Using square process method, we can get the values of x to be 12 and 6.
Define square process?The formula a (x + m)2 + n = a (x + m)2 + n is the simplest to remember while learning how to complete the square technique.
The following formulas can be used to compute m and n in this situation: m = b/2a and n = c - (b2/4a).
From the question,
x² - 18x + 72= 0
⇒ x² - 18x = -72
Complete the square by adding the half of the square of the coefficient of x to both sides of the expression as shown:
⇒ x² - 18x + (18/2) ² = -72 + (18/2) ²
⇒ x² - 18x + 9² = -72 + 81
⇒ (x-9) ² = 9
⇒ x-9 = ± 3
So, values of x are:
x = 3 + 9
= 12
x = -3 + 9
= 6
Therefore, the values of x are 12 and 6.
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What is the volume of the prism?
Enter your answer, as a mixed number in simplest form.
________________________________
(reporting wrong/spam answers)
(giving brainliest to the correct answer)
________________________________
The calculated volume of the prism with the dimension 6 1/2 cm by 2 1/2 cm by 2 1/2 cm is 325/8 cm³
Calculating the volume of the prism?To find the volume of a rectangular prism, we need to multiply its length, width, and height.
In this case, the length is 6 1/2 cm, the width is 2 1/2 cm, and the height is also 2 1/2 cm.
First, we need to convert the mixed numbers to improper fractions.
6 1/2 = 13/2
2 1/2 = 5/2
Now, we can multiply the three values together to find the volume:
Volume = length x width x height
Volume = (13/2) x (5/2) x (5/2)
Volume = (13 x 5 x 5) / (2 x 2 x 2)
Volume = 325/8
Therefore, the volume of the rectangular prism is 325/8 cm³
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I will mark you brainiest!
Which of the following pairs of quadrilaterals have diagonals that are congruent?
A) Rhombus and a rectangle
B) A parallelogram and a square
C) a rectangle and a square
D) a life and a trapezoid
The only pair of quadrilaterals that have congruent diagonals is a rectangle and a square, and the answer is C.
What distinguishes a quadrilateral?These attributes are:
There are four of them.There are four of them.360° is the total of all interior angles.There are two diagonals in them.Both regular and irregular quadrilaterals exist. A regular quadrilateral must have four equal sides, four equal angles, and diagonals that cross each other in a bisecting direction.C) A rectangle and a square: A rectangle's diagonals are congruent, and a square's diagonals are also congruent. The solution is C because a square is a particular case of a rectangle in which all sides are congruent.
Hence, a rectangle and a square are the only pair of quadrilaterals with congruent diagonals, and the answer is C.
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Enter your answer and show all the steps that you use to solve this problem in the space provided.
Find the circumference of the circle (use 3.14 for pi). Show your work. Round to the nearest tenth.
The circumference of the circle is 144.44 yards
What is the circumference of the circleThe circumference of a circle is the total distance around the edge of the circle. It's computed using the following formula:
Circumference = 2πr.
where r is the circle's radius and represents the ratio of a circle's circumference to its diameter by a mathematical constant π that roughly equals 3.14159.
We can also use the formula below whenever we have the diameter of the circle given
c = πd
where d is the diameter of the circle (the distance across the circle passing through the center).
From the image given, the circumference of the circle is given as;
c = 2πr
r = 23yd
c = 2 * 3.14 * 23
c = 144.44
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Check here for instructional material to complete this problem.
Evaluate the formula z =
X-μ
0
√n
when μ = 123, n = 26, x= 127, and o=7.
Z= (Round to three decimal places as needed.)
Answer:
Z = 2.91
Step-by-step explanation:
Mean: 123
Sample Size: 26
Standard Deviation: 7
x = 127
z = (x - μ) / (σ / [tex]\sqrt{n}[/tex] )
[tex]z=\frac{127-123}{\frac{7}{\sqrt{26} } } \\z= 2.91[/tex]
**If this is a z-table question, then P (x = 127) = P (z = 2.91) = 0.9982.**
A PVC pipe has an inner diameter of 5 cm and an outer diameter of 6.5 cm. The PVC has a density of 1.38 g/cm³. What is the mass of a pipe that is 30 cm long in grams? Round to the nearest hundredth.
Hence, in answering the stated question, we may say that As a result, the function mass of the 30 cm long PVC pipe is roughly 733.48 grammes, rounded to the nearest tenth.
what is function?Mathematicians investigate numbers and their variants, equations and associated structures, forms and their locations, and prospective locations for these things. The term "function" refers to the relationship between a group of inputs, each with its own output. A function is a connection of inputs and outputs in which each input results in a single, distinct outcome. Each function has its own domain, codomain, or scope. The letter f is commonly used to denote functions (x). An x represents entry. On functions, one-to-one capabilities, so multiple capabilities, in capabilities, and on functions are the four basic types of accessible functions.
The volume of the PVC pipe can be estimated by subtracting the volumes of the outer and inner cylinders:
V = π/4 × (D² - d²) × L
where V denotes volume, is the mathematical constant pi (roughly equivalent to 3.14159), D denotes outer diameter, d denotes inner diameter, and L denotes pipe length.
V = π/4 × (6.5² - 5²) × 30\sV = 531.13 cm³
PVC pipe mass can be estimated by multiplying its volume by its density:
m = V × ρ
With the provided density, we get:
1.38 g/cm3 m = 733.48 g m = 531.13 cm3
As a result, the mass of the 30 cm long PVC pipe is roughly 733.48 grammes, rounded to the nearest tenth.
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The circles have the same center. What is the area of the shaded region?
Answer:
The area of the shaded region is 160.2 in² (to the nearest tenth).
Step-by-step explanation:
The area of the shaded region can be calculated by subtracting the area of the inner circle from the area of the outer circle.
[tex]\boxed{\begin{minipage}{4 cm}\underline{Area of a circle}\\\\$A=\pi r^2 $\\\\where:\\ \phantom{ww}$\bullet$ $r$ is the radius. \\\end{minipage}}[/tex]
If the circles have the same center, and the inner circle has a radius of 7 in, then the outer circle has a radius of:
[tex]\implies r = 7 + 3 = 10\; \sf in[/tex]
Therefore, the area of the shaded region is:
[tex]\begin{aligned}\sf Area_{shaded\;region}&=\sf Area_{outer\;circle}-Area_{inner\;circle}\\&=\pi \cdot 10^2 - \pi \cdot 7^2\\&=100\pi - 49 \pi\\&=51 \pi\\& = 160.221225...\\&=160.2\; \sf in^2\;(nearest\;tenth)\end{aligned}[/tex]
HELP FAST
LORAN is a long range hyperbolic navigation system. Suppose two LORAN transmitters are located at the coordinates and , where unit distance on the coordinate plane is measured in miles A receiver is located somewhere in the first quadrant. The receiver computes that the difference in the distances from the receiver to these transmitters is 180 miles.
What is the standard form of the hyperbola that the receiver sits on if the transmitters behave as foci of the hyperbola?
[tex]$$16[(x_2 - x_1)^2 + (y_2 - y_1)^2]x^2 - 32(x_2 - x_1)x^3 + 16(x_2 - x_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]x + 16[(y_2 - y_1)^2 + (x_2 - x_1)^2]y^2 - 32(y_2 - y_1)y^3 + 16(y_2 - y_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]y + [(x_2 - x_1)^2 + (y_2 - y_1)^2 - 180^2]^2 = 0$$[/tex]
this is the standard form of the hyperbola that the receiver sits on if the transmitters behave as foci of the hyperbola.
What is hyperbola ?
A hyperbola is a type of conic section that has two separate parts, called branches, which are mirror images of each other. It is defined as the set of all points in a plane, such that the difference between the distances from two fixed points, called foci, is a constant. Hyperbolas have many applications in science, engineering, and mathematics.
Given two LORAN transmitters located at the coordinates [tex]$(x_1, y_1)$[/tex] and [tex](x_2, y_2)$[/tex], where unit distance on the coordinate plane is measured in miles.
Let the coordinates of the receiver be [tex](x,y)$.[/tex]
The distance from the receiver to the first transmitter is given by [tex]$\sqrt{(x - x_1)^2 + (y - y_1)^2}$[/tex], and the distance from the receiver to the second transmitter is given by [tex]\sqrt{(x - x_2)^2 + (y - y_2)^2}$.[/tex]
Since the difference in the distances from the receiver to these transmitters is 180 miles, we have:
[tex]$$\sqrt{(x - x_1)^2 + (y - y_1)^2} - \sqrt{(x - x_2)^2 + (y - y_2)^2} = 180$$[/tex]
Squaring both sides, we get:
[tex]$$(x - x_1)^2 + (y - y_1)^2 - 2\sqrt{(x - x_1)^2 + (y - y_1)^2} \sqrt{(x - x_2)^2 + (y - y_2)^2} + (x - x_2)^2 + (y - y_2)^2 = 180^2$$[/tex]
Rearranging, we get:
[tex]$$(x - x_1)^2 + (y - y_1)^2 - (x - x_2)^2 - (y - y_2)^2 = 4\sqrt{(x - x_1)^2 + (y - y_1)^2} \sqrt{(x - x_2)^2 + (y - y_2)^2} - 180^2$$[/tex]
Using the identity $a^2 - b^2 = (a + b)(a - b)$, we can simplify the left-hand side as:
[tex]$$4x(x_2 - x_1) + 4y(y_2 - y_1) = 4\sqrt{(x - x_1)^2 + (y - y_1)^2} \sqrt{(x - x_2)^2 + (y - y_2)^2} - 180^2$$[/tex]
Squaring both sides again and simplifying, we get:
[tex]$$16[(x_2 - x_1)^2 + (y_2 - y_1)^2]x^2 - 32(x_2 - x_1)x^3 + 16(x_2 - x_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]x + 16[(y_2 - y_1)^2 + (x_2 - x_1)^2]y^2 - 32(y_2 - y_1)y^3 + 16(y_2 - y_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]y + [(x_2 - x_1)^2 + (y_2 - y_1)^2 - 180^2]^2 = 0$$[/tex]
this is the standard form of the hyperbola that the receiver sits on if the transmitters behave as foci of the hyperbola.
Therefore, [tex]$$16[(x_2 - x_1)^2 + (y_2 - y_1)^2]x^2 - 32(x_2 - x_1)x^3 + 16(x_2 - x_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]x + 16[(y_2 - y_1)^2 + (x_2 - x_1)^2]y^2 - 32(y_2 - y_1)y^3 + 16(y_2 - y_1)[(y_2 - y_1)^2 + (x_2 - x_1)^2 - 180^2]y + [(x_2 - x_1)^2 + (y_2 - y_1)^2 - 180^2]^2 = 0$$[/tex]
this is the standard form of the hyperbola that the receiver sits on if the transmitters behave as foci of the hyperbola.
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UCF students pay an average of 1,245 dollars for books. The standard deviation of costs of books is sigma = 102 dollars. Select 36 UCF students at random. Find the probability that the sample mean cost of books of 36 students exceeds 1,245+ (1.96)(102)/6.
I need help solving this!
After answering the provided question, we can conclude that As a result, expression the likelihood that the sample mean book cost of 36 UCF students exceeds $1,278.6 is approximately 0.0427, or 4.27%.
what is expression ?In mathematics, an expression is a collection of symbols, digits, and companies that portray a statistical correlation or formula. An expression can be a single number, a mutable, or a combination of both of them. Addition, subtraction, proliferation, division, and exponentiation are examples of mathematical operators. Expressions are used extensively in mathematics, including arithmetic, calculus, and geometry. They are used in mathematical formula representation, equation solution, and mathematical relationship simplification. \
[tex]P(x > 1278.6) = P(z > (1278.6-1245)/(102/36)) P(z > 1.72) = 0.0427 P(z > 1.72) = 0.0427[/tex]
As a result, the likelihood that the sample mean book cost of 36 UCF students exceeds $1,278.6 is approximately 0.0427, or 4.27%.
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The circumference of a circular garden is approximately 34 feet. What is the approximate area inside the circular garden?
Answer:
Approxiamaltely 91.95 feet
Step-by-step explanation:
i-Ready
Find the surface area of the box shown.
S.A. =
Nets and Surface Area- Instruction-Level F
in.²
3 in
12 in
10 in
X
The surface area of the box shown is 186 square inches (186 in²).
What is surface area?Surface area is the measure of the area on a two-dimensional surface. It is the sum of the areas of all the shapes that make up a two-dimensional object. It can be used to calculate the area of a sphere, a cylinder, a rectangular prism, and more.
The box shown is a three-dimensional rectangular prism. The surface area (S.A.) of a rectangular prism is calculated by adding the area of each of its six faces. The area of each face is calculated by multiplying the length of the face by its width.
For the box shown, the length is 3 inches (3 in), the width is 12 inches (12 in), and the height is 10 inches (10 in). To find the surface area, we need to calculate the area of each face and add them together. The surface area of this box is calculated as follows:
Front and back faces: 3 in x 10 in = 30 in²
Left and right faces: 12 in x 10 in = 120 in²
Top and bottom faces: 3 in x 12 in = 36 in²
Total surface area: 30 in² + 120 in² + 36 in² = 186 in²
Therefore, the surface area of the box shown is 186 square inches (186 in²).
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Yuri has a large rectangular card measuring 1.2 meters by 0.8 meters, he wants to cut it up to make small rectangular cards each measuring 13 centimeters by 11.5 centimeters. Work out the largest number of cards that he can make
The number of smaller card that could be cut from the larger rectangular card is 64.
How to find the area of a rectangle?Yuri has a large rectangular card measuring 1.2 meters by 0.8 meters, he wants to cut it up to make small rectangular cards each measuring 13 cm by 11.5 cm.
Let's convert the units.
1.2 m = 120 cm
0.8 = 80 cm
Therefore, let's find the area of the rectangular card.
area of the large rectangular card = lw
where
l = lengthw = widtharea of the large rectangular card = 120 × 80
area of the large rectangular card = 9600 cm²
area of each small rectangular card = 11.5 × 13.5
area of each small rectangular card = 149.5 cm²
Therefore,
largest number of card that can be cut out from the larger card = 9600 / 149.5 = 64.2140468227
largest number of card that can be cut out from the larger card ≈ 64
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Which two pairs of measurements are equal?
Answer:
cm³ and ml
m³ and litre
This is the all you will need to know
Evaluate each expression for the given values.
4 |m - n|
If m = -7 and n=2
The expression will give 36 after evaluating.
What is an Expression?
In mathematics, an expression is a combination of numbers, variables, and mathematical operations that can be evaluated or simplified. An expression may contain one or more terms, which are separated by operators such as addition (+), subtraction (-), multiplication (*), division (/), and exponentiation (^).
Expressions can represent various mathematical concepts, such as equations, inequalities, functions, and polynomials.
Given: m = -7 and n = 2,
We know that, the mode function converts the function into positive value.
So, |m - n| = |-7 - 2| = 9
Now,
4 |m - n| = 4 * 9 = 36
So the expression 4 |m - n| evaluates to 36 when m = -7 and n = 2.
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if 6 people share four sandwich so each person gets the same amount how much will each person get
Answer:
4/6 = 23
Step-by-step explanation:
pls someone help asap
Answer:
2x+15
Step-by-step explanation:
Answer:
2x + 15
Step-by-step explanation:
First, we are doubling x.
We know that doubling is the same thing as multiplying by 2:
2x
Next, we are adding fifteen:
2x + 15
5 Lanco got 52% on his science test - What fraction of the test did be get correct what fraction did he get incorrect
Answer: 13/25
Step-by-step explanation:
A car travels at a constant speed of 60 miles per hour. The distance the car travels in miles is a function of time t , in hours, given by d ( t ) = 60 t . Find the inverse function by expressing the time of travel in terms of the distance traveled. Call this function t ( d ) . t ( d ) = Find t ( 160 ) . Round to 1 decimal place. t ( 160 ) =
If the car travels 160 miles, it will take approximately 2.7 hours to cover that distance.
An inverse function is a function that "undoes" the effect of another function. More specifically, if we have a function f(x), its inverse function g(x) will undo the effect of f(x), such that if we apply f(x) and then g(x) to an input x, we get back the original input.
To find the inverse function of d(t) = 60t, we need to solve for t in terms of d. We start by setting d equal to the original function and solving for t:
d = 60t
Dividing both sides by 60, we get:
t = d/60
So the inverse function is t(d) = d/60.
To find t(160), we substitute 160 for d in the equation t(d) = d/60:
t(160) = 160/60
t(160) = 2.67 (rounded to 1 decimal place)
Therefore, if the car travels 160 miles, it will take approximately 2.7 hours to cover that distance.
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-5 x = - 10
what is the answer?
Answer:
=2
Step-by-step explanation:
You divide by five on each side of the = and then after that you should have X equals two!
using figure 1.25, estimate the average rate of change of the number of farm²⁶ in the US between 1950 and 1970.
The average rate of change of the number of farm²⁶ in the US between 1950 and 1970 would be = 8.3 farms/year
How to calculate the average rate of change?From the given graph above which shows the relationship between the number of farms and years. The line drawn from the origin shows an irregular relationship between the two variables.
The number of years between 1950 and 1970 = 20 years.
The number of farms that existed for those 20 years =5.2- 2.8 = 2.4 years
Therefore the average rate of change = 20/2.4 = 8.3 farms/year.
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Find the length of AB.
Answer:
The answer is 25
Students at Shoreham school held a bake sale to raise money to buy books they earned $90 if five classes share the money equally, how much will each class get?
Answer:
$18 were given to each class
Step-by-step explanation:
90÷5=18
9x -6y = 54 find x intercept and find y intercept
Answer:
x-intercept(s):
(
6
,
0
)
y-intercept(s):
(
0
,
−
9
)
Step-by-step explanation:
14. A circular piece of paper of radius 20 cm is cut in half
and each half is made into a hollow cone by joining
the straight edges. Find the slant height and base
radius of each cone.
Answer:
10 cm
Step-by-step explanation:
Given:
A circular piece of paper of a radius of 20 cm is cut in half and each half is made into a hollow cone by joining the straight edges.
To find:
Find the slant height and base radius of each cone.
Solution:
The radius of the circular piece of paper = 20 cm
Finding the slant height of each cone:
Since the straight edges of the semi-circular part is joined together to form a cone
∴ Slant height of the cone so formed = Radius of the circular piece = 20 cm
Thus, the slant height of the cone is → 20 cm.
Finding the base radius of each cone:
Let "r" cm be the base radius of each cone.
We have,
[Length of the base of each cone] = [Length of each semi-circular part of the original circular piece of paper]
⇒
2
�
�
=
2
�
×
�
�
�
�
�
�
�
�
�
�
�
�
�
�
�
�
�
�
�
�
�
�
2
2πr=
2
2π × radius of original circle
⇒
2
�
=
2
×
20
2
2r=
2
2×20
⇒
2
�
=
20
2r=20
⇒
�
=
10
�
�
r=10cm
Thus, the base radius of each cone is → 10 cm.
Please Help! This composite figure is created by placing a sector of a circle on a triangle. What is the area of this composite figure? Use 3.14 for . Round to the nearest hundredth. Show your work
The area of the composite figure is the sum of the area of the sector and the triangle . Therefore, the area of the composite figure is 95.52 cm².
How to find the area of the composite figure?This composite figure is created by placing a sector of a circle on a triangle. The area of the composite figure can be found as follows:
The composite figure is a combination of a sector and a right triangle. Therefore, the area of the composite figure is the sum of the area of the sector and the area of the right triangle.
area of the composite figure = area of the triangle + area of the sector
Hence,
area of the composite figure = 1 / 2 bh + ∅ / 360 × πr²
area of the composite figure = 1 / 2 × 6 × 8 + 82 / 360 × 3.14 × 10²
area of the composite figure = 48 / 2 + 25748 / 360
area of the composite figure = 24 + 71.5222222222
area of the composite figure = 95.5222222222
Therefore,
area of the composite figure = 95.52 cm²
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I’m not sure what angles they are I’m stuck help please
Answer:
Answer would be triangle CAB
NO LINKS!!!! URGENT HELP PLEASE!!!
Please help me with this Special Right Triangle: 45-45-90
Answer:
x = 13.44 (2 d.p.)
y = 13.44 (2 d.p.)
Step-by-step explanation:
The interior angles of a triangle sum to 180°. Therefore, the missing angle of the given triangle is 45°. This means the triangle is a 45-45-90 triangle.
What is a 45-45-90 triangle?A 45-45-90 triangle is a special right triangle in that the measures of its sides are in the proportion x : x : x√2 where:
x are the sides opposite the 45 degree angles (legs).x√2 is the side opposite the right angle (hypotenuse).As the given triangle is a 45-45-90 triangle, sides x and y are the same length.
As the hypotenuse (side opposite the right angle) is 19 units in length, then x√2 = 19. To find the length of x (and y), solve for x:
[tex]\implies x\sqrt{2} = 19[/tex]
[tex]\implies \dfrac{x\sqrt{2}}{\sqrt{2}} = \dfrac{19}{\sqrt{2}}[/tex]
[tex]\implies x= \dfrac{19\sqrt{2}}{2}[/tex]
[tex]\implies x=13.44\; \sf units\;(2\;d.p.)[/tex]
Solutionx = 13.44 (2 d.p.)y = 13.44 (2 d.p.)3. A cannonball is fired into the air with an initial vertical velocity of 128 feet per second. The release point is 6 feet above the ground. The function h =-16t2+128t+6 represents the height h (in feet) of the cannonball after t seconds.
a find the height of the cannonball each second after it is fired
b use the graph of the model to determine how long the cannonball is in the air
a) After one second in the air, the cannonball's height is:
[tex]h = -16(1)^2 + 128(1) + 6 = 118 feet[/tex]
b) 8 seconds pass while the cannonball is in the air (from when it is fired until it hits the ground).
what is velocity?The pace at which an object's position changes in relation to a frame of reference and time is what is meant by velocity. Although it may appear sophisticated, velocity is just the act of moving quickly in one direction. Since it is a vector quantity, the definition of velocity requires both magnitude (speed) and direction. Its SI equivalent is the meter per second (ms-1). A body is considered to be accelerating if its velocity changes, either in magnitude or direction.
from the question:
a) We can enter values of t into the equation[tex]h = -16t^2 + 128t + 6[/tex] and evaluate to obtain the height of the cannonball each second after it is shot.
The height of the cannonball at time t = 0 is as follows:
[tex]h = -16(0)^2 + 128(0) + 6 = 6 feet[/tex]
When t = 1, the cannonball has been in the air for 1 second, so its height is:
[tex]h = -16(1)^2 + 128(1) + 6 = 118 feet[/tex]
b) The graph of the function [tex]h = -16t^2 + 128t + 6[/tex] can be used to calculate how long the projectile has been in the air. When the cannonball is six feet above the ground, it is said to be in the air. The values of t must be determined when h is larger than or equal to 6.
Finding the values of t where the graph crosses the line y = 6 is one technique to do this. Another is to graph the function. Another method is to solve for t while setting h = 6:
[tex]-16t^2 + 128t + 6 = 6[/tex]
[tex]-16t^2 + 128t = 0[/tex]
-16t(t - 8) = 0
t = 0 or t = 8
Hence, the cannonball flies for 8 seconds (from when it is fired until it hits the ground).
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A pair of dice is rolled, and the number that appears uppermost on each die is observed. Refer to this experiment and find the probability of the given event. (Enter your answer as a fraction.)
The sum of the numbers is an odd number.
The probability that the sum of the numbers when two dice are rolled is an odd number is given as follows:
0.5.
How to calculate a probability?A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.
Each dice has six possible outcomes, hence the total number of outcomes when two dice are rolled is given as follows:
6² = 36.
When we look at the pattern of the sum of two dice, from (1,1), (1,2), ..., to (6,6) we see that they alternate between even numbers and odd numbers, hence:
18 of the outcomes have an even sum.18 of the outcomes have an odd sum.Hence the probability is given as follows:
p = 18/36 = 0.5.
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70 divided by 33.8 plsss I have to do my hw
Answer:
Step-by-step explanation:
70/33.8=2.07100592
In triangle SRK below, medians SC, KE and RL at M.
Which statement must always be true?
The statement that must always be true fοr the median οf the triangle is RM = KM.
Why is this statement always be true?The statement that must always be true fοr the centrοid οf the triangle is RM = KM. Since, RM and KM are bοth part οf the median that cοnnect at the centrοid and are divided intο 2 halves.
A median in a triangle is a line segment that jοins οne οf the triangle's vertices tο the midway οf the οther side. There are three medians in every triangle, and they all cοme tοgether at the centrοid. The segment frοm the vertex tο the centrοid is twice as lοng as the segment frοm the centrοid tο the midpοint οf the οppοsing side.
The centrοid is the centre οf mass οf the triangle and splits each median intο twο segments. A median divides a triangle intο six smaller triangles οf equal size, passing thrοugh the centrοid οf each οf these smaller triangles, amοng οther nοtewοrthy qualities.
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