during keon's golf drive, the angular velocity of his club is zero at the top of the backswing and 33 rad/s at the bottom of the downswing just before ball impact. the downswing lasts 0.29 s, and the distance from the club head to the axis of rotation is 1.88 m at the bottom of the downswing. what is the average tangential acceleration of the club during the downswing (in m/s2)?

Answers

Answer 1

The average tangential acceleration of the club during the downswing is 113.79 rad/s².

Centripetal acceleration is due to the change within the direction of tangential speed, whereas tangential acceleration is due to any trade inside the value of the tangential speed.

The tangential acceleration is while the rotational velocity adjustments, that is 0 for uniform circular motion. while vector speed adjustments path however not important. for this reason Tangential acceleration =zero. Angular acceleration is the trade in angular velocity divided by using time, whilst tangential acceleration is the change in linear speed divided through time.

given,

∆ ω = 33 rad/s

∆t = 0.29 sec

α = (change in ω)/(change in t)  

   α = 33 rad/s / 0.29 s = 113.79 rad/s²

tangential acceleration = r α = 1.88*113.79 = 213.93 m/s2

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Related Questions

The deepest section of ocean in the world is the Mariana Trench, located in the Pacific Ocean. Here,the ocean floor is as low as 10,918m below the surface. If the index of refraction of water is 1.33, howlong would it take a laser beam to reach the bottom of the treach?

Answers

Given:

The depth of the trench, d=10,918 m

The refractive index of the water, n=1.33

To find:

The time it takes for the laser beam to reach the bottom of the ocean.

Explanation:

The refractive index of water is given by,

[tex]n=\frac{c}{v}[/tex]

Where c is the velocity of the laser in vacuum and v is the velocity of the laser in water.

On substituting the known values,

[tex]\begin{gathered} 1.33=\frac{3\times10^8}{v} \\ \implies v=\frac{3\times10^8}{1.33} \\ =2.3\times10^9\text{ m/s} \end{gathered}[/tex]

The velocity is given by the equation,

[tex]v=\frac{d}{t}[/tex]

Where t is the time it takes for the laser to reach the bottom of the trench.

On substituting the known values,

[tex]\begin{gathered} 2.3\times10^8=\frac{10,918}{t} \\ \implies t=\frac{10,918}{2.3\times10^8} \\ =47.5\times10^{-6}\text{ s} \\ =47.5\text{ }\mu\text{s} \end{gathered}[/tex]

Final answer:

The laser beam would reach the bottom in 47.5 μs

what is a tone? multiple choice question. a sound with definite and steady vibrations a note that is emphasized the distance between two pitches the distinctive sound quality of an instrument

Answers

A tone is a sound with definite and steady vibrations.

What is tone?
The author's attitude toward the topic they are writing about is the definition of tone in literature. The Latin word tonus, which means a sound or accent, and the French word tonne, which denotes a musical sound, are the origins of the word tone. Whether the author intends it or not, the reader always picks up on the tone of a work of literature. The words an author chooses as well as how they are used make up their diction. The way an author speaks affects the reader's mood. The syntax, point of view (a particular attitude as well as way of describing a subject), diction, and degree of formality used in writing all convey the tone of the piece. Writing can take on a formal or informal tone.

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i would appreciate it if you could help me if would help a bunch on getting caught up with my work.

Answers

2. Experiment:

We need to make a circuit to test which of the materials are conductors and insulators.

Build the circuit as shown below.

If the light bulb is on then it is a conductor otherwise it is an insulator.

Keep replacing the material one by one to test all the materials.

A periodic wave has a wavelength of 1.6 m and a speed of 16 m/s. What is the wave frequency?

Answers

ANSWER

10 Hz

EXPLANATION

Given:

• The wavelength of a periodic wave, λ = 1.6 m

,

• Its speed, v = 16 m/s

Find:

• The wave frequency, f

The frequency of a wave is given by the quotient between the wave's speed and its wavelength,

[tex]f=\frac{v}{\lambda}[/tex]

Replace the known values and solve,

[tex]f=\frac{16m\/s}{1.6m}=10\text{ }\frac{1}{s}=10\text{ }Hz[/tex]

Hence, the frequency of the wave is 10 Hz.

Find the total translational kinetic energy of0.5 L of oxygen gas held at a temperature of3◦C and a pressure of 1.5 atm.Answer in units of J.

Answers

Given

Volume of the oxygen gas is

[tex]V=0.5L=0.0005m^3[/tex]

The temperature is

[tex]T=3^oC[/tex]

Pressure is

[tex]\begin{gathered} P=1.5atm \\ \Rightarrow P=1.5\times101325=151,987.5Pa \end{gathered}[/tex]

To find

The translational kinetic energy

Explanation

The translational kinetic energy is given by

[tex]K=\frac{3}{2}nRT[/tex]

For ideal gas,

[tex]PV=nRT[/tex]

Thus,

[tex]\begin{gathered} K=\frac{3}{2}PV \\ \Rightarrow K=\frac{3}{2}\times151987.5\times0.0005 \\ \Rightarrow K=113.99J \end{gathered}[/tex]

Conclusion

The translational kinetic energy is 113.99J

a cart with a mass of 2.0 kg is pulled across a level desk by a horizontal foirce of 4.0n. if the coeffiecient of kinetic friciton is 0.12 what is the acceleration of the cart

Answers

Answer:

The acceleration of the cart:

a =  0.82 m/s²

Explanation:

 Given:

m = 2.0 kg

F = 4.0 N

μ = 0.12

g = 9.8 m/s²

___________

a - ?

Friction force:

Ff = μ·m·g

2 Newton's law:

m·a = F - Ff

The acceleration of the cart:

a = ( F - Ff) /m

a =  F/m - (μ·m·g) / m

a =  F/m - μ·g

a = 4.0 / 2.0 - 0.12·9.8 ≈ 0.82  m/s²

32. heavy rain reduces your ability to see and be seen; in daytime turn on your a. windshield wipers. b. low beam headlights. c. windshield defroster. d. all of the above

Answers

Heavy rain reduces your ability to see and be seen. So in daytime turn on all of the above ( d ) mentioned options.

Windshield wipers and windshield defroster are for the ability to see and the low beam headlights are for the ability to be seen by others. If it is night time drive below the speed limit because it is extremely hard to maneuver under those conditions.

Windshield wipers wipes the water off your windshield consistently. Low beam headlights indicate the presence of your car. Windshield defroster condenses the frosted windshield.

Therefore, in daytime turn on your windshield wipers, low beam headlights and windshield defroster.

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The separation distance between two 2.0 kg masses is decreased by two-thirds. How is the gravitational force between them affected?

Answers

Given:

The mass of two objects is: m1 = m2 = m = 2 kg

The distance between the object is decreased by two-thirds

To find:

How on reducing the distance, the gravitational force between them affects them.

Explanation:

Let the distance between two objects each having mass "m" be "r". The gravitational force between them is given as:

[tex]F_1=G\frac{m_1\times m_2}{r^2}[/tex]

Here, G is the universal gravitational constant.

Substituting the values in the above equation, we get:

[tex]\begin{gathered} F_1=G\times\frac{2\text{ kg}\times2\text{ kg}}{r^2} \\ \\ F_1=G\times\frac{4\text{ kg}^2}{r^2}..........(1) \end{gathered}[/tex]

Now, the distance between the mass is reduced by two-thirds. Thus, the new distance between them will be "R" which is given as:

[tex]R=r-\frac{2}{3}r=r(1-\frac{2}{3})=\frac{r}{3}[/tex]

Now, the gravitational force between two masses with their distance of separation reduced by two-thirds is given as:

[tex]F_2=G\frac{m_1\times m_2}{R^2}[/tex]

Substituting the values in the above equation, we get:

[tex]\begin{gathered} F_2=G\times\frac{2\text{ kg}\times2\text{ kg}}{(\frac{r}{3})^2} \\ \\ F_2=G\times\frac{4\text{ kg}^2}{\frac{r^2}{9}} \\ \\ \begin{equation*} F_2=G\times\frac{9\times4\text{ kg}^2}{r^2} \end{equation*} \\ \\ F_2=9\times(G\times\frac{4\text{ kg}^2}{r^2})..........(2) \end{gathered}[/tex]

Substituting equation (1) in equation (2), we get:

[tex]\begin{gathered} F_2=9\times(G\times\frac{4\text{ kg}^2}{r^2}) \\ \\ F_2=9F_1 \end{gathered}[/tex]

From the above equation, we observe that the new gravitational force F2 between two masses when their distance of separation is reduced by two-thirds will be nine times that of the original value of gravitational force F1.

Final answer:

The new gravitational force F2 between two masses when their distance of separation is reduced by two-thirds will be nine times that of the original value of gravitational force F1.

Four different balls with different masses (measured in grams) were dropped from the same height on Earth. Assuming no other forces acted on the balls, match each ball with the gravitational force (measured in newtons) it experienced as it fell.gravitational force = 9.8 m/s2

Answers

We will have the following:

1. 143 g = 0.143 kg:

[tex]F=(0.143kg)(9.8m/s{}^2)\Rightarrow F=1.4014N[/tex]

2. 110 g = 0.110 kg:

[tex]F=(0.110kg)(9.8m/s^2)\Rightarrow F=1.078N[/tex]

3. 410 g = 0.410 kg:

[tex]F=(0.410kg)(9.8m/s^2)\Rightarrow F=4.018N[/tex]

4. 46 g = 0.046 kg:

[tex]F=(0.046kg)(9.8m/s^2)\Rightarrow F=0.4508N[/tex]

From this we can see that the given weights do not correspond to any of the values of column B, since the calculations to obtain the values of column B were done using grams, instead of kg, thus those values do not correspond to the unit of force Newtons.

What is the BEAT FREQUENCY when 512 Hz and a 515 Hz tuning forks are sounded at the same time?

Answers

The beat frequency is 3 beats/sec.

Beat frequency(n) can be found by using the following formula:

n=f2-f1, where f2 and f1 are the given frequencies

n= 515-512

n= 3 beats/sec

Therefore the beat frequency when 512 Hz and 512Hz tuning forks are sounded together is 3 beats/sec.

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When resistors are put in series next to each other, their overall resistance isA. Larger than that of any individual resistorB.the same as the resistance of one of the resistorsC. Smaller than the resistance of any of the resistors

Answers

Answer:

A. Larger than that of any individual resistor

Explanation:

When resistors are put in series, the overall resistance is equal to the sum of all the resistances. So, the overall resistance will be larger than that of any individual resistor.

Hey surveyor is drawing property lines . He draws one line that is 25.0 m long and is 20° south of west.  how long is the western component of the vector he has drawn?

Answers

Answer:

23.5 m

Explanation:

25 m * cos 20   =23.5 m

A tennis player can accelerate a tennis ball at 295m/s² using an average force of
58 N with his racquet. What is the mass of the tennis ball?

Answers

answer of the question is into the picture ️

5. An object travels with constant speed through 1km for one minutes and 20 seconds and accelerates with 0.125m/s² for 20 seconds, what is the total displacement? A) 1250 m B) 275 m C) 1275 m D) 1225m​

Answers

Answer:

C)  Total displacement = 1275 m or 1.275 km

Explanation:

We'll break this into two parts:  

1) Displacement during constant speed, and

2) Displacement during the acceleration phase.

Constant Speed

The displacement for this segment is already stated:  1 km.  But the information includes the time, which will allow us to calculate the speed of travel.  We'll need this for the next phase of acceleration.

Distance = Speed x Time

Speed = Distance/Time

Time = 1 minute + 20 sec, or 80 sec.

Speed = 1 km/80 sec

Speed = 0.0125 km/sec

Since we'll be using meters (not km) in the next step, convert 0.0125 km/sec to m/sec with a conversion factor:  

  (0.0125 km/sec)*(1000m/1 km) = 12.5 m/sec

Acceleration Phase

The obect is moving at a speed of 12.5 m/sec (from above) and then accelerates at a rate of 0.125 m/sec^2 for 20 seconds.

The distance (s) an object travels during this acceleration (a) is gven by:

  s = vi*t + (1/2)a*t^2,

where vi is the initial velocity (12.5 m/sec in this case), a is the acceleration (0.125 m/sec^2), and t is the time (20 seconds).

s = (12.5 m/sec)(20 sec) + (1/2)(0.125 m/sec^2)*(20 sec)^2

s = 275 meters

Now add the two distances:

1) Constant Speed Phase = 1000 m

2)  Acceleration Phase    =  275 m

Total displacement = 1275 m or 1.275 km

larry uses a lever to list a box. where does inefficiency occur in the lever

Answers

Answer:

low internal resistance.

Explanation:

A lever has a high efficiency due to the fact that it has low internal resistance. The work it puts out is almost equal to the work it receives, because energy used up by friction is quite small. On the other hand, an a pulley might be relatively inefficient due to a considerably greater amount of internal friction.

a passenger walks along the aisle of a train at a speed of 1.3 m/s. the train moves at a speed of 30.2 m/s with respect to the ground. calculate the relativistic correction to the classical value of the passenger speed with respect to the ground. what is the percentage of this correction?

Answers

The parameters of speed are time divided by distance.The most often used unit of speed in daily life is the kilometer per hour (km/h), or miles per hour in the US and the UK. The SI's unit of speed is the metre per second (m/s) (mph).

How are speeds determined?

Speed is calculated as follows: speed = distance * time.Knowing the units for distance and time is necessary to calculate the units for speed.The units will be in metres per second (m/s) in this example since the distance is measured in metres (m) and the time is measured in secondsWe have provided The passengers' speed in relation to the train is 2.30 mph, not 2.30 g.Additionally, the passenger is moving at a speed of 30.2m/s relative to the ground.And at a 28 degree angle to the north-west.Therefore, the cost for us passengers will be 4.5 cost 28 and the I. component will be 30.2 signed 28.

Now that we know the train's velocity with respect to the ground, we can calculate the passengers' velocity with respect to the train by subtracting the train's velocity with respect to the ground.We shall rearrange this equation once we have determined a city of trained individuals with regard to the ground.Now, if we just insert all of these variables, the passenger's velocity is equal to 30.2 28° I + 4.5 Cost 28° J minus 2.30 G.And after calculation, this will be equal to 3.97 G -2.30 G less, or -2.11 I.Furthermore, this will result in -2.11 I plus 1.67 G.The equation for training velocity with respect to the ground will now be as follows.The size and direction of the trend's velocity with respect to the ground must be determined.Therefore, the magnitude will be 2.11 sq plus 1.67, square root off.We shall rearrange this equation once we have determined a city of trained individuals with regard to the ground.Now, if we just insert all of these variables, the passenger's velocity is equal to -4.5 9 28° I + 4.5 Cost 28° J minus 2.30 G.Calculating yields a value of 2.69 meters per second, and the direction is equal to 2.11 divided by 1.67, which will result in 51.63 agreement.As a result, the trend's magnitude and direction will be B, 2.69 m/s, and 51.63°, respectively, with regard to the ground.

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As a result, the trend's magnitude and direction will be B, 2.69 m/s, and 51.63°, respectively, with regard to the ground.

How are speeds determined?Knowing the units for distance and time is important to determine the units for speed. In this example, the units will be measured in metres per second (m/s), as the distance is measured in metres (m) and the time is measured in seconds.We have said that, rather than 2.30 g, the passengers' speed in respect to the train is 2.30 mph.In addition, the passenger is traveling at a relative speed of 30.2 m/s to the ground.Additionally, at a 28-degree northwestern angle.As a result, our guests will pay 4.5 cost 28 and the I. component will be signed at 30.2 and be.

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a pipe that is 0.46 m long and open at both ends vibrates in the second overtone with a frequency of 1150 hz. in this situation, the distance from the center of the pipe to the nearest antinode is closest to group of answer choices zero. 7.7 cm. 15 cm. 12 cm. 3.8 cm.

Answers

The distance of the center pipe to the nearest antinode at the second harmonic frequency is closest to 12 cm.

We need to know about the harmonic frequency to solve this problem. When the string is vibrating at its second harmonic frequency, it should follow the rule

λ = L

where λ is wavelength and L is the length of the string

From the question above, we know that

f = 1150 Hz

L = 0.46 cm

Find the wavelength

λ = L

λ = 0.46 m

The distance from the center of the pipe to the nearest antidote is equal to 1/4 of the wavelength. Hence,

s = 1/4 λ

s = 1/4 . 0.46

s = 0.115 m

s ~ 12 cm

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describe the forces that are acting on the cake as it falls and when it lands on the ground.

Answers

Answer:

gravitational force

Explanation:

expressed the weight of the object.

When the cake falls into the ground gravitational force and electromagnetic forces are working on it and when it lands on the ground gravitational, electromagnetic and normal force act on it.

What is Force?

Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces. For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.

Two fundamental forces are at play while the ball falls: gravity, which causes the ball to descend, and electromagnetic forces, which causes the ball to interact with the air.

The gravity force still affects the ball when it strikes the ground, but it is less significant than the electromagnetic force generated by the earth and the ball itself. The deformation and restoration of the ball's shape are caused by the EM (electromagnetic) inside the ball. The ball stops descending due to the EM force with the earth.

So the simple answer is consistent with the other answers here: the electromagnetic force is responsible for the force between the ball and the ground.

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a boy and a girl are at rest on separate skis 12 m apart on a horizontal icy surface. the boy and his skis have twice the inertia of the girl and her skis. determine the location of the center of mass in meters measured from the position of the girl.

Answers

With the position of the girl as a reference point, the center of mass is 8 m from the girl position.

If there are two objects as shown on the attached picture, the center of mass is:

xc = m₁ / (m₁ + m₂) . x₁ +  m₂ / (m₁ + m₂) . x₂

From the problem, we know that the boy and his skis have twice the inertia of the girl and her skis. We can replace the mass in the equation with inertia, hence:

xc = I₁ / (I₁ + I₂) . x₁ +  I₂ / (I₁ + I₂) . x₂

Let:

I₁ =  the girl's inertia

I₂ = the boy's inertia

Hence,

I₂ = 2 I₁

Let make the position of the girl as a reference point, then,

x₁ = 0

x₂ = 12

Plug these parameters into the formula:

xc = I₁ / (I₁ + I₂) . 0 + 2 I₁ / (I₁ +  2 I₁) . 12

xc = 2/3 . 12 = 8 m

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On his trip from home to school, Noah Omwerk drives along three streets after exiting the driveway. He drives 1.85 miles south, 2.43 miles east, and 0.35 miles north. Determine the magnitude of Noah's resultant displacement. And the angle from East to South.

Answers

The resultant displacement of Noah from the question is  2.9 miles.

What is the resultant displacement?

The displacement is a vector quantity. Recall that a vector quantity is going to posses both a magnitude and a direction as we can see. This implies that the result of the vector which is the single vector that has the combines effect in magnitude and direction as all the vectors put together would be obtained by a geometric rather than an algebraic method. We now have to apply the rules that are used to obtain the resultant vector in each of the cases that does apply here.

We are now told that he drives 1.85 miles south, 2.43 miles east, and 0.35 miles north. The resultant of the vector in the North - South direction is; 1.85 miles - 0.35 miles = 1.5 miles.

Then the general resultant vector is obtained from;

R = √(1.5)^2 + (2.43)^2

R = 2.9 miles

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Neptune has a mass that is about 17 times the mass of earth. the distance between the sun and neptune is about 30.1 times the distance between the sun and earth. if the gravitational force between the sun and earth is 3.5 x 1028 n, which is closest to the force between neptune and the sun? 6 x n 6 x n 6 x n 6 x n

Answers

Answer: 6 x 10^26 N

Explanation:

a uniformly charged conducting sphere of 1.22 m radius has a surface charge density of 8.13 c/m*. (a) find the charge on the sphere. (4) what ts the total electric flux leaving the surface of the sphere? (c) calculate the electric field at the surface of the sphere.

Answers

We select a spherical-shaped Gaussian surface that is concentric with the conducting sphere and has a little bigger radius. Gauss's law determines the flux:

ϕ= ϵ 0 q \s​ = 8.85×10 −12 C 2 /N.m 2

3.66×10 −5 C =4.1×10 6 N.m 2 /C

What makes it the Gauss law?

Gauss' Law, which bears the name of German physicist Carl Friedrich Gauss, is the third of Maxwell's four equations. According to Gauss' Law, an electric charge, qv, or static electricity, produces an electric field, E. (voltage). According to this equation, adding more charge will result in a larger electric field.

According to Gauss's Law, the flux of an electric field through a closed surface equals the contained charge divided by a constant.

Gauss's Law may be used to determine the field due to four different types of equally charged objects: a straight wire, an infinite plate sheet, a thin spherical shell, and a low evenly charged sphere.

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psychology is the ___ study of behavior and mental processes

Answers

Answer:

scientific study

Explanation:

I hope that helps

Answer:

scientific studies

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Equal masses are suspended from two separate wires made of the same material. The wires have identical lengths. The first wire has a larger cross-sectional area than the second wire. Which wire will stretch the least?.

Answers

The original lengths of both wires are equal, the thicker wire will stretch less as a result since Young's Modulus predicts that its original length will change less.

Young's modulus is a measurement of a material's capacity to endure changes in length when subjected to compression or tension along its length. Young's modulus, also known as the modulus of elasticity, is determined by dividing the longitudinal stress by the strain. i.e.

Young's modulus = stress/strain

We can assume that the thicker wire must have less strain if it suffers less stress than the thinner wire because strain is defined as the percentage change in length.

Therefore we can said that, For the Young's modulus to remain constant, which it does, it must also drop correspondingly as strain rises. The thicker wire will stretch less as a result since its original length will change less because both wires started off the same length.

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a lighthouse is located on a small island 5 km away from the nearest point p on a straight shoreline and its light makes seven revolutions per minute. how fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from p? (round your answer to one decimal place.)

Answers

188.4 km/min is the beam of light moving along the shoreline.

The lighthouse is 5 km far away from the nearest Point P on a straight shoreline. This is often radius of the encirclement of the beam of light moving at 7 rpm.

At 7 rpm, One Circumference of the sunshine takes 70/7 = 10 seconds 2πr is= 2.π.5 km in 10 seconds or

In one second the beam covers 10π/10 = π km or 3.14 km/s.

Now, if the purpose P is 1 km away from the lighthouse, the Radius is reduced to 1 from 5 km,

Consequently The Angular displacement would remain the identical but the speed would be slower for one circumference i.e. 2πr in 10 seconds.

Or one second= (2π.1)/10

= .628π km

= π/10

= 3.14 km/s

By converting km/s into km/min

The answer will be = 188.4 km/min.

188.4 km/min fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from point P.

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a 7.0 g bullet is fired into a 1.5 kg ballistic pendulum. the bullet emerges from the block with a speed of 200 m/s, and the block rises to a maximum height of 11.7 cm. find the initial speed of the bullet.

Answers

the initial speed of the bullet: 520.31 m/sec

using the conservation of linear momentum we write

 m1u1 +  m2 u2 = m1 v1  +  m2v2

where u1 and u2  are the initial velocities of masses m1 and m2\

where v1, and v2  are the final velocities of masses m1 and m2\

hence  (.007) (u1)  + 1.5(0) =  1.5(v2)  +  .007(200)

using the energy equation for the block alone we get

mgh  = 1/2 m (v2[tex])^2[/tex]

hence    9.8(.0117) =.5 (v2[tex])^2[/tex]

hence v2= 1.494 m/sec

substitute it in 1

we get,

(.007) (u1)  + 1.5(0) =  1.5(1.494 )  +  .007(200)

           u1 =initial speed of the  bullet= 520.31 m/sec

What is Speed?

The definition of speed can be given as a measure of the distance travelled by an object and the time needed to travel the distance. Simply put, it is a measure of how fast an object is moving, but it does not give direction. If we get direction by speed, it is called "velocity".

Speed ​​can be calculated in science. The speed formula is a formula derived from science and is used to calculate different speeds. The formula for speed is:

[tex]Speed = \frac{Distance}{Time}[/tex]

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would not be an indication of a car getting ready to pull into your lane. a. a turn signal b. a hand signal c. wheels turned toward the street d. an open car door

Answers

The option that would not be an indication of a car getting ready to pull into your lane is an open car door ( d ).

Option A is an indication of a car getting ready to pull into your lane because a turn signal is an indicator installed in the car to indicate the change of lanes. Option C is an indication of a car getting ready to pull into your lane, but it is not a 100% indication, because not every driver is going to notice if your wheels are turned or not.    

Option B is an indication of a car getting ready to pull into your lane during day time because during day time the turn signal might not be bright enough to see. So one probably uses hand signal to make sure that other drivers see clearly that you are about to change lanes.

Therefore, the option that would not be an indication of a car getting ready to pull into your lane is an open car door ( d ).

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when resistors 1 and 2 are connected in series, the equivalent resistance is 13.6. when they are connected in parallel, the equivalent resistance is 2.40. what are (a) the smaller resistance and (b) the larger resistance of these two resistors?

Answers

The larger resistance is R₂ =12Ω.

Resistance values are expressed in ohms (Ω). when an electron differential exists among terminals, energy will float from excessive to low. Resistance counteracts that waft. The greater the resistance, the lower the current. Conversely, the decrease in the resistance, the extra the modern.

series connection:- R equivalent = R₁ + R₂

                                     R₁ + R₂ = 13.6 Ω

R₁ = 13.6 Ω - R₂

parallel connection:- R equival;ent =  R₁R₂ / R₁ + R₂

                                       2.40 = R₁R₂ / R₁ + R₂

2.40 = R₁R₂ / 13.6 Ω

R₁R₂ = 2.40 × 13.6 Ω

 R₁R₂ = 32.64 Ω

2.40 = R₁R₂ / R₁ + R₂

R₁ + R₂ =  32.64 Ω /  2.40 Ω

R₁ + R₂ = 13.6.

​  must be 4.0Ω and 13.6Ω, respectively.

(a) The smaller resistance is R₁ =4.0Ω

(b) The larger resistance is R₂ =12Ω

An electric-powered cutting-edge flows when electrons flow through a conductor, consisting of a metallic cord. The moving electrons can collide with the ions in the steel. This makes it greater tough for the present day to flow, and reasons for resistance.

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a 60- kg mountain climber moves 10 m up a vertical slope. if the muscles in her body convert chemical energy into gravitational potential energy with an efficiency of no more than 5%, what is the chemical energy used to climb the slope?

Answers

120000 Joules of Chemical Energy is used by the climber to climb the rope.

As the climber is moving up, its gravitation potential energy energy (G) will be given by,

Gravitational potential Energy = MgH

G = MgH

Where,

M is mass of climber which is 69 Kg,

g is acceleration due to gravity which is 10m/s².

H is the height above the earth's surface which is 10 meters.

It is provided that the chemical energy is converted to gravitational energy at a rate of 5%.

So, we can write,

5% Chemical energy (C) = Gravitational potential energy (G)

So,

5%C = MgH

Putting all the values,

5C/100 = 60(10)(10)

C = 120000 Joules.

The used chemical energy is 120000 Joules.

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A 10 kg box is pulled across a level floor, where the coefficient of kinetic friction is
0.35. What horizontal force is required for an acceleration of 2.0 m/s2?

Answers

A 10 kg box is pulled across a level floor, where the coefficient of kinetic friction is 0.35. The horizontal force is required for an acceleration of 2.0 m/s2 will be 54.3 N

Newton’s second law states that the acceleration of an object depends upon two variables – the net force acting on the object and the mass of the object.  The acceleration of the body is directly proportional to the net force acting on the body and inversely proportional to the mass of the body.

equation of motion will be

F(net) =  mass * acceleration

F - fr = m * a

where

F = force by which the box is moving

fr = force due to friction

m = mass of the object

a = acceleration by the object is moving

F = fr + m * a

  = (mu * N) + ma                                          where N = mg

  = (mu * mg) + ma

  = (0.35 * 10 * 9.8) + 10 * 2

  = 54.3 N

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