Answer:
Given:
[tex] \\ {\tt{A = \left [ \: \begin{array}{ c c c} \: \: \: \: 2 & -3 & - 5 \\ - 1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1& - 3 & - 4\end{array} \: \: \: \right] \: and \: B = \left[\begin{array}{c c c} \: \: \: \: 2 & - 2 & - 4 \\ - 1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & - 2 & - 3\end{array} \right]}}[/tex]
Matrix A is of order 3 × 3 and Matrix B is of order 3 × 3
To Show:
Matrix AB = A , BA = BFormula Used:
[tex]\\ { \rm{ \left[ \begin{array}{c c c} a_{11} & a_{12} & a_{13} \\ a_{21} & a_{22} & a_{23} \\ a_{31} & a_{32} & a_{33}\end{array} \right] \times \left[ \begin{array}{c c c} b_{11} & b_{12} & b_{13} \\ b_{21} & b_{22} & b_{23} \\ b_{31} & b_{32} & b_{33} \end{array} \right] = \: \left[ \begin{array}{c c c} \: \: a_{11}b_{11} + a_{12}b_{21} + a_{13}b_{31} & a_{11}b_{12} + a_{12}b_{22} + a_{13}b_{32} & a_{11}b_{13} + a_{12}b_{23} + a_{13}b_{33} \\ \: \: a_{21}b_{11} + a_{22}b_{21} + a_{23}b_{31} & a_{21}b_{12} + a_{22}b_{22} + a_{23}b_{32}&a_{21}b_{13} + a_{22}b_{23} + a_{23}b_{33} \\ \: \: a_{31}b_{11} + a_{32}b_{21} + a_{33}b_{31}&a_{31}b_{12} + a_{32}b_{22} + a_{33}b_{32} & a_{31}b_{13} + a_{32}b_{23} + a_{33}b_{33}\end{array} \right]}}[/tex]
If A is a matrix of order a×b and B is a matrix of order c×d , then matrix AB exits and is of order a×d , if and only if b = c.
[tex] \: \: [/tex]
If A is a matrix of order a×b and B is a matrix of order c×d , then matrix BA exits and is of order c×b , if and only if d = a.
[tex] \: \: [/tex]
____________________________________________________________________For Matrix AB, a = 3, b = c = 3, d = 3 , thus Matrix AB is of order 3×3
[tex]\\ { \rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = \left[\begin{array}{c c c} \: \: \: \: 2(2)-3(-1)-5(1) & \: \: \: \: 2(-2)-3(3)-5(-2) & \: \: \: \: 2(-4)-3(4)-5(-3) \\ -1(2)+4(-1)+5(1) & -1(-2)+4(3)+5(-2) & -1(-4)+4(4)+5(-3)\\ \: \: \: \: 1(2)-3(-1)-4(1) & \: \: \: \: 1(-2)-3(3)-4(-2) & \: \: \: \: 1(-4)-3(4)-4(-3) \end{array} \right]}}[/tex]
[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 4 + 3 - 5 & \: \: \: -4 -9 + 10 & \: \: -8 - 12 + 15 \\ -2 - 4 + 5 & \: \: \: \: \: \: + 2 + 12 - 10 & \: \: \: \: \: 4 + 16 - 15 \\ \: \: \: \: \: 2 + 3 - 4 & \: \: -2 - 9 + 8 & -4 - 12 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right]}}[/tex]
[tex]\\ {\rm{Matrix \: AB = \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: 5 \\ \: \: \: \: 1 & -3 & -4 \end{array} \right] = Matrix \: A}}[/tex]
Matrix AB = Matrix A____________________________________________________________________For Matrix BA, a = 3, b = c = 3, d = 3 , thus Matrix BA is of order 3 × 3
[tex]\\ {\rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] \times \left[ \begin{array}{c c c} \: \: \: \: 2 & -3 & -5 \\ -1 & \: \: \: \: 4 & \: \: \: \: 5 \\ \: \: \: \: \: 1 & -3 & -4 \end{array} \right]}}= \left[ \begin{array}{c c c} \: \: \: \: \: 2(2) -2(-1) -4(1) & \: \: \: \: 2(-3) -2(4) -4(-3) & \: \: \: \: 2(-5) -2(5) -4(-4) \\ \: -1(2) + 3(-1) + 4(1) & -1(-3) + 3(4) +4(-3) & -1(-5) + 3(5) + 4(-4) \\ \: \: \: \: \: 1(2) -2(-1) -3(1) & \: \: \: \: 1(-3) -2(4) -3(-3) & \: \: \: \: 1(-5) -2(5) -3(-4) \end{array} \right][/tex]
[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 4 + 2 - 4 & \: \: \: -6 -8 + 12 & \: \: -10 - 10 + 16 \\ -2 - 3 + 4 & \: \: \: \: \: \: +3 + 12 - 12 & \: \: \: \: \: + 5 + 15 - 16 \\ \: \: \: \: \: 2 + 2 - 3 & \: -3 -8 +9 & \: \: \: \: \: -5 -10 + 12 \end{array} \right] = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right]}}[/tex]
[tex]\\{ \rm{Matrix \: BA = \left[ \begin{array}{c c c} \: \: \: \: 2 & -2 & -4 \\ -1 & \: \: \: \: 3 & \: \: \: \: 4 \\ \: \: \: \: 1 & -2 & -3 \end{array} \right] = Matrix \: B}}[/tex]
Matrix BA = Matrix B____________________________________________________________________7. Which statement proves that a quadrilateral is a rhombus? A There is no line of symmetry B. All four sides are congruent C. The diagonals bisect each other D. The diagonals are perpendicular
Answer:
B. All four sides are congruent
Step-by-step explanation:
To prove a quadrilateral is equal, prove the four sides to be equalAs the defining feature of a rhombus is that it has 4 equal sidesHow to solve x + y[tex]\frac{dy}{dx}[/tex] = 0
Given that solution goes to (2,0) Neither x nor y can exceed 2
Answer:
The answer is {D}
Step-by-step explanation:
Solve
4x957+8465x563+834
please help i need an answer for my homework
Answer:
the answer should be 477,0457 if x means multiply but if not you are not putting the equation in a correct way
Answer:
4770457
you just need to calculate them
Find the area of the parallelograms below. 21m 33m 21m
Answer:
a. 693²
b. 148.2 yd²
Step-by-step explanation:
The area of a parallelogram is the product of its base length and the height measured perpendicular to that base.
__
a.A = bh = (21 m)(33 m) = 693 m²
__
b.A = bh = (19 yd)(7.8 yd) = 148.2 yd²
What is the mean , median
What is 45% of 69/3???
Answer:
10.35
Step-by-step explanation:
69/3 = 23
45% of 23 = 10.35
15 POINTS ANSWER FAST!
A rectangle PQRS and square LMNO are drawn side by side. The length SR of the rectangle is labeled as 14 inches, and the width QR is labeled as 7 inches. The side LM of the square is labeled as 7 inches.
Anna says that the length of diagonal SQ is two times the length of diagonal OM.
Is Anna correct? Justify your answer and show all your work. Your work should state the theorem you used to find the lengths of the diagonals.
. There is 40% decresed in price on a sale. It is futher decresed by 5% find the total decreased percentage
Let x be the original price of the object.
After the 40% discount, the price of the object now becomes;
x-0.4x=0.6x
0.6x is our new price after the first discount.
Now if we want to find the price after the second discount, (5%)
That would come off to be;
0.6x-0.6(0.05)x=0.6x-0.03x=0.57x
Our last price is 0.57x
If you notice, there was a 43% discount in total, as it goes to 57% of its original price.
This is very non intuitive for some people, as they may think there will be a 45% discount.
What is the value of X?
Sin 55° = cos X.
Enter your answer in the box.
Answer:
x = 35°
Step-by-step explanation:
sin x = cos (90° - x)
sin 55° = cos (90° - 55°)
sin 55° = cos 35°
x = 35°
Allen was making trail mix, but he only wanted to make of the recipe. If the whole recipe called for of a cup of peanuts, how many cups will he need to make of the recipe? Choose the model that matches the situation.
It can be inferred that the amount of nuts that Allen requires depends on the amount of the recipe that he wants to make.
How many cups of nuts does Allen require to make the recipe?According to the information provided, one serving of the recipe calls for one cup of nuts. According to this, it can be inferred that to make a smaller or larger portion of the recipe, this amount must be divided or multiplied.
For example, if Allen calls for making two servings of the recipe, he would use two cups of nuts, while if he calls for making a half serving, he would use half a cup of nuts.
Note: The question is missing because there is some missing information. However I can answer it based on my general prior knowledge.
Learn more about recipes in: https://brainly.com/question/1320828
Answer:
1/6
Step-by-step explanation:
Answer the question 3523+4353
Answer:
7,876
Step-by-step explanation:
brainliest please
How many lines pass
through two points?
A. infinite
B. 1
C. zero
D. 2
Answer:
1
Step-by-step explanation:
Only 1 line can pass through two points.
Three DVDs and four CDs cost $92. Two DVDs and three CDs cost
$65. Find the cost of each tape and CD.
Answer:
DVD: $16
CD: $11
Step-by-step explanation:
These two linear equations can represent the system of equations where x equals the cost of a DVD and y equals the cost of a CD:
3x+4y=92
2x+3y=65
When graphed, the solution is at (16,11).
Therefore, one DVD costs $16 and one CD costs $11.
Mr. and Mrs. Williams hope to send their daughter to college in twelve years. How much money should they invest now at an interest rate of 8.5% per year,
compounded continuously, in order to be able to contribute $9000 to her education?
[tex]~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$9000\\ P=\textit{original amount deposited}\\ r=rate\to 8.5\%\to \frac{8.5}{100}\dotfill &0.085\\ t=years\dotfill &12 \end{cases} \\\\\\ 9000=Pe^{0.085\cdot 12}\implies 9000Pe^{1.02}\implies \cfrac{9000}{e^{1.02}}=P\implies 3245.35\approx P[/tex]
This semicircle has a radius of 8cm . What is the area of this figure?
Answer:
100.48 cm² (Option 2)⠀
Step-by-step explanation:
⠀
We know,
[tex]{\longrightarrow \qquad \boldsymbol{\pmb{Area_{(semicircle)} = \dfrac{1}{2}( \pi {r}^{2} ) }}}[/tex]
⠀
Where,
r is the radius of the semicircle. Here, the radius is 8 cm .We will take the value of π as 3.14 .⠀
Now, Substituting the values in the formula :
⠀
[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it \dfrac{1}{2} \times 3.14 \times ({8})^{2} }}}[/tex]
[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it \dfrac{1}{ \cancel2} \times 3.14 \times \cancel{64} }}}[/tex]
⠀
[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it {1} \times 3.14 \times 32 }}}[/tex]
⠀
[tex]{\longrightarrow \qquad \rm{{Area_{(semicircle)} = \it {1} \times 100.48 }}}[/tex]
⠀
[tex]{\longrightarrow \qquad \boldsymbol{ \pmb{Area_{(semicircle)} \approx \it 100.48 }}}[/tex]
⠀
Therefore,
The area of the semicircle is 100.48 cm² approximately .Answer:
100.48 cm² ( option 2 )
Step-by-step explanation:
Given:-
Radius of semicircle :- 8cmTo find:-
Area of the figureSolution:-
Area of semi-circle :-
[tex] \frac{1}{2} \pi \: r {}^{2} [/tex]
1/2 × 3.14 × 8²
[tex]100.48 \: cm {}^{2} [/tex]
Triangle J K L is shown. Angle J K L is a right angle. An altitude is drawn from point K to point M on side L J to form a right angle. The length of K M is 6 and the length of M J is 3.
What is the length of line segment LJ?
9 units
12 units
15 units
18 units
Answer:
I think 9 units is the correct answer
Answer:
its 15 units
Step-by-step explanation:
momma told me it was right
Which of the following statements about area is not true?
A. Area is the total space within the outside edges of a two-dimensional object.
B. Area can be found by counting the number of unit squares that fill a space.
C. Area is the total distance around the outside of a shape.
D. Area is used to help describe the dimensions of a shape.
Answer:
C. Area is the total distance around the outside of a shape.
Step-by-step explanation:
Answer:
Area is the total distance around the outside of a shape, Would be correct.
Step-by-step explanation:
help please .and thank u :)
Answer:
5/8
Step-by-step explanation:
because 1 minus 3/8 is 5/8
If an article is sold for rs 99000 after discount of 10％ on marked price and adding 10％ of Value added tax VAT find marked price
Answer:
100000 rupees
Step-by-step explanation:
x × 0.90 × 1.10 = 99000x = 100000geometry. find RN. pls help!!
Apply Thales theorem
[tex]\\ \rm\rightarrowtail \dfrac{MR}{RN}=\dfrac{MQ}{QP}[/tex]
[tex]\\ \rm\rightarrowtail \dfrac{10}{RN}=\dfrac{8}{5}[/tex]
[tex]\\ \rm\rightarrowtail 8RN=50[/tex]
[tex]\\ \rm\rightarrowtail RN=50/8[/tex]
[tex]\\ \rm\rightarrowtail RN=6.25[/tex]
Answer:
RN = 6.25
Step-by-step explanation:
Triangle Proportionality Theorem: If a line parallel to one side of a triangle intersects the other two sides, then it divides the two sides proportionally.
Therefore,
MQ : MP = MR : MN
⇒ 8 : (8 + 5) = 10 : (10 + RN)
⇒ 8 : 13 = 10 : (10 + RN)
⇒ [tex]\sf\dfrac{8}{13}=\dfrac{10}{10+RN}[/tex]
Cross multiply and solve:
⇒ 8(10 + RN) = 10 × 13
⇒ 80 + 8RN = 130
⇒ 8RN = 130 - 80
⇒ 8RN = 50
⇒ RN = 50 ÷ 8
⇒ RN = 6.25
need help please again
Answer:
7 hours
Step-by-step explanation:
d=rt
d is distance
r is speed
t is time
here we need to find (t)
so d/r is t
so t is 455/65
t is 7
what is the area of this object?
Answer: no idea
Step-by-step explanation:
sketch the graph of y=2x^2-3x-4
1. quadrilateral with 4 right angles
Answer:
Square
Step-by-step explanation:
What is the area of the parallelogram QRST?
[tex]\text{Area of parallelogram QRST} = QR \times TU = 20 ~in \times 18~in =360 in^2[/tex]
Write the standard equation of the circle with center (-10,-5) that passes through the point (-7.5)
The standard form of the equation of the circle is
(Type an equation. Simplify your answer.)
Answer:
(x +10)² +(y +5)² = 9
Step-by-step explanation:
The standard form equation for a circle with center (h, k) and radius r is ...
(x -h)² +(y -k)² = r²
The radius of your circle is the distance between the center and the given point. Those points lie on the same horizontal line, so the radius is the difference of their x-coordinates:
r = (-7) -(-10) = 3
The equation of the circle is ...
(x -(-10))² +(y -(-5))² = 3²
(x +10)² +(y +5)² = 9
A bag contains 9 green marbles, 6 purple marbles, 4 red marbles, 10 blue marbles, and 7 orange marbles. One marble is randomly selected from the bag.
What is the probability that the marble selected is blue or purple?
The probability that the marble selected is blue or purple is the likelihhood of selecting a blue or purple marble
The probability that the marble selected is blue or purple is 0.444
How to determine the probability?From the question, we have:
Green = 9
Purple = 6
Red = 4
Blue = 10
Orange = 7
So, the total number of marbles is:
Total = 9 + 6 + 4 + 10 + 7
Total = 36
The number of blue or purple marbles is;
Blue or purple = 10 + 6
Blue or purple = 16
So, the probability that the marble selected is blue or purple
p = 16/36
Evaluate
p = 0.444
Hence, the probability that the marble selected is blue or purple is 0.444
Read more about probability at:
https://brainly.com/question/251701
ach of the
7
cats in a pet store was weighed. Here are their weights (in pounds).
5, 9, 9, 16, 12, 15, 6
Find the median and mean weights of these cats.
If necessary, round your answers to the nearest tenth.
Answer: 10.3, 9
Step-by-step explanation:
FIND THE MISSING LENGTH.
Answer:
x = 9
x+7 = 16
Step-by-step explanation:
The triangles in this geometry are similar, so the ratios of corresponding sides are proportional.
long side/short side = (x+7)/12 = 12/x
x(x +7) = 12²
x +7x -144 = 0 . . . . . subtract 144 to put in standard form
(x +16)(x -9) = 0 . . . . factor
x = 9 . . . . . . only the positive solution is useful here
The missing lengths are ...
x = DC = 9x+7 = DA = 1699x78
123x56
98x172
38x900
Answer:
99x78=7722
123x56=6888
98x172=16856
900x38=34200
Step-by-step explanation: