Answer:
Explanation:
The number of mole of the hydrogen sample at 27 C and 750 mmHg pressure is:
[tex]n=\frac{PV}{RT}=\frac{(0.9898\times 10^{5})(5\times 10^{-3})}{(8.314)(27+273)}\approx 0.0198[/tex] mol
This number of mole will be the same although we change the pressure and temperature. For STP (Temperature = 0 C = 273 K, and Pressure = 760 mmHg = 76 cmHg = 1 Bar = 1.01 x [tex]10^{5}[/tex] Pa):
[tex]P'V'=nRT' \rightarrow V'=\frac{nRT'}{P'}=\frac{0.0198(8.314)(273)}{1.01\times 10^{5}}\approx 44.49 \times 10^{-5}[/tex] in [tex]m^{3}[/tex]. But in L, we find that V' = 0.4449 L
The sound intensity at a distance of 19 m from a noisy generator is measured to be 0.24 W/m2. What is the sound intensity at a distance of 27 m from the generator
Answer:
0.1111 W/m²
Explanation:
If all other parameters are constant, sound intensity is inversely proportional to the square of the distance of the sound. That is,
I ∝ (1/r²)
I = k/r²
Since k can be the constant of proportionality. k = Ir²
We can write this relation as
I₁ × r₁² = I₂ × r₂²
I₁ = 0.25 W/m²
r₁ = 16 m
I₂ = ?
r₂ = 24 m
0.25 × 16² = I₂ × 24²
I₂ = (0.25 × 16²)/24²
I₂ = 0.1111 W/m²
how did we compensate for friction
A child is pulling a wagon at a constant speed. What is the net force acting on the wagon?
The net force acting on the wagon when it is pulled at a constant speed is zero (0).
What is net force?The net force acting on an object is the sum of all the forces acting on the object. The net force on an object is determined by applying Newton's second law of motion as shown below;
F(net) = ma
where;
m is the mass of the objecta is the acceleration of the objectConstant speedConstant speed is a situation where the speed of the object does not change with time.
At constant speed, the acceleration of the object is zero (0).
F(net) = m x 0
F(net) = 0
Thus, the net force acting on the wagon when it is pulled at a constant speed is zero (0).
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2. How long would it take a car to reach 50 m/s if they accelerated at a constant rate of 5.44
m/s?? Assume the car begins at rest.
9.19 seconds (2dp)
Given:
v = 50m/s
u = 0 m/s
a = 5.44 m/s
t = ?
Substitute values into the equation v = u + at
v = u + at
50 = 0 + 5.44 x t
t = 50/5.44
t = 9.19 seconds
Time is in seconds as the velocity and acceleration are in metres per second instead of kilometres per hour
A point charge q = -6.0nC is located at the origin. The electric field (in N/C) vector at the point x = -8.0m, y= +1.5m is?
Answer:
Explanation:
The position between point charge q to x = -8.0 m and y = 1.5 m is:
[tex]r=\sqrt{x^{2}+y^{2}}=\sqrt{(-8)^{2}+(1.5)^{2}}=\sqrt{66.25}\approx 8.13[/tex] meter
Then the magnitude of the electric field E is:
[tex]E=\frac{1}{4\pi\epsilon_{o}} \frac{q}{r^{2}}=(9\times 10^{9}) \frac{6.0\times 10^{-9}}{66.25}\approx 0.81 N/C[/tex]
For the vector of E:
[tex]\tan\theta=\frac{1.5}{-8}=-0.1875 \rightarrow \theta = -10.61^{0}[/tex]
[tex]E_{x}=E\cos (-10.16)=(0.81)(0.984)=0.79704 N/C[/tex]
[tex]E_{y}=E\sin\theta = -0.81(0.184)=-0.14904 N/C[/tex]
[tex]\vec{E}=0.79704\hat{i}-0.14904\hat{j}[/tex] in N/C
The Earth's history is shaped by different geological processes over a wide range of space and time.
For example, in the late 1900s, a crater was discovered near the town of Wetumpka, Alabama. Scientists found shocked quartz in the core samples collected from the crater. Shocked quartz occurs as a result of intense metamorphism (change in the structure of rocks).
Which of the following geological processes is most likely responsible for the formation of the crater?
A. erosion by water
B. tectonic plate movement
C. volcanic eruption
D. meteor impact
meteor impact this ecological processes is most likely responsible for the formation of the crater. Hence option D is correct.
What is meteor impact ?A collision between celestial objects that has quantifiable effects is called an impact event. The most frequent impact events involve asteroids, comets, or meteoroids and have little impact. However, impact events have been shown to occur often in planetary systems and have physical repercussions. However, many surface impacts are reduced by atmospheres through atmospheric entry when massive objects strike terrestrial planets like the Earth. Nonetheless, there may be major physical and biospheric effects. The majority of the solid objects in the Solar System are covered with impact craters and structures, which provide the best empirical evidence for their frequency and size. Since the birth of the Solar System, impact events appear to have had a substantial impact on how the Solar System has changed. Significant impact events have impacted Earth's history and have been linked
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A town is considering building a biodiesel power plant that would burn a biomass to generate electricity. Which of the following correctly lists an advantage and a disadvantage of this project?
Advantage: it could get rid of some unwanted waste. Disadvantage it would emit pollution into the air.
Advantage: it reduces dependence on fossil fuels. Disadvantage: it would create new jobs for the area.
Advantage: it produces carbon dioxide, Disadvantage: building the power plant would be expensive.
Advantage: it would use existing garbage and agricultural waste. Disadvantage: there is no way to use the power created.
Answer:
Advantage: it could get rid of some unwanted waste. Disadvantage: it would emit pollution into the air.
The measured value of mass M in an experiment is M = 0.743 ± 0.005kg. The error in 2M is
Select one:
dM
3dM
2.5 dM
2dM
Given the measured value of mass M in the experiment the error in 2M is ; dM
Given data :
Measured value of mass M = ( 0.743 ± 0.005 ) kg
The error in 2M in the measured valueThe error in 2M in the measured value M = 0.743 ± 0.005 kg is dM while the error in M² will be 2dM
Hence we can conclude that the measured value of mass M in the experiment the error in 2M is ; dM.
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A charged particle moves in a uniform magnetic field of 0.775 T
with a period of 4.79×10−6 s.
Find its charge-to-mass ratio ||/.
Hi there!
Recall that a charge that enters a magnetic field while moving experiences a magnetic force that causes it to enter a state of uniform circular motion.
We know the following (For a point charge):
[tex]F_B = qv B[/tex]
q = Charge (C)
v = velocity (m/s)
B = Magnetic field (T)
Fb= Magnetic force (N)
The equation for centripetal force:
[tex]F_c = \frac{mv^2}{r}[/tex]
m = mass (kg)
v = velocity (m/s)
r = radius (m)
Fc = Centripetal force (N)
Since we are given its period:
[tex]T = \frac{2\pi r}{v}\\\\v = \frac{2\pi r}{T}[/tex]
Plug this expression into the above equations. Since the magnetic force equals the centripetal force, set them equal to each other and simplify.
[tex]q\frac{2\pi r}{T} B = \frac{m}{r}(\frac{2\pi r}{T})^2[/tex]
Cancel out the expression.
[tex]qB = \frac{m}{r} (\frac{2\pi r}{T})[/tex]
Cancel out 'r'.
[tex]qB = \frac{2\pi m}{T}[/tex]
Now, we can simplify as necessary to find a value for 'q' over 'm':
[tex]\frac{q}{m} = \frac{2\pi }{TB} = \frac{2\pi }{(4.79 \times 10^{-6})(0.775)} = \boxed{1692554.464}[/tex]
Thus, the charge is 1.693 ×10⁶ times larger than its mass.
The Empire State Building is about 381m high. If you threw a baseball downward at 25 m/s from the top of the building how fast would it be traveling just before it landed?
Answer:
Explanation:
You can use that [tex]v = v_{o}+gt[/tex] or [tex]v^{2}=v_{o}^{2}+2gh=(25)^{2}+(2)(10)(381)=8245 \rightarrow v \approx 90.8[/tex] m/s.
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A 0.14 kg baseball is dropped from rest. It has a momentum of 0.78 kg.m/s just before it lands on the ground. For what amount of time was the ball in the air?
Answer:
0.568
Explanation:
velocity = -9.8 (t) + Vo
Vo= 0 so v= 9.8(t)
Momentum = mass x velocity
v * 0.14 kg = 0.78 kg m/s
v = 5.571 m/sec
v= 9.8(t) , so substituting v we get , 5.571 = 9.8 * t
t = 5.571/9.8 = 0.568 seconds
What is the best definition of
work?
A. net force equals zero
B. a force exerted over a distance
a
C. pair of forces where one is of greater strength
Answer:
Work is best defined as a force exerted on a body to cause it move over a certain distance.
work=force×displacement×cosθ
Explanation:
Which of the following examples of the streets Newton second law of motion
Explanation:
Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.
find the half life of a radioactive natural which decays to 6.25% of it's original no. of nuclei in 50 seconds.
Answer:
After 1 decay it has .9375 of its value left
.9375^n = 1/2
What is the value of n (number of decays)
n log .9375 = -.693
n =.693 / .0645 = 10.7
After 10.7 periods of 50 sec it will have 1/2 of its original nuclei left
1/2 life = 10.7 * 50 sec = 537 sec = 8.95 min
Which points in the diagram would have Spring tides?
points A and B
points A and C
points C and D
points B and D
Answer:
If the Sun was on the left side of the diagram it would be points A and C
Explanation:
Spring tides are when the Sun, Earth, and Moon are aligned together. Neap tides occur when when the Sun, Earth, and Moon are forming a right angle.
Answer:
C and d mark mwe braliest
Explanation:
Is water Wet or Dry. Explain.
Explanation:
Water is wet, in the sense of being a liquid which flows easily, because its viscosity is low, which is because its molecules are rather loosely joined together.
Answer:
Liquid water is not itself wet, but can make other solid materials wet.
Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.
Whether an object is wet or dry depends on a balance between cohesive and adhesive forces. Cohesive forces are attractive forces within the liquid that cause the molecules in the liquid to prefer to stick together. Cohesive forces are also responsible for surface tension. If the cohesive forces are very strong, then the liquid molecules really like to stay close together and they won't spread out on the surface of an object very much. On the contrary, adhesive forces are the attractive forces between the liquid and the surface of the material. If the adhesive forces are strong, then the liquid will try and spread out onto the surface as much as possible. So how wet a surface is depends on the balance between these two forces. If the adhesive forces (liquid-solid) are bigger than the cohesive forces (liquid-liquid), we say the material becomes wet, and the liquid tends to spread out to maximize contact with the surface. On the other hand, if the adhesive forces (liquid-solid) are smaller than the cohesive forces (liquid-liquid), we say the material is dry, and the liquid tends to bead-up into a spherical drop and tries to minimize the contact with the surface.
Water actually has pretty high cohesive forces due to hydrogen bonding, and so is not as good at wetting surfaces as some liquids such as acetone or alcohols. However, water does wet certain surfaces like glass for example. Adding detergents can make water better at wetting by lowering the cohesive forces . Water resistant materials such as Gore-tex fabric is made of material that is hydrophobic (water repellent) and so the cohesive forces within the water (liquid-liquid) are much stronger than the adhesive force (liquid-solid) and water tends to bead-up on the outside of the material and you stay dry.
ture or false
A land breeze is when the cooler air over the ocean moves in toward land.
Answer:
False
Explanation:
A land breeze is when air flows from land to water. The question above is describing a sea breeze, which is when cool ocean air blows toward land.
A Rich has been hooked and is puilling on the line as shown in the figure below.
RO
18
If the pole makes an angle of 25° with the horizontal, the distance between the point where the line is attached to the pole and the anglers hand is L. 2.45 m, and the fish
pulls on the line such that the tension in the line is T-166 Nat an angle 35.0 below the horizontal, determine the magnitude (in N.m) of the torque exerted by the fish
about an axis perpendicular to the page and passing through the angler's hand.
Nm
For the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand is mathematically given as
Z = 360.33Nm
What is the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand?
Generally, the equation for the Torque is mathematically given as
Z = force x perpendicular distance
Z = Tcos30° x L
Z = 166(0.886) x 2.45
Z = 360.33Nm
In conclusion s the magnitude in N.m of the torque exerted by the fish about an axis perpendicular to the page and passing through the angler's hand
Z = 360.33Nm
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A body is piloted at a point. A force of 10 N is applied at a distance of 30 cm from the pivot. Find the amount of force about the pivot .
Question :-
A Body is Pivoted at a Point. A Force of 10 N is Applied at a Distance of 30 cm from the Pivot. Find the Amount of Force about the Pivot.Answer :-
Amount of Force is 3 Nm .Explanation :-
As per the provided information in the given question, The Force is given as 10 Newton . The Distance is given as 30 cm [ 0.3 m ] . And, we have been asked to calculate the Amount of Force .
For calculating the Force , we will use the Formula :-
[tex] \bigstar \: \: \: \boxed{ \: \sf {Moment \: of \: Force \: = \: Force \: \times \: Distance} \: } [/tex]
Therefore , by Substituting the given values in the above Formula :-
[tex] \dag \: \: \: \sf {Moment \: of \: Force \: = \: Force \: \times \: Distance} [/tex]
[tex] \longmapsto \: \: \: \sf {Moment \: of \: Force \: = \: 10 \: \times \: 0.3} [/tex]
[tex] \longmapsto \: \: \: \textbf {\textsf {Moment \: of \: Force \: = \: 3}} [/tex]
Hence :-
Amount of Force = 0.3 Nm .[tex] \underline {\rule {185pt}{4pt}} [/tex]
Astronomers often detect stars that are rotating extremely rapidly, known as neutron stars. These stars are believed to have formed in the inner core of a larger star that collapsed, due to its own gravitation, to a star of a very small radius and very high density. Before collapse suppose the core of such star is the size of our Sun (R=7 x 10km) with mass 2.0 times as great as the Sun, and is rotating at a speed of 1 revolution every 10 days. If it were to undergo gravitational collapse to a neutron star of radius 10 km, what would its rotational speed be? Assume the star is a uniform solid sphere at all times. (1 = MR2) a
Based on law of conservation of angular momentum, the rotational speed of the star is equal to 6,000 rev/s.
Given the following data:
Radius of Sun = 7 × 10⁵ km.Mass of star = 2 Mass of Sun (M = 2M).Radius of star = 10 km.Time = 10 days.How to calculate the rotational speed.First of all, we would determine the initial angular speed of the neutron star as follows:
[tex]\omega_i = \frac{1 \;Rev}{10 \;days} \\\\\omega_i = \frac{1 \;Rev}{10 \times 24 \times 60 \times 60}\\\\\omega_i = 1.157 \times 10^{-6}\;rev/s[/tex]
Mathematically, the moment of inertia of a uniform solid sphere is given by this formula:
[tex]I=\frac{2}{5} mr^2[/tex]
Where:
I is the moment of inertia.m is the mass.r is the radius.In order to determine the rotational speed of this neutron star, we would apply the law of conservation of angular momentum:
[tex]L_1 = L_2\\\\I_1\omega_1 = I_2\omega_2\\\\\frac{2}{5} m_1r_1^2 \omega_1 = \frac{2}{5} m_2r_2^2\omega_2\\\\m_1r_1^2 \omega_1 = m_2r_2^2\omega_2\\\\\omega_2 =\frac{r_1^2 \omega_1}{r_2^2}[/tex]
Substituting the given parameters into the formula, we have;
[tex]\omega_2 = \frac{ (7 \times 10^5 )^2 \times 1.157 \times 10^{-6}}{ (10 )^2}\\\\\\\omega_2 = \frac{ (7 \times 10^5 )^2 \times 1.157 \times 10^{-6}}{ 10 0}\\\\\omega_2 =\frac{566,930}{100}[/tex]
Final angular speed = 5,669 ≈ 6,000 rev/s.
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You ride your bike north for 100 m at a constant speed of 5 m/Your acceleration is…
Answer:
our acceleration is 0 because there is a constant speed..
a = final speed - initial speed / time
final speed = initial speed ( since speed is constant)
therefore acceleration is 0
✓ 4.) A certain molecule has an energy-level diagram for its vibrational energy in
which two levels are 0.0141eV apart. Find the wavelength of the emitted
line for the molecule as it falls from one of these levels to the other. [h
6.63 x 10-34 kgm s-?, C = 3 x 108ms-1, lev = 1.602 x 10^-19j
Answer:
Explanation:
You can use [tex]\Delta E=\frac{\hbar c}{\lambda} \rightarrow \lambda =\frac{\hbar c}{E} = \frac{1240 eV.nm}{0.0141 eV} \approx 87943.26[/tex] in nm.
Here the hc = 1240 eV.nm in eV and nanometer unit.
A 3 Hz wave has a wavelength of 0.4 m. Calculate the speed of the wave (in m/s).
The speed of the wave with the given frequency and wavelength is 1.2m/s.
Given the data in the question;
Wavelength of the wave; [tex]\lambda = 0.4m[/tex]Frequency; [tex]f = 3Hz = 3s^{-1}[/tex]Speed of the wave; [tex]v = \ ?[/tex]WavelengthWavelength is the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
It is expressed as;
[tex]\lambda = \frac{v}{f}[/tex]
Where v is velocity/speed and f is frequency.
Now, we can easily get the speed of the wave by substituting our given values into the expression above.
[tex]\lambda = \frac{v}{f} \\\\0.4m = \frac{v}{3s^{-1}}\\ \\v = 0.4m * 3s^{-1}\\\\v = 1.2ms^{-1}\\\\v = 1.2m/s[/tex]
Therefore, the speed of the wave with the given frequency and wavelength is 1.2m/s.
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.. In the reaction 238 92U ---- X + 2 4 He, the particle represented by X is . answer choices . 234 90 Th. 234 92 U. 238 93 Np. 242 94Pu. ... Which conditions are required
My question
• Complete the following reaction:
238 92U = ______ + ________ + 4 2He
…Is this the same question as the answer
Answer:
234 90 +energy
Explanation:
because alpha decrease by 4 2helium
why did the ball move the same distance when it was on the flatbed truck that accelerated 0.2 m/s?
The relative velocity of the ball with respect to the truck is same as that of the truck with respect to the ball at equal time.
What is relative velocity?The relative velocity of an object is the velocity of the object observed with respect to rest frame of another object.
Distance traveled by the objectThe distance traveled by each object is determined from the prouduct of velocity and time of motion.
d = vt
where;
v is velocityt is timeThus, if the ball moved the same distance when it was on the flat bed truck, then the relative velocity of the ball with respect to the truck is same as that of the truck with respect to the ball at equal time.
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Write a letter to an influential person about how and why to take action on climate change.
Take action on climate change has a positive effect on health of organisms and environment.
How and why to take action on climate change?Spread awareness and encourage friends, family and co-workers to reduce carbon pollution, reduce burning of fossil fuels by using electrical vehicle and devices. Always buy sustainable products and avoid the use of plastics.
We have to take action on climate change because it improved health, maintain the population of organism, and reduced inequality. So we can conclude that take action on climate change has a positive effect on health of organisms and environment.
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Two pendula are shown in the figure. Each consists of a solid ball with uniform density and has a mass M. They are each suspended from the ceiling with massless rod as shown in the figure. The ball on the left pendulum is very small. The ball of the right pendulum has radius 1/2 L.
Find the period T of the right pendulum for small displacements in s.
The period (T) of the right pendulum for small displacements in s is equal to 1.49 seconds.
How to calculate the period (T).Mathematically, the time taken by this pendulum to undergo a small displacement is given by this formula:
[tex]T=2\pi \sqrt{\frac{L}{g} }[/tex]
Where:
L is the length.g is the acceleration due to gravity.Scientific data:
Acceleration due to gravity (g) = 9.8 m/s².
Assuming a randomized variable for the length of the rope to be 1.2 meter. Also, we know that the right pendulum has a radius of 1/2L.
1/2L = L/2
L/2 = 1.1/2
L/2 = 0.55 meter.
Substituting the parameters into the formula, we have;
[tex]T=2\times 3.142 \sqrt{\frac{0.55}{9.8} }\\\\T=6.284 \times \sqrt{0.0561} \\\\T=6.284 \times 0.2369[/tex]
T = 1.49 seconds.
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A rocket weighing 220,000 N is taking off from Earth with a total thrust of
500,000 N at an angle of 20 degrees, as shown in the image below. What is
the approximate vertical component of the net force that is moving the rocket
away from Earth?
20°
Vertical
Component
of Net Force
Thrust
500,000 N
Weight
220,000 N
The vertical component of the net force that is moving the rocket away from Earth is determined as 171,010.1 N.
Vertical component of the lift force
The vertical component of the net force that is moving the rocket away from Earth is determined as follows;
Fy = Fsinθ
where;
F is applied forceθ is the angle of inclinationFy = 500,000 x sin(20)
Fy = 171,010.1 N
Thus, the vertical component of the net force that is moving the rocket away from Earth is determined as 171,010.1 N.
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Answer:
250,000
Explanation:
The reasoning question please i need help
Answer:
speed of the friend that is 8m from the center:
0.8π m/s
the distance she will travel in one rotation is:
10
Her speed compared to you is faster because, she is farther away from the axis compared to you.
Explanation:
for the speed, it says the farther you are from the axis the greater your speed is, and for the person who was 4m from the axis of rotation their speed was 0.4 because they are closer to the axis so therefore their speed is slower. so for the friend that is 8m from the axis of rotation its most likely their speed would be 0.8 m/s.
in one revolution you travel 8m your original distance from the axis was 4m so, 8-4 = 4, which means one revolution is plus 4 to your original distance. since the question is asking for rotation and not revolution you can do 4 ÷ 2 which is 2, so for rotation you need to add 2 to your original distance, so 8 + 2 = 10
A atom in its ground state contains 18 electrons. how many of these electrons are in orbital l=0 values?