**Answer:**

gas moves around the most so it would have the most kinetic energy and solids would have the least as they only vibrate a tiny bit(not visible to the naked eye)

23 and 24 only please help!

**Answer:**

23: Acceleration 24:1m/s^2

**Explanation:**

[tex]a = (v_f - v_i) /delta(t)\\a=(16-10)/6\\a=6/6\\a=1m/s^2[/tex]

An external force of 25 N acts on a system for 10 s. What is the impulse delivered to the system?

**Answer:**

I = 250N*s

**Explanation:**

I = F*t

I = impulse or momentum

F = Force

t = time

I = 25N*10s

I = 250N*s

The distance between adjacent nodes in a standing wave pattern is 25.0 cm. What is the

wavelength? If the frequency is 200. Hz, what is the speed of the wave?

**Answer:**

Answer:

Speed of the wave in the string will be 3.2 m/sec

Explanation:

We have given frequency in the string fixed at both ends is 80 Hz

Distance between adjacent antipodes is 20 cm

We know that distance between two adjacent anti nodes is equal to half of the wavelength

So \frac{\lambda }{2}=20cm

2

λ

=20cm

\lambda =40cmλ=40cm

We have to find the speed of the wave in the string

Speed is equal to v=\lambda f=0.04\times 80=3.2m/secv=λf=0.04×80=3.2m/sec

So speed of the wave in the string will be 3.2 m/sec

What is the surface temperature of Sirius B in Kelvins?

Answer: The surface temperature of Sirius B is 25,200 Kelvins(K).

Explanation: You would think Sirius would have a surface temperature of 9,940 Fahrenheit. That is somewhat correct, but Sirius is a binary star consisting of a main-sequence star of spectral type A0 or A1, termed Sirius A, and a faint white dwarf companion of spectral type DA2, termed Sirius B. Sirius, Sirius A, and Sirius B, are all different stars. Sirius A has a temperature of 9,940 Kelvins, but Sirius B has a temperature of 25,200 Kelvins(K).

That would be 9,940 kelvins (K)

Hope it helps! :D

A bicycle accelerates from rest to 6m/s in a distance of 50m, calculate the acceleration

50x6=300 this is the answer I think

The **acceleration **of the bicycle is 0.12 m/[tex]s^{2}[/tex].

We know that acceleration is the change in velocity divided by the change in time. In this case, the **bicycle** is accelerating from rest to a velocity of 6 m/s. The change in time is the time it takes the bicycle to travel 50 m.

We can use the following **equation **to find the acceleration:

a = (v2 - v1) / t

where:

a is the acceleration

v2 is the **final velocity** (6 m/s)

v1 is the **initial velocity** (0 m/s)

t is the time

Plugging in the values from the problem, we get:

a = (6 m/s - 0 m/s) / 50 s

= 0.12 m/[tex]s^{2}[/tex].

Therefore, the acceleration of the bicycle is 0.12 m/[tex]s^{2}[/tex].

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astronomers have determined the surface temperature of stars by studying their colors. what color emission represents stars with the hottest temperatures?

**Answer:**

Blue

**Explanation:**

Did the question already

An open train car rolls along a track while it is being filled with sand. There is negligible friction. As a result of

the accumulating sand, what happens to the speed of the train car? (Assume negligible friction and the cart is

just rolling along, not receiving any additional force to regulate its speed.)

**Answer:**

**Explanation:**

An **open** **train **car rolls along a track while it is being filled with sand. There is **negligible friction**. The **speed **of the **train **car will be slowed **down**.

Between two **surfaces **that are sliding or attempting to slide over one another, there is a force called **friction**. For instance, friction makes it challenging to push a book down the floor.

**Friction **always moves an object in a direction that is counter to the direction that it is traveling or **attempting **to move.

**Speed **indicates the rate of movement of something or someone. If you know how far something has **traveled **and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance x time.

Therefore, an **open railway **car is packed with sand and is rolling along a track. Very little **friction **exists. The railway car's speed will be slowed down.

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Calculate the force of gravity of a 25kg block resting on the earth (M=5.97x10^24kg). The radius of the earth is 6.38x10^6m.

I already know...

[tex](6.67*10^{-11})(25)(5.97*10^{24} )/(6.38*10^6)^2[/tex]

But I don't understand what steps I have to take to solve that equation

From **Newton's law of gravity**, the force of gravity is **245 Newtons**

To calculate the force of gravity of a 25kg block resting on the earth of mass M = 5.97x10^24kg with the radius r of the earth is 6.38x10^6m, let us first list out all the given parameters

Mass m = 25 kg

Mass of the earth M = 5.97x10^24kg

Radius r = 6.38x10^6m

Force F = ?

The formula to calculate the force of gravity is

**F = (GMm)/**[tex]r^{2}[/tex]

Where G = 6.67 x [tex]10^{-11}[/tex]

Substitute all the parameters

F = (6.67 x [tex]10^{-11}[/tex] x 5.97x10^24 x 25) / (6.38x10^6)^2

F = 9.9 x [tex]10^{15}[/tex] / 4.07 x [tex]10^{13}[/tex]

F = 244.56 N

F = 245 Newtons (approximately)

Therefore, the force of gravity is **245 Newtons**

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Explain briefly about viscous force

The **viscous force** refers to the **resistance **of a **fluid **to **flow**. It is **measured **in Newton-second per square meter.

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The solar mass of the Sun is 1. The orbital period of Jupiter is 11. 9 Earth years. What is the distance between Jupiter and the Sun? 5. 2 AU 41 AU 52 AU 410 AU.

The **distance **between **Jupiter **and the **sun **is **5.2 AU.**

According to** Kepler's third law**, the square of the **period **of revolution of planets is proportional to the cube of their **mean distances** from the sun. From this; **T^2 = r^3.**

Now, we are told that the orbital period (T) is **11. 9 Earth years**. We have to make the distance the subject of the formula.

r =T^2/3

r = (11.9)^2/3

r =** 5.2 AU**

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**Answer:**

The answer is A. 5.2 AU

**Explanation:**

in jus dat ni ni fr

Iron, Nickel, Copper, Zinc... These are all what kind of metals?

**Answer:**

there very old

**Explanation:**

Which car will experience a greater KE, a car traveling at 16 m/s or a half as massive car traveling at 32 m/s

**Answer:**

The car that is hald as massive

**Explanation:**

We can use the eqation for kinetic energy to solve this problem

KE = 1/2mv^2 (where m is mass and v is velocity/speed)

Lets give the original car a mass of 100kg and use the equation

KE = 1/2(100kg)(16m/s)^2 = 12800J

and now lets find kinetic energy of the half as massive car

KE2 = 1/2(50kg)(32m/s)^2 = 25600J

From this, we find that the hald as massive car will experience a greater kinetic energy while travling at double the velocity

1) A blinking light of constant period is situated on a lab cart. Which diagram best represents a photograph of

the light as the cart moves with constant velocity?

How do I solve this?

**Option C** with **uniform displacement** at each **time **interval represents the **photograph **of **light **as the cart moves with **constant velocity.**

At** constant velocity**, the change in **displacement **with **time **is uniform. The displacement of the given object in motion increases at equal rate.

At **constant velocity**, the initial velocity is equal to the final velocity.

v₁ = v₂

The **acceleration **of the object at constant velocity is **zero**, because the change in velocity with time will be zero.

[tex]a = \frac{\Delta v}{\Delta t} \\\\a = \frac{v_2- v_1}{t} \\\\v_2 = v_1\\\\a = \frac{v_1 - v_1}{t} \\\\a = 0[/tex]

Thus, from the given options we can conclude that **option C** with **uniform displacement** at each **time **interval represents the **photograph **of **light **as the cart moves with **constant velocity.**

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An object of length 3.00 cm is inside a plastic block with index of refraction 1.40. If the object is viewed from directly above, what is the length of its image?

The **length **of its image = [tex]-3cm[/tex]

Given,

**length **of object, [tex]h_o = 3 cm[/tex]

We know, for flat refracting surface,

Image distance = object distance

So,

**magnification **is = [tex]-1[/tex]

**length **of the image,

[tex]h_i = magnification * h_o\\\\h_i = -1 * 3 \\\\h_i = -3cm[/tex]

Here, **negative **sign means inverted image.

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what is the capacitance of capacitor

**Answer:**

The capacitance C of a capacitor is defined as the ratio of the maximum charge Q that can be stored in a capacitor to the applied voltage V across its plates. In other words, capacitance is the largest amount of charge per volt that can be stored on the device: C = Q V . 1 F = 1 C 1 V .

**Explanation:**

A capacitor's capacity to hold an electric charge when a potential difference (voltage) is applied across its plates is measured by the **capacitance** of the device.

It can be calculated using the formula C = Q/V,

where Q is the electric charge stored on the capacitor in **coulombs** (C), C is the capacitance in farads (F), and V is the voltage across the capacitor in volts (V). The **capacitor's physical **properties, such as the area of the plates, the space between them (dielectric separation), and the substance between the plates (dielectric constant), all affect capacitance. A better charge storage capability is indicated by a higher capacitance value.

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pls answer this question is due today

Answers:Speed for section A = **15 km per hour**Speed for section B = **0 km per hour**Speed for section C = **60 km per hour**Speed for section D = **40 km per hour**

=============================================

Explanation:

To compute the speed, we divide the distance traveled over the time duration.

For instance, if a car goes 100 km in 5 hours, then its speed is 100/5 = 20 km per hour.

-----------------

For section A, the car travels 30 km over the course of 2 hours (since 11:00-9:00 = 2:00)

speed = distance/time = (30 km)/(2 hrs) = 15 km/hr

-----------------

We don't need to do any computations for section B. It's a flat horizontal line, so the speed is zero. There's no change in distance, so the car is stationary for this 1 hour period.

You could say speed = distance/time = 0/1 = 0 km/hr if you wanted.

-----------------

For section C, its change in distance is 60-30 = 30 km and the change in time is 0.5 hour (because it spans from 12:00 to 12:30)

So, speed = distance/time = (30 km)/(0.5 hr) = 60 km/hr

The steeper slope of section C, compared to section A, means the car is going faster.

-----------------

Section D spans from 12:30 to 14:00. This is a time period of 14:00-12:30 = 1:30 = 1.5 hours. The change in distance is 60 km

(60 km)/(1.5 hrs) = 40 km/hr

The speed of the car during section D is 40 km per hour.

Side note: if you were talking about velocities instead of speeds, then section D would have a negative velocity of -40 km/hr to indicate the car is going the opposite direction (compared to sections A and C). However, speed is always nonnegative.

For the equation BaCl2 + Na2SO4 → BaSO4 + 2NaCl, how many chlorine atoms are on the reactants side and on the products side?

**Answer:2 reactants 2 products.
**

**
**

**this is a balanced chemical equation. That means the number of chlorine before the arrow will be the same after the arrow**

**Explanation: i think this answer will help you very much**

NEES HELP!!!!

Which of the following is "NOT" a theory of the formation of the universe?

A. Steady State Theory

B. Doppler Theory

C. Oscillating Theory

D. Big Bang Theory

**Answer:**

Doppler Theory

**Explanation:**

it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.

Solve the science problem

**Answer:**

ybuTouch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.Touch and hold a clip to pin it. Unpinned clips will be deleted after 1 hour.

Read this statement: Biotechnology uses primary clarifiers for biological nutrient removal.

Which part of the statement is not true?

Biological nutrients are found in wastewater.

Primary clarifiers remove biological nutrients.

Biological nutrients are part of biotechnology processes.

Biological nutrient removal is part of wastewater management.

**Primary clarifiers** removing biological **nutrients** is not true. **Primary clarifiers**

involves the use of processes such as **sedimentation** in order to remove

**particles** floating or other** inorganic solids** from the **waste water.**

Biological **nutrients** such as nitrogen and phosphorus are found in waste

water and **removal** of these important nutrients for other uses is a part of

**waste water **management.

The **secondary** clarifiers are the ones responsible for the **removal** of

**biological nutrients** in the **waste water** through biofiltration etc.

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Determine the percent composition of chromium (III) flouride CrF3

(Show your solution)

**Answer:**

Molar mass of CrF3, Chromium(III) Fluoride is 108.9913096 g/mol

51.9961+18.9984032·3

Mass percentage of the elements in the composition

Element Symbol Atomic Mass Number of Atoms Mass Percent

Chromium Cr 51.9961 1 47.707%

Fluorum F 18.9984032 3 52.294%

Notes on using the Molar Mass Calculator

Chemical formulas are case-sensitive.

Enter subscripts as simple numbers.

The converter uses a simple dot instead of using a midpoint typographic dot (·) in formulas for adduct molecules, such as water of hydration.

Example: type CuSO4.5H2O instead of CuSO₄·5H₂O.

**Explanation:**

please mark my answer in brainlist plz

Two parents are having a child The father has freckles which are a dominant trait The mother does not have trecktes Find the possibility of the chad having tracks.

**Answer:**

2:3

**Explanation:**

mathqway

A go cart with a mass of 60 kg is moving at a rate of 10 m/s. How much Kinetic Energy does the go cart have?

**Answer:**

**Explanation:**

The kinetic energy of an object can be found by using the formula

[tex]k = \frac{1}{2} m {v}^{2} \\ [/tex]

m is the mass in kg

v is the velocity in m/s

From the question

m = 60 kg

v = 10 m/s

We have

[tex]k = \frac{1}{2} \times 60 \times {10}^{2} \\ = 30 \times 100 \\ = 3000[/tex]

We have the final answer as

3000 JHope this helps you

**Answer:**

[tex]\boxed {\boxed {\sf 3000 \ J}}[/tex]

**Explanation:**

Kinetic energy is the energy an object has due to motion. It is calculated using the following formula:

[tex]KE=\frac{1}{2} mv^2[/tex]

The mass of the go-cart is 60 kilograms and the velocity is 10 meters per second.

m= 60 kg v= 10 m/sSubstitute the values into the formula.

[tex]KE= \frac{1}{2} (60 \ kg)(10 \ m/s)^2[/tex]

Solve the exponent.

(10 m/s)² = 10 m/s * 10 m/s = 100 m²/s²[tex]KE = \frac{ 1}{2} (60 \ kg)(100 \ m^2/s^2)[/tex]

Multiply the numbers together.

[tex]KE= 30 \ kg * 100 \ m^2/s^2[/tex]

[tex]KE= 3000 \ kg*m^2/s^2[/tex]

Convert the units. 1 kilogram meter squared per second squared is equal to 1 Joule, so our answer of 3000 kg*m²/s² equals 3000 Joules.

[tex]KE= 3000 \ J[/tex]

The go-cart has **3000 Joules** of kinetic energy.

Which of the following is the goal of physical fitness test? *

a. to determine the level of fitness.

b. to identify the area of development/improvement.

c. all of the above

d. to identify strengths and weaknesses.

**Answer**

**C**

**hope this helps!!**

*please mark brainliest if correct!! Trying to level up!!

in the bohr model, what is the ratio of its kinetic energy to its potential energy?

The centrifugal force C = mv^2/r = kq^2/r^2 = P centripetal force. m is the electron mass, q are the proton and electron charges (opposites), and r is the Bohr radius.

Thus 1/2 mv^2/r = 1/2 kq^2/r^2 and KE = 1/2 mv^2 = 1/2 kq^2/r = 1/2 PE

Therefore KE/PE = 1/2, no matter what state the electron is in.

How does the temp of water change when it is heated on a stove top and it begins to boil.

**Answer: **

**The temperature will no longer rise with the heat because the energy. When the water is boiled on the steam, the temperature rises when heat is given**

**Explanation:**

which distance indicator can be used to measure the most distant objects?

The **distance indicator** can be used to measure the **most distant objects** among all indicators stated above is **Type Ia supernovae**

In the field of **Astronomy**, there are different kind of distance indicators that can be used to measure the distance objects.

Few among them are :

Cepheids Type Ia supernovae Parallax Main-sequence fitting**Cepheid** variables can be measured up to 18 million light years.

The expansion rate of the universe can also be measured by trying to measure the apparent brightness of the **Type Ia supernovae**

**Parallax** means illusory state of an object when viewed from different points

**Main sequence fitting** makes use of a H-R diagram of the cluster to determine the distance to a stellar cluster.

The **distance indicator** can be used to measure the most distant objects among all indicators stated above is **Type Ia supernovae**

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PE:

Write T in the blank if the statement is true and E if it is false.

_____1. A basketball game starts with a jump ball.

_____2. Basketball is a cardiovascular work-out.

_____3. The middle of the basketball court is called the sideline.

_____4. Unlimited substitutions are allowed during a regular basketball game.

_____5. If the ball crosses the sideline, it is considered out of bounds and goes to the other team.

_____6. A turnover is any loss of the ball without a shot being taken.

_____7. A player may intentionally kick the ball for the team's benefit.

_____8. When dribbling a ball, a basketball you want to keep the ball below your waist and off to the side of your body.

_____9. If your opponent shoots at the wrong hoop your team receives the points.

_____10. After a player stops dribbling the ball in basketball, he or she is allowed 4 steps to pass or shoot.

**Answer:**

The answers are:

T, T, F, F, T, T, F, F, T, T, F

Good luck!

Two billiard balls having the same mass and speed roll directly toward each other. What is their combined momentum after they meet

Their combined **momentum **after they meet is 0.

According to the law of conservation of **momentum**, absent an external force, the combined **momentum **of two or more bodies operating upon one another in an isolated system remains constant. As a result, **momentum **cannot be gained or lost.

Let the **mass **of each billiard balls = m.

If the initial **velocity **of first ball is u; according to the question, the initial **velocity **of the second ball be -u.

Hence, initial **momentum **of the first ball is: P₁ = mu

initial **momentum **of the second ball is: P₂ = -mu

Hence, total initial **momentum **of the two balls = P₁ + P₂ = mu + ( -mu) = 0.

So, according to law of conservation of **momentum**:

Their combined **momentum **after they meet is = 0.

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The **combined momentum **of the two billiard balls after they meet is zero.

When two pool balls of the same size and speed roll directly at each other and collide, their **momentum **will increase.

Let us denote the **speed **of the first ball as [tex]\rm p_1[/tex] and the speed of the second ball as [tex]\rm p_2[/tex]. The **momentum **of the balls are equal in magnitude but opposite in direction because they have the **same mass **and **velocity**.

[tex]\rm p_1= -p_2[/tex]

When the balls collide, their **momentum increases**:

Total **momentum **after the collision= [tex]\rm p_1+ p_2[/tex]

Substituting the relationship

[tex]\rm p_1= -p_2[/tex]

Total **momentum **after the collision

[tex]\rm p_1- p_1= 0[/tex]

Therefore, the **combined momentum **of the two billiard balls after they meet is zero.

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Why would poor clusters of galaxies be more likely to have irregular shapes then rich

clusters

Other clusters with hundreds to thousands of galaxies are called rich clusters. The low mass of a poor cluster prevents the cluster from holding onto its members tightly. The poor cluster tends to be a bit more irregular in shape than a rich cluster. Each large spiral has several smaller galaxies orbiting them.

These Milky Way **companion **galaxies are easily visible from dark locations in the Southern Hemisphere. Prime examples of erratic galaxies are the Large and Small **Magellanic **clouds (left and right, respectively).

In comparison to a rich cluster, the poor cluster **typically **has a slightly more erratic shape. A number of smaller galaxies orbit each major spiral. The Small and Large **Magellanic **clouds are the two most well-known examples of atypical galaxies.

When two galaxies collide, **irregular **galaxies frequently result. This unusual Cartwheel Galaxy was created when a tiny galaxy slid through the **centre **of a massive spiral galaxy.

Therefore, Rich **clusters **are other clusters that include hundreds to thousands of galaxies. A weak cluster can't cling to its **members **strongly because of its low bulk.

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At a restaurant, 30% of customers donate to charity in exchange for a coupon. Estimate the probability that it will take at least four customers to find one who donates.
Ms.yuhas from beloved community charter school is smart and helpful
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Karls rectangular vegetable garden is 20 feet by 45 feet, and Makennas is 25 feet by 40 feet. Whose garden is larger in area?
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It's even better if you have a telescope or binoculars. Both allow you to see planets, the moon, and stars even closer. Telescopes are more powerful than binoculars. With a telescope, you can see the moon close enough to see its features. Labeled images can help you find different places on the moon or other objects in the night sky. Even without a telescope, you will still be able to find some of these places.Select the comparative adjectives from the passage.