The frequency of light emitted is 24.63 x [tex]10^1^5[/tex] Hz when an electron jumps from the 2nd to the 1st orbit in a hydrogen atom.
According to Bohr, the electrons in the atom's structure are situated around the nucleus at particular energy levels. An electron must either acquire or lose energy as it transitions from one of these energy levels to another. It is known as an absorption when an electron obtains energy and as an emittance when it loses energy. Both processes involve the absorption or emission of a PHOTON energy particle, which in turn causes the absorption or emission of light. Because various elements have varying energies, they each emit or absorb light in varying quantities (wavelengths).
The wavelength or wave number is used to compute the frequency of light emitted.
The frequency of light emitted is inversely proportional to its wavelength.
Given:
Jump from 2nd orbit to 1st orbit
Planck’s constant, h = 6.626 x [tex]10^-^3^4[/tex]
To find:
Frequency of light emitted, υ = ?
Formula:
E = hυ
Calculations:
[tex]E = 13.6 * Z^2( \frac{1}{n_1^2} - \frac{1}{n_2^2} )[/tex]
E = hυ = 13.6 x 1 x [tex](1 - \frac{1}{4})[/tex]
υ x 6.626 x [tex]10^-^3^4[/tex] = 10.2 x 1.6 x [tex]10^-^1^9[/tex]
υ = 24.63 x [tex]10^1^5[/tex] Hz
Result:
The frequency of light emitted is 24.63 x [tex]10^1^5[/tex] Hz.
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A noiseless 4-khz channel is sampled every 1 msec. what is the maximum data rate? how does the maximum data rate change if the channel is noisy, with a signal-to-noise ratio of 30 db?
The correct answer is 9.908 bps.
Maximum data rate according to Nyquist theorem = 2 H log2V bits/sec, where H=4KHZ (or 4000Hz)
No matter how frequently it is sampled, a noiseless channel may transport an infinite quantity of data. Simply send lots of data for each sample. For the 4 kHz channel,
maximum data rate= 2*4000*log2(2) = 8000 bits/sec
Due to more data there will be more channels and having more information will take more time on a channel and thus there will be more channel capacity.
Maximum data rate=H log2(1+S/N) bps
Substituting the values,
Maximum data rate = 2*log2(1+30) => 2*log2(31) [log base 2 of 31 is 4.954]
Therefore, Maximum data rate = 9.908 bps
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How long does it take for a radio message to travel from earth to the moon and back? (see the inside back cover of the textbook for the necessary data.)
Radio communication can travel from Earth to the moon and return in about 2.5 seconds.
This is due to the fact that radio signals move at a speed of roughly 300,000 km/s and that there are 350,000 km between the Earth and the moon. Therefore, the total travel time is 1.25 seconds there and 1.25 seconds back.
The longest electromagnetic spectrum’s wavelengths that are found in radio waves are mostly found at frequencies of 300 gigahertz and below. The wavelength for 300 GHz is 1 mm, while the wavelength for 30 Hz is 10,000 kilometers.
What are radio waves and how do these radio waves work?Radio waves are electromagnetic radiation types that are most commonly used in communication devices like radios, mobile phones, and televisions.
These gadgets are designed to take in radio waves and then transform them into sound waves by causing mechanical movements in the speaker.
How are radio waves produced?Electromagnetic waves are sent and received by the radio equipment in order to operate. An extremely fast-moving electrical current makes up the radio signal.
This field is broadcasted by a transmitter by using an antenna. After this, a receiver picks up the field and then converts it to the audio heard on the radio.
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a ball is thrown upward from the ground with an initial speed of 15.2 m/s; at the same instant, another ball is dropped from a building 10 m high. after how long will the balls be at the same height above the ground? s
The time at which both balls will be at the same height is 0.6 seconds.
The initial speed at which the ball is thrown upward =
15.2 m/s
Height of the building from where another ball is dropped = 19 m
Let the distance travelled by the first ball is d.
d = (10 m - h)
The height of the ball that is falling from a 10 m high building is,
[tex]y _{f} = y _{i} + v _{i} - \frac{1}{2} gt ^{2} [/tex]
[tex](-10 -h) = \frac{1}{2} gt^{2} [/tex]
[tex]h = 10 - \frac{1}{2} gt ^{2} [/tex]
The height of the ball that is thrown upward with 15.2 m/s is,
[tex]y _{f} = y _{i} + v _{i} - \frac{1}{2} gt ^{2} [/tex]
[tex]h = (15.2)t- \frac{1}{2} gt ^{2} [/tex]
The time at which both balls will be at the same height is,
[tex] (15.2)t- \frac{1}{2} gt ^{2} = 10 - \frac{1}{2} gt ^{2}[/tex]
[tex]t = \frac{10}{15.2} [/tex]
t = 0.6 s
Therefore, the time at which both balls will be at the same height is 0.6 seconds.
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As a projectile moves along its trajectory, check all of the following that are true statements.
Question 8 options:
1) As the projectile moves down, its vertical velocity is positive.
2) As the projectile moves up, its acceleration increases.
3)As the projectile moves down, its acceleration remains constant.
4) As the projectile moves up, its vertical velocity remains constant.
5) As the projectile moves up, its vertical velocity decreases.
6) As the projectile moves down, its vertical velocity increases.
7) As the projectile moves down, its vertical velocity decreases.
8) As the projectile moves up, its acceleration remains constant.
9) As the projectile moves down, its vertical velocity is negative.
10) As the projectile moves down, its vertical velocity remains constant.
11) As the projectile moves up, its vertical velocity is negative.
12) As the projectile moves up, its vertical velocity is positive.
13) As the projectile moves up, its vertical velocity increases.
14) As the projectile moves down, its horizontal velocity remains constant.
15) Acceleration changes as the projectile moves.
16) As the projectile moves down, its acceleration decreases.
17) As the projectile moves up, its horizontal velocity remains constant.
As the projectile moves down, its vertical velocity is positive.
As the projectile moves down, its acceleration remains constant.
As the projectile moves up, its vertical velocity decreases.
As the projectile moves down, its vertical velocity increases.
As the projectile moves up, its acceleration remains constant.
As the projectile moves up, its vertical velocity is negative.
As the projectile moves down, its horizontal velocity remains constant.
As the projectile moves up, its horizontal velocity remains constant.
What is projectile motion?
A projectile is any object thrown into space upon which the only acting force is gravity. The primary force acting on a projectile is gravity.
In a projectile motion, acceleration is always constant and acts vertically downward. Also velocity changes during a projectile motion.
The true statements about projectile motion in the given options include;
As the projectile moves down, its vertical velocity is positive.As the projectile moves down, its acceleration remains constant.As the projectile moves up, its vertical velocity decreases.As the projectile moves down, its vertical velocity increases.As the projectile moves up, its acceleration remains constant. As the projectile moves up, its vertical velocity is negative.As the projectile moves down, its horizontal velocity remains constant.As the projectile moves up, its horizontal velocity remains constant.Learn more about projectile motion here: https://brainly.com/question/24216590
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How did the photoelectric effect lead einstein to propose that light is quantized?
The correct answer is Einstein proposed that light must be made up of packets to explain the photoelectric effect (particles). The frequency of a light packet affects how much energy it contains. Whether or not a single photon has enough energy to knock an electron loose determines whether or not a metal will emit electrons.
The kinetic energy of the electrons is precisely proportional to intensity because, according to wave theory, the energy of electromagnetic waves is uniformly distributed over the wavefront and solely depends on the intensity of the input light beam. However, it was discovered through experimentation that the kinetic energy is unrelated to the brightness of the incident light.
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a jogger runs along a straight and level road for a distance of 8.0 km and then runs back to her starting point. the time for this roundtrip is 2.0 h. which one of the following is true and why?
Her average speed is 8.0 km/h, and her average velocity is 0 km/h. The
average velocity of the jogger is zero since net displacement is zero.
What is velocity?Velocity is the directional speed of a thing moving as an indication of its speed of progress prepared as seen from a particular edge of reference and as assessed by a particular standard of time (for instance 60 km/h toward the north). Speed is a urgent thought in kinematics, the piece of dated mechanics that portrays the development of bodies. Velocity is a genuine vector sum; both significance and heading are supposed to describe it. The scalar through and through worth (degree) of speed is called speed, being a perceptive decided unit whose sum is assessed in the SI (decimal norm) as meters each second (m/s or m⋅s−1). If there is a change of speed, heading or both, the thing should go through a speed increment.
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Question 2 (1 point)
A football is punted and flies upward at 19.6 m/s. It is in the air for
Blank 1:
seconds before it lands. (report a whole number)
Answer:
Statement of the given problem,
A ball is thrown vertically upwards at 19.6 m/s. For its complete trip (up and back down to the starting position), what is its average speed?
Let H & T denote the maximum height (in m) of the given ball & the time (in s) required for it to reach there.
Hence from above data we get following kinematic relations,
T = [19.6 m/s - 0 m/s)]/(9.8 m/s^2) [9.8 m/s^2 = gravitational acceleration (assumed)]
or T = 2 (s)
H = (19.6 m/s)*(2 s) - (1/2)*(9.8 m/s^2)*(2 s)^2
or H = 19.6 (m)
Therefore,
assuming vertically upward & downward motions are identical with respect to time & distance covered by the given ball,
the required average speed of the ball during its travel up and back down to the starting position
= (total travel-distance)/(total travel-time)
= 2*(19.6 m)/[2*(2 s)]
= 9.8 m/s [Ans]
two circular plates, each with a radius of 8.22 cm, have equal and opposite charges of magnitude 3.052 μc. calculate the electric field between the two plates. assume that the separation distance is small in comparison to the diameter of the plates. electric field: n/c the plates are slowly pulled apart, doubling the separation distance. again, assume the separation distance remains small in comparison to the diameter of the plates. what changes occur with the electric field between the plates? the electric field decreases by a factor of 2. the electric field stays the same. the electric field increases by a factor of 2. the electric field decreases by a factor of 4. the electric field increases by a factor of 4.
If the separation distance is doubled, then the electric field decreases by a factor of 4.
What is the electric field strength?We know that the electric field strength is known to depend on the magnitude of the charge and the distance of separation. We know that the electric field refers to the region in which the influence of a charge is felt. Recall that a charge is a specie that is positively or negatively charged. The charge on a specie must always be shown by its sign.
We know that the electric field is the region in space where the influence of a charge can be felt. If a charge is placed in the vicinity of another charge, the second charge would experience a force due to the presence of the first charge. This is because the second charge was brought into the electric field of the first charge.
Thus we know that;
E = Kq/r^2
Where;
E = electric field strength
q = magnitude of charge
r = distance of separation
Now;
E = 9.0* 10^9 * 3.052 * 10^-6/(8.22 * 10^-2)^2
E = 4 N/C
Given that the electric filed strength is inversely proportional to the distance of separation, when the distance between the charges is doubled, the electric field decreases by a factor of 4.
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Jose is measuring the size of a box he will be using in a coming experiment. He measures the dimensions of the box as 1.1m x 0.250m x 0.73m. Using the correct number of significant figures, what is the volume of this box?
Answer: 0.20075
Explanation:
The average birth weight of a new born baby is 7 pounds. However, this weight can vary as much as 4.5 pounds. What is an absolute value inequality to describe this situation?
An absolute value inequality to describe this situation will be
| 2.5 ≤ W ≤ 11.5 |
What is Absolute Value ?An absolute value can be a value of any variable which will always be non - negative value.
Given that an average birth weight of a new born baby is 7 pounds. However, this weight can vary as much as 4.5 pounds. This means the weight can be
7 + 4.5 = 11.5
or
7 - 4.5 = 2.5
If W = average birth weight of a new born baby which is 7 pounds
Therefore, an absolute value inequality to describe this situation will be
| 2.5 ≤ W ≤ 11.5 |
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In your own words, explain the similarities and differences between velocity and acceleration?
The rate of change of displacement is known as velocity. The rate at which velocity changes is called acceleration. Due to the fact that it includes both magnitude and direction, velocity is a vector quantity. Acceleration is likewise a vector quantity as it is only the rate of change of velocity.
Speed serves as the baseline for both velocities and acceleration measurements. Speed is a scalar quantity that measures the amount of distance traveled over a period of time. Acceleration and velocity are both vector quantities, which means they both employ magnitudes and a designated direction. The rate of motion of an object is measured by both speed and velocity. The fact that speed is a scalar quantity, nevertheless, means that it can be quantified.
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in a downhill ski race, surprisingly, little advantage is gained by getting a running start. (this is because the initial kinetic energy is small compared with the gain in gravitational potential energy on even small hills.) to demonstrate this, find the final speed for a skier who skies 68.5 m along a 33.0° slope starting from rest. (neglect any friction.)
The final speed of the skier is 27.31 m/s
Calculationsin33° = h/68.5
h= 68.5 x sin 33°
=37.30m
According to Conservation of Energy,
mgh=1/2 m[tex]v^{2}[/tex]
[tex]v^{2}[/tex]= [tex]\sqrt{2gh}[/tex]
[tex]\sqrt{2*10*37.30}[/tex]
=27.31 m/s
What is Gravitational Potential Energy?The energy that is possessed by a body or a particle due to the change in its position while it is present in a gravitational field is called as the Gravitational potential energy or Gravitational Energy.
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Construction workers are building a new skyscraper in a major
city. A crane operator is using a crane to lift a heavy box of
supplies (with a mass of 568 kg) to the top of the building
when the cord suddenly snaps!
The box of supplies free-falls to the ground from a height of
138 m.
How many seconds does it take for the supplies to crash into
the ground below?
Answer:
The time taken for the box of supplies to crash into the ground below is 3.75 s
Data obtained from the questionFrom the question given above, the following data were obtained:
Mass (m) of box supplies = 568 KgHeight (h) = 138 mAcceleration due to gravity (g) = 9.8 m/s²Time (t) =? How to determine the time taken fall to the groundThe time taken for the box of supplies to fall to the ground can be obtained as follow:
h = ½gt²
138 = ½ × 9.8 × t²
138 = 4.9 × t²
Divide both side by 4.9
t² = 138 / 4.9
Take the square root of both side
t = √(138 / 4.9)
t = 3.75 s
Thus, it will take the box of supplies 3.75 s to crash into the ground.
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A physics teacher is desperate to break his students
of a physics misconception. To do this, he drops a
book from a height of 1.4 m. How fast is the book
going when it hits the ground?
If a book is drops from a height of 1.4 m, then the speed with which book hits the ground is 5.2 m/s.
Given,
Initial velocity = 0m/s
Height = h = 1.4m
Acceleration due to gravity = 9.8 m/s2.
This can be calculated by using third equation of motion,
v2 - u2 = 2gh
where,
v is the final velocity
u is the initial velocity
h is the height
and g is the acceleration due to gravity.
By substituting all the values, we get
v2 = 2 × 1.4 × 9.8
v2 = 27.44
v = 5.2 m/s
Thus, we concluded that if a book is drops
from a height of 1.4 m, then the speed with which book hits the ground is 5.2 m/s.
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the driver of the car maintains a constant speed of 20 m/s . determine the angular velocity of the camera tracking the car when θ
The angular velocity is θ" = 0.302rad/s
Given data,
r = 100cos(2θ)
r = -200sin(2θ)θ"
For angular velocity,
[tex]v = \frac{dr}{dt} u^{r} +r\frac{dθ}{dt}[/tex]
[tex]v = \sqrt{\frac{dr}{dt} } ^{2} + \sqrt\frac{rdθ}{dt} ^{2}[/tex]
So, v = 20m/s
[tex]20 = \sqrt{} [-200sin(2θ)θ" + \sqrt{} [100cos(2θ)θ"[/tex][tex]]^{2}[/tex]
[tex]400 = [-200sin(2*15)θ']^{2} + [100cos(2*15)θ']^{2}[/tex]
On solving for angular velocity, we get
θ" = 0.302rad/s
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which of the following best explains why mars' and venus' surface temperatures vary, despite both planets having atmospheres that contain mostly carbon dioxide?
The best explains why mars' and venus' surface temperatures vary, despite both planets having atmospheres that contain mostly carbon dioxide because
Venus has a dense atmosphere that prevents heat from the surface from escaping. Mars's thin atmosphere is unable to hold a lot of heat. Red sand and rocks on Mars' surface reflect heat.
High mountains cover Venus' surface, absorbing heat.
when Venus first fashioned, it maximum probable contained more nitrogen, oxygen, or even water than the early Earth did. The planet had a runaway greenhouse effect, which heated it up and caused its surface water to turn into steam and gas.This became followed by using the absence of a magnetic subject, which both never absolutely evolved or shut down. This intended that the solar wind, which splits water into oxygen and hydrogen, had no way to guard the environment.Venus also lacks plate tectonics, so carbon dioxide is not trapped in rocks that sink again into the hot mantle. those lighter additives were stripped away through sun radiation, giving them sufficient electricity to get away into space, leaving simply the heavier carbon dioxide in the back of.Find out more information about carbon dioxide.
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In what net direction will water diffuse (by osmosis) when the following solutions are brought into contact with each other on different sides of a semipermeable membrane?
When the following solutions are brought into touch with one another on various sides of a semipermeable membrane, the net direction that water would diffuse (via osmosis) is that Water travels through osmosis from low solute concentration areas to high solute concentration areas.
What is osmosis?Osmosis is the naturally occurring diffusion or passage of water or other solvents over a semipermeable membrane (one that prevents the passage of solutes, or dissolved compounds).
German plant physiologist Wilhelm Pfeffer began a systematic study of the crucial biological process in 1877.
What elements determine the net rate and direction of osmosis?Both the pressure gradient and the concentration gradient affect the net direction and rate of osmosis.
What three forms of osmosis are there?Hypertonic, isotonic, and hypotonic are the three osmotic states.
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The combonation of all forces acting on an object
Choices
The combonation of all forces acting on an object is called resultant force.
The difference between the forces that are acting on an object as part of a system is known as the resultant force. For instance, a resultant force of 7N to the right is produced by a 3N force to the left and a 10N force to the right.
The Pythagorean theorem is used to calculate the resultant force when two forces are acting perpendicularly to one another. The formula for the resultant force is FR = F1 + F2 + F3. Where. The three forces that are acting on an object in the same direction are F1, F2, and F3.
Therefore, the combonation of all forces acting on an object is called resultant force.
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A cannonball is fired at an angle of 18.2° above the horizontal at a velocity of 74.3 m/s. What are the horizontal and vertical components of the velocity of the cannonball?
ANSWER: 70.6m/s horizontal 23.2m/s vertical
1. The horizontal component of the velocity is 70.6 m/s
2. The vertical component of the velocity is 23.2 m/s
Data obtained from the questionFrom the question given, the following data were obtained:
Initial velocity (u) = 74.3 m/sAngle of projection (θ) = 18.2°Horizontal component =?Vertical component =?1. How to determine the horizontal component of the velocity Initial velocity (u) = 74.3 m/sAngle of projection (θ) = 18.2°Horizontal component =?Horizontal component = u × Cosθ
Horizontal component = 74.3 × Cos18.2
Horizontal component = 70.6 m/s
2. How to determine the vertical component of the velocity Initial velocity (u) = 74.3 m/sAngle of projection (θ) = 18.2°Vertical component =?Vertical component = u × Sineθ
Vertical component = 74.3 × Sine18.2
Vertical component = 23.2 m/s
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in a thundercloud there may be electric charges of 39.0 c near the top of the cloud and -39.0 c near the bottom of the cloud. these charges are separated by 1.50 km. what is the electric force on the top charge?
The electric force on the top charge is -9.1158 x [tex]10^{5}[/tex]N.
CalculationThe electric force is given by
F=[tex]k_{e}[/tex][tex]\frac{q_{1}q_{2} }{(r_{12})^2 }[/tex] = (8.99 x [tex]10^{9}[/tex] N.[tex]m^{2}/C^{2}[/tex]) [tex]\frac{(+39C)(-39C)}{(1500m)^2}[/tex]
=-9.1158 x [tex]10^{5}[/tex]N
= 9.1158 x [tex]10^{5}[/tex]N downward
What is Coulombs law?The Coulomb’s inverse-square law, that is sometimes known as Coulomb’s law, is a kind of experimental physical principle that measures the force exerted between two electrically charged particles that are considered stationary.
The electric force between two charged objects at rest include electrostatic force and Coulomb force.
Coulomb listed the following characteristics of the electric force for charges in a resting state: Unlike charges attract each other whereas like charges repel one another.
As a result, a positive charge pulls a negative charge toward it whereas two negative charges repel one another. The line between the two charges is where the attraction or repulsion occurs.
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What is the solution to this equation?
X+ 14 = -6
• A. x = -8
• B. x = -20
• C. x=8
• D. x= 20
Answer: It is B
Explanation:
1. x + 14 = -6
2. x + 14 -14 = -6 -14
3. x = -20
4. So, x = -20
After which action would the concentration of a solution remain constant
adding water to the solution
adding solute to the solution
evaporating water from the container
removing solution from the container
Answer: removing solution from the container
Explanation:
Answer: removing solution from the container
Explanation:
You are traveling on an airplane. The velocity of the plane with respect to the air is 120 m/s due east. The velocity of the air with respect to the ground is 43 m/s at an angle of 30° west of due north.
1)What is the speed of the plane with respect to the ground?
The speed of the plane with respect to the ground will be 117.89 meters per second.
In this question, we need to determine the plane's relative speed to the ground because that will move east at 130 meters per second. The wind is blowing roughly in this direction at 30 meters per second and is at an angle of 30 degrees west of north.
Therefore, we need to identify the x and y components of the wind in order to compare these. We know that x will be equal to 30 times the cosine of our angle. Y will equal 30 times the sine of 60 degrees and we obtain a cosine of 60 degrees. Therefore, in this instance, 30 cosine of 60 will result in 15 and 30 sin of 60 will result in 15 square roots of 3 points.
Therefore, if we want to determine the magnitude of the plane with respect to the graph, we must combine our similar forces. To do this, we will need the square root of 130 for the plane, the minus sign because the wind is blowing in the opposite direction in this case, the x minus 15 square, the n plus our y component, 15 square root of 3 square, and the plane itself.
We now know that 3600 seconds equal 1 hour when translated to seconds. Therefore, we are aware that distance equals velocity multiplied by time. We should arrive at 24804 meters if we multiply our speed, which is 117.89 meters per second, by 3600 seconds.
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Find the velocity vector w , if the wind is blowing from the southeast at 20 km/hour. give an exact simplified answer. w =
The velocity vector is 20√2 i - 20√2 j.
When considering motion in two dimensions we use the terms unit vectors i and j.
As shown in the adjoining diagram,
Let the North direction be represented by +j.
Let the South direction be represented by -j.
Let the East direction be represented by +i.
Let the West direction be represented by -i.
We are given, that the wind is blowing from the southeast direction at 20 km/hr.
On resolving its velocity in the south and east directions,
The velocity in vertical direction is 20cos45 -j = -20√2 j.
The velocity is horizontal direction is 20sin45 i = 20√2 i.
Thus, the velocity vector is 20√2 i - 20√2 j.
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a particle undergoes three successive displacements in a plane, as follows: , 4.00 m southwest; then , 5.00 m east; and finally , 6.00 m in a direction 60.0° north of east. choose a coordinate system with the y axis pointing north and the x axis pointing east. what are (a) the x component and (b) the y component of ? what are (c) the x component and (d) the y component of ? what are (e) the x component and (f) the y component of ? next, consider the net displacement of the particle for the three successive displacements. what are (g) the x component, (h) the y component, (i) the magnitude, and (j) the direction of the net displacement? if the particle is to return directly to the starting point, (k) how far and (l) in what direction should it move?
let east is the positive x direction
north is the positive y direction
for the net displacement
d = 4 * (- cos(45) i - j * sin(45)) + 5 i + 6 * (cos(60) i + j * sin(60))
d = 5.17 i + 2.37 j
for the return vector
d = - 5.17 i - 2.37 j
d = sqrt(5.17^2 + 2.37^2) at arctan(2.37/5.17) degree south of west
d = 5.69 m at 24.6 degree south of west
the return vector is 5.69 m at 24.6 degree south of west
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If the mass of a sliding block is tripled while a constant net force is applied, by how much does the acceleration change?.
The correct answer is rate of acceleration will be reduced by 3.
Newton's law states that the force acting on an object is inversely proportional to its rate of acceleration. This means that if an object's mass remains constant, its acceleration will fluctuate in accordance with its applied force, and vice versa.
A vector number called acceleration can be used to describe how quickly an object changes its velocity. If an object is constantly altering its velocity, it is still accelerating.
By Newton's law.
F=ma
The force is F.
m is the object's mass.
A represents acceleration.
The mass will triple if
a'=1/3×F/m
a'=a/3
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During which trial or trials is the magnitude of the average velocity the largest?
Speed is the time rate at which an object is moving along a path
Velocity is the rate of motion, speed, or action.
While Trial B and Trial D do not have the same average velocity, the only difference is the direction! The magnitudes are the same. Neither one is 'larger' than the other, and it is only because of how we chose our axes that Trial B has a positive average velocity while Trial D has a negative average velocity. In Trial C the object does not move, so it has an average velocity of zero. During Trial A the object has a positive average velocity but its magnitude is less than that in Trial B and Trial D.
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Solenoid is wound with 2000 turns per meter when the current is 5.2 a, what is the magnetic field within the solenoid?
The magnetic field within the solenoid is 0.013T
What is Solenoid ?An electromagnet known as a solenoid creates a regulated magnetic field using a helical coil of wire whose length is significantly higher than its diameter. When an electric current is sent through the coil, it may create a consistent magnetic field inside a defined region of space.
A solenoid operates by creating an electromagnetic field surrounding an armature, which is a moving core. The electromagnetic field causes the armature to move, and when it does, it opens and closes valves or switches, converting electrical energy into mechanical motion and force.
The magnetic field within the solenoid can be calculated by the expression given below.
Write the expression for magnetic field within the solenoid.
B = u₀nI
B = 4π * 10⁻⁷ * 2000 * 5.2
= 0.013 T
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Please help I need it
Answer:
Red dots are electrons and the middle thing is nucleus
Explanation:
+1 charge is for protons because they are always positive
-1 charge is for electrons because they are always negative
Nucleus is the centre part of an atom that consists of protons and neutrons.
What height does a frictionless playground slide need so that a 35 kg child reaches the bottom at a speed of 4.7 m/s?
By conservation of energy, the height of the playground slide should be 108.241 meters.
We need to know about the conservation of energy to solve this problem. The energy can not be created or destroyed, the only way is to change to another form. It can be written as
Ei = Ef
where Ei is initial energy and Ef is the final energy
From the question above, we know that
m = 35 kg
v = 4.7 m/s
The playground slide is converting the potential energy from height to kinetic energy. Hence,
Ei = Ef
PE = KE
m . g . h = 1/2 . m . v²
h = 1/2 . g . v²
h = 1/2 . 9.8 . 4.7²
h = 108.241 meters
Hence, the height of playground slide should be 108.241 meters to reach 4.7 m/s of velocity at bottom.
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