(CO 6) Find the regression equation for the following data setx 245 187 198 189 176 266 210 255y 50 54 55 78 44 41 51 60cannot be determinedŷ = 74.17x – 0.09ŷ = -0.09x + 74.17ŷ = 0.09x – 74.17
Answers
Answer
ŷ = -0.09x + 74.17
Explanation
For the given data set:
x 245 187 198 189 176 266 210 255
y 50 54 55 78 44 41 51 60
The sum of x = 245 + 187 + 198 + 189 + 176 + 266 + 210 + 255 = 1726
The sum of y = 50 + 54 + 55 + 78 + 44 + 41 + 51 + 60 = 433
Mean x = 1726/8 = 215.75
Mean y = 433/8 = 54.125
Sum of squares (SSx) = 8391.5
Sum of products (SP) = -779.75
(Check the table below of the data for a better understanding).
The regression Equation is given by ŷ = bX + a
b = SP/SSx = -779.75/8391.5 = -0.09292
a = My - bMx = 54.13 - (-0.09 x 215.75) = 74.17279
Therefore, the regression equation for the data set is: ŷ = -0.09292x + 74.17279
The correct answer is ŷ = -0.09x + 74.17
Related Questions
Solve the problem. Use 3.14 as the approximate value of pie
Answers
The volume of a cylinder is calculated using the formula:
[tex]V=\pi r^2h[/tex]where r is the radius of the cylinder and h is the height.
From the question, we have the following parameters:
[tex]\begin{gathered} diameter=4.8 \\ \therefore \\ r=\frac{4.8}{2}=2.4 \\ and \\ h=6.66 \end{gathered}[/tex]Therefore, we c n calculae tehe volume of a cylinder to be:
[tex]\begin{gathered} V=3.14\times2.4^2\times6.66 \\ V=120.455424 \end{gathered}[/tex]For four cylinders, the combined volume will be:
[tex]\begin{gathered} V=120.455424\times4 \\ V=481.821696 \end{gathered}[/tex]The volume i 481 .82 cubic inches.
a coyote can run a hundred one in 5.3 seconds a jack-rabbit can run 75 m in 4.7 seconds compared their unit speeds to determine which animal is faster round to the nearest whole unit Blank#1 Coyote speedBlank#2 Jack Rabbit speedBlank#3 Which one is faster
Answers
Answer
Coyote's speed = 19 m/s
Jack Rabbit's speed = 16 m/s
The Coyote is faster since 19 > 16.
Explanation
To answer this, we need to note that the relationship between speed, distance and time is given as
Speed = (Distance/Time)
For the Coyote,
Distance = 101 m
Time = 5.3 seconds
Speed = (Distance/Time)
Coyote's speed = (101/5.3) = 19 m/s
For the Jack Rabbit,
Distance = 75 m
Time = 4.7 seconds
Speed = (Distance/Time)
Jack Rabbit's speed = (75/4.7) = 16 m/s
Since 19 m/s is evidently greater than 16 m/s, we can conclude that the Coyote is faster than the Jack Rabbit.
Hope this Helps!!!
Susanna has played the piano for s years. Patrick has played the piano for 4 more than twice the number of years that susanna has been playing the piano. which expression correctly shows the number of years that Patrick has been playing the piano.2s + 44s + 22 (s + 4)(s - 4) ÷ 3none of the above
Answers
Given data:
The expression for Patrick paly Piano is,
[tex]P=2s+4[/tex]Thus, the first option is correct.
A friend plans to purchase a 72-inch tv at a particular store for a cost of $1500. The store is offering 25% off any one item. He also has an internet coupon for an additional 10% off any discounted price. How much will your friend save (a) in dollar amount and (b) in percent?
Answers
the The Solution.
The marked price of the 72-inch TV = $1500
25% discount makes the actual discount to be:
[tex]\begin{gathered} \text{Actual Discount = 25 \% of 1500} \\ \text{ = }\frac{25}{100}\times1500=\text{ \$375} \end{gathered}[/tex]So, the discounted price will now be
Discounted price = 1500 - 375 = $1125
He has an additional 10% internet coupon discount on already dicounted price ($1125) .
[tex]\begin{gathered} \text{Additional discount = 10\% of 1125} \\ \text{ =}\frac{10}{100}\times1125=\text{ \$112.50} \end{gathered}[/tex]a. The friend will save
[tex]\begin{gathered} 375+112.50 \\ =\text{ \$487.50} \end{gathered}[/tex]b. in percentage, he saved
[tex]\frac{487.5}{1500}\times100=32.5\text{ \%}[/tex]Therefore, the correct answers are:
a. $487.50
b. 32.5%
12. A teacher weighed 148 lbs. in 1999 and weighs 190 lbs. In 2020. What was the rate ofchange in weight?
Answers
Given,
The weight of the teacher in 1999 is 148 lbs.
The weight of the teacher in 2020 is 190 lbs.
The rate of change in weight is,
[tex]\begin{gathered} \text{Rate of change=}\frac{190-148}{2020-1999} \\ =\frac{42}{21} \\ =2 \end{gathered}[/tex]The teacher gained 2 pounds per year.
Hence, option A is correct.
Which of the following tables represents a function?
Answers
Answer:
Table A represents a function
Step-by-step explanation:
Table A represents function because it is the only table that doesn't repeat an output or input number.
1. Consider the graph f(x) = 34. Describe how to graph thetransformation f(x – 3) + 2.
Answers
If the graph shows a constant function, the value of f(x) will always be the same no matter which value does x take. It means: to graph the transformation of this function do an horizontal translation right 3 units (which would show the same graph, basically) and then do a vertical translation up 2 units
question 5 only. determine the missing side length QP. the triangles are not drawn to scale.
Answers
This is a simple question.
First, we can see both triangles are proportional, it means it has the same relation between its sides even if one is in a large scale and the other on a a small scale.
Now we can identify which side corresponds to which side. Once side AC is the longest one for triangle ABC it means its equivalent for triangle PQR is the side RP, so the equivalent for side AB is side QP. Once we know that we can write the following relation and calculate:
Calculate the average rate of change for the function f(x) = 3x4 − 2x3 − 5x2 + x + 5, from x = −1 to x = 1.
a
−5
b
−1
c
1
d
5
Answers
Average rate of change for the function f(x) = 3x⁴ -2x³ -5x² +x +5 from
x =-1 to x=1 is equal to -1.
As given in the question,
Given function :
f(x) = 3x⁴ -2x³ -5x² +x +5
Formula for average rate of change for (a, f(a)) and (b, f(b))
[f(b) -f(a)] / (b-a)
Substitute the value of a=-1 and b=1
f(-1)=3(-1)⁴ -2(-1)³-5(-1)² +(-1) +5
= 3+2-5-1+5
=4
f(1)=3(1)⁴ -2(1)³-5(1)² +(1) +5
= 3-2-5+1+5
= 2
Average rate of change = (2-4)/(1-(-1))
= -2/2
=-1
Therefore, average rate of change for the function f(x) = 3x⁴ -2x³ -5x² +x +5 from x =-1 to x=1 is equal to -1.
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6-Find the measure of ∠AEB.A. 122°B. 132°C. 142°D. 152°7-Find the measure of ∠BEC.A. 58 °B. 48°C. 38°D. 28°8-Find the measure of ∠CED.A. 52 °B. 48 °C. 42 °D. 32°9-Find the measure of ∠FEB.A. 142°B. 180°C. 90°D. 0°10-Find the measure of ∠FED.A. 0°B. 180°C. 45°D. 90°
Answers
The answer for 6 is C. 142°
Explanation
∠AEB = 180 - ∠AEF (Sum of angle on a straight line)
∠AEB = 180 - 38 = 142°
(8-4) mulitiply (3-2)=
Answers
what is the sum of 141.2-79.83
Answers
Given:
141.2 - 79.83
Here, we are to subtract 79.83 from 141.2
Let's evaluate the given expression.
We have:
[tex]\begin{gathered} 141.20 \\ -79.83 \\ _{\text{ \_\_\_\_\_\_\_\_\_\_\_\_\_\_\_}} \\ \text{ 61.37} \end{gathered}[/tex]ANSWER:
61.37
Two functions are shown. f(x) = 29(0.5)* g(x) = 18x + 14 What is the value of f(2) + g(4)?
Answers
Answer:
93.25
Explanation:
Given the below functions;
[tex]\begin{gathered} f(x)=29(0.5)^x \\ g(x)=18x+14 \end{gathered}[/tex]To be able to find the value of f(2) + g(4), we have to 1st determine the value of f(2) and f(4) as shown below;
[tex]\begin{gathered} f(2)=29(0.5)^2=29\ast0.25=7.25 \\ g(4)=18(4)+14=72+14=86 \end{gathered}[/tex]Let's go ahead and find the value of f(2) + g(4);
[tex]f(2)+g(4)=7.25+86=93.25[/tex]K
Determine whether the statement is true or false, and explain why.
The derivative value f'(a) equals the slope of the tangent line to the graph of y=f(x) at x = a.
Choose the correct answer below.
OA. The statement is true because f'(x) is a function of x.
B. The statement is false because f(a) gives the instantaneous rate of change of f' at x = a.
OC. The statement is true because f'(a) gives the instantaneous rate of change of fat x = a.
OD. The statement is false because f'(a) gives the average rate of change of f from a to x.
Answers
Answer: C. The statement is true because f'(a) gives the instantaneous rate of change of fat x = a.
An object is dropped from 27 feet below the tip of the pinnacle atop a 1471-ft tall building. The height h of the object after t seconds is giveh= - 16t^2 + 1444. Find how many seconds pass before the object reaches the ground.How many seconds pass before the object reaches the ground
Answers
The Solution:
Given:
[tex]h=-16t^2+1444.[/tex]We are required to find t when h = 0.
[tex]\begin{gathered} -16t^2+1444=0 \\ \\ -16t^2=-1444 \end{gathered}[/tex]Divide both sides by -16.
[tex]t^2=\frac{-1444}{-16}=90.25[/tex][tex]\begin{gathered} t=\sqrt{90.25} \\ \\ t=9.5\text{ or }t=-9.5 \end{gathered}[/tex]Thus, the correct answer is 9.5 seconds.
determine the solution,if it exists,for each system of linear equation. Verify your solution on the coordinate plane. x + 3 = y 3x + 4y = 7
Answers
then
[tex]\begin{gathered} 3\mleft(y-3\mright)+4y=7 \\ 3y-9+4y=7 \\ 7y-9=7 \\ 7y-9+9=7+9 \\ 7y=16 \\ \frac{7y}{7}=\frac{16}{7} \\ y=\frac{16}{7} \end{gathered}[/tex]replacing in x
[tex]undefined[/tex].Find the area of the sector with radius 4 and central angle, ∅= 45°
Answers
Remember that the formula for the area of a sector is:
[tex]A=\frac{\pi\cdot r^2\cdot\theta}{360}[/tex]Where:
• r, is the radius
,• Theta ,is the central angle (in degrees)
Using this formula and the data given,
[tex]\begin{gathered} A=\frac{\pi\cdot4^2\cdot45}{360} \\ \rightarrow A=2\pi \end{gathered}[/tex]15% of $764.69rounded to the nearest cent.
Answers
Percentage is expressed in terms of 100. To find 15% of 764.69, we would multiply ratio of 15% to 100% by 764.69. Thus, we have
15/100 * 764.69
= 114.7035
Write an equation for the graph below in point-slope form and then solve rewrite in slope-intercept form.
Answers
We are given the graph of a line and we are asked to determine its equation in point-slope form.
The general form in slope point form of a line is:
[tex]y-y_0=m(x-x_0)[/tex]Where:
[tex]\begin{gathered} m=\text{ slope} \\ (x_0,y_0)\text{ is apoint in the line} \end{gathered}[/tex]to determine the slope we will use the following formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where:
[tex](x_1,y_1);(x_2,y_2)=\text{ points on the line}[/tex]We will choose two points on the line from the graph:
[tex]\begin{gathered} (x_1,y_1)=(0,1) \\ (x_2,y_2)=(2,2) \end{gathered}[/tex]Now, we plug in the values in the formula for the slope:
[tex]m=\frac{2-1}{2-0}=\frac{1}{2}[/tex]Now, we substitute the value of the slope in the equation of the line:
[tex]y-y_0=\frac{1}{2}(x-x_0)[/tex]Now, we plug in the first point we choose for the line:
[tex]\begin{gathered} y-1=\frac{1}{2}(x-0) \\ \\ y-1=\frac{1}{2}x \end{gathered}[/tex]And thus we have determined the equation of the line in point-slope form.
The slope-intercept form is the following:
[tex]y=mx+b[/tex]To convert this equation to slope-intercept form, we will take the previous equations and we will add 1 to both sides:
[tex]y=\frac{1}{2}x+1[/tex]And thus we have determined the slope-intercept form of the equations of the line.
I got the picture and will send it to you show the coordinates of the points that create the shape of the image
Answers
We have the following:
[tex]\begin{gathered} P(1-1,-3+3)\rightarrow P^{\prime}(0,0) \\ Q(3-1,-1+3)\rightarrow Q^{\prime}(2,2) \\ R(4-1,-3+3)\rightarrow R^{\prime}(3,0) \end{gathered}[/tex]now,
The answer is:
What transaction occurs when an investor decides to liquidate assets?
A. buy
B. hold
C. sell
D. speculate
Answers
Answer:
What transaction occurs when an investor decides to liquidate assets?
A. buy
B. hold
(C. sell)
D. speculate
Step-by-step explanation:
I got a 5/5 on the test and i got the answer from a quizlet (:
Sell is the answer
The correct option is (C).
Given,
In the question:
What transaction occurs when an investor decides to liquidate assets?
Now, According to the question:
when an investor decides to liquidate assets.
when an investor decides to liquidate assets means he or she want to sell the property in the open market, in other words liquidate assets means
converting non- liquid assets into liquid assets.
In investing, liquidation occurs when an investor closes their position in an asset. Liquidating an asset is usually carried out when an investor or portfolio manager needs cash to re-allocate funds or rebalance a portfolio. An asset that is not performing well may also be partially or fully liquidated.
According to the statement
Therefore, Sell is the answer
The correct option is (C).
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[tex]8.25 \div 6[/tex]8.25 divid by 6
Answers
We want to calculate the following number
[tex]\frac{8.25}{6}[/tex]To make the calcul.ation easier, we will transform the number 8.25 into a fraction. Recall that
[tex]8.25=\frac{825}{100}[/tex]So, so far, we have
[tex]\frac{8.25}{6}=\frac{\frac{825}{100}}{6}[/tex]Also, recall that
[tex]6=\frac{6}{1}[/tex]So, we have
[tex]\frac{\frac{825}{100}}{6}=\frac{\frac{825}{100}}{\frac{6}{1}}[/tex]Now, recall that when we divide fractions, we have
[tex]\frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot d}{b\cdot c}[/tex]In this case, we have a=825,b=100,c=6,d=1.
So we have
[tex]undefined[/tex]A sector of a circle has a central angle of 60∘ . Find the area of the sector if the radius of the circle is 9 cm.
Answers
Step-by-step explanation:
area of a sector is theta ÷360 ×πr²
Sue would like to join a gym. Gym A has a $56 joining fee with $3 per visit. Gym B has a $30 joining fee with a $5 per visit. Let x represent the number of visits. After how many visits would the cost of the two gyms be the same?
Answers
Let x represent the number of visits it will take for the cost of the two gyms to be the same.
Gym A has a $56 joining fee with $3 per visit. This means that the cost of x visits of gym A would be
3 * x + 56
= 3x + 56
Gym B has a $30 joining fee with a $5 per visit. This means that the cost of x visits of gym B would be
5 * x + 30
= 5x + 30
For both costs to be the same, it means that
3x + 56 = 5x + 30
5x - 3x = 56 - 30
2x = 26
x = 26/2
x = 13
After 13 visits, the cost of the two gyms would be the same
what is the area of a triangle with the legth of 8in,12in,6in
Answers
Area is
[tex]A=\frac{1}{2}bh=\frac{1}{2}\times6\times8=\frac{48}{2}=24[/tex]answer: 24 sq in
How to draw the graphs of the following non-linear functions?y=x^2 + 1y=3^x + 1
Answers
The first step is to substitute values of x into each equation.
For y = x^2 + 1,
if x = - 2, y = (- 2)^2 + 1 = 4 + 1 = 5
if x = - 1, y = (- 1)^2 + 1 = 1 + 1 = 2
if x = 0, y = (0)^2 + 1 = 0 + 1 = 1
if x = 1, y = (1)^2 + 1 = 1 + 1 = 2
if x = 2, y = (2)^2 + 1 = 4 + 1 = 5
We would plot the corresponding values of x and y on the graph as shown below
For y = 3^(x + 1),
if x = - 2, y = 3^(-2 + 1) = 3^-1 = 0.33
if x = - 1, y = 3^(-1 + 1) = 3^0 = 1
if x = 0, y = 3^(0 + 1) = 3^1 = 3
if x = 1, y = 3^(1 + 1) = 3^2 = 9
if x = 2, y = 3^(2 + 1) = 3^3 = 27
We would plot the corresponding values of x and y on the graph as shown below
Evaluate the expression (4x^3y^-2)(3x^-2y^4) for x = –2 and y = –1.
Answers
Answer:
3x−2y)(4x+3y)
It can be written as =3x(4x+3y)−2y(4x+3y)
By further calculation =12x
2
+9xy−8xy−6y
2
So we get =12x
2
+xy−6y
2
Solve the inequality for x and identify the graph of its solution.|x+ 2] < 2Choose the answer that gives both the correct solution and the correct graph.
Answers
| x + 2 | < 2
-2 < x + 2 < 2
-2 - 2 < x + 2 < 2 - 2
-4 < x < 0 This is the inequality
Letter B is the right choice.
Katie opened a savings account and deposited 1,000.00 as principal the account earns 4% interest compounded quarterly what is the balance after 6 years
Answers
P = $1000
r = 4% = 4/100 = 0.04
t = 6 years
Therefore,
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ A=1000(1+\frac{0.04}{4})^{4\times6} \\ A=1000\times1.26973464853 \\ A=1269.73464853 \\ A=\text{ \$1269.73} \end{gathered}[/tex]Can you Help me with this i cannot do ir
Answers
To translate f(x) 4 units down we subtract 4 from f(x):
[tex]f(x)-4.[/tex]Now, to reflect f(x)-4 over the x-axis we multiply by -1:
[tex]-1(f(x)-4)=-f(x)+4.[/tex]Answer:
[tex]g(x)=-\sqrt[3]{x-2}+4.[/tex]