By what means can the internal energy of a closed system increase?.

A:

The white light is divided into its component hues - red, orange, yellow, green, blue, and violet - as it passes through the prism. Dispersion is the splitting of visible light into its many hues.

B:

Dispersion is the splitting of visible light into its many hues. Each hue is associated with a certain wave frequency, as stated in the Light and Color unit, and different frequencies of light waves bend at different rates while passing through a prism.

C:

The white light is divided into its component hues - red, orange, yellow, green, blue, and violet - as it passes through the prism. Dispersion is the splitting of visible light into its many hues.

D:

The sun and the weather combine to create a rainbow. As it passes from air to denser water, light enters a water droplet, slowing and bending. The light bounces off the interior of the droplet, separating the wavelengths—or colors—that make up the droplet. A rainbow is created as light escapes the droplet.

Answer:

S = θ R      where S is the arc length and θ the arc length in radians

S = 2.5 ft * 4 π^3 rad = 2.5 * 124 = 310 ft       (1 radian = 2.5 ft)

Assuming 4π3 means 4π^3

The Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.

It is defined as the combination of points that and every point has an equal distance from a fixed point ( called the center of a circle).

We have Reagan rides on a playground roundabout with a radius of 2.5 feet.

We know the relation between arc length and radius of the circle:

S = R∅

Here R = 2.5 feet, and central angle ∅ = 4π/3

[tex]\rm S = 2.5\times \frac{4\pi}{3}[/tex]

S = 10.47 feet ≈ 10 feet

Thus, the Reagan travel over an angle of 4π/3radians is 10.47 or 10 feet if the Reagan rides on a playground roundabout with a radius of 2. 5 feet.

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The sampling rate that's given regarding the CPU will produce a rate of 256kps.

The following can be gotten from the question:

Sampling rate = 8KHx

Number of bits = 32

The data rate will be:

= 32 × 8kbps

= 256kps

In conclusion, the sampling rate that's given regarding the CPU will produce a rate of 256kps.

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The sampling rate specified for the CPU will result in a 256kb/s rate.Sampling rate is also known as the sampling frequency.

The number of samples per second collected from a continuous signal to create a discrete or digital signal is referred to as sampling rate or sampling frequency.

The given data in the problem is;

Sampling rate= 100 mhz cpu

Number of  bits=32

The rate of the data is;

[tex]\rm R = 32 \times 8 kb/ s \\\\ \rm R = 256 kb / s \\\\[/tex]

Hence the sampling rate specified for the CPU will result in a 256kb/s rate.

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Answer:

the current is 5.2 Amps

During the collision an impulse is created which due to which is equal to change in momentum.

Mathematically,

[tex]\green{ \underline { \boxed{ \sf{Impulse, F\times t = m (v-u) }}}}[/tex]

where

Now,

[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times (0-30) \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times -30 \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf F = -\frac{25500}{0.4} \\\end{gathered} [/tex]

[tex]\begin{gathered}\\\implies\quad \sf F = -63750 N \\\end{gathered} [/tex]

[tex]\quad\quad\quad\quad\quad\quad[/tex](-ve sign denotes opposite direction)

Therefore, a force of 63750 Newton will act on the car in opposite direction.

The expression, in terms of defined quantities and g is therefore Fu =((mg/2) +2 mp) g

This can be defined as a balance or any of various other instruments or devices for weighing.

The expression in terms of defined quantities and g, for the force that the scale under left pillar shows that Fu =((mg/2) +2 mp) g .

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The expression, in terms of defined quantities and g, for the force that the scale under left pillar is (m(b)/2+2m(d))g.

Equilibrium is the location of the system, in which the system be static does not change its position with respect to time.

The image of the uniform beam which has two pillar is attached below. In this pillar,

The expression, in terms of defined quantities and g, for the force that the scale under left pillar has to be find out.

In the equilibrium position torque in left pillar is zero,

[tex]\tau_{right} =0[/tex]

It can be written as,

[tex]F_L\dfrac{L}{3}=m_bg\dfrac{L}{6}+m_dg\dfrac{2L}{3}[/tex]

[tex]F_L=\left(\dfrac{m_b}{2}+2m_d\right)g[/tex]

Thus, the expression, in terms of defined quantities and g, for the force that the scale under left pillar is (m(b)/2+2m(d))g.

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Answer:

The buoyant force on a submerged object depends upon the volume of the object.

Explanation:

Answer:

Any of those terms can be converted to either of the other terms, so either term is correct. People are accustomed to everyday temperatures in Fahrenheit. The ideal gas law specifies that

P V = N R T     where T is in Kelvin which is Celsius + 273 deg.

The magnitude of the centripetal force on the car is 69.6 N.

This is a force acting on a body in circular path and it is directed to the center around which the body is moving.

To calculate the centripetal force on the car, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the magnitude of the centripetal force on the car is 69.6 N.

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option D

hope it helps...!!!

Answer:

B.

Explanation:

You have to divide.
10.0/20.0 = 0.50

I apologize if it is incorrect-

I hope it helps! Have a great day!

Anygays-

Answer:

B

Explanation:

a=v/t

a=(40m/s)÷(80s)

a=0.5m/s

Hi there!

We can use the work-energy theorem and apply it to this situation.

At the top of the ramp, the ball only has gravitational potential energy, and at the bottom of the ramp, the ball has BOTH translational and rotational kinetic energy.

We must use the following equations:
[tex]GPE = mgh \\KE_T = \frac{1}{2}mv^2\\\\KE_R = \frac{1}{2}I \omega^2[/tex]

m = mass of sphere (kg)
g = acceleration due to gravity (m/s²)

h = height of ramp (m)

v = final velocity (m/s)
I = Moment of Inertia (kgm²)

ω = angular velocity (rad/sec)

Since:
[tex]E_i = E_f\\\\mgh = \frac{1}{2}mv^2 + \frac{1}{2}I\omega ^2[/tex]

In order to make things easier, since the ball is not slipping, we can relate angular velocity to translational velocity:
[tex]\omega = \frac{v}{r}[/tex]

Also, recall the equation for the moment of inertia for a solid sphere:
[tex]I = \frac{2}{5}mr^2[/tex]

We can use these to simply our equation:
[tex]KE_R = \frac{1}{2}(\frac{2}{5}mr^2)(\frac{v}{r})^2 = \frac{1}{5}mv^2[/tex]

Now, we can rewrite the equation and solve for 'v'.

[tex]mgh = \frac{1}{2}mv^2 + \frac{1}{5}mv^2\\\\mgh = \frac{7}{10}mv^2\\\\v = \sqrt{\frac{10gh}{7}} = \sqrt{\frac{10(9.8)(2.2 - 1.87)}{7}} = 2.149\frac{m}{s}[/tex]

a)

We can begin by solving for the time taken for the ball to land on the ground. The ball only has a horizontal velocity, so this is essentially a free-fall situation. Use the rearranged kinematic equation:
[tex]t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2(1.87)}{9.8}} = .6178 s[/tex]

Now, use the following equation to solve for horizontal distance given horizontal velocity and time:
[tex]d_x = v_x t\\\\d_x = 2.149 * .6178 = \boxed{1.328 m}[/tex]

b)
We can use the previously-stated relationship between translational and angular velocity to solve for the angular velocity.

[tex]\omega = \frac{v}{r}[/tex]
It is given that the diameter is 0.14 m, so the radius is 1/2th the diameter, or 0.07 m.

Solve for the angular velocity:
[tex]\omega = \frac{2.149}{0.07} = 30.706 \frac{rad}{sec}}[/tex]

Using the above fall time and dimensional analysis to convert from rad/sec to revolutions, we can solve for the # of revolutions made by the ball:
[tex]\frac{30.706rad}{sec} * .6178 sec * \frac{1 rev}{2\pi rad} = \boxed{3.019 rev}[/tex]

The image distance when a boy holds a toy soldier in front of a concave mirror, with a focal length of 0.45 m. is -0.56 m.

This is the distance between the image formed and the focus when an object is placed in front of a plane mirror.

To calculate the image distance, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1 and solve for the image distance

Hence, The image distance is -0.56 m.

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Answer:

50N

Explanation:

this is because 5×10all over 100 ,0 will cancile 0 remaining 10 ,1 into 10 ,10times ,so 5×10 =50N

The type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.

A parallel circuit has branches that split the current such that just a portion of it passes through each branch.

The voltage or potential difference between each branch of a parallel circuit is the same, but the currents might differ.

A parallel circuit is having more than one path in order to reach it on time he has to take a different path.

Hence the type of circuit does this traffic situation model will be a parallel circuit because there is more than one path.

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Answer:

C) a parallel circuit because there is more than one path

Explanation:

C) a parallel circuit because there is more than one path

The tension does no (zero) work

F· S = W

Since the tension is perpendicular to the direction of motion, and there is no change in S the work done is zero.

Answer:

As Per Provided Information

Mass of carrot 69 grams

Volume of carrot 150 cm³

we have been asked to determine the density of carrot .

Using Formulae

[tex] \bf \: Density = \cfrac{Mass \: of \: carrot}{Volume \: of \: carrot}[/tex]

Substituting the given value and let's solve it to determine the density of carrot.

[tex] \longrightarrow\sf \: Density = \cfrac{69}{150} \\ \\ \\ \longrightarrow\sf \: Density = \cancel\cfrac{69}{150} \\ \\ \\ \longrightarrow\sf \: Density =0.46 \: gm \: {cm}^{ - 3} [/tex]

Therefore,

Answer:

I for a rod about its center is I = M L^2 / 12

A = L (1/2 - 1/3) = L / 6     distance from middle to location L/3

A^2 = L^2 / 36

I = M L^2 (1/12 + 1/36) = M L^2 (4 / 36) = M L^2 / 9

I about given location by parallel axis theorem

Answer:

40n

Explanation:

10×25 all over 100 ,25 into hundred 4 times 10×4 =40n

Answer:

The volume of a gas is dependent on pressure and temperature.

Explanation:

Pressure and temperature affect different gases differently giving varied conclusions to the exact volume of that gas.

:-befrank

The most likely reason for Mrs. Wilson's warning will be the magnet might lose its magnetism.

Magnetism is a component of the larger phenomena of electromagnetic. The most well-known effects occur in ferromagnetic materials,

Which are highly attracted by magnetic fields and maybe magnetized to become permanent magnets, hence creating magnetic fields. It is also feasible to demagnetize a magnet.

We should not drop a magnet on the floor since magnets progressively lose magnetism and grow weak over time if they are not properly preserved.

Hence this is most likely the reason for Mrs. Wilson's warning will be the magnet might lose its magnetism.

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Answer:

The correct answer is A!

Explanation:

~Hope this helps! :)

Answer:

Finance costs (also known as interest fees) aren't added to your account in a set amount like other fees.

OR

A credit card is a payment card that is issued to users to allow them to pay a merchant for products and services depending on their outstanding debt. The card issuer opens a revolving account for the cardholder and provides a line of credit from which the cardholder can borrow money to pay a merchant or get a cash advance. Consumer credit cards and business credit cards are the two types of credit cards available. The majority of the cards are plastic, however, there are a few metals and gemstone-encrusted metal cards.

Explanation:

In series connection the current flow remains constant

Answer:

The units for specific heat can either be joules per gram per degree (J/goC) or calories per gram per degree

Explanation:

Answer:

A

Explanation:

Direct because it's still passes electricity through ir

Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ [/tex]

Where ,

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ [/tex]

[tex] \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ [/tex]

[tex] \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }} [/tex]

Hence :-

[tex] \underline {\rule {210pt} {4pt}} [/tex]

Note :-

Answer:

Question :-

If a Train going with 60 m/s Speed hits the Brakes, and takes 85 sec to stop. What is the Acceleration of the Train ?

Answer :-

Acceleration of Train is 0.70 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Speed of the Train is 60 m/s . Time taken to stop the Train is 85 sec . And, we have been asked to calculate the Acceleration of the Train .

For calculating the Acceleration , we will use the Formula :-

\begin{gathered} \bigstar \: \: \: \boxed { \sf{ \: Acceleration \: = \: \dfrac{v \: - \: u}{t} \: }} \\ \end{gathered}

★

Acceleration=

t

v−u

Where ,

V denotes to Final Velocity .

U denotes to Initial Velocity .

T denotes to Time Taken .

Therefore , by Substituting the given values in the above Formula :-

\begin{gathered} \dag \: \: \: \: \sf{Acceleration \: = \: \dfrac{Final \: Velocity \: - \: Initial \: Velocity}{Time} } \\ \end{gathered}

†Acceleration=

Time

FinalVelocity−InitialVelocity

\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{0 \: - \: 60}{85} } \\ \end{gathered}

⟼Acceleration=

85

0−60

\begin{gathered} \longmapsto \: \: \: \sf{Acceleration \: = \: \dfrac{60}{85} } \\ \end{gathered}

⟼Acceleration=

85

60

\longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 0.70 }}⟼Acceleration = 0.70

Hence :-

Acceleration = 0.70 m/s² .

\underline {\rule {210pt} {4pt}}

Note :-

Kindly Scroll the Screen from Right to Left for Better View .

Answer:

At some point on say, the receiving screen, light emanating from the left side of the slit will be out of phase (a difference of 1/2 wavelengths) from   light coming from the center of the slit.

Thus for every point that is left of the center of the slit, there will be a point on the right side of the slit that is out of phase,

There will be no light on the screen at that particular point and thus there will be a dark fringe there.

That is the basic explanation for the appearance of dark and bright fringes on the receiving screen.