Can someone help with these questions??
Will be helpful

Let first consider the equations one by one and will be solving one by one ;

[tex]{:\implies \quad \sf x+\dfrac{1}{y}=4}[/tex]

Multiplying both sides by y will lead ;

[tex]{:\implies \quad \sf xy+1=4y}[/tex]

[tex]{:\implies \quad \boxed{\sf xy=4y-1\quad \cdots \cdots(i)}}[/tex]

Now, consider the second equation which is ;

[tex]{:\implies \quad \sf y+\dfrac{1}{x}=\dfrac14}[/tex]

Multiplying both sides by x will yield

[tex]{:\implies \quad \sf xy+1=\dfrac{x}{4}}[/tex]

[tex]{:\implies \quad \sf xy=\dfrac{x}{4}-1}[/tex]

[tex]{:\implies \quad \boxed{\sf xy=\dfrac{x-4}{4}\quad \cdots \cdots(ii)}}[/tex]

As LHS of both equations (i) and (ii) are same, so equating both will yield;

[tex]{:\implies \quad \sf 4y-1=\dfrac{x-4}{4}}[/tex]

Multiplying both sides by 4 will yield

[tex]{:\implies \quad \sf 16y-4=x-4}[/tex]

[tex]{:\implies \quad \sf 16y=x}[/tex]

Dividing both sides by y will yield :

[tex]{:\implies \quad \boxed{\bf{\dfrac{x}{y}=16}}}[/tex]

Hence, the required answer is 16

Answer:

it is 35.91, 36 to the nearest cent

Step-by-step explanation:

I don't know how to explain it to u sorry

Using the vertex of a quadratic equation, it is found that P is at a maximum for l = -0.5 thousand foot-candles.

A quadratic equation is modeled by:

[tex]y = ax^2 + bx + c[/tex]

The vertex is given by:

[tex](x_v, y_v)[/tex]

In which:

[tex]x_v = -\frac{b}{2a}[/tex]

[tex]y_v = -\frac{b^2 - 4ac}{4a}[/tex]

Considering the coefficient a, we have that:

In this problem, the function for P is given by:

[tex]P(l) = \frac{110l}{l^2 + l + 4}[/tex]

The function will be at a maximum when the denominator is at a minimum. The denominator is a quadratic function with coefficients a = 1, b = 1, c = 4, hence:

[tex]l_v = -\frac{b}{2a} = -\frac{1}{2} = -0.5[/tex]

P is at a maximum for l = -0.5 thousand foot-candles.

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Answer:

All are complementary angles

Step-by-step explanation:

See attachment

The cost of a washer is $1184 while the cost of a drier is $296

Given Data

Hence,

w+d = 1184 -------------1

we know that the cost of the washer is three times the cost of the dryer.

w = 3d -------------------2

put w = 3d in equation 1

3d + d = 1184

4d = 1184

d = 1184/4

d = 296

The cost of a drier is $296

put d = $296 in equation 2

w = 3*296

w = $888

Check:

$888+$296 = $1184

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Answer:

The answer should be about 114.

Step-by-step explanation:

Of you look at the shape of the other angles. B and D seem to be about 90 and the shape of A is just a little bit bigger than ninety. I started by adding 78, 90, and 90 together which gave me 246. Then I subtracted 246 from 360 which gave me 114. I had estimated the answer to be around 110.

Answer:

7/2(a+b)

Step-by-step explanation:

To add fractions you need to find the LCM (least common multiplier) and then combine.

least common multiplier of a+b, 2(a+b) : 2(a + b)

Adjust fractions based of LCM

2/2(a + b) + 5/2(a +b)

2+5/2 (a + b) =

7/2 (a + b)

I hope this makes sense! :)

Answer:

i belive the answer is 73

Step-by-step explanation:

45+62=107

180-107=73

The marginal utility is the extra satisfaction derived from the consumption of a product.

Your information isn't well written. Therefore, an overview of utility will be given. The total utility is the total amount of satisfaction that a consumer derives from a product.

The marginal utility simply means the extra satisfaction that's gotten from a product when an additional unit is consumed.

The formula for marginal utility will be:

= Total utility difference/Quantity of goods difference

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Answer:

Let x = cube root of 400

Using a calculator x = 7.368 to 3 decimal places

So: 7 < x < 8

first off let's change the mixed fractions to improper fractions, and let's Hailey's account first.

[tex]\stackrel{mixed}{9\frac{1}{4}}\implies \cfrac{9\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{37}{4}} ~\hfill \stackrel{mixed}{8\frac{7}{8}}\implies \cfrac{8\cdot 8+7}{8}\implies \stackrel{improper}{\cfrac{71}{8}} \\\\[-0.35em] ~\dotfill[/tex]

[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &\stackrel{43000(2)}{\$86000}\\ P=\textit{original amount deposited}\dotfill & \$43000\\ r=rate\to \frac{71}{8}\%\to \frac{~~ \frac{71}{8}~~}{100}\dotfill &0.08875\\ t=years \end{cases} \\\\\\ 86000=43000e^{0.08875\cdot t}\implies \cfrac{86000}{43000}=e^{0.08875t}\implies 2=e^{0.08875t}[/tex]

[tex]\ln(2)=\ln(e^{0.08875t})\implies \log_e(2)=\log_e(e^{0.08875t})\implies \ln(2)=0.08875t \\\\\\ \cfrac{\ln(2)}{0.08875}=t\implies 7.81\approx t[/tex]

ok, now we know how long it takes for Hailey's money to double, how much money does Aiden have by then?

[tex]~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$43000\\ r=rate\to \frac{37}{4}\%\to \frac{~~ \frac{37}{4}~~}{100}\dotfill &0.0925\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &\frac{\ln(2)}{0.08875} \end{cases}[/tex]

[tex]A=43000\left(1+\frac{0.0925}{12}\right)^{12\cdot \frac{\ln(2)}{0.08875}}\implies A=43000\left( \frac{4837}{4800} \right)^{\frac{12\ln(2)}{0.08875}}\implies \boxed{A\approx 88311}[/tex]

notice, in Hailey's amount we used the logarithmic value for "t", just to avoid any rounding issues.

Given: f(x)=2x(cube)-6x+x

reaminder of f(x) when (x+1) diveded

to find value of k

solution,

f(x)=2x(cube)-6x+k

f(-1)=7

2(-1)(cube)+6+k=7

4+x=7

k=7

Hence,k=7

Answer:

[tex]\sqrt{X-5}[/tex], [tex]-\sqrt{X-5}[/tex]

Step-by-step explanation:

Replace X with Y

solve for Y; X = Y^2 + 5

subtract 5 from both sides

X - 5 = Y^2

take the square root

Y = plus or minus sqrt(X-5)

sqrt(X-5); -sqrt(X-5)

how many pieces of tape can be cutted.

[tex]5 \frac{1}{3} \div \frac{2}{3} [/tex]

[tex] = (5 + 0) + ( \frac{1}{3} + \frac{2}{3} )[/tex]

[tex] = 5 + \frac{1 + 2}{3} [/tex]

[tex] = 5 + \frac{3}{3} [/tex]

[tex] = 5 + \frac{3 \div 3}{3 \div 3} [/tex]

[tex] = 5 + \frac{1}{1} [/tex]

[tex] = 6[/tex]

therefore, 6 pieces of tape can be cutted.

Answer:

a = 70 degrees.

Step-by-step explanation:

Use this circle angle theorem:

The angle subtended by an arc at the center of a circle = 2 times the angle subtended by the arc on the circumference.

So m < a = 1/2 * 140 = 70 degrees.

Answer:

180 - 90 - 60

Step-by-step explanation:

all internal angles of a triangle add up to 180. this means A must be equal to 180 - 90 - 60 = 30

Answer:

30

Step-by-step explanation:

A triangle always = 180 degrees :)

So first we can add :D

60 + 90 + a = 180

150 + a = 180

Now we subtract :)

180 - 150 = 30

The answer is 30!

Have an amazing day!!

Please rate and mark brainliest!!

Using the z-distribution, it is found that the data provides convincing evidence that the proportion has increased.

At the null hypotheses, it is tested if the proportion has not increased, that is, the difference of the 2017 proportion and the 2014 proportions is not positive, hence:

[tex]H_0: p_2 - p_1 \leq 0[/tex]

At the alternative hypothesis, it is tested if the proportion has increased, hence:

[tex]H_1: p_2 - p_1 > 0[/tex]

For each sample, they are given by:

[tex]p_1 = 0.197, s_1 = \sqrt{\frac{0.197(0.803)}{61}} = 0.0509[/tex]

[tex]p_2 = 0.383, s_2 = \sqrt{\frac{0.385(0.615)}{52}} = 0.0675[/tex]

Hence, for the distribution of differences, they are given by:

[tex]\overline{p} = p_2 - p_1 = 0.383 - 0.197 = 0.186[/tex]

[tex]s = \sqrt{s_1^2 + s_2^2} = \sqrt{0.0509^2 + 0.0675^2} = 0.0845[/tex]

It is given by:

[tex]z = \frac{\overline{p} - p}{s}[/tex]

In which p = 0 is the value tested at the null hypothesis.

Hence:

[tex]z = \frac{\overline{p} - p}{s}[/tex]

[tex]z = \frac{0.186 - 0}{0.0845}[/tex]

z = 2.2

Considering a right-tailed test, as we are testing if the proportion is higher than a value, the critical value at the 0.05 significance level is [tex]z^{\ast} = 1.645[/tex].

Since the test statistic is greater than the critical value for the left tailed test, the data provides convincing evidence that the proportion has increased.

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Answer:

the answer is 3.

Step-by-step explanation:

mode if what numberhappens most often

Answer:

  a. 885,920

  b. year 8

Step-by-step explanation:

The population at a given time is described by the exponential formula ...

  P(t) = P0·e^(-0.04t)

where P0 is given as 1,000,000.

We are asked for the value of P(3). This ccan be found by substituting 3 for t in the equation and evaluating the numerical expression.

  P(3) = 1,000,000·e^(-0.04·3) = 1,000,000·e^(-0.12)

  P(3) ≈ 886,920

The population when t=3 is about 886,920.

__

We can put the given numbers in the equation and solve for t.

  750,000 = 1,000,000·e^(-0.04t)

  0.75 = e^(-0.04t) . . . . . divide by 1,000,000

  ln(0.75) = -0.04t . . . . . take the natural log

  -ln(0.75)/0.04 = t ≈ 7.192

The population will drop below 750,000 in year 8.

_____

Additional comment

These values can be confirmed by a graphing calculator.

Note that "year 1" is the year between t=0 and t=1. So, "year 8" is the year between t=7 and t=8.

Answer:

ok it's a good question... so answer to that is... I also don't know..

Answer:

the graph will be an exponential function that crosses the y-axis at about (0, -4).

Step-by-step explanation:

Answer:

The answer is the first graph.

Step-by-step explanation:

I just did the quiz

Answer:

372

Step-by-step explanation:

area of trapezium = a+b/2 * h

a is the length on top

b is the length on the bottom

h is the height

7+24/2*24=

=372

If the monthly payments mad s $200, the number of months it would take to pay off the loan is 46.54 months.

The first step is to determine the total value of the loan.

Total value of the loan = (1 + interest) x amount of the loan

Amount of the loan = 9000 - 500 = $8,500

Total value of the loan = (1.095) x $8500 = $9307.50

Number of months it would take to pay off the loan = total value of the loan / monthly payments

$9307.50 / 200 = 46.54 months

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Answer:

68 and 22 degrees

Step-by-step explanation:

Complimentary angles sum to 90

x  +   (x-46) = 90

2x = 90 + 46

2x = 136

x = 68    and the other is 68 - 46 = 22

First, we have "at least 120 bagels"

So we write ≥120 bagels.

Now, we are given that:-

Mrs. Trevino already has 2 dozen bagels.

Remember, a dozen is equal to 12, so if we have 2 dozen, then we have

[tex]\sf{2*12=24}\longleftarrow\sf{Mrs.Trevino~already~has~24~bagels}[/tex]

Now, she'll buy the remaining bagels in packages of 6, so we write

6x (packages of 6)

So the inequality looks like so:-

[tex]\sf{6x+24\geq 120}[/tex]

Now, let's solve the inequality :)

First, subtract 24 from both sides:-

[tex]\sf{6x\geq 120-24}[/tex]

[tex]\sf{6x\geq 96}[/tex]

Divide both sides by 6:-

[tex]\bigstar{\boxed{\pmb{x\geq 16}}}\longleftarrow\sf{number~of~packages~she~should~buy}[/tex]

Hope everything is clear :)

Answer:

The ratio of the new distance to the old distance is  (11/2) .

The intensity is inversely proportional to the square of the distance,

so the new intensity will be  (2/11)²  times the old intensity.

Intensity =                 8,000 (2/11)² =

                              32,000 / 121  =  262.463  units

  Rounded to the nearest whole unit:  262 units

Step-by-step explanation:

264 units of intensity came from a distance of 11 miles option (c) 264 units is correct.

It is given that the intensity is 8000 units at a distance of 2 miles.

It is required to find the intensity at a distance of 2 miles.

Fraction number consists of two parts one is the top of the fraction number which is called the numerator and the second is the bottom of the fraction number which is called the denominator.

The intensity of a radio signal from the radio station varies inversely as the square of the distance from the station.

Suppose the Intensity of the signal is I and the distance is d, then:

[tex]\rm I \propto\frac{1}{d^2}[/tex]

Intensity from the station [tex]\rm I_1=8000 \ units[/tex]

[tex]\rm I_1[/tex] intensity at distance [tex]\rm d_1=2 \ miles[/tex]

Intensity from the station [tex]=\rm I_2[/tex]

[tex]\rm I_1[/tex] intensity at distance [tex]\rm d_2=11 \ miles[/tex]

[tex]\rm \frac{I_2}{I_1} = \frac{d_1^2}{d_2^2}[/tex]       (From the proportional relation)

[tex]\rm \frac{I_2}{8000} = \frac{2^2}{11^2}[/tex]

[tex]\rm I_2 =8000\times\frac{4}{121} \\\\\rm I_2 = 264.46 \ units[/tex] ≈ 264 units

Thus, the 264 units of intensity came from a distance of 11 miles.

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[tex]y = 2x - 7[/tex]

should be it

Answer:

Its C

Step-by-step explanation:

Why? because its C

Answer:

1935 were supporting the home team

Step-by-step explanation:

Since there are 4,500 people attending the game, we must find 43% of that. Doing this, we need to multiply 43% or .43 by 4,500.

After solving, you should get 1,935. There were 1,935 people supporting the home team.

Answer:

Step-by-step explanation:

Given

Remember :

Solving

Answer:

[tex]\huge\boxed{\bf\:\frac{w^{6}}{9}}[/tex]

Step-by-step explanation:

[tex]\frac{ 3 ^ { -2 } \times k ^ { 0 } \times w ^ { 0 } }{ w ^ { -6 } }[/tex]

Any number with 0 as its exponent will be equal to 1. So,

[tex]\frac{3^{-2} \times 1 \times 1}{w^{-6}}\\= \frac{3^{-2}}{w^{6}}[/tex]

Now,

[tex]\frac{3^{-2}}{w^{6}}\\= 3^{-2}w^{6}[/tex]

Then,

[tex]3^{-2}w^{6}\\= \frac{1}{3^{2}}w^{6}\\= \frac{1}{9}w^{6}\\= \boxed{\bf\:\frac{w^{6}}{9}}[/tex]

[tex]\rule{150pt}{2pt}[/tex]