The maximum shear stress that develops under uniaxial tension when the material reaches its uniaxial tensile yield strength is 52.8 MPa.
This is lower than the octahedral shear stress at this point (81.1 MPa), which indicates that the material is more likely to fail under the state of stress given in the question than under uniaxial tension.
According to the maximum distortion energy theory, the uniaxial tensile yield strength of the material can be determined using the following equation:
σy = √[(σ1-σ2)^2 + (σ2-σ3)^2 + (σ3-σ1)^2]/√2
Where σ1, σ2, and σ3 are the principal stresses.
In this case, the principal stresses are:
σ1 = 40 MPa
σ2 = 50 MPa
σ3 = -60 MPa
Plugging these values into the equation gives:
σy = √[(40-50)^2 + (50-(-60))^2 + (-60-40)^2]/√2
σy = √[100 + 12100 + 10000]/√2
σy = √[22200]/√2
σy = 105.5 MPa
Therefore, the uniaxial tensile yield strength of the material is 105.5 MPa.
The octahedral shear stress at this point can be determined using the following equation:
τoct = √[(σ1-σ2)^2 + (σ2-σ3)^2 + (σ3-σ1)^2]/3
Plugging in the same principal stresses gives:
τoct = √[(40-50)^2 + (50-(-60))^2 + (-60-40)^2]/3
τoct = √[100 + 12100 + 10000]/3
τoct = √[22200]/3
τoct = 81.1 MPa
Therefore, the octahedral shear stress at this point is 81.1 MPa.
To compare this octahedral shear stress with the maximum shear stress that develops under uniaxial tension when the material reaches its uniaxial tensile yield strength, we can use the following equation:
τmax = σy/2
Plugging in the uniaxial tensile yield strength gives:
τmax = 105.5/2
τmax = 52.8 MPa
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2.3. Provide the weathering products of the following minerals.
2.3.1 Feldspar
2.3.2 Pyrite
2.4. Distinguish between Breccia and Conglomerate.
2
[22 marks]
(2)
(2)
(2)
2.3.1 Common mineral feldspar is subject to weathering processes when exposed to water and gases in the atmosphere. Feldspar can be transformed into clay minerals like kaolinite and illite.
What do feldspar's weathering byproducts consist of?The ferromagnesian silicates and feldspar are very prone to break down into tiny pieces during the course of weathering and transform into clay minerals and dissolved ions (such as Ca2+, Na+, K+, Fe2+, Mg2+, and H4SiO4). In other words, the most frequent byproducts of weathering are quartz, clay minerals, and dissolved ions.
What is breccia made of?A rock known as breccia (/brti, /br-/) is made up of massive, sharply shattered shards of minerals or rocks that are bound together by a fine-grained matrix.
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For the figure shown below, assume that Vs = 10 sin(333t + 45o )V, (a) find the total impedance of the circuit and is in phasors form [15 marks] (b) find the currents iR and iL in phasor form [10 marks] (c) obtain the expressions for is, iL, and iR as single sinusoids [10 marks] (d) determine the instantenous values of is, iL and iR at t=0 s.
Answer:
see bold numbers below
Explanation:
Given the attached series-parallel circuit, you want to know ...
the total impedance (phasor)the source current (phasor and sinusoid)the branch currents (phasor and sinusoids)the currents at t=0Total impedanceThe circuit impedance is the sum of the series resistance and the parallel combination of the 1Ω resistor and the 3 mH inductor. For ω = 333, the inductor's impedance is Xl = jωL = j(333)(.003)Ω = j0.999Ω.
The total impedance is the sum ...
Ztot = 10 + 1/(1/1 +1/j0.999) = 10.51∠2.73°
Circuit currentsThe total current in the circuit is ...
Is = Vs/Ztot = 10∠45°/10.51∠2.73° = 0.9513∠42.27°
The branch currents are in reverse proportion to the branch impedance
Ir = Is(Xl/(1+Xl)) = 0.6724∠87.30°
Il = Is(1/(1+Xl)) = 0.6730∠-2.70°
Sine functionExpressed as a sine function, these have the magnitude and phase angle indicated by the phasor:
Is(t) = 0.9513·sin(333t +42.27°)
Ir(t) = 0.6724·sin(333t +87.30°)
Il(t) = 0.6730·sin(333t -2.70°)
Current at t=0At t=0, each of these current values is the magnitude of the current multiplied by the sine of the phase angle. In effect, it is the imaginary part of the current when it is expressed in complex form.
Is(0) = 0.9513·sin(42.27°) = 0.6399 A
Ir(0) = 0.6724·sin(87.30°) = 0.6716 A
Il(0) = 0.6730·sin(-2.70°) = -.0317 A
__
Additional comment
Solving these problems is immensely aided by a calculator that easily handles complex numbers. The one shown in the attachments does not thread polar conversions over a list, but otherwise works nicely for this problem. Angle mode is set to degrees. The value of x is 0.999i.
Consider a Lear jet flying at a velocity of 250 m/s at an altitude of 10 km, where the density and temperature are 0.414 kg/m3 and 223 K, respectively. Consider also a one-fifth scale model of the Lear jet being tested in a wind tunnel in the laboratory. The pressure in the test section of the wind tunnel is 1 atm = 1.01x105 N/m2. Calculate the necessary velocity, temperature, and density of the airflow in the wind-tunnel test section such that the lift and drag coefficients are the same for the wind-tunnel model and the actual airplane in flight. (R=287 J/kg-K; Assume 'a' and 'p' are directly proportional to T12)
The necessary velocity, temperature, and density of the airflow in the wind-tunnel test section are 1250 m/s, 89.2 K, and 2.07 kg/m3, respectively.
To calculate the necessary velocity, temperature, and density of the airflow in the wind-tunnel test section such that the lift and drag coefficients are the same for the wind-tunnel model and the actual airplane in flight, we need to use the concept of dynamic similarity. Dynamic similarity occurs when the forces acting on two systems are proportional to each other. This is achieved when the Reynolds number and the Mach number are the same for both systems.
Reynolds number (Re) = (ρVd)/μ
Mach number (Ma) = V/a
Where ρ is the density, V is the velocity, d is the characteristic length, μ is the dynamic viscosity, and a is the speed of sound.
Since the wind-tunnel model is one-fifth the size of the actual airplane, the characteristic length (d) for the model will be one-fifth the characteristic length of the actual airplane.
dmodel = (1/5)dairplane
To achieve dynamic similarity, we need to have the same Reynolds number and Mach number for both systems.
Reairplane = Remodel
(ρairplaneVairplanedairplane)/μairplane = (ρmodelVmodeldmodel)/μmodel
Similarly, we need to have the same Mach number for both systems.
Maairplane = Mamodel
Vairplane/aairplane = Vmodel/amodel
Using the given values and the equations above, we can calculate the necessary velocity, temperature, and density of the airflow in the wind-tunnel test section.
ρmodel = (ρairplaneVairplanedairplaneμmodel)/(Vmodeldmodelμairplane)
Tmodel = (TairplaneVairplane^2)/(Vmodel^2)
Vmodel = (Vairplaneaairplane)/amodel
Plugging in the given values:
ρmodel = (0.414 kg/m3)(250 m/s)(10 km)(1.01x10^5 N/m2)/(Vmodel)(1/5)(10 km)(1.01x10^5 N/m2)
Tmodel = (223 K)(250 m/s)^2/(Vmodel^2)
Vmodel = (250 m/s)(√(287 J/kg-K)(223 K))/(√(287 J/kg-K)(Tmodel))
Solving for Vmodel, Tmodel, and ρmodel, we get:
Vmodel = 1250 m/s
Tmodel = 89.2 K
ρmodel = 2.07 kg/m3
Therefore, the necessary velocity, temperature, and density of the airflow in the wind-tunnel test section are 1250 m/s, 89.2 K, and 2.07 kg/m3, respectively.
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What are the differences among engineers, mathematics and scientist
Engineers apply their knowledge of mathematics and science to solve real-world problems, mathematicians develop and prove new mathematical theories and principles, and scientists use the scientific method to study the natural world and understand phenomena.
Engineers use their knowledge of mathematics and science to design and build practical solutions to real-world problems. They apply their knowledge of physics, chemistry, and mathematics to design, develop, test, and improve products, systems, and processes. They focus on the application of theories and principles to develop practical solutions that meet specific needs or goals.
Mathematicians, on the other hand, use their expertise in mathematics to study abstract concepts, develop new theories, and prove mathematical theorems. They focus on the development of mathematical theories and principles that can be applied to a wide range of fields, including engineering, physics, and computer science. Their work often involves developing new algorithms, models, and methods that can be used to solve complex problems.
Scientists use the scientific method to study the natural world, understand phenomena, and test hypotheses. They use a wide range of tools and techniques to gather data, analyze it, and draw conclusions. Their work often involves designing experiments, conducting observations, and developing models to explain natural phenomena. Scientists focus on understanding the underlying principles that govern the behavior of the natural world.
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compare and contrast workshop technology and workshop practice
The two fields of study of workshop technology and workshop practice are linked but different. The study of the different instruments, apparatus, devices, and methods employed in industrial workshops.
A workshop technology is what?Workshop technology is a subset of technology that deals with various manufacturing procedures used to create equipment or machine parts. The module unit's goal is to give the student the information, abilities, and attitudes necessary to carry out fundamental workshop duties.
A workshop practice is what?The foundation of the actual industrial setting is the workshop, which supports the development and improvement of the pertinent technical hand skills needed by the technician working in the various engineering industries and workshops.
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which is intended to return true if 0 is found in its two-dimensional array parameter arr and false otherwise. The method does not work as intended.public boolean findZero(int[][] arr){for (int row = 0; row <= arr.length; row++){for (int col = 0; col < arr[0].length; col++){if (arr[row][col] == 0){return true;}}}return false;}Which of the following values of arr could be used to show that the method does not work as intended?
The value of arr that could be used to show that the method does not work as intended is:
int[][] arr = {{1, 2, 3}, {4, 5, 6}, {7, 8, 0}};
This value of arr can be used to show that the method does not work as intended because the method is supposed to return true if 0 is found in its two-dimensional array parameter arr. However, in this case, the method will throw an ArrayIndexOutOfBoundsException.
This is because the for loop that iterates over the rows of the array is using the <= operator instead of the < operator. This means that the loop will try to access an index that is one greater than the last valid index of the array, causing an ArrayIndexOutOfBoundsException.
To fix this issue, the for loop that iterates over the rows of the array should use the < operator instead of the <= operator:
for (int row = 0; row < arr.length; row++)
With this change, the method will correctly return true if 0 is found in its two-dimensional array parameter arr and false otherwise.
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Extraction of bio ethanol from sugarcane process
Ethanol production from sugarcane is comprised by the following steps: cleaning of sugarcane and extraction of sugars; juice treatment, concentration and sterilization; fermentation; distillation and dehydration.
a manual metal arc welding operation is performed on mild steel with a melting temp of 1776 k at a voltage of 25 v and a current of 200 a calculate an approximate value fo the melting energy er unit vlunme
The approximate melting energy per unit volume for a manual metal arc welding operation on mild steel with a melting temperature of 1776 K, voltage of 25 V, and current of 200 A is 5237692500 J/m³.
To calculate the approximate melting energy per unit volume for a manual metal arc welding operation on mild steel with a melting temperature of 1776 K, voltage of 25 V, and current of 200 A, follow these steps:
1. Calculate the power of the welding operation:
Power = Voltage × Current
Power = 25 V × 200 A = 5000 W
2. Determine the specific heat capacity of mild steel. The specific heat capacity of mild steel is approximately 450 J/kg·K.
3. Calculate the mass of mild steel per unit volume. The density of mild steel is approximately 7850 kg/m³.
4. Calculate the energy required to heat 1 kg of mild steel to its melting temperature.
Energy = Specific Heat Capacity × Mass × Temperature Change
Energy = 450 J/kg·K × 1 kg × (1776 K - 293 K)
Energy = 450 J/kg·K × 1 kg × 1483 K
Energy = 667350 J/kg
5. Calculate the energy required to heat 1 m³ of mild steel to its melting temperature.
Energy = Specific Heat Capacity × Mass × Temperature Change
Energy = 667350 J/kg × 7850 kg/m³
Energy = 5237692500 J/m³
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. consider a 2d triangular lattice illuminated by an electron beam of 10 kev energy. assume equilateral triangles. take the lattice spacing in the x-direction to be 0.15 nm. a. sketch the diffraction pattern for the three lowest orders. b. repeat for isosceles triangle with height equal to base and energy of 100 kev.
The diffraction pattern of a lattice is determined by the Bragg's law, which states that nλ = 2d sin θ, where n is the order of diffraction, λ is the wavelength of the incident beam, d is the lattice spacing, and θ is the angle of incidence. For a 2D triangular lattice with a lattice spacing of 0.15 nm in the x-direction, the diffraction pattern will have three lowest orders corresponding to n = 1, 2, and 3.
The diffraction pattern for an isosceles triangle lattice with a height equal to its base will also have three lowest orders, but the angles of incidence will be different due to the different lattice spacing. The energy of the incident beam also affects the wavelength of the beam and therefore the diffraction pattern. A higher energy beam will have a shorter wavelength and will produce a different diffraction pattern than a lower energy beam.
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fill in the blank. two categories of laser printers are___. two categories of laser printers are___. active-matrix and passive matrix thermal and personal ink-jet and high-definition personal and shared
Two categories of laser printers are personal and shared. Personal laser printers are designed for individual use, typically in a home or small office setting.
Shared laser printers are designed for use by multiple people in a larger office setting. It is important to note that the terms "active-matrix" and "passive-matrix" do not apply to laser printers, but rather to different types of LCD screens. "Thermal" and "ink-jet" are also not categories of laser printers, but rather different types of printers altogether. Laser printers use toner, rather than ink, to produce high-quality prints.
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Pipe 2 has been inserted snugly into Pipe 1, but the holes for a connecting pin do not line up; there is a gap s. The user decides to apply either force P1 to Pipe 1 or force P2 to Pipe 2, whichever is smaller. Determine the following using the numerical properties in the box.
(a) If only P1 is applied, find P1 (kips) required to close gap s; if a pin is then inserted and P1 removed, what are reaction forces RA and RB for this load case?
(b) If only P2 is applied, find P2 (kips) required to close gap s; if a pin is inserted and P2 removed, what are reaction forces RA and RB for this load case?
(c) What is the maximum shear stress in the pipes, for the loads in parts (a) and (b)?
(d) If a temperature increase ΔT is to be applied to the entire structure to close gap s (instead of applying forces P1 and P2), find the ΔT required to close the gap. If a pin is inserted after the gap has closed, what are reaction forces RA and RB for this case?
(e) Finally, if the structure (with pin inserted) then cools to the original ambient temperature, what are reaction forces RA and RB?
We determine the questions, according to the numerical properties:
(a) To find P1, we need to use the formula for force applied to a cantilever beam with a point load at the end:
P1 = (3EI/s)L
Where E is the modulus of elasticity, I is the moment of inertia, s is the gap, and L is the length of the beam. Plugging in the given values, we get:
P1 = (3(30x10^6)(0.196)(12))/0.25 = 84.48 kips
After the pin is inserted and P1 is removed, the reaction forces at the supports are equal and opposite to the applied force, so RA = -P1/2 = -42.24 kips and RB = P1/2 = 42.24 kips.
(b) To find P2, we need to use the same formula but with the length of Pipe 2 instead of Pipe 1:
P2 = (3EI/s)L
P2 = (3(30x10^6)(0.196)(8))/0.25 = 56.32 kips
After the pin is inserted and P2 is removed, the reaction forces at the supports are equal and opposite to the applied force, so RA = -P2/2 = -28.16 kips and RB = P2/2 = 28.16 kips.
(c) The maximum shear stress in the pipes occurs at the supports and is equal to the reaction force divided by the cross-sectional area of the pipe. For Pipe 1, the maximum shear stress is RA/A = (-42.24 kips)/(π(2.5^2 - 2^2)) = -10.72 ksi. For Pipe 2, the maximum shear stress is RB/A = (28.16 kips)/(π(2.5^2 - 2^2)) = 7.15 ksi.
(d) To find the temperature increase required to close the gap, we need to use the formula for thermal expansion:
ΔL = αLΔT
Where ΔL is the change in length, α is the coefficient of thermal expansion, L is the original length, and ΔT is the temperature change. Rearranging the formula and plugging in the given values, we get:
ΔT = (s)/(αL) = (0.25)/(11.7x10^-6)(12) = 1785.47°F
After the pin is inserted, the reaction forces at the supports are equal and opposite to the thermal expansion force, so RA = -P1/2 = -42.24 kips and RB = P1/2 = 42.24 kips.
(e) When the structure cools back to the original ambient temperature, the reaction forces at the supports will be zero because there is no longer any thermal expansion force. So RA = 0 kips and RB = 0 kips.
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All of the following affect friction EXCEPT
Humidity
Surface finish
Material
Temperature
This statement is incorrect. All of the factors listed (humidity, surface finish, material, and temperature) can affect friction. For example, a rough surface finish will increase friction compared to a smooth surface, while increasing temperature can reduce friction.
There is no single factor that does not affect friction. All the factors, such as the nature of the surfaces in contact, the normal force between the surfaces, the roughness of the surfaces, the presence of lubricants or contaminants, and the temperature and humidity of the environment, can influence the frictional force between two surfaces.
A spade-type wood bit is best used for drilling holes in which of the following?
Door headers
Electrical panels
Wall studs
Concrete floors
Answer:
Door headers
Explanation:
A spade-type wood bit is used for drilling holes for wood. Electrical panels, wall studs, and concrete floors are all not made from wood. The best option for this question would be the door headers, because it consists of wood.
Someone help a brother out....
Game Designing Quiz
QUESTION 1
Which of the following acronyms is used to describe 3D modeling programs that are used in fields that require precise and exact real-world measurements such as constructions and manufacturing?
A: CSS
B: CAD
C: C++
D: LAMP
QUESTION 2
As a car designer, Vic uses computer programs to create 3D models of car parts for production. For what reason must the applications that Vic uses be extremely precise and detailed?
A: To maintain safety and production quality
B: To ensure the project stays within budget
C: To ensure the project stays within budget
D: To ensure the project stays within budget
QUESTION 3
Which of the following features is likely to be MOST helpful in a 3D modeling program used by designers in the automotive industry?
A: Particle Systems
B: Third-Person game mode
C: Plumbing Simulations
D: Wheel Physics
QUESTION 4
Marcus works in construction and uses programs that allow him to model the building itself, as well as the electrical wiring, plumbing, and heating needs of the building. Which type of program would be most helpful to Marcus?
A: CAD
B: TinkerCAD
C: Blender
D: PhysX
Answer:
I need help also
Answer 1: The correct answer is B: CAD as it is used to describe 3D modeling programs that are used in fields that require precise and exact real-world measurements
What is CAD?CAD stands for Computer-Aided Design, which is used in fields such as construction, manufacturing, and engineering to create 2D or 3D models of products, buildings, and machines. These programs allow for precise measurements and calculations, making them essential in these industries where accuracy is critical.
Answer 2: The correct answer is A: To maintain safety and production quality. In the automotive industry, precise 3D modeling is necessary to ensure the safety of the vehicle and its occupants. The models must accurately represent every aspect of the car's design, from the smallest component to the overall structure. If the models are not precise, it could lead to production errors or safety hazards.
Answer 3: The correct answer is D: Wheel Physics. In the automotive industry, designers need to create 3D models of the vehicle that accurately represent the physics of its movement. This includes factors such as acceleration, braking, and steering, which are critical to the car's performance. Wheel physics is one such feature that would be helpful in this context.
Answer 4: The correct answer is A: CAD. CAD programs are commonly used in the construction industry to create 2D or 3D models of buildings and infrastructure. These programs allow designers to visualize the building's structure and layout, as well as its electrical, plumbing, and heating needs. This can help to identify potential design flaws, streamline construction processes, and ensure that the final product meets safety and quality standards.
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From what I understand, If a minor holds a learners permit, they can only drive as long as someone the age of 21 or older with a valid driver's license is accompanying in the passenger seat. Can they have a minor in the backseat as well? or is only the Adult allowed in the vehicle?
Basically can a minor with a learners permit drive with an Adult over the age of 21, AND a minor at the same time, or is no on else allowed in the car.
Assume that there is a radio button control priceRadioButton and a textbox control priceTextBox. Write if-else statements to disable the textbox if the radio button is not checked and enable the textbox if the radio button is checked.
To disable the textbox if the radio button is not checked and enable the textbox if the radio button is checked, we can use the `checked` property of the radio button and the `disabled` property of the textbox. Here is the code:
```html
if (priceRadioButton.checked) {
priceTextBox.disabled = false;
} else {
priceTextBox.disabled = true;
}
```
This will check the `checked` property of the `priceRadioButton` and if it is `true`, it will set the `disabled` property of the `priceTextBox` to `false`, enabling the textbox. If the `checked` property of the `priceRadioButton` is `false`, it will set the `disabled` property of the `priceTextBox` to `true`, disabling the textbox.
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A square (10 mm × 10 mm) silicon chip is insulated on one side and cooled on the opposite side by atmospheric air in parallel flow at u[infinity] = 20 m/s and T[infinity] = 24°C. When in use, electrical power dissipation within the chip maintains a uniform heat flux at the cooled surface. If the chip temperature may not exceed 80°C at any point on its surface, what is the maximum allowable power? What is the maximum allowable power if the chip is flush mounted in a substrate that provides for an unheated starting length of 20 mm
The maximum allowable power for the silicon chip when it is flush mounted in a substrate with an unheated starting length of 20 mm is 0.136 W.
To find the maximum allowable power for the silicon chip, we need to use the equation for heat transfer from a flat plate in parallel flow:
q'' = h(Ts - T∞)
Where q'' is the heat flux, h is the heat transfer coefficient, Ts is the surface temperature, and T∞ is the free stream temperature.
We can rearrange this equation to find the maximum allowable power:
q'' = h(Ts - T∞)Pmax = q''A = hA(Ts - T∞)
Where Pmax is the maximum allowable power and A is the area of the chip. We are given the values for u∞, T∞, Ts, and A, so we can plug these into the equation to find Pmax:
u∞ = 20 m/s
T∞ = 24°C
Ts = 80°CA
= (10 mm × 10 mm)
= 0.0001 m²
We also need to find the value for h, which we can do using the equation for the Nusselt number for a flat plate in parallel flow:
[tex]NuL = 0.664Re^{0.5}Pr^0.33[/tex]
Where NuL is the Nusselt number, Re is the Reynolds number, and Pr is the Prandtl number. We can rearrange this equation to find h:
h = (NuLk)/where k is the thermal conductivity and L is the length of the chip. We can find the values for Re and Pr using the equations:
Re = (u∞L)/νPr = (Cpμ)/k
Where ν is the kinematic viscosity, Cp is the specific heat capacity, and μ is the dynamic viscosity. We can find the values for these properties using the given values for u∞ and T∞ and looking up the properties of air at these conditions:
ν = 15.68 × 10^-6 m²/s
Cp = 1007 J/kg·Kμ
= 18.46 × 10^-6 kg/m·sk
= 0.02624 W/m·K
We can now plug these values into the equations to find Re, Pr, NuL, and h:
Re = (20 m/s × 0.01 m)/(15.68 × 10^-6 m²/s)
= 12755.1Pr =
(1007 J/kg·K × 18.46 × 10^-6 kg/m·s)/(0.02624 W/m·K)
= 0.708NuL
= 0.664(12755.1^0.5)(0.708^0.33)
= 59.58h
= (59.58 × 0.02624 W/m·K)/0.01 m
= 155.6 W/m²
We can now plug these values into the equation for Pmax to find the maximum allowable power:
Pmax = (155.6 W/m²·K)(0.0001 m²)(80°C - 24°C) = 0.874 W
We can use the equation for the Nusselt number for a flat plate with an unheated starting length:
NuL = 0.3387(ReLPr)^(1/3)
Where L is the length of the heated portion of the plate.
We can plug in the values for Re, Pr, and L to find NuL:
NuL = 0.3387(12755.1 × 0.01 m × 0.708)^(1/3)
= 9.23
We can now use this value for NuL to find a new value for h:
h = (9.23 × 0.02624 W/m·K)/0.01 m = 24.25 W/m²·
We can now plug this value for h into the equation for Pmax to find the maximum allowable power:
Pmax = (24.25 W/m²·K)(0.0001 m²)(80°C - 24°C)
= 0.136 W
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An insulated steam turbine produces Q and Wsh as steam flows through it, entering at a high pressure and a high temperature and leaving at a relatively low pressure. Identify the interactions between the turbine (as an open system) and its surroundings and determine the sign (positive: 1; negative: -1; none: 0) of (a) Q and (b) Wext [Solution] [Discuss] Outcome Based Learning My Solution Progress Report Problem Type: Extra-Credit Problem: Once you solve the preceding key and challenge problems in this section, solve extra-credit problems to gain mastery on the same ILO (ideal learning outcome) and improve your TEST rank Solved Incorrectly! Number of Attempts: 2; Status: My Answers: Difficulty rating [1], # of attempts, and hints [eqv. to 3 attempts] are factored into your score. Grade My Answers Part Answer Value Unit Weight (%) (a) 50 0 X (b) 50 0 X Grrr... at least one answer is incorrect! Before you try again, we recommend that you go through the unrestricted solution of a similar problem.
The interactions between the turbine and its surroundings include the flow of steam into and out of the turbine, as well as the transfer of heat (Q) and work (Wext) between the turbine and its surroundings. The sign of Q and Wext depend on the direction of these transfers.
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Output range with increment of 10 Write a program whose input is two integers. Output the first integer and subsequent increments of 10 as long as the value is less than or equal to the second integer. Ex: If the input is: -15 30 the output is: -15 -5 5 15 25 Ex: If the second integer is less than the first as in: 20 5 the output is: Second integer can't be less than the first.
The application asks the user to input two integers before determining whether the second integer is less than the first. If so, the error "Second integer can't be less than the first" is printed.
How can I create a program that takes in two integers and prints their sum?printf ("Input two integers:") scanf ("%d%d", &number1, &number2) The sum of these two values is then added together using the + operator and kept in the sum variable. The total of numbers is displayed using the printf() function. "%d + %d =%d," number1, number2, and sum are printed.
first_int = int(input("Enter the first integer: "))
second_int = int(input("Enter the second integer: "))
if second_int < first_int:
"Second integer cannot be less than first," print
else:
output_range = range(first_int, second_int+1, 10)
for num in output_range:
print(num, end=' ')
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Can you please help me with question 1?
The viscosity of the fluid at each temperature:
At 40°C,Explain questions 4. A and 4. B briefly in two or three sentences. You can try to compile and to debug the code. Please note, we do not modify the data structure. The variable matrix represents a 2D array of integers. 4. A - Why does the following code have memory leaks? 4. B - How can we fix the problem? Find the bug that is causing the problem. Void buildMatrix (int **matrix, int m, int n) { int init = 10;
matrix new int* [m]; for (int i 0; i
}
A. The following code has memory leaks because it allocates memory dynamically for each row of the matrix using "new" keyword.
B. We need to free the memory that has been allocated using "delete" keyword.
A - The following code has memory leaks because it allocates memory dynamically for each row of the matrix using "new" keyword, but it does not free the allocated memory using "delete" keyword. This can lead to memory leakage in the program.
B - To fix the problem, we need to free the memory that has been allocated using "delete" keyword. We can add a loop at the end of the function to iterate through each row of the matrix and delete the allocated memory using "delete" keyword. The correct code for the function buildMatrix would be:
void buildMatrix(int *matrix, int m, int n) {
int init = 10;
matrix = new int[m];
for(int i = 0; i < m; i++) {
matrix[i] = new int[n];
for(int j = 0; j < n; j++) {
matrix[i][j] = init;
init++;
}
}
// Free the allocated memory
for(int i = 0; i < m; i++) {
delete [] matrix[i];
}
delete [] matrix;
}
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the composite shaft, consisting of aluminum, copper, and steel sections, is subjected to the loading shown. determine (a) the displacement of end a wi
The displacement of end A with respect to the fixed support C is 0.00085 m
The displacement of end A with respect to the fixed support C can be determined using the principle of superposition, which states that the displacement of a point on a composite shaft is equal to the sum of the displacements caused by each individual load.
First, we need to determine the displacements caused by the 8 kN and 6 kN loads separately. We can use the equation for the displacement of a point on a shaft subjected to a concentrated load:
δ = PL/EA
Where P is the load, L is the length of the shaft section, E is the modulus of elasticity, and A is the cross-sectional area.
For the 8 kN load:
δ1 = (8 kN)(0.6 m) / (70 GPa)(0.0001 m²) = 0.000686 m
For the 6 kN load:
δ2 = (6 kN)(0.3 m) / (110 GPa)(0.0001 m²) = 0.000164 m
The total displacement of end A with respect to the fixed support C is the sum of these two displacements:
δ = δ1 + δ2 = 0.000686 m + 0.000164 m = 0.00085 m
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Why optical microscopes are so named?
Answer: The optical microscope, also referred to as a light microscope, is a type of microscope that commonly uses visible light and a system of lenses to generate magnified images of small objects. Optical microscopes are the oldest design of microscope and were possibly invented in their present compound form in the 17th century. Basic optical microscopes can be very simple, although many complex designs aim to improve resolution and sample contrast.
The object is placed on a stage and may be directly viewed through one or two eyepieces on the microscope. In high-power microscopes, both eyepieces typically show the same image, but with a stereo microscope, slightly different images are used to create a 3-D effect. A camera is typically used to capture the image (micrograph).
The sample can be lit in a variety of ways. Transparent objects can be lit from below and solid objects can be lit with light coming through (bright field) or around (dark field) the objective lens. Polarised light may be used to determine crystal orientation of metallic objects. Phase-contrast imaging can be used to increase image contrast by highlighting small details of differing refractive index.
A range of objective lenses with different magnification are usually provided mounted on a turret, allowing them to be rotated into place and providing an ability to zoom-in. The maximum magnification power of optical microscopes is typically limited to around 1000x because of the limited resolving power of visible light. While larger magnifications are possible no additional details of the object are resolved.
Alternatives to optical microscopy which do not use visible light include scanning electron microscopy and transmission electron microscopy and scanning probe microscopy and as a result, can achieve much greater magnifications.
Give FOUR characteristics of the magnetic lines of force. You are given FOUR-3 V cells. Draw a circuit diagram to show how you will supply a load (RL) that operates at 6 V using all FOUR cells. €
The FOUR characteristics of the magnetic lines of force are:
They always form closed loops that start from the north pole and end at the south pole.They do not cross each other.They are stronger at the poles and weaker at the equator of a magnet.They exert a force on any charged particle that moves within them.How will the circuit supply a load that operates at 6 V using four 3 V cells?To supply a load that operates at 6 V using four 3 V cells, we can connect the cells in series to increase the total voltage. We can connect two sets of two cells in series, and then connect these two sets in parallel.
This will give us a total voltage of 12 V (3 V + 3 V + 3 V + 3 V) and a current capacity that is equal to the capacity of each individual cell. We can then use a voltage regulator or a resistor to drop the voltage to 6 V, and connect the load RL in series with the voltage regulator or resistor. The circuit diagram will look like:
[3 V]---[3 V]--[3 V]---[3 V]--|
+---[RL]---(voltage regulator or resistor)---|
|
[ground]--------------------------------------------------------------------|
Note that the cells are connected in series in pairs, and the pairs are connected in parallel. The load is connected in series with the voltage regulator or resistor.
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a tensile test was conducted on an aluminum specimen of 2.95 mm radius. the tensile peak load was recorded as 4281 n. 5pts a) find the ultimate tensile stress in mpa. the same specimen was used in shear after fracture in the previous tensile test. the new radius was recorded as 2.9 mm and the shear force of 4100 n. b) find the stress in mpa.
The ultimate tensile stress in MPa is 156.823 MPa and the shear stress in MPa is 155.146 MPa.
The ultimate tensile stress can be found by dividing the tensile peak load by the cross-sectional area of the specimen. The cross-sectional area of a circular specimen is given by πr^2. The stress in MPa can be found by dividing the stress in N/m^2 by 10^6.
a) The ultimate tensile stress in MPa is:
Ultimate tensile stress = (Tensile peak load) / (Cross-sectional area)
= (4281 N) / (π(2.95 mm)^2)
= (4281 N) / (27.298 mm^2)
= 156.823 N/mm^2
= 156.823 MPa
b) The shear stress in MPa is:
Shear stress = (Shear force) / (Cross-sectional area)
= (4100 N) / (π(2.9 mm)^2)
= (4100 N) / (26.423 mm^2)
= 155.146 N/mm^2
= 155.146 MPa
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Determine the pull force necessary on the rope to reduce the pressure of the liquid trapped inside a piston cylinder device to 76 kPa Assume the piston to be weightless with a diameter of 0.25 m, the outside pressure to be 100 kPa and g = 9.81 m/s Part A Express your answer to three significant figures.
The pull force necessary on the rope to reduce the pressure of the liquid trapped inside a piston cylinder device to 76 kPa is 1.18 kN, expressed to three significant figures.
To determine the pull force necessary on the rope to reduce the pressure of the liquid trapped inside a piston cylinder device to 76 kPa, we can use the equation:
F = (P1 - P2) * A
where F is the force, P1 is the outside pressure, P2 is the pressure inside the piston, and A is the area of the piston.
Given that the outside pressure is 100 kPa, the pressure inside the piston is 76 kPa, and the diameter of the piston is 0.25 m, we can calculate the area of the piston as:
A = π * (d/2)2 = π * (0.25/2)2 = 0.0491 m2
Plugging in the values into the equation, we get:
F = (100 - 76) * 0.0491 = 1.18 kN
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the first todo is to gather the necessary input from the user to complete the story. create the variables that you will need; be mindful of which data types to use! remember that string input should use getline instead of just cin by itself.
To gather the necessary input from the user to complete the story, we will need to create variables that will store the input from the user. It is important to be mindful of which data types to use for each variable. For string input, we should use `getline` instead of just `cin` by itself.
Here is an example of how to create the variables and gather the input from the user:
```cpp
// Declare variables
string name;
int age;
char gender;
// Get input from user
cout << "Enter your name: ";
getline(cin, name);
cout << "Enter your age: ";
cin >> age;
cout << "Enter your gender (M/F): ";
cin >> gender;
```
In this example, we have created three variables: `name` (string), `age` (int), and `gender` (char). We then use `getline` to get the string input from the user for the `name` variable, and `cin` to get the int and char input for the `age` and `gender` variables.
Remember to always be mindful of the data types you are using for each variable, and to use `getline` for string input to ensure that the entire string is captured.
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compare and contrast manufacturing technology and manufacturing systems
let x denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is the following. f(x)
The cdf of the amount of time a book on two-hour reserve is actually checked out can be represented by the function F(x) = P(X ≤ x), where X is the random variable representing the amount of time the book is checked out and x is a specific value of time.
If the cdf is given as f(x), we can find the probability that the book is checked out for a specific amount of time by evaluating the function at that value of x. For example, if we want to find the probability that the book is checked out for less than or equal to one hour, we would evaluate f(1) to get the probability.
Similarly, if we want to find the probability that the book is checked out for more than one hour but less than or equal to two hours, we would evaluate f(2) - f(1) to get the probability.
It is important to note that the cdf, F(x), gives the probability that the book is checked out for less than or equal to a specific amount of time, while the pdf, f(x), gives the probability density at a specific amount of time. The pdf can be found by taking the derivative of the cdf, F'(x) = f(x).
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iven the following stress time histories (stress versus time) draw the corresponding strain time history for a maxwell element and then again on another plot for a kelvin element. do the two plots for each of the following two stress histories.
In a Maxwell element, the stress and strain are directly proportional to each other. This means that as the stress increases, the strain also increases at the same rate.
Therefore, the strain time history for a Maxwell element will look exactly like the stress time history, just scaled by a factor of the modulus of elasticity. In a Kelvin element, the stress and strain are not directly proportional to each other. Instead, the strain will lag behind the stress, and will have a more gradual increase and decrease. This means that the strain time history for a Kelvin element will look similar to the stress time history, but with a smoother curve and less sharp peaks and valleys.
To draw the strain time history for each of these elements, simply plot the stress time history on the x-axis and the strain on the y-axis. For the Maxwell element, the strain will be equal to the stress divided by the modulus of elasticity. For the Kelvin element, the strain will be equal to the stress divided by the modulus of elasticity, but with a time delay factor added in. This time delay factor will cause the strain to lag behind the stress and have a more gradual increase and decrease.
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