Answers
X, Y, and Z components of the vector are 398, 384 and 279 resp.
Vector is a physical quantity which has both magnitude and direction. Vector A can be written as A = a₁i + a₂j + a₃k where a₁, a₂, a₃ are components along X, Y, Z axis resp. and i,j,k, are the unit vectors along X,Y,Z axis resp.
In this figure
vector F is at angle 36° from y axis, hence
x = Fcos33 = 475cos33 = 398 N
y = Fcos36 = 475cos36 = 384 N
z = Fsin36 = 475sin36 = 279 N
The vector can be written as
F = 398i + 384j + 279k
Hence x, y and z components of this force is 398, 384 and 279 resp.
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Related Questions
Carnot engine A operates between temperatures of 500°C and 300°C. Carnot engine B operates between 900°C and 700°C. Which statement correctly compares the efficiencies of the engines?
A.Both engines have the same efficiency.
B.Engine B is more efficient than engine A.
C.**Engine A is more efficient than engine B.
Answers
Answer: check the pic
Explanation:
A 20 kg child is on a swing that hangs from 2.6-m-long chains. What is her maximum speed if she swings out to a 50 degree angle?
Answers
At the highest point of the swing, the child has maximum potential energy and zero kinetic energy. At the lowest point of the swing, the child has maximum kinetic energy and zero potential energy. Therefore, the total energy of the system remains constant, and we can write:
PE = KE
where PE is the potential energy and KE is the kinetic energy.
The potential energy of the child on the swing can be calculated as:
PE = mgh
where m is the mass of the child, g is the acceleration due to gravity, and h is the height of the swing at the highest point. Since the swing hangs from 2.6-m-long chains, the height of the swing at the highest point is:
h = 2.6 m - 2.6 m cos(50°) = 1.32 m
Substituting the values, we get:
PE = (20 kg)(9.81 m/s^2)(1.32 m) = 258.2 J
At the lowest point of the swing, all the potential energy is converted to kinetic energy. The kinetic energy of the child on the swing can be calculated as:
KE = (1/2)mv^2
where v is the speed of the child at the lowest point. Substituting the values, we get:
KE = (1/2)(20 kg)v^2
Equating the potential and kinetic energies, we get:
PE = KE
mgh = (1/2)mv^2
2gh = v^2
v = sqrt(2gh)
Substituting the values, we get:
v = sqrt(2 × 9.81 m/s^2 × 1.32 m) = 4.06 m/s
Therefore, the maximum speed of the child on the swing is 4.06 m/s.
Share an experience you've had with the bureaucracy. In thinking about that experience, how would you describe the bureaucracy? What characteristics of the bureaucracy did you observe in that experience? Please explain. (Refer to Weber's theory of bureaucracy in the module.)
Answers
Bureaucracy theory explains the basis of the systematic formation of any organization and ensures efficiency and economic effectiveness.
Bureaucracy is the theory proposed by Max Weber. It forms the ideal model for the management and administration of the organization and ensures its efficiency of organization into focus.
It includes six basic principles. They are Authority Hierarchy, Division of labor, impersonality, Career Orientation, Formal rules and regulations, and Selection process.
The characteristics of bureaucracy include: It can control and regulate the behavior of people in an organization. It is the organization that has the power to make decisions. The organizations have certain rules to follow by the people.
Bureaucracy is found in large organizations like governments and corporations. It has standardized methods, and procedures to practice. It doesn't allow any flexibility for the organization.
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A 2.0-kg block sliding on a rough horizontal surface is attached to one end of a horizontal spring (k = 250 N/m) which has its other end fixed. The block passes through the equilibrium position with a speed of 2.6 m/s and first comes to rest at a displacement of 0.20 m from equilibrium. What is the coefficient of kinetic friction between the block and the horizontal surface?
Select one:
a.
0.32
b.
0.45
c.
0.58
d.
0.19
e.
0.26
Clear my ch
Answers
The coefficient of kinetic friction between the block and the horizontal surface is approximately 0.32, The correct choice is a.
We can use conservation of energy to solve this problem. Initially, the block has kinetic energy, which is gradually dissipated by friction until it comes to rest at the maximum displacement from equilibrium.
The initial kinetic energy of the block is:
K = (1/2) * mv²
where m is the mass of the block and v is its speed. Plugging in the given values, we get:
K = (1/2) * (2.0 kg) * (2.6 m/s)² = 6.76 J
At the maximum displacement from equilibrium, all of this energy has been dissipated by friction and converted into potential energy stored in the spring:
U = (1/2) * k * x²
where k is the spring constant and x is the maximum displacement from equilibrium. Plugging in the given values, we get:
U = (1/2) * (250 N/m) * (0.20 m)² = 5 J
Since energy is conserved, we can set K equal to U:
K = U
(1/2) * mv² = (1/2) * k * x²
Solving for the coefficient of kinetic friction, we get:
μk = (kx² - mv²) / (mgx)
where g is the acceleration due to gravity. Plugging in the given values, we get:
μk = [(250 N/m) * (0.20 m)² - (2.0 kg) * (2.6 m/s)²] / [(2.0 kg) * (9.81 m/s²) * (0.20 m)]
μk ≈ 0.32
Option a is correct.
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1) Compute the x and y components of the following vectors, and state them in component form.
a) A 8.0 m South
b) B-15.0 m at 30-East of North
c) C = 12.0 m at 25-South of West -
d) D=10.0 m at 53-West of North-
Answers
a) A = 8.0 m South
Since the vector is directly along the South direction, there is no x component.
x component: 0 m
y component: -8.0 m (negative because it's southward)
Component form: A = (0, -8.0)
b) B = -15.0 m at 30° East of North
To find the components, we can use the following relationships:
x component: B_x = B * sin(θ)
y component: B_y = B * cos(θ)
B_x = -15.0 * sin(30°) = -15.0 * 0.5 = -7.5 m
B_y = -15.0 * cos(30°) = -15.0 * (sqrt(3)/2) ≈ -12.99 m
Component form: B ≈ (-7.5, -12.99)
c) C = 12.0 m at 25° South of West
x component: C_x = -C * cos(θ) (negative because it's westward)
y component: C_y = -C * sin(θ) (negative because it's southward)
C_x = -12.0 * cos(25°) ≈ -10.85 m
C_y = -12.0 * sin(25°) ≈ -5.16 m
Component form: C ≈ (-10.85, -5.16)
d) D = 10.0 m at 53° West of North
x component: D_x = -D * sin(θ) (negative because it's westward)
y component: D_y = D * cos(θ)
D_x = -10.0 * sin(53°) ≈ -8.0 m
D_y = 10.0 * cos(53°) ≈ 6.0 m
Component form: D ≈ (-8.0, 6.0)
The x component of vector A is 0 since it points purely in the y direction (South), while the y component is -8.0 m (negative since it points downwards):
A = (0, -8.0 m)
b) B -15.0 m at 30-East of North:
To find the components, we first visualize the vector as shown below:
N
|
|
| 30°
| /
|/
+------------- E
The x component of B is found by projecting the vector onto the x-axis (which is East). This gives us:
Bx = -15.0 m * sin(30°) = -7.5 m
The y component of B is found by projecting the vector onto the y-axis (which is North). This gives us:
By = -15.0 m * cos(30°) = -13.0 m
Therefore, the component form of vector B is:
B = (-7.5 m, -13.0 m)
c) C = 12.0 m at 25-South of West:
To find the components, we first visualize the vector as shown below:
N
|
|
|
|
| 25°
| /
|/
+------------- W
The x component of C is found by projecting the vector onto the x-axis (which is West). This gives us:
Cx = -12.0 m * cos(25°) = -10.9 m
The y component of C is found by projecting the vector onto the y-axis (which is North). This gives us:
Cy = -12.0 m * sin(25°) = -5.1 m
Therefore, the component form of vector C is:
C = (-10.9 m, -5.1 m)
d) D = 10.0 m at 53-West of North:
To find the components, we first visualize the vector as shown below:
N
|
|
| 53°
| /
|/
+------------- W
The x component of D is found by projecting the vector onto the x-axis (which is West). This gives us:
Dx = -10.0 m * sin(53°) = -8.1 m
The y component of D is found by projecting the vector onto the y-axis (which is North). This gives us:
Dy = 10.0 m * cos(53°) = 6.2 m
Therefore, the component form of vector D is:
D = (-8.1 m, 6.2 m)
Two point charges each carrying a charge of +3.5 E−6 C are located 3.5 meters away from each other.
How strong is the electrostatic force between the two points (k = 9.0 E9 Nm2/C2)?
Is this force a repulsive force or an attractive force?
Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits to receive full credit.
Answers
Charge on each point, q = +3.5E-6 C
Distance between the points, r = 3.5 m
Coulomb's constant, k = 9.0E9 Nm²/C²
The equation for the electrostatic force between two point charges is given by:
F = k * (q1 * q2) / r^2
where F is the force between the charges, q1 and q2 are the magnitudes of the charges, r is the distance between the charges, and k is Coulomb's constant.
Substituting the given values, we get:
F = (9.0E9 Nm²/C²) * [(3.5E-6 C) * (3.5E-6 C)] / (3.5 m)²
F = 2.3E-2 N
Therefore, the electrostatic force between the two point charges is 2.3E-2 N.
Since both charges are positive, the electrostatic force between them is a repulsive force.
Answer: the answer is 0.009N
Explanation: as we know, force =KqQ/R^2
F= 9*10^9*3.5*10^-6*3.5*10^-6/(3.5)^2
F=9*10^-3N
A cube of ice is taken from the freezer at -8.7°C and placed in a 104 g glass cup filled with 330 g of water. Both the water & the cup are at 22.5°C. Eventually the system reaches thermal equilibrium at 15.4°C. Determine Qcup,
Qwater (for the water initially in the cup), Qice, & the mass of the ice.
Quip=
Qwater =
Qice =
Mice =
Answers
The value of the heat changes is as follows:
Qcup = -271 JQwater = -12284 JQice = 3951 JMice = 38.95 gWhat is the heat quantity of the cup, Qcup?The heat quantity of the cup, Qcup is calculated using the formula below:
Q = mcΔT
where;
Q is the heat absorbed or released,m is the mass of the substance,c is its specific heat capacity,ΔT is the change in temperature.The heat absorbed by the glass cup, Qcup will be:
Qcup = 104 * 0.385 * (15.4- 22.0)
Qcup = -271 J
The heat absorbed by the water, Qwater will be:
Qwater = 330 * 4.184 * *(15.4 - 22.5)
Qwater = -12284 J
The mass of the ice, Mice, that melted will be:
Heat absorbed by ice = Heat released by water + heat released by cup
-MiceΔHf = Qwater + Qcup
where
ΔHf is the heat of fusion of ice = 333.55 J/gMice = -(Qwater + Qcup) / ΔHf
Mice = -(-1228 - 271) / 333.55
Mice = 38.95 g
Finally, the heat absorbed by the ice will be:
Qice = mcΔT
Qice = (38.95 g) (2.108 J/g°C) (15.4°C - (-8.7°C))
Qice = 3951 J
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orange orb has an emissivity of 0.418 and its surroundings are at 273°C. The orange orb is absorbing heat via radiation at a rate of 362
W and it is emitting heat via radiation at a rate of 384 W. Determine the surface area of the orb, the temperature of the orb, & Pnet
A=
Torb=
Phet =
Answers
The orange orb has a surface area, temperature, and a net rate of heat transmission per unit surface area of:
A= 0.1257 m²Torb= 363.7 K (90.5°C)Pnet = 175.1 W/m²How to solve emissivity?To solve this problem, using the equation that combines rates of heat transfer via radiation, emissivity, and surface area of object:
P_net = εσA(T_orb⁴ - T_sur⁴)
where P_net = net rate of heat transfer via radiation,
ε = emissivity of the object (which is given as 0.418),
σ = Stefan-Boltzmann constant, 5.67 x 10⁻⁸ W/m²K⁴,
A = surface area of the object,
T_orb = temperature of the object, and
T_sur = temperature of the surroundings.
First, find the net rate of heat transfer via radiation:
P_net = 384 W - 362 W = 22 W
Plug in the given values and solve for the surface area:
22 W = 0.418 x 5.67 x 10⁻⁸ W/m²K⁴ x A x (T_orb⁴ - 273⁴)
Solving for A:
A = 4πr² = 4π (d/2)² = 4π (0.1 m)² = 0.1257 m²
where assuming the orange orb is a sphere with a diameter of 0.1 m.
Solve for the temperature of the orange orb:
22 W = 0.418 x 5.67 x 10⁻⁸ W/m²K⁴ x 0.1257 m² x (T_orb⁴ - 273⁴)
T_orb⁴ - 273⁴ = 22 W / (0.418 x 5.67 x 10⁻⁸ W/m²K⁴ x 0.1257 m²) = 97417 K⁴
Taking the fourth root of both sides:
T_orb = (97417 K⁴ + 273⁴)^(1/4) = 363.7 K
Calculate the net rate of heat transfer per unit surface area:
P_net/A = 22 W / 0.1257 m² = 175.1 W/m²
Therefore, the surface area of the orange orb is 0.1257 m², its temperature is 363.7 K (90.5°C), and the net rate of heat transfer per unit surface area is 175.1 W/m².
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An electron that has a velocity with x component 2.0 × 106 m/s and y component 3.0 x 106 m/s moves through a uniform magnetic field with x component 0.024 T and y component -0.12 T. (a) Find the magnitude of the magnetic force on the electron. (b) Repeat your calculation for a proton having the same velocity.
Answers
F = q * v * B * sin(theta)
where
- F is the magnetic force
- q is the charge of the particle
- v is the velocity of the particle
- B is the magnetic field
- theta is the angle between the velocity and the magnetic field
(a) For an electron, q = -1.6 x 10^-19 C, v = (2.0 x 10^6) i + (3.0 x 10^6) j m/s, B = (0.024) i - (0.12) j T, and theta = 90 degrees (since the velocity is perpendicular to the magnetic field).
Plugging in the values, we get:
F = (-1.6 x 10^-19) * ((2.0 x 10^6) i + (3.0 x 10^6) j) * ((0.024) i - (0.12) j) * sin(90 degrees)
F = 4.8 x 10^-13 N
Therefore, the magnitude of the magnetic force on the electron is 4.8 x 10^-13 N.
(b) For a proton, q = 1.6 x 10^-19 C (since the proton has a positive charge), and all other values are the same as for the electron.
Plugging in the values, we get:
F = (1.6 x 10^-19) * ((2.0 x 10^6) i + (3.0 x 10^6) j) * ((0.024) i - (0.12) j) * sin(90 degrees)
F = -1.2 x 10^-14 N
Therefore, the magnitude of the magnetic force on the proton is 1.2 x 10^-14 N.
There are two resistors connected in parallel: R1-43 Ohms and R2-43 Ohms.
Determine the equivalent resistance. Round your answer to 2 significant digits only. For example, if the answer is 65.4 Ohms write 65.
Answers
The equivalence resistance rounded off to two significant digits is
22 Ohms.How to find the equivalent resistanceThe equation used to work out the equivalent resistance of two resistors in parallel is as follows:
1/Req = 1/R1 + 1/R2
When R1 and R2 are set at 43 Ohms, we can fill in the placed values like so:
1/Req = 1/43 + 1/43
Simplifying to reduce the equation
1/Req = 2/43
cross multiplying the sides of the equation:
2 x Req = 43
Isolating Req
Req = 43/2
Req = 21.5 Ohms
Req = 22 Ohms to 2 significant figures
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A pool noodle has a density of 145 kg/m3, a length of 1.65 m and a radius of 2.5 cm. How many pool noodles would be needed to make a raft that would support the weight of a person with a mass of 65.0kg?
Answers
The number of pool noodles that would be needed to support the weight is 20.
What is the volume of single pool noodle?
The volume of a single pool noodle is calculated as follows;
V = πr²h
V = π (0.025)² x 1.65
V = 0.00324 m³
The weight of the water displaced is calculated as follows;
W = ρVg
where;
ρ is the density of waterV is the volumeg is gravityW = 1000 x 0.00324 x 9.8
W = 31.75 N
The number of pool noodles needed to support a person is calculated as follows;
= (65 x 9.8 ) / (31.75)
= 20
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A simple circuit contains a battery connected with wires to a small bulb that has a resistance of 150 ohms. If the power dissipated by the bulb is 0.4 W, what is the voltage of the battery?
Remember to identify all data (givens and unknowns), list equations used, show all your work, and include units and the proper number of significant digits to receive full credit.
Answers
Answer: The answer is 7.75v
Explanation; As we know,
power dissipated= (voltage)^2/resistance
0.4w = v^2/150
v^2=0.4w*150ohm
v^2=60
v=7.75v
calculate the distance an object moves if 25J of work is done with 3.0N of force
Answers
The distance an object moves if 25J of work is done with 3.0N of force is 8.33 m.
For a given amount of force, F, and a given distance, d, the formula for calculating work done is as follows:
Work done = Force x distance
So, the distance would be,
Work done / force = 25/3 = 8.33 m.
Work is the energy exerted by an object when it applies a force to move another object over some distance.
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A man is in a helicopter ascending vertically at constant rate of 24.5m/s accidentally drops a toy out the window when the helicopter is 120.0m above the ground. (g = 9.8m / s)
a. How long will it take the toy to reach the ground
b. What will its speed be when it hits the ground?
Answers
It will take the toy 5.02 seconds to reach the ground, The speed at which the toy hits the ground is 49.0 m/s.
Free fall is the motion of an object falling solely under the influence of gravity. In free fall, the object experiences an acceleration of 9.8 m/s^2 downwards towards the ground (assuming no air resistance), regardless of its mass or size.
a. To determine the time it takes for the toy to reach the ground, we can use the formula for the height of an object in free fall:
h = (1/2)gt^2
Where h is the initial height, g is the acceleration due to gravity, and t is time.
At the instant the toy is dropped, its initial height above the ground is h = 120.0 m, and the acceleration due to gravity is g = 9.8 m/s^2. Thus, we can rearrange the formula to solve for time:
t = sqrt(2h/g)
t = sqrt(2(120.0 m)/(9.8 m/s^2)) = 5.02 s
So, it will take the toy approximately 5.02 seconds to reach the ground.
b. To find the speed at which the toy hits the ground, we can use the formula for final velocity in free fall:
v = sqrt(2gh)
Where v is the final velocity, g is the acceleration due to gravity, and h is the initial height. At impact, the initial height of the toy is 0 m. Therefore:
v = sqrt(2gh)
v = sqrt(2(9.8 m/s^2)(120.0 m))
v = 49.0 m/s
So, the speed at which the toy hits the ground is approximately 49.0 m/s.
Hence, The toy will fall to the earth in 5.02 seconds, hitting the ground at a speed of 49.0 m/s.
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A bungee jumper with mass 50.0 kg jumps from a high bridge. After arriving at his lowest point, he oscillates up and down, reaching a low point five more times in 28.0 s. He eventually comes to rest 27.0 m below the level of the bridge. Assume very little damping.
Estimate the spring constant of the bungee cord assuming SHM.
Estimate the unstretched length of the bungee cord assuming SHM.
Express your answer with the appropriate units.
Answers
The unstretched length of the bungee cord is 29.4 m.
Simple harmonic motion is a type of periodic motion in which the displacement of an object from its equilibrium position is directly proportional to the force acting on it and is always directed towards the equilibrium position. It is characterized by a sinusoidal pattern of motion and has many real-world applications, including in oscillations of springs and pendulums.
We can solve this problem by applying the principles of simple harmonic motion (SHM) to the bungee jumper's oscillations.
Let's begin by finding the period of oscillation, T. The time it takes for the bungee jumper to reach the lowest point and return to the same point is one period of oscillation. From the problem, we know that the bungee jumper completes 6 cycles (5 low points plus the initial jump) in 28.0 s. Therefore, the period of oscillation is:
T = 28.0 s / 6 = 4.67 s
Next, we can use the formula for the period of an object undergoing SHM to find the spring constant, k, of the bungee cord:
T = 2π √(m/k)
where m is the mass of the bungee jumper. Rearranging this formula to solve for k, we get:
k = (4π²m) / T²
Substituting the given values, we get:
k = (4π² × 50.0 kg) / (4.67 s)² = 360 N/m
So the spring constant of the bungee cord is approximately 360 N/m.
To find the unstretched length of the bungee cord, we can use the fact that the bungee jumper comes to rest 27.0 m below the level of the bridge. At this point, all of the potential energy from the initial jump has been converted into elastic potential energy stored in the bungee cord. Therefore, the total energy of the system is:
E = mgh = (1/2)kx²
where h is the height from which the bungee jumper initially jumped (we assume that there is no air resistance), and x is the unstretched length of the bungee cord.
Substituting the given values, we get:
(50.0 kg)(9.81 m/s²)(27.0 m) = (1/2)kx²
Solving for x, we get:
x = √[(2mgh)/k] = √[(2 × 50.0 kg × 9.81 m/s² × 27.0 m) / 360 N/m] ≈ 29.4 m
Hence, the unstretched length of the bungee cord is approximately 29.4 m.
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In the figure four particles are fixed along an x axis, separated by distances d = 4.80 cm. The charges are 41 = +4e, q2=-e, 93 = +e, and q4 = +12e, with e = 1.60 × 10-19 C. What is the value of the net electrostatic force on (a) particle 1 and (b) particle 2 due to the other particles?
Answers
(a) Because the particles are all separated by the same distance, the distances for F13 and F14 are the same as for F12.
(b) Because particle 4 is three spacings distant from particle 2, the distance for F24 is 3d.
How to determine net electrostatic force?To calculate the net electrostatic force on a given particle, calculate the electrostatic force due to each of the other particles and then add them vectorially.
(a) The electrostatic force between two particles with charges q₁ and q₂ separated by a distance r is given by Coulomb's law as:
F = (1/4πε₀) × |q₁q₂| / r²
where ε₀ is the electric constant.
Using this formula, calculate the electrostatic force on particle 1 due to particle 2, which is:
F12 = (1/4πε₀) × |q₁q₂| / d² = (1/4πε₀) × 4e × e / (0.048 m)²
Similarly, calculate the electrostatic force on particle 1 due to particle 3 and particle 4:
F13 = (1/4πε₀) × |q₁q₃| / d² = (1/4πε₀) × 4e × e / (0.048 m)²
F14 = (1/4πε₀) × |q₁q₄| / (2d)² = (1/4πε₀) × 4e × 12e / (0.096 m)²
The distances for F13 and F14 are the same as for F12 because the particles are all separated by the same distance.
Add the forces vectorially:
F1net = F12 + F13 + F14
The direction of the net force will depend on the signs of the charges and their relative positions.
(b) To find the net electrostatic force on particle 2 due to the other particles, use the same method.
F21 = F12 (since the force is equal and opposite)
F23 = (1/4πε₀) × |q₂q₃| / d² = (1/4πε₀) × e × e / (0.048 m)²
F24 = (1/4πε₀) × |q₂q₄| / (3d)² = (1/4πε₀) × e × 12e / (0.144 m)²
The distance for F24 is 3d because particle 4 is three spacings away from particle 2.
Add the forces vectorially:
F2net = F21 + F23 + F24
The direction of the net force will depend on the signs of the charges and their relative positions.
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Why do we know so much Earth's Composition?
A.Digging to the inner core
B.Looking at the Earth's Magnetic Field
C.Studying Seismic Waves
Answers
Answer:
C
Explanation:
Since we can't go to the center of Earth, we have to rely on indirect observations of the materials of the interior. The seismic waves are generated by earthquakes and explosions that travel through Earth and across its surface. Thanks to that, it reveals the structure of the interior of the planet. Thousands of earthquakes occur every year, and each one provides a glimpse of the Earth's interior.
The figure shows wire 1 in cross section; the wire is long and straight, carries a current of 4.20 mA out of the page, and is at distance d₁ = 2.58 cm from a surface. Wire 2. which is parallel to wire 1 and also long, is at horizontal distance d-5.05 cm from wire 1 and carries a current of 6.88 mA into the page. What is the x component of the magnetic force per unit length on wire 2 due to wire 1?
Answers
Wire 1 in cross section; the wire is long and straight, carries a current of 4.20 mA out of the page, and is at distance d₁ = 2.58 cm from a surface. Wire 2. which is parallel to wire 1 and also long, is at horizontal distance d-5.05 cm from wire 1 and carries a current of 6.88 mA.
To find the x component of the magnetic force per unit length on wire 2 due to wire 1, we can use the formula for the magnetic force between two parallel current-carrying wires we get
F = μ₀I₁I₂/(2πd)
Where F is the magnetic force per unit length, μ₀ is the magnetic constant (4π x [tex]10^{-7}[/tex]Tm/A), I₁ and I₂ are the currents in the wires, and d is the distance between the wires.
In this problem, we need to find the x component of the magnetic force per unit length on wire 2 due to wire 1. We can break down the problem into components by considering the direction of the magnetic field due to wire 1 at the position of wire 2. The magnetic field due to wire 1 will be perpendicular to both wire 1 and wire 2, and will be directed into the page.
To find the x component of the magnetic force, we need to consider the component of the magnetic force that is perpendicular to wire 2. This component will be directed along the x axis, and will have a magnitude of
[tex]F_{x}[/tex] = Fsinθ
Where θ is the angle between the direction of the magnetic force and the x axis. Since the magnetic force is directed into the page, θ is 90 degrees, and sinθ = 1.
Substituting the values given in the problem, we get
F = (4π x [tex]10^{-7}[/tex]Tm/A)(4.20 x[tex]10^{-3}[/tex] A)(6.88 x [tex]10^{-3}[/tex]A)/(2π*0.0258 m)
F = 3.99 x [tex]10^{-10}[/tex] N/m
Therefore, the x component of the magnetic force per unit length on wire 2 due to wire 1 is
[tex]F_{x}[/tex] = Fsinθ= (3.99 x [tex]10^{-10}[/tex] N/m)(1) = 3.99 x [tex]10^{-10}[/tex] N/m
Hence, the x component of the magnetic force per unit length on wire 2 due to wire 1 is 3.99 x [tex]10^{-10}[/tex] N/m.
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please I need answer
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The coefficient of friction between the two surfaces is tan α.
option B.
What is coefficient of friction?The coefficient of friction between two surfaces that are in contact is the ratio of the force of friction to normal reaction.
Mathematically, the formula for coefficient of friction is given as;
μ = Ff/Fn
where;
Ff is the force of frictionFn is the normal forceFor the given diagram,
Ff = mg sinα
Fn = mg cosα
The coefficient of friction;
μ = mg sinα/mg cosα
μ = sinα/cosα = tan α
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Respond to all of the following in a minimum of 175 words
- Visualization is a powerful tool to have in your motivation toolbox. For this week’s My Vision Board and Reflection Worksheet assignment, you will take time to visualize your goals, not just the outcome, but each step to get there. Do you see a relationship between the process and practice of visualizing and maintaining motivation? Explain how you perceive the relationship or lack of it.
-Self-discipline is taking personal responsibility of your willingness and desire to finish tasks and reach your goals. The readings discussed several ways to increase your level of self-discipline. Which of the strategies discussed this week do you think you will use to increase your level of self-discipline in your life? Share a bit about why you think those strategies will work best for you.
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Visualizing your objectives aids in sustaining inspiration by making your ambitions more perceptible and attainable.
Why is this important?By contemplating the actions required to reach a desired outcome, individuals can foster lucidity and guidance, thereby pleasing them with determination for moving forward. Additionally, focusing on the process of accomplishment through visualization helps divide the steps needed to attain those objectives, thus reducing their complexity, making it less menacing, and rendering them easier to achieve.
Various strategies towards increasing self-discipline were also proposed: setting apparent goals, creating schedules, sidestepping enticement, and practicing mindfulness amongst others.
Personally, I find that determining clear-cut aims and scheduling activities are the most productive tactics to pursue. This approach establishes definite targets and creates an environment that favors concentration whereby dedicating time for working towards set purposes becomes convenient.
This system constructs accountability while instilling discipline as daily progression is made toward target achievements during scheduled times - this encourages further motivation and commitment.
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Note that this prompt has to do with Vision Setting, motivation and Self Discipline.
What is the explanation for the above?
The connection between maintaining motivation and visualization is undeniable. Visualization involves the creation of a mental image that represents your desired outcome, allowing you to keep your eyes on the prize, which helps increase motivation levels.
Note that, breaking down the steps needed to achieve your goals through visualization can make the process less daunting while ensuring consistent progress towards success. Mental checkpoints where achievements are recognized further strengthen one's resolve, thus fueling motivation for even greater accomplishments.
Developing self-discipline is crucial and comes with various techniques for improving it. Optimizing productivity can sometimes be challenging for individuals like myself who struggle with distractions while working.
Fortunately, creating a detailed schedule has always been an effective solution for managing such situations. By factoring-in designated time slots within this timetable per individual tasks, focusing intently can be achieved without succumbing to environmental disturbances experienced in regular work environments.
To additionally promote personal drive during these sessions of focus-creation we should endeavor attainable objectives which will boost our overarching mission amid these intentional work segments.
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if I'm here, and you are not, what's the difference between the space of being here or not?
[tex]tobe \: or \\ nottobe[/tex]
seeing is believing.. joker said to??? on all the days I've been alone.. does anyone see me crying?
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if I'm here, and you are not, then the difference between the space of being here or not is it presence itself. Space is a three-dimensional continuum containing positions and directions.
A three-dimensional continuum that contains locations and directions is called space. Physical space is frequently imagined in three linear dimensions in classical physics. Modern physicists often believe that it eventually becomes a part of spacetime, an unbounded continuum of four dimensions. It is believed that grasping the idea of space is essential to comprehending the physical cosmos. Philosophers dispute on whether it is a thing in and of itself, a connection between entities, or a component of a conceptual framework.
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2) Let the angle 8 be the angle that the vector à makes with the I, the x-direction. Find the angle
for the vectors with the following components:
a) Ax=2.00 m and Ay--1.00 m
b) Ax=2.00 m and Ay= 1.00 m
c) Ax= -2.00 m and Ay 1.00
d) Ax= -2.00 m and Ay-1.00 m
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(a) Ax=2.00 m and Ay--1.00 m, the angle of the vector is 153.4⁰.
(b) Ax=2.00 m and Ay= 1.00 m, the angle of the vector is 26.6⁰.
(c) Ax= -2.00 m and Ay 1.00 m, the angle of the vector is 333.43⁰.
(d) Ax= -2.00 m and Ay = -1.00 m, the angle of the vector is 206.6⁰.
What is the angle of the vectors?The angle of the vectors is known as the direction of the vectors and it is calculated as follows
(a) Ax=2.00 m and Ay--1.00 m, the angle of the vector;
tan θ = Ay/Ax
tan θ = (-1/2)
θ = arc tan (-1/2)
θ = -26.6⁰ = (180 - 26.6⁰) = 153.4⁰ (2nd quadrant).
(b) Ax=2.00 m and Ay= 1.00 m, the angle of the vector;
tan θ = Ay/Ax
tan θ = (1/2)
θ = arc tan (1/2)
θ = 26.6⁰ (1st quadrant).
(c) Ax= -2.00 m and Ay 1.00 m, the angle of the vector;
tan θ = Ay/Ax
tan θ = (-1/2)
θ = arc tan (-1/2)
θ = -26.6⁰ = (360 - 26.6⁰) = 333.43⁰ (4th quadrant).
(d) Ax= -2.00 m and Ay = -1.00 m, the angle of the vector;
tan θ = Ay/Ax
tan θ = (1/2)
θ = arc tan (1/2)
θ = 26.6⁰ = (180 + 26.6⁰) = 206.6⁰ (3rd quadrant).
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Two balloons with charges of 5 nC and -4 nC attract each other with a radius of 2.5 cm. Determine the force between the two balloons.
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Answer:
The force between the two balloons can be calculated using Coulomb's law:
F = k * (q1 * q2) / r^2
Substituting the given values, we get:
F = 9 × 10^9 * (5 × 10^-9 * (-4 × 10^-9)) / (0.025)^2
F ≈ -1.44 × 10^-4 N
The force between the two balloons is approximately -1.44 × 10^-4 N. The negative sign indicates that the force is attractive.
Construct a parallel-plate capacitor where a second line of charges equal in size and opposite in charge are placed below the line of positive charges. Examine what the "E-field" is like between the plates using a sensor.
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A capacitor with two lines of charge on its parallel plates. The bottom plate has an equal line of negative charges that are the opposite in charge to the positive charges on the top plate, while the top plate has a line of positive charges.
As a result, an electric field (E-field) is produced between the plates that can be measured with a sensor.
In a parallel-plate capacitor, the E-field between the plates is uniform and pointed perpendicularly to the plates. It is represented by the equation E = σ/ε, where ε is the permittivity of the medium between the plates and σ is the charge density (charge per unit area) on the plates.
In this instance, the charge density on the top and bottom plates is the same but with opposing signs since the lines of charges on the plates are equal in size and opposite in charge. Assume that the top plate has positive charges and the bottom plate has negative charges, and that the charge density on both plates equals.
A sensor placed between the capacitor's plates will now allow us to measure the E-field, which will reveal that it is constant and perpendicular to the plates. E = σ/ε, where σ, is the charge density and is the permittivity of the medium between the plates, will be the magnitude of the E-field.
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What is the velocity of a sound wave that travels 2500 m in 8.2 s.
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Explanation:
V=lander f. where,
v is the velocity of the sound wave
f is the frequency of sound wave(Hz)
L is the wavelength
so we simply just divide 2500 by 8.2 that gives us 304.88ms-¹
hopefully I get this right!
Can someone help me with my physics sheet? I don’t understand it.. thank you
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Acceleration of the skydiver during the free fall is 4.13 m/s².
1) Mass of the skydiver, m = 83 kg
Weight, W = mg = 83 x 9.8
W = 813.4 N
Free fall acceleration is the acceleration that a body travelling in free fall experiences due to only the gravitational pull of the earth. This is the acceleration brought on by gravity.
Since there is no air resistance, the acceleration of the skydiver during the free fall is the acceleration due to gravity, g.
Freebody diagram is given in Fig.1.
2) Mass of the skydiver, m = 78 kg
Air resistance acting on him, F' = 470 N
mg - 470 = ma
813.4 - 470 = ma
a = 343.4/83
a = 4.13 m/s²
Freebody diagram is given in fig.2.
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A woman lifts a barbell 2.0 m in 5.0 s. If she lifts it the same distance in 10 s, the work done by her is:
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The work done by the woman is independent of the time taken to lift the barbell, as long as the distance lifted remains constant.
The work done by the woman lifting the barbell can be calculated using the formula:
work = force x distance
Assuming the force required to lift the barbell remains constant, the work done is directly proportional to the distance lifted.
Therefore, if the woman lifts the barbell 2.0 m in 5.0 s, the work done is:
work1 = force x distance1 = force x 2.0 m
If she lifts it the same distance in 10 s, the work done is:
work2 = force x distance2 = force x 2.0 m
Since the distance lifted is the same in both cases, the work done by the woman is the same, and can be expressed as:
work1 = work2 = force x 2.0 m
Therefore, the work done by the woman is independent of the time taken to lift the barbell, as long as the distance lifted remains constant.
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Which two options are forms of potential energy?
A. Chemical energy
B. Sound energy
c. Electrical energy
D. Thermal energy
E. Nuclear energy
Answers
A. Chemical energy
E. Nuclear energy
Therefore, options A and E are the correct answers.
An electron is accelerated from rest across the gap of a capacitor (two parallel plates charged -Q and +Q respectively). A hole in the top plate allows the electron to emerge with a constant velocity of v = 27 m/s. If the gap between the plates is d = 0.94 m, what is the magnitude of the electric field between the plates?
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The magnitude of the electric field between the plates is 5.87 × 10^5 N/C.
The electron gains kinetic energy as it is accelerated across the gap of the capacitor. This energy is equal to the work done on the electron by the electric field between the plates of the capacitor. We can use this relationship to determine the magnitude of the electric field.
The kinetic energy gained by the electron can be expressed as:
K = (1/2)mv^2
where K is the kinetic energy, m is the mass of the electron, and v is its velocity. The work done on the electron by the electric field is given by:
W = qEd
where W is the work done, q is the charge of the electron, E is the electric field, and d is the distance between the plates.
Since the electron is negatively charged, it will be accelerated from the negative plate (-Q) to the positive plate (+Q) of the capacitor. The charge on an electron is -1.602 × 10^-19 C. Therefore, the work done on the electron is:
W = qEd = (-1.602 × 10^-19 C)(E)(0.94 m)
The kinetic energy gained by the electron is equal to the work done on it by the electric field, so:
K = W = (1/2)mv^2
Substituting the known values and solving for the electric field gives:
E = (2qK) / (md^2) = (2(-1.602 × 10^-19 C)(0.5m_e(27 m/s)^2)) / ((9.11 × 10^-31 kg)(0.94 m)^2)
where m_e is the mass of the electron.
E = 5.87 × 10^5 N/C
Therefore, the magnitude of the electric field between the plates is approximately 5.87 × 10^5 N/C.
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ܩܩܘܤ ← Interconv problems ... Interconversion problems between kinetic energy and potential energy 1. An object has a mass of 25 kilograms: to. How much is the potential energy if the height is 30 m. b. How much is the kinetic energy at a height of 30 m. If the object is in repose? c. How much is the kinetic energy if the object low at 15 m.? d. How much are the kinetic energy and potential energy when the height is 5 m? and. How much is the kinetic energy and the potential energy of the object just before touch the floor (that is, when the height is 0)? 2. An object has a mass of 56 kilograms: How much is the energy power if the height is 37 m. b. How much is the kinetic energy at a height of 37 m. If the object is in repose? c. How much is the kinetic energy if the object under 25 m. d. How much are the kinetic energy and potential energy when the height is 10 m.? and. How much is the kinetic energy and the potential energy of the object just before touch the floor (that is, when the height is 0)? 3. An object has a mass of 41 kilograms: to. How much is the potential energy if the height is 42 m. b. How much is the kinetic energy at a height of 42 m. If the object is in repose? c. How much is the kinetic energy if the object dropped to 36 m. d. How much are the ki netic energy and potential energy when the height is 18 m.? and. How much is the kinetic energy and the potential energy of the object just before touch the floor (that is, when the height is 0)? 4. An object has a mass of 52 kilograms: to. How much is the potential energy if the height is 38 m. b. How much is the kinetic energy at a height of 38 m. If the object is in repose? c. How much is the kinetic energy if the object dropped to 23 m. d. How much are the kinetic energy and potential energy when the height is 12 m? and. How much is the kinetic energy and the potential energy of the object just before touch the floor (that is, when the height is 0)?
Answers
a. The energy will be 7350 Joules.
b. Due Due to the object remaining at rest, its kinetic energy is zero.
c. The value obtained is v is 17.1 m/s.
d. When the object was initially at rest at 30 m, all of its energy was putative energy which totalled 7350 J.
How to calculate the energyPE = mgh = (25 kg)(9.8 m/s^2)(30 m) = 7350 J
Additionally, PE at 5 m is PE = mgh = (25 kg)(9.8 m/s^2)(5 m) = 1225 J. As enforced by the rule of conservation of energy, PE = KE at any point during the fall. Bearing this in mind, at 5 m KE equals 1225 J.
When the object was initially at rest at 30 m, all of its energy was putative energy which totalled 7350 J.
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