex]A=1725\text{ }ft^2[/tex]

Hence, the answer is:

[tex]1725\text{ }ft^2[/tex]

On a particular day, the amount of untreated water coming into the plant can be modeled by f(t) = 100 + 30cos(t/6) where t is in hours since midnight and f(t) represents thousands of gallons of water. The amount of treated water at any given time, t, can be modeled by g(t) = 30e^cos(t/2)a) Define a new function, a′(t), that would represent the amount of untreated water inside the plant, at any given time, t.b) Find a′ (t).c) Determine the critical values of this function over the interval [0, 24).

Answers

a)The amount of untreated water inside the plant will be the difference between the difference f(t) - g(t), then, a(t) can be defined as follows:

[tex]a(t)=100+30cos(\frac{t}{6})-30e^{cos(\frac{t}{2})}[/tex]

b) the derivative of a(t) is the following:

[tex]a^{\prime}(t)=-5sin(\frac{t}{6})+15sin(\frac{t}{2})e^{cos(\frac{t}{2})}[/tex]

c) the critical values of a(t) over the interval [0, 24) are:

[tex]\begin{gathered} t=0 \\ t=6\pi \end{gathered}[/tex]

Hello! I need a little bit of help with this question please. (This information is not from an open test, it is a book as I'm studying for the ASVAB I am going to take later on.)

Answers

Given:

[tex]\sqrt{100}-\sqrt{64}[/tex]

To find:

We need to solve this sum and find the final answer

Step-by-step solution:

To solve this problem, we need to know the square root of 100 and 64.

√100 = 10

√64 = 8

[tex]\begin{gathered} =\sqrt{100}-\sqrt{64} \\ \\ =10\text{ - 8} \\ \\ =2 \end{gathered}[/tex]

Final answer:

Thus 2 (Option A) is the correct answer.

3-35. Fisher thinks that any two lines must have a point of intersection. Is he correct? If so, explain how youknow. If not, produce a counterexample. That is, find two lines that do not have a point of intersection and explainhow you know

Answers

Any two lines must have a point of intersection, with ONLY ONE exception : when the lines are parallel. That means they have exactly the same inclination or Slope.

As an example of two lines that hasnt point of intersection they are

y = 5x + 16

y = 5x + 11

We know both lines have no point of intersection because

both have the same slope or inclination m. By comparation with slope intercept equation

y = mx + b

then we see both have same inclination, and b is 11 in one line and 16 in the other line. This means both lines are parallel with one line going over the other line, without touching it in any point.

work out sues total pay

Answers

Sue's total pay for the year given the salary, bonus and share of profit is  £38,110.

What is the total pay?

Sue's total pay for the year is a function of the salary, the share of the profit that she earns and the bonus.

Salary for the year = monthly salary x number of months in a year

£1410 x 12 = £16,920

The next step is to determine the profit last year

Profit = total revenue - total cost

£549,000 - £473,500 = £75,500

Now determine the share of profit that Sue would earn.

Share of profit = 26% x  £75,500

0.26 x  £75,500 = £19,630

Now determine the total bonus she would earn : 4 x £390 = £1560

Total salary = £1560 +  £19,630 +  £16,920 = £38,110

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What is a stem and leaf plot? How is it used and how exactly do i solve one? (an example would be great)

Answers

A stem and leaf plot is a table where each of the data is divided into two parts. The stem, that is the first digit and the leaf is the last digits. Let's say that we have the following set of data.

[tex]10,\text{ 12, 25, 28, 29, 35, 38, 40, 44}[/tex]

If we want to make a stem and leaf plot of that data, we first write a column where we place the first digit of each number without repetition, like this:

[tex]\begin{gathered} 1 \\ 2 \\ 3 \\ 4 \end{gathered}[/tex]

These are the stems. Now the leaves are the last digit of each number put in order next to the corresponding first digit, like this:

[tex]\begin{gathered} 1\parallel\text{ 0 2} \\ 2\parallel\text{ 5 8 9} \\ 3\text{ }\parallel\text{5 8} \\ 4\text{ }\parallel\text{0 4} \end{gathered}[/tex]

Polynomial Functions:Find P(-1) and p(2) for each function.“P(x) = 4-3x”

Answers

[tex]P(x)=4-3x[/tex]

P(-1):

[tex]\begin{gathered} P(-1)=4-3(-1) \\ P(-1)=4+3 \\ P(x)=7 \end{gathered}[/tex]

P(2):

[tex]\begin{gathered} P(2)=4-3(2) \\ P(2)=4-6 \\ P(2)=-2 \end{gathered}[/tex]

write an equation of each parabola in vertex form. Vertex (3,-2) Point (2,3)

Answers

The equation of Parabola in the vertex form with vertex (3,-2) and point(2,3) is y = 5(x-3)² - 2 .

The equation of parabola with vertex (h,k) is denoted by the equation

y = a(x-h)² + k

In the question ,

it is given that

the vertex of the Parabola is (3,-2) and the point is (2,3)

So, the equation of the parabola with vertex (3,-2) will be

y = a(x-3)² - 2

Since the point (2,3) lies on the parabola ,

So, 3 = a(2-3)² - 2

3 + 2 = a*(-1)²

5 = a

Substituting a in the equation  y = a(x-3)² - 2 ,

we get

y = 5(x-3)² - 2

Therefore , The equation of Parabola in the vertex form with vertex (3,-2) and point(2,3) is y = 5(x-3)² - 2 .

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I am struggling with this question. could you help me please??

Answers

Problem

Solution

Let x = age, W= weight the two variables of interest

We have the following probabilities given:

P(x<37) =0.142

P(W< 2500) = 0.051

P(x <37 AND W<2500)= 0.031

And we want the following probability and we can use the total probability rule:

P(x < 37 OR W< 2500) = P(x<37) +P(W< 2500) -P(x<37 AND W<2500)

If we replace we got:

P(x < 37 OR W< 2500)= 0.142+ 0.051- 0.031= 0.162

what is the y intercept of y = 250 + 15x

Answers

The y-intercept of y = 250 + 15x is (0,250)

What is y-intercept?

A line's y-intercept is the distance in y coordinates from the line's intersection with the y-axis at its origin. A location on the graph where x is 0 is known as the y-intercept. The y-intercept of a line that is perpendicular to the x-axis is undefined.

This is an illustration of a y-intercept. Think about the line y = x + 3. The point where this graph crosses the y-axis is (0,3). Therefore, the y-intercept of the line y = x+ 3 is (0,3).

Here to determine the y-intercept put x=0,

Given, y = 250 + 15x

Replacing x by 0 in the above equation we get,

y = 250 + 15×0

y=250 +0

y=250

Therefore, the y-intercept of y = 250 + 15x is (0,250)

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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.Solve the inequality and describe the solution set.y-6 > 1232, Math symbolsRelations► Geometry► Groups► Trgonometry3 of 3 AnsweredType here to searcho66F Mosty clou

Answers

The problem gives the inequality:

[tex]y-6\ge12[/tex]

solving for y we get:

[tex]\begin{gathered} y\ge12+6 \\ y\ge18 \end{gathered}[/tex]

The solution set is all real numbers equal or greater than 18, i.e.,

[tex]\lbrack18,+\infty)[/tex]

In an arithmetic sequence with a1=-5 and d=-3, which term is -24?The term -24 is the ___th term of the sequence

Answers

Given:

[tex]\begin{gathered} a_1=-15 \\ d=-3 \\ a_n=-24 \end{gathered}[/tex]

To find:

The value of n.

Explanation:

The nth term formula for the arithmetic sequence is,

[tex]a_n=a_1+(n-1)d[/tex]

Substituting the given values we get,

[tex]\begin{gathered} -24=-15+(n-1)(-3) \\ -24=-15-3n+3 \\ -24=-3n-12 \\ -3n=-24+12 \\ -3n=-12 \\ n=4 \end{gathered}[/tex]

Thus, -24 is the 4th term of the sequence.

Final answer:

The term -24 is the 4th term of the sequence.

J(-6-2)3-*NWMark this and return2--9-8-7-6-5-4-3-2-3₁ 1 2 3 4 5 61-5737-2-cd-6--7--8-2 do-9--10--11--12--13-8 9 10 11 xK(8,-9)What is the x-coordinate of the point that divides thedirected line segment from J to K into a ratio of 2:5?X == (m²²7 m )(x₂ − ×₁) + X₁m+n0 000-22Save and ExitNextSubmit

Answers

Use the given formula:

[tex]x=(\frac{m}{m+n})(x_2-x_1)+x_1[/tex]

Being m: 2 and n: 5

x1: -6

x2: 8

[tex]\begin{gathered} x=(\frac{2}{2+5})(8-(-6))+(-6) \\ \\ x=\frac{2}{7}*(14)-6 \\ \\ x=4-6 \\ \\ x=-2 \end{gathered}[/tex]Then, the x-coordinate of th point that divides the directed line segment from J to K into a ratio 2:5 is -2Answer: -2

At a school on Monday, 3 out of every 4 students were wearing shirts. There were 600 students present in school on Monday. How many of the students were wearing shirts? A. 599, because 600 - (4 - 3) = 599 B. 450, because C. 50, because 600 - (4 x 3) = 50 600 - Student D. 800, because 450 4= Students 3=sludents 4 600 600 800 so

Answers

3 out of 4 students mean

3/4th students were wearing shirts.

Total students = 600

So,

3/4th of 600 students were wearing shirt.

Let us calcualte (3/4)th of 600:

[tex]\begin{gathered} \frac{3}{4}\times600 \\ =\frac{3\times600}{4} \\ =\frac{1800}{4} \\ =450 \end{gathered}[/tex]Answer

450 students

Send me Answers for Questions A, B, and C

Answers

Answer: A) 4 B) 30 C) 6

Step-by-step explanation:

For question A, you subtract the highest number and the lowest number (10-6)

For question B, you add all the frequency numbers together

For question C, you use your answer on B and divide it by 5

Which formula can be used to find the sum of the mesures of all the interior angles of a regular polygon with n sides?

A. S = (n-2)180 degrees
B. S = (n+2)180 degrees
C. S = (n-2)90 degrees
D. S = (n+2)90 degrees

Answers

Answer:180(n – 2),

Step-by-step explanation:

Which values are solutions to the inequality below?Check all that apply.√x ≤ 5A. 1B. 18C. -5D. 25E. 24F. 625

Answers

Given the inequality:

[tex]\sqrt[]{x}<5[/tex]

We need to solve the inequality to get a range of values for x.

This we can do by finding the square of both sides:

[tex]\begin{gathered} (\sqrt[]{x})^2<5^2 \\ x<25 \end{gathered}[/tex]

On checking the options given, we will pick the numbers that are strictly less than 25.

Therefore, the correct options are:

OPTION A

OPTION B

OPTION C

OPTION F

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A cannery needs to know the volume-to-surface-area ratio of a can to find the size that will create the greatest profit. Find the volume-to-surface-area ratio of a can.Hint : For a cylinder, S = 2r2 + 2rh and V = r2h.a. 1/2b. 2(r+h) / rhc. r(2r + 2h rh)d. rh / 2(r+h) Can someone help me pls, i have another 3 questions like this :s Complete each equation so that it has infinitely many solutions. 12x - x + 8 + 3x = __x + __ (__ are blanks) Find the volume of a cuboid with the following measurmentsLength:4.5 cm Breadth: 2 cm Height: 50 cm ans is :45,000 But I am not getting the correct ans please send working The vertices of ABC are A(2, 3), B(3, 5), and C(4, 1). If (x,y)--> (x-4, y-1), give the vertices of ABC. Solve for x. Write the reasons next to each step.Submit723x+10 Determine whether 17y = 3x 19 is quadratic or not. Explain.No; there is no x2 term, so a = 0.No; there is no x-term, so b = 0.No; there is no constant term, so c = 0.Yes; it can rewritten in the form y = ax2 + bx + c. three components down, one to go! that last component is called net exports. for example, let's start with an economy with consumption of $350, economic investment of $200, and government purchases of $180. if overall gdp calculated via the expenditure method is $700, then what must that tell us about net exports? In 1940, what did Louie feel pulled to do and why? Use evidence from the text to support your response. I wanted to know if this is the right answer In 1990, the cost of tuition at a large Midwestern university was $104 per credit hour. In 1998, tuition had risen to $184 per credit hour. How does Steinbeck construct loneliness in the story? Despite living in close proximity, all of the characters seem to be lonely. Is loneliness caused by socially imposed barriers, personal choice, or both? Explain. johnson's selling and administrative budget is based on budgeted unit sales, which are 4,600 units for august. the variable selling and administrative expense is $7.30 per unit. the budgeted fixed selling and administrative expense is $51,980 per month, which includes depreciation of $6,440 per month. the remainder of the fixed selling and administrative expense represents current cash flows. the cash disbursements for selling and administrative expenses on the august selling and administrative expense budget should be: (x^4/7^-8)^7Solve asap pls Find the measure of the missing arc (dont worry about the degree symbol) Using a social or political issue from the Progressive Era, compare and contrast whether that issue still exists today and what are the similarities and differences with the issues today? If the issue does not exist today, please state why you believe that the issue no longer exists in our society.Also, think about how people protested, demonstrated, and otherwise expressed their desire for change of the policy or treatment of the targeted group. millie sees pretty, colored butterflies on all the walls. she also hears gentle music, which is not actually there. the presence of these behaviors illustrates symptoms of schizophrenia. a. positive b. psychomotor c. active d. negative 3. What is humanism and how is the concept connected to the Renaissance? What happened after Emperor Wudi expanded Chinas empire over a larger territory?New schools were created to train scholars.The people migrated to other lands. The amount of trade dropped dramatically. Citizens became less involved in government. State the rational number represented by each letter on the number line as a decimal.