Approximate square root of 35 using an appropriate linear approximation.

Using the z-distribution, as we are working with a proportion, it is found that you should sample 577 households.

A confidence interval of proportions is given by:

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which:

The margin of error is given by:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In this problem, we have a 95% confidence level, hence[tex]\alpha = 0.95[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.95}{2} = 0.975[/tex], so the critical value is z = 1.96.

In this problem, the estimate is of [tex]\pi = 0.6[/tex], and we want a margin of error of M = 0.05, hence we solve for n to find the sample size.

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.05 = 1.96\sqrt{\frac{0.6(0.4)}{n}}[/tex]

[tex]0.05\sqrt{n} = 1.96\sqrt{0.6(0.4)}[/tex]

[tex]\sqrt{n} = \frac{1.96\sqrt{0.6(0.4)}}{0.05}[/tex]

[tex](\sqrt{n})^2 = \left(\frac{1.96\sqrt{0.6(0.4)}}{0.05}\right)^2[/tex]

[tex]n = 576.24[/tex]

Rounding up, you should sample 577 households.

More can be learned about the z-distribution at https://brainly.com/question/25890103

Answer:

4 5/6 quarts or 4.83 quarts

Step-by-step explanation:

5 1/2 quart pot has an equal value to 11/2 quart pot

it is filled with 2/3 quarts of water

Therefore, the quarts of water the pot can hold is;

11/2 - 2/3

LCM = 6

11/2 - 2/3 ÷ 6

33 - 4 ÷ 6

29/6

:. 29/6 quarts(4 5/6 quarts or 4.83 quarts) of water is the amount needed to fill the 5 1/2 quart pot

Answer:

[tex]4 \cot {}^{2} (45) - 3 \tan {}^{2} (60) + 2 \sec {}^{2} (60) = 3 \\ [/tex]

[tex]LHS = 4 \cot {}^{2} (45) - 3 \tan {}^{2} (60) + 2 \sec {}^{2} (60) \\[/tex]

let us first take a look at the values of the trigonometric ratios given in the question so that we get quite clear about what is to be done.

here ,

[tex] \cot(45) = 1 \\ \\ \tan(60) = \sqrt{3} \\ \\ \sec(60) = 2[/tex]

now ,

we just have to plug in the values considering certain other things given in the question and we're done!

so let's start ~

[tex]4(1) {}^{2} - 3( \sqrt{3} ) {}^{2} + 2(2) {}^{2} \\ \\ \dashrightarrow \: 4(1) - 3(3) + 2(4) \\ \\ \dashrightarrow \: 4 - 9 + 8 \\\\ \dashrightarrow \: 12 - 9 \\ \\\dashrightarrow \: 3 = RHS[/tex]

hence , proved ~

hope helpful :D

Answer:

Michelle walks 1 4 hour every day of the week (Monday through Sunday). Sandra walks 2 4 hour per day, but only on weekdays (Monday through Friday). Both Michelle and Sandra continue their routines for 9 weeks. Calculate who walked the most over this 9 week period, and calculate how much more time this person walked than the other person. Be sure to show how you calculated each person's total walking time as a mixed fraction, and show how you calculated how much more time was walked by either Michelle or Sandra as a mixed fraction. this is a word problom

Answer:

people are not doing it it's because that it's multiplying mixed numbers by whole numbers and we don't really need to do that

Step-by-step explanation:

✰ Given Information :-

⠀

A cylinder with following dimensions :

⠀

✰ To Find :-

⠀

⠀

✰ Formula Used :-

⠀

[tex] \qquad \star \: \underline{ \boxed{ \purple{\sf Volume_{Cylinder} = \pi {r}^{2} h}}} \: \star[/tex]

⠀

Where,

⠀

✰ Solution :-

⠀

Putting the values in the formula, we get,

⠀

[tex] \sf \longrightarrow Volume=3.14 \times {(3)}^{2} \times 5 \\ \\ \\ \sf \longrightarrow Volume=3.14 \times 45 \: cm \: \: \: \: \: \\ \\ \\ \sf \longrightarrow \underline{ \boxed{ \green{ \frak{Volume= {141 .3 \: cm}^{3} }}}} \: \star \: \: \: \: \: \\ [/tex]

⠀

Thus, the volume of the cylinder is 141.3 cm³.

⠀

[tex] \underline{ \rule{230pt}{2pt}} \\ \\ [/tex]

Step-by-step explanation:

As it is given that, a cylinder has radius 3 inches and height 5 inches and we are to find the volume of the cylinder, also a extra information is given that is a cone has the same radius and height.

[tex] \: [/tex]

We know,

[tex]{ \longrightarrow\qquad{\frak {\pmb{Volume_{(cylinder) } = \pi {r}^{2}h }}}} \\ \\[/tex]

Where,

[tex] \: [/tex]

Now, we will substitute the given values in the formula :

[tex] \: [/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{Volume_{(cylinder) } = 3.14 \times ( {3})^{2} \times 5 }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{Volume_{(cylinder) } = 3.14 \times 9 \times 5 }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{\sf {\pmb{Volume_{(cylinder) } = 3.14 \times 45 }}}} \\ \\[/tex]

[tex]{ \longrightarrow\qquad{\frak {\pmb{Volume_{(cylinder) } = 141.3 }}}} \\ \\[/tex]

Note :

Answer:

Step-by-step explanation:

First establish the pattern. Notice the sequence of numbers below. These are the ones making up the pattern. You can go as far as 47 - 31 which gives 16 which is 4^2.

18 -17 = 1 = 1^2

22 - 18 = 4 = 2^2

31 - 22 = 9 = 3^2

47 - 31 = 16 = 4^2

=================

Call the number comming x.  47 taken from x must give 5^2 which is 25

x - 47 = 5^2

x - 47 = 25                        Add 47 to both sides

x  -47 + 47 = 25 + 47

x  = 72

=================

72 -47 = 25 which is 5^2.

Answer: The next number is 72

Answer:

it is the same because slope is a measure of steepness.

Step-by-step explanation:

(0,1) (2,4)

4-1/2-0=3/2

slope=3/2

The dimension of the box of the greatest volume that can be constructed in this way is 12x12x3 and the volume is 432.

Let x be the side of the square to remove. Then the volume of the box is:

V(x) = (18 - 2x)² * x = 324x - 72x² + 4x³

To find the maximum volume, differentiate and set it to 0:

V'(x) = 324 - 144x + 12x²

0 = x² - 12x + 27

0 = (x - 9)(x - 3)

x = 3 or 9

When x = 3,

V"(x) =-144+24x

V"(3) =-144+72=-72<0

so volume is maximum at x=3

Therefore the box is 12x12x3 and the volume is 432.

Learn more about dimension on:

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Answer:

128

6

12

48

Step-by-step explanation:

Answer:

2827.43 cm^2

Step-by-step explanation:

Hope this helped! <3 Have a great day :) Brainliest please?

Answer:

A = $1,742.75

A = P + I

Where

P is the principal (1,500.00)

I is the interest (242.75)

Steps:

First, convert R as a percent to r as a decimal

r = R/100

r = 1.5/100

r = 0.015 rate per year,

Then solve the equation for A

[tex]A = Pe^{rt}\\A = 1,500.00(2.71828)^{(0.015)(10)}\\A = $1,742.75[/tex]

Summary:

The total amount with compound interest on a principal of $1,500.00 at a rate of 1.5% per year compounded continuously over 10 years is $1,742.75.

Answer:

The answer is $1.85

Step-by-step explanation:

Now, we know that the cost of 5 chocolate bars are $5.75.

For 1 chocolate bar

5.75 ÷ 5 = $1.15

Here, we get the price of 1 chocolate bar

So, the cost of 2 chocolate bars and 3 packets of sweets are $7.85.

2 × chocolate bar = 2 × (1.15) = $2.3

Now, we want to find only the cost of one packet of sweets.

So,

7.85 – 2.3 = $5.55

3 packets of sweets cost $5.55

For 1 packets of sweets

5.55 ÷ 3 = $1.85

Thus, The cost of one packet of sweets = $1.85

Step-by-step explanation:

please mark me as brainlest

Answer:

I hope it helped you

Step-by-step explanation:

Pls refer the given attachment

Answer:

O = 15

Step-by-step explanation:

.mean ' is the average

(12 + 16 + O + 14 + 8) / 5 = 13

50 + O = 65

O = 15

Answer: 3/4 is 75%

Step-by-step explanation: Since his fav number is 36 the half of 36 is 18 bc 18 + 18 is 36

Answer:

22.97

Step-by-step explanation:

17 divided by pi is 5.41

5.41 divided by 2 is 2.075

r^2(pi)

is 2.075 x 2.075 x 3.41 is 22.97

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve ~

[tex]\qquad \tt \dashrightarrow \:x - \dfrac{1}{2} \geqslant 43 [/tex]

[tex]\qquad \tt \dashrightarrow \:x \geqslant43 + \dfrac{1}{2} [/tex]

[tex]\qquad \tt \dashrightarrow \:x \geqslant \dfrac{86 + 1}{2} [/tex]

[tex]\qquad \tt \dashrightarrow \:x \geqslant \dfrac{87}{2} [/tex]

hope this helps Belinda aunty ~

Answer:

Let's first try to find the angle supplementary to measure 141°.

(Supplementary angles are two angles that add up together to equal 180°).

Set up an equation;

141 + x(unknown angle measure) = 180°

Solve for x:-

141 + x = 180

-141        -141

x = 39°.

Now that we've found one of the interior angles measure to this triangle, we will use this value to figure out the angle measure next to 'x'.

If we think of the line (highlighted in the picture I attached to this), extended, we can kind of make out of this line as a transversal cutting into the two parallel lines(L & M).

Furthermore, the measured angle 39°, is an alternate interior angle with the missing angle next to 'x'(highlighted with yellow in my picture).

And, alternate interior angles are congruent(meaning they measure the same degree).

Therefore, we can infer that the missing angle next to 'x' is also 39°.

Now that we've found one angle measure and another angle(given) next to x, we can see that angle x and those two angle measures (48° and 39°) combined are supplementary!

So now that we know that angles 48° and 39° are supplementary with x, we can find the value of x by finding it's supplement value!

Arrange an equation;

(48 + 39) + x = 180°

Simplify and solve for x:-

87 + x = 180

-87        -87

x = 93°, hence ∠X = 93°.

I think you meant to say

[tex]\ln(x+y) = 4xy[/tex]

and not "4 times y" on the right side (which would lead to a complex value for y when x = 0). Note that when x = 0, the equation reduces to ln(y) = 0, so that y = 1.

Implicitly differentiating both sides with respect to x, taking y = y(x), and solving for dy/dx gives

[tex]\dfrac{1+\frac{dy}{dx}}{x+y} = 4y + 4x\dfrac{dy}{dx}[/tex]

[tex]\implies \dfrac{dy}{dx} = \dfrac{4xy+4y^2-1}{1-4x^2-4xy}[/tex]

Note that when x = 0 and y = 1, we have dy/dx = 3.

Differentiate both sides again with respect to x :

[tex]\dfrac{d^2y}{dx^2} = \dfrac{(1-4x^2-4xy)\left(4y+4x\frac{dy}{dx}+8y\frac{dy}{dx}\right)-(4xy+4y^2-1)\left(-8x-4y-4x\frac{dy}{dx}\right)}{(1-4x^2-4xy)^2}[/tex]

No need to simplify; just plug in x = 0, y = 1, and dy/dx = 3 to get

[tex]\dfrac{d^2y}{dx^2} \bigg|_{x=0} = \boxed{40}[/tex]

Answer:

1. 4/5+2/3=?

The fractions have unlike denominators. First, find the Least Common Denominator and rewrite the fractions with the common denominator.

LCD(4/5, 2/3) = 15

Multiply both the numerator and denominator of each fraction by the number that makes its denominator equal the LCD. This is basically multiplying each fraction by 1.

(45×33)+(23×55)=?

Complete the multiplication and the equation becomes

12/15+10/15=?

The two fractions now have like denominators so you can add the numerators.

Then: 12+10/15=22/15

This fraction cannot be reduced. The fraction

22/15 is the same as 22÷15

Convert to a mixed number using long division for 22 ÷ 15 = 1R7, so

22/15=17/15

Therefore: 4/5+2/3=17/15

Solution by Formulas Apply the fractions formula for addition, to 4/5+2/3 and solve

(4×3)+(2×5)/5×3

=12+10/15

=22/15 Convert to a mixed number using long division for 22 ÷ 15 = 1R7, so 22/15=17/15 Therefore:4/5+2/3=1  7/15

Step-by-step explanation:

Answer:

See below.

Step-by-step explanation:

1.

2.

3.

4.

Answer:

yea

Step-by-step explanation:

[tex]"20cm"[/tex]

[tex]Area\ of\ rq=a^2[/tex]

[tex]a=\sqrt{200}=10\bullet \sqrt{2}[/tex]

[tex]d\ iargul=\sqrt{2}9[/tex]

             [tex]=10\times \sqrt{2}\times \sqrt{2}[/tex]

             [tex]=20cm[/tex]

I hope this helps you

:)

Step-by-step explanation:

[tex] 2 \frac{1}{3} \times \frac{3}{4} \\

[/tex]2 1/3 = 7/3

[tex] \frac{7}{3} \times \frac{3}{4} \\ [/tex]

21/12 = 7/4

Answer:

Events A and B are independent of each other, so P⁡(B∣A)=P⁡(B)=0.95726.

Explanation -

I got this answer from Plato.

Answer:

10,000 is the total amount of.money that was distributed

[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]

Let's solve for x ~

[tex]\qquad \sf  \dashrightarrow \:4x - 16 = 64[/tex]

[tex]\qquad \sf  \dashrightarrow \:4(x - 4) = 64[/tex]

[tex]\qquad \sf  \dashrightarrow \:(x - 4) = 64 \div 4[/tex]

[tex]\qquad \sf  \dashrightarrow \:x - 4 = 16[/tex]

[tex]\qquad \sf  \dashrightarrow \:x = 16 + 4[/tex]

[tex]\qquad \sf  \dashrightarrow \:x =20[/tex]

[tex] \boxed{ \bf \huge \: Answer \: }[/tex]

[tex] \: \: [/tex]

[tex] \sf \large \: 4x - 16 = 64[/tex]

[tex] \: \: [/tex]

[tex] \sf \large \: 4x = 64 + 16[/tex]

[tex] \: \: [/tex]

[tex] \sf \large \: 4x = 40[/tex]

[tex] \: [/tex]

[tex] \sf \large \: x = \cancel \frac{80}{4} [/tex]

[tex] \: \: [/tex]

[tex] \sf \large x = 20[/tex]

[tex] \: \: [/tex]

Hope It's Helps uh Miss<3"

The required length of the rectangle is 12/5 feet and the width is 9/5 feet.

The equation model is defined as the model of the given situation in the form of an equation using variables and constants.

Here,
Let's denote the length of the rectangle as L and the width as W.

From the problem statement, we know that:

3L = 4W (equation 1)

We also know that the perimeter P is given by:

P = 2L + 2W = 8 2/5 feet

Multiplying both sides by 5 to get rid of the fraction, we get:

10L + 10W = 42

Dividing by 2, we get:

5L + 5W = 21 (equation 2)

Now we can use equations 1 and 2 to solve for L and W.

First, we can substitute equation 1 into equation 2 to get an equation in terms of W:

5L + 15L/4 = 21

Multiplying both sides by 4, we get:

20L + 15L = 84

35L = 84

L = 84/35 = 12/5 feet

Now we can substitute the value of L into equation 1 to get the value of W:

3L = 4W

3(12/5) = 4W

W = 9/5 feet

Therefore, the length of the rectangle is 12/5 feet and the width is 9/5 feet.

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Answer:

Use the geometric sequence formula since you are multiplying each town's villagers by the amount your teacher gave you.

Step-by-step explanation:

Plug in the parts of the formula from the numbers given in the question, then you can calculate the number of villagers needed for the 15th town.

Answer:

35.375 Villagers Live in the 15th village

Step-by-step explanation:

Brennan can use the Geometric Sequence formula to predict the number of villagers in the 15th town.

(work attached)

Answer:

C. tanS = 5/12, tanT = 12/5

Step-by-step explanation:

Tangent has NOTHING to do with hypotenuse, do we can easily eliminate answer choices involving 13, the hypotenuse. For angle S, the opposite side measures 5 and the adjacent side measures 12. For angle T, the opposite side measures 12 and the adjacent side measures 5. See this below algebraically

tanθ = opp/adj

tanS = 5/12

tanT = 12/5

I hope this helps!

so let's say the equation is y = ax² + bx + c, where a,b,c are constants.

we know that f(3) = 5, or namely when x = 3 , y = 5.

we also know that f'(3) = 6, or namely the slope at the point (3,5) is 6.

we also know that at (3,5) the 2nd derivative is 4, so a positive number simply tell us its concavity, is up, so is a parabola opening upwards.

[tex]y=ax^2+bx+c\implies \left. \cfrac{dy}{dx}=2ax+b \right|_{x=3}~~ = ~~ 6\implies 6=2ax+b \\\\\\ 6=2a(\stackrel{x}{3})+b\implies 6=6a+b\implies 6-6a=b\implies \boxed{6(1-a)=b} \\\\[-0.35em] ~\dotfill\\\\ \left. \cfrac{d^2y}{dx^2}=2a \right|_{x=3}~~ = ~~4\implies 2a=4\implies a=\cfrac{4}{2}\implies \boxed{a=2}~\hfill \boxed{-6=b} \\\\[-0.35em] ~\dotfill[/tex]

[tex]y=2x^2-6x+c\qquad \begin{cases} x=3\\ y = 5 \end{cases}\implies 5=2(3)^2-6(3)+c\implies \boxed{5=c} \\\\\\ y=2x^2-6x+5~\hfill y(2)=2(2)^2-6(2)+5\implies \blacktriangleright y(2)=1 \blacktriangleleft[/tex]