Answer:
umm I also need help sorry
Explanation:
help..
Answer:
1.07 X 10^15 kg
Explanation:
You are standing on a moving bus, facing forward, and you suddenly fall forward. You can imply form this that the bus’s
Beth moves a 15 N book 20 meters in 10 seconds. How much power was produced?
Answer:
30 Watts
Explanation:
Power = Work/Time
Work = Force*Distance
Power = Force * Distance / Time
Power = 15 N * 20 meters / 10 sec
Power = 30 Watts
As you enter the lab, you find two bottles labeled "concentrated ammonium phosphate." In one paragraph, using your own words, describe the steps you could take to change one of the bottles into a diluted solution, and one of the bottles into a saturated solution.
Answer:
Butane is a four member carbon chain.
The properties of butane are as follows.
Butane is less denser than water.
In the presence of air, it readily burns to form water vapour and carbon dioxide. The reaction is as follows.
It has a boiling point of .
Butane has faint petroleum like odor.
Butane does not react with water.
Butane has weak dispersion force and water has strong hydrogen bonding. The weak dispersion force is unable to break the hydrogen bonding hence, butane does not dissolve in water.
Thus, we can conclude that the chemical properties butane burns readily in air and does not react with water are true out of the given list of options.
Explanation:
State two devices that transfer heat out of a cool environment into a warm environment
Answer:
Heat pump
Refrigerators
Explanation:
Some devices like heat pump and refrigerators used transfers of thermal energy in a cool region to warm other region.
These types of devices used for transferring heat energy by thermal conduction method.
!!!!!
While following directions on a treasure map, a person walks 45.0 m south, then turns and
walks 7.50 m east. What is the direction of the straight line that the treasure hunter could have
walked directly from the starting to reach the same spot?
(1 Point)
9.5° south of east
9.5° east of south
21° south of east
21° east of south
Answer:
46 m at 9.5 degrees east of south
Explanation:
the fall of a body on the earth's surface cannot be a complete free fall why ?
Explanation:
because the boy has larger surface area due to which he offers the larger air resistance which decreases the acceleration so, he will fall towards the earth's surface approximately with constant velocity.
What does this same experiment( the picture) tell you about light waves? Explain.
A steel rod has a diameter of 3.75cm.Express it's diameter in millimeters and meter
Answer:
3.75cm into millimetres
= 3.75 * 10
37.5 millimetres
3.75 cm into metres
3.75/100
= 0.0375m
A hot air balloon holds 7.40 x 107 liters of gas. In order for the hot air balloon to rise into the sky, it must be heated to 120°C. Once the balloon is up in the air, the air needs to be cooled in order for the balloon to land. If the temperature of the balloon is decreased to 40.0°C, what will the new volume of the gas be?
Remember to pay close attention to the units of temperature before beginning your calculations.
Answer:
2.467×10^7 litres
Explanation:
Using the formula V1/T1 = V2/T2
V1 and V2 are the initial and final volume respectively
T1 and T2 are their respective temperatures
Given
V1 = 7.4×10^7litres
T1 = 120°C
T2 = 40°C
Required
V2
From the formula
V2 = V1T2/T1
V2 = 7.4×10^7(40)/120
V2 = (7.4×10^7)/3
V2 = 2.467×10^7 litres
Hence the new volume of the gas will be 2.467×10^7 litres
If you launch an object in space, it
will continue to move forward
until an external force stops it.
This is a characteristic of which
law?
Answer:
I believe this represents Newton's first law of motion. Any object in motion will continue to move until a force stops it, be it friction or a physical object.
---Spring Question---
A 0.84 kg ball is held at rest against a spring (k = 142 N/m) that has been compressed 0.06 m. The ball and spring are on a table and the ball is 2.0 m above the ground. If friction between the ball and the table is negligible, then how far from the edge of the table (in meters) will the ball hit the ground?
Answer:
The distance from the edge of the table at which the ball will hit the ground is approximately 0.49 meters
Explanation:
The mass of the ball = 0.84 kg
The spring constant k = 142 N/m
The compression of the spring = 0.06
Therefore, by conservation of energy, we have;
The potential energy of the spring = The kinetic energy given to the ball
The potential energy of the spring = 1/2 × k × x² = 1/2 × 142 × 0.06² = 0.2556
The potential energy of the spring = 0.2556 J
The kinetic energy given to the ball = 1/2 × m × v²
Where;
v = The final velocity of the ball
Substituting gives;
1/2 × 0.84 × v² = 0.2556
∴ v = √(0.2556/(1/2 × 0.84)) ≈ 0.78
The final velocity of the ball = v ≈ 0.78 m/s
The height of the ball above the ground, h = 2.0 m
Therefore, we have;
The time, t, it takes the ball to touch the ground from the 2.0 m height, h, is given as follows;
h = 1/2·g·t²
t = √(2·h/g)
Where;
g = The acceleration due to gravity = 9.81 m/s²
∴ By substitution, we have;
t = √(2 × 2/9.81) ≈ 0.63855
t ≈ 0.63855 s
The distance from the edge of the table at which the ball will hit the ground = The horizontal distance covered during before the ball hits the ground
The horizontal distance covered during before the ball hits the ground = The (horizontal) velocity of the ball × The time it takes the ball to touch the ground
∴ The horizontal distance covered during before the ball hits the ground = 0.78 × 0.62855 ≈ 0.490269 ≈ 0.49
The distance from the edge of the table at which the ball will hit the ground = The horizontal distance covered during before the ball hits the ground ≈ 0.49 m
When is the object traveling at a constant velocity?
A
B
C
D
It is moving at a constant velocity the entire time
d
I think the most common way of doing it was for the first
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 41.5-gram mass is attached at the 28.5-cm mark, the fulcrum must be moved to the 39.2-cm mark for balance. What is the mass of the meter stick
Answer:
The value is [tex]M = 42.3 \ kg[/tex]
Explanation:
From the question we are told that
The first position of the fulcrum is x = 49.7 cm
The mass attached is [tex]m = 41.5 \ g[/tex]
The position of the attachment is [tex]x_1 = 28.5 \ cm[/tex]
The second position of the fulcrum is [tex]x_2 = 39.2 \ cm[/tex]
Generally the sum of clockwise torque = sum of anti - clockwise torque
So
[tex]CWT = m (x_2 - x_1)[/tex]
Here CWT stands for clockwise torque
[tex]ACWT = M ( x - x_2)[/tex]
So
[tex]m (x_2 - x_1) = M ( x - x_2)[/tex]
=> [tex]41.5 (39.2 - 28.5 ) = M ( 49.7 -39.2 )[/tex]
=> [tex]M = 42.3 \ kg[/tex]
For an object to have potential energy it must be...?
A) At rest
B) Light weight
C) Moving
D) Elevated (height)
Please I need help, thank you!
Answer the following
1) A piece of gold weighis 240 g and has a volume of 20 cm^3. Find the density of gold.
2) What is the perpendicular distance between the force and the turning point if a force
of 25 N produces a moment of force of 12.5 Nm
pls answer fast I will mark as brainlist
Answer:
1. 12 g/cm³
2. 0.5 m
Explanation:
1.
The weight of the gold is 240 g
The volume is 20 cm³
Density = Mass/ volume
Density = 240 / 20 = 12 g/cm³
2.
The formula for moment of a force is ;
Force * distance perpendicular between force and the turning point of force
Given that the moment of force is 12.5 Nm and force is 25 N then the perpendicular distance between the force and the turning point will be;
12.5 = 25 * d
12.5/25 = d
0.5 = d
d= 0.5 m
If an arrow is fired from a bow with a perfectly horizontal velocity of 60.0 m/s and the arrow had a vertical velocity of 6m/s just before it hit the ground, how long will it take to strike the ground ?
Answer:
t = 1,28 s
Explanation: This problem is a projectile motion problem.
V₀ₓ = V₀ * cosθ
Vₓ = constant all the way
Vₓ = V₀ₓ
tanθ = Vyi/Vxi that means in any point of the trajectory
tanθ = 6 / 60 ( just before touching the ground )
tanθ = 0,1 then arctan 0,1 ≈ 6⁰
sin 6⁰ = 0,1045
cos 6⁰ = 0,9945
V₀ₓ = V₀ * cosθ ⇒ V₀ = V₀ₓ / cosθ ⇒ V₀ = 60 / 0,9945
V₀ = 60,33 m/s
V₀y = V₀ * sin θ ⇒ V₀y = 60,33 * 0,1045 ⇒ V₀y = 6,30 m/s
Vy = V₀y - g * t
At maximum y Vy = 0 ( the middle of the trajectory)
g*tm = V₀y ⇒ tm= V₀y / g
tm = 6,30 / 9,8
tm = 0,64 s ( time to reach maximum y )
Then the time of fligh is twice 0,64 s
t = 0,64 * 2
t = 1,28 s
Incident ray X passes parallel to the principal axis of a concave lens. Incident ray Y passes parallel to the principal axis of a convex lens.
How do the rays behave differently after passing through each lens?
Ray X continues moving in the same direction, and ray Y refracts and passes through the focal point located behind the lens.
Both rays refract and move as though they passed through the focal point.
Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Both rays continue moving in the same direction.
Answer:
Explanation:
It would be option C. Ray x appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Answer:
c. Ray X appears as though it passed through the focal point in front of the lens, and ray Y passes through the focal point on the other side of the lens.
Explanation:
marcus is on a merry-go-round holding a string. you are standing next to him and holding the other end of the string so that the string forms a tangent line to the edge of the merry-go-round. if marcus is 2 meters from the center of the ride, what torque are you applying on him if you pull 30 N? _Nm
Answer: 60 nm
Multiply 30 and 2
What is the tangential velocity of a record player which makes 11 revolutions in 20 seconds?
Velocity is defined as rate of change of displacement wit respect to time.
tangential velocity is (11/10)πr , where r is radius of circular track.
Since, tangential velocity is, [tex]=\frac{distance}{time}[/tex]
In one revolution, distance travelled is circumference of circular track.
If radius of circular track is r , then distance travelled in one revolution is, = 2πr
So, 11 revolutions = 11(2πr) = 22πr
Time taken = 20 second
So, tangential velocity = 22πr/20 = (11/10)πr meter per second.
Learn more:
https://brainly.com/question/14401457
A 50 kg circus worker stands on a merry go round platform. If the worker's acceleration is 2.5 m/s2, what is her centripetal force?
F = ma
= 50kg × 2.5 m/s²
= 125 N
Answer : 125N
Explanation :
F = Force (N)
m = mass (kg)
a = acceleration (m/s²)
I need help with the questions when it says what is the topic and rest
Voltage has been described as similar to the water in the water pipes in your home. What other analogy can you think of that is similar to voltage?
You go to the store and buy 3 apples. Each apple has a mass of 4.66 grams. What is the total mass of apples you bought.
Remember the difference between a counted and a measured number.
NEEP HELP!
Taking Finals
its 13.98. it's simple multiplication 3* 4.66= 13.98
Need help can someone tell what each circuit is
Answer:
In geometry, parallel lines are lines in a plane which do not meet; that is, two straight lines in a plane that do not intersect at any point are said to be parallel. Colloquially, curves that do not touch each other or intersect and keep a fixed minimum distance are said to be parallel.
In a series circuit, the current that flows through each of the components is the same, and the voltage across the circuit is the sum of the individual voltage drops across each component. ... In a series circuit, every device must function for the circuit to be complete.
In a series circuit, all components are connected end-to-end, forming a single path for current flow. In a parallel circuit, all components are connected across each other, forming exactly two sets of electrically common points.
Explanation:
I hope these helps^,^ ^_^
HELPPP MEE!!
A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m. The force of friction between the refrigerator and the floor is 230
N. Calculate the coefficient of friction between the floor & refrigerator.
Answer: The coefficient of friction is 0.35
Explanation:
We can write the friction force as:
F = N*μ
Where N is the normal force between the refrigerator and the ground, as the full weight of the refrigerator is acting on the ground, the normal force will be exactly equal to the weight of the refrigerator, then:
N = 650N
And μ is the coefficient of friction.
And for this case, the force is 230N, then we have:
F = N*μ
230N = 650N*μ
(230N/650N) = μ = 0.35
Notice that the distance did not matter for this calculation.
A plane lands and comes to a complete stop. If the plane covers 200 m and decelerates at 7.5 m/s2 , what was the planes initial velocity as it touched the runway?
Answer:
The initial velocity of the plane is 54.77 m/s
Explanation:
Given;
distance covered by the plane, d = 200 m
deceleration of the plane, a = - 7.5 m/s²
The initial velocity of the plane is given by the following kinematic equation;
v² = u² + 2ad
where;
v is the final velocity of the plane when the plane comes to a complete stop = 0
u is the initial velocity of the plane
0 = u² + 2(-7.5 x 200)
0 = u² - 3000
u² = 3000
u = √3000
u = 54.77 m/s
Therefore, the initial velocity of the plane is 54.77 m/s
A woman can lift barrels a vertical distance of 1 meter or can roll them up a 2-meter long ramp to the same elevation. If she uses the ramp, the applied force required is
Answer:
answer is 1/2 as much force required
Do you think the inner planets should be explored or should the money be spent on other things? Justify your opinion.
Answer:
yes i think that inner planets should be explored because if we ever find new life or are able to live there then i think its worth takeing a risk.
Explanation:
PLEASE HELP ME!!!!!!!!!!!!
Answer:
It is either A or D I think it is A.
Determine the energy lost, due to friction, as an 8000 N car that skids to a stop, if its initial velocity was 12 m/s.
Answer:
58,800Joules
Explanation:
The energy lost is equal to the workdone by the car as it skids.
Workdone = Force * Distance
Given
Force = 8000N
Get the distance using the equation of motion
v² = u² - 2gS
0² = 12² - 2(9.8)S
-12² = - 2(9.8)S
-144 = -19.6S
S = 144/19.6
S = 7.35m
Calculate the required energy
Workdone = 8000 * 7.35
Workdone = 58,800Joules
Hence the energy lost due to friction is 58,800Joules