what’s the answer? To solve the law of cosine I don’t understand this math I rly need help.
Answers
The length of u to the nearest centimeter is about 30 cm.
We are given that;'
s = 730 cm, t = 270 cm and U=125°.
Now,
The Law of Cosines states that for any triangle with sides a, b and c and angle C opposite to side c, we have:
c2=a2+b2−2abcosC
To find c = u. Plugging in the values, we get:
u2=7302+2702−2×730×270×cos125°
Using a calculator, we get:
u2≈912.9
Taking the square root of both sides, we get:
u≈30.21
Rounding to the nearest centimeter, we get:
u≈30cm
Therefore, by the law of cosine the answer will be 30 cm.
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Related Questions
Anna took a job that paid $116 the first week. She was guaranteed a raise of 7% each week. How much money will she make in all over 10 weeks? Round the answer to the nearest cent, and number answer only.
Answers
Anna will make $1602.71 in all over 10 weeks.
Here, the first week salary of Anna = $116
i.e., the initial salary a = $116
She was guaranteed a raise of 7% each week.
so, her salary in the next week would be,
116 + 7% of 116
7 percent of 116 is:
116 × 7/100 = 8.12
so, her salary will be $124.12
So, the equation for the salary after 'm' weeks would be,
[tex]n = 116\times (1 + 0.07)^{m - 1}\\\\n = 116\times (1 .07)^{m - 1}[/tex]
Using this equation , the salary in the second week m = 2 would be,
n = 124.12
Salary in the third week m = 3 would be,
n = 116 × [tex](1.07)^{3-1}[/tex]
n = 132.81
Salary in the fourth week m = 4 would be,
n = 116 × [tex](1.07)^{4-1}[/tex]
n = 142.11
Salary in the fifth week m = 5 would be,
n = 116 × [tex](1.07)^{5-1}[/tex]
n = 152.05
Salary in the sixth week m = 6 would be,
n = 116 × (1.07)⁶⁻¹
n = 162.7
Salary in the seventh week m = 7 would be,
n = 116 × (1.07)⁷⁻¹
n = 174.08
Salary in the eighth week m = 8 would be,
n = 116 × (1.07)⁸⁻¹
n = 186.27
Salary in the nineth week m = 9 would be,
n = 116 × (1.07)⁹⁻¹
n = 199.31
And the salary after the tenth week m = 10 would be,
n = 116 × (1.07)¹⁰⁻¹
n = 213.26
The total money after 10 weeks would be,
T = 116 + 124.12 + 132.81+ 142.11 + 152.05 + 162.7 + 174.08 + 186.27 + 199.31 + 213.26
T = $1602.71
This is the required amount.
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Ellen bought a pedometer wristband to track how many steps she takes. Each day she recorded the number of steps in a table. At the end of the week, she found her mean number of steps was 10,000. She made a bar graph to show her daily steps for the week. Which graph could show Ellen’s steps?
THANKS SO MUCH!!!
Answers
Answer:
it is b got it right on my test
Step-by-step explanation:
The required graph that shows Ellen's steps where her mean steps for a week is 10000 is graph 2 where the data are as,
Day 1 = 11000 , Day 2 = 9000, Day 3 = 10000, Day 4 = 12000, Day 5 = 8000, Day 6 ≈ 10000, Day 7 ≈ 10000
Mean of ungrouped data is the average of all the values of the observation in the data set.
Mean = (Summation of all values in data set)/ (Number of observations)
Here there are 7 observations and the mean number of steps is 10000.
For graph 1 the values for each day of the week are as,
Day 1 = 8000 , Day 2 = 9000, Day 3 = 12000, Day 4 = 2000, Day 5 = 6000, Day 6 = 10000, Day 7 = 10000
Thus, the mean number of steps is = (8000+ 9000+ 12000+ 2000+ 6000+ 10000 + 10000) / 7
= 8143 (approximately) ≠ 10000
For graph 2 the values for each day of the week are as,
Day 1 = 11000 , Day 2 = 9000, Day 3 = 10000, Day 4 = 12000, Day 5 = 8000, Day 6 ≈ 10000, Day 7 ≈ 10000
Thus, the mean number of steps is = (11000+ 9000+ 10000+ 12000+ 8000+ 10000 + 10000) / 7
= 10000
For graph 3 the values for each day of the week are as,
Day 1 = 7000 , Day 2 = 14000, Day 3 = 11500, Day 4 = 10000, Day 5 = 4500, Day 6 = 6000, Day 7 = 11000
Thus, the mean number of steps is = (7000+ 14000+ 11500+ 10000+ 4500+ 6000 + 11000) / 7
= 9143 (approximately) ≠ 10000
For graph 4 the values for each day of the week are as,
Day 1 = 8000 , Day 2 = 9000, Day 3 = 9500, Day 4 = 10000, Day 5 = 9000, Day 6 = 7000, Day 7 = 11000
Thus, the mean number of steps is = (8000+ 9000+ 9500+ 10000+ 9000+ 7000 + 11000) / 7
= 9071 (approximately) ≠ 10000
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use the product to rewrite log16(256b)
Answers
Log₁₆(256b) in terms of the logarithm of b, which is the factor that was multiplied by 256 inside the logarithm is 2 + log₁₆(b)
We can use the product rule of logarithms, which states that the logarithm of a product is equal to the sum of the logarithms of the factors.
Therefore, we can write
log₁₆(256b) = log₁₆(256) + log₁₆(b)
We can simplify log₁₆(256) as follows:
log₁₆(256) = log₁₆(16^2) = 2
Therefore, we have:
log₁₆(256b) = log₁₆(256) + log₁₆(b)
= 2 + log₁₆(b)
So, we have rewritten log₁₆(256b) in terms of the logarithm of b, which is the factor that was multiplied by 256 inside the logarithm.
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If the amount of food available is increased, then the cricket frog population will (increase/decrease/stay the same) over the span of five years.
Answers
The value of the expression 0.738 divided by 8.2 is between which two numbers?
A) 0.06 and 0.08 B) 0.08 and 0.1 C) 0.1 and 0.5 D) 0.7 and 1
Answers
0.738 ≈ 0.7
8.2 ≈ 8.0
Then we can divide 0.7 by 8.0:
0.7 / 8.0 ≈ 0.0875
So the value of the expression is approximately 0.0875. This is between the values in answer choice B, 0.08 and 0.1. Therefore, the answer is B) 0.08 and 0.1.
Answer:
B) 0.08 and 0.1
The answer was 0.09, which is between 0.08 and 0.1
10+x/2 evaluate the expression for givin values of the variable
Answers
The value of the expression when x = 4 is 12.
The value of the expression when x = -8 is 6.
We have,
To evaluate the expression 10 + x/2 for a given value of the variable x, we simply substitute the value of x into the expression and simplify.
For example:
If x = 4:
10 + x/2 = 10 + 4/2
= 10 + 2
= 12
So when x = 4, the value of the expression is 12.
If x = -8:
10 + x/2 = 10 + (-8)/2
= 10 - 4
= 6
So when x = -8, the value of the expression is 6.
Thus,
The value of the expression when x = 4 is 12.
The value of the expression when x = -8 is 6.
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Solve for x, y and z
2x – y + 3z = 10
x + 3y – 2z = 5
3x – 2y + 4z = 12
Answers
The solution to the system of equations is:
x = 3, y = 2, z = 2
To solve for x, y, and z, we can use the elimination method or substitution method. Here, we will use the elimination method.
First, we will eliminate y from the equations by multiplying the first equation by 3 and the second equation by 1, and then adding them:
(3) (2x – y + 3z = 10)
6x – 3y + 9z = 30
(1) (x + 3y – 2z = 5)
x + 3y – 2z = 5
Adding the two equations gives:
7x + 7z = 35
Simplifying, we get
x + z = 5 (Equation 1)
Next, we will eliminate y again by multiplying the second equation by 2 and the third equation by 3, and then adding them:
(2) (x + 3y – 2z = 5)
2x + 6y – 4z = 10
(3) (3x – 2y + 4z = 12)
9x – 6y + 12z = 36
Adding the two equations gives:
11x + 8z = 46
Substituting x + z = 5 from Equation 1 into the above equation, we get:
11(x + z) + 8z = 46
11x + 19z = 46
Solving for z, we get:
z = 2
Substituting z = 2 into x + z = 5 from Equation 1, we get:
x + 2 = 5
x = 3
Finally, substituting x = 3 and z = 2 into any of the original equations, we can solve for y:
2x – y + 3z = 10
2(3) – y + 3(2) = 10
6 – y + 6 = 10
y = 2
Therefore, the solution to the system of equations is:
x = 3
y = 2
z = 2
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Oliver did the high jump three times. His scores were 7.016 feet, 5.42 feet, and 8.308 feet. How many feet did he jump in total? pleas help im in test
Answers
The total height of the three jumps is A = 20.744 feet
Given data ,
1st high jump score: 7.016 feet
2nd high jump score: 5.42 feet
3rd high jump score: 8.308 feet
On adding the scores , we get
7.016 + 5.42 + 8.308 = 20.744 feet
On simplifying the equation , we get
A = 20.744 feet
Hence , Oliver jumped a total of 20.744 feet in the three high jumps
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The two tables show the number of copies of album x y and z sold in outlets A , B C and D of w company.
Which outlet sold the greatest amount of copies of album x in July and august
Answers
Outlet A: 80 + 90 = 170
Outlet B: 60 + 70 = 130
Outlet C: 70 + 80 = 150
Outlet D: 90 + 80 = 170
Outlets A and D both sold the greatest amount of copies of album X in July and August, with 170 copies sold each. Therefore, the answer is either A or D.
What transformation were used
Answers
Since ΔJKL was transformed to create ΔMNO, the sequence of transformations that were used include the following:
Reflection over the y-axis.
(x, y) → (x, y - 9).
What is a reflection over the y-axis?In Geometry, a reflection over or across the y-axis or line x = 0 is represented and modeled by this transformation rule (x, y) → (-x, y).
By applying a reflection over the y-axis to the coordinate of the given triangle JKL, we have the following coordinates:
Coordinate J = (3, 7) → Coordinate J' = (-(3), 7) = (-3, 7).
Next, we would apply a vertical translation by shifting triangle J'K'L' down by 9 units to produce ΔMNO;
(x, y) → (x, y - 9).
J' (-3, 7) → (-3, 7 - 9) = M' (-3, -2).
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The sum of four consecutive integers is 250. What is the greatest of these integers?
Answers
The greatest of the given integers is 64.
Given that, the sum of four consecutive integers is 250. We need to find what is the greatest of these integers.
Let the consecutive integers be = x, x+1, x+2, x+3
Therefore,
x + x+1 + x+2 + x+3 = 250
4x + 6 = 250
2x + 3 = 125
2x = 122
x = 61
Therefore, the greatest integer = 61 + 3 = 64
Hence, the greatest of the given integers is 64.
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 1.What did Ruskin write about Nocturne in Black and Gold: Falling Rocket?
2. How did Whistler defend his work in court? ( You need to mention the two paintings he brought with him to court.)
3. What was the outcome of the trial?
4. Why do you think the lawsuit was important in the history of art?
Answers
2. Whistler defended his work by claiming that he was not trying to depict a specific subject, but rather the mood and atmosphere of a fireworks display. He also brought two other paintings to court, Nocturne in Blue and Silver: Chelsea and Nocturne in Blue and Gold: Old Battersea Bridge, to demonstrate that his style was consistent across multiple works.
3. The trial ended in Whistler's favor, with the jury ruling that Ruskin's criticisms had not damaged Whistler's reputation or his ability to sell his paintings.
4. The lawsuit was important in the history of art because it raised questions about the nature of art and the role of the artist. Whistler's defense of his work as an expression of mood and atmosphere, rather than a realistic depiction of a specific subject, challenged traditional notions of art and paved the way for new artistic movements such as Impressionism. The trial also highlighted the importance of critical reviews in shaping public perception of art, and the potential for artists to use the legal system to protect their reputations and livelihoods.
How do I do my calculations?
Answers
The area of the shaded region for the normal distribution is approximately 0.6985.
We have,
To find the area of the shaded region under the standard normal distribution curve between z = -0.87 and z = 1.24, we can use a standard normal distribution table or a calculator with a standard normal distribution function.
Using a standard normal distribution table, we look up the area to the left of z = -0.87 and the area to the left of z = 1.24 and then subtract the smaller area from the larger area to find the area between z = -0.87 and z = 1.24.
The table value for z = -0.87 is 0.1949, and the table value for z = 1.24 is 0.8934.
The area between z = -0.87 and z = 1.24 is:
= 0.8934 - 0.1949
= 0.6985
So the area of the shaded region is approximately 0.6985.
Thus,
The area of the shaded region for the normal distribution is approximately 0.6985.
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The parallel dotplots below display the number of absences for students in each of two classes.
2 dotplots titled class absences. The number lines go from 0 to 10 and are labeled number of absences. Class D, 0, 7; 1, 11; 2, 4; 3, 3. Class C, 0, 8; 1, 10, 2, 4; 3, 1; 5, 1; 10, 1.
Which of the following statements is true?
The range for the distribution of the number of absences is larger for class D.
The range for the distribution of the number of absences is larger for class C.
The IQR for the distribution of the number of absences is larger for class D.
The IQR for the distribution of the number of absences is larger for class C.
Answers
+-------+---+---+---+---+--+--+--+
| Class D | + |
+-------+---+---+---+---+--+--+--+
| Class C | + |
+-------+---+---+---+---+--+--+--+
0 1 2 3 4 5 6 7 8 9 10
- The range is the difference between the highest and lowest observations in each class.
Range for Class D: 11 - 0 = 11
Range for Class C: 10 - 0 = 10
Therefore, the statement "The range for the distribution of the number of absences is larger for class D" is true.
- The IQR is the difference between the third quartile (Q3) and the first quartile (Q1).
Q1 for Class D is 2 and Q3 for Class D is 7. Therefore, IQR for Class D is 7 - 2 = 5.
Q1 for Class C is 1 and Q3 for Class C is 8. Therefore, IQR for Class C is 8 - 1 = 7.
Therefore, the statement "The IQR for the distribution of the number of absences is larger for class C" is true.
The range, difference of maximum and minimum values, is larger for Class C with a range of 10 compared to Class D with a range of 3. The data provided is not sufficient to calculate the IQR (Interquartile Range) for either class.
Explanation:To begin, let's understand what the terms 'range' and 'IQR' (Interquartile Range) refer to in statistics. The range is simply the difference between the largest and smallest data values. The IQR is the range of the middle 50% of the values when ordered from lowest to highest.
For Class D, the lowest absence number is 0 and the highest is 3, thus the range is 3-0 = 3. For Class C, the lowest absence number is 0 and the highest is 10, so the range is 10-0 = 10. Thus, the range for the distribution of absences is larger for Class C.
Calculating IQR requires determining the 1st Quartile (Q1) and 3rd Quartile (Q3) values and subtracting Q1 from Q3. The data given doesn't include enough information to directly calculate these values and hence, it is impossible to definitively say which class has a larger IQR based on the provided information.
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Help. I need game credits for GMM
Answers
The difference of p and z times the sum of p and z is p² - 2pz - z².
How to represent expression?An algebraic expression in mathematics is an expression which is made up of variables and constants, along with algebraic operations such as addition, subtraction, division and multiplication.
Hence, the difference of p and z times the sum of p and z can be represented as follows:
Therefore,
(p - z) × (p + z) = (p - z) (p + z)
(p - z) (p + z) = p² - pz - pz - z²
p² - pz - pz - z² = p² - 2pz - z²
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32 T W Proving Triangle Congruent; determine if AAS, SAS, SSS, HL, ASA
Answers
10: HL
11: AAS
12: SSS
13: SSS
14: HL
15: AAS
16: AAS
17: HL
18: AAS
19: SAS
20 AAS
1: SAS
2: ASA
3: HL
4: HL
5: ASA
6: ASA
7: HL
8: SSS
9: HL
If a > O and y > 0, which expression is equivalent to v 768219 g372
• A.
162°y18 32g
• B.
-O c. 1604 ° V324,
O D.
8ay18 /12ry
Answers
The expression 16x⁹y¹⁸√3xy is equivalent to √769x¹⁹y³⁷
If a > O and y > 0, which expression is equivalent to √769x¹⁹y³⁷
Factor and rewrite the radicand in exponential form:
√16²×3x¹⁸×xy³⁶×y
Simplify the radical expression:
16x⁹y¹⁸ √2²×3xy
Factor and rewrite the radicand in exponential form:
8x⁹y¹⁸√2²×3xy
8x⁹y¹⁸.2√3xy
Multiply the monomials:
16x⁹y¹⁸√3xy
Hence, the expression 16x⁹y¹⁸√3xy is equivalent to √769x¹⁹y³⁷
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In △ABC, AB=6 cm, AC=15 cm, and m∠A=48°.
What is the area of △ABC?
Enter your answer as a decimal in the box. Round only your final answer to the nearest hundredth.
Answers
The area of triangle ABC is : 33.44 cm²
What is the Area of a Triangle?The area of a triangle is the region enclosed within the sides of the triangle. The area of a triangle varies from one triangle to another depending on the length of the sides and the internal angles. The area of a triangle is expressed in square units, like, m2, cm2, in2, and so on.
We have the information from the question is:
In triangle ABC :
AB=6 cm,
AC=15 cm, and
m ∠A=48°.
We have to find the area of Triangle ABC
Area of triangle is : 1/2 × bc × (SinA)
Area of Triangle = 1/2 × 6 × 15 × (Sin 48° )
We know the value of Sin 48° is 0.7431
Area of Triangle = (1/2) × 66.88
Area of triangle = 33.44 cm²
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Olympic size swimming pools are 50 meters long and 25 meters wide with a minimum depth of 2 meters. If the swimming pool is a rectangular prism and water weighs 1000 kilograms per cubic meter, what is the weight of the water in the smallest possible full Olympic size pool in kilograms?
Answers
Answer:
660,430 gallons AKA 2499.9995045071 kilograms
you would proably round it to 2500 kilograms
Step-by-step explanation:
looked it up, had the same measurements as you gave
at+a+fair+Daniel+and+Claire+went+on+a+ride+that+has+two+separate+circular+tracks.+Daniel+rode+in+a+purple+car+that+travels+a+total+distance+of+265+feet+around+the+track+.+Ciara+rode+in+a+yellow+car+that+travels+a+total+distance+of+170+feet+around+the+track.+They+drew+drew+a+sketch+of+the+ride.+What+is+the+difference+ofthe+radii+of+the+two+circle+tracks
Answers
Note that the difference in the radii of the two circular tracks is about 13.68 ft
How did we get that?recall that the circumference of a circle is denoted by the expression
C = 2πr
In this case, C = Circumference
and r radius
Since we have two tracks
Let ra = radius of the purple track and
rb = radius of the yello track
So
265 = 2πra
170 = 2πrb
making ra and rb subject of the expression we have
ra = 256/(2π) =40.7436654315 ≈ 40.74
rb = 170 / (2π) = 27.0563403256 ≈ 27.06
Hence, the difference is
40.74 - 27.06 = 13.68ft
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Full Question:
at a fair Daniel and Claire went on a ride that has two separate circular tracks. Daniel rode in a purple car that travels a total distance of 265 feet around the track . Ciara rode in a yellow car that travels a total distance of 170 feet around the track. They drew drew a sketch of the ride. What is the difference ofthe radii of the two circle tracks
$18,389
is invested, part at 10%
and the rest at 8%
. If the interest earned from the amount invested at 10%
exceeds the interest earned from the amount invested at 8%
by $621.02
, how much is invested at each rate? (Round to two decimal places if necessary.)
Answers
x + y = 18389 (equation 1)
0.10x - 0.08y = 621.02 (equation 2)
From equation 1, we can solve for y:
y = 18389 - x
Substituting this into equation 2, we get:
0.10x - 0.08(18389 - x) = 621.02
0.10x - 1471.12 + 0.08x = 621.02
0.18x = 2092.14
x = 11623
Substituting this back into equation 1, we get:
11623 + y = 18389
y = 6766
Therefore, $11623 is invested at 10% and $6766 is invested at 8%.
PLEASE HELP (WILL GIVE BRAINLIEST)
Answers
Answer:
$5.50(2/3)π(6.5^3) = $3,163.45
$5.50(2/3)(3.14)(6.5^3) = $3,161.85
$3,161.85 is the correct answer.
I need help! pls and thank u!
Answers
Evaluating the given function, we can see that the intensity at 35 cm is 0.816
How to find the intensity at 35 cm from the source?The intensity at a distance d in centimeters is given by the function:
I = 100*d⁻²
Here we want to find the intensity at 35 centimeters from the source, then we need to evaluate the function above at d = 35, doing that we will get:
I = 100*35⁻²
I = 100/(35²)
I = 0.816
The intensity at 35 centimeters from the source is 0.816.
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A girl is three years older than her brother. If their combined age is 35 years, how old is each?
Answers
Answer: The brother is 16 and she is 19.
Step-by-step explanation:
35 - 3 = 32
32 / 2 = 16
16 + 3 = 19
In an election, the median number of votes a candidate received in 6 towns was 250. Which statement MUST be true about this election?
OA. The total number of votes the candidate received in the election was 1500.
OB. The candidate received at least 250 votes in half of the 6 towns.
OC. The candidate received exactly 250 votes in at least two of the towns.
O D. The total number of votes received by all the candidates in the election was 1500.
Answers
Answer:
B. The candidate received at least 250 votes in half of the 6 towns.
This is because the median number of votes is the middle value when all the vote counts are put in order. This means that at least three towns gave the candidate more than 250 votes, and at least three towns gave the candidate fewer than 250 votes. So, the candidate received at least 250 votes in half of the 6 towns. The total number of votes the candidate received in the election cannot be determined from this information. Similarly, the number of votes received in individual towns cannot be determined.
The time it takes to preform a task has a continuous uniform distribution between 43 min and 57 min. What is the the probability it takes between 48 and 49.9 min. Round to 4 decimal places. P(48 < X < 49.9) =
Answers
The probability of the task taking between 48 and 49.9 minutes is 0.1357 or 13.57% (rounded to four decimal places).
To calculate this probability, we first need to find the total probability of the entire range between 43 and 57 minutes. This can be found by subtracting the lower bound from the upper bound and dividing by the total range:
P(43 < X < 57) = (57 - 43) / (57 - 43) = 1
Since the probability of the entire range is 1, we can find the probability of any sub-interval by dividing the length of the sub-interval by the length of the total range. Therefore, the probability of the task taking between 48 and 49.9 minutes is:
P(48 < X < 49.9) = (49.9 - 48) / (57 - 43) = 1.9 / 14 = 0.1357 or 13.57%
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I don’t understand how to solve and find the system here. Please help, I need it to be done in three hours.
Answers
The system of equations in the context of this problem is given as follows:
5h + 3c = 340.2h + 6c = 400.The solution is given as follows:
h = 35, c = 55.
How to model the system of equations?The variables used for the system of equations are given as follows:
Variable h: Amount earned with a haircut.Variable c: Amount earned with a color treatment.Considering the Monday's earnings, the equation is given as follows:
5h + 3c = 340.
Considering the Wednesday's earnings, the equation is given as follows:
2h + 6c = 400.
Hence the system is:
5h + 3c = 340.2h + 6c = 400.Simplifying the second equation by 2, we have that:
h + 3c = 200.
Subtracting the first equation by the second, we can obtain the value of h as follows:
4h = 140
h = 140/4
h = 35.
Hence the value of c is given as follows:
c = (200 - 35)/3
c = 55.
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sage team brought 224 cans they brought 3 times cans as asifs team joes team brought 4 times as asifs team how much cans did joes team bring in
Answers
The number of cans brought by Joes team is J = 299 cans
Given data ,
Let the number of cans brought by Joes team be J
Now , sage team brought 224 cans
And , sage team brought 3 times cans as asifs team
And , joes team brought 4 times as asifs team
On simplifying the equation , we get
Asif's team brought 224/3 = 74.67 (rounded to the nearest whole number) cans.
Joe's team brought 74.67 x 4 = 298.68
So , J = 299 cans
Hence , the equation is solved and J = 299 cans
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Find the range of the following: 20, 3, 95, 54, 71, 66
Answers
Answer:
92.
Step-by-step explanation:
To find the range of the set of numbers 20, 3, 95, 54, 71, 66, we first need to find the difference between the largest and smallest numbers in the set.
Largest number = 95
Smallest number = 3
Range = Largest number - Smallest number
Range = 95 - 3
Range = 92
Therefore, the range of the set of numbers 20, 3, 95, 54, 71, 66 is 92.
Answer:92
Step-by-step explanation: highest-lowest
it helps to put the terms in order first
95-3=92
What is the solution to this system?
(1, 0)
(1, 6)
(8, 26)
(8, –22)
x = –2
Answers
Answer:
Step-by-step explanation:The system of equations represented by the given points is:1x + 0y = 1 (equation 1)
1x + 6y = 1 (equation 2)
8x + 26y = 1 (equation 3)
8x - 22y = 1 (equation 4)
We can use the first equation to solve for x in terms of y:1x + 0y = 1
1x = 1
x = 1
Then we can substitute x=1 into equations 2-4 to obtain three equations in terms of y:1(1) + 6y = 1 => 6y = 0 => y = 0
8(1) + 26y = 1 => 26y = -7/8 => y = -7/208
8(1) - 22y = 1 => -22y = -7/8 - 7 => y = 15/44
Therefore, the solution to the system is x = 1 and y = -7/208 or y = 0 or y = 15/44.
However, we are given that x = -2, which contradicts our solution of x = 1. Therefore, there is no solution to the system with the given values.